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  • HP 6735s Brightness hotkey problem; where is brightness panel?

    - by Paul
    I have installed ubuntu 11.10 on my laptop hp 6735s. The screen is often too dark and i want to make it brighter, although the hotkeys Fn+F7/F8 are not working. I have tried some things: Firstly it appears that sometimes they are in fact working, after reboot they either work and continue to do so or they don't. I've read about a brightness applet; but where can i find or install it? I have tried some grub options; acpi_osi=Linux and acpi_backlight=vendor but nothing changes. I don't want to add another question but since it might be related: my laptop also gets quite hot, i'm having doubts whether ubuntu connects to the available sensors and cooling plans (or how does it work???); sensors (or psensor) only shows 2 sensors both named temp1. Any help is greatly appreciated! Paul

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  • How do i put this chunk of code into a php variable?

    - by Theron Chong
    if (isset($_SESSION['name'])){ //select BID and duedates which are between the range of 1-3 days // before due date from current date $query = "SELECT DueDate FROM item WHERE DueDate BETWEEN '$warning2' and '$warning' and user='$_SESSION[name]' ORDER BY DueDate DESC"; $find = mysql_query($query); $alert = mysql_num_rows($find); if ($alert>=1){ echo "You have got " .$alert. " item(s) due on: </br >"; while ($item = mysql_fetch_array($find)){ echo $item['DueDate']; echo "<br />"; } } echo "Success!"; } Question: How do i input all this code into a single php variable, say $alert. I am not clear of where to put single quotes or double quotes to make it work. At the end of the day, I will be using the variable for a javascript alert box.

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  • status update error (null field)

    - by ejah85
    hai guys... i .ve the problem that i cannot be recovered yet... i have one form where admin need to approve or reject the booking request... i've set the b_status field in table usage IN PROCESS default value... i want to update the b_status value BOOKING APPROVED when user click APPROVE button.. otherwise, the b_status will update the value as BOOKING REJECTED when user click on the REJECT button here's is the form code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM vehicle WHERE v_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr><td>&nbsp;</td></tr> <tr> <tr> <td width="200"><font face="Arial" size="2" font color="#000000">Registration Number </font></td> <td><select name="regno"> <option value="" selected>--Registration No--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['regno']; ?>"><?php echo $row['regno']; ?></option> <?php } ?> </select></td> <td><font face="Arial" size="2" font color="#000000">Reason</font></td> <td><textarea name="reason" rows="3" cols="50 "value = ""></textarea></td> </tr> <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM driver WHERE d_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr> <td><font face="Arial" size="2" font color="#000000">Driver</font></td> <td><select id = "d_name" name="d_name"> <option value="" selected>--Driver Name--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['d_name']; ?>"><?php echo $row['d_name']; ?></option> <?php } ?> </select></td> </tr> <tr> <?php mysql_close($db); ?> </table> <p></p> <center><input name="APPROVED" type="submit" id="APPROVED" value="APPROVED"> <input name="REJECT" type="submit" id="REJECT" value="REJECT"> </center> </div> </center> and this is the process page code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $bookingno=mysql_real_escape_string($_POST['bookingno']); $username=mysql_real_escape_string($_POST['username']); $name=mysql_real_escape_string($_POST['name']); $department=mysql_real_escape_string($_POST['department']); $g_date=mysql_real_escape_string($_POST['g_date']); $g_time=mysql_real_escape_string($_POST['g_time']); $r_date=mysql_real_escape_string($_POST['r_date']); $r_time=mysql_real_escape_string($_POST['r_time']); $destination=mysql_real_escape_string($_POST['destination']); $pass_num=mysql_real_escape_string($_POST['pass_num']); $trip_purpose=mysql_real_escape_string($_POST['trip_purpose']); $regno=mysql_real_escape_string($_POST['regno']); $d_name=mysql_real_escape_string($_POST['d_name']); $reason=mysql_real_escape_string($_POST['reason']); $b_status=mysql_real_escape_string($_POST['b_status']); $sql = "INSERT INTO `usage` VALUES('$bookingno','$username','$name','$department','$g_date','$g_time','$r_date','$r_time','$destination', '$pass_num','$trip_purpose','$regno','$d_name','$reason','$b_status')"; $query = "INSERT INTO `usage` VALUES b_status ='BOOKING APPROVED'"; $result = @mysql_query($query); $query1 = "UPDATE driver SET d_status ='OUT' WHERE '$d_name'=d_name"; $result1 = @mysql_query($query1); if(isset($_POST['APPROVED'])) { $query2 = "UPDATE `usage` SET b_status ='BOOKING APPROVED' WHERE '$b_status'='IN PROCESS'"; $result2 = @mysql_query($query2); } if (isset($_POST['REJECT'])) { $query3 = "UPDATE `usage` SET b_status ='BOOKING REJECTED' WHERE '$b_status'='IN PROCESS'"; $result3 = @mysql_query($query3); } //$result = mysql_query($sql) or die ("error!"); $result = mysql_query($sql) or trigger_error (mysql_error().' in '.$sql); i.ve the problem on the b_status field.. plz guys... help me ya :-)

