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  • Many users send using a single address, replies to that single address go to many users

    - by Keyslinger
    I work in an office with a Microsoft Exchange server for email. I would like to have the following workflow: John, Mary, or Sam send a message from Outlook on their respective computers. The customer receives the message from the address "[email protected]" The customer replies to the message from [email protected] and it is received by John, Mary, or Sam depending on who sent the message (if it was sent by John, the reply is sent to John, and so on). All users should also be able to send emails from their respective addresses as well (e.g. [email protected], etc.) Is this possible? If so, how can it be accomplished?

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  • Many users send using a single address, replies to that single address go to many users

    - by Keyslinger
    I work in an office with a Microsoft Exchange server for email. I would like to have the following workflow: John, Mary, or Sam send a message from Outlook on their respective computers. The customer receives the message from the address "[email protected]" The customer replies to the message from [email protected] and it is received by John, Mary, or Sam depending on who sent the message (if it was sent by John, the reply is sent to John, and so on). All users should also be able to send emails from their respective addresses as well (e.g. [email protected], etc.) Is this possible? If so, how can it be accomplished?

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  • MS Outlook Voting mismatch

    - by Robert Ilbrink
    I did send out an Outlook vote to hundreds of employees, using their email address (which is mostly [email protected], but there are many exceptions). The incoming votes are not matched against the email address, but against the display name. Unfortunately, the display name has no real standard either. So instead of seeing this: [email protected] Voted: Yes Mary[email protected] Voted: No I see this: [email protected] Mary[email protected] Doe, Johnathan Philip Voted: Yes Doe - Peeters, Marian Voted: No In the actual list I see the addresses that I sent the vote to PLUS extra lines with the votes that came back. Is there a quick way to match my "send" list with the "received" list? One thing I thought of was to dump the global address book in a file and in Excel use =vlookup. But that seems a lot of work (and I am not even sure that I have the authorization to dump the address book).

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  • Table header is not shown

    - by Vivien
    My error is that the table headers of my two tables are not shown. Right now I am setting the header with new JTable(data, columnNames). Here is an example which shows, my problem: public class Test extends JFrame { private static final long serialVersionUID = -4682396888922360841L; private JMenuBar menuBar; private JMenu mAbout; private JMenu mMain; private JTabbedPane tabbedPane; public SettingsTab settings = new SettingsTab(); private void addMenuBar() { menuBar = new JMenuBar(); mMain = new JMenu("Main"); mAbout = new JMenu("About"); menuBar.add(mMain); menuBar.add(mAbout); setJMenuBar(menuBar); } public void createTabBar() { tabbedPane = new JTabbedPane(JTabbedPane.TOP); tabbedPane.addTab("Settings", settings.createLayout()); add(tabbedPane); tabbedPane.setTabLayoutPolicy(JTabbedPane.SCROLL_TAB_LAYOUT); } private void makeLayout() { setTitle("Test"); setLayout(new BorderLayout()); setPreferredSize(new Dimension(1000, 500)); addMenuBar(); createTabBar(); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pack(); setVisible(true); } public void start() { javax.swing.SwingUtilities.invokeLater(new Runnable() { public void run() { makeLayout(); } }); } public static void main(String[] args) { Test gui = new Test(); gui.start(); } public class SettingsTab extends JPanel { public JScrollPane createLayout() { JPanel panel = new JPanel(new MigLayout("")); JScrollPane sp = new JScrollPane(panel); sp.setVerticalScrollBarPolicy(ScrollPaneConstants.VERTICAL_SCROLLBAR_ALWAYS); panel.add(table1(), "growx, wrap"); panel.add(Box.createRigidArea(new Dimension(0,10))); panel.add(table2()); // panel.add(Box.createRigidArea(new Dimension(0,10))); return sp; } public JPanel table1() { JPanel panel1 = new JPanel(); String[] columnNames = {"First Name", "Last Name"}; Object[][] data = { {"Kathy", "Smith"}, {"John", "Doe"}, {"Sue", "Black"}, {"Jane", "White"}, {"Joe", "Brown"}, {"John", "Doe"}, {"Sue", "Black"}, {"Jane", "White"}, {"Joe", "Brown"} }; final JTable table = new JTable(data, columnNames); tableProperties(table); panel1.add(table); panel1.setLayout(new BoxLayout(panel1, BoxLayout.Y_AXIS)); return panel1; } public JPanel table2() { JPanel panel1 = new JPanel(); String[] columnNames = {"First Name", "Last Name"}; Object[][] data = { {"Kathy", "Smith"}, {"John", "Doe"}, {"Sue", "Black"}, {"Jane", "White"}, {"Joe", "Brown"}, {"John", "Doe"}, {"Sue", "Black"}, {"Jane", "White"}, {"Joe", "Brown"} }; final JTable table = new JTable(data, columnNames); table.setPreferredScrollableViewportSize(new Dimension(500, 70)); table.setFillsViewportHeight(true); tableProperties(table); panel1.add(table); panel1.setLayout(new BoxLayout(panel1, BoxLayout.Y_AXIS)); return panel1; } public void tableProperties(JTable table) { table.setAutoResizeMode(JTable.AUTO_RESIZE_ALL_COLUMNS); table.repaint(); table.revalidate(); } } } Any recommendations what I am doing wrong?

