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  • How do I share files with someone who does not have a ubuntu one account

    - by Bob
    I tried to search for an answer, except that, uhhh there is no search. I want to share a Ubuntu One folder with people who do not have a Ubuntu One account. Is that possible? I found this answer in the faq, "Yes! Since Ubuntu 10.04 LTS, Ubuntu One supports sharing files publicly. Right click on a file already synchronized by Ubuntu One and select "Publish via Ubuntu One". Right-click on the file again and select "Copy Ubuntu One public URL". You can now paste the URL and share it with whoever you want." That doesn't seem to help me with 11.04. There is no 'Publish via Ubuntu One' button in 11.04. Does anyone know if there is a way to share files with non-ubuntu users? If so, how? Thanks In Advance, Bob

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  • SQLUniversity Professional Development Week: Learning To Fly

    - by andyleonard
    Introduction Clem and Jim Bob were out hunting the other day in the woods south of Farmville. As they crossed a ridge, they came upon a big ol' Momma Bear and her cub. The larger bear immediately started towards them. Jim Bob took off running as fast as he could. He stopped when he realized Clem wasn't with him. And when he saw Clem reaching into his pack, Jim Bob was incredulous: "Hurry Clem! That bar's comin' fast! You need to out run 'er!" Clem kicked off his boots and pulled running shoes out...(read more)

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  • Podcast Show Notes: William Ulrich and Neal McWhorter on Business Architecture

    - by Bob Rhubart
    The latest ArchBeat podcast program features a four-part conversation with William Ulrich and Neal McWhorter, the authors of Business Architecture: The Art and Practice of Business Transformation, available from Meghan-Kiffer Press. Listen to Part 1 Bill and Neal cover the basics and discuss the effects of the lack of business architecture on organizations. Listen to Part 2 (Jan 19) What really happens to the billions of dollars annually invested in IT. Listen to Part 3 (Jan 26) Why the IT and business sides of many organizations can’t play nice. Listen to Part 4 (Feb 2) How IT architects and business architects can work together to get the ship back on course and keep it there. Connect William Ulrich Website | LinkedIn | Business Architecture Guild Neal McWhorter Website | LinkedIn | Business Architecture Group on OMG Coming Soon Bob Hensle, Director, Oracle Enterprise Architecture Group, discusses the recently launched IT Solutions from Oracle (ITSO) library of documents. Excerpts from a recent OTN Architect Community Virtual Meet-up. Stay tuned: RSS del.icio.us Tags: business architecture,enterprise architecture,arch2arch,archbeat,podcast,business transformation,oracle,oracle technology network Technorati Tags: business architecture,enterprise architecture,arch2arch,archbeat,podcast,business transformation,oracle,oracle technology network

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  • Ensure we're found in Facebook search for both full & abbreviated company names?

    - by hawbsl
    We have a client with a facebook page, let's say his company is called Bob Roberts Super Widgets. And if you search in Facebook for Bob Roberts Super Widgets then up he pops. But the shorthand he's commonly known by is BR Super Widgets and indeed the website we've created for him is br-super-widgets.com. In Facebook, searching for BR Super Widgets doesn't show up our Mr Bob. We don't have a lot of Facebook expertise, so asking for help here. Does anyone know how to ensure you're found in Facebook search for both short and long company names? Have found this this similar question in the Facebook forum but the poor old questioner never got a response.

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  • Ensure we're found in Facebook search for both full & abbreviated company names?

    - by hawbsl
    We have a client with a facebook page, let's say his company is called Bob Roberts Super Widgets. And if you search in Facebook for Bob Roberts Super Widgets then up he pops. But the shorthand he's commonly known by is BR Super Widgets and indeed the website we've created for him is br-super-widgets.com. In Facebook, searching for BR Super Widgets doesn't show up our Mr Bob. We don't have a lot of Facebook expertise, so asking for help here. Does anyone know how to ensure you're found in Facebook search for both short and long company names? Have found this this similar question in the Facebook forum but the poor old questioner never got a response.

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  • When is a Use Case layer needed?

