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  • Tying PyQt4 QAction triggered() to local class callable doesn't seem to work. How to debug this?

    - by Jon Watte
    I create this object when I want to create a QAction. I then add this QAction to a menu: class ActionObject(object): def __init__(self, owner, command): action = QtGui.QAction(command.name, owner) self.action = action self.command = command action.setShortcut(command.shortcut) action.setStatusTip(command.name) QtCore.QObject.connect(action, QtCore.SIGNAL('triggered()'), self.triggered) def triggered(self): print("got triggered " + self.command.id + " " + repr(checked)) Unfortunately, when the menu item is selected, the 'triggered' function is not called. QtCore.QObject.connect() returns True. Nothing is printed on the console to indicate that anything is wrong, and no exception is thrown. How can I debug this? (or, what am I doing wrong?)

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  • pyramid traversal resource url no attribute __name__

    - by Santana
    So I have: resources.py: def _add(obj, name, parent): obj.__name__ = name obj.__parent__ = parent return obj class Root(object): __parent__ = __name__ = None def __init__(self, request): super(Root, self).__init__() self.request = request self.collection = request.db.post def __getitem__(self, key): if u'profile' in key: return Profile(self.request) class Profile(dict): def __init__(self, request): super(Profile, self).__init__() self.__name__ = u'profile' self.__parent__ = Root self.collection = request.db.posts def __getitem__(self, name): post = Dummy(self.collection.find_one(dict(username=name))) return _add(post, name, self) and I'm using MongoDB and pyramid_mongodb views.py: @view_config(context = Profile, renderer = 'templates/mytemplate.pt') def test_view(request): return {} and in mytemplate.pt: <p tal:repeat='item request.context'> ${item} </p> I can echo what's in the database (I'm using mongodb), but when I provided a URL for each item using resource_url() <p tal:repeat='item request.context'> <a href='${request.resource_url(item)}'>${item}</a> </p> I got an error: 'dict' object has no attribute '__name__', can someone help me?

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  • Problems using User model in django unit tests

    - by theycallmemorty
    I have the following django test case that is giving me errors: class MyTesting(unittest.TestCase): def setUp(self): self.u1 = User.objects.create(username='user1') self.up1 = UserProfile.objects.create(user=self.u1) def testA(self): ... def testB(self): ... When I run my tests, testA will pass sucessfully but before testB starts, I get the following error: IntegrityError: column username is not unique It's clear that it is trying to create self.u1 before each test case and finding that it already exists in the Database. How do I get it to properly clean up after each test case so that subsequent cases run correctly?

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  • Encoding with url and api

    - by user2950824
    So I have this web app set up and running and it works fine for any username that you request, but when i try http://mrcastelo.pythonanywhere.com/lol/euw/Nazaré, it simply doesnt work - the error that I get on the server is the following: iddata= getJSON(urllolbase+region+urlid+username) #SummonerID UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 5: ordinal not in range(128) It is annoying me greatly, I've tried some other threads but none of them came to a fix. The api that I am using (www.legendaryapi.com) does accept this because this works. Any idea on how to fix this?

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  • passing self data into a recursive function

    - by user272689
    I'm trying to set a function to do something like this def __binaryTreeInsert(self, toInsert, currentNode=getRoot(), parentNode=None): where current node starts as root, and then we change it to a different node in the method and recursivly call it again. However, i cannot get the 'currentNode=getRoot()' to work. If i try calling the funcion getRoot() (as above) it says im not giving it all the required variables, but if i try to call self.getRoot() it complains that self is an undefined variable. Is there a way i can do this without having to specify the root while calling this method?

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  • Validation on ManyToManyField before Save in Models.py

    - by Heyl1
    I have the following models: class Application(models.Model): users = models.ManyToManyField(User, through='Permission') folder = models.ForeignKey(Folder) class Folder(models.Model): company = models.ManyToManyField(Compnay) class UserProfile(models.Model): user = models.OneToOneField(User, related_name='profile') company = models.ManyToManyField(Company) What I would like to do is to check whether one of the users of the Application has the same company as the Application (via Folder). If this is the case the Application instance should not be saved. The problem is that the ManyToManyFields aren't updated until after the 'post-save' signal. The only option seems to be the new m2m_changed signal. But I'm not sure how I then roll back the save that has already happened. Another option would be to rewrite the save function (in models.py, because I'm talking about the admin here), but I'm not sure how I could access the manytomanyfield content. Finally I've read something about rewriting the save function in the admin of the model in admin.py, however I still wouldn't know how you would access the manytomanyfield content. I have been searching for this everywhere but nothing I come across seems to work for me. If anything is unclear, please tell me. Thanks for your help! Heleen

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  • Django complex queries

    - by Josh K
    I need to craft a filter for an object that checks date ranges. Right now I'm performing a very inefficient loop which checks all the objects. I would like to simplify this to a database call. The logic is you have a start and an end date objects. I need to check if the start OR the end is within the range of an appointment. if (start >= appointment.start && start < appointment.end) || (end > appointment.start && end <= appointment.end) I could do this in SQL, but I'm not as familiar with the Django model structure for more complex queries.