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  • Learn Lean Software Development and Kanban Systems

    - by Ben Griswold
    I did an in-house presentation on Lean Software Development (LSD) and Kanban Systems this week.  Beyond what I had previously learned from various podcasts, I knew little about either topic prior to compiling my slide deck.  In the process of building my presentation, I learned a ton.  I found the concepts weren’t very difficult to grok; however, I found little detailed information was available online. Hence this post which is merely a list of valuable resources. Principles of Lean Thinking, Mary Poppendieck Lean Software Development, May Poppendieck Lean Programming, Mary Poppendieck Lean Software Development, Wikipedia Implementing Lean Software Thinking: From Concept to Cash, Poppendieck Lean Software Development Overview, Darrell Norton Lean Thinking: Banish Waste and Create Wealth in Your Corporation The Goal: A Process of Ongoing Improvement The Toyota Way Extreme Toyota: Radical Contradictions That Drive Success at the World’s Best Manufacturer Elegant Code Cast 17 – David Laribee on Lean / Kanban Herding Code Episode 42: Scott Bellware on BDD and Lean Development Seven Principles of Lean Software Development, Przemys?aw Bielicki Kanban Boards for Agile Project Management with Zen Author Nate Kohari Herding Code 55: Nate Kohari brings Your Moment of Zen James Shore on Kanban Systems Agile Zen Product Site A Leaner Form of Agile, David Laribee Kanban as Alternative Agile Implementation, Mark Levison Lean Software Development, Dr. Christoph Steindl Glossary of Lean Manufacturing Terms Why Pull? Why Kanban?, Corey Ladas

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  • Code Trivia #4

    - by João Angelo
    Got the inspiration for this one in a recent stackoverflow question. What should the following code output and why? class Program { class Author { public string FirstName { get; set; } public string LastName { get; set; } public override string ToString() { return LastName + ", " + FirstName; } } static void Main() { Author[] authors = new[] { new Author { FirstName = "John", LastName = "Doe" }, new Author { FirstName = "Jane", LastName="Doe" } }; var line1 = String.Format("Authors: {0} and {1}", authors); Console.WriteLine(line1); string[] serial = new string[] { "AG27H", "6GHW9" }; var line2 = String.Format("Serial: {0}-{1}", serial); Console.WriteLine(line2); int[] version = new int[] { 1, 0 }; var line3 = String.Format("Version: {0}.{1}", version); Console.WriteLine(line3); } } Update: The code will print the first two lines // Authors: Doe, John and Doe, Jane // Serial: AG27H-6GHW9 and then throw an exception on the third call to String.Format because array covariance is not supported in value types. Given this the third call of String.Format will not resolve to String.Format(string, params object[]), like the previous two, but to String.Format(string, object) which fails to provide the second argument for the specified format and will then cause the exception.

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  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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  • JLabel which hides text after reaching certain length or number of values

    - by Patrick Kiernan
    The purpose of the JLabel is to show who a message is to, like in a mail client e.g. To: John, Mary, Peter, Frank, Tom, Harry I will have the names in a vector so can build up a string from that and then set the label's text to this string. However it has the potential to get quite long. I was think it might be nice to have something like this: To: John, Mary, Peter, Frank, Tom, Harry, ... Then when you click on the '...', it will expand more or just show a tool tip if you mouse over the ... Yes this idea is stolen from Thunderbird! I am open to other ideas, don't have to use a JLabel. Thanks.

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  • What is the best way to join/merge two tables by column cell matching in Excel?

