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  • Kernel error causing cpu to go into shutdown state

    - by EpsilonVector
    What kind of Kernel error can cause the cpu to go into a shut down state? I'm doing a homework assignment in OS, and we did changes in sched.c (adding a new scheduling policy, which involved ading another prio_array to the queue and switching between them when needed). Processes using this policy cause the cpu to enter a shut down state when they finish. Any suggestions where to look?

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  • JAVA: Can't get context parameters in Filter

    - by DaTval
    Hello, I have a filter and parameters in web.xml web.xml is like this: <filter> <description> </description> <display-name>AllClassFilter</display-name> <filter-name>AllClassFilter</filter-name> <filter-class>com.datval.homework.AllClassFilter</filter-class> <init-param> <param-name>DB_URL</param-name> <param-value>jdbc:derby:C:/Users/admin/workspace/homework03/homework/databases/StudentsDB;create=true</param-value> </init-param> <init-param> <param-name>DB_DIALECT</param-name> <param-value>org.hibernate.dialect.DerbyDialect</param-value> </init-param> <init-param> <param-name>DB_DRIVER</param-name> <param-value>org.apache.derby.jdbc.EmbeddedDriver</param-value> </init-param> </filter> mapping is working well. But I can't get this parameters in my filter. public void init(FilterConfig config) throws ServletException { // TODO Auto-generated method stub debugMessage = config.getInitParameter("debugMessage"); ctx = config.getServletContext(); } public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { // TODO Auto-generated method stub // place your code here ctx.log("Start - " + debugMessage); String myDbUrl = ctx.getInitParameter("DB_URL"); String DB_DIALECT = ctx.getInitParameter("DB_DIALECT"); String DB_DRIVER = ctx.getInitParameter("DB_DRIVER"); Map<String,String> pr = new HashMap<String,String>(); pr.put("hibernate.connection.url", myDbUrl); pr.put("hibernate.dialect", DB_DIALECT); pr.put("hibernate.connection.driver_class", DB_DRIVER); EntityManagerFactory emf = Persistence.createEntityManagerFactory("students",pr); EntityManager em = emf.createEntityManager(); request.setAttribute("em", em); chain.doFilter(request, response); em.close(); ctx.log("end - " + debugMessage); } I have checked and myDbUrl is null. What I'm doing wrong? Any idea? Sorry about code, I will change it later :)

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  • System loops using non-integers?

    - by mary
    I wrote a .sh file to compile and run a few programs for a homework assignment. I have a "for" loop in the script, but it won't work unless I use only integers: #!/bin/bash for (( i=10; i<=100000; i+=100)) do ./hw3_2_2 $i done The variable $i is an input for the program hw3_2_2, and I have non-integer values I'd like to use. How could I loop through running the code with a list of decimal numbers?

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  • muti user dungeon help

    - by mudman
    ive created a single user dungeon which i would like to create into a multi user dungoen so at least two plays can play how would i do that what code do i need to add can anyone help? i would show coding but if i do then everyone would see it and all my work will be copied as i know other students do use this site to so plz understand my situation and yes this is a homework/assignment work.

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  • Subset Problem -- Any Materials?

    - by bobber205
    Yes this is a homework/lab assignment. I am interesting in coming up with/finding an algorithm (I can comprehend :P) for using "backtracking" to solve the subset sum problem. Anyone have some helpful resources? I've spent the last hour or so Googling with not much like finding something I think I could actually use. xD Thanks SO!

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  • Preventing threads from writing to the same file

    - by EpsilonVector
    I'm implementing an FTP-like protocol in Linux kernel 2.4 (homework), and I was under the impression that if a file is open for writing any subsequent attempt to open it by another thread should fail, until I actually tried it and discovered it goes through. How do I prevent this from happening? PS: I'm using open() to open the file.

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  • C++ Why isn't call by reference needed for strcpy()

    - by Ribbs
    I have a homework assignment with a number of questions. One is asking why the strcpy() function doesn't need the call by reference operator for CStrings. I've looked through the book numerous times and I can't, for the life of me, find the answer. Can anyone help explain this to me? It is an array of sorts so I would think you would need the call by reference.

