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  • Parsing XML elements with dynamic namespace prefix in PHP

    - by BugKiller
    I have the following XML ( you can say SOAP request ) : <SOAPENV:Envelope xmlns:SOAPENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:NS="http://xyz.gov/headerschema" > <SOAPENV:Header> <NS:myHeader> <NS:SourceID>223423</NS:SourceID> </NS:myHeader> </SOAPENV:Header> </SOAPENV:Envelope> I use the following code and it works fine : <?php $myRequest ='<SOAPENV:Envelope xmlns:SOAPENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:NS="http://xyz.gov/headerschema" > <SOAPENV:Header> <NS:myHeader> <NS:SourceID>223423</NS:SourceID> </NS:myHeader> </SOAPENV:Header> </SOAPENV:Envelope>'; $xml = simplexml_load_string($myRequest, NULL, NULL, "http://schemas.xmlsoap.org/soap/envelope/"); $namespaces = $xml->getNameSpaces(true); $soapHeader = $xml->children($namespaces['SOAPENV'])->Header; $myHeader = $soapHeader->children($namespaces['NS'])->myHeader; echo (string)$myHeader->SourceID; ?> The Problem I know the prefix ( SOAPENV + NS ) , but the clients could change the prefix to whatever they want, so they may send me xml document that has ( MY-SOAPENV + MY-NS) prefixes. My Question How can I handle this since the namespace prefixes are not static , how can I parse it ? Thanks

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  • Sending a password securely using gwt and app engine?

    - by user246114
    Hi, I set up session handling on a google app project. This is supposed to allow my users to login and maintain state across pages. I just dumped it into the default greeting service to try it out: public class GreetingServiceImpl extends RemoteServiceServlet implements GreetingService { public void sessionTest(String username) { HttpSession session = getThreadLocalRequest().getSession(false); session.setAttribute("username", username); } } then attempting to pull it out in my landing project.jsp page: <% String username = null; HttpSession mysession = request.getSession(false); if (mysession.getAttribute("username") != null) { username = (String)mysession.getAttribute("username"); } else { username = "(not logged in yet)"; } <p>You are: <%= username %> </p> %> It works, but I don't know how to send the data in sessionTest() securely. If I were sending the user's password in there too, it would be in the clear. This would be ok (I think) if I was using https, but google app engine does not allow you to use https under custom domains (like www.mysite.com), they have to be under the (mysite.appspot.com) domain. I'm kind of stuck here - how do we send passwords securely? If I was using php, I think I could use digest authentication (I'm not too experienced here) - can we do something like that with gwt + gae? Thanks

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  • android populating gridivew from a url string

    - by user1685991
    I am building an android application in which i am trying to read data from a url and want to display the data in a gridview. But i have some problem or dont understand to how to display the array list on grdiview. Here is my code for reading data from php url ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); //http post try{ HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://sml.com.pk/a/smldb.php"); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); is = entity.getContent(); }catch(Exception e){ Log.e("log_tag", "Error in http connection"+e.toString()); } //convert response to string try{ BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8); sb = new StringBuilder(); sb.append(reader.readLine() + "\n"); String line="0"; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); result=sb.toString(); }catch(Exception e){ Log.e("log_tag", "Error converting result "+e.toString()); } //paring data double des; double value; try{ jArray = new JSONArray(result); JSONObject json_data=null; for(int i=0;i<jArray.length();i++){ json_data = jArray.getJSONObject(i); LAT=json_data.getDouble("TITLE"); LANG=json_data.getDouble("A"); } } catch(JSONException e1){ Toast.makeText(getBaseContext(), "No Vehicles Found" ,Toast.LENGTH_LONG).show(); } catch (ParseException e1) { e1.printStackTrace(); } Here TITLE and A are my two columns of DB Table and i want to display them on gridview please any one help me to do this according to my current code. Here is my live url for data string http://sml.com.pk/a/smldb.php

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  • In Process Explorer is it possible change scaling of activity graph the be able to further analyse graph?