    - by blunders
    I've found this excel add-in to buy that appears to do what I need, but I'd rather have code that's open to use as I wish. While a GUI is nice, it's not required. In an attempt to make the question more clear, I'm adding some two sample "input" tables in tab delimited form, and the resulting output table: SAMPLE_INPUT_TABLE_01 NAME<tab>Location John<tab>US Mike<tab>CN Tom<tab>CA Sue<tab>RU SAMPLE_INPUT_TABLE_02 NAME<tab>Age John<tab>18 Mike<tab>36 Tom<tab>54 Mary<tab>18 SAMPLE_OUTPUT_TABLE_02 NAME<tab>Age<Location> John<tab>18<tab>US Mike<tab>36<tab>CN Tom<tab>54<tab>CA Sue<tab>""<tab>RU Mary<tab>18<tab>"" If it matters, I'm using Office 2010 on Windows 7.

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  • T-SQL How To: Compare and List Duplicate Entries in a Table

    - by Dan7el
    SQL Server 2000. Single table has a list of users that includes a unique user ID and a non-unique user name. I want to search the table and list out any users that share the same non-unique user name. For example, my table looks like this: ID User Name Name == ========= ==== 0 parker Peter Parker 1 parker Mary Jane Parker 2 heroman Joseph (Joey) Carter Jones 3 thehulk Bruce Banner What I want to do is do a SELECT and have the result set be: ID User Name Name == ========= ==== 0 parker Peter Parker 1 parker Mary Jane Parker from my table. I'm not a T-SQL guru. I can do the basic joins and such, but I'm thinking there must be an elegant way of doing this. Barring elegance, there must be ANY way of doing this. I appreciate any methods that you can help me with on this topic. Thanks! ---Dan---

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  • sorting a php array

    - by cute
    how do i sort this array by the nums... Array( [nums] => Array ( [0] => 34 [1] => 12 [2] => 13 ) [players] => Array ( [0] => Mike [1] => Bob [2] => Mary ) ) ... so that i get this one? Array( [nums] => Array ( [0] => 12 [1] => 13 [2] => 34 ) [players] => Array ( [0] => Bob [1] => Mary [2] => Mike ) )

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  • Can MySQL Nested Select return list of results

    - by John
    Hi I want to write a mysql statement which will return a list of results from one table along with a comma separated list of field from another table. I think an example might better explain it Table 1 ======================== id First_Name Surname ---------------------- 1 Joe Bloggs 2 Mike Smith 3 Jane Doe Table 2 ======================== id Person_Id Job_id --------------------- 1 1 1 2 1 2 3 2 2 4 3 3 5 3 4 I want to return a list of people with a comma separated list of job_ids. So my result set would be id First_Name Surname job_id ------------------------------ 1 Joe Bloggs 1,2 2 Mike Smith 2 3 Jane Doe 3,4 I guess the sql would be something like select id, First_Name, Surname, (SELECT job_id FROM Table 2) as job_id from Table 1 but obviously this does not work so need to change the '(SELECT job_id FROM Table 2) as job_id' part. Hope this makes sense Thanks John

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  • UNIX Parse HTML Page Display Contents of a Tag - One Liner?

    - by NJTechie
    I have an HTML file and I am interested in the data enclosed by <pre> </pre> tags. Is there a one-liner that can do achieve this? Sample file : <html> <title> Hello There! </title> <body> <pre> John Working Kathy Working Mary Working Kim N/A </pre> </body> </html> Output should be : John Kathy Mary Kim Much appreciated guys, thank you!

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  • SQL Join Problem

    - by Harley
    Table one contains ID|Name 1 Mary 2 John Table two contains ID|Color 1 Red 1 Blue 2 Green 2 Blue 2 Black I want to end up with is ID|Name|Red|Blue|Green|Black 1 Mary    Y      Y 2 John            Y        Y       Y Thanks for and help.

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  • Search and Replace within a Text file using mySQL queries

    - by user241000
    How can I create PHP to search the testing.txt file for each name in the database table and replace the name with the database table id? So that the text file looks like this: 3 | 1 | 4 | 5 2 | 3 | 6 4 | 5 | 2 and so forth an so on... I have a mysql table called "nameslist" that looks like this: --------------------- id | name --------------------- 1 | bob 2 | john 3 | tom and so forth an so on... I have a text file called "testing.txt" that looks like this: tom | bob | mary | paul john | tom | rachel mary | paul | john and so forth an so on...

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  • How to Import a CSV file containing multiple sections into R?

