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  • How to properly use the .animate() function -- top

    - by sadmicrowave
    Is this the proper way to use the .animate(top) function? Positive number (animate down)-- $("div#container div#history-menu").animate({top:'180px'}, 600); Negative number (animate up)-- $("div#container div#history-menu").animate({top:'-180px'}, 600); Because I'm getting a java error in my error console that says: "error in parsing value for property 'top'. Declaration Dropped."

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  • How to handle ordering of @Rule's when they are dependant on eachother

    - by Lennart Schedin
    I use embedded servers that run inside Junit test cases. Sometimes these servers require a working directory (for example the Apache Directory server). The new @Rule in Junit 4.7 can handle these cases. The TemporaryFolder-Rule can create a temporary directory. A custom ExternalResource-Rule can be created for server. But how do I handle if I want to pass the result from one rule into another: import static org.junit.Assert.assertEquals; import java.io.*; import org.junit.*; import org.junit.rules.*; public class FolderRuleOrderingTest { @Rule public TemporaryFolder folder = new TemporaryFolder(); @Rule public MyNumberServer server = new MyNumberServer(folder); @Test public void testMyNumberServer() throws IOException { server.storeNumber(10); assertEquals(10, server.getNumber()); } /** Simple server that can store one number */ private static class MyNumberServer extends ExternalResource { private TemporaryFolder folder; /** The actual datafile where the number are stored */ private File dataFile; public MyNumberServer(TemporaryFolder folder) { this.folder = folder; } @Override protected void before() throws Throwable { if (folder.getRoot() == null) { throw new RuntimeException("TemporaryFolder not properly initialized"); } //All server data are stored to a working folder File workingFolder = folder.newFolder("my-work-folder"); dataFile = new File(workingFolder, "datafile"); } public void storeNumber(int number) throws IOException { dataFile.createNewFile(); DataOutputStream out = new DataOutputStream(new FileOutputStream(dataFile)); out.writeInt(number); } public int getNumber() throws IOException { DataInputStream in = new DataInputStream(new FileInputStream(dataFile)); return in.readInt(); } } } In this code the folder is sent as a parameter into the server so that the server can create a working directory to store data. However this does not work because Junit processes the rules in reverse order as they are defined in the file. The TemporaryFolder Rule will not be executed before the server Rule. Thus the root-folder in TempraryFolder will be null, resulting that any files are created relative to the current working directory. If I reverse the order of the attributes in my class I get a compile error because I cannot reference a variable before it is defined. I'm using Junit 4.8.1 (because the ordering of rules was fixed a bit from the 4.7 release)

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  • Question on First Order Logic formula

    - by none
    Hi, Can someone validate the following. I am supposed to 'write a formula asserting that for every number there's a unique next number...true for integers for instance' L(x,y) means x is smaller than y the intended Domain is the Integer numbers Can I give ∀x ∀y [ x<y ⇒ ( ∃z : z<x ∨ y<z ) ] Thanks

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  • C++ program Telephone Directory from a file

    - by Stacy Doyle
    I am writing a program for a phone directory. The user inputs a name and the program searches the file and either outputs the number or an error because the persons name is not in the file. The program should also ask the user if they would like to continue using the program and look up another number. So far runs and asks for the name and then prints the error message that I put in place saying that the name is not in the database. I am guessing that I must not really be having my program look in the file but not sure what to do also don't know how to get the program to run again if the user chooses to continue. #include <iostream> #include <fstream> #include <string> #include <iomanip> using namespace std; char chr; int main() { string first; string last; string number; string firstfile; string lastfile; string numberfile; int cont; ifstream infile; infile.open("name and numbers.dat"); //opening the file infile>>firstfile>>lastfile>>numberfile; cout<<"Enter a first and last name."<<endl; //Asking user for the input cin>>first>>last; //input the data { if(first==firstfile && last==lastfile) //if the entered information matches the information in the file cout<<first<<" "<<last<<"'s number is "<<numberfile<<endl; //this is printed else cout<<"Sorry that is not in our database."<<endl; //if the information doesn't match this is printed } cout<<"Would you like to search for another name? Y or N"<<endl; //user is asked if they would like to continue cin>>cont; infile.close(); //close file cin>>chr; return 0; }

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  • Make a server for a chat

    - by Sebastian
    Hello, I would like to make a server for a chat and I wonder whether a server must, for example, connect to MySQL whenever a client enter to a room to check if he is moderator or banned from this room. Is it necessary that I use MySQL to update the number of connected clients whenever a client go to another room(to display the number of connected clients on a web page)?

