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  • How to create an Universal Binary for iTunes Connect Distribution?

    - by balexandre
    I created an app that was rejected because Apple say that my App was not showing the correct iPad window and it was showing the same iPhone screen but top left aligned. Running on simulator, I get my App to show exactly what it should, a big iPad View. my app as Apple referees that is showing on device: my app running the simulator (50% zoom only): my code in the Application Delegate is the one I published before - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { // The default have the line below, let us comment it //MainViewController *aController = [[MainViewController alloc] initWithNibName:@"MainView" bundle:nil]; // Our main controller MainViewController *aController = nil; // Is this OS 3.2.0+ ? #if __IPHONE_OS_VERSION_MAX_ALLOWED >= 30200 if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) // It's an iPad, let's set the MainView to our MainView-iPad aController = [[MainViewController alloc] initWithNibName:@"MainView-iPad" bundle:nil]; else // This is a 3.2.0+ but not an iPad (for future, when iPhone/iPod Touch runs with same OS than iPad) aController = [[MainViewController alloc] initWithNibName:@"MainView" bundle:nil]; #else // It's an iPhone/iPod Touch (OS < 3.2.0) aController = [[MainViewController alloc] initWithNibName:@"MainView" bundle:nil]; #endif // Let's continue our default code self.mainViewController = aController; [aController release]; mainViewController.view.frame = [UIScreen mainScreen].applicationFrame; [window addSubview:[mainViewController view]]; [window makeKeyAndVisible]; return YES; } on my target info I have iPhone/iPad My question is, how should I build the app? Use Base SDK iPhone Simulator 3.1.3 iPhone Simulator 3.2 my Active Configuration is Distribution and Active Architecture is arm6 Can anyone that already published app into iTunes Connect explain me the settings? P.S. I followed the Developer Guideline on Building and Installing your Development Application that is found on Creating and Downloading Development Provisioning Profiles but does not say anything regarding this, as I did exactly and the app was rejected.

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  • Why can't I refresh the list of packages?

    - by Elysium
    This might be a duplicate, but I can't find a solution in other posts. Whenever I try to update I get this message: ERROR###ERROR###ERROR###ERROR###ERROR###ERROR###ERROR E:Encountered a section with no Package: header, E:Problem with MergeList /var/lib/apt/listspackages.medibuntu.org_dists_quantal_free_i18n_Translation-en, E:The package lists or status file could not be parsed or opened. I have tried runnig this in the terminal: sudo rm /var/lib/apt/lists/* -vf sudo apt-get update It doesn't work at all. I cant even open the software sources and "sudo apt-get check" gives me this message: Reading package lists... Error! E: Encountered a section with no Package: header E: Problem with MergeList /var/lib/apt/lists/packages.medibuntu.org_dists_quantal_free_i18n_Translation-en E: The package lists or status file could not be parsed or opened. UPDATE: solution for me was to remove the medibuntu-keyring through synaptic manager and removed mediubuntu from the software sources too manually. This seems to have solved the problem. The update manager doesnt give me any error messages anymore.

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  • using '.each' method: how do I get the indexes of multiple ordered lists to each begin at [0]?

    - by shecky
    I've got multiple divs, each with an ordered list (various lengths). I'm using jquery to add a class to each list item according to its index (for the purpose of columnizing portions of each list). What I have so far ... <script type="text/javascript"> /* Objective: columnize list items from a single ul or ol in a pre-determined number of columns 1. get the index of each list item 2. assign column class according to li's index */ $(document).ready(function() { $('ol li').each(function(index){ // assign class according to li's index ... index = li number -1: 1-6 = 0-5; 7-12 = 6-11, etc. if ( index <= 5 ) { $(this).addClass('column-1'); } if ( index > 5 && index < 12 ) { $(this).addClass('column-2'); } if ( index > 11 ) { $(this).addClass('column-3'); } // add another class to the first list item in each column $('ol li').filter(function(index) { return index != 0 && index % 6 == 0; }).addClass('reset'); }); // closes li .each func }); // closes doc.ready.func </script> ... succeeds if there's only one list; when there are additional lists, the last column class ('column-3') is added to all remaining list items on the page. In other words, the script is presently indexing continuously through all subsequent lists/list items, rather than being re-set to [0] for each ordered list. Can someone please show me the proper method/syntax to correct/amend this, so that the script addresses/indexes each ordered list anew? many thanks in advance. shecky p.s. the markup is pretty straight-up: <div class="tertiary"> <h1>header</h1> <ol> <li><a href="#" title="a link">a link</a></li> <li><a href="#" title="a link">a link</a></li> <li><a href="#" title="a link">a link</a></li> </ol> </div><!-- END div class="tertiary" -->

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  • How do I connect multiple sortable lists to each other in jQuery UI?

