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  • django flatpage redirects

    - by Joe
    I want to make sure all of my flatpages have the "www" subdomain and redirect to it if they don't. I've looked at some middlewares that redirect to www, but 1. they usually redirect all urls to www and 2. the ones I've found don't work with flatpages. I don't want all of my site urls to redirect to include the www subdomian, just the flatpages. Anyone know how I should go about doing this? Thanks

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  • Permission to view, but not to change! - Django

    - by RadiantHex
    Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

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  • How to loop X times in Django?

    - by Mark
    I have user reviews on my site. Each review has a rating of 1-5 stars. I want to print that many stars. How do I do it? I only see {% for X in Y %} which lets you iterate over a list, but not a certain number of times.

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  • CharField values disappearing after save (readonly field)

    - by jamida
    I'm implementing simple "grade book" application where the teacher would be able to update the grades w/o being allowed to change the students' names (at least not on the update grade page). To do this I'm using one of the read-only tricks, the simplest one. The problem is that after the SUBMIT the view is re-displayed with 'blank' values for the students. I'd like the students' names to re-appear. Below is the simplest example that exhibits this problem. (This is poor DB design, I know, I've extracted just the relevant parts of the code to showcase the problem. In the real example, student is in its own table but the problem still exists there.) models.py class Grade1(models.Model): student = models.CharField(max_length=50, unique=True) finalGrade = models.CharField(max_length=3) class Grade1OForm(ModelForm): student = forms.CharField(max_length=50, required=False) def __init__(self, *args, **kwargs): super(Grade1OForm,self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) if instance and instance.id: self.fields['student'].widget.attrs['readonly'] = True self.fields['student'].widget.attrs['disabled'] = 'disabled' def clean_student(self): instance = getattr(self,'instance',None) if instance: return instance.student else: return self.cleaned_data.get('student',None) class Meta: model=Grade1 views.py from django.forms.models import modelformset_factory def modifyAllGrades1(request): gradeFormSetFactory = modelformset_factory(Grade1, form=Grade1OForm, extra=0) studentQueryset = Grade1.objects.all() if request.method=='POST': myGradeFormSet = gradeFormSetFactory(request.POST, queryset=studentQueryset) if myGradeFormSet.is_valid(): myGradeFormSet.save() info = "successfully modified" else: myGradeFormSet = gradeFormSetFactory(queryset=studentQueryset) return render_to_response('grades/modifyAllGrades.html',locals()) template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myGradeFormSet.management_form }} {% for myform in myGradeFormSet.forms %} {# myform.as_table #} <tr> {% for field in myform %} <td> {{ field }} {{ field.errors }} </td> {% endfor %} </tr> {% endfor %} </table> <input type="submit" value="Submit"> </form>

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  • raw_id_fields for modelforms

    - by nbv4
    I have a modelform which has one field that is a ForeignKey value to a model which as 40,000 rows. The default modelform tries to create a select box with 40,000 options, which, to say the least is not ideal. Even more so when this modelform is used in a formset factory! In the admin, this is easiely avoidable by using "raw_id_fields", but there doesn't seem to be a modelform equivalent. How can I do this? Here is my modelform: class OpBaseForm(ModelForm): base = forms.CharField() class Meta: model = OpBase exclude = ['operation', 'routes'] extra = 0 raw_id_fields = ('base', ) #does nothing The first bolded line works by not creating the huge unwieldy selectbox, but when I try to save a fieldset of this form, I get the error: "OpBase.base" must be a "Base" instance. In order for the modelform to be saved, 'base' needs to be a Base instance. Apparently, a string representation of a Base primary key isn't enough (at least not automatically). I need some kind of mechanism to change the string that is given my the form, to a Base instance. And this mechanism has to work in a formset. Any ideas? If only raw_id_fields would work, this would be easy as cake. But as far as I can tell, it only is available in the admin.