    - by PaulHurleyuk
    I want to import the contents of a csv file into R, the csv file contains multiple sections of data vertically, seperated by blank lines and asterisks. For example ******************************************************** * SAMPLE DATA ****************************************** ******************************************************** Name, DOB, Sex Rod, 1/1/1970, M Jane, 5/7/1980, F Freddy, 9.12,1965, M ******************************************************* * Income Data **************************************** ******************************************************* Name, Income Rod, 10000 Jane, 15000 Freddy, 7500 I would like to import this into R as two seperate dataframes. Currently I'm manually cutting the csv file up into smaller files, but I think I could do it using read.csv and the skip and nrows settings of read.csv, If I could work out where the secion breaks are. This gives me a logical TRUE for every blank line ifelse(readLines("DATA.csv")=="",TRUE,FALSE) I'm hoping someone has already solved this problem.

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  • Need help joining tables...

    - by yuudachi
    I am a MySQL newbie, so sorry if this is a dumb question.. These are my tables. student table: SID (primary) student_name advisor (foreign key to faculty.facultyID) requested_advisor (foreign key to faculty.facultyID) faculty table: facultyID (primary key) advisor_name I want to query a table that shows everything in the student table, but I want advisor and requested_advisor to show up as names, not the ID numbers. so like it displays like this on the webpage: Student Name: Jane Smith SID: 860123456 Current Advisor: John Smith Requested advisor: James Smith not like this Student Name: Jane Smith SID: 860123456 Current Advisor: 1 Requested advisor: 2 SELECT student.student_name, SID, student_email, faculty.advisor_name FROM student INNER JOIN faculty ON student.advisor = faculty.facultyID; this comes out close, but I don't know how to get the requested_advisor to show up as a name.

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  • jQuery Cycle Plugin - Content not cycling

    - by fmz
    I am setting up a page with jQuery's Cycle plugin and have four divs set to fade. I have the code in place, the images set, but it doesn't cycle properly. Firefox says there is a problem with the following code: <script type="text/javascript"> $(document).ready(function() { $('.slideshow').cycle({ fx: 'fade' }); }); </script> Here is the html: <div class="slideshow"> <div id="mainImg-1" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number One.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> <div id="mainImg-2" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number Two.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> <div id="mainImg-3" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number three.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> <div id="mainImg-4" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number Fout.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> Here is the CSS: .slideshow { width: 946px; height: 283px; border: 1px solid #c29c5d; margin: 8px; overflow: hidden; z-index: 1; } #mainImg-1 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-2 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-3 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-4 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-1 .quote, #mainImg-2 .quote, #mainImg-3 .quote, #mainImg-4 .quote { width: 608px; height: 168px; float: right; margin: 80px 11px 0 0; background: url(../_images/bg_quoteBox.png) repeat-x; } Before you go off and say, "hey, those images are all the same". You are right, the images are all the same right now, but the text should be rotating as well and there is a slight difference there. In addition, the fade should still show up. Anyway, you can see the dev page here: http://173.201.163.213/projectpath/first_trust/index.html I would appreciate some help to get this cycling through as it should. Thanks!

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  • How to write two-dimensional array to xml in Scala 2.8.0

    - by Shadowlands
    The following code (copied from a question from about a year ago) works fine under Scala 2.7.7, but does not behave correctly under Scala 2.8.0 (Beta 1, RC8). import scala.xml class Person(name : String, age : Int) { def toXml(): xml.Elem = <person><name>{ name }</name><age>{ age }</age></person> } def peopleToXml(people: Array[Person]): xml.Elem = { <people>{ for {person <- people} yield person.toXml }</people> } val data = Array(new Person("joe",40), new Person("mary", 35)) println(peopleToXml(data)) The output (according to 2.7.7) should be: <people><person><name>joe</name><age>40</age></person><person><name>mary</name><age>35</age></person></people> but instead comes out as: <people>\[Lscala.xml.Elem;@17821782</people> How do I get this to behave as it did in 2.7.x?