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  • Write failed, errno 0

    - by EpsilonVector
    I have a client server situation in which I receive data using read(socket, char_buf, BUF_SIZE) and then try to write it into a log file using write(filefd, char_buf, strlen(char_buf)) Strangely enough this fails (write returns -1), and yet the errno is set to 0, and I can print the message, AND the log file descriptor works (I write to it before and after this command). What's going on?? (Working on Linux kernel 2.4 (homework))

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  • ZigBee Maximum Bandwidth

    - by Kris
    What is the maximum rated bandwidth for ZigBee? I can't seem to find this information anywhere, not even on the ZigBee Alliance website at http://www.zigbee.org/ I did find some information elsewhere, but it dated back to 2004, so I'm guessing it's different now that it was 5 years ago. Thanks!

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  • Which subnet masks are valid for a subnetted Class B address?

    - by Daddy Warbox
    Yes, this is a school question, and yes I already know the correct possible answers (supposedly), so I'm not going to bother posting them. Instead, I just want to understand the meaning of this question. I know what class B addresses are, and what valid class B subnet addresses are. I guess one way to define my question is to ask why the answer "255.255.0.0" is wrong, necessarily? That seems to defy my understanding, or else some part of my brain is just not registering the question correctly. Thanks in advance.

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  • Linux bash: when to use egrep instead of grep?

    - by Michael Mao
    Hi all : I am preparing for a Linux terminal assessment now, I tried to Google and found most resources are referring to the basic "grep" rather than the more powerful "egrep" -- well, that is at least what the professor said in lecture. I am always working with small samples so performance tuning is a thing too far away. So basically I'd like to know are there any areas where I must switch to egrep to do it in a better way? Is it safe to work with basic "grep" as for now? will there be potential risks? Sorry about my limited knowledge on Linux shell commands, the man page looks like a maze to me and honestly I haven't put much time in understanding all the features both command provide.

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  • retransmission of lost TCP segment

    - by tcpip
    What will happen in the following scenario (assume the connection is already established): (stack A) send 10 byte data (stack B) send ACK for 10 byte data (stack B) send 200 byte data (stack B) send 100 byte data (stack B) send 50 byte data (stack A) send ACK for 350 byte data and also send 70 bytes data This segment gets lost and does not reach machine B. (stack B) retransmit 200 byte data (step 3) (stack A) send ACK for 200 byte data and the next expected seq number as the one for 70 bytes data Question: Should 70 bytes data be also transferred with the ACK in step 8? Note that the retransmission timer for step 6 has not expired yet.

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  • How do I configure DFS replication using the command line?

    - by zneak
    Hello everyone, I'm in the process of making a script to automate DFS creation and replication for an exam I have next week. So, assuming I have a namespace: dfsutil root adddom \\Foo\bar 'My namespace' And I have a link: dfsutil link add \\Foo\Bar\CoolStuff \\Server2\CoolStuff 'Neat stuff' How can I use the command line to replicate \\Server2\CoolStuff over, say, \\Server3\CoolStuff? When I use dfscmd: dfscmd /add \\Foo\Bar\CoolStuff \\Server3\CoolStuff It says it ended correctly, but opening up the MMC shows that there are no replication groups for CoolStuff. Thanks!

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  • Word document can not open on user's system

    - by Malyadri
    I try to open a word document in my web application. It opens fine on localhost, but now I am publishing my web application on a server. Users that access the published web application (like http://10.0.23.57/StandardOperatingProcedure/Default.aspx) can not open the word document on their system. winword.exe opens on the server but can not open the word document. Access my system to author systems also same problem is coming. (Word document does not open on user's system. The word instance opens on my system.)

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  • hard drive sectors vs. tracks

    - by Phenom
    In one rotation, how many sectors are passed over and how many tracks are passed over? If you know the average value of sectors per track for a hard drive, how do you use this to estimate the number of cylinders? Do all modern hard drives have 63 sectors per track? Are there any hard drives that have more than this?

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  • maximum size filesystem on my test .... approach?