    - by Meta-Knight
    In his blog post The Clean Architecture Uncle Bob suggests a 4-layer architecture. I understand the separation between business rules, interfaces and infrastructure, but I wonder if/when it's necessary to have separate layers for domain objects and use cases. What added value will it bring, compared to just having the uses cases as "domain services" in the domain layer? The only useful info I've found on the web about a use case layer is an article by Martin Fowler, who seems to contradict Uncle Bob about its necessity: At some point I may run into the problems, and then I'll make a Use Case Controller - but only then. And even when I do that I rarely consider the Use Case Controllers to occupy a separate layer in the system architecture. Edit: I stumbled upon a video of Uncle Bob's Architecture: The Lost Years keynote, in which he explains this architecture in depth. Very informative.

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  • Trying to setup a gateway via pppoe

    - by Bob
    I just installed Ubuntu 12.04 on a computer. I want to use this computer as a router for my other computers. The computer only has 1 network card, there is no slot for a second card. I can get the computer to connect to my ISP via pppoe and it can access the web. However the other computers on my local net can only see the router computer. I have tried 2 different pppoe packages, roaring penguin and network-manager-gnome. When I get it to work I will be replacing a 15 year old computer that is running Slackware 7.1. The old computer is currently my router. It is running Roaring Penguin I tried to setup the new computer with the same Roaring Penguin parameters as the old computer. Bob

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  • Port 21 will not open. status is closed. forward port 21 to new domains.

    - by Bob Swaggerty
    I am having a problem opening port 21 on my Linux Ubuntu server. No matter what i do, i can not get my status to change from closed to open. Here is a recent iptables command i used and the result iptables -A INPUT -p tcp -m tcp --dport 21 -j ACCEPT nmap -p21-22,25,80,443 CCR1 Starting Nmap 4.53 ( http://insecure.org ) at 2012-06-19 03:13 CDT Interesting ports on CCR1.chennaichristianradio.com (5.10.69.98): PORT STATE SERVICE 21/tcp closed ftp 22/tcp open ssh 25/tcp closed smtp 80/tcp open http 443/tcp closed https I also used commands from the advise from this forum http://www.cyberciti.biz/faq/iptables-open-ftp-port-21/ I need to open this for FTP access to the server, and ultimately I need to forward port 21 to 2 domains i am setting up. Thank you for any assistance you can provide -Bob Swaggerty

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  • Forbes.com: Oracle's message is Loud & Clear – “We’ve Got The Cloud”

    - by Cinzia Mascanzoni
    In a two-part series on Oracle's cloud strategy, Bob Evans reports on the October 4 meeting where Wall Street analysts questioned Mark Hurd and Safra Catz about the company's positioning for the shift to cloud computing. Access the article and read the Q&A exchanges between the analysts and Hurd and Catz. And then check out Bob's related Forbes.com piece "The Dumbest Idea of 2013," in response to the preposterous chatter that Larry Ellison and Oracle don't "get" the cloud. His powerful six-point argument unravels our competitors' spin. Go to the two-part strategy article. Read the "Dumbest Idea." Follow Bob on Twitter as he frequently updates his Oracle Voice column on Forbes.com.

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  • russian characters not accepted in php / phpmyadmin ?

    - by Bob Deckx
    I have a website in 3 languages: english, dutch and russian. There's a little CMS where the user can update the text on the website. everything works good, except for the russian text.. If I enter any russian text in the form in the CMS, I get "????" in the phpmyadmin database and on the website. I am completely new to charsets, it's the first time I am building a website in a language that is not supported like in this case.. Could someone please tell me what's the problem here? and what I have to do to make this work in russian language?

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  • how does public key cryptography work

    - by rap-uvic
    Hello, What I understand about RSA is that Alice can create a public and a private key combination, and then send the public key over to Bob. And then afterward Bob can encrypt something using the public key and Alice will use the public and private key combo to decrypt it. However, how can Alice encrypt something to be sent over to Bob? How would Bob decrypt it? I ask because I'm curious how when I log onto my banking site, my bank sends me data such as my online statements. How does my browser decrypt that information? I don't have the private key.