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  • How to create a link to Nintex Start Workflow Page in the document set home page

    - by ybbest
    In this blog post, I’d like to show you how to create a link to start Nintex Workflow Page in the document set home page. 1. Firstly, you need to upload the latest version of jQuery to the style library of your team site. 2. Then, upload a text file to the style library for writing your own html and JavaScript 3. In the document set home page, insert a new content editor web part and link the text file you just upload. 4. Update the text file with the following content, you can download this file here. <script type="text/javascript" src="/Style%20Library/jquery-1.9.0.min.js"></script> <script type="text/javascript" src="/_layouts/sp.js"></script> <script type="text/javascript"> $(document).ready(function() { listItemId=getParameterByName("ID"); setTheWorkflowLink("YBBESTDocumentLibrary"); }); function buildWorkflowLink(webRelativeUrl,listId,itemId) { var workflowLink =webRelativeUrl+"_layouts/NintexWorkflow/StartWorkflow.aspx?list="+listId+"&ID="+itemId+"&WorkflowName=Start Approval"; return workflowLink; } function getParameterByName(name) { name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]"); var regexS = "[\\?&]" + name + "=([^&#]*)"; var regex = new RegExp(regexS); var results = regex.exec(window.location.search); if(results == null){ return ""; } else{ return decodeURIComponent(results[1].replace(/\+/g, " ")); } } function setTheWorkflowLink(listName) { var SPContext = new SP.ClientContext.get_current(); web = SPContext.get_web(); list = web.get_lists().getByTitle(listName); SPContext.load(web,"ServerRelativeUrl"); SPContext.load(list, 'Title', 'Id'); SPContext.executeQueryAsync(setTheWorkflowLink_Success, setTheWorkflowLink_Fail); } function setTheWorkflowLink_Success(sender, args) { var listId = list.get_id(); var listTitle = list.get_title(); var webRelativeUrl = web.get_serverRelativeUrl(); var startWorkflowLink=buildWorkflowLink(webRelativeUrl,listId,listItemId) $("a#submitLink").attr('href',startWorkflowLink); } function setTheWorkflowLink_Fail(sender, args) { alert("There is a problem setting up the submit exam approval link"); } </script> <a href="" target="_blank" id="submitLink"><span style="font-size:14pt">Start the approval process.</span></a> 5. Save your changes and go to the document set Item, you will see the link is on the home page now. Notes: 1. You can create a link to start the workflow using the following build dynamic string configuration: {Common:WebUrl}/_layouts/NintexWorkflow/StartWorkflow.aspx?list={Common:ListID}&ID={ItemProperty:ID}&WorkflowName=workflowname. With this link you will still need to click the start button, this is standard SharePoint behaviour and cannot be altered. References: http://connect.nintex.com/forums/27143/ShowThread.aspx How to use html and JavaScript in Content Editor web part in SharePoint2010

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  • Class-Level Model Validation with EF Code First and ASP.NET MVC 3