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  • In Javascript, how to avoid NaN when adding arrays

    - by Jonas
    I'm trying to add the values of two arrays in javascript eg. [1,2,1] + [3,2,3,4] The answer should be 4,4,4,4 but I'm either getting 4,4,4 or 4,4,4,NaN if I change the 1st array length to 4. I know a 4th number needs to be in the 1st array, but i can't figure out how to tell javascript to make it 0 rather then undefined if there is no number.

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  • How do you create a MANIFEST.MF that's available when you're testing and running from a jar in produ

    - by warvair
    I've spent far too much time trying to figure this out. This should be the simplest thing and everyone who distributes Java applications in jars must have to deal with it. I just want to know the proper way to add versioning to my Java app so that I can access the version information when I'm testing, e.g. debugging in Eclipse and running from a jar. Here's what I have in my build.xml: <target name="jar" depends = "compile"> <property name="version.num" value="1.0.0"/> <buildnumber file="build.num"/> <tstamp> <format property="TODAY" pattern="yyyy-MM-dd HH:mm:ss" /> </tstamp> <manifest file="${build}/META-INF/MANIFEST.MF"> <attribute name="Built-By" value="${user.name}" /> <attribute name="Built-Date" value="${TODAY}" /> <attribute name="Implementation-Title" value="MyApp" /> <attribute name="Implementation-Vendor" value="MyCompany" /> <attribute name="Implementation-Version" value="${version.num}-b${build.number}"/> </manifest> <jar destfile="${build}/myapp.jar" basedir="${build}" excludes="*.jar" /> </target> This creates /META-INF/MANIFEST.MF and I can read the values when I'm debugging in Eclipse thusly: public MyClass() { try { InputStream stream = getClass().getResourceAsStream("/META-INF/MANIFEST.MF"); Manifest manifest = new Manifest(stream); Attributes attributes = manifest.getMainAttributes(); String implementationTitle = attributes.getValue("Implementation-Title"); String implementationVersion = attributes.getValue("Implementation-Version"); String builtDate = attributes.getValue("Built-Date"); String builtBy = attributes.getValue("Built-By"); } catch (IOException e) { logger.error("Couldn't read manifest."); } } But, when I create the jar file, it loads the manifest of another jar (presumably the first jar loaded by the application - in my case, activation.jar). Also, the following code doesn't work either although all the proper values are in the manifest file. Package thisPackage = getClass().getPackage(); String implementationVersion = thisPackage.getImplementationVersion(); Any ideas?

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  • segmented reduction with scattered segments

    - by Christian Rau
    I got to solve a pretty standard problem on the GPU, but I'm quite new to practical GPGPU, so I'm looking for ideas to approach this problem. I have many points in 3-space which are assigned to a very small number of groups (each point belongs to one group), specifically 15 in this case (doesn't ever change). Now I want to compute the mean and covariance matrix of all the groups. So on the CPU it's roughly the same as: for each point p { mean[p.group] += p.pos; covariance[p.group] += p.pos * p.pos; ++count[p.group]; } for each group g { mean[g] /= count[g]; covariance[g] = covariance[g]/count[g] - mean[g]*mean[g]; } Since the number of groups is extremely small, the last step can be done on the CPU (I need those values on the CPU, anyway). The first step is actually just a segmented reduction, but with the segments scattered around. So the first idea I came up with, was to first sort the points by their groups. I thought about a simple bucket sort using atomic_inc to compute bucket sizes and per-point relocation indices (got a better idea for sorting?, atomics may not be the best idea). After that they're sorted by groups and I could possibly come up with an adaption of the segmented scan algorithms presented here. But in this special case, I got a very large amount of data per point (9-10 floats, maybe even doubles if the need arises), so the standard algorithms using a shared memory element per thread and a thread per point might make problems regarding per-multiprocessor resources as shared memory or registers (Ok, much more on compute capability 1.x than 2.x, but still). Due to the very small and constant number of groups I thought there might be better approaches. Maybe there are already existing ideas suited for these specific properties of such a standard problem. Or maybe my general approach isn't that bad and you got ideas for improving the individual steps, like a good sorting algorithm suited for a very small number of keys or some segmented reduction algorithm minimizing shared memory/register usage. I'm looking for general approaches and don't want to use external libraries. FWIW I'm using OpenCL, but it shouldn't really matter as the general concepts of GPU computing don't really differ over the major frameworks.

