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  • How to create a default association for files with no extension

    - by acidzombie24
    I am using http://www.pnotepad.org/ (i wouldnt mind switching to something else if it lightweight and has most/all features i like which i'll check on a app by app basis) When i create a new tab/file and save it unless i write .txt i get a file with no extention. Which makes it hard to open since i cant double click it (i dont think i can tell win7 to set a default app for files with no extension) How do i make pnotepad save with a .txt when non are specified?

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  • How to create a ghost environment?

    - by manwood
    I want to create a ghost or image of a fresh Windows XP development environment with all the various bits of software installed and ready to go, so that when the OS gets clogged or the main disk fails I can simply install the ghost rather than having to run through the entire install and setup process all over again. What is the best way to go about doing this? Cheers.

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  • Create an image of a CentOS system

    - by Grant unwin
    I provide a server (and site) to a client via Rackspace Cloud Hosting, and my client wants to now host the entire thing within his own account. Since it's not possible to just transfer the ownership, I need to somehow create an image of the machine via SSH which I can then use on a new server. Is this possible, and does anyone know of a way of doing this. Note I am talking about virtualised machines here, but I only have access to the virtualised partition and not the system as a whole.

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  • Data Sources (ODBC) hangs when trying to create a new database connection

    - by FredrikD
    When I try to create a new database connection, the Data Sources (ODBC) programs hangs or takes a very long time to find the list of available SQL Servers. This only happens when there are other computers on the network, when my machine (a standard Windows 7 laptop) is alone, it works just fine. My question is: What should I look for in terms of SQL server or ODBC configurations that will take away this random behaviour?

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  • Create text file named after a cell containing other cell data

    - by user143041
    I tried using the code below for the Excel program on my `Mac Mini using the OS X Version 10.7.2 and it keeps saying Error due to file name / path: (The Excel file I am creating is going to be a template with my formulas and macros installed which will be used over and over). Sub CreateFile() Do While Not IsEmpty(ActiveCell.Offset(0, 1)) MyFile = ActiveCell.Value & ".txt" fnum = FreeFile() Open MyFile For Output As fnum Print #fnum, ActiveCell.Offset(0, 1) & " " & ActiveCell.Offset(0, 2) Close #fnum ActiveCell.Offset(1, 0).Select Loop End Sub What Im trying to do: 1st Objective I would like to have the following data to be used to create a text file. A:A is what I need the name of the file to be. B:2 is the content I need in the text file. So, A2 - "repair-video-game-Glassboro-NJ-08028.txt" is the file name and B2 to be the content in the file. Next, A3 is the file name and B3 is the content for the file, etc. ONCE the content reads what is in cell A16 and B16 (length will vary), the file creation should stop, if not then I can delete the additional files created. This sheet will never change. Is there a way to establish the excel macro to always go to this sheet instead of have to select it with the mouse to identify the starting point? 2nd Objective I would like to have the following data to be used to create a text file. A:1 is what I need the name of the file to be. B:B is the content I want in the file. So, A2 - is the file name "geo-sitemap.xml" and B:B to be the content in the file (ignore the .xml file extension in the photo). ONCE the content cell reads what is in cell "B16" (length will vary), the file creation should stop, if not then I can adjust the cells that have need content (formulated content you see in the image is preset for 500 rows). This sheet will never change. Is there a way to establish the excel macro to always go to this sheet instead of have to select it with the mouse to identify the starting point? I can Provide the content in the cells that are filled in by excel formulas that are not not to be included in the .txt files. It is ok if it is not possible. I can delete the extra cells that are not populated (based on the data sheet). Please let me know if you need any more additional information or clarity and I will be happy to provide it.

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  • How can I create my own Android Home Screen Launcher

    - by Sam_k
    I want to know how I can create my own customised home screen for Android. I have used Viewpager to add and remove screens from the home screen, creating 5 screens as default, and then adding and removing further pages in with ViewPager. I have tried both Viewpager and PagerAdapter, as per this link. Is this the best approach so that in future I can add widgets and shortcuts with viewpager and make a launcher icon?