    - by ScottGu
    Earlier this week the data team released the CTP5 build of the new Entity Framework Code-First library.  In my blog post a few days ago I talked about a few of the improvements introduced with the new CTP5 build.  Automatic support for enforcing DataAnnotation validation attributes on models was one of the improvements I discussed.  It provides a pretty easy way to enable property-level validation logic within your model layer. You can apply validation attributes like [Required], [Range], and [RegularExpression] – all of which are built-into .NET 4 – to your model classes in order to enforce that the model properties are valid before they are persisted to a database.  You can also create your own custom validation attributes (like this cool [CreditCard] validator) and have them be automatically enforced by EF Code First as well.  This provides a really easy way to validate property values on your models.  I showed some code samples of this in action in my previous post. Class-Level Model Validation using IValidatableObject DataAnnotation attributes provides an easy way to validate individual property values on your model classes.  Several people have asked - “Does EF Code First also support a way to implement class-level validation methods on model objects, for validation rules than need to span multiple property values?”  It does – and one easy way you can enable this is by implementing the IValidatableObject interface on your model classes. IValidatableObject.Validate() Method Below is an example of using the IValidatableObject interface (which is built-into .NET 4 within the System.ComponentModel.DataAnnotations namespace) to implement two custom validation rules on a Product model class.  The two rules ensure that: New units can’t be ordered if the Product is in a discontinued state New units can’t be ordered if there are already more than 100 units in stock We will enforce these business rules by implementing the IValidatableObject interface on our Product class, and by implementing its Validate() method like so: The IValidatableObject.Validate() method can apply validation rules that span across multiple properties, and can yield back multiple validation errors. Each ValidationResult returned can supply both an error message as well as an optional list of property names that caused the violation (which is useful when displaying error messages within UI). Automatic Validation Enforcement EF Code-First (starting with CTP5) now automatically invokes the Validate() method when a model object that implements the IValidatableObject interface is saved.  You do not need to write any code to cause this to happen – this support is now enabled by default. This new support means that the below code – which violates one of our above business rules – will automatically throw an exception (and abort the transaction) when we call the “SaveChanges()” method on our Northwind DbContext: In addition to reactively handling validation exceptions, EF Code First also allows you to proactively check for validation errors.  Starting with CTP5, you can call the “GetValidationErrors()” method on the DbContext base class to retrieve a list of validation errors within the model objects you are working with.  GetValidationErrors() will return a list of all validation errors – regardless of whether they are generated via DataAnnotation attributes or by an IValidatableObject.Validate() implementation.  Below is an example of proactively using the GetValidationErrors() method to check (and handle) errors before trying to call SaveChanges(): ASP.NET MVC 3 and IValidatableObject ASP.NET MVC 2 included support for automatically honoring and enforcing DataAnnotation attributes on model objects that are used with ASP.NET MVC’s model binding infrastructure.  ASP.NET MVC 3 goes further and also honors the IValidatableObject interface.  This combined support for model validation makes it easy to display appropriate error messages within forms when validation errors occur.  To see this in action, let’s consider a simple Create form that allows users to create a new Product: We can implement the above Create functionality using a ProductsController class that has two “Create” action methods like below: The first Create() method implements a version of the /Products/Create URL that handles HTTP-GET requests - and displays the HTML form to fill-out.  The second Create() method implements a version of the /Products/Create URL that handles HTTP-POST requests - and which takes the posted form data, ensures that is is valid, and if it is valid saves it in the database.  If there are validation issues it redisplays the form with the posted values.  The razor view template of our “Create” view (which renders the form) looks like below: One of the nice things about the above Controller + View implementation is that we did not write any validation logic within it.  The validation logic and business rules are instead implemented entirely within our model layer, and the ProductsController simply checks whether it is valid (by calling the ModelState.IsValid helper method) to determine whether to try and save the changes or redisplay the form with errors. The Html.ValidationMessageFor() helper method calls within our view simply display the error messages our Product model’s DataAnnotations and IValidatableObject.Validate() method returned.  We can see the above scenario in action by filling out invalid data within the form and attempting to submit it: Notice above how when we hit the “Create” button we got an error message.  This was because we ticked the “Discontinued” checkbox while also entering a value for the UnitsOnOrder (and so violated one of our business rules).  You might ask – how did ASP.NET MVC know to highlight and display the error message next to the UnitsOnOrder textbox?  It did this because ASP.NET MVC 3 now honors the IValidatableObject interface when performing model binding, and will retrieve the error messages from validation failures with it. The business rule within our Product model class indicated that the “UnitsOnOrder” property should be highlighted when the business rule we hit was violated: Our Html.ValidationMessageFor() helper method knew to display the business rule error message (next to the UnitsOnOrder edit box) because of the above property name hint we supplied: Keeping things DRY ASP.NET MVC and EF Code First enables you to keep your validation and business rules in one place (within your model layer), and avoid having it creep into your Controllers and Views.  Keeping the validation logic in the model layer helps ensure that you do not duplicate validation/business logic as you add more Controllers and Views to your application.  It allows you to quickly change your business rules/validation logic in one single place (within your model layer) – and have all controllers/views across your application immediately reflect it.  This help keep your application code clean and easily maintainable, and makes it much easier to evolve and update your application in the future. Summary EF Code First (starting with CTP5) now has built-in support for both DataAnnotations and the IValidatableObject interface.  This allows you to easily add validation and business rules to your models, and have EF automatically ensure that they are enforced anytime someone tries to persist changes of them to a database.  ASP.NET MVC 3 also now supports both DataAnnotations and IValidatableObject as well, which makes it even easier to use them with your EF Code First model layer – and then have the controllers/views within your web layer automatically honor and support them as well.  This makes it easy to build clean and highly maintainable applications. You don’t have to use DataAnnotations or IValidatableObject to perform your validation/business logic.  You can always roll your own custom validation architecture and/or use other more advanced validation frameworks/patterns if you want.  But for a lot of applications this built-in support will probably be sufficient – and provide a highly productive way to build solutions. Hope this helps, Scott P.S. In addition to blogging, I am also now using Twitter for quick updates and to share links. Follow me at: twitter.com/scottgu

