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  • How can I disable a model field in a django form

    - by jammon
    I have a model like this: class MyModel(models.Model): REGULAR = 1 PREMIUM = 2 STATUS_CHOICES = ((REGULAR, "regular"), (PREMIUM, "premium")) name = models.CharField(max_length=30) status = models.IntegerField(choices = STATUS_CHOICES, default = REGULAR) class MyForm(forms.ModelForm): class Meta: model = models.MyModel In a view I initialize one field and try to make it non-editable: myform = MyForm(initial = {'status': requested_status}) myform.fields['status'].editable = False But the user can still change that field. What's the real way to accomplish what I'm after?

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  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

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  • Transaction within transaction

    - by user281521
    Hello, I want to know if open a transaction inside another is safe and encouraged? I have a method: def foo(): session.begin try: stuffs except Exception, e: session.rollback() raise e session.commit() and a method that calls the first one, inside a transaction: def bar(): stuffs try: foo() #<<<< there it is :) stuffs except Exception, e: session.rollback() raise e session.commit() if I get and exception on the foo method, all the operations will be rolled back? and everything else will work just fine? thanks!!

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  • Using Django view variables inside templates

    - by William
    Hi, this is a rather basic question (I'm new to Django) but I'm having trouble using a variable set in my view inside my template. If I initialize a string or list inside my view (i.e. h = "hello") and then attempt to call it inside a template: {{ h }} there is neither output nor errors. Similarly, if I try to use a variable inside my template that doesn't exist: {{ asdfdsadf }} there is again no error reported. Is this normal? And how can I use my variables within my templates. Thanks!

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  • Best practice- How to team-split a django project while still allowing code reusal

    - by Infinity
    I know this sounds kind of vague, but please let me explain- I'm starting work on a brand new project, it will have two main components: "ACME PRODUCT" (think Gmail, Meebo, etc), and "THE SITE" (help, information, marketing stuff, promotional landing pages, etc lots of marketing-induced cruft). So basically the url /acme/* will load stuff in the uber cool ajaxy application, and every other URI will load stuff in the other site. Problem: "THE SITE" component is out of my hands, and will be handled by a consultants team that will work closely with marketing, And I and my team will work solely on the ACME PRODUCT. Question: How to set up the django project in such a way that we can have: Seperate releases. (They can push new marketing pages and functionality without having to worry about the state of our code. Maybe even separate Subversion "projects") Minimize impact (on our product) of whatever flying-unicorns-hocus-pocus the other team codes into the site. Still allow some code reusal. My main concern is that the ACME product needs to be rock solid, and therefore needs to be somewhat isolated of whatever mistakes/code bloopers the consultants make in their marketing side of the site. How have you handled this? Any ideas? Thanks!

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  • Django: automatically import MEDIA_URL in context

    - by pistacchio
    Hi, like exposed here, one can set a MEDIA_URL in settings.py (for example i'm pointing to Amazon S3) and serve the files in the view via {{ MEDIA_URL }}. Since MEDIA_URL is not automatically in the context, one have to manually add it to the context, so, for example, the following works: #views.py from django.shortcuts import render_to_response from django.template import RequestContext def test(request): return render_to_response('test.html', {}, context_instance=RequestContext(request)) This means that in each view.py file i have to add from django.template import RequestContext and in each response i have to explicitly specify context_instance=RequestContext(request). Is there a way to automatically (DRY) add MEDIA_URL to the default context? Thanks in advance.

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  • Horizontal scrolling in a wx.RichTextCtrl

    - by Sam
    I have a RichTextCtrl created as follows: self.userlist = wx.richtext.RichTextCtrl(self, style=wx.TE_MULTILINE|wx.TE_READONLY|wx.HSCROLL) It all works fine, except for the wx.HSCROLL style. If I change the RichTextCtrl to a regular TextCtrl, it correctly horizontal scrolls on long lines, rather than wrapping, but on the RichTextCtrl it wraps regardless. Is there an easy way to make it scroll horizontally? (I do, unfortunately, need the RichTextCtrl's featureset for this object.)

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  • Send Special Keys to Gtk.VteTerminal

    - by Ubersoldat
    Hi I have this OSS Project called Monocaffe connections manager which uses the Gtk.VteTerminal widget from PyGTK. A nice feature is that it allows the users to send commands to different servers' consoles (cluster mode) using a Gtk.TextView for the input. The way I send key strokes to each Gtk.VteTerminal is by using the feed_child method. For common keys there's no problem: I simply feed what the TextView receives to all the terminals, but when doing so with special keys I get into a little trouble. For "Return" I catch the event and feed the terminal a '\n'. For back-space is the same, catch the event and feed a '\b'. def cluster_backspace(self, widget): return self.cluster_send_key('\b') The problem comes with other keys like Tab, Arrows, Esc which I don't know how to feed as str to the terminal to recognize them. In the case of Esc is a real pain, because the users can edit the same file on different servers using vi, but cannot escape insert mode. Anyway, I'm not looking for a complete solution, just ideas since I've ran out of them. Thanks.

