Search Results

Search found 15224 results on 609 pages for 'parallel python'.

Page 399/609 | < Previous Page | 395 396 397 398 399 400 401 402 403 404 405 406  | Next Page >

  • How to get a template tag to auto-check a checkbox in Django

    - by Daniel Quinn
    I'm using a ModelForm class to generate a bunch of checkboxes for a ManyToManyField but I've run into one problem: while the default behaviour automatically checks the appropriate boxes (when I'm editing an object), I can't figure out how to get that information in my own custom templatetag. Here's what I've got in my model: ... from django.forms import CheckboxSelectMultiple, ModelMultipleChoiceField interests = ModelMultipleChoiceField(widget=CheckboxSelectMultiple(), queryset=Interest.objects.all(), required=False) ... And here's my templatetag: @register.filter def alignboxes(boxes, cls): """ Details on how this works can be found here: http://docs.djangoproject.com/en/1.1/howto/custom-template-tags/ """ r = "" i = 0 for box in boxes.field.choices.queryset: r += "<label for=\"id_%s_%d\" class=\"%s\"><input type=\"checkbox\" name=\"%s\" value=\"%s\" id=\"id_%s_%d\" /> %s</label>\n" % ( boxes.name, i, cls, boxes.name, box.id, boxes.name, i, box.name ) i = i + 1 return mark_safe(r) The thing is, I'm only doing this so I can wrap some simpler markup around these boxes, so if someone knows how to make that happen in an easier way, I'm all ears. I'd be happy with knowing a way to access whether or not a box should be checked though.

    Read the article

  • Can pydoc/help hide the documentation for inherited class methods and attributes?

    - by EOL
    When declaring a class that inherits from a specific class: class C(dict): added_attribute = 0 the documentation for C lists all the methods of dict (either through help(C) or pydoc). Is there a way to hide the inherited methods from the automatically generated documentation (the documentation string can refer to the base class, for non-overwritten methods)? This would be useful: pydoc lists the functions defined in a module after its classes. Thus, when the classes have a very long documentation, a lot of less than useful information is printed before the new functions provided by the module are presented, which makes the documentation harder to exploit (you have to skip all the documentation for the inherited methods until you reach something specific to the module being documented).

    Read the article

  • How to bind a double precision using psycopg2

    - by user337636
    I'm trying to bind a float to a postgresql double precision using psycopg2. ele = 1.0/3.0 dic = {'name': 'test', 'ele': ele} sql = '''insert into waypoints (name, elevation) values (%(name)s, %(ele)s)''' cur = db.cursor() cur.execute(sql, dic) db.commit() sql = """select elevation from waypoints where name = 'test'""" cur.execute(sql_out) ele_out = cur.fetchone()[0] ele_out 0.33333333333300003 ele 0.33333333333333331 Obviously I don't need the precision, but I would like to be able to simply compare the values. I could use the struct module and save it as a string, but thought there should be a better way. Thanks

    Read the article

  • How do I compare two complex data structures?

    - by Phil H
    I have some nested datastructures, each something like: [ ('foo', [ {'a':1, 'b':2}, {'a':3.3, 'b':7} ]), ('bar', [ {'a':4, 'd':'efg', 'e':False} ]) ] I need to compare these structures, to see if there are any differences. Short of writing a function to explicitly walk the structure, is there an existing library or method of doing this kind of recursive comparison?

    Read the article

  • mount command pid

    - by lakshmipathi
    Trying to mount a device and get the pid of mount command. cmd="/bin/mount /dev/sda1 /mnt" os.system(cmd) Now how to obtain the pid of mount command? There plenty of mounted device available on my system ,something like ps | grep mount won't work.

    Read the article

  • List all form related errors in django

    - by Mridang Agarwalla
    Hi, Is there a direct way of listing out 'all' form errors in Django templates. I'd like to list out both field and non-field errors and any other form errors. I've found out how to do this on a per-field basis but as said earlier, I'd like to list out everything. The method I'm using doesn't seem to list out everything. {% for error in form.errors %} {{ error|escape }} {% endfor %} Thanks.

    Read the article

  • Django - urls.py - Filenames with a hash/pound (#) sign?