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  • Apache mod_wsgi error: ImportError: No module named django.core.handlers.wsgi

    - by bigmac
    I am using Python 2.7 with mod_python 3.3.1 and mod_wsgi 3.3. I get an Internal Server Error and this stack trace in the apache logs: [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Target WSGI script '/home/one/codebase/campman/wsgi_handler.py' cannot be loaded as Python module. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Exception occurred processing WSGI script '/home/one/codebase/campman/wsgi_handler.py'. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] Traceback (most recent call last): [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] File "/home/one/codebase/campman/wsgi_handler.py", line 13, in <module> [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi

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  • Apache mod_wsgi error: ImportError: No module named django.core.handlers.wsgi

    - by bigmac
    I am using Python 2.7 with mod_python 3.3.1 and mod_wsgi 3.3. I get an Internal Server Error and this stack trace in the apache logs: [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Target WSGI script '/home/one/codebase/campman/wsgi_handler.py' cannot be loaded as Python module. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Exception occurred processing WSGI script '/home/one/codebase/campman/wsgi_handler.py'. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] Traceback (most recent call last): [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] File "/home/one/codebase/campman/wsgi_handler.py", line 13, in <module> [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi

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  • How to debug slow queries in Django+Postgres

    - by lacker
    My database queries from Django are starting to take 1-2 seconds and I'm having trouble figuring out why. Not too big a site, about 1-2 requests per second (that hit Django; static files are just served from nginx.) The thing that confuses me is, I can replicate the slowness in the Django shell using debug mode. But when I issue the exact same queries at an sql prompt they are fast. It takes about a second for a query to return, but when I check connection.queries it reports the time as under 10 ms. Here's an example (from the Django shell): >>> p = PlayerData.objects.get(uid="100000521952372") >>> a = time.time(); p.save(); print time.time() - a 1.96812295914 >>> for d in connection.queries: print d["time"] ... 0.002 0.000 0.000 How can I figure out where this extra time is being spent? I'm using Apache+mod_wsgi in daemon mode, but this happens with just the django shell as well, so I figure it is not apache-related.

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  • How can Django/WSGI and PHP share / on Apache?

    - by Mark Snidovich
    I have a server running an established PHP site, as well as some Django apps. Currently, a VirtualHost set up for PHP listens on port 80, and requests to certain directories are proxied to a VirtualHost set up for Django with WSGI. I'd like to change it so Django handles anything not existing as a PHP script or static file. For example, / -parsed by PHP as index.php /page.php -parsed as PHP normally /images/border.jpg -served as a static file /johnfreep -handled by Django (interpreted by urls.py) /pages/john -handled by Django /(anything else) - handled by Django I have a few ideas. It seems the options are 'php first' or 'wsgi first'. set up Django on port 80, and set Apache to skip all the known PHP, CSS or image files. Maybe using SetHandler? Anything else goes to Django to be parsed by urls.py. Set up a script referring everything to Django as a 404 handler on PHP. So, if a file is not found for a name, it sends the request path to a VirtualHost running Django to be parsed.