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  • find xml element by attribute

    - by Moudy
    Using JQuery or Javascript how would I return 'Mary Boone' from the xml below starting out with the show 'id' attribute of '2'? I'm thinking something along the lines of - var result = xml.getElementByAttribute("2").gallery.text(); the XML: <shows> <show id="1"> <artist>Andreas Gursky</artist> <gallery>Matthew Marks</gallery> <medium>photography</medium> </show> <show id="2"> <artist>Eric Fischl</artist> <gallery>Mary Boone</gallery> <medium>painting</medium> </show> </shows>

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  • Rails / JBuilder - Entity array with has_many attributes

    - by seufagner
    I have two models, Person and Image and I want return an json array of Persons with your Images. But I dont want return all Image attributes, but produces a different result. Code below: class Person < ActiveRecord::Base has_many :images, as: :imageable validates :name, presence: true accepts_nested_attributes_for :images, :reject_if => lambda { |img| img['asset'].blank? } end class Image < ActiveRecord::Base belongs_to :imageable, polymorphic: true mount_uploader :asset, ImageUploader validates :asset, presence: true end zzz.jbuilder.json template json.persons(@rodas, :id, :name, :images) json produced: { "rodas": [{ "id": 4, "name": "John", "images": [ { "asset": { "url": "/uploads/image/xxxx.png" } }, { "asset": { "url": "/uploads/image/yyyyy.jpeg" } } ]}, { "id": 19, "name": "Mary", "images": [ { "asset": { "url": "/uploads/image/kkkkkkk.png" } } ] }] } I want something like: { "rodas": [ { "id": 4, "name": "John", "images": [ "/uploads/image/xxxx.png" , "/uploads/image/yyyy.jpeg" ] }, { "id": 10, "name": "Mary", "images": [ "/uploads/image/dddd.png" , "/uploads/image/xxxx.jpeg" ] } ]}

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  • Algorithm to find a measurement of similarity between lists.

    - by Cubed
    Given that I have two lists that each contain a separate subset of a common superset, is there an algorithm to give me a similarity measurement? Example: A = { John, Mary, Kate, Peter } and B = { Peter, James, Mary, Kate } How similar are these two lists? Note that I do not know all elements of the common superset. Update: I was unclear and I have probably used the word 'set' in a sloppy fashion. My apologies. Clarification: Order is of importance. If identical elements occupy the same position in the list, we have the highest similarity for that element. The similarity decreased the farther apart the identical elements are. The similarity is even lower if the element only exists in one of the lists. I could even add the extra dimension that lower indices are of greater value, so a a[1] == b[1] is worth more than a[9] == b[9], but that is mainly cause I am curious.

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  • Wizard based feature install in sharepoint 2007?

    - by JL
    I have a feature that gets installed using a WSP package, when the feature is activated, I would like the following to happen: The feature will contain a list definition. When the feature gets activated by an end user (the user physically clicks the feature activation button in site features admin) - I would like a modal dialog to appear then ask the user to provide some additional details. 3.1 The additional details will be supplying a certain number of names. For example Mary, John, Peter. Form logistics I can handle. Once the form is complete that information needs to somehow get back to the feature reciever, so that I can then take the base list definition, and use it as a template to create list instances for all the names supplied - so if user had supplied Mary and Peter, then 2 list instances will be created when this feature is activated. Is any of this possible with MOSS 2007? Thank you

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • Why isn't my File.Move() working?

    - by yeahumok
    I'm not sure what exactly i'm doing wrong here...but i noticed that my File.Move() isn't renaming any files. Also, does anybody know how in my 2nd loop, i'd be able to populate my .txt file with a list of the path AND sanitized file name? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; using System.Text.RegularExpressions; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { //recurse through files. Let user press 'ok' to move onto next step string[] files = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); foreach (string file in files) { Console.Write(file + "\r\n"); } Console.WriteLine("Press any key to continue..."); Console.ReadKey(true); //End section //Regex -- find invalid chars string pattern = " *[\\~#%&*{}/<>?|\"-]+ *"; string replacement = " "; Regex regEx = new Regex(pattern); string[] fileDrive = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); List<string> filePath = new List<string>(); //clean out file -- remove the path name so file name only shows string result; foreach(string fileNames in fileDrive) { result = Path.GetFileName(fileNames); filePath.Add(result); } StreamWriter sw = new StreamWriter(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing\File_Renames.txt"); //Sanitize and remove invalid chars foreach(string Files2 in filePath) { try { string sanitized = regEx.Replace(Files2, replacement); sw.Write(sanitized + "\r\n"); System.IO.File.Move(Files2, sanitized); System.IO.File.Delete(Files2); } catch (Exception ex) { Console.Write(ex); } } sw.Close(); } } } I'm VERY new to C# and trying to write an app that recurses through a specific drive, finds invalid characters (as specified in the RegEx pattern), removes them from the filename and then write a .txt file that has the path name and the corrected filename. Any ideas?

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