    - by therobyouknow
    Is there any way to zoom in, in the System Internals Process Explorer graph? Background I'm trying to work out why my PC freezes/locks up for about a second (the pointer does not move) every so often. This has only been happening for the last 2 days. There is a very narrow spike associated with the freeze, but it's hard to hover over it an analyse what is causing it. My PC spec: ThinkPad X201S 1440x900 i7 2.0GHz 8Gb RAM, 256GB Samsung 840Pro SSD, Windows 8.1 Pro 64bit CalDigit USB 3.0 ExpressCard 34, Ultrabase X200 with DisplayPort to HDMI

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  • JLabel transparency problem

    - by Rendicahya
    I have a dark-gray JPanel with a JLabel on it. I set new Color(0, 0, 0, .5f) (tranparent) as the background of the JLabel and I change the text several times using a button. The problem is, everytime the text is changed, the previous text still remains behind the new text. I change the text from "123456789" to "1234567", "12345" and "123". Here is the screenshot: How do I get rid of this "shadow"? Here's the code: public class TransparentJLabel extends JFrame { private int i = 0; private String[] value = {"123456789", "1234567", "12345", "123", "1"}; public TransparentJLabel() { setSize(300, 160); setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); setLayout(null); JPanel panel = new JPanel(); panel.setBackground(new Color(102, 102, 102)); panel.setLayout(null); panel.setBounds(0, 0, 300, 160); final JLabel label = new JLabel(); label.setText(value[0]); label.setFont(new Font("Times New Roman", 1, 36)); label.setForeground(new Color(255, 255, 255)); label.setBackground(new Color(0, 0, 0, .5f)); label.setHorizontalAlignment(SwingConstants.CENTER); label.setOpaque(true); label.setBounds(10, 10, 270, 70); JButton button = new JButton(); button.setText("Change"); button.setBounds(100, 90, 90, 25); button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { label.setText(value[++i]); } }); panel.add(label); panel.add(button); add(panel); } public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { new TransparentJLabel().setVisible(true); } }); } }

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  • Getting Junk characters while trying to print the file contents using Java

    - by user1523797
    I am reading a file's contents and trying to print the contents using java. But it prints junk characters along with the file content. Code: import java.io.*; public class ReadFile { public String readFile(String filePath){ StringBuilder contents = new StringBuilder(); File file = new File(filePath); try{ String lines = null; FileReader fileReader1 = new FileReader(file); BufferedReader buffer = new BufferedReader(fileReader1); while((lines = buffer.readLine())!=null){ contents.append(lines); } buffer.close(); } catch(FileNotFoundException ex){ System.out.println("File not found."); }catch(IOException ex){ System.out.println("Exception ocurred."); } return contents.toString(); } public static void main(String[] args){ ReadFile rf = new ReadFile(); String lines = rf.readFile("C:\\Data\\FaultDn.txt"); System.out.println("Original file contents: " + lines); } } The file contents are: partner.cisco.com:org-root/mac-pool-QA_MAC_Pool_5-Sep-2012_12:00 The output is: ![Alt Output](C:\Users\safarhee\Desktop\Output.jpg) Can you please point me to what I am missing in this code?

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  • Learning OOP in PHP, trying to refactor my code. Can't connect to database anymore.

    - by Cortopasta
    Thought I understood how classes work, then I tried this code: class user { var $dbcon; var $dbinfo; var $con; var $error; function dbConnect() { $this->dbinfo['server'] = "localhost"; $this->dbinfo['database'] = "foolish_faith"; $this->dbinfo['user'] = "user"; $this->dbinfo['password'] = "password"; $this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database']; $this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']); $this->dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $this->error = $this->dbcon->errorInfo(); if ($error[0] != "") { print "Error!"; print_r($error); } } } Now it just spits out this error: Fatal error: Uncaught exception 'PDOException' with message 'invalid data source name' in E:\PortableApps\xampp\htdocs\dbcon.php:24 Stack trace: #0 E:\PortableApps\xampp\htdocs\dbcon.php(24): PDO-__construct('', NULL, NULL) #1 E:\PortableApps\xampp\htdocs\login.php(4): user-dbConnect() #2 {main} thrown in E:\PortableApps\xampp\htdocs\dbcon.php on line 24 Can anybody see what I'm doing wrong, as I'm sure it has to do with my lack of knowledge when it comes to classes?

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  • JSF: How to forward a request to another page in action?

