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  • Elegent way to collapse or expand sub-sequences of a list in Python?

    - by forgot
    I want to collapse or expand sub-sequences of a list e.g. ['A', 'B', 'D', 'E', 'H'] -> ['AB', 'DE', 'H'] and vice versa currently I wrote some ugly code like: while True: for i, x in enumerate(s): if x == 'A' and s[i+1] == 'B': s[i:i+2] = 'AB' break else: break For people who asking 'why do that thing': Actually I'm working on a optimizing compiler and this is the peephole part. Writing pattern matching is a little annoying.

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  • How to determine whether a linked list contains a loop?

    - by ET
    During a preparation for a job interview, I encountered the following question: How can you determine whether a linked list (of any type) contains a loop, using additional space complexity of O(1)? You cannot assume that the loop starts at the first node (and of course, the loop doesn't have to contain all nodes). I couldn't find the answer, though I have the feeling it's quite simple...

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  • How can I acquire an aggregated list of known proxy IP addresses?

    - by Howard3
    I'd like to use this to help maintain a good defence against people trying to skirt the rules of my system. I've found TOR endpoints, nothing that's readily available to be shot into a script (needs to be parsed) but they work. However I need a list which goes beyond TOR yet I cannot find anything conclusive just yet. Any suggestions would be greatly appreciated.

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  • How should I grab pairs from a list in python?

    - by tomaski
    Say I have a list that looks like this: ['item1', 'item2', 'item3', 'item4', 'item5', 'item6', 'item7', 'item8', 'item9', 'item10'] Using Python, how would I grab pairs from it, where each item is included in a pair with both the item before and after it? ['item1', 'item2'] ['item2', 'item3'] ['item3', 'item4'] ['item4', 'item5'] ['item5', 'item6'] ['item6', 'item7'] ['item7', 'item8'] ['item8', 'item9'] ['item9', 'item10'] Seems like something i could hack together, but I'm wondering if someone has an elegant solution they've used before?

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  • Office 365 - Outlook shows Global Address List clicking "Rooms" during a meeting request

    - by TheCleaner
    This appears to be a "known" issue, but apparently no fix for it. However, I've been impressed before at the tenacity of the experts here to figure out an answer/fix. ISSUE When booking a New Meeting in Outlook (2013 or 2010) and choosing the Rooms button: The default list that opens is the Offline Global Address List: Which means a user has to change from the Offline Global Address List to the All Rooms list as shown here in order to easily pick from the list of actual rooms/resources: This isn't the default however for On-Premise Exchange servers. They default "correctly" to the All Rooms list when you click the Rooms button in the meeting request. While the option of using the Room Finder is there and does work, users have to know to click the Room Finder choice and it doesn't fix the actual root issue here. MY RESEARCH A few links I've found: http://community.office365.com/en-us/forums/158/t/41013.aspx http://community.office365.com/en-us/forums/148/p/24139/113954.aspx http://community.office365.com/en-us/forums/172/t/58824.aspx It was suggested that it might be that the "msExchResourceAddressLists attribute has incorrect value set". I checked my config by running: Get-OrganizationConfig | Select-Object ResourceAddressLists and the output was what it should be: ResourceAddressLists -------------------- {\All Rooms} QUESTION Does anyone have a fix that will make the All Rooms list be the default list when clicking the Rooms button in Outlook when using Office 365 / Exchange Online?

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  • ArrayList<String> NullPointerException

    - by Carlucho
    Am trying to solve a labyrinth by DFS, using adj List to represent the vertices and edges of the graph. In total there are 12 nodes (3 rows[A,B,C] * 4 cols[0,..,3]). My program starts by saving all the vertex labels (A0,..C3), so far so good, then checks the adjacent nodes, also no problems, if movement is possible, it proceeds to create the edge, here its where al goes wrong. adjList[i].add(vList[j].label); I used the debugger and found that vList[j].label is not null it contains a correct string (ie. "B1"). The only variables which show null are in adjList[i], which leads me to believe i have implemented it wrongly. this is how i did it. public class GraphList { private ArrayList<String>[] adjList; ... public GraphList(int vertexcount) { adjList = (ArrayList<String>[]) new ArrayList[vertexCount]; ... } ... public void addEdge(int i, int j) { adjList[i].add(vList[j].label); //NULLPOINTEREXCEPTION HERE } ... } I will really appreaciate if anyone can point me on the right track regrading to what its going wrong... Thanks!

