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  • How is this site opening a new window

    - by user217428
    Normally we can specify a target in the link or use javascript window.open to open a new window. But when I access this site www.wenxuecity.com (It is a chinese site) I could't find out how it opens each news in a new window. no target in the link. debug javascript doesn't show any call to window.open Could someone tell me how it is implemented? Thanks

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  • Default FileField names for Django files

    - by Adam Nelson
    I have a model: class Example(models.Model): unique_hash = models.CharField(max_length=32,unique=True) content = models.FileField(upload_to='source',blank=True,verbose_name="HTML Content File") I would like to be able to set the content filename to default to a callable, but I don't see any way to have the callable reference unique_hash (or vice versa). Is this possible?

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  • How can we protect ourselves from other third parties installing DLLs with the same names as some of

    - by Integer Poet
    Our product includes several DLLs built from open source into files with default names as delivered by the open source developers. We're careful to install the files in our own directories and we carefully manage the search path (only for our processes) to keep the loader happy. Another developer -- a towering intellect -- decided it would be easier to install their own build of some of the same open source into C:\WINDOWS under the same default DLL filenames. Consequently, when we launch a process which depends on these open source DLLs, the system searches C:\WINDOWS before our directories and finds the DLLs installed by the other developer. And they are, of course, incompatible. Ideas which have occurred to me so far: rename all our DLLs to avoid the default names, which would only make it less likely we would encounter collisions load all our DLLs by full path so the loader captures their names into RAM and doesn't search anywhere else the next time they are requested For various reasons, neither of these options is palatable at the moment. What else can we do to defend ourselves against the towering intellects of the world?

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  • Can an ActiveRecord before_save filter halt the save without halting the transaction?

    - by Michael Boutros
    Is there any way for a before_save filter to halt the entire save without halting the transaction? What I'm trying to do is have a "sample" version of my model that the user can interact with and save but the changes themselves are never actually saved. The following will halt the transaction and (naturally) return false when I call @model.update_attributes: before_filter :ignore_changes_if_sample def ignore_changes_if_sample if self.sample? return false end end Thanks!

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  • uploading app problem in developers site

    - by Siva K
    hi i have posted one of my app in market.android.com when i am trying to post second app it shows "You have another application on Market with the same package name. Go to that other application, and click upgrade" I dont want to upgrade it but i want my second app to be posted. When i tried to change the package name it showed lots of errors, so i decided to create the app once again in a new package and project name, it seems to be a very lengthy process.... pls help me to solve the issue bcoz i have created all my app in same package name unknowingly.......

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  • How can I use Perl to determine whether the contents of two files are identical?

    - by Zaid
    This question comes from a need to ensure that changes I've made to code doesn't affect the values it outputs to text file. Ideally, I'd roll a sub to take in two filenames and return 1or return 0 depending on whether the contents are identical or not, whitespaces and all. Given that text-processing is Perl's forté, it should be quite easy to compare two files and determine whether they are identical or not (code below untested). use strict; use warnings; sub files_match { my ( $fileA, $fileB ) = @_; open my $file1, '<', $fileA; open my $file2, '<', $fileB; while (my $lineA = <$file1>) { next if $lineA eq <$file2>; return 0 and last; } return 1; } The only way I can think of (sans CPAN modules) is to open the two files in question, and read them in line-by-line until a difference is found. If no difference is found, the files must be identical. But this approach is limited and clumsy. What if the total lines differ in the two files? Should I open and close to determine line count, then re-open to scan the texts? Yuck. I don't see anything in perlfaq5 relating to this. I want to stay away from modules unless they come with the core Perl 5.6.1 distribution.