    - by Abs
    I'm new to jQuery, and I'm totally struggling with using jQuery UI's sortable. I'm trying to put together a page to facilitate grouping and ordering of items. My page has a list of groups, and each group contains a list of items. I want to allow users to be able to do the following: 1. Reorder the groups 2. Reorder the items within the groups 3. Move the items between the groups The first two requirements are no problem. I'm able to sort them just fine. The problem comes in with the third requirement. I just can't connect those lists to each other. Some code might help. Here's the markup. <ul id="groupsList" class="groupsList"> <li id="group1" class="group">Group 1 <ul id="groupItems1" class="itemsList"> <li id="item1-1" class="item">Item 1.1</li> <li id="item1-2" class="item">Item 1.2</li> </ul> </li> <li id="group2" class="group">Group 2 <ul id="groupItems2" class="itemsList"> <li id="item2-1" class="item">Item 2.1</li> <li id="item2-2" class="item">Item 2.2</li> </ul> </li> <li id="group3" class="group">Group 3 <ul id="groupItems3" class="itemsList"> <li id="item3-1" class="item">Item 3.1</li> <li id="item3-2" class="item">Item 3.2</li> </ul> </li> </ul> I was able to sort the lists by putting $('#groupsList').sortable({}); and $('.itemsList').sortable({}); in the document ready function. I tried using the connectWith option for sortable to make it work, but I failed spectacularly. What I'd like to do is have the every groupItemsX list connected to every groupItemsX list but itself. How should I do that?

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  • How to convert linq entitySet AND CHILDREN to lists?

    - by Abe Miessler
    I ran into an error when trying to serialize a linq entitySet. To get around this i converted the entitySet to a list. The problem I have run into now is that it's child entity sets are not converting to a list and when I try to serialize the parent those are now throwing an error. Does anyone know of a way to convert a linq entitySet AND it's children to lists? p.s. I'm new to linq so if any of this dosn't make sense let me know

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  • How to drag items between 2 sorted lists with jQuery?

    - by sa125
    Hi - I'm trying to implement drag/drop/sort between 2 list elements: <ul id="first"> <li>item 1</li> <li>item 2</li> <li>item 3</li> </ul> <ul id="second"> <li>item 4</li> <li>item 5</li> <li>item 6</li> </ul> Basically I just want to be able to pass items between the lists and sort the items in each list. What's the simplest way to implement this using jQuery?

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  • Most efficent way to create all possible combinations of four lists in Python?

    - by Baresi
    I have four different lists. headers, descriptions, short_descriptions and misc. I want to combine these into all the possible ways to print out: header\n description\n short_description\n misc like if i had (i'm skipping short_description and misc in this example for obvious reasons) headers = ['Hello there', 'Hi there!'] description = ['I like pie', 'Ho ho ho'] ... I want it to print out like: Hello there I like pie ... Hello there Ho ho ho ... Hi there! I like pie ... Hi there! Ho ho ho ... What would you say is the best/cleanest/most efficent way to do this? Is for-nesting the only way to go?

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  • In SICP exercise 2.26 using DrScheme, why does cons return a list, instead of a pair of lists?

    - by limist
    In SICP exercise 2.26, this Scheme code is given: (define x (list 1 2 3)) (define y (list 4 5 6)) Then this cons call is given: (cons x y) I expected a pair of lists would result, ((1 2 3) (4 5 6)) but the interpreter gives, ((1 2 3) 4 5 6) ...a list with 4 elements, the first being a list. Why is y treated differently? I've tried looking up other SICP answers for an explanation, but couldn't find something satisfactory. So could any Scheme/Lisp experts please shed some light on this aspect of cons? Thanks in advance for any insight.

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  • How do I get Mathematica to thread a 2-variable function over two lists, using functional programmin

    - by Leah Wrenn Berman
    Lets say I have a function f[x_, y_], and two lists l1, l2. I'd like to evaluate f[x,y] where x runs over the list l1 and y runs over the list l2, and I'd like to do it without having to make all pairs of the form {l1[[i]],l2[[j]]}. (Motivation: I'm trying to implement some basic Haskell programs in Mathematica. In particular, I'd like to be able to code the Haskell program isMatroid::[[Int]]->Bool isMatroid b =and[or[sort(union(xs\\[x])[y]'elem'b|y<-ys]|xs<-b,ys<-b, xs<-x] I think I can do the rest of it, if I can figure out the original question, but I'd like the code to be Haskell-like. Any suggestions for implementing Haskell-like code in Mathematica would be appreciated.)

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  • Why are difference lists more efficient than regular concatenation?

    - by Craig Innes
    I am currently working my way through the Learn you a haskell book online, and have come to a chapter where the author is explaining that some list concatenations can be ineffiecient: For example ((((a ++ b) ++ c) ++ d) ++ e) ++ f Is supposedly inefficient. The solution the author comes up with is to use 'difference lists' defined as newtype DiffList a = DiffList {getDiffList :: [a] -> [a] } instance Monoid (DiffList a) where mempty = DiffList (\xs -> [] ++ xs) (DiffList f) `mappend` (DiffList g) = DiffList (\xs -> f (g xs)) I am struggling to understand why DiffList is more computationally efficient than a simple concatenation in some cases. Could someone explain to me in simple terms why the above example is so inefficient, and in what way the DiffList solves this problem?