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  • Converting a generic list into JSON string and then handling it in java script

    - by Jalpesh P. Vadgama
    We all know that JSON (JavaScript Object Notification) is very useful in case of manipulating string on client side with java script and its performance is very good over browsers so let’s create a simple example where convert a Generic List then we will convert this list into JSON string and then we will call this web service from java script and will handle in java script. To do this we need a info class(Type) and for that class we are going to create generic list. Here is code for that I have created simple class with two properties UserId and UserName public class UserInfo { public int UserId { get; set; } public string UserName { get; set; } } Now Let’s create a web service and web method will create a class and then we will convert this with in JSON string with JavaScriptSerializer class. Here is web service class. using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Services; namespace Experiment.WebService { /// <summary> /// Summary description for WsApplicationUser /// </summary> [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] [System.ComponentModel.ToolboxItem(false)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. [System.Web.Script.Services.ScriptService] public class WsApplicationUser : System.Web.Services.WebService { [WebMethod] public string GetUserList() { List<UserInfo> userList = new List<UserInfo>(); for (int i = 1; i <= 5; i++) { UserInfo userInfo = new UserInfo(); userInfo.UserId = i; userInfo.UserName = string.Format("{0}{1}", "J", i.ToString()); userList.Add(userInfo); } System.Web.Script.Serialization.JavaScriptSerializer jSearializer = new System.Web.Script.Serialization.JavaScriptSerializer(); return jSearializer.Serialize(userList); } } } Note: Here you must have this attribute here in web service class ‘[System.Web.Script.Services.ScriptService]’ as this attribute will enable web service to call from client side. Now we have created a web service class let’s create a java script function ‘GetUserList’ which will call web service from JavaScript like following function GetUserList() { Experiment.WebService.WsApplicationUser.GetUserList(ReuqestCompleteCallback, RequestFailedCallback); } After as you can see we have inserted two call back function ReuqestCompleteCallback and RequestFailedCallback which handle errors and result from web service. ReuqestCompleteCallback will handle result of web service and if and error comes then RequestFailedCallback will print the error. Following is code for both function. function ReuqestCompleteCallback(result) { result = eval(result); var divResult = document.getElementById("divUserList"); CreateUserListTable(result); } function RequestFailedCallback(error) { var stackTrace = error.get_stackTrace(); var message = error.get_message(); var statusCode = error.get_statusCode(); var exceptionType = error.get_exceptionType(); var timedout = error.get_timedOut(); // Display the error. var divResult = document.getElementById("divUserList"); divResult.innerHTML = "Stack Trace: " + stackTrace + "<br/>" + "Service Error: " + message + "<br/>" + "Status Code: " + statusCode + "<br/>" + "Exception Type: " + exceptionType + "<br/>" + "Timedout: " + timedout; } Here in above there is a function called you can see that we have use ‘eval’ function which parse string in enumerable form. Then we are calling a function call ‘CreateUserListTable’ which will create a table string and paste string in the a div. Here is code for that function. function CreateUserListTable(userList) { var tablestring = '<table ><tr><td>UsreID</td><td>UserName</td></tr>'; for (var i = 0, len = userList.length; i < len; ++i) { tablestring=tablestring + "<tr>"; tablestring=tablestring + "<td>" + userList[i].UserId + "</td>"; tablestring=tablestring + "<td>" + userList[i].UserName + "</td>"; tablestring=tablestring + "</tr>"; } tablestring = tablestring + "</table>"; var divResult = document.getElementById("divUserList"); divResult.innerHTML = tablestring; } Now let’s create div which will have all html that is generated from this function. Here is code of my web page. We also need to add a script reference to enable web service from client side. Here is all HTML code we have. <form id="form1" runat="server"> <asp:ScriptManager ID="myScirptManger" runat="Server"> <Services> <asp:ServiceReference Path="~/WebService/WsApplicationUser.asmx" /> </Services> </asp:ScriptManager> <div id="divUserList"> </div> </form> Now as we have not defined where we are going to call ‘GetUserList’ function so let’s call this function on windows onload event of javascript like following. window.onload=GetUserList(); That’s it. Now let’s run it on browser to see whether it’s work or not and here is the output in browser as expected. That’s it. This was very basic example but you can crate your own JavaScript enabled grid from this and you can see possibilities are unlimited here. Stay tuned for more.. Happy programming.. Technorati Tags: JSON,Javascript,ASP.NET,WebService

