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  • Heroku SSL: Pem is invalid / Key doesn't match the Pem certificate

    - by Jane
    I bought a Gandi.net SSL certificate and I'm following this tutorial. I created the key file. then transformed it to CSR then added it to Gandi website and waited for the CRT. then removed the password from the key === result : [FINAL KEY] then merged the CRT and the FINAL KEY into one file == result : [FINAL PEM] then heroku ssl:add final_pem final_key --app app_name and... got Pem is invalid / Key doesn't match the Pem certificate. I tried 3 times and I really don't know what's going one. Can you help ?

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  • How to set the itemdata in a combox from key value

    - by glinch
    Hi, How would i set the itemdata from getting just the ID/key of a row, if i didnt know what order it is in on the list For example I have a combo box showing the following: cmbPeople: ID Name 2 Rod 4 Jane 6 Freddy eg. I know I want Jane to be the focus of the combo box, and i have the ID but i dont know that its the second item in the list ( Me.cmbPeople.ItemData(1) ) How would I go about doing this?? Thanks in advance for any help

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  • LINQ/C#: Where & Foreach using index in a list/array

    - by Andrew White
    Hi, I have a list/array and need to process certain elements, but also need the index of the element in the processing. Example: List Names = john, mary, john, bob, simon Names.Where(s = s != "mary").Foreach(MyObject.setInfo(s.index, "blah") But cannot use the "index" property with lists, inversely if the names were in an Array I cannot use Foreach... Any suggestions?

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  • How to do a join that removes values?

    - by Georg
    Customers Holidays id | name customer_id | start | end ---+------ ------------+--------+------ 1 | Peter 1 | 5 | 10 2 | Simon 1 | 15 | 20 3 | Mary 2 | 5 | 20 How should my SQL query look that out of start=11,end=14 I get these customers: Peter Mary Is this even manageable with a simple SQL join, or do I need to use sub-queries?

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  • Best way to manually sort random text files?

    - by Jane
    I have about 1000 text files and I need to view each, and move it to a folder if it's the correct one. I can only do basic sorting by length/size, and I can't grep because the text is random. How can I do this besides manually openiing + saving each in gedit. I'm on Ubuntu Linux. Thanks

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  • How to loop through items in a js object?

    - by Blankman
    how can I loop through these items? var userCache = {}; userCache['john'] = {ID: 234, name: 'john', ... }; userCache['mary'] = {ID: 567, name: 'mary', ... }; userCache['douglas'] = {ID: 42, name: 'douglas', ... }; the length property doesn't work? userCache.length

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  • My PC becomes very slow after changing page file in XP.

    - by Jane
    Hello there, I have 5 partitions in my computer (C, D, E, F, G), and C: is the system partition. Recently I changed the page file setting to use 768-768 MB from the G:, without changing the C: default value (256-512 MB). Everything runs fine until I rebooted my PC. I unset the G:'s page file before I rebooted my PC. Well, after I rebooted my PC, my XP becomes VERY slow. damn slow. I don't know how long I wasted to wait for the boot screen to disappear. (Well, maybe about 1-3 mins. Normally it is under 10 secs) and when I tried to enter the desktop, it just like using a computer without a VGA card, or VGA driver installed. Very slow. Any suggestions to fix this problem? Because I hate to repair-install my XP =\ Thanks.

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  • Create a binary indicator matrix in R

    - by Brian Vanover
    I have a list of data indicating attendance to conferences like this: Event Participant ConferenceA John ConferenceA Joe ConferenceA Mary ConferenceB John ConferenceB Ted ConferenceC Jessica I would like to create a binary indicator attendance matrix of the following format: Event John Joe Mary Ted Jessica ConferenceA 1 1 1 0 0 ConferenceB 1 0 0 1 0 ConferenceC 0 0 0 0 1 Is there a way to do this in R? Sorry for the poor formatting.

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  • maintaing a sorted list that is bigger than memory

    - by tcurdt
    I have a list of tuples. [ "Bob": 3, "Alice: 2, "Jane": 1, ] When incrementing the counts "Alice" += 2 the order should be maintained: [ "Alice: 4, "Bob": 3, "Jane": 1, ] When all is in memory there rather simple ways (some more or some less) to efficiently implement this. (using an index, insert-sort etc) The question though is: What's the most promising approach when the list does not fit into memory. Bonus question: What if not even the index fits into memory? How would you approach this?