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  • How do I correctly organize output into columns?

    - by wrongusername
    The first thing that comes to my mind is to do a bunch of \t's, but that would cause words to be misaligned if any word is longer than any other word by a few characters. For example, I would like to have something like: Name Last Name Middle initial Bob Jones M Joe ReallyLongLastName T Instead, by including only "\t"'s in my cout statement I can only manage to get Name Last Name Middle initial Bob Jones M Joe ReallyLongLastName T or Name Last Name Middle initial Bob Jones M Joe ReallyLongLastName T What else would I need to do?

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  • Trouble with MySQL: CONCAT_WS(' ', name_first, name_middle, name_last) like '%keyword%'

    - by AJB
    hey folks, I'm setting up a keyword search across multiple fields: name_first, name_middle, name_last but I'm not getting the results I'd like. Here's the query: "SELECT accounts_users.user_ID, users.name_first, users.name_middle, users.name_last, users.company FROM accounts_users, users WHERE accounts_users.account_ID = '$account_ID' AND accounts_users.user_ID = users.id AND CONCAT_WS(' ', users.name_first, users.name_middle, users.name_last) LIKE '$user_keyword%' ORDER BY users.name_first ASC" So, if I've got three names in the DB: Aaron J Ban Aaron J Can Bob L Lawblaw And if the user_keyword == "bob lawblaw" I get no result. If user_keyword == "bob L" then it returns Bob L Lawblaw. Obviously I can't force people to include the persons middle name in their keyword search but I'm stuck for the proper way to do this. All help is greatly appreciated.

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  • Objective C - when should "typedef" precede "enum", and when should an enum be named?

    - by Scott Pendleton
    In sample code, I have seen this: typedef enum Ename { Bob, Mary, John} EmployeeName; and this: typedef enum {Bob, Mary, John} EmployeeName; and this: typedef enum {Bob, Mary, John}; but what compiled successfully for me was this: enum {Bob, Mary, John}; I put that line in a .h file above the @interface line, and then when I #import that .h file into a different class's .m file, methods there can see the enum. So, when are the other variants needed? If I could name the enum something like EmployeeNames, and then, when I type "EmployeeNames" followed by a ".", it would be nice if a list pops up showing what the enum choices are.

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  • How to differenciate the data when doing a UNION on 2 SELECTS ?

    - by wiooz
    If I have the following two tables : Employes Bob Gina John Customers Sandra Pete Mom I will do a UNION for having : Everyone Bob Gina John Sandra Pete Mom The question is : In my result, how can I creat a dumn column of differenciate the data from my tables ? Everyone Bob (Emp) Gina (Emp) John (Emp Sandra (Cus) Pete (Cus) Mom (Cus) I want to know from with table the entry is from withouth adding a new column in the database... SELECT Employes.name FROM Employes UNION SELECT Customers.name FROM Customers;

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  • MySQL Query GROUP_CONCAT Over Multiple Rows