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  • How can I css for List/grid in div with border?

    - by Saidul Haque Nayan
    I want to create a list table in DIV with border. When more content of width of a column then line break and border increase but other column border not increase. see the example: Untitled Document /list/ .list_container{ float:left; width: 550px; margin-bottom:10px; font-family: vardana; } .list_row{ float:left; width: 548px; border-bottom:1px #9F9F9F solid; } .list_row:hover{ background-color:#CCCCCC; } .list_rowHeader{ float:left; width: 548px; border-bottom:1px #9F9F9F solid; border-top:1px #9F9F9F solid; font-weight: bold; background-color: #FF0000; color: #FFFFFF; } .list_column{ float:left; padding: 3px; border-left: 1px #9F9F9F solid; } .list_columnLast{ float:left; padding: 3px; border-left: 1px #9F9F9F solid; border-right: 1px #9F9F9F solid; } .even{ background-color:#E0E0E0!important;} .odd{ background-color:#FFFFFF!important;} </style> </head> <body> <div class="list_container" > <div class="list_rowHeader" > <div class="list_column" style="width: 250px;">Name</div> <div class="list_column" style="width: 96px;"> Bid Amount</div> <div class="list_columnLast" style="width: 180px;"> Email </div> </div> <div class="list_row even" > <div class="list_column" style="width: 250px;">Saidul Haque</div> <div class="list_column" style="width: 96px;"> 2131231</div> <div class="list_columnLast" style="width: 180px;"> [email protected]</div> </div> <div class="list_row odd" > <div class="list_column" style="width: 250px;">Saidul Haque, Sonargaon, Bangladesh Dhaka, </div> <div class="list_column" style="width: 96px;"> 2131231</div> <div class="list_columnLast" style="width: 180px;"> [email protected]</div> </div> <div class="list_row even" > <div class="list_column" style="width: 250px;">Saidul Haque</div> <div class="list_column" style="width: 96px;"> 2131231</div> <div class="list_columnLast" style="width: 180px;"> [email protected]</div> </div> </div> </body> Any body solve this problem?

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  • is it wasteful/bad design to use a vector/list where in most instances it will only have one element

    - by lucid
    is it wasteful/bad design to use a vector/list where in most instances it will only have one element? example: class dragon { ArrayList<head> = new ArrayList<head> Heads; tail Tail = new tail(); body Body = new body(); dragon() { theHead=new head(); Heads.add(theHead); } void nod() { for (int i=0;i<Heads.size();i++) { heads.get(i).GoUpAndDown(); } } } class firedragon extends dragon { } class icedragon extends dragon { } class lightningdragon extends dragon { } // 10 other one-headed dragon declarations here class hydra extends dragon { hydra() { anotherHead=new head(); for (int i=0;i<2;i++) { Heads.add(anotherHead); } } } class superhydra extends dragon { superhydra() { anotherHead=new head(); for (int i=0;i<4;i++) { Heads.add(anotherHead); } } }

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  • Is it possible to return a list of all ranges from all worksheets in an Excel 2002 workbook?