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  • Converting OpenGL coordinates to lower UIView (and UIImagePickerController)

    - by John Qualis
    I am new to OpenGL on the iPhone. I am developing an iPhone app similar to a barcode reader but with an extra OpenGL layer. The bottommost layer is UIImagePickerController, then I use UIView on top and draw a rectangle at certain coordinates on the iPhone screen. So far everything is OK. Then I am trying to draw an OpenGL 3-D model in that rectangle. I am able to load a 3-D model in the iPhone based on this code here - http://iphonedevelopment.blogspot.com/2008/12/start-of-wavefront-obj-file-loader.html I am not able to transform the coordinates of the rectangle into OpenGL coordinates. Appreciate any help. Do I need to use a matrix to translate the currentPosition of the 3-D model so it is drawn within myRect? The code is given below. -(void)setupView:(GLView*)view { const GLfloat zNear = 0.01, zFar = 1000.0, fieldOfView = 45.0; GLfloat size; glEnable(GL_DEPTH_TEST); glMatrixMode(GL_PROJECTION); size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); CGRect rect = view.bounds; glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glViewport(0, 0, rect.size.width, rect.size.height); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glClearColor(0.0f, 0.0f, 0.0f, 0.0f); NSString *path = [[NSBundle mainBundle] pathForResource:@"plane" ofType:@"obj"]; OpenGLWaveFrontObject *theObject = [[OpenGLWaveFrontObject alloc] initWithPath:path]; Vertex3D position; position.z = -8.0; position.y = 3.0; position.x = 2.0; theObject.currentPosition = position; self.plane = theObject; [theObject release]; } - (void)drawView:(GLView*)view; { static GLfloat rotation = 0.0; glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glLoadIdentity(); glColor4f(0.0, 0.5, 1.0, 1.0); // the coordinates of the rectangle are // myRect.x, myRect.y, myRect.width, myRect.height // Do I need to use a matrix to translate the currentPosition of the // 3-D model so it is drawn within myRect? //glOrthof(-160.0f, 160.0f, -240.0f, 240.0f, -1.0f, 1.0f); [plane drawSelf]; }

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  • Django menu item sorting

    - by doktorno
    Hi i've got MenuItem model : MenuItem(models.Model) name=models.CharField(max_length=50) url = models.URLField() position = models.IntegerField() Class Meta: ordering =['position'] then i'm retriving it by MenuItem.objects.all() My question is how can i make any user friendly interface in admin panel to allow sorting MenuItems - for example list with + and - buttons to move MenuItem up and down ....

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  • How to access image folder in django

    - by anc1revv
    I just started django and i want to access images uploaded by a user. here is my model: class Food(models.Model): name = models.CharField(max_length=100) price = models.DecimalField(max_digits=4, decimal_places=2) quantity = models.IntegerField(blank=True, null=True) description = models.CharField(max_length=200) location = models.CharField(max_length=100) time = models.DateTimeField() photo_thumbnail = models.ImageField(upload_to="images") photo_fullsize = models.ImageField(upload_to="images") i stored the image in the "images" folder below the html is this: img src="{{steak.photo_thumbnail}}" and steak.photo_thumbnail = images/steak_and_egg_thumbnail_1.png here is the error i get: [06/Jul/2012 19:08:24] "GET /menu/ HTTP/1.1" 200 99 [06/Jul/2012 19:08:24] "GET /menu/images/steak_and_egg_thumbnail_1.png HTTP/1.1" 404 2127

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  • rake does not returning anything

    - by CHID
    Hi, I jus created a rails application. I created a model using ruby script/generate model Article next i edited the my articles.rb file by adding these lines in self.up method def self.up create_table :articles do |t| t.string :title t.text :body t.string :published_at t.timestamps end end Now i ran rake db:migrate . But migrate does not work, it simply does no print anything. Anyone knows where i am going wrong?

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  • Serialize the @property methods in a Python class.