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  • Allowing the specific format of email address in MVC input

    - by user219315
    Hi I have a page in MVC where i want to take the email adddress as the input which can be of format like:"Jone Davi" <[email protected]>, "Ben Miller" <[email protected]>, "Jane Ton" <[email protected]>, Then from this I want to parse the valid emailaddress.But on click of the submit button getting error message" A potentially dangerous Request.Form value was detected from the client " Thus is there any way to take the input of email address in above format and bypass the security error for that specific page. Thanks in advance.

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  • piping in UNIX doubt

    - by Happy Mittal
    In The Unix Programming Environment by K & P, it is written that " The programs in a pipeline actually run at the same time, not one after another. This means that programs in a pipeline can be interactive;" How can programs run at same time? For ex: $ who | grep mary | wc -l How grep mary will be executed until who is run or how wc -l will be executed until it knows results of previous programs?

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  • split sting in xsl for content with /

    - by kristina
    I have some content being pulled in from an external xml with xsl. in the xml the title is merged with the author with a backslash seperating them. How do I seperate the title and author in xsl so I can have them with differnt tags The Maze / Jane Evans to be The Maze Jane Evans Thanks

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  • Encoding arbitrary data into numbers?

    - by Pekka
    Is there a common method to encode and decode arbitrary data so the encoded end result consists of numbers only - like base64_encode but without the letters? Fictitious example: $encoded = numbers_encode("Mary had a little lamb"); echo $encoded; // outputs e.g. 122384337422394237423 (fictitious result) $decoded = numbers_decode("122384337422394237423"); echo $decoded; // outputs "Mary had a little lamb"

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  • Simplest way to print an array in Java

    - by Alex Spurling
    What's the simplest way of printing an array of primitives or of objects in Java? Here are some example inputs and outputs: int[] intArray = new int[] {1, 2, 3, 4, 5}; //output: [1, 2, 3, 4, 5] String[] strArray = new String[] {"John", "Mary", "Bob"}; //output: [John, Mary, Bob]

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  • Fix static ip address problems in Ubuntu 10.04

    - by jane
    I used Network Manager in Ubuntu 10.04 to set a static ip address and assigned one that was already in use. Now my computer will not boot (nfs crashes). I booted from a live cd to change the configuration on the file system in /etc/network/interfaces but the file looks to be the default. Where does the network manager (the gui from system- preferences) store it's configuration so I can overwrite it and enter the correct ip addresss and have a happy working computer again. thanks!!

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  • I can't open a Word file because it's too large

    - by Jane
    I was creating a file with MS Word 2007 where I included a number of images. I didn't compress them as I was putting them into the file. I managed to save the file, but have not been able to reopen it ever since, as it says that I have exceeded the 32 MB limit. I am working on an old Macbook (OS X 10.4.11). I have tried to open the file in both OpenOffice and LibreOffice, but it just causes those programs to crash. Is there any way of reducing the file size without opening the document?

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  • C# lost local variable window from debug (f11 step by step)

    - by Jane
    I was running my code (visual studio 2010) and I accidentally closed the window that shows the state of variables step by step. I think it was called locals but I can't find it on any of the menu option. Would appreciate any help on this, I didn't realize how handy it was until now - The following link is what my local window looks like when selecting debug/start debugging/selecting breakpoints, which I'm don't find helpful. This is what my window used to look like: http://www.google.co.nz/imgresum=1&hl=en&sa=N&biw=1600&bih=761&tbm=isch&tbnid=Sa5AmVW5BxxakM:&imgrefurl=http://www.codeproject.com/Articles/79508/Mastering-Debugging-in-Visual-Studio-2010-A-Beginn&docid=4Iskh8P-E7oVSM&imgurl=http://www.codeproject.com/KB/cs/MasteringInDebugging/debug30_small.png&w=640&h=228&ei=TjKBUKGwKcXVsgauvIGYDQ&zoom=1&iact=hc&vpx=1119&vpy=441&dur=1559&hovh=134&hovw=376&tx=219&ty=79&sig=104270260849502265426&page=1&tbnh=91&tbnw=256&start=0&ndsp=22&ved=1t:429,r:0,s:20,i:134 It's probably a mode/option within debugging I need to select but I can't figure out how to get it back to the nice and simple variable state display..