    - by miya
    I'm using django and realized that when the filename that the user wants to access (let's say a photo) has the pound sign, the entry in the url.py does not match. Any ideas? url(r'^static/(?P<path>.*)$', 'django.views.static.serve', {'document_root': MEDIA_ROOT}, it just says: "/home/user/project/static/upload/images/hello" does not exist when actually the name of the file is: hello#world.jpg Thanks, Nico

    Read the article

  • Sort a list of dicts by dict values

    - by ensnare
    I have a list of dictionaries: [{'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}, {'title':'Apple News','title_url':'Apple_News','id':2}] I'd like to sort it by the title, so elements with A go before Z: [{'title':'Apple News','title_url':'Apple_News','id':2}, {'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}] What's the best way to do this? Also, is there a way to ensure the order of each dictionary key stays constant, e.g., always title, title_url, then id? Thank you.

    Read the article

  • some register.inclusion_tag error in my code using django

    - by zjm1126
    my helloworld_tags: from django import template register = template.Library() def show_profile(): return {"eee": '333'} register.inclusion_tag("b.html")(show_profile) my view: def b(request): return render_to_response('b.html') my html: {% load helloworld_tags%} dsad {{ eee }} but only show 'dsad' ,not show 'dsad333' why?? thanks

    Read the article

  • Removing the port number from URL

    - by DrewSSP
    I'm new to anything related to servers and am trying to deploy a django application. Today I bought a domain name for the app and am having trouble configuring it so that the base URL does not need the port number at the end of it. I have to type www.trackthecharts.com:8001 to see the website when I only want to use www.trackethecharts.com. I think the problem is somewhere in my nginx, gunicorn or supervisor configuration. gunicorn_config.py command = '/opt/myenv/bin/gunicorn' pythonpath = '/opt/myenv/top-chart-app/' bind = '162.243.76.202:8001' workers = 3 root@django-app:~# nginx config server { server_name 162.243.76.202; access_log off; location /static/ { alias /opt/myenv/static/; } location / { proxy_pass http://127.0.0.1:8001; proxy_set_header X-Forwarded-Host $server_name; proxy_set_header X-Real-IP $remote_addr; add_header P3P 'CP="ALL DSP COR PSAa PSDa OUR NOR ONL UNI COM NAV"'; } } supervisor config [program:top_chart_gunicorn] command=/opt/myenv/bin/gunicorn -c /opt/myenv/gunicorn_config.py djangoTopChartApp.wsgi autostart=true autorestart=true stderr_logfile=/var/log/supervisor_gunicorn.err.log stdout_logfile=/var/log/supervisor_gunicorn.out.log Thanks for taking a look.

    Read the article

  • Writing a post search algorithm.

    - by MdaG
    I'm trying to write a free text search algorithm for finding specific posts on a wall (similar kind of wall as Facebook uses). A user is suppose to be able to write some words in a search field and get hits on posts that contain the words; with the best match on top and then other posts in decreasing order according to match score. I'm using the edit distance (Levenshtein) "e(x, y) = e" to calculate the score for each post when compared to the query word "x" and post word "y" according to: score(x, y) = 2^(2 - e)(1 - min(e, |x|) / |x|) Each word in a post contributes to the total score for that specific post. This approach seems to work well when the posts are of roughly the same size, but sometime certain large posts manages to rack up score solely on having a lot of words in them while in practice not being relevant to the query. Am I approaching this problem in the wrong way or is there some way to normalize the score that I haven't thought of?

    Read the article

  • Adding a child node to a JSON node dynamically

    - by Sai
    I have to create a nested multi level json depending on the resultset that I get from MYSQL. I created a json object initially. Now I want to add child nodes to the already child nodes in the object. d = collections.OrderedDict() jsonobj = {"test": dict(updated_at="today", ID="ID", ads=[])} for rows1 in rs: jsonobj['list']["ads"].append(dict(unit = "1", type ="ad_type", id ="123", updated_at="today", x_id="111", x_name="test")) cur.execute("SELECT * from f_test") rs1 = cur.fetchall() for rows2 in rs1: propertiesObj = [] d["name"]="propName" d["type"]="TypeName" d["value"]="Value1" propertiesObj.append(d) jsonobj['play_list']["ads"].append() Here in the above line I want to add another child node to [play_list].[ads] which is a array list again. the output should look like the following [list].[ads].[preferences].