    - by Satya
    I want to forward request to another page from action class I am using below code in my jsf action : public String submitUserResponse(){ ...... ...... parseResponse(uri,request,response); .... return "nextpage"; } public String parseResponse(String uri,request,response){ if(uri != null){ RequestDispatcher dispatcher = request.getRequestDispatcher(uri); dispatcher.forward(request, response); return null; } ................. .................. return "xxxx"; } "submitUserResponse" method is being called when user clicks the submit button from the jsp and this method returns "nextpage" string here request forwards to next page in normal flow. but in my requirement i will call "submitUserResponse () " which will execute and forwrd request to next page.It is going. but it is displaying some exceptions in server That is : java.lang.IllegalStateException: Cannot forward after response has been committed Here my doubts are: 1.why next lines of code is being executed after forwarding my request using dispatched.forward(uri) . Same thing happening in response.sendRedirect("").

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  • Using jQuery with form to eliminate spam

    - by Thierry-Dimitri Roy
    I have put a form on a web page where the user can send us data. Unfortunately, the webmaster does get a lot of spam through this form and the valid submissions gets buried. I have used captcha to bypass this problem. But I think that everyone would agree that captcha is a big annoyance to users. I switched to another solution: now the URL of the submit form points to null: <form id="sendDataForm" action="/null" method="post"> ... </form> And I bypass the form submission using jQuery excellent form plugin: $('#sendDataForm').ajaxForm({ url: '/ajax-data/' }); Since then, no spam has reached the webmaster, and valid comments gets through. The only drawbacks is that users without javascript cannot send us the form. But since this is on top of a javascript web application, we can safely assume that these are not valid users. My question is: in a world where 99% of users has javascript enabled (and a mechanism for those user could be build that uses captcha), why is this solution not more used? What drawback am I not seeing?

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  • Android: Gzip/Http supported by default?

    - by OneWorld
    I am using the code shown below to get Data from our server where Gzip is turned on. Does my Code already support Gzip (maybe this is already done by android and not by my java program) or do I have to add/change smth.? How can I check that it's using Gzip? For my opionion the download is kinda slow. private static InputStream OpenHttpConnection(String urlString) throws IOException { InputStream in = null; int response = -1; URL url = new URL(urlString); URLConnection conn = url.openConnection(); if (!(conn instanceof HttpURLConnection)) throw new IOException("Not an HTTP connection"); try { HttpURLConnection httpConn = (HttpURLConnection) conn; httpConn.setAllowUserInteraction(false); httpConn.setInstanceFollowRedirects(true); httpConn.setRequestMethod("GET"); httpConn.connect(); response = httpConn.getResponseCode(); if (response == HttpURLConnection.HTTP_OK) { in = httpConn.getInputStream(); if(in == null) throw new IOException("No data"); } } catch (Exception ex) { throw new IOException("Error connecting"); } return in; }

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  • Reference problem when returning an object from array in PHP

    - by avastreg
    I've a reference problem; the example should be more descriptive than me :P I have a class that has an array of objects and retrieve them through a key (string), like an associative array: class Collection { public $elements; function __construct() { $this->elements = array(); } public function get_element($key) { foreach($this->elements as $element) { if ($element->key == $key) { return $element; break; } } return null; } public function add_element ($element) { $this->elements[] = $element; } } Then i have an object (generic), with a key and some variables: class Element { public $key; public $another_var; public function __construct($key) { $this->key = $key; $this->another_var = "default"; } } Now, i create my collection: $collection = new Collection(); $collection->add_element(new Element("test1")); $collection->add_element(new Element("test2")); And then i try to change variable of an element contained in my "array": $element = $collection->get_element("test1"); $element->another_var = "random_string"; echo $collection->get_element("test1")->another_var; Ok, the output is random_string so i know that my object is passed to $element in reference mode. But if i do, instead: $element = $collection-get_element("test1"); $element = null; //or $element = new GenericObject(); $element-another_var = "bla"; echo $collection-get_element("test1")-another_var; the output is default like if it lost the reference. So, what's wrong? I have got the references to the variables of the element and not to the element itself? Any ideas?

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  • selenium and firefox timeout behavior