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  • Running multiple FCGI/Django on Nginx for load sharing

    - by Barry
    I am running a web-service on Nginx/FastCGI/Django. Our processing time is fairly long and CPU intensive and I would like to be able to run multiple processes of Django/FastCGI to share the load. How do I set Nginx to rout requests from a single source to multiple instances of Django/FastCGI? (I can run the multiple instances on multiple ports/sockets, but I don't know how to make Nginx share the processing load between them.) Any help much appreciated.

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  • Problem with deploying django application on mod_wsgi

    - by Shehzad009
    Hello, I seem to have a problem deploying django with mod_wsgi. In the past I've used mod_python but I want to make the change. I have been using Graham Dumpleton notes here http://code.google.com/p/modwsgi/wiki/IntegrationWithDjango1, but it still seem to not work. I get a Internal Server Error. django.wsgi file: import os import sys sys.path.append('/var/www/html') sys.path.append('/var/www/html/c2duo_crm') os.environ['DJANGO_SETTINGS_MODULE'] = 'c2duo_crm.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() WSGIScriptAlias / /var/www/html/c2duo_crm/apache/django.wsgi Apache httpd file: <Directory /var/www/html/c2duo_crm/apache> Order allow,deny Allow from all </Directory> In my apache error log, it says I have this error This is not all of it, but I've got the most important part: [Errno 13] Permission denied: '/.python-eggs' [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] The Python egg cache directory is currently set to: [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] /.python-eggs [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] Perhaps your account does not have write access to this directory? You can [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] change the cache directory by setting the PYTHON_EGG_CACHE environment [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] variable to point to an accessible directory.

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  • Django apache + mod_wsgi with virtualenv

    - by ArgsKwargs
    I have some questions running multiple Django sites on a VPS I have a server that uses openPanel to automatically create VirtualHosts within apache2. My ideal situation is that I would have multiple virtualenvs with different dependencies installed so the python dist-packages directory isn't contaminated for different Django sites. For example: /home/user/virtualenv1 /home/user/virtualenv2 My django applications reside at /var/www, so For example: /var/www/djangosite1 /var/www/djangosite2 Now I've read upon openPanel docs and figured out the best thing todo is create a django.conf file inside the mydomain.com.inc folder, which looks something like: /etc/apache2/openpanel.d/mydomain.com.inc/django.conf DocumentRoot /var/www/djangosite1/project WSGIScriptAlias / /var/www/djangosite1/project/wsgi.py WSGIDaemonProcess mydomain python-path=/home/user/virtualenv1/lib/python2.6/site-packages <Directory /var/www/djangosite1/project> Order allow,deny Allow from all </Directory> Alias /static /var/www/djangosite1/project/static-root Now my problem is that this setup seems unable to find the virtualenv site-packages thus not recognizing any dependencies available in the given virtualenv Also, commenting out this line doesn't seem to break or change a thing: WSGIDaemonProcess mydomain python-path=/home/user/virtualenv1/lib/python2.6/site-packages For example: > service apache2 start ImportError: No module named South When I install South outside the virtualenv everything works

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  • MediaTemple Django Bad Gateway

    - by Eeyore
    I have a site running on GS server on MediaTemple. It's Django/PostgreSQL setup. For some reason from time to time I get Bad Gateway error and I can't figure out what's causing it. What can cause this error? What else can I do to find the cause of the problem? url.access-deny = ( "~", ".inc" ) fastcgi.server = ( "/main.fcgi" => ( "main" => ( "socket" => "/var/tmp/" + appname + ".sock", # don't change this "check-local" => "disable", ) ) ) alias.url = ( "/media/" => "/home/xxx/data/python/django/django/contrib/admin/media/", "/static/" => "/home/xxx/containers/django/site/static/", ) url.rewrite-once = ( "^(/media.*)$" => "$1", "^(/static.*)$" => "$1", "^/favicon\.ico$" => "/media/favicon.ico", "^(/.*)$" => "/main.fcgi$1", ) server.error-handler-404 = "/main.fcgi"