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  • Syntax for combining joins in mysql

    - by UltraVi01
    I seem to remember reading somewhere that there is a way to combine LEFT JOIN statements into a more simple query. I have the following query and was hoping someone could kindly take a look at it. SET @userId = 8; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug, user u, profile p LEFT JOIN user_block ub ON @userId = ub.blocked_id LEFT JOIN user_block ub2 ON @userId = ub2.blocker_id LEFT JOIN user_user uu ON @userId = uu.user_id LEFT JOIN friend_request fr ON @userId = fr.user_id WHERE ug.user_id = u.id AND u.profile_id = p.id AND (ub.blocker_id IS NULL OR ub.blocker_id != ug.user_id) AND (ub2.blocked_id IS NULL OR ub2.blocked_id != ug.user_id) AND (uu.user_friends_id IS NULL OR uu.user_friends_id != ug.user_id) AND (fr.to_user_id IS NULL OR (fr.to_user_id != ug.user_id)) AND ug.user_id!=@userId AND p.suggestible AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4

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  • jquery dropdownbox auto populated with mysql data

    - by Xin
    I've got 2 dropdownboxes. Dropdownbox 1 shows all the tables from a database. When dropdownbox 1 is selected; dropdownbox 2 will be populated with tablefields from the selected table. dropdownbox 1: This dropdown is populated with the following mysql query: "show tables from testdb" dropdownbox 2: This dropdown will auto populate when dropdownbox 1 is selected. Dropdownbox 2 will be populate with the following query: "describe tablename" //tablename selected from dropdownbox 1 I want to make this using jquery. Can anyone point me into the right direction?

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  • PHP - database not selected. What is wrong with my code?

    - by Petr
    Hi, I am learning PHP and tried to connect to MySQL. Altough I am using select DB, is still reports "No database selected". What is wrong, please? Thanks. <?php $user="test"; $pass="aaa"; ConnectToDb(); function ConnectToDb() { $pripojeni=mysql_connect('localhost',$user,$pass); $selectedDB=mysql_select_db('1a'); if($query=mysql_query('select * from project')) { while($d=mysql_fetch_array($query)) { echo "TEST"; } } else echo mysql_error($pripojeni); } ?>

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  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

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  • How to invert rows and columns using a T-SQL Pivot Table

    - by Jeff Stock
    I have a query that returns one row. However, I want to invert the rows and columns, meaning show the rows as columns and columns as rows. I think the best way to do this is to use a pivot table, which I am no expert in. Here is my simple query: SELECT Period1, Period2, Period3 FROM GL.Actuals WHERE Year = 2009 AND Account = '001-4000-50031' Results (with headers): Period1, Period2, Period3 612.58, 681.36, 676.42 I would like for the results to look like this: Desired Results: Period, Amount Period1, 612.58 Period2, 681.36 Period3, 676.42 This is a simple example, but what I'm really after is a bit more comlex than this. I realize I could produce theses results by using several SELECT commands instead. I'm just hoping someone can shine some light on how to accomplish this with a Pivot Table or if there is yet a better way.

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  • Hbase schema design -- to make sorting easy?

    - by chen
    I have 1M words in my dictionary. Whenever a user issue a query on my website, I will see if the query contains the words in my dictionary and increment the counter corresponding to them individually. Here is the example, say if a user type in "Obama is a president" and "Obama" and "president" are in my dictionary, then I should increment the counter by 1 for "Obama" and "president". And from time to time, I want to see the top 100 words (most queried words). If I use Hbase to store the counter, what schema should I use? -- I have not come up an efficient one yet. If I use word in my dictionary as row key, and "counter" as column key, then updating counter(increment) is very efficient. But it's very hard to sort and return the top 100. Anyone can give a good advice? Thanks.

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  • Google App Engine update an object from servlet not working ?

