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  • MySQL function to compare values in a db table against the previous

    - by Stuart
    Iam quite new to functions in SQL and I would like to create a function to compare values in a MySQL table against previous and I am not sure how to do this. For example (iId is the input value) DECLARE pVal INT(20); DECLARE val INT(20); SELECT price INTO pVal FROM products WHERE Id=iId; SELECT price FROM products; IF price == pVal THEN SET val = price; END IF; Thanks

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  • MySQL - Add Values In Query And Return As Single Value

    - by Sjwdavies
    I'm trying to query a database, and return a set of values. Part of the data i'm trying to return is an insurance premium breakdown. Is it possible to run a query, that selects multiple fields, then adds then and returns them as a single value? I've seen SUM() but the examples i've seen show it as adding up the results of an entire field - where as i need it to add specific fields for each row returned. Any help is much appreciated.

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  • Converting html entities into their values in python

    - by tipu
    I use this regex on some input, [^a-zA-Z0-9@#] However this ends up removing lots of html special characters within the input, such as 227;, #1606;, #1588; (i had to remove the & prefix so that it wouldn't show up as the actual value..) is there a way that I can convert them to their values so that it will satisfy the regexp expression? I also have no idea why the text decided to be so big.

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  • Beautify Integer values for comparing as strings

    - by Zahra
    Hi. For some reason I need to enter my integer values to database as string, then I want to run a query on them and compare those integers as strings. Is there any way to beautify integer numbers (between 1 and 1 US billion as an example) so I can compare them as strings? Thanks in advance.

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  • Different values for Time.now when using activerecord

    - by Josué Lima
    I have this weird situation: When I do on rails console Time.now or Time.zone.now I get the same values (suppose they run at the sime time: 2014-06-05 23:38:06 -0300) But when I use Time.now in a query like: Match.where("datetime = ?", Time.now) it returns the time 3 hours ahead! .to_sql output: SELECT `matches`.* FROM `matches` WHERE (datetime = '2014-06-06 02:38:06') any thoughts on that? Rails 4 Mysql 5.5

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  • Extract two double Values from String using RegEx in Java

    - by tzippy
    I am reading a file by line and need to extract latitude and longitude from it. This how lines can looks: DE 83543 Rott am Inn Bayern BY Oberbayern Landkreis Rosenheim 47.983 12.1278 DE 21147 Hamburg Hamburg HH Kreisfreie Stadt Hamburg 53.55 10 What's for sure is, there are no dots surrounded by digits except for the ones representing the doubles. Unfortunately there are Values without a dot, so it's probably best to check for numbers from the end of the String. thanks for your help!

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  • jquery drop down for selecting multiple values

    - by prince23
    Hi, i want to develop dropdown inside a check box . this url shows me how to do it. http://dropdown-check-list.googlecode.com/svn/trunk/demo.html but the code isnt given how to implement it in project. i need to bind my datatable to this dropdow. and once user selects a value and clicks on the button in .cs file i should be able to get all these values if any one knows how to slove this issue let me know thank you

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  • C++ - 3 possible values in Variable?

    - by noryb009
    I need to store a 30 letter combination, but each letter can only be "0", "1" or "2". When I use sizeof(myString), it returns 32. I want to use this 30 letter combination to access a row of an array, so I'm wondering if it is possible to use a 3 value bool of some sort to store 1 of 3 values in.

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  • Finding unique maximum values in a list using python

    - by mikip
    Hi I have a list of points as shown below points=[ [x0,y0,v0], [x1,y1,v1], [x2,y2,v2].......... [xn,yn,vn]] Some of the points have duplicate x,y values. What I want to do is to extract the unique maximum value x,y points For example, if I have points [1,2,5] [1,1,3] [1,2,7] [1,7,3] I would like to obtain the list [1,1,3] [1,2,7] [1,7,3] How can I do this in python Thanks

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  • hibernate annotation- extending base class - values are not being set - strange error

    - by gt_ebuddy
    I was following Hibernate: Use a Base Class to Map Common Fields and openjpa inheritance tutorial to put common columns like ID, lastModifiedDate etc in base table. My annotated mappings are as follow : BaseTable : @MappedSuperclass public abstract class BaseTable { @Id @GeneratedValue @Column(name = "id") private int id; @Column(name = "lastmodifieddate") private Date lastModifiedDate; ... Person table - @Entity @Table(name = "Person ") public class Person extends BaseTable implements Serializable{ ... Create statement generated : create table Person (id integer not null auto_increment, lastmodifieddate datetime, name varchar(255), primary key (id)) ; After I save a Person object to db, Person p = new Person(); p.setName("Test"); p.setLastModifiedDate(new Date()); .. getSession().save(p); I am setting the date field but, it is saving the record with generated ID and LastModifiedDate = null, and Name="Test". Insert Statement : insert into Person (lastmodifieddate, name) values (?, ?) binding parameter [1] as [TIMESTAMP] - <null> binding parameter [2] as [VARCHAR] - Test Read by ID query : When I do hibernate query (get By ID) as below, It reads person by given ID. Criteria c = getSession().createCriteria(Person.class); c.add(Restrictions.eq("id", id)); Person person= c.list().get(0); //person has generated ID, LastModifiedDate is null select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] ReadAll query : //read all Query query = getSession().createQuery("from " + Person.class.getName()); List allPersons=query.list(); Corresponding SQL for read all select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] - Found [2] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test2] as column [person8_] But when I print out the list in console, its being more weird. it is selecting List of Person object with ID fields = all 0 (why all 0 ?) LastModifiedDate = null Name fields have valid values I don't know whats wrong here. Could you please look at it? FYI, My Hibernate-core version : 4.1.2, MySQL Connector version : 5.1.9 . In summary, There are two issues here Why I am getting All ID Fields =0 when using read all? Why the LastModifiedDate is not being inserted?

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  • length between 2 values

    - by alex
    In R, what is the most efficient way to count the length between 2 values. for example, i have vector x , which are all randomly choose from 1 to 100, how can i find out the length between the first"2" and first"40", x=(1,2,3,4,5,6,7,40,1,2,3,21,4,1,23,4,43,23,4,12,3,43,5,36,3,45,12,31,3,4,23,41,23,5,53,45,3,7,6,36) for this vector, the answer should be 5 and 6

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  • Hiernate's version values in Grails app

    - by xain
    Hi, looking at a database dump file, and I see many records in various tables with their version number set in values other than 0 (even 94 in one case). I understand it has to do with hibernate locking strategy, but my concern is that today is Sunday, and the site has almost no visitors so is: is this normal ? Or is there a known hibernate bug or even some programming malpractice producing this ? Thanks in advance.

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