    - by PeteGO
    I'm getting name and address data out of generic question / answer data to create some kind of normalised reporting database. The query I've got uses group_concat and works for individual sets of questions but not for multiple sets. I've tried to simplify what I'm doing by using just forename and surname and just 3 records, 2 for 1 person and 1 for another. In reality though there are more than 300,000 records. Example of results with qs.Id = 1. QuestionSetId Forename Surname ------------------------------------------------------- 1 Bob Jones Example of results with qs.Id IN (1, 2, 3). QuestionSetId Forename Surname ------------------------------------------------------- 3 Bob,Bob,Frank Jones,Jones,Smith What I would like to see for qs.Id IN (1, 2, 3). QuestionSetId Forename Surname ------------------------------------------------------- 1 Bob Jones 2 Bob Jones 3 Frank Smith So how can I make the 2nd example return a separate row for each set of name and address information? I realise the current way the data is stored is "questionable" but I cannot change the way the data is stored. I can get sets of individual answers but not sure how to combine the others. My simplified Schema that I cannot change: CREATE TABLE StaticQuestion ( Id INT NOT NULL, StaticText VARCHAR(500) NOT NULL); CREATE TABLE Question ( Id INT NOT NULL, Text VARCHAR(500) NOT NULL); CREATE TABLE StaticQuestionQuestionLink ( Id INT NOT NULL, StaticQuestionId INT NOT NULL, QuestionId INT NOT NULL, DateEffective DATETIME NOT NULL); CREATE TABLE Answer ( Id INT NOT NULL, Text VARCHAR(500) NOT NULL); CREATE TABLE QuestionSet ( Id INT NOT NULL, DateEffective DATETIME NOT NULL); CREATE TABLE QuestionAnswerLink ( Id INT NOT NULL, QuestionSetId INT NOT NULL, QuestionId INT NOT NULL, AnswerId INT NOT NULL, StaticQuestionId INT NOT NULL); Some example data for only forename and surname. INSERT INTO StaticQuestion (Id, StaticText) VALUES (1, 'FirstName'), (2, 'LastName'); INSERT INTO Question (Id, Text) VALUES (1, 'What is your first name?'), (2, 'What is your forename?'), (3, 'What is your Surname?'); INSERT INTO StaticQuestionQuestionLink (Id, StaticQuestionId, QuestionId, DateEffective) VALUES (1, 1, 1, '2001-01-01'), (2, 1, 2, '2008-08-08'), (3, 2, 3, '2001-01-01'); INSERT INTO Answer (Id, Text) VALUES (1, 'Bob'), (2, 'Jones'), (3, 'Bob'), (4, 'Jones'), (5, 'Frank'), (6, 'Smith'); INSERT INTO QuestionSet (Id, DateEffective) VALUES (1, '2002-03-25'), (2, '2009-05-05'), (3, '2009-08-06'); INSERT INTO QuestionAnswerLink (Id, QuestionSetId, QuestionId, AnswerId, StaticQuestionId) VALUES (1, 1, 1, 1, 1), (2, 1, 3, 2, 2), (3, 2, 2, 3, 1), (4, 2, 3, 4, 2), (5, 3, 2, 5, 1), (6, 3, 3, 6, 2); Just in case SQLFiddle is down here are the 3 queries from the examples I've linked to: 1: - working query but only on 1 set of data. SELECT MAX(QuestionSetId) AS QuestionSetId, GROUP_CONCAT(Forename) AS Forename, GROUP_CONCAT(Surname) AS Surname FROM (SELECT x.QuestionSetId, CASE x.StaticQuestionId WHEN 1 THEN Text END AS Forename, CASE x.StaticQuestionId WHEN 2 THEN Text END AS Surname FROM (SELECT (SELECT link.StaticQuestionId FROM StaticQuestionQuestionLink link WHERE link.Id = qa.QuestionId AND link.DateEffective <= qs.DateEffective AND link.StaticQuestionId IN (1, 2) ORDER BY link.DateEffective DESC LIMIT 1) AS StaticQuestionId, a.Text, qa.QuestionSetId FROM QuestionSet qs INNER JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId INNER JOIN Answer a ON qa.AnswerId = a.Id WHERE qs.Id IN (1)) x) y 2: - working query but undesired results on multiple sets of data. SELECT MAX(QuestionSetId) AS QuestionSetId, GROUP_CONCAT(Forename) AS Forename, GROUP_CONCAT(Surname) AS Surname FROM (SELECT x.QuestionSetId, CASE x.StaticQuestionId WHEN 1 THEN Text END AS Forename, CASE x.StaticQuestionId WHEN 2 THEN Text END AS Surname FROM (SELECT (SELECT link.StaticQuestionId FROM StaticQuestionQuestionLink link WHERE link.Id = qa.QuestionId AND link.DateEffective <= qs.DateEffective AND link.StaticQuestionId IN (1, 2) ORDER BY link.DateEffective DESC LIMIT 1) AS StaticQuestionId, a.Text, qa.QuestionSetId FROM QuestionSet qs INNER JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId INNER JOIN Answer a ON qa.AnswerId = a.Id WHERE qs.Id IN (1, 2, 3)) x) y 3: - working query on multiple sets of data only on 1 field (answer) though. SELECT qs.Id AS QuestionSet, a.Text AS Answer FROM QuestionSet qs INNER JOIN QuestionAnswerLink qalink ON qs.Id = qalink.QuestionSetId INNER JOIN StaticQuestionQuestionLink sqqlink ON qalink.QuestionId = sqqlink.QuestionId INNER JOIN Answer a ON qalink.AnswerId = a.Id WHERE sqqlink.StaticQuestionId = 1 /* FirstName */ AND sqqlink.DateEffective = (SELECT DateEffective FROM StaticQuestionQuestionLink WHERE StaticQuestionId = 1 AND DateEffective <= qs.DateEffective ORDER BY DateEffective DESC LIMIT 1)

