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  • VirtualBox VM running web server not accessible via external IP

    - by mwigdahl
    I have a Windows 7 machine running VirtualBox with an Ubuntu guest. The guest has a Bitnami LAMP stack installed. I have the guest configured for Bridged networking, and I can access the guest web server just fine from other machines on my LAN using the guest's IP. I'm trying to configure port forwarding so that I can access the web server from outside my LAN. (The router is a 2WIRE model as I'm on ATT's UVerse). I've set up port forwarding for ports 80 and 443 to the guest's IP in a similar manner to how I had them set up for my previous, physical web server, which worked just fine. However, I cannot seem to access the new, virtual web server using my external IP on the forwarded port. I suspected Windows Firewall issues on the host, but disabling it didn't solve the issue. Anyone have advice on what I should try next? EDIT: I've now attempted disabling the firewall on the guest with sudo ufw disable -- that doesn't seem to help either. However, after checking the router's port forwarding in more detail I may see the problem. My VM is named "linux" and in the router's configuration pages it shows up inconsistently. Sometimes it reports with a valid LAN IP and other times it doesn't show up with any IP. Even when it shows the correct IP the router indicates that it is disconnected. Could this be an indication that the 2WIRE router doesn't play well with VirtualBox's bridged networking mode?

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  • Variable host IP address in iptables rule

    - by DrakeES
    I am running CentOS 6.4 with OpenVZ on my laptop. In order to provide Internet access for the VEs I have to apply the following rule on the laptop: iptables -t nat -A POSTROUTING -j SNAT --to-source <LAPTOP_IP> It works fine. However, I have to work in different places - office, home, partner's office etc. The IP of my laptop is different in those places, so have to alter the rule above each time I change place. I have created a workaround which basically determines the IP and applies the rule: #!/bin/bash IP=$(ifconfig | awk -F':' '/inet addr/&&!/127.0.0.1/{split($2,_," ");print _[1]}') iptables -t nat -A POSTROUTING -j SNAT --to-source $IP The workaround above works. I only still have to execute it manually. Perhaps I could make it a hook executing whenever my laptop obtains an IP address from DHCP - how can I do that? Also, I am just wondering if there is an elegant way of getting it done in the first place - iptables? Maybe there is a syntax allowing to specify "current hardware ip addres" in the rule?

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  • Scraping with multiple IP, in java.

    - by Titi Wangsa bin Damhore
    Well basically I have a scraping application. It scrapes around n items per minute. currently i have only one IP. The site i'm scraping allows me 3 connections per IP. I'm thinking about getting another IP. so i'll be able to get 6 connections. in theory i should be able to get n items in 40 seconds, more or less. currently i'm using java (commons-httpcore) to get the job done. I'm not sure if this is java question or an OS question. my machine has IP 1 and IP 2 how do i connect to, say, www.microsoft.com, using IP 1 and using IP2? how can i specify, which ip i want to use to do a connection?

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  • How can I host a website on a dynamically-assigned IP address?

    - by nick
    I recently upgraded my internet to the point that it is much faster and more reliable than my current webhost. I would like to move my current domain to be hosted at home, but my IP address is dynamic. As far as I know, I only get a new IP when I restart my modem and or router (which is almost never) or when cable one (my ISP) pushes out a firmware update (rarely). There are a few ways I can see doing this: Convince my ISP to give me a static IP Assign my router my current IP to force a static IP (which might work?) Set my DNS record to my current IP address and update it on the rare occasions that it changes. Obviously I'm hoping that the first one works, but I don't want to pay a lot of extra money (if that's what it takes) to get a static IP address. Which of these options will work most reliably?