    - by ashchristopher
    Is there a way to have any @property definitions passed through to a json serializer when serializing a Django model class? example: class FooBar(object.Model) name = models.CharField(...) @property def foo(self): return "My name is %s" %self.name Want to serialize to: [{ 'name' : 'Test User', 'foo' : 'My name is Test User', },]

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  • JS window.close() let IE hang

    - by p4bl0.666
    Hi all, for reason I won't bore you with, I'm writing an asp.net application that must open some pages in new browser windows. I managed to open them within a postback (don't ask why, I just needed to) with this code: script = String.Format(@"window.open(""{0}"", ""{1}"");", url, target); ScriptManager.RegisterStartupScript(page, typeof(Page), "Redirect", script, true); Now I have new windows each one with a button that should close it. I have simply an onclick="window.close()" (but that prompts me when I'm closing the browser) or window.open('','_self','');window.close() (horrible, I agree but it's the only way I found to avoid the JS prompt) On firefox it works perfectly but on IE7 (the browser our customers have) after 2-3 times I use that button to close the window I can't open other windows (in both cases, with or without the JS prompt). With the method above it does nothing, and with a <a href="mypage.aspx" target="_blank">click me</a> a new window is opened but hangs on loading (it doesn't even calls the Page_Load). What could be the cause? How can I solve this? Thank you.

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  • $this.attr() stops Jquery dialog from opening

    - by user342391
    I am using the following code to post my form data to player/index.php and open it in a dialog. Because I have multiple of these forms in my table I need to use $(this). But now it doesn't open in a dialog. New code (doesn't open dialog but display data in url): $("#recordingdialog").dialog({ //other options, width, height, etc... modal: true, bgiframe: true, autoOpen: false, height: 200, width: 350, draggable: true, resizeable: true, title: "Play Recording",}); $(this).click(function() { $.post('player/index.php', $(this).attr('form').serialize(), function (data) { $("#recordingdialog").html(data).dialog("open"); }); return false; }); Old code (only works on one form): $("#recordingdialog").dialog({ //other options, width, height, etc... modal: true, bgiframe: true, autoOpen: false, height: 550, width: 550, draggable: true, resizeable: true, title: "Play Recording",}); $("#wavajax button").click(function() { $.post('player/index.php', $("#wavajax").serialize(), function (data) { $("#recordingdialog").html(data).dialog("open"); }); return false; });

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  • Response.BinaryWrite calls the ASPX page twice

    - by Jon.ee
    I am trying to open a file in the browser using BinaryWriter. This causes the a dialog window to open and prompt the user to save or open the file. That behavior is fine; however, if I select open, the aspx page is called again and after a long wait the file finally opens. I set the ContentType Response.BinaryWrite(binary); Response.End(); Repsonse.Close(); This behavior only occurs with excel and word files. Browser IE8

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  • Facncybox in Jquery

    - by user319740
    I am using jquery.fancybox-1.2.1.js of fancy box in asp.net application Q1: In the base page i have datagrid and on combobox. on slection of combobox the datagrid is populated. From the datagrid I open the fancybox when user click on Edit link. I open new page like In EditProjectTask.aspx i have the controls in edible mode. Now if user closes the window using default icon provided in fancybox. then if user select some other option from combox the url changes into EditProjectTask?Task= 86 Q2: # From the # datagrid I open the fancybox when user click on Edit link. I open new page like In EditProjectTask.aspx i have the controls in edible mode. Now when user updates the the content I want to close the fancybox and also refresh the parent window. I have achieved this using After update i # But it reloads all the page. Can I use some Ajax call.

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  • Anyone know how you can get a Google dev phone to make Android apps?

    - by Bobafett
    Hi there, I am thinking about converting my web apps into Android apps to reach the Android market. I do not have an Android phone. Can someone tell me how I can possibly get a Google developer phone (other than going to Google I/O, etc)? I realize this is somewhat of a ridiculous request but I have read blogs of people being enticed by google and offered a free phone to convert their web apps into Android apps. So I figure there is no harm in asking. Any insight would be helpful. Thanks I am also wondering what the cost of the developer phone is once you pay your $25 to enter the android market place as a developer through the developer account.