    - by Md. Reazul Karim
    I am facing this strange timeout behavior. I tried to load some page using: WebDriver drv = new FirefoxDriver(); drv.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS); drv.get(url); String email = ""; try { WebElement aElem = Util.safeFindElementByXpath(drv, "//p[1]/a[1]"); if (aElem != null) { email = aElem.getAttribute("href"); } } catch (Exception e) { } drv.quit(); return email; The safeFindElementByXpath is: static WebElement safeFindElementByXpath(WebDriver driver, String xpath) { try { return driver.findElement(By.xpath(xpath)); } catch (NoSuchElementException e) { return null; } } Now I set the firefox network.http.connection-timeout and network.http.connection-retry-timeout both to 10. Now if I restart the firefox I can see the new values. But if I try to run the above code - the firefox window opens and it waits for a particular website for a long time. Hence I open another tab in the same firefox window and check the values of timeout and find them to be 90 and 250. If I change the values on that same window, the selenium code immediately finishes requesting for the page (ie it goes after the exception block). So the thing is that the same code will work on many sites and I don't know beforehand which site is invalid/down and I was thinking of putting this code in a separate thread and kill the thread after some time from the calling thread. But that is not possible I guess because the child thread has no way to poll anything as it is stuck at page request and can't go to the polling code afterwards. Now the thing is that I want any kind of hack/workaround to accomplish this: try getting the emails for good sites and if there are bad sites just give up after a certain period (press the panic button sorta thing). Thanks

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  • Image change on mouseover with jQuery..

    - by playahabana
    Hi, I am a comlete beginner to pretty much all things web design and am trying to construct my first website. I am attempting to hand code it without the ue of a CMS in order to learn as much as possible as quickly as possible. I am trying to make an imge change on mouseover for my top nav menu, and have the following jQuery functions: $(document).ready(function(){ $(".navlist img").each(function) { rollsrc = $(this).attr("src"); rollON = rollsrc.replace(/.jpg$/ig,"_link.png"); $("<img>").attr("src",rollON); $(".navlist a").mouseover(function(){ }); imgsrc= $(this).children("img").attr("src"); matches = imgsrc.match(/_link.png); if (!matches) { imgsrcON = imgsrc.replace(/.jpg$/ig,"_link.png"); $(this).children("img").attr("src", imagesrcON); } $(".navlist a").mouseout(function(){ $(this).children("img").attr("src", imgsrc); }); }); my html is as follows: <div id="nav"> <ul class="navmenu"> <li><a href="index.html"><img class="swap" src="images/links/home.jpg" alt="Home" border="none"></a></li> <li><a href="#"><img class="swap" src="images/links/ourbar.jpg" alt="Our Bar" border="none"></a> <ul class="navdrop"> <li ><a href="#"><img class="swap" src="images/links/cockteles.jpg" alt="Our Cocktails" border="none"></a></li> <li ><a href="#"><img class="swap" src="images/links/celebrate.jpg" alt="Celebrate in Style" border="none"></a></li> </ul> </li> <li><a href="#"><img class="swap" src="images/links/ourcigars.jpg" alt="Our Cigars" border="none"></a> <ul class="navdrop"> <li><a href="#"><img class="swap" src="images/links/edicionlimitadas.jpg" alt="Edition Limitadas" border="none"></a></li> <li><a href="our_cigars.html"><img class="swap" src="images/links/cigartasting.jpg" alt="Cigar Tastings" border="none"></a></li> </ul> </li> <li><a href="#"><img class="swap" src="images/links/personalcigar.jpg" alt="Personal Cigar Roller" border="none"></a></li> <li><a href="our_cigars.html"><img class="swap" src="images/links/photogallery.jpg" alt="Photo Gallery" border="none"></a></li> <li><a href="#"><img class="swap" src="images/links/contactus.jpg" alt="Contact Us" border="none"></a></li> </ul></div></div><!--end banner--> the image src for the alt image is in the form eg."images/links/home_link.png" and is the same for every image. I have checked this and checked this, could some body please give me a pointer as to where I am going wrong? Or a pointer to a tutorial for this effect? I have looked at a few and this seems to be the best for what I am attempting, but as I said I don't really know what I'm doing so any advice gratefully received.....

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  • Jquery Modal Popup opens twice on Single Click with ASP.Net MVC3

    - by user1704379
    I am using Modal Popup in my MVC3 application it works fine but opens twice for a single Click on the link. The Modal pop is triggered from the 'Index' view of my Home Controller. I am calling a view 'PopUp.cshtml' in my modal popup. The related ActionMethod 'PopUp' for the respective view is in my 'Home' controller. Here is the code, Jquery code on layout.cshtml page, <script type="text/javascript"> $.ajaxSetup({ cache: false }); $(document).ready(function () { $(".openPopup").live("click", function (e) { e.preventDefault(); $("<div></div><p>") .attr("id", $(this).attr("data-dialog-id")) .appendTo("body") .dialog({ autoOpen: true, title: $(this).attr("data-dialog-title"), modal: true, height: 250, width: 900, left: 0, buttons: { "Close": function () { $(this).dialog("close"); } } }) .load(this.href); }); $(".close").live("click", function (e) { e.preventDefault(); $(this).dialog("close"); }); }); </script> cshtml code in 'PopUp.cshtml' @{ ViewBag.Title = "PopUp"; Layout = null; } <h2>PopUp</h2> <p> Hello this is a Modal Pop-Up </p> Call modal popup code in Index view of Home Controller, <p> @Html.ActionLink("Click here to open modal popup", "Popup", "Home",null, new { @class = "openPopup", data_dialog_id = "popuplDialog", data_dialog_title = "PopUp" }) </p> What am I doing wrong that the modal pop up opens twice ? Thanks in Advance !