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  • Two strange efficiency problems in Mathematica

    - by Jess Riedel
    FIRST PROBLEM I have timed how long it takes to compute the following statements (where V[x] is a time-intensive function call): Alice = Table[V[i],{i,1,300},{1000}]; Bob = Table[Table[V[i],{i,1,300}],{1000}]^tr; Chris_pre = Table[V[i],{i,1,300}]; Chris = Table[Chris_pre,{1000}]^tr; Alice, Bob, and Chris are identical matricies computed 3 slightly different ways. I find that Chris is computed 1000 times faster than Alice and Bob. It is not surprising that Alice is computed 1000 times slower because, naively, the function V must be called 1000 more times than when Chris is computed. But it is very surprising that Bob is so slow, since he is computed identically to Chris except that Chris stores the intermediate step Chris_pre. Why does Bob evaluate so slowly? SECOND PROBLEM Suppose I want to compile a function in Mathematica of the form f(x)=x+y where "y" is a constant fixed at compile time (but which I prefer not to directly replace in the code with its numerical because I want to be able to easily change it). If y's actual value is y=7.3, and I define f1=Compile[{x},x+y] f2=Compile[{x},x+7.3] then f1 runs 50% slower than f2. How do I make Mathematica replace "y" with "7.3" when f1 is compiled, so that f1 runs as fast as f2? Many thanks!

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  • SQL Server: pulling and updating local data

    - by SDReyes
    Hi guys, I have two SQL Server 2008 databases called Anna and Bob. Bob has to pull and transform data from Anna to keep updated his tables. Ideally Bob will be always synchronized with Anna, but some delay would be acceptable. What is the best way to do this? Thanks in advance.

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  • bbcode hyperlink issue (help!!)

    - by Jorm
    I'm having an annoying :) I use regexes from this: http://forums.codecharge.com/posts.php?post_id=77123 if you enter [url]www.bob.com[/url] it leads too http://localhost/test/www.bobsbar.com So I added before http://$1 in the replacement. That fix it but then [url]http://www.bob.com[/url] will lead to http://http://www.bobsbar.com How would you fix this? I want my users to be able to post links with AND without http:// and i want it to redirect to the site -_- Hope you understand this. Jorm Edit function bbcode_format($str) { $str = htmlentities($str); $find = array( '/\[url\](.*?)\[\/url\]/is', // hyperlink '/\[url\](http[s]?:\/\/)(.*?)\[\/url\]/is' // hyperlink http-protocol ); $replace = array( '<a href="$1" rel="nofollow" title="$1">$1</a>', '<a href="$1$2" rel="nofollow" title="$2">$2 THIS WORKS</a>' ); $str = preg_replace($find, $replace, $str); return $str; } both www.bob.com and http://www.bob.com uses the first replacement

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  • Unique ways to use the Null Coalescing operator

    - by Atomiton
    I know the standard way of using the Null coalescing operator in C# is to set default values. string nobody = null; string somebody = "Bob Saget"; string anybody = ""; anybody = nobody ?? "Mr. T"; // returns Mr. T anybody = somebody ?? "Mr. T"; // returns "Bob Saget" But what else can ?? be used for? It doesn't seem as useful as the ternary operator, apart from being more concise and easier to read than: nobody = null; anybody = nobody == null ? "Bob Saget" : nobody; // returns Bob Saget So given that fewer even know about null coalescing operator... Have you used ?? for something else? Is ?? necessary, or should you just use the ternary operator (that most are familiar with)

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  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

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  • What's the use of Ant's extension-point if/unless attributes?