    - by Frank
    I use the following code to update an object from servlet in Google App Engine : String Time_Stamp=Get_Date_Format(6),query="select from "+Contact_Info_Entry.class.getName()+" where Contact_Id == '"+Contact_Id+"' order by Contact_Id desc"; PersistenceManager pm=null; try { pm=PMF.get().getPersistenceManager(); // note that this returns a list, there could be multiple, DataStore does not ensure uniqueness for non-primary key fields List<Contact_Info_Entry> results=(List<Contact_Info_Entry>)pm.newQuery(query).execute(); Contact_Info_Entry A_Contact_Entry=results.get(0); A_Contact_Entry.Extra_10=Time_Stamp; pm.makePersistent(A_Contact_Entry); } catch (Exception e) { Send_Email(Email_From,Email_To,"Check_License_Servlet Error [ "+Time_Stamp+" ]",new Text(e.toString()+"\n"+Get_Stack_Trace(e)),null); } finally { pm.close(); } The value "[ 2010-05-13 Thu 15:58:31 ]" was in A_Contact_Entry.Extra_10, but it seems "pm.makePersistent(A_Contact_Entry);" was not executed. The object was not updated and there was no error message, why ? How to fix it ?

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  • Oracle - correlated subquery problems

    - by FrustratedWithFormsDesigner
    I have this query: select acc_num from (select distinct ac_outer.acc_num, ac_outer.owner from ac_tab ac_outer where (ac_outer.owner = '1234567') and ac_outer.owner = (select sq.owner from (select a1.owner from ac_tab a1 where a1.acc_num = ac_outer.acc_num order by a1.a_date desc, a1.b_date desc, a1.c_date desc) sq where rownum = 1) order by dbms_random.value()) subq order by acc_num; The idea is to get all acc_nums (not a primary key) from ac_tab, that have an owner of 1234567. Since an acc_num in ac_tab could have changed owners over time, I am trying to use the inner correlated subqueries to ensure that an acc_num is returned ONLY if it's most recent owner is 12345678. Naturally, it doesn't work (or I wouldn't be posting here ;) ) Oracle gives me an error: ORA-000904 ac_outer.acc_num is an invalid identifier. I thought that ac_outer should be visible to the correlated subqueries, but for some reason it's not. Is there a way to fix the query, or do I have to resort to PL/SQL to solve this? (Oracle verison is 10g)

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  • How sql server evaluates the multiple different joins?

    - by ziang
    Hi, i have a general question about how sql server evaluates the joins.The query is SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id Q1: What tables is the left join based on? I know it will based on the TABLEC but what is the other one? Is it the result of the first inner join or the TABLEB specified in the left join condition? Q2: Is "LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id" equivalent to "LEFT JOIN TABLEC ON TABLEB.id = TABLEC.id" Q3: Is the query equivalent to the following one? (with TABLEB.id replaced by TABLEA.id?) SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEA.id Thank you!

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  • for loop with count from array, limit output? PHP

    - by Philip
    print '<div id="wrap">'; print "<table width=\"100%\" border=\"0\" align=\"center\" cellpadding=\"3\" cellspacing=\"3\">"; for($i=0; $i<count($news_comments); $i++) { print ' <tr> <td width="30%"><strong>'.$news_comments[$i]['comment_by'].'</strong></td> <td width="70%">'.$news_comments[$i]['comment_date'].'</td> </tr> <tr> <td></td> <td>'.$news_comments[$i]['comment'].'</td> </tr> '; } print '</table></div>'; $news_comments is a 3 diemensional array from mysqli_fetch_assoc returned from a function elsewhere, for some reason my for loop returns the total of the array sets such as [0][2] etc until it reaches the max amount from the counted $news_comments var which is a return function of LIMIT 10. my problem is if I add any text/html/icons inside the for loop it prints it in this case 11 times even though only array sets 1 and 2 have data inside them. How do I get around this? My function query is as follows: function news_comments() { require_once '../data/queries.php'; // get newsID from the url $urlID = $_GET['news_id']; // run our query for newsID information $news_comments = selectQuery('*', 'news_comments', 'WHERE news_id='.$urlID.'', 'ORDER BY comment_date', 'DESC', '10'); // requires 6 params // check query for results if(!$news_comments) { // loop error session and initiate var foreach($_SESSION['errors'] as $error=>$err) { print htmlentities($err) . 'for News Comments, be the first to leave a comment!'; } } else { print '<div id="wrap">'; print "<table width=\"100%\" border=\"0\" align=\"center\" cellpadding=\"3\" cellspacing=\"3\">"; for($i=0; $i<count($news_comments); $i++) { print ' <tr> <td width="30%"><strong>'.$news_comments[$i]['comment_by'].'</strong></td> <td width="70%">'.$news_comments[$i]['comment_date'].'</td> </tr> <tr> <td></td> <td>'.$news_comments[$i]['comment'].'</td> </tr> '; } print '</table></div>'; } }// End function Any help is greatly appreciated.