    - by generalt
    Hello all. I want to extract "special" data from an Excel 2002 (client requirement, cannot change) workbook and worksheets contained therein. I have classified ranges in this "special" data category. I would like to acquire a list of all ranges in, ideally, all worksheets in a workbook. The attributes I'm interested in are the range name, and the range address. I have been googling for a while now, and have not found anything relevant. I was assuming the Excel 2002 API would expose something like this: ApplicationClass app = new ApplicationClass(); Workbook workbook = app.Workbooks.Open(@"c:\file.xls", ...); Worksheet worksheet = workbook.Worksheets["sheet1"] as Worksheet; Range[] ranges = worksheet.GetAllRanges(); or something similar. However, I am sadly mistaken. Is this possible with Excel 2002?

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  • Convert a generic list to an array

    - by Freewind
    I have searched for this, but unfortunately, I don't get the correct answer. class Helper { public static <T> T[] toArray(List<T> list) { T[] array = (T[]) new Object[list.size()]; for (int i = 0; i < list.size(); i++) { array[i] = list.get(i); } return array; } } Test it: public static void main(String[] args) { List<String> list = new ArrayList<String>(); list.add("abc"); String[] array = toArray(list); System.out.println(array); } But there is an error thrown: Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to [Ljava.lang.String; at test.Helper.main(Helper.java:30) How to solve this?

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  • Properly removing an Integer from a List<Integer>

    - by Yuval A
    Here's a nice pitfall I just encountered. Consider a list of integers: List<Integer> list = new ArrayList<Integer>(); list.add(5); list.add(6); list.add(7); list.add(1); Any educated guess on what happens when you execute list.remove(1)? What about list.remove(new Integer(1))? This can cause some nasty bugs. What is the proper way to differentiate between remove(int index), which removes an element from given index and remove(Object o), which removes an element by reference, when dealing with lists of integers? The main point to consider here is the one @Nikita mentioned - exact parameter matching takes precedence over auto-boxing.

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  • Deleting a node in a circular linked list c++?

    - by angad Soni
    I was wondering if anyone could help me understand if this code for deleting a node from a circular linked list would work, or if there is something i'm missing out on. using c++ to code. void circularList::deleteNode(int x) { node *current; node *temp; current = this-start; while(current->next != this->start) { if(current->next->value == x) { temp = current->next; current->next = current->next->next; delete current->next; } } }

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  • Have I checked every consecutive subset of this list?

    - by Nathan
    I'm trying to solve problem 50 on Project Euler. Don't give me the answer or solve it for me, just try to answer this specific question. The goal is to find the longest sum of consecutive primes that adds to a prime below one million. I use wrote a sieve to find all the primes below n, and I have confirmed that it is correct. Next, I am going to check the sum of each subset of consecutive primes using the following method: I have a empty list sums. For each prime number, I add it to each element in sums and check the new sum, then I append the prime to sums. Here it is in python primes = allPrimesBelow(1000000) sums = [] for p in primes: for i in range(len(sums)): sums[i] += p check(sums[i]) sums.append(p) I want to know if I have called check() for every sum of two or more consecutive primes below one million The problem says that there is a prime, 953, that can be written as the sum of 21 consecutive primes, but I am not finding it.

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  • In Drools Rules, how to use two different ArrayList objects,obj1 is used in rule 1 and obj2 used in rule2?

    - by Jenn
    I am doing ksession.insert(list) and after that I have to fire rule 1 in the drl file, then ksession.insert(list) and fire rule 2 in the drl. Could someone tell me how to achieve this. I read about agenda filters and facthandles but do not really know how to get this to work Below is some code: ArrayList list = new ArrayList(); list.add(product1); list.add(product2); list.add(product3); ksession.insert(list); ksession.fireAllRules("fire rule 1 in drl"); //remove list? ArrayList list2 = new ArrayList(); list2.add(str1); list2.add(str2); list2.add(str3); ksession.insert(list2); ksession.fireAllRules("fire rule 2 in drl");

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  • use proxy from a list

    - by user1505181
    I am trying to write a program which neeeds to use a proxy 3 times then move onto the next proxy in a list and so on. the user will enter their proxy list into a list/textfile and the program will use the first in the list and then carry on through the list until it gets to the end. How do i get the proxy details from the list and use them using httpwebrequest? i have no problem using a proxy if i set it within the code but dont know how to get it to work through the list basically it is like this: user enters a list of proxies into a text file program uses first proxy in list 3 times then moves onto next. this repeats until finished.