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  • Tomcat and IIS 7 both on different ip's and different ports

    - by n00b
    I have Tomcat and IIS 7 installed together on a Windows 2008 server. The machine has two IPs (134.133.1.1 and 134.133.2.2). I want Tomcat to handle 134.133.1.1, on port 80, and IIS to handle both 134.133.2.2, on port 80 AND 134.133.1.1, on port 443, but can't seem to get the last two together (I can get one or the other by themselves on IIS, along with the first IP address on Tomcat). I have configured Tomcat to successfully listen to ip 134.133.1.1, on port 80 with this configuration; <Connector port="80" protocol="HTTP/1.1" address="134.133.1.1" connectionTimeout="20000" redirectPort="8443" /> I also have a site configured in IIS bound to ip 134.133.1.1, on port 443 (SSL). When I turn on IIS, after Tomcat, I can reach both 134.133.1.1:80 (Tomcat) and 134.133.1.1:443 (IIS) successfully (as desired). The problem now comes when I want to introduce a new site via IIS, at the new ip address. In IIS I have setup a new site at IP 134.133.2.2, port 80. I can not start the site. The event log shows this error; Unable to bind to the underlying transport for [::]:80. The IP Listen-Only list may contain a reference to an interface which may not exist on this machine. The data field contains the error number. I think this is because IIS 7 tries to listen to port 80 on all IPs, and it cant because Tomcat is taking port 80 for 134.133.1.1. From reading, the resolution is to specify the IP address you want IIS to bind on port 80. The problem is, when I add 134.133.2.2 to the iplisten list, then I get a 404 when I try navigating to 134.133.1.1:443. I assume this is because IIS is no longer listening to ANY port on 134.133.1.1. How do I resolve this such that IIS will return both sites? EDIT: Per request my IIS binding for site A is 134.133.2.2 on port 80 (http) and 134.133.2.2 on port 443. For site B in IIS, the binding is 134.133.1.1 on port 443 (https). Note the IPs in this example are just for example purposes, but consistent with my setup.

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  • VirtualBox Port Forward not working when Guest IP *IS* specified (while doc says opposite)

    - by Patrick
    Trying to port forward from host (Mac OS X) 127.0.0.1:8282 - guest (CentOS)'s 10.10.10.10:8080. Existing port forwards include 127.0.0.1:8181 and 9191 to guest without any IP specified (so whatever it gets through DHCP, as explained in the documentation). Here is how the non-working binding was added: VBoxManage modifyvm "VM name" --natpf1 "rule3,tcp,127.0.0.1,8282,10.10.10.10,8080" Here is how the working ones were added: VBoxManage modifyvm "VM name" --natpf1 "rule1,tcp,127.0.0.1,8181,,80" VBoxManage modifyvm "VM name" --natpf1 "rule2,tcp,127.0.0.1,9191,,9090" And by "non-working", I of course mean not listening (as a prerequisite to forwarding): $ lsof -Pi -n|grep Virtual|grep LISTEN VirtualBo 27050 user 21u IPv4 0x2bbdc68fd363175d 0t0 TCP 127.0.0.1:9191 (LISTEN) VirtualBo 27050 user 22u IPv4 0x2bbdc68fd0e0af75 0t0 TCP 127.0.0.1:8181 (LISTEN) There should be a similar line above but with 127.0.0.1:8282. Just to be clear, this port is listening perfectly fine on the guest itself. And when I remove the guest IP (i.e., clear the 10.10.10.10) the forward works fine, albeit to eth0 (not eth1 where I need it). I can tcpdump and watch the traffic flow back and forth. And yes, I've disabled iptables entirely while testing -- it's not getting blocked anywhere on the guest. As VirtualBox writes in their documentation, you are required to specify the guest IP if it's static (makes sense, no DHCP record it keeps): "If for some reason the guest uses a static assigned IP address not leased from the built-in DHCP server, it is required to specify the guest IP when registering the forwarding rule:". However, doing so (as I need to), seems to break the port forward with nary a report in any log file I can find. (I've reviewed everything in ~/Library/VirtualBox/). Other notes: While I used the above command to add the third rule, I've also verified it showed up correctly in GUI and then removed/re-added from there just to make sure). This forum link -- while very dated -- looks somewhat related in that a port forward to a static IP was not appearing (perhaps they think due to lack of gratuitous arp being sent for host to know IP is there/avail?). Anyway, what gives? Is this still buggy? Any suggestions? If not, easy enough workarounds? What's interesting is that this works perfectly fine on another user's Mac, however he's running a slightly older version (4.3.6 v. 4.3.12).