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  • Linux: Create files and direcotires but not delete them

    - by Peraz
    I have a process that create directories and files inside a working directory, ex: /workingdir/file1 /workingdir/file2 /workingdir/dir1/file1 /workingdir/dir1/dir2/file1 /workingdir/dir1/file2 I need to avoid deletion/overwrites of created folders/files for that user, but allow subsequent folders/subfolders/files creation. I try permissions, gid, acl with no luck. What is the correct way to do that ? (i can use a cron job if needed)

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  • create iso from windows xp 64 setup files...

    - by alma
    hi i have the following windows xp 64 bit files(starting with uppercase letter are folders): Amd64, Docs,I386,Support,autorun,readme,setup,... how can i create the iso from these files? it keeps asking for boot image file? i try to burn it(as bootable disc) into cd, but it asks for boot image? where is boot image file?

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  • create shortcut in kubuntu for tora.

    - by darkapple
    I've installed TOra with a tutorial I found. So, to start TOra, I've to go to terminal and type following command '/usr/local/tora/bin/tora'. I want create a applicaion link in desktop to TOra. I tried creating application link but in terminal I see following /usr/local/tora/bin/tora: error while loading shared libraries: libclntsh.so.11.1: cannot open shared object file: No such file or directory help

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  • Cannot create Windows Service for MySQL (Vista)

    - by Matt W
    I uninstalled MySQL 5.1 from Vista as I lost the username/password, however I forgot to stop the MySQL service before doing so. Now whenever I try to reinstall it I get to the final configuration screen which then fails with the message "Cannot create Windows Service for MySQL Error:0". I've uninstalled MySQL and removed all related files/folders/registry entries but still no joy... Does anyone know a way to resolve this as I can't seem to find a fix online anywhere!

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  • Create a primary partition on Windows 7

    - by TutorialPoint
    I have windows 7 installed. On the moment i have the following partitions on 1 hard disk: (300 GB) C: (Windows) (Primary, System, Boot, Page File, Crash Dump, Active) 100 GB D: (Data) (Logical) 100 GB E: (System Reserved created after Boot repair) (primary, system) 100 MB Now i want to create a new primary partition on this disk, because i have +/- 100 GB left, for a new OS. However when trying to make a new partition, it makes it a Logical partition, not Primary. How to make it primary...?

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  • Augeas - create new ini section

    - by Tim Brigham
    I have a config file in augeas using a custom lens that outputs the data as follows. /files/opt/../server.conf/target[1] = "general" /files/opt/../server.conf/target[1]/serverName = "XXX" /files/opt/../server.conf/target[1]/guid = "XXX0XXX" /files/opt/../server.conf/target[2] = "sslConfig" /files/opt/../server.conf/target[2]/sslKeysfilePassword = "$1$XXXXX" This works well - some of the target names contain colons, etc so I need to use the target[x] format. What is the correct ins syntax to create a new section in my INI using this syntax?

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  • Windows8.1 create shortcuts with a custom group in My Computer

    - by user222010
    I have did many research about this. And what I could gather is something like this http://lifehacker.com/add-any-shortcut-to-my-computer-with-this-simple-tweak-479751317. The problem with that is it put the shortcuts under the Network Shortcuts, and this is not what I want. I want to create a shortcut in the My Computer explorer under a specific group such as Important Apps. So, how can I get that?

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  • How to create a database deadlock using jdbc and JUNIT