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  • Oracle XE + ODP.NET ANNOYING VIEW ERROR

    - by Alex
    Sup guys, heres my view: CREATE OR REPLACE VIEW SISTEMA.VWTELA AS SELECT TEL_DLTELA AS Tela, TEL_DLDESCRICAO As Descricao, TEL_DLTABELA As Tabela, CASE WHEN to_char(TEL_STATIVO) = to_char(1) THEN to_char('Yes') ELSE to_char('No') END as Ativo, TEL_IDTELA AS IDTEL FROM SISTEMA.TEL_TELA; When i do a SELECT * FROM SISTEMA.VWTELA it works fine from PL/SQL Developer but when i launch the query from my VB.NET application it throws me a super annoying error ORA-01722. Any ideas? The Application code works perfecty with any query so its not application code error but prolly some "super cool feature" from ODP.NET. Already tried to_number, to_whatever and same error always happens.

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  • Limit the size of a directory by deleting old files

    - by Sulliwane
    I have a IP cam which save its recordings in a specific directory named Camera1 in my Ubuntu Server 12.04. I would like to limit the size of this folder to 5 gigs, by deleting -say once a day- the oldest files. I first checked the quota program but it doesn't seem to allow the creation of new files and deleting of the old ones. So I think the best workaround would be to run a bash script ? But I have no idea how to write it... Thank you guys !

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  • What would be the most efficient use of e-mail addresses for ecommerce

    - by user18323
    I am not sure if this is exactly the right section. What do you find the most efficient, clear and reachable use of e-mail addresses to use for the customer? I thought a standard 'sales, 'support' might work but it might look a little samey. Do users respond well when e-mails are replied by staff with named e-mail addresses such as [email protected] or a generic one? I am currently developing a small scale ecommerce website to gain some hands on insight into web retail. Any additional advice would be brilliant.

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  • GQL, Aggregation and Order By

    - by Koran
    Hi, How can GQL support ORDER BY when it does not support aggregation? The question is - if say the result of the query is more than 1000, does ORDER BY return fully ordered list or only the first 1000 items which is then ordered? To explain the question more: is conceptually MIN() same as query.orderby('asc').fetch(1)? If it is properly ordering the list, then how can it not provide COUNT(), since to properly order the list, GQL possibly has to parse through the whole list - in which case, COUNT() is not an issue at all? Or is item indexed and kept in some type of tree so that it does not need to parse it all the time?

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  • Multiple Java EE Agents on Single Managed Server

    - by tina.wang
    A default JEE agent is created when you create domain, which is named as OracleDIAgent. 1. In Studio, duplicate the agent, change its name to genAgent, change the web application context to genagent. 2: Go to datasource of genAgent, drop all datasources.3: Generate server template. put the jar file under odi\common\templates\wls 4: Deploy this template by update the existing domain. Bring up the config.cmd, choose update existing domain. 5: Update the domain using the template that just generated. Go through the Configuration wizard. (I did not modify anything or configure anything here). 6: The wizard will give information says the deployment was successful. 7: Bring up the admin server and ODI_server1. 

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  • Java Session Like Object

    - by scriptmonster
    I have been developing a project and in this project i have designed my code to do the same job after a specified time interval continuously. The job that wanted to be done has a lot of distinct cycles. The interval is small to execute them normally thus i used threads. Until that point everything is clear for me. To decrease the process and information transaction i wanted to put an session like object that holds the given data and provide it to any thread at anytime. With this object i plan to not query the same configuration information from database at everytime but if it exists on the session take it else query and store on session. I'm not sure how to implement this structure. Regards,

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  • How to dynamically order many-to-many relationship in JPA or HQl?

    - by Indrek
    I have a mapping like this: @ManyToMany(cascade = CascadeType.PERSIST) @JoinTable( name="product_product_catalog", joinColumns={@JoinColumn(name="product_catalog", referencedColumnName="product_catalog")}, inverseJoinColumns={@JoinColumn(name="product", referencedColumnName="product")}) public List<Product> products = new ArrayList<Product>(); I can fetch the products for the catalog nicely, but I can't (dynamically) order the products. How could I order them? I probably have to write a many-to-many HQL query with the order-by clause? I though of passing the orderBy field name string to the query, or is there a better solution? Tables are: products, product_catalog, product_product_catalog (associative table) P.S. Using Play! Framework JPASupport for my entities.