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  • GIT and Django Projects

    - by Garfonzo
    I have two servers, a Dev server and a Production server. The Production server runs a live Django site, while the Dev server has a copy of the Django project. I use the Dev server to work on the Django site, make improvements, fix bugs, etc. Once I am satisfied with how the Dev version is working, I move the whole Django directory from the Dev server and replace the same directory on the Production server. The two servers are not on the same LAN so the process is not straight forward. There are a few issues with this that I am having so far. Moving the whole directory is laborious and time consuming If I only change a few files, it is even move tedious to replace a few files than the whole directory since the project is getting fairly large and I worry that I'll miss something I often run into permission issues after I've moved things It's super inefficient, and, due to lack of time, I haven't bothered figuring out a new method. Now it's just getting out of hand and i need to address the situation. I am thinking I need to move to a GIT repository for this process. But my question is how would I set this all up? Do I host the repository on the Production server, pull from the Dev server, do work, then commit? Then I would pull from the Production server (same server the repo is hosted on) to run the current working version? Do I host the repo on the Dev Server, pulling from the same server to do work on the repo, then pull a working version onto the Production server? Should I be hosting the repo on a different server than the Production server and the Dev server (a third server)? Are there any special considerations with Django and repos that I need to worry about? Thanks for the help :)

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  • UK-based web hosting with Django support

    - by mattbd
    I'm planning to set up a personal website in the near future, and I'd like to use Django on the site. I haven't yet made any decisions about hosting and I was thinking of going with Fasthosts, who support Python, but their website doesn't mention Django at all. Anyone know whether they support it or not? If not, can anyone recommend a good UK-based web host that does support Django?

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  • Django on Windows 2003 Slow Initially

    - by John
    I have setup Django to run on a windows 2003 server following the steps on the django wiki. Everything works fine and there are no errors. Only one instance of Django is setup on the server at the moment. However whenever the first page is requested it takes about 10 seconds to load the page. After this every page loads instantly. All my searches about speed issues with Django on windows refer to the local server, but not when using IIS and PyISAPIe. Thanks

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  • What could cause Django to start failing its own tests after an OS and Django reinstall?

    - by Macha
    I had to reinstall my OS, and so, I reinstalled django 1.1. Since reinstalling, when I run tests in my app, I get several failures from django.contrib.auth. Logs: http://dpaste.com/178153/ I asked on #django, and no one is too sure what the cause of the errors are. Some of my own code fails its tests, because it's not fully written yet, but that shouldn't cause django to fail it's core tests... I have included django.contrib.admin, which was mentioned as a possible cause.

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  • MVC 2 Entity Framework View Model Insert