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  • Should .net comments start with a capital letter and end with a period?

    - by Hamish Grubijan
    Depending on the feedback I get, I might raise this "standard" with my colleagues. This might become a custom StyleCop rule. is there one written already? So, Stylecop already dictates this for summary, param, and return documentation tags. Do you think it makes sense to demand the same from comments? On related note: if a comment is already long, then should it be written as a proper sentence? For example (perhaps I tried too hard to illustrate a bad comment): //if exception quit vs. // If an exception occurred, then quit. If figured - most of the time, if one bothers to write a comment, then it might as well be informative. Consider these two samples: //if exception quit if (exc != null) { Application.Exit(-1); } and // If an exception occurred, then quit. if (exc != null) { Application.Exit(-1); } Arguably, one does not need a comment at all, but since one is provided, I would think that the second one is better. Please back up your opinion. Do you have a good reference for the art of commenting, particularly if it relates to .Net? Thanks.

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  • How to pass XML from C# to a stored procedure in SQL Server 2008?

    - by Geetha
    I want to pass xml document to sql server stored procedure such as this: CREATE PROCEDURE BookDetails_Insert (@xml xml) I want compare some field data with other table data and if it is matching that records has to inserted in to the table. Requirements: How do I pass XML to the stored procedure? I tried this, but it doesn’t work:[Working] command.Parameters.Add( new SqlParameter("@xml", SqlDbType.Xml) { Value = new SqlXml(new XmlTextReader(xmlToSave.InnerXml, XmlNodeType.Document, null)) }); How do I access the XML data within the stored procedure? Edit: [Working] String sql = "BookDetails_Insert"; XmlDocument xmlToSave = new XmlDocument(); xmlToSave.Load("C:\\Documents and Settings\\Desktop\\XML_Report\\Books_1.xml"); SqlConnection sqlCon = new SqlConnection("..."); using (DbCommand command = sqlCon.CreateCommand()) { **command.CommandType = CommandType.StoredProcedure;** command.CommandText = sql; command.Parameters.Add( new SqlParameter("@xml", SqlDbType.Xml) { Value = new SqlXml(new XmlTextReader(xmlToSave.InnerXml , XmlNodeType.Document, null)) }); sqlCon.Open(); DbTransaction trans = sqlCon.BeginTransaction(); command.Transaction = trans; try { command.ExecuteNonQuery(); trans.Commit(); sqlCon.Close(); } catch (Exception) { trans.Rollback(); sqlCon.Close(); throw; } Edit 2: How to create a select query to select pages, description based on some conditions. <booksdetail> <isn_13>700001048</isbn_13> <isn_10>01048B</isbn_10> <Image_URL>http://www.landt.com/Books/large/00/7010000048.jpg</Image_URL> <title>QUICK AND FLUPKE</title> <Description> PRANKS AND JOKES QUICK AND FLUPKE </Description> </booksdetail>

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  • Can't open COM1 from application launched at startup

    - by n0rd
    I'm using WinLIRC with IR receiver connected to serial port COM1 on Windows 7 x64. WinLIRC is added to Startup folder (Start-All applications-Startup) so it starts every time I log in. Very often (but not all the time) I see initialization error messages from WinLIRC, which continue for some time (couple of minutes) if I retry initialization, and after some retries it initializes correctly and works fine. If I remove it from Startup and start manually at any other moment it starts without errors. I've downloaded WinLIRC sources and added MessageBox calls here and there so I can see what happens during initialization and found out that CreateFile call fails: if((hPort=CreateFile( settings.port,GENERIC_READ | GENERIC_WRITE, 0,0,OPEN_EXISTING,FILE_FLAG_OVERLAPPED,0))==INVALID_HANDLE_VALUE) { char buffer[256]; sprintf_s(buffer, "CreateFile(%s) failed with %d", settings.port, GetLastError()); MessageBox(NULL, buffer, "debug", MB_OK); hPort=NULL; return false; } I see message box saying "CreateFile(COM1) failed with 5", and 5 is an error code for "Access denied" error according to this link. So the question is why opening COM-port can fail with such error right after booting Windows and proceed normally few seconds or minutes later?