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  • Disable printing extraneous job info when I print a images

    - by pgrytdal
    As of 10/11/12 I this is still a problem. Peterling, that link you gave me was for Windows. Not Ubuntu. I need to know how to do this in Ubuntu. Whenever I print off an image, before the actual image prints, I get these weird "print job" sheets. (I named them that, because I don't know what else to call them.) They say something like: Media Limits: 0.12 x 0.38 to 8.38 x 10.38 inches Job ID: Officejet-Pro-L7700-64 Driver: hp-officejet_pro_17700.ppd Driver version: Description: HP Officejet Pro L7700 Make and Model: HP Officejet Pro L7700, hpcups 3.12.2 Printer: Officejet-Pro-L7700 Created at: Fri Sep 28 14:12:53 2012 Printed at: Fri Sep 28 14:12:53 2012 How do I fix this so the page doesn't print?

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  • How to get all the fields of a row using the SQL MAX function?

    - by Yiannis Mpourkelis
    Consider this table (from http://www.tizag.com/mysqlTutorial/mysqlmax.php): Id name type price 123451 Park's Great Hits Music 19.99 123452 Silly Puddy Toy 3.99 123453 Playstation Toy 89.95 123454 Men's T-Shirt Clothing 32.50 123455 Blouse Clothing 34.97 123456 Electronica 2002 Music 3.99 123457 Country Tunes Music 21.55 123458 Watermelon Food 8.73 This SQL query returns the most expensive item from each type: SELECT type, MAX(price) FROM products GROUP BY type Clothing $34.97 Food $8.73 Music $21.55 Toy $89.95 I also want to get the fields id and name that belong to the above max price, for each row. What SQL query will return a table like this? Id name type price 123455 Blouse Clothing 34.97 123458 Watermelon Food 8.73 123457 Country Tunes Music 21.55 123453 Playstation Toy 89.95

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  • Removing duplicate SQL records to permit a unique key

    - by j pimmel
    I have a table ('sales') in a MYSQL DB which should have rightfully have had a unique constraint enforced to prevent duplicates. To first remove the dupes and set the constraint is proving a bit tricky. Table structure (simplified): 'id (unique, autoinc)' product_id The goal is to enforce uniqueness for product_id. The de-duping policy I want to apply is to remove all duplicate records except the most recently created, eg: the highest id Or to put another way, I would like to delete duplicate records, excluding the ids matched by the following query: select id from sales s inner join (select product_id, max(id) as maxId from sales group by product_id having count(product_id) > 1) groupedByProdId on s.product_id and s.id = groupedByProdId.maxId I've struggled with this on two fronts - writing the query to select the correct records to delete and then also the constraint in MYSQL where a subselect FROM clause of a DELETE cannot reference the same table from which data is being removed.

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  • code duplication in sql case statements

    - by NS
    Hi I'm trying to output something like the following but am finding that there is a lot of code duplication going on. | australian_has_itch | kiwi_has_itch | | yes | no | | no | n/a | | n/a | no | ... My query looks like this with two case statements that do the same thing but flip the country (my real query has 5 of these case statements): SELECT CASE WHEN NOT EXISTS ( SELECT person_id FROM people_with_skin WHERE people_with_skin.person_id = people.person_id AND people.country = "Australia" ) THEN 'N/A' WHEN EXISTS ( SELECT person_id FROM itch_none_to_report WHERE people.country = "Australia" AND person_id = people.person_id ) THEN 'None to report' WHEN EXISTS ( SELECT person_id FROM itchy_people WHERE people.country = "Australia" AND person_id = people.person_id ) THEN 'Yes' ELSE 'No' END australian_has_itch, CASE WHEN NOT EXISTS ( SELECT person_id FROM people_with_skin WHERE people_with_skin.person_id = people.person_id AND people.country = "NZ" ) THEN 'N/A' WHEN EXISTS ( SELECT person_id FROM itch_none_to_report WHERE people.country = "NZ" AND person_id = people.person_id ) THEN 'None to report' WHEN EXISTS ( SELECT person_id FROM itchy_people WHERE people.country = "NZ" AND person_id = people.person_id ) THEN 'Yes' ELSE 'No' END kiwi_has_itch, FROM people Is there a way for me to condense this somehow and not have so much code duplication? Thanks!

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