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  • Update Facebook Page's status using pyfacebook

    - by thornomad
    I am attempting to add functionality to my Django app: when a new post is approved, I want to update the corresponding Facebook Page's status with a message and a link to the post automatically. Basic status update. I have downloaded and installed pyfacebook - and I have read through the tutorial from Facebook. I have also seen this suggestion here on SO: import facebook fb = facebook.Facebook('YOUR_API_KEY', 'YOUR_SECRET_KEY') fb.auth.createToken() fb.login() # THIS IS AS FAR AS I CAN GET fb.auth.getSession() fb.set_status('Checking out StackOverFlow.com') When I get to the login() call, however, pyfacebook tries to open lynx so I can login to Facebook 'via the web' -- this is, obviously, not going to work for me because the system is supposed to be automated ... I've been looking, but can't find out how I can keep this all working with the script and not having to login via a web browser. Any ideas?

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  • Sort a list of dicts by dict values

    - by ensnare
    I have a list of dictionaries: [{'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}, {'title':'Apple News','title_url':'Apple_News','id':2}] I'd like to sort it by the title, so elements with A go before Z: [{'title':'Apple News','title_url':'Apple_News','id':2}, {'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}] What's the best way to do this? Also, is there a way to ensure the order of each dictionary key stays constant, e.g., always title, title_url, then id? Thank you.

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  • pandas read rotated csv files

    - by EricCoding
    Is there any function in pandas that can directly read a rotated csv file? To be specific, the header information in the first col instead of the first row. For example: A 1 2 B 3 5 C 6 7 and I would like the final DataFrame this way A B C 1 3 5 2 5 7 Of corse we can get around this problem using some data wangling techniques like transpose and slicing. I am wondering there should be a quick way in API but I could not find it.

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  • Django: Update order attribute for objects in a queryset

    - by lazerscience
    I'm having a attribute on my model to allow the user to order the objects. I have to update the element's order depending on a list, that contains the object's ids in the new order; right now I'm iterating over the whole queryset and set one objects after the other. What would be the easiest/fastest way to do the same with the whole queryset? def update_ordering(model, order): """ order is in the form [id,id,id,id] for example: [8,4,5,1,3] """ id_to_order = dict((order[i], i) for i in range(len(order))) for x in model.objects.all(): x.order = id_to_order[x.id] x.save()

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  • django test client trouble

    - by Anton Koval'
    I've got a problem... we're writing project using django, and i'm trying to use django.test.client with nose test-framework for tests. Our code is like this: from simplejson import loads from urlparse import urljoin from django.test.client import Client TEST_URL = "http://smakly.localhost:9090/" def test_register(): cln = Client() ref_data = {"email": "[email protected]", "name": "???????", "website": "http://hot.bear.com", "xhr": "true"} print urljoin(TEST_URL, "/accounts/register/") response = loads(cln.post(urljoin(TEST_URL, "/accounts/register/"), ref_data)) print response["message"] and in nose output I catch: Traceback (most recent call last): File "/home/psih/work/svn/smakly/eggs/nose-0.11.1-py2.6.egg/nose/case.py", line 183, in runTest self.test(*self.arg) File "/home/psih/work/svn/smakly/src/smakly.tests/smakly/tests/frontend/test_profile.py", line 25, in test_register response = loads(cln.post(urljoin(TEST_URL, "/accounts/register/"), ref_data)) File "/home/psih/work/svn/smakly/parts/django/django/test/client.py", line 313, in post response = self.request(**r) File "/home/psih/work/svn/smakly/parts/django/django/test/client.py", line 225, in request response = self.handler(environ) File "/home/psih/work/svn/smakly/parts/django/django/test/client.py", line 69, in __call__ response = self.get_response(request) File "/home/psih/work/svn/smakly/parts/django/django/core/handlers/base.py", line 78, in get_response urlconf = getattr(request, "urlconf", settings.ROOT_URLCONF) File "/home/psih/work/svn/smakly/parts/django/django/utils/functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'ROOT_URLCONF' My settings.py file does have this attribute. If I get the data from the server with standard urllib2.urllopen().read() it works in the proper way. Any ideas how I can solve this case?