    - by Isawpalmetto
    I am trying to create a database deadlock and I am using JUnit. I have two concurrent tests running which are both updating the same row in a table over and over again in a loop. My idea is that you update say row A in Table A and then row B in Table B over and over again in one test. Then at the same time you update row B table B and then row A Table A over and over again. From my understanding this should eventually result in a deadlock. Here is the code For the first test. public static void testEditCC() { try{ int rows = 0; int counter = 0; int large=10000000; Connection c=DataBase.getConnection(); while(counter<large) { int pid = 87855; int cCode = 655; String newCountry="Egypt"; int bpl = 0; stmt = c.createStatement(); rows = stmt.executeUpdate("UPDATE main " + //create lock on main table "SET BPL="+cCode+ "WHERE ID="+pid); rows = stmt.executeUpdate("UPDATE BPL SET DESCRIPTION='SomeWhere' WHERE ID=602"); //create lock on bpl table counter++; } assertTrue(rows == 1); //rows = stmt.executeUpdate("Insert into BPL (ID, DESCRIPTION) VALUES ("+cCode+", '"+newCountry+"')"); } catch(SQLException ex) { ex.printStackTrace(); //ex.getMessage(); } } And here is the code for the second test. public static void testEditCC() { try{ int rows = 0; int counter = 0; int large=10000000; Connection c=DataBase.getConnection(); while(counter<large) { int pid = 87855; int cCode = 655; String newCountry="Jordan"; int bpl = 0; stmt = c.createStatement(); //stmt.close(); rows = stmt.executeUpdate("UPDATE BPL SET DESCRIPTION='SomeWhere' WHERE ID=602"); //create lock on bpl table rows = stmt.executeUpdate("UPDATE main " + //create lock on main table "SET BPL="+cCode+ "WHERE ID="+pid); counter++; } assertTrue(rows == 1); //rows = stmt.executeUpdate("Insert into BPL (ID, DESCRIPTION) VALUES ("+cCode+", '"+newCountry+"')"); } catch(SQLException ex) { ex.printStackTrace(); } } I am running these two separate JUnit tests at the same time and am connecting to an apache Derby database that I am running in network mode within Eclipse. Can anyone help me figure out why a deadlock is not occurring? Perhaps I am using JUnit wrong.

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  • Routing error when trying to use same view for update and create flows (Rails 3)

    - by Jamis Charles
    My overall use case: I have a Listing model that has many images. The Listing detail page lists all the fields that can be updated inline (through ajax). I want to be able to use the same view for both update listing and create new listing. My listing controller looks as follows: def detail @listing = Listing.find(params[:id]) @image = Image.new #should this link somewhere else? respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end def create # create a new listing and save it immediately. Assign it to guest, with a status of "draft" @listing = Listing.new(:price_id => 1) # Default price id # save it to db # TODO add validation that it has to have a price ID, on record creation. So the view doesn't break. @listing.save @image = Image.new # redirect_to "/listings/detail/@listing.id" #this didn't work respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end The PROBLEM I'm using a partial that shows the same form for the create view and the detail view. This works perfectly except for one thing: When I pull up http://0.0.0.0:3000/listings/detail/7, it works perfectly. When I pull up http://0.0.0.0:3000/listings/new, I get the following error: Showing /Applications/MAMP/htdocs/rails_testing/feedbackd/app/views/listings/_edit_form.html.erb where line #100 raised: No route matches {:action="show", :controller="images"} Extracted source (around line #100): 97: <!-- Form for new images --> 98: <div class="span-20 append-bottom"> 99: <!-- <%# form_for :image, @image, :url => image_path, :html => { :multipart => true } do |f| %> --> 100: <%= form_for @image, :url => image_path, :html => { :multipart => true } do |f| %> 101: <%= f.text_field :description %><br /> 102: <%= f.file_field :photo %> 103: <%= submit_tag "Upload" %> What I think the issue is: When I upload a new image (I'm using Paperclip), it requires the listing_id to create the image record. Since the listing_id isn't passed in with listings/new it can't find the listing_id. How can I pass in the id? Via a redirect? What's the best way to solve this? Thank you.