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  • Can anyone help with java? Finding common nodes from two linked lists using recursion

    - by Dan
    I have to write a method that returns a linked list with all the nodes that are common to two linked lists using recursion, without loops. For example, first list is 2 - 5 - 7 - 10 second list is 2 - 4 - 8 - 10 the list that would be returned is 2 - 10 I am getting nowhere with this.. What I have been think of was to check each value of the first list with each value of the second list recursively but the second list would then be cut by one node everytime and I cannot compare the next value in the first list with the the second list. I hope this makes sense... Can anyone help?

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  • Python - Flatten a dict of lists into unique values?

    - by Jonathan Vanasco
    I have a dict of lists in python: content = {88962: [80, 130], 87484: [64], 53662: [58,80]} I want to turn it into a list of the unique values [58,64,80,130] I wrote a manual solution, but it's a manual solution. I know there are more concise and more elegant way to do this with list comprehensions, map/reduce , itertools , etc. anyone have a clue ? content = {88962: [80, 130], 87484: [64], 53662: [58,80]} result = set({}) for k in content.keys() : for i in content[k]: result.add(i) # and list/sort/print just to compare the output r2 = list( result ) r2.sort() print r2

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  • What's the proper way of importing option lists into an Android app?

    - by Scott
    I have been storing option lists for my Android app in a cloud table. For example, categories like "historical fiction","biography","science fiction", etc. I see the following pros and cons: Pro: I can make changes to the list without sending an app update to Google Play Not normalized - I can use the text in my other data tables instead of a reference ID Con: App needs to take time to download from the web each time (or at least check for changes) English only I believe the "proper" way to do this is the use the XML resource files. But I need to make sure the selection references correctly with my data. That is, my app needs to understand that "Poetry" and "Poesía" are the same thing. Is the correct thing to do: Forget about it since I'll never get to the point where I'm translating my app anyway Use a string-array and use the index (0...x) to know what the selection is Use a 2-dimensional string-array with a reference ID in the first column and the text in the second?

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  • How do I avoid nesting forms when offering inline editing of lists with checkboxes for mass updates.

    - by adam
    A lot of sites offer the ability to edit lists of items inline as well as allowing multiple items to be selected via checkboxes and have an action performed all at once e.g. delete, mark as spam etc. But how do you implement this without violating html rules. I need one form for the checkboxes with individual submit_tags for the mass actions. But after a user clicks on an item in the list, another form via Ajax will be inserted within the checkbox form. How do I avoid doing this? I'm using rails and jQuery.

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  • How would I initialize these two lists so that modifying one doesn't modify the other?

    - by Brandon
    I'm aware of why this is happening, but is there any way to do this without having to implement ICloneable or a Copy() method? Preferably .net 2.0, but 3.5 is fine if it is necessary. Essentially I'm trying to implement an undo method. In most cases I can just perform the reverse action in the Undo(), but for others that is not possible. So I want to keep two lists. One for the list of items that I will be modifying, and one for the original, unmodified list of items. This way if I need to do an undo, I just delete the modified items and replace them with the originals. Most of the ways I've tried to assign the _originalItems variable doesn't work, so what would I need to do? public MyClass(List<SelectedItems> selectedItems) { _selectedItems = new List<SelectedItems>(selectedItems); _originalItems = ?? }

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  • How can I convert this string to list of lists?

    - by Phrixus
    Hi, what I'm trying to do is.. if a user types in [[0,0,0], [0,0,1], [1,1,0]] and press enter, the program should convert this string to several lists; one list holding [0][0][0], other for [0][0][1], and the last list for [1][1][0] I thought tuple thing would work out but no luck... :( I started phython yesterday -- (I'm C / C++ guy.) and cannot use the full advantages of this language... Does python have a good way to handle this? I need help~ :'(

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  • How do I remove initial indents on numbered lists?

    - by Peter
    In Word 2007 I want all numbers in a numbered list to be down the LH margin in line with the paragraphs. When a numbered list is selected, the numbers 1,2,3 are indented by a default 0.63cm. Ctrl-Shift-M will shift this indent back to the left margin. How do I permanently remove that initial indent and save that change to the normal template so that all new documents have zero indent on a newly inserted numbered list? (Same issue in Word 2010)

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  • Can Windows 7 Jump Lists be made to behave like menus when dragged out with a mouse?

    - by FocusStealer
    On a traditional menu, if you mousedown on the menu title, drag down, then release on a menu item, it will trigger that menu item immediately, e.g. in Notepad: Left mouse button down on File Drag down to New Release mouse button will start a new file without requiring an additional click. However, when dragging out a Jump List on Windows 7, you must additionally click the desired item to launch it. Is there any way to change this behavior?

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