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  • any faster alternative??

    - by kaushik
    I have to read a file from a particular line number and i know the line number say "n": i have been thinking of two choice: 1)for i in range(n) fname.readline() k=readline() print k 2)i=0 for line in fname: dictionary[i]=line i=i+1 but i want to know faster alternative as i might have to perform this on different files 20000 times. is there is any other better alternatives?? thanking u

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  • What would you do to make this code more "over-engineered"? [closed]

    - by Mez
    A friend and I got bored, and, long story short, decided to make an over-engineered FizzBuzz in PHP <?php interface INumber { public function go(); public function setNumber($i); } class FBNumber implements INumber { private $value; private $fizz; private $buzz; public function __construct($fizz = 3 , $buzz = 5) { $this->setFizz($fizz); $this->setBuzz($buzz); } public function setNumber($i) { if(is_int($i)) { $this->value = $i; } } private function setFizz($i) { if(is_int($i)) { $this->fizz = $i; } } private function setBuzz($i) { if(is_int($i)) { $this->buzz = $i; } } private function isFizz() { return ($this->value % $this->fizz == 0); } private function isBuzz() { return ($this->value % $this->buzz == 0); } private function isNeither() { return (!$this->isBuzz() AND !$this->isFizz()); } private function isFizzBuzz() { return ($this->isFizz() OR $this->isBuzz()); } private function fizz() { if ($this->isFizz()) { return "Fizz"; } } private function buzz() { if ($this->isBuzz()) { return "Buzz"; } } private function number() { if ($this->isNeither()) { return $this->value; } } public function go() { return $this->fizz() . $this->buzz() . $this->number(); } } class FizzBuzz { private $limit; private $number_class; private $numbers = array(); function __construct(INumber $number_class, $limit = 100) { $this->number_class = $number_class; $this->limit = $limit; } private function collectNumbers() { for ($i=1; $i <= $this->limit; $i++) { $n = clone($this->number_class); $n->setNumber($i); $this->numbers[$i] = $n->go(); unset($n); } } private function printNumbers() { $return = ''; foreach($this->numbers as $number){ $return .= $number . "\n"; } return $return; } public function go() { $this->collectNumbers(); return $this->printNumbers(); } } $fb = new FizzBuzz(new FBNumber()); echo $fb->go(); In theory, what could we/would you do to make it even more "over-engineered"?

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  • Length of current selection in Eclipse

    - by Grzegorz Oledzki
    Do you know any easy way to know what is the length of current selection in Eclipse? I.e. I select a line fragment and would like to know how many characters are there? Usually I count them manually, but that's stupid. When being desperate I move to the start, check the column number, move to the end, check the column number, subtract, think a minute if I should add 1 or not... and my selection is lost.

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  • Typecast cross-platform compatibility

    - by kaykun
    Hi, what I'm trying to do is append a binary integer into a string object. So far I have this: int number = 5; cppstring.append((char*)&number, 4); It works fine on a x86 system with Windows, but some people are saying its not cross-platform and is unsafe. What is the preferred method to do this?

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  • Recommended way to perform Lucene search without limit

    - by Thomas
    The Lucene documents tell me that "Hits" will be removed from the API in Lucene 3.0. Deprecated. Hits will be removed in Lucene 3.0. Use search(Query, Filter, int) instead. The proposed overload limits the number of documents returned to the value of the int. So my question is: what is the recommended way to perform a search in Lucene with no limit on the number of documents to be returned?

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  • MS Access ADODB.recordset character limit is 2036!? Can this be increased?

    - by souper-dragon
    In the following AccessVBA code, I am trying to write a record to a memo field called "Recipient_Display": oRec1.Fields("RECIPIENT_DISPLAY") = Left(sRecipientDisplayNames, Len(sRecipientDisplayNames) - 2) When the string contains 2036 characters, the write completes. Above this number I get the following error: Run-time error'-2147217887(80040e21)': Could not update; currently locked by another session on this machine. What is the significance of this number 2036 and is there a property I can adjust that will allow the above update to take place?