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  • Ruby on Rails: create records for multiple models with one form and one submit

    - by notblakeshelton
    I have a 3 models: quote, customer, and item. Each quote has one customer and one item. I would like to create a new quote, a new customer, and a new item in their respective tables when I press the submit button. I have looked at other questions and railscasts and either they don't work for my situation or I don't know how to implement them. I also want my index page to be the page where I can create everything. quote.rb class Quote < ActiveRecord::Base attr_accessible :quote_number has_one :customer has_one :item end customer.rb class Customer < ActiveRecord::Base #unsure of what to put here #a customer can have multiple quotes, so would i use: has_many :quotes #<----? end item.rb class Item < ActiveRecord::Base #also unsure about this #each item can also be in multiple quotes quotes_controller.rb class QuotesController < ApplicationController def index @quote = Quote.new @customer = Customer.new @item = item.new end def create @quote = Quote.new(params[:quote]) @quote.save @customer = Customer.new(params[:customer]) @customer.save @item = Item.new(params[:item]) @item.save end end items_controller.rb class ItemsController < ApplicationController def index end def new @item = Item.new end def create @item = Item.new(params[:item]) @item.save end end customers_controller.rb class CustomersController < ApplicationController def index end def new @customer = Customer.new end def create @customer = Customer.new(params[:customer]) @customer.save end end quotes/index.html.erb <%= form_for @quote do |f| %> <%= f.fields_for @customer do |builder| %> <%= label_tag :firstname %> <%= builder.text_field :firstname %> <%= label_tag :lastname %> <%= builder.text_field :lastname %> <% end %> <%= f.fields_for @item do |builder| %> <%= label_tag :name %> <%= builder.text_field :name %> <%= label_tag :description %> <%= builder.text_field :description %> <% end %> <%= label_tag :quote_number %> <%= f.text_field :quote_number %> <%= f.submit %> <% end %> When I try submitting that I get an error: Can't mass-assign protected attributes: item, customer So to try and fix it I updated the attr_accessible in quote.rb to include :item, :customer but then I get this error: Item(#) expected, got ActiveSupport::HashWithIndifferentAccess(#) Any help would be greatly appreciated.

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  • Create a WCF REST Client Proxy Programatically (in C#)

    - by Tawani
    I am trying to create a REST Client proxy programatically in C# using the code below but I keep getting a CommunicationException error. Am I missing something? public static class WebProxyFactory { public static T Create<T>(string url) where T : class { ServicePointManager.Expect100Continue = false; WebHttpBinding binding = new WebHttpBinding(); binding.MaxReceivedMessageSize = 1000000; WebChannelFactory<T> factory = new WebChannelFactory<T>(binding, new Uri(url)); T proxy = factory.CreateChannel(); return proxy; } public static T Create<T>(string url, string userName, string password) where T : class { ServicePointManager.Expect100Continue = false; WebHttpBinding binding = new WebHttpBinding(); binding.Security.Mode = WebHttpSecurityMode.TransportCredentialOnly; binding.Security.Transport.ClientCredentialType = HttpClientCredentialType.Basic; binding.UseDefaultWebProxy = false; binding.MaxReceivedMessageSize = 1000000; WebChannelFactory<T> factory = new WebChannelFactory<T>(binding, new Uri(url)); ClientCredentials credentials = factory.Credentials; credentials.UserName.UserName = userName; credentials.UserName.Password = password; T proxy = factory.CreateChannel(); return proxy; } } So that I can use it as follows: IMyRestService proxy = WebProxyFactory.Create<IMyRestService>(url, usr, pwd); var result = proxy.GetSomthing(); // Fails right here

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  • ASP.NET MVC DropDownList SelectedValue works on Edit action, but not Create action

    - by davekaro
    I have the following code in my controller (for Edit and Create): model.Templates = new SelectList(PageManagementService.PageTemplateFetchList(), "PageId", "Title", 213); the "213" is an Id for one of the pages - just using it for testing. And this is in my view (for Edit and Create): <%= this.Html.DropDownListFor(model => model.Page.TemplateId, this.Model.Templates)%> <%= this.Model.Templates.SelectedValue %> When I go to the Create form, I see the dropdown list, but the tag with value="213" is not selected. I even output the SelectedValue to make sure it's 213 - and I see 213. When I go to the Edit form, I see the dropdown list, and the tag with value="213" is selected. On the Create form, none of the tags have a "selected" attribute. On the Edit form, the tag with value="213" has the "selected" attribute. Am I missing something? What could be causing this? Anyone see this behavior before?

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