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  • Write to PDF using PHP from android device

    - by Brent Mitchell
    I am trying to write to a pdf file on php server. I have sent variables to the server, create the pdf document, then have my phone download the document to view on device. The variables seem not to write on the php file. I have my code below public void postData() { try { Calculate calc = new Calculate(); HttpClient mClient = new DefaultHttpClient(); StringBuilder sb=new StringBuilder("myurl.com/pdf.php"); HttpPost mpost = new HttpPost(sb.toString()); String value = "1234"; List nameValuepairs = new ArrayList(1); nameValuepairs.add(new BasicNameValuePair("id",value)); mpost.setEntity(new UrlEncodedFormEntity(nameValuepairs)); } catch (UnsupportedEncodingException e) { Log.w(" error ", e.toString()); } catch (Exception e) { Log.w(" error ", e.toString()); } } And my php code to write the variable "value" onto the pdf document: //code to reverse the string if($_POST[] != null) { $reversed = strrev($_POST["value"]); $this->SetFont('Arial','u',50); $this->Text(52,68,$reversed); } I am just trying to write the variable in a random spot, but the variable the if statement is always null and I do not know why. Thanks. Sorry if it is a little sloppy.

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  • In CakePHP, how do I create a form to list models withing a date range?

    - by anonymous coward
    I have a very simple model that includes the auto-filled field much like 'created'. (DateTime format). I'd like to use the Form helpers if possible, to validate the date fields and whatnot. I'd like a simple form with a "Begin Date" (YMD, 12 hours), and an "End Date" (same format). There is already a controller action set up as follows: function view_between($start_date = null, $end_date = null) { // ... stuff that works correctly when the URL is manually entered. } Have I defined the controller wrong, or how can I pass these values into that function? The reason I'm stuck is because I tried adding a $form->input('my_datetime_field' ...) twice, but obviously the name/id were the same on the respective elements. I have also tried using $form->dateTime(...) with similar results. I'm not sure how to uniquely identify a Begin and End date selection, when it should interact with a single field. Am I going about this wrong? A kind shove in the right direction should suffice.

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  • Hibernate CreateSQL Query Problem

    - by Shaded
    Hello All I'm trying to use hibernates built in createsql function but it seems that it doesn't like the following query. List =hibernateSession.createSQLQuery("SELECT number, location FROM table WHERE other_number IN (SELECT f.number FROM table2 AS f JOIN table3 AS g on f.number = g.number WHERE g.other_number = " + var + ") ORDER BY number").addEntity(Table.class).list(); I have a feeling it's from the nested select statement, but I'm not sure. The inner select is used elsewhere in the code and it returns results fine. This is my mapping for the first table: <hibernate-mapping> <class name="org.efs.openreports.objects.Table" table="table"> <id name="id" column="other_number" type="java.lang.Integer"> <generator class="native"/> </id> <property name="number" column="number" not-null="true" unique="true"/> <property name="location" column="location" not-null="true" unique="true"/> </class> </hibernate-mapping> And the .java public class Table implements Serializable { private Integer id;//panel_facility private Integer number; private String location; public Table() { } public void setId(Integer id) { this.id = id; } public Integer getId() { return id; } public void setNumber(Integer number) { this.number = number; } public Integer number() { return number; } public String location() { return location; } public void setLocation(String location) { this.location = location; } } Any suggestions? Edit (Added mapping)

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  • TDD approach for complex function

    - by jamie
    I have a method in a class for which they are a few different outcomes (based upon event responses etc). But this is a single atomic function which is to used by other applications. I have broken down the main blocks of the functionality that comprise this function into different functions and successfully taken a Test Driven Development approach to the functionality of each of these elements. These elements however aren't exposed for other applications would use. And so my question is how can/should i easily approach a TDD style solution to verifying that the single method that should be called does function correctly without a lot of duplication in testing or lots of setup required for each test? I have considered / looked at moving the blocks of functionality into a different class and use Mocking to simulate the responses of the functions used but it doesn't feel right and the individual methods need to write to variables within the main class (it felt really heath robinson). The code roughly looks like this (i have removed a lot of parameters to make things clearer along with a fair bit of irrelevant code). public void MethodToTest(string parameter) { IResponse x = null; if (function1(parameter)) { if (!function2(parameter,out x)) { function3(parameter, out x); } } // ... // more bits of code here // ... if (x != null) { x.Success(); } }

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  • In ArrayBlockingQueue, why copy final member field into local final variable?