    - by jocco
    Hello all I'm new at the site, and I have a question. I got this question at a test and really like to know the correct approach to solving this problem? Here is the question. In an indexed filesystem the first indexblock (inode) has 12 direct pointers and 1 pointer to an indirect indexblock. The filesystem is implemented on a disk with a diskblock-size of 1024 bytes. All pointers are 32 bit. Question: what is the maximum filesize (Kilobytes) of this filesystem? If it's possible not an just an answer but an explanation. edit: It was a multiple choice btw with 4 answers a. 13 K b. 268 K c. 524 K d. 1036 K As for my approach I only got as far as to know that 1 pointer is 32 bit Also I found something else here on the site which seems very usefull. http://stackoverflow.com/questions/2755006/understanding-the-concept-of-inodes Ok i got this far There are 12 blocks and each block is 1024 bytes. 1024 * 12 = 12288 bytes or 12 KB directly accessible. Please correct me if I'm wrong. Each pointer is 32 Bit = 4Byte And to be honest at this point I'm starting to get confused especially since my answer is way over any of my multiple choice answers.

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  • jQuery to add vertical scroll bar for a fixed height div container

    - by Michael Mao
    Hi all: This is uni homework so sorry about :my password protected url Please enter usersame as "uts" and password as "10479475", without the wrapper quotes. It it almost completed, please follow simple steps to see where my problem dwells: step1: click on any continent highlighted on world map; step2: click on any city marked on continent map; step3: enter quantity ranging from 1 to 6 into the upper-right table; step4 : there you go, in the table below, once row is equal or greater than 3, then the size of table starts to "overlap" on top of the footer section and continues to grow, which is not what I want. I want to achieve the effect that the table size has a limited max-height, so once actual height exceeds the threshold, then I can have a vertical scroll bar so to "stack up" my table and not to break the overall structure. It turns out that my lazy initial design now gets myself stuck in a problem... Any suggestion and hint on how to get this?

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  • Write a function that compares two strings and returns a third string containing only the letters th

    - by Pritam
    Hi All, I got this homework. And have solved it in following way. I need your comments whether it is a good approach or I need to use any other data sturcture to solve it in better way. public string ReturnCommon(string firstString, string scndString) { StringBuilder newStb = new StringBuilder(); if (firstString != null && scndString != null) { foreach (char ichar in firstString) { if (!newStb.ToString().Contains(ichar) && scndString.Contains(ichar)) newStb.Append(ichar); } } return newStb.ToString(); }

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  • C Programming - Convert an integer to binary

    - by leo
    Hi guys - i was hopefully after some tips opposed to solutions as this is homework and i want to solve it myself I am firstly very new to C. In fact i have never done any before, though i have previous java experience from modules at university. I am trying to write a programme that converts a single integer in to binary. I am only allowed to use bitwise operations and no library functions Can anyone possibly suggest some ideas about how i would go about doing this. Obviously i dont want code or anything, just some ideas as to what avenues to explore as currenty i am a little confused and have no plan of attack. Well, make that a lot confused :D thanks very much

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  • Help me finish this Python 3.x self-challenge.

    - by Hamish Grubijan
    This is not a homework. I saw this article praising Linq library and how great it is for doing combinatorics stuff, and I thought to myself: Python can do it in a more readable fashion. After half hour of dabbing with Python I failed. Please finish where I left off. Also, do it in the most Pythonic and efficient way possible please. from itertools import permutations from operator import mul from functools import reduce glob_lst = [] def divisible(n): return (sum(j*10^i for i,j in enumerate(reversed(glob_lst))) % n == 0) oneToNine = list(range(1, 10)) twoToNine = oneToNine[1:] for perm in permutations(oneToNine, 9): for n in twoToNine: glob_lst = perm[1:n] #print(glob_lst) if not divisible(n): continue else: # Is invoked if the loop succeeds # So, we found the number print(perm) Thanks!

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  • Help me finish this Python self-challenge.

    - by Hamish Grubijan
    This is not a homework. I saw this article praising Linq library and how great it is for doing combinatorics stuff, and I thought to myself: Python can do it in a more readable fashion. After half hour of dabbing with Python I failed. Please finish where I left off. Also, do it in the most Pythonic and efficient way possible please. from itertools import permutations from operator import mul from functools import reduce glob_lst = [] def divisible(n): return (sum(j*10^i for i,j in enumerate(reversed(glob_lst))) % n == 0) oneToNine = list(range(1, 10)) twoToNine = oneToNine[1:] for perm in permutations(oneToNine, 9): for n in twoToNine: glob_lst = perm[1:n] #print(glob_lst) if not divisible(n): continue else: # Is invoked if the loop succeeds # So, we found the number print(perm) Thanks!

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