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  • Android device unable to obtain ip address connecting to AP created with Hostapd

    - by user114392
    I have a wired internet connection that works behind an authenticated proxy server. I followed the steps mentioned here and managed to create a hotspot which my google nexus 7 detects. However, it seems stuck at "obtaining an ip address" and is not able to connect to the internet. I initially received the following error message when running the script in the terminal: dnsmasq: failed to create listening socket for 127.0.0.1: Address already in use [fail] I figured it is because of a conflict with the network manager, I commented out the "dns=dnsmasq" line in the nm configuration file. After a network-manager restart, the first error doesn't show up but I get the following: Configuration file: /etc/hostapd.conf Failed to create interface mon.wlan0: -23 (Too many open files in system) Try to remove and re-create mon.wlan0 In both cases, however, the hotspot is created and is detected by my android device. only that it cannot "obtain an ip address" and connect to it. Is it because my eth0 connects via a proxy server? Or could there be something wrong with the dnsmasq config? Any help would be appreciated.

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  • VBScript Regular Expressions to check IP address validity with some adtional characters

    - by yael
    How to create VB script Irregular expression syntax to check the VPparam (IP address validity) When the last octatat of the IP address is a range between ip's (x-y) and between each IP we can put the "," separator in order to add another IP example of VBparam VBparam=172.17.202.1-20 VBparam=172.17.202.1-10,192.9.200.1-100 VBparam=172.17.202.1-10,192.9.200.1-100,180.1.1.1-20 THX yael

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  • How to get the client ip address in ASP.Net MVC?

    - by melaos
    hi guys, i'm totally new to the asp.net mvc stack and i was wondering what happened to the simple Page object and the Request ServerVariables object? basically what i wanted to do is to pull out the client's pc ip address. but i fail to understand how the current MVC structure has changed all of this. as far as i can understand, most of the variable object has been replaced by the HttpRequest variants? anybody care to share some resources? really a sea of stuff to learn in the asp.net mvc world :) thanks.

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  • IP address detection for geo-location or MAC address much secure?

    - by SuperRomia
    Recent study many websites are using geo-location technology on their Websites. I'm planning to implement one website which can be detect the web visitor more accurate. An found that Mozilla is using some kind of detect MAC address technology in their Geo-Location web service. Is it violate some privacy issue? I believe most of Geo-location service providers only offer country to city level. But the Mac address detection enable to locate the web visitors' location more correctly than using IP address detection. If detect the MAC address is not practical, which geo-location service provider is offering more accurate data to detect my Website visitor around the world?

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  • iphone SDK: How to check user set up a valid IP , Netmask , Router ???

    - by WebberLai
    It is simple to understand after this pic. I add fewtextfields in tableview I already set the keyboard style is number pad. Now the problems is 1.Do I need to create 12 textfields ???ex. UITextField *ip1,ip2,ip3,ip4....or just set different tag for textfield ? 2.How to check user enter wrong char not 3 valid numbers (even the keyboard is set number pad,but it might can paste words...) 3.How to check user did follow this setting rules ??? <1If IP1 is 0~223 , IP2 need to be set 0~255,IP3,IP4 both are 0~255 <2If IP1 is 172 ,IP2 is set 16~31.IP3,IP4 both are 0~255; If IP1 is 192 ,IP2 must be 168.IP3 IP4 are 0~255 <3Netmask set default 255.255.255.0 <4Router 0~223 ,0~255 ,0~255 ,0~255 This IP setting rules is my friends tech me this ...I not sure the rules is right or not?