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  • In Python, is it better to use list comprehensions or for-each loops?

    - by froadie
    Which of the following is better to use and why? Method 1: for k, v in os.environ.items() print "%s=%s" % (k, v) Method 2: print "\n".join(["%s=%s" % (k, v) for k,v in os.environ.items()]) I tend to lead towards the first as more understandable, but that might just be because I'm new to Python and list comprehensions are still somewhat foreign to me. Is the second way considered more Pythonic? I'm assuming there's no performance difference, but I may be wrong. What would be the advantages and disadvantages of these 2 techniques? (Code taken from Dive into Python)

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  • Segmentation fault in a function to reverse a singly linked list recursivley.

    - by Amanda
    I am implementing a function to recursively reverse a linked-list, but getting seg-fault. typedef struct _node { int data; struct _node *next; } Node, *NodeP; NodeP recursiveReverseList(NodeP first){ if(first == NULL) return NULL; if(first->next == NULL) return first; NodeP rest = recursiveReverseList(first->next); rest->next = first; first->next = NULL; return first; } Can you please help? P.S. The iterative version is working fine though. Its not homework. Just practicing C. Thank you all :)

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  • Sorting and Re-arranging List of HashMaps

    - by HonorGod
    I have a List which is straight forward representation of a database table. I am trying to sort and apply some magic after the data is loaded into List of HashMaps. In my case this is the only hard and fast way of doing it becoz I have a rules engine that actually updates the values in the HashMap after several computations. Here is a sample data representation of the HashMap (List of HashMap) - {fromDate=Wed Mar 17 10:54:12 EDT 2010, eventId=21, toDate=Tue Mar 23 10:54:12 EDT 2010, actionId=1234} {fromDate=Wed Mar 17 10:54:12 EDT 2010, eventId=11, toDate=Wed Mar 17 10:54:12 EDT 2010, actionId=456} {fromDate=Sat Mar 20 10:54:12 EDT 2010, eventId=20, toDate=Thu Apr 01 10:54:12 EDT 2010, actionId=1234} {fromDate=Wed Mar 24 10:54:12 EDT 2010, eventId=22, toDate=Sat Mar 27 10:54:12 EDT 2010, actionId=1234} {fromDate=Wed Mar 17 10:54:12 EDT 2010, eventId=11, toDate=Fri Mar 26 10:54:12 EDT 2010, actionId=1234} {fromDate=Sat Mar 20 10:54:12 EDT 2010, eventId=11, toDate=Wed Mar 31 10:54:12 EDT 2010, actionId=1234} {fromDate=Mon Mar 15 10:54:12 EDT 2010, eventId=12, toDate=Wed Mar 17 10:54:12 EDT 2010, actionId=567} I am trying to achieve couple of things - 1) Sort the list by actionId and eventId after which the data would look like - {fromDate=Wed Mar 17 10:54:12 EDT 2010, eventId=11, toDate=Wed Mar 17 10:54:12 EDT 2010, actionId=456} {fromDate=Mon Mar 15 10:54:12 EDT 2010, eventId=12, toDate=Wed Mar 17 10:54:12 EDT 2010, actionId=567} {fromDate=Wed Mar 24 10:54:12 EDT 2010, eventId=22, toDate=Sat Mar 27 10:54:12 EDT 2010, actionId=1234} {fromDate=Wed Mar 17 10:54:12 EDT 2010, eventId=21, toDate=Tue Mar 23 10:54:12 EDT 2010, actionId=1234} {fromDate=Sat Mar 20 10:54:12 EDT 2010, eventId=20, toDate=Thu Apr 01 10:54:12 EDT 2010, actionId=1234} {fromDate=Wed Mar 17 10:54:12 EDT 2010, eventId=11, toDate=Fri Mar 26 10:54:12 EDT 2010, actionId=1234} {fromDate=Sat Mar 20 10:54:12 EDT 2010, eventId=11, toDate=Wed Mar 31 10:54:12 EDT 2010, actionId=1234} 2) If we group the above list by actionId they would be resolved into 3 groups - actionId=1234, actionId=567 and actionId=456. Now here is my question - For