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  • Prolog Family tree

    - by Tania
    Hi I have a Question in prolog , I did it but its not showing answers When i ask about the brothers,sisters,uncles,aunts This is what I wrote, what's wrong ? /*uncle(X, Y) :– male(X), sibling(X, Z), parent(Z, Y).*/ /*uncle(X, Y) :– male(X), spouse(X, W), sibling(W, Z), parent(Z, Y).*/ uncle(X,Y) :- parent(Z,Y), brother(X,Z). aunt(X,Y) :- parent(Z,Y), sister(X,Z). sibling(X, Y) :- parent(Z, X), parent(Z, Y), X \= Y. sister(X, Y) :- sibling(X, Y), female(X). brother(X, Y) :- sibling(X, Y), male(X). parent(Z,Y) :- father(Z,Y). parent(Z,Y) :- mother(Z,Y). grandparent(C,D) :- parent(C,E), parent(E,D). aunt(X, Y) :– female(X), sibling(X, Z), parent(Z, Y). aunt(X, Y) :– female(X), spouse(X, W), sibling(W, Z), parent(Z, Y). male(john). male(bob). male(bill). male(ron). male(jeff). female(mary). female(sue). female(nancy). mother(mary, sue). mother(mary, bill). mother(sue, nancy). mother(sue, jeff). mother(jane, ron). father(john, sue). father(john, bill). father(bob, nancy). father(bob, jeff). father(bill, ron). sibling(bob,bill). sibling(sue,bill). sibling(nancy,jeff). sibling(nancy,ron). sibling(jell,ron). And one more thing, how do I optimize the rule of the brother so that X is not brother to itself.

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  • How do I Handle Ties When Ranking Results in MySQL?

    - by Laxmidi
    Hi, How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem: SET @rank=0; SELECT student_names.students, @rank := @rank +1 AS rank, scores.grades FROM student_names LEFT JOIN scores ON student_names.students = scores.students ORDER BY scores.grades DESC So imagine the the above query produces: Students Rank Grades Al 1 90 Amy 2 90 George 3 78 Bob 4 73 Mary 5 NULL William 6 NULL Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place. The correct ranking should be: Students Rank Grades Al 1 90 Amy 1 90 George 3 78 Bob 4 73 Mary 5 NULL William 5 NULL If anyone has any advice, please let me know. Thank you! -Laxmidi

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  • SQL Server, how to join a table in a "rotated" format (returning columns instead of rows)?

    - by Joshua Carmody
    Sorry for the lame title, my descriptive skills are poor today. In a nutshell, I have a query similar to the following: SELECT P.LAST_NAME, P.FIRST_NAME, D.DEMO_GROUP FROM PERSON P JOIN PERSON_DEMOGRAPHIC PD ON PD.PERSON_ID = P.PERSON_ID JOIN DEMOGRAPHIC D ON D.DEMOGRAPHIC_ID = PD.DEMOGRAPHIC_ID This returns output like this: LAST_NAME FIRST_NAME DEMO_GROUP --------------------------------------------- Johnson Bob Male Smith Jane Female Smith Jane Teacher Beeblebrox Zaphod Male Beeblebrox Zaphod Alien Beeblebrox Zaphid Politician I would prefer the output be similar to the following: LAST_NAME FIRST_NAME Male Female Teacher Alien Politician --------------------------------------------------------------------------------------------------------- Johnson Bob 1 0 0 0 0 Smith Jane 0 1 1 0 0 Beeblebrox Zaphod 1 0 0 1 1 The number of rows in the DEMOGRAPHIC table varies, so I can't say with certainty how many columns I need. The query needs to be flexible. Yes, it would be trivial to do this in code. But this query is one piece of a complicated set of stored procedures, views, and reporting services, many of which are outside my sphere of influence. I need to produce this output inside the database to avoid breaking the system. Any ideas? This is MS SQL Server 2005, by the way. Thanks.

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  • Filter entities that match all pairs

    - by Jon
    I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there?

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  • How can I get a distinct list of elements in a hierarchical query?

    - by RenderIn
    I have a database table, with people identified by a name, a job and a city. I have a second table that contains a hierarchical representation of every job in the company in every city. Suppose I have 3 people in the people table: [name(PK),title,city] Jim, Salesman, Houston Jane, Associate Marketer, Chicago Bill, Cashier, New York And I have thousands of job type/location combinations in the job table, a sample of which follow. You can see the hierarchical relationship since parent_title is a foreign key to title: [title,city,pay,parent_title] Salesman, Houston, $50000, CEO Cashier, Houston, $25000 CEO, USA, $1000000 Associate Marketer, Chicago, $75000 Senior Marketer, Chicago, $125000 ..... The problem I'm having is that my Person table is a composite key, so I don't know how to structure the start with part of my query so that it starts with each of the three jobs in the cities I specified. I can execute three separate queries to get what I want, but this doesn't scale well. e.g.: select * from jobs start with city = (select city from people where name = 'Bill') and title = (select title from people where name = 'Bill') connect by prior parent_title = title UNION select * from jobs start with city = (select city from people where name = 'Jim') and title = (select title from people where name = 'Jim') connect by prior parent_title = title UNION select * from jobs start with city = (select city from people where name = 'Jane') and title = (select title from people where name = 'Jane') connect by prior parent_title = title How else can I get a distinct list (or I could wrap it with a distinct if not possible) of all the jobs which are above the three people I specified?