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  • A duplicate name has been detected on the TCP network

    - by MSedm
    When I installed my domain controller and DNS, I had 2 NIC on the server. Both NIC has its own IP address. NICs are not teamed, they are seperate and ip address are in the same subnet. Both IP address are now registered in the DNS. i found them in Forward and reverse lookup zone. Everything working ok except the following error in the event log. "A duplicate name has been detected on the TCP network......" Now I have realized that this is because of the second NIC. My question is if i disable the second NIC, what happen to those DNS record assiciated with the second ip address? How do I remove all the DNS recored for the disabled NIC? There are A record, some record with the name (same as parent folder), PTR record and may be more. How do i disable second NIC and remove all the associated DNS recoreds? Please help.

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  • Duplicate file finder

    - by Andrija
    I need free duplicate file finder/remover app, with ability to find duplicate files/folders by name and/or by size and to remove one of duplicates. Can you please recommend any? and why? Thanks EDIT: Changed to CW. Please add more apps to list if you know any.

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  • triple duplicate acknowledgement in TCP congestion control

    - by Salvador Dali
    If this doesn't belong here, please tell me where is an appropriate place for such question. I am trying to understand ideas behind tcp congestion control mechanisms, and I am failing to understand why we need triple duplicate acknowledgement to trigger window change. In my opinion, double duplicate acknowledgement will be enough to get that the previous package is lost. So why we need the third ack?

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  • SYSLINUX 4.07 EDD 2013-07-25 Copyright (C) 1994-2013 H. Peter Anvin et al [duplicate]

    - by Aniel Arias
    This question already has an answer here: Not booting from USB or CD (SYSLINUX Message) 10 answers this what is happening, i downloaded (ubuntu-gnome-14.04.1-desktop) and (elementaryos-unstable-amd64.20140810) to try out in my laptop and i have use (unetbootin-windows-608) and (Universal-USB-Installer-1.9.5.5) but i get this message every time i try to boot from the usb (SYSLINUX 4.07 EDD 2013-07-25 Copyright (C) 1994-2013 H. Peter Anvin et al) however i tried in an old desktop that i have and it works although the installer gets stuck on most of the time at the part of reading partitions/hard drives so please i really need help with this. note: i did installed os x long time ago and i broke windows installation then fix it following some online tutorials just for FYI thanks please can somebody help to fix this problem, i have been looking on google but haven't found anything in concrete. please help

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  • Running a program in background using command-line [duplicate]

    - by user291957
    This question already has an answer here: Running programs in the background from terminal 4 answers How do I run a program in the background of a shell, with the ability to close the shell while leaving the program running which should not disturb the window i am working on? Lets say my UI is having problems or for some reason, I need to boot up a program from the terminal window. The program should not disturb my window in which i am working on but it should be opened from the command line and i should be able to get access to it using the normal shortcut ALT+TAB. Even the command line should exit after running the command I tried this .... "gedit file-name & exit" this is working fine but the gedit file is opening in the foreground (let i be working on some application like mozilla. After running the command ..... gedit file is coming upwards and i have to flip to mozilla again but the command should just open the gedit file not shifting to gedit application from the mozilla window)

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  • Preventing duplicate Data with ASP.NET AJAX