    - by cannibalcorpse
    This is driving me crazy. Hopefully my question makes sense... I'm using MVC 2 and Entity Framework 1 and am trying to insert a new record with two navigation properties. I have a SQL table, Categories, that has a lookup table CategoryTypes and another self-referencing lookup CategoryParent. EF makes two nav properties on my Category model, one called Parent and another called CategoryType, both instances of their respective models. On my view that creates the new Category, I have two dropdowns, one for the CategoryType and another for the ParentCategory. When I try and insert the new Category WITHOUT the ParentCategory, which allows nulls, everything is fine. As soon as I add the ParentCategory, the insert fails, and oddly (or so I think) complains about the CategoryType in the form of this error: 0 related 'CategoryTypes' were found. 1 'CategoryTypes' is expected. When I step through, I can verifiy that both ID properties coming in on the action method parameter are correct. I can also verify that when I go to the db to get the CategoryType and ParentCategory with the ID's, the records are being pulled fine. Yet it fails on SaveChanges(). All that I can see is that my CategoryParent dropdownlistfor in my view, is somehow causing the insert to bomb. Please see my comments in my httpPost Create action method. My view model looks like this: public class EditModel { public Category MainCategory { get; set; } public IEnumerable<CategoryType> CategoryTypesList { get; set; } public IEnumerable<Category> ParentCategoriesList { get; set; } } My Create action methods look like this: // GET: /Categories/Create public ActionResult Create() { return View(new EditModel() { CategoryTypesList = _db.CategoryTypeSet.ToList(), ParentCategoriesList = _db.CategorySet.ToList() }); } // POST: /Categories/Create [HttpPost] public ActionResult Create(Category mainCategory) { if (!ModelState.IsValid) return View(new EditModel() { MainCategory = mainCategory, CategoryTypesList = _db.CategoryTypeSet.ToList(), ParentCategoriesList = _db.CategorySet.ToList() }); mainCategory.CategoryType = _db.CategoryTypeSet.First(ct => ct.Id == mainCategory.CategoryType.Id); // This db call DOES get the correct Category, but fails on _db.SaveChanges(). // Oddly the error is related to CategoryTypes and not Category. // Entities in 'DbEntities.CategorySet' participate in the 'FK_Categories_CategoryTypes' relationship. // 0 related 'CategoryTypes' were found. 1 'CategoryTypes' is expected. //mainCategory.Parent = _db.CategorySet.First(c => c.Id == mainCategory.Parent.Id); // If I just use the literal ID of the same Category, // AND comment out the CategoryParent dropdownlistfor in the view, all is fine. mainCategory.Parent = _db.CategorySet.First(c => c.Id == 2); _db.AddToCategorySet(mainCategory); _db.SaveChanges(); return RedirectToAction("Index"); } Here is my Create form on the view : <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div> <%= Html.LabelFor(model => model.MainCategory.Parent.Id) %> <%= Html.DropDownListFor(model => model.MainCategory.Parent.Id, new SelectList(Model.ParentCategoriesList, "Id", "Name")) %> <%= Html.ValidationMessageFor(model => model.MainCategory.Parent.Id) %> </div> <div> <%= Html.LabelFor(model => model.MainCategory.CategoryType.Id) %> <%= Html.DropDownListFor(model => model.MainCategory.CategoryType.Id, new SelectList(Model.CategoryTypesList, "Id", "Name"))%> <%= Html.ValidationMessageFor(model => model.MainCategory.CategoryType.Id)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.Name) %> <%= Html.TextBoxFor(model => model.MainCategory.Name)%> <%= Html.ValidationMessageFor(model => model.MainCategory.Name)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.Description)%> <%= Html.TextAreaFor(model => model.MainCategory.Description)%> <%= Html.ValidationMessageFor(model => model.MainCategory.Description)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.SeoName)%> <%= Html.TextBoxFor(model => model.MainCategory.SeoName, new { @class = "large" })%> <%= Html.ValidationMessageFor(model => model.MainCategory.SeoName)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.HasHomepage)%> <%= Html.CheckBoxFor(model => model.MainCategory.HasHomepage)%> <%= Html.ValidationMessageFor(model => model.MainCategory.HasHomepage)%> </div> <p><input type="submit" value="Create" /></p> </fieldset> <% } %> Maybe I've just been staying up too late playing with MVC 2? :) Please let me know if I'm not being clear enough.

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • Returning modified data to a template

    - by Duncan
    I need to amend QuerySet data when i return it to a template. for example, model.objects.all() returns a date (with other fields), but i also want to return the number of days since that date has passed. This is so that in the template, i can say "you last logged in 4 days ago". What is the best way to do this?

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  • How do I filter values in a Django form using ModelForm?

    - by malandro95
    I am trying to use the ModelForm to add my data. It is working well, except that the ForeignKey dropdown list is showing all values and I only want it to display the values that a pertinent for the logged in user. Here is my model for ExcludedDate, the record I want to add: class ExcludedDate(models.Model): date = models.DateTimeField() reason = models.CharField(max_length=50) user = models.ForeignKey(User) category = models.ForeignKey(Category) recurring = models.ForeignKey(RecurringExclusion) def __unicode__(self): return self.reason Here is the model for the category, which is the table containing the relationship that I'd like to limit by user: class Category(models.Model): name = models.CharField(max_length=50) user = models.ForeignKey(User, unique=False) def __unicode__(self): return self.name And finally, the form code: class ExcludedDateForm(ModelForm): class Meta: model = models.ExcludedDate exclude = ('user', 'recurring',) How do I get the form to display only the subset of categories where category.user equals the logged in user?

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