    Read the article

  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

    Read the article

  • Query for model by key

    - by Jason Hall
    What I'm trying to do is query the datastore for a model where the key is not the key of an object I already have. Here's some code: class User(db.Model): partner = db.SelfReferenceProperty() def text_message(self, msg): user = User.get_or_insert(msg.sender) if not user.partner: # user doesn't have a partner, find them one # BUG: this line returns 'user' himself... :( other = db.Query(User).filter('partner =', None).get() if other: # connect users else: # no one to connect to! The idea is to find another User who doesn't have a partner, that isn't the User we already know. I've tried filter('key !=, user.key()), filter('__key__ !=, user.key()) and a couple others, and nothing returns another User who doesn't have a partner. filter('foo !=, user.key()) also returns nothing, for the record.

    Read the article

  • Inlines in Django Admin

    - by Oli
    I have two models, Order and UserProfile. Each Order has a ForeignKey to UserProfile, to associate it with that user. On the django admin page for each Order, I'd like to display the UserProfile associated with it, for easy processing of information. I have tried inlines: class UserInline(admin.TabularInline): model = UserProfile class ValuationRequestAdmin(admin.ModelAdmin): list_display = ('address1', 'address2', 'town', 'date_added') list_filter = ('town', 'date_added') ordering = ('-date_updated',) inlines = [ UserInline, ] But it complains that UserProfile "has no ForeignKey to" Order - which it doesn't, it's the other way around. Is there a way to do what I want?

    Read the article

  • PyParsing: Is this correct use of setParseAction()?

    - by Rosarch
    I have strings like this: "MSE 2110, 3030, 4102" I would like to output: [("MSE", 2110), ("MSE", 3030), ("MSE", 4102)] This is my way of going about it, although I haven't quite gotten it yet: def makeCourseList(str, location, tokens): print "before: %s" % tokens for index, course_number in enumerate(tokens[1:]): tokens[index + 1] = (tokens[0][0], course_number) print "after: %s" % tokens course = Group(DEPT_CODE + COURSE_NUMBER) # .setResultsName("Course") course_data = (course + ZeroOrMore(Suppress(',') + COURSE_NUMBER)).setParseAction(makeCourseList) This outputs: >>> course.parseString("CS 2110") ([(['CS', 2110], {})], {}) >>> course_data.parseString("CS 2110, 4301, 2123, 1110") before: [['CS', 2110], 4301, 2123, 1110] after: [['CS', 2110], ('CS', 4301), ('CS', 2123), ('CS', 1110)] ([(['CS', 2110], {}), ('CS', 4301), ('CS', 2123), ('CS', 1110)], {}) Is this the right way to do it, or am I totally off? Also, the output of isn't quite correct - I want course_data to emit a list of course symbols that are in the same format as each other. Right now, the first course is different from the others. (It has a {}, whereas the others don't.)

    Read the article

  • Function for averages of tuples in a dictionary

    - by Billy Mann
    I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

    Read the article

  • Histogram in Matplotlib with input file

    - by Arkapravo
    I wish to make a Histogram in Matplotlib from an input file containing the raw data (.txt). I am facing issues in referring to the input file. I guess it should be a rather small program. Any Matplotlib gurus, any help ? I am not asking for the code, some inputs should put me on the right way !

    Read the article

  • Wordpress & Django -- One domain, two servers. Possible?

    - by DomoDomo
    My question is about hosting Django and Wordpress under one domain, but two physical machines (actually, they are VMs but same diff). Let's say I have a Django webapp at example.com. I'd like to start a Wordpress blog about my webapp, so any blog page rank mojo flows back to my webapp, I'd like the blog address t be example.com/blog. My understanding is blog.example.com would not transfer said page rank mojo. Because I'm worried about Wordpress security flaws compromising my Django webapp, I want to host Django and Wordpress on two physically separate machines. Given all that, is it possible using re-write rules or a reverse proxy server to do this? I know the easy way is to make my Wordpress blog a subdomain, but I really don't want to do that. Has anyone done this in the past, is it stable? If I need a third server to be a dedicated reverse proxy, that's totally fine. Thanks!

    Read the article

< Previous Page | 395 396 397 398 399 400 401 402 403 404 405 406  | Next Page >