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  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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  • How to invert alternate bits of a number

    - by Cupidvogel
    The problem is how to invert alternate bits of a number, starting from the LSB. Currently what I am doing is first doing a count = -1 while n: n >>= 1 count += 1 to first find the position of the leftmost set bit, then running a loop to invert every alternate bit: i = 0 while i <= count: num ^= 1<<i i += 2 Is there a quick hack solution instead of this rather boring loop solution? Of course, the solution can't make any asumption about the size of the integer.

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  • subplot matplotlib wrong syntax

    - by madptr
    I am using matplotlib to subplot in a loop. For instance, i would like to subplot 49 data sets, and from the doc, i implemented it this way; import numpy as np import matplotlib.pyplot as plt X1=list(range(0,10000,1)) X1 = [ x/float(10) for x in X1 ] nb_mix = 2 parameters = [] for i in range(49): param = [] Y = [0] * len(X1) for j in range(nb_mix): mean = 5* (1 + (np.random.rand() * 2 - 1 ) * 0.5 ) var = 10* (1 + np.random.rand() * 2 - 1 ) scale = 5* ( 1 + (np.random.rand() * 2 - 1) * 0.5 ) Y = [ Y[k] + scale * np.exp(-((X1[k] - mean)/float(var))**2) for k in range(len(X1)) ] param = param + [[mean, var, scale]] ax = plt.subplot(7, 7, i + 1) ax.plot(X1, Y) parameters = parameters + [param] ax.show() However, i have an index out of range error from i=0 onwards. Where can i do better to have it works ? Thanks

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  • Matplotlib not showing up in Mac OSX

    - by Werner
    Hi, I am running Mac OSX 10.5.8. I installed matplotlib using macports. I get some examples from the matplotlib gallery like this one, without modification: http://matplotlib.sourceforge.net/examples/api/unicode_minus.html I run it, get no error, but the picture does not show up. In Linux Ubuntu I get it. Do you know what could be wrong here? Thanks

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  • Solution for distributing MANY simple network tasks?

    - by EmpireJones
    I would like to create some sort of a distributed setup for running a ton of small/simple REST web queries in a production environment. For each 5-10 related queries which are executed from a node, I will generate a very small amount of derived data, which will need to be stored in a standard relational database (such as PostgreSQL). What platforms are built for this type of problem set? The nature, data sizes, and quantities seem to contradict the mindset of Hadoop. There are also more grid based architectures such as Condor and Sun Grid Engine, which I have seen mentioned. I'm not sure if these platforms have any recovery from errors though (checking if a job succeeds). What I would really like is a FIFO type queue that I could add jobs to, with the end result of my database getting updated. Any suggestions on the best tool for the job?

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  • Replace ",**" with a linebreak using RegEx (or something else)

    - by John
    I'm getting started with RegEx and I was wondering if anyone could help me craft a statement to convert coordinates as follows: 145.00694,-37.80421,9 145.00686,-37.80382,9 145.00595,-37.8035,16 145.00586,-37.80301,16 to 145.00694,-37.80421 145.00686,-37.80382 145.00595,-37.8035 145.00586,-37.80301 (Strip off the last comma and value and turn it into a line break.) I can't figure out how to use wildcards to do something like that. Any help would be greatly appreciated! Thanks.

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  • Is there something similar to 'rake routes' in django?

    - by The MYYN
    In rails, on can show the active routes with rake (http://guides.rubyonrails.org/routing.html): $ rake routes users GET /users {:controller=>"users", :action=>"index"} formatted_users GET /users.:format {:controller=>"users", :action=>"index"} POST /users {:controller=>"users", :action=>"create"} POST /users.:format {:controller=>"users", :action=>"create"} Is there a similar tool/command for django showing the e.g. the URL pattern, the name of the pattern (if any) and the associated function in the views?

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  • Online job-searching is tedious. Help me automate it.

    - by ehsanul
    Many job sites have broken searches that don't let you narrow down jobs by experience level. Even when they do, it's usually wrong. This requires you to wade through hundreds of postings that you can't apply for before finding a relevant one, quite tedious. Since I'd rather focus on writing cover letters etc., I want to write a program to look through a large number of postings, and save the URLs of just those jobs that don't require years of experience. I don't require help writing the scraper to get the html bodies of possibly relevant job posts. The issue is accurately detecting the level of experience required for the job. This should not be too difficult as job posts are usually very explicit about this ("must have 5 years experience in..."), but there may be some issues with overly simple solutions. In my case, I'm looking for entry-level positions. Often they don't say "entry-level", but inclusion of the words probably means the job should be saved. Next, I can safely exclude a job the says it requires "5 years" of experience in whatever, so a regex like /\d\syears/ seems reasonable to exclude jobs. But then, I realized some jobs say they'll take 0-2 years of experience, matches the exclusion regex but is clearly a job I want to take a look at. Hmmm, I can handle that with another regex. But some say "less than 2 years" or "fewer than 2 years". Can handle that too, but it makes me wonder what other patterns I'm not thinking of, and possibly excluding many jobs. That's what brings me here, to find a better way to do this than regexes, if there is one. I'd like to minimize the false negative rate and save all the jobs that seem like they might not require many years of experience. Does excluding anything that matches /[3-9]\syears|1\d\syears/ seem reasonable? Or is there a better way? Training a bayesian filter maybe?