    - by mjlee
    In ArrayBlockingQueue, any method that requires lock will get set 'final' local variable before calling 'lock()'. public boolean offer(E e) { if (e == null) throw new NullPointerException(); final ReentrantLock lock = this.lock; lock.lock(); try { if (count == items.length) return false; else { insert(e); return true; } } finally { lock.unlock(); } } Is there any reason to set a local variable 'lock' from 'this.lock' when field 'this.lock' is final also. Additionally, it also set local variable of E[] before acting on. private E extract() { final E[] items = this.items; E x = items[takeIndex]; items[takeIndex] = null; takeIndex = inc(takeIndex); --count; notFull.signal(); return x; } Is there any reason for copying to local final variable?

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  • Restrict second screen to certain window/application

    - by Daniel Hepper
    I have a system with two screens. On the primary screen, I want to use Windows in a normal way. On the secondary screen, I want to display a window of a certain application and nothing else. In no case should anything else than this specific window show up on the secondary screen: no other applications, no dialog boxes. If possible, I want to restrict the mouse pointer to the primary screen as well. I tried UltraMon, but I think my requirements go beyond its features. Any ideas?

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  • Is it possible to cache all the data in a SQL Server CE database using LinqToSql?

    - by DanM
    I'm using LinqToSql to query a small, simple SQL Server CE database. I've noticed that any operations involving sub-properties are disappointingly slow. For example, if I have a Customer table that is referenced by an Order table, LinqToSql will automatically create an EntitySet<Order> property. This is a nice convenience, allowing me to do things like Customer.Order.Where(o => o.ProductName = "Stopwatch"), but for some reason, SQL Server CE hangs up pretty bad when I try to do stuff like this. One of my queries, which isn't really that complicated takes 3-4 seconds to complete. I can get the speed up to acceptable, even fast, if I just grab the two tables individually and convert them to List<Customer> and List<Order>, then join then manually with my own query, but this is throwing out a lot of what makes LinqToSql so appealing. So, I'm wondering if I can somehow get the whole database into RAM and just query that way, then occasionally save it. Is this possible? How? If not, is there anything else I can do to boost the performance besides resorting to doing all the joins manually? Note: My database in its initial state is about 250K and I don't expect it to grow to more than 1-2Mb. So, loading the data into RAM certainly wouldn't be a problem from a memory point of view. Update Here are the table definitions for the example I used in my question: create table Order ( Id int identity(1, 1) primary key, ProductName ntext null ) create table Customer ( Id int identity(1, 1) primary key, OrderId int null references Order (Id) )

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  • how to add data in Table of Jasper Report using Java

    - by Areeb Gillani
    i am here to ask you just a simple question that i am trying to pass data to a jasper report using java but i dont know how to to, because the table data is very dynamic thats y cannot pass sql query. any idea for this. i have a 2D array of object type, where i have all the data... so how can i pass that... Thanx in advance...!:) ConnectionManager con = new ConnectionManager(); con.establishConnection(); String fileName = "Pmc_Bill.jrxml"; String outFileName = "OutputReport.pdf"; HashMap params = new HashMap(); params.put("PName", pname); params.put("PSerial", psrl); params.put("PGender",pgen); params.put("PPhone",pph); params.put("PAge",page); params.put("PRefer",pref); params.put("PDateR",dateNow); try { JasperReport jasperReport = JasperCompileManager.compileReport(fileName); if(jasperReport != null ) System.out.println("so far so good "); // Fill the report using an empty data source JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, new JRTableModelDataSource(tbl.getModel()));//con.connection); try{ JasperExportManager.exportReportToPdfFile(jasperPrint, outFileName); System.out.printf("File exported sucessfully"); }catch(Exception e){ e.printStackTrace(); } JasperViewer.viewReport(jasperPrint); } catch (JRException e) { JOptionPane.showMessageDialog(null, e); e.printStackTrace(); System.exit(1); }

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