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  • sqlite3 JOIN, GROUP_CONCAT using distinct with custom separator

    - by aiwilliams
    Given a table of "events" where each event may be associated with zero or more "speakers" and zero or more "terms", those records associated with the events through join tables, I need to produce a table of all events with a column in each row which represents the list of "speaker_names" and "term_names" associated with each event. However, when I run my query, I have duplication in the speaker_names and term_names values, since the join tables produce a row per association for each of the speakers and terms of the events: 1|Soccer|Bobby|Ball 2|Baseball|Bobby - Bobby - Bobby|Ball - Bat - Helmets 3|Football|Bobby - Jane - Bobby - Jane|Ball - Ball - Helmets - Helmets The group_concat aggregate function has the ability to use 'distinct', which removes the duplication, though sadly it does not support that alongside the custom separator, which I really need. I am left with these results: 1|Soccer|Bobby|Ball 2|Baseball|Bobby|Ball,Bat,Helmets 3|Football|Bobby,Jane|Ball,Helmets My question is this: Is there a way I can form the query or change the data structures in order to get my desired results? Keep in mind this is a sqlite3 query I need, and I cannot add custom C aggregate functions, as this is for an Android deployment. I have created a gist which makes it easy for you to test a possible solution: https://gist.github.com/4072840

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  • making arrays from tab-delimited text file column

    - by absolutenewbie
    I was wondering if anyone could help a desperate newbie with perl with the following question. I've been trying all day but with my perl book at work, I can't seem to anything relevant in google...or maybe am genuinely stupid with this. I have a file that looks something like the following: Bob April Bob April Bob March Mary August Robin December Robin April The output file I'm after is: Bob April April March Mary August Robin December April So that it lists each month in the order that it appears for each person. I tried making it into a hash but of course it wouldn't let me have duplicates so I thought I would like to have arrays for each name (in this example, Bob, Mary and Robin). I'm afraid to upload the code I've been trying to tweak because I know it'll be horribly wrong. I think I need to define(?) the array. Would this be correct? Any help would be greatly appreciated and I promise I will be studying more about perl in the meantime. Thank you for your time, patience and help. #!/usr/bin/perl -w while (<>) { chomp; if (defined $old_name) { $name=$1; $month=$2; if ($name eq $old_name) { $array{$month}++; } else { print "$old_name"; foreach (@array) { push (@array, $month); print "\t@array"; } print "\n"; @array=(); $array{$month}++; } } else { $name=$1; $month=$2; $array{month}++; } $old_name=$name; } print "$old_name"; foreach (@array) { push (@array, $month); print "\t@array"; } print "\n";

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  • Graph-structured databases and Php

    - by stagas
    I want to use a graph database using php. Can you point out some resources on where to get started? Is there any example code / tutorial out there? Or are there any other methods of storing data that relate to each other in totally random/abstract situations? - Very abstract example of the relations needed: John relates to Mary, both relate to School, John is Tall, Mary is Short, John has Blue Eyes, Mary has Green Eyes, query I want is which people are related to 'Short people that have Green Eyes and go to School' - answer John - Another example: TrackA -> ArtistA -> ArtistB -> AlbumA -----> [ label ] -> AlbumB -----> [ A ] -> TrackA:Remix -> Genre:House -> [ Album ] -----> [ label ] TrackB -> [ C ] [ B ] Example queries: Which Genre is TrackB closer to? answer: House - because it's related to Album C, which is related to TrackA and is related to Genre:House Get all Genre:House related albums of Label A : result: AlbumA, AlbumB - because they both have TrackA which is related to Genre:House - It is possible in MySQL but it would require a fixed set of attributes/columns for each item and a complex non-flexible query, instead I need every attribute to be an item by itself and instead of 'belonging' to something, to be 'related' to something.

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