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  • How to get the related_name of a many-to-many-field?

    - by amann
    I am trying to get the related_name of a many-to-many-field. The m2m-field is located betweeen the models "Group" and "Lection" and is declared in the group-model as following: lections = models.ManyToManyField(Lection, blank=True) The field looks like this: <django.db.models.fields.related.ManyToManyField object at 0x012AD690> The print of field.__dict__ is: {'_choices': [], '_m2m_column_cache': 'group_id', '_m2m_name_cache': 'group', '_m2m_reverse_column_cache': 'lection_id', '_m2m_reverse_name_cache': 'lection', '_unique': False, 'attname': 'lections', 'auto_created': False, 'blank': True, 'column': 'lections', 'creation_counter': 71, 'db_column': None, 'db_index': False, 'db_table': None, 'db_tablespace': '', 'default': <class django.db.models.fields.NOT_PROVIDED at 0x00FC8780>, 'editable': True, 'error_messages': {'blank': <django.utils.functional.__proxy__ object at 0x00FC 7B50>, 'invalid_choice': <django.utils.functional.__proxy__ object at 0x00FC7A50>, 'null': <django.utils.functional.__proxy__ object at 0x00FC7 A70>}, 'help_text': <django.utils.functional.__proxy__ object at 0x012AD6F0>, 'm2m_column_name': <function _curried at 0x012A88F0>, 'm2m_db_table': <function _curried at 0x012A8AF0>, 'm2m_field_name': <function _curried at 0x012A8970>, 'm2m_reverse_field_name': <function _curried at 0x012A89B0>, 'm2m_reverse_name': <function _curried at 0x012A8930>, 'max_length': None, 'name': 'lections', 'null': False, 'primary_key': False, 'rel': <django.db.models.fields.related.ManyToManyRel object at 0x012AD6B0>, 'related': <RelatedObject: mymodel:group related to lections>, 'related_query_name': <function _curried at 0x012A8670>, 'serialize': True, 'unique_for_date': None, 'unique_for_month': None, 'unique_for_year': None, 'validators': [], 'verbose_name': 'lections'} Now the field should be accessed via a lection-instance. So this is done by lection.group_set But i need to access it dynamically, so there is the need to get the related_name attribute from somewhere. Here in the documentation, there is a note that it is possible to access ManyToManyField.related_name, but this doesn't work for my somehow.. Help would be a lot appreciated. Thanks in advance.

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  • differences between "d.clear()" and "d={}"

    - by Tshepang
    On my machine, the execution speed between "d.clear()" and "d={}" is over 100ns so am curious why one would use one over the other. import timeit def timing(): d = dict() if __name__=='__main__': t = timeit.Timer('timing()', 'from __main__ import timing') print t.repeat()

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  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

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  • My QFileSystemModel doesn't work as expected in PyQt

    - by Skilldrick
    I'm learning the Qt Model/View architecture at the moment, and I've found something that doesn't work as I'd expect it to. I've got the following code (adapted from Qt Model Classes): from PyQt4 import QtCore, QtGui model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) #prints True print model.data(parentIndex).toString() #prints name of current directory childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows #prints 0 (even though the current directory has directory and file children) The question: Is this a problem with PyQt, have I just done something wrong, or am I completely misunderstanding QFileSystemModel? According to the documentation, model.rowCount(parentIndex) should return the number of children in the current directory. The QFileSystemModel docs say that it needs an instance of a Gui application, so I've also placed the above code in a QWidget as follows, but with the same result: import sys from PyQt4 import QtCore, QtGui class Widget(QtGui.QWidget): def __init__(self, parent=None): QtGui.QWidget.__init__(self, parent) model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) print model.data(parentIndex).toString() childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows def main(): app = QtGui.QApplication(sys.argv) widget = Widget() widget.show() sys.exit(app.exec_()) if __name__ == '__main__': main()

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  • How to update Geo-Location in fireeagle

    - by Ganesh
    Hi Every One, I am developing an application on fireeagle, there i need to update the users exact location, with out asking any information from the user (i.e) lat, long e.t.c., If it is not possible using yahoo fireeagle, please let me know if there exists any other api's other than yahoo fireeagle. If they can get the exact location of web user in 'Lat' and 'Long', either from 'Pc' or from 'Mobile' browser. Thanks in advance.

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