    - by Yousef_Jadallah
      Some times you need to prevent  User names ,E-mail ID's or other values from being duplicated by a new user during Registration or any other cases,So I will add a simple approach to make the page more user-friendly. Instead the user filled all the Registration fields then press submit after that received a message as a result of PostBack that "THIS USERNAME IS EXIST", Ajax tidies this up by allowing asynchronous querying while the user is still completing the registration form.   ASP.NET enables you to create Web services can be accessed from client script in Web pages by using AJAX technology to make Web service calls. Data is exchanged asynchronously between client and server, typically in JSON format. I’ve added an article to show you step by step  how to use ASP.NET AJAX with Web Services , you can find it here .   Lets go a head with the steps :   1-Create a new project , if you are using VS 2005 you have to create ASP.NET Ajax Enabled Web site.   2-Create your own Database which contain user table that have User_Name field. for Testing I’ve added SQL Server Database that come with Dot Net 2008: Then I’ve created tblUsers:   This table and this structure just for our example, you can use your own table to implement this approach.   3-Add new Item to your project or website, Choose Web Service file, lets say  WebService.cs  .In this Web Service file import System.Data.SqlClient Namespace, Then Add your web method that contain string parameter which received the Username parameter from the Script , Finally don’t forget to qualified the Web Service Class with the ScriptServiceAttribute attribute ([System.Web.Script.Services.ScriptService])     using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Services; using System.Data.SqlClient;     [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] [System.Web.Script.Services.ScriptService] public class WebService : System.Web.Services.WebService {     [WebMethod] public int CheckDuplicate(string User_Name) { string strConn = @"Data Source=.\SQLEXPRESS;AttachDbFilename=|DataDirectory|\TestDB.mdf;Integrated Security=True;User Instance=True"; string strQuery = "SELECT COUNT(*) FROM tblUsers WHERE User_Name = @User_Name"; SqlConnection con = new SqlConnection(strConn); SqlCommand cmd = new SqlCommand(strQuery, con); cmd.Parameters.Add("User_Name", User_Name); con.Open(); int RetVal= (int)cmd.ExecuteScalar(); con.Close(); return RetVal; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   Our Web Method here is CheckDuplicate Which accept User_Name String as a parameter and return number of the rows , if the name will found in the database this method will return 1 else it will return 0. I’ve applied  [WebMethod] Attribute to our method CheckDuplicate, And applied the ScriptService attribute to a Web Service class named WebService.   4-Add this simple Registration form : <fieldset> <table id="TblRegistratoin" cellpadding="0" cellspacing="0"> <tr> <td> User Name </td> <td> <asp:TextBox ID="txtUserName" onblur="CallWebMethod();" runat="server"></asp:TextBox> </td> <td> <asp:Label ID="lblDuplicate" runat="server" ForeColor="Red" Text=""></asp:Label> </td> </tr> <tr> <td colspan="3"> <asp:Button ID="btnRegistration" runat="server" Text="Registration" /> </td> </tr> </table> </fieldset> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   onblur event is added to the Textbox txtUserName, This event Fires when the Textbox loses the input focus, That mean after the user get focus out from the Textbox CallWebMethod function will be fired. CallWebMethod will be implemented in step 6.   5-Add ScriptManager Control to your aspx file then reference the Web service by adding an asp:ServiceReference child element to the ScriptManager control and setting its path attribute to point to the Web service, That generate a JavaScript proxy class for calling the specified Web service from client script.   <asp:ScriptManager runat="server" ID="scriptManager"> <Services> <asp:ServiceReference Path="WebService.asmx" /> </Services> </asp:ScriptManager> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }     6-Define the JavaScript code to call the Web Service :   <script language="javascript" type="text/javascript">   // This function calls the Web service method // passing simple type parameters and the // callback function function CallWebMethod() { var User_Name = document.getElementById('<%=txtUserName.ClientID %>').value; WebService.CheckDuplicate(User_Name, OnSucceeded, OnError); }   // This is the callback function invoked if the Web service // succeeded function OnSucceeded(result) { var rsltElement = document.getElementById("lblDuplicate"); if (result == 1) rsltElement.innerHTML = "This User Name is exist"; else rsltElement.innerHTML = "";   }   function OnError(error) { // Display the error. alert("Service Error: " + error.get_message()); } </script> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   This call references the WebService Class and CheckDuplicate Web Method defined in the service. It passes a User_Name value obtained from a textbox as well as a callback function named OnSucceeded that should be invoked when the asynchronous Web Service call returns. If the Web Service in different Namespace you can refer it before the class name this Main formula may help you :  NameSpaceName.ClassName.WebMethdName(Parameters , Success callback function, Error callback function); Parameters: you can pass one or many parameters. Success callback function :handles returned data from the service . Error callback function :Any errors that occur when the Web Service is called will trigger in this function. Using Error Callback function is optional.   Hope these steps help you to understand this approach.

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