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  • How to save links with tags and parameters in TextField

    - by xRobot
    I have this simple Post model: class Post(models.Model): title = models.CharField(_('title'), max_length=60, blank=True, null=True) body = models.TextField(_('body')) blog = models.ForeignKey(Blog, related_name="posts") user = models.ForeignKey(User) I want that when I insert in the form the links, then these links are saved in the body from this form: http://www.example.com or www.example.com to this form ( with tag and rel="nofollow" parameter ): <a href="http://www.example.com" rel="nofollow">www.example.com</a> How can I do this ? Thanks ^_^

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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • Google App Engine Python Datastore

    - by python appengine
    Basically what Im trying to make is a data structure where it has the users name, id, and datejoined. Then i want a "sub-structure" where it has the users "text" and the date it was modified. and the user will have multiple instances of this text. class User(db.Model): ID = db.IntegerProperty() name = db.StringProperty() datejoined = db.DateTimeProperty(auto_now_add=True) class Content(db.Model): text = db.StringProperty() datemod= db.DateTimeProperty(auto_now_add = True) Is the code set up correctly?

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  • explain this macro

    - by deostroll
    #define __T(x) L ## x Found in code from one of the MFC source header file. It is mostly used for converting strings to ........ (I don't know what). If I am correct it converts strings to LPCTSTR...don't know what that type is either... I can't seem to convert char* into LPCTSTR. While MFC file handling, the following code will always return error while trying to open the file... char* filepath = "C:\\Program Files\\Microsoft Office\\Office12\\BITMAPS\\STYLES\\GLOBE.WMF"; if( !file.Open((LPCTSTR)filepath , CFile::modeRead, &fexp) ) { fexp.ReportError(); return 1; } But instead if I wrote it this way, it doesn't give error: if( !file.Open( _T("C:\\Program Files\\Microsoft Office\\Office12\\BITMAPS\\STYLES\\GLOBE.WMF") , CFile::modeRead, &fexp) ) { fexp.ReportError(); return 1; } I am looking at passing a variable as the first argument to the CFile::Open() method.

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  • Django: Save an uploaded file to a FileField

    - by David Wolever
    I feel a little stupid for having to ask this… But I can't seem find it documented anywhere. If I've got a Model with FileField, how can I stuff an uploaded FILE into that FileField? For example, I'd like to do something like this: class MyModel(Model): file = FileField(...) def handle_post(request, ...): mymodel = MyModel.objects.get(...) if request.FILES.get("newfile"): mymodel.file = request.FILES["newfile"] But that doesn't appear to work.

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  • IntegrityError with Booleand Fields and Postgresql

    - by xRobot
    I have this simple Blog model: class Blog(models.Model): title = models.CharField(_('title'), max_length=60, blank=True, null=True) body = models.TextField(_('body')) user = models.ForeignKey(User) is_public = models.BooleanField(_('is public'), default = True) When I insert a blog in admin interface, I get this error: IntegrityError at /admin/blogs/blog/add/ null value in column "is_public" violates not-null constraint Why ???

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  • update dialog title for each click

    - by Scarface
    Hey guys I have a quick question, I have a dialog box that has multiple links with different attributes. Each time a link is clicked, the attribute src is printed inside of the dialog box so that each link has a unique output in the dialog. My problem is simply that only the first src title is in every box and I would like to change that as well with each click. I separated the line containing title to show the problem. If anyone has any ideas I would appreciate it. <a class="open" src="something" title="Click to play">link</a> <a class="open" src="something else" title="Click to play">link2</a> $('.open').click(function() { src=$(this).attr('src'); $('#show').html(''+src+''); $(\"#show\").dialog({hide: 'clip', width: 400,height: 150,position: 'center', show: 'clip',stack: true,title: ''+src+'', minHeight: 25, minWidth: 100, autoOpen: false,resizable:false}); $('#show').dialog('open'); })

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  • How to do a back-reference on Google AppEngine?

    - by jCuga
    I'm trying to access an object that is linked to by a db.ReferenceProperty in Google app engine. Here's the model's code: class InquiryQuestion(db.Model): inquiry_ref = db.ReferenceProperty(reference_class=GiftInquiry, required=True, collection_name="inquiry_ref") And I am trying to access it in the following way: linkedObject = question.inquiry_ref and then linkedKey = linkedObject.key but it's not working. Can anyone please help?

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