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  • How fast are App Engine db.get(keys) and A.all(keys_only=True).filter('b =', b).fetch(1000)?

    - by Liron Shapira
    A db.get() of 50 keys seems to take me 5-6 seconds. Is that normal? What is the time a function of? I also did a A.all(keys_only=True).filter('b =', b).fetch(1000) where A.b is a ReferenceProperty. I did 50 such round trips to the datastore, with different values of b, and the total time was only 3-4 seconds. How is this possible? db.get() is done in parallel, with only one trip to the datastore, and I would think that looking up an entity by key is a faster operation than fetch.

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  • PyGTK: Radiobuttons are still displayed after removal

    - by canavanin
    Hi everyone! I am using PyGTK and the gtk.assistant. On one page I would like to display two radiobuttons in case the user selected a certain option on a previous page. The labels of the buttons - and whether the buttons are to be present at all - are to depend entirely on that earlier selection. Furthermore, if the user goes back and changes that selection, the page containing the radiobuttons is to be updated accordingly. I have got as far as having the radiobuttons displayed when necessary, and with the correct labels. The trouble is that if I go back and change the determining selection, or if I move one page further than the 'radiobutton page' and then move back, the buttons are not only not removed (in case that would have been required), their number has also doubled. To show you what I'm doing, here's part of my code (I've left out bits that do unrelated things, that's why the function name doesn't fit). The function is called when the "prepare" signal is emitted prior to construction of the 'radiobutten page'. def make_class_skills_treestore(self): print self.trained_by_default_hbox.get_children() # PRINT 1 for child in self.trained_by_default_hbox.get_children(): if type(child) == gtk.RadioButton: self.trained_by_default_hbox.remove(child) #child.destroy() # <-- removed the labels, but not the buttons print self.trained_by_default_hbox.get_children() # PRINT 2 class_skills = self.data.data['classes'][selected_class].class_skills.values() default_trained_count = (class_skills.count([True, True]) , class_skills.count([True, False])) num_default_trained_skills = default_trained_count[1] / 2 # you have to pick one of a pair --> don't # count each as trained by default for i in range(default_trained_count[0]): # those are trained by default --> no choice num_default_trained_skills +=1 selected_class = self.get_classes_key_from_class_selection() if default_trained_count[1]: for skill in self.data.data['classes'][selected_class].class_skills.keys(): if self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and not self.default_radio: self.default_radio.append(gtk.RadioButton(group=None, label=skill)) elif self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and self.default_radio: self.default_radio.append(gtk.RadioButton(group=self.default_radio[0], label=skill)) if self.default_radio: for radio in self.default_radio: self.trained_by_default_hbox.add(radio) self.trained_by_default_hbox.show_all() self.trained_by_default_hbox and self.trained_by_default_label, as well as self.default_radio stem from the above function's class. I have two print statements (PRINT 1 and PRINT 2) in there for debugging. Here's what they give me: PRINT 1: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>, <gtk.RadioButton object at 0x8fc4d4c (GtkRadioButton at 0x90e4018)>, <gtk.RadioButton object at 0x8fc4cac (GtkRadioButton at 0x90ceec0)>] PRINT 2: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>] So the buttons have indeed been removed, yet they still show up on the page. I know the code requires some refactoring, but first I'd like to get it to work at all... If someone could help me out that would be great! Thanks a lot in advance for your replies - any kind of help is highly appreciated.

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  • poplib and email module will not reloop through a message if it has alread read it

    - by user1440925
    I'm currently trying to write a script that gets messages from my gmail account but I'm noticing a problem. If poplib loops through a message in my inbox it will never loop through it again. Here is my code import poplib, string, email user = "[email protected]" password = "p0ckystyx" message = "" mail = poplib.POP3_SSL('pop.gmail.com') mail.user(user) mail.pass_(password) iMessageCount = len(mail.list()[1]) message = "" msg = mail.retr(iMessageCount) str = string.join(msg[1], "\n") frmMail = email.message_from_string(str) for part in frmMail.walk(): if part.get_content_type() == "text/plain": print part.get_payload() mail.quit() Every time I run this script it goes to the next newest email and just skips over the email that was shown last time it was run.

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