each group having the same eventId, I need to update the records so that they have wider fromDate to toDate. Meaning, if you consider the last two rows they have same actionId = 1234 and same eventId = 11. Now we can to pick the least fromDate from those 2 records which is Wed Mar 17 10:54:12 and farther toDate which is Wed Mar 31 10:54:12 and update those 2 record's fromDate and toDate to Wed Mar 17 10:54:12 and Wed Mar 31 10:54:12 respectively. Any ideas? PS: I already have some pseudo code to start with. import java.util.ArrayList; import java.util.Calendar; import java.util.Collections; import java.util.Comparator; import java.util.Date; import java.util.HashMap; import java.util.List; import org.apache.commons.lang.builder.CompareToBuilder; public class Tester { boolean ascending = true ; boolean sortInstrumentIdAsc = true ; boolean sortEventTypeIdAsc = true ; public static void main(String args[]) { Tester tester = new Tester() ; tester.printValues() ; } public void printValues () { List<HashMap<String,Object>> list = new ArrayList<HashMap<String,Object>>() ; HashMap<String,Object> map = new HashMap<String,Object>(); map.put("actionId", new Integer(1234)) ; map.put("eventId", new Integer(21)) ; map.put("fromDate", getDate(1) ) ; map.put("toDate", getDate(7) ) ; list.add(map); map = new HashMap<String,Object>(); map.put("actionId", new Integer(456)) ; map.put("eventId", new Integer(11)) ; map.put("fromDate", getDate(1)) ; map.put("toDate", getDate(1) ) ; list.add(map); map = new HashMap<String,Object>(); map.put("actionId", new Integer(1234)) ; map.put("eventId", new Integer(20)) ; map.put("fromDate", getDate(4) ) ; map.put("toDate", getDate(16) ) ; list.add(map); map = new HashMap<String,Object>(); map.put("actionId", new Integer(1234)) ; map.put("eventId", new Integer(22)) ; map.put("fromDate",getDate(8) ) ; map.put("toDate", getDate(11)) ; list.add(map); map = new HashMap<String,Object>(); map.put("actionId", new Integer(1234)) ; map.put("eventId", new Integer(11)) ; map.put("fromDate",getDate(1) ) ; map.put("toDate", getDate(10) ) ; list.add(map); map = new HashMap<String,Object>(); map.put("actionId", new Integer(1234)) ; map.put("eventId", new Integer(11)) ; map.put("fromDate",getDate(4) ) ; map.put("toDate", getDate(15) ) ; list.add(map); map = new HashMap<String,Object>(); map.put("actionId", new Integer(567)) ; map.put("eventId", new Integer(12)) ; map.put("fromDate", getDate(-1) ) ; map.put("toDate",getDate(1)) ; list.add(map); System.out.println("\n Before Sorting \n "); for(int j = 0 ; j < list.size() ; j ++ ) System.out.println(list.get(j)); Collections.sort ( list , new HashMapComparator2 () ) ; System.out.println("\n After Sorting \n "); for(int j = 0 ; j < list.size() ; j ++ ) System.out.println(list.get(j)); } public static Date getDate(int days) { Calendar cal = Calendar.getInstance(); cal.setTime(new Date()); cal.add(Calendar.DATE, days); return cal.getTime() ; } public class HashMapComparator2 implements Comparator { public int compare ( Object object1 , Object object2 ) { if ( ascending == true ) { return new CompareToBuilder() .append(( ( HashMap ) object1 ).get ( "actionId" ), ( ( HashMap ) object2 ).get ( "actionId" )) .append(( ( HashMap ) object2 ).get ( "eventId" ), ( ( HashMap ) object1 ).get ( "eventId" )) .toComparison(); } else { return new CompareToBuilder() .append(( ( HashMap ) object2 ).get ( "actionId" ), ( ( HashMap ) object1 ).get ( "actionId" )) .append(( ( HashMap ) object2 ).get ( "eventId" ), ( ( HashMap ) object1 ).get ( "eventId" )) .toComparison(); } } } }

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