    - by Robert Menteer
    When you define an extension-point in an Ant build file you can have it conditional by using the if or unless attribute. On a target the if/unless prevent it's tasks from being run. But an extension-point doesn't have any tasks to conditionally run, so what does the condition do? My thought (which proved to be incorrect in Ant 1.8.0) is it would prevent any tasks that extend the extension-point from being run. Here is an example build script showing the problem: <project name = "ext-test" default = "main"> <property name = "do.it" value = "false" /> <extension-point name = "init"/> <extension-point name = "doit" depends = "init" if = "${do.it}" /> <target name = "extend-init" extensionOf = "init"> <echo message = "Doing extend-init." /> </target> <target name = "extend-doit" extensionOf = "doit"> <echo message = "Do It! (${do.it})" /> </target> <target name = "main" depends = "doit"> <echo message = "Doing main." /> </target> </project> Using the command: ant -v Relults in: Apache Ant version 1.8.0 compiled on February 1 2010 Trying the default build file: build.xml Buildfile: /Users/bob/build.xml Detected Java version: 1.6 in: /System/Library/Frameworks/JavaVM.framework/Versions/1.6.0/Home Detected OS: Mac OS X parsing buildfile /Users/bob/build.xml with URI = file:/Users/bob/build.xml Project base dir set to: /Users/bob parsing buildfile jar:file:/Users/bob/Documents/Development/3P-Tools/apache-ant-1.8.0/lib/ant.jar!/org/apache/tools/ant/antlib.xml with URI = jar:file:/Users/bob/Documents/Development/3P-Tools/apache-ant-1.8.0/lib/ant.jar!/org/apache/tools/ant/antlib.xml from a zip file Build sequence for target(s) `main' is [extend-init, init, extend-doit, doit, main] Complete build sequence is [extend-init, init, extend-doit, doit, main, ] extend-init: [echo] Doing extend-init. init: extend-doit: [echo] Do It! (false) doit: Skipped because property 'false' not set. main: [echo] Doing main. BUILD SUCCESSFUL Total time: 0 seconds You will notice the target extend-doit is executed but the extention-point itself is skipped. Since an extention-point doesn't have any tasks exactly what has been skipped? Any targets that depend on the extention-point still get executed since a skipped target is a successful target. What is the value of the if/unless attributes on an extention-point?

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  • Accessing a class's containing namespace from within a module

    - by SFEley
    I'm working on a module that, among other things, will add some generic 'finder' type functionality to the class you mix it into. The problem: for reasons of convenience and aesthetics, I want to include some functionality outside the class, in the same scope as the class itself. For example: class User include MyMagicMixin end # Should automagically enable: User.name('Bob') # Returns first user named Bob Users.name('Bob') # Returns ALL users named Bob User(5) # Returns the user with an ID of 5 Users # Returns all users I can do the functionality within these methods, no problem. And case 1 (User.name('Bob')) is easy. Cases 2–4, however, require being able to create new classes and methods outside User. The Module.included method gives me access to the class, but not to its containing scope. There is no simple "parent" type method that I can see on Class nor Module. (For namespace, I mean, not superclass nor nested modules.) The best way I can think to do this is with some string parsing on the class's #name to break out its namespace, and then turn the string back into a constant. But that seems clumsy, and given that this is Ruby, I feel like there should be a more elegant way. Does anyone have ideas? Or am I just being too clever for my own good?

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  • Question on compiling java program

    - by Hulk
    I am a newbie to java, i have a query, /home/bob/java/jdk1.5.0_06/bin/javac /home/bob/output/a.java In the above when the program is compiled how to generate the classfile in /home/bob/class. Also how should the environment variables set for the following i.e, JAVA_HOME,CLASSPATH,JAVAPATH Thanks..

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