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  • SSL Authentication with Certificates: Should the Certificates have a hostname?

    - by sixtyfootersdude
    Summary JBoss allows clients and servers to authenticate using certificates and ssl. One thing that seems strange is that you are not required to give your hostname on the certificate. I think that this means if Server B is in your truststore, Sever B can pretend to be any server that they want. (And likewise: if Client B is in your truststore...) Am I missing something here? Authentication Steps (Summary of Wikipeida Page) Client Server ================================================================================================= 1) Client sends Client Hello ENCRIPTION: None - highest TLS protocol supported - random number - list of cipher suites - compression methods 2) Sever Hello ENCRIPTION: None - highest TLS protocol supported - random number - choosen cipher suite - choosen compression method 3) Certificate Message ENCRIPTION: None - 4) ServerHelloDone ENCRIPTION: None 5) Certificate Message ENCRIPTION: None 6) ClientKeyExchange Message ENCRIPTION: server's public key => only server can read => if sever can read this he must own the certificate - may contain a PreMasterSecerate, public key or nothing (depends on cipher) 7) CertificateVerify Message ENCRIPTION: clients private key - purpose is to prove to the server that client owns the cert 8) BOTH CLIENT AND SERVER: - use random numbers and PreMasterSecret to compute a common secerate 9) Finished message - contains a has and MAC over previous handshakes (to ensure that those unincripted messages did not get broken) 10) Finished message - samething Sever Knows The client has the public key for the sent certificate (step 7) The client's certificate is valid because either: it has been signed by a CA (verisign) it has been self-signed BUT it is in the server's truststore It is not a replay attack because presumably the random number (step 1 or 2) is sent with each message Client Knows The server has the public key for the sent certificate (step 6 with step 8) The server's certificate is valid because either: it has been signed by a CA (verisign) it has been self-signed BUT it is in the client's truststore It is not a replay attack because presumably the random number (step 1 or 2) is sent with each message Potential Problem Suppose the client's truststore has certs in it: Server A Server B (malicous) Server A has hostname www.A.com Server B has hostname www.B.com Suppose: The client tries to connect to Server A but Server B launches a man in the middle attack. Since server B: has a public key for the certificate that will be sent to the client has a "valid certificate" (a cert in the truststore) And since: certificates do not have a hostname feild in them It seems like Server B can pretend to be Server A easily. Is there something that I am missing?

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  • JAVA gzip.read AND PHP

    - by Mantas
    I have line in JAVA and in while i get number: i = gzipinputstream1.read(abyte0, j, 4096); From while number: 959 1552 1577 1617 1680 when i want use in php: $i = fread($handle, 959): while return: 959, 959, 959, 5 How make that in PHP result will be the some. thanks

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  • c++ i need help with this program. everytime i try to run it, i got a problem

    - by FOXMULDERIZE
    1-the program must read numeric data from a file. 2-only one line per number 3-half way between those numbers is a negative number. 4-the program must sum those who are above the negative number in a acumulator an those below the negative number in another acumulator. 5-the black screen shall print both results and determined who is grater or equal. include include using namespace std; void showvalues(int,int,int[]); void showvalues2(int,int); void sumtotal(int,int); int main() { int total1=0; int total2=0; const int SIZE_A= 9; int arreglo[SIZE_A]; int suma,total,a,b,c,d,e,f; ifstream archivo_de_entrada; archivo_de_entrada.open("numeros.txt"); //lee/// for(int count =0 ;count < SIZE_A;count++) archivo_de_entrada>>arreglo[count] ; archivo_de_entrada.close(); showvalues(0,3,arreglo); showvalues2(5,8); sumtotal(total1,total2); system("pause"); return 0; } void showvalues(int a,int b,int arreglos) { int total1=0; //muestra//////////////////////// cout<< "los num son "; for(int count = a ;count <= b;count++) total1 += arreglos[count]; cout < } void showvalues2(int c,int d) { ////////////////////////////// int total2=0; cout<< "los num 2 son "; for(count =5 ;count <=8;count++) total2 = total2 + arreglo[count]; cout < void sumtotal(int e,int f) { ///////////////////////////////// cout<<"la suma de t1 y t2 es "; total= total1 + total2; cout< }

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