Search Results

Search found 14016 results on 561 pages for 'mysql 5 5'.

Page 404/561 | < Previous Page | 400 401 402 403 404 405 406 407 408 409 410 411  | Next Page >

  • How can I use a php array in a mysql search query?

    - by ThinkingInBits
    I was going to use the scuttle solution on: http://www.pui.ch/phred/archives/2005/04/tags-database-schemas.html for handling searches on my website. I was wondering how I could take the search input from a user and turn it into a single query. For instance, let's say a user inputted 'blue dogs' in their search query... How could I dynamically update the query to include ('blue', 'dogs') in union and intersection queries?

    Read the article

  • Using $this when not in object context--i am using the latest version of php and mysql

    - by user309381
    This is user.php: include("databse.php");//retrieving successfully first name and lastname from databse file into user.php class user { public $first_name; public $last_name; public static function full_name() { if(isset($this->first_name) && isset($this->last_name)) { return $this->first_name . " " . $this->last_name; } else { return ""; } } } ?> Other php file, index.php: <?php include(databse.php); include(user.php); $record = user::find_by_id(1); $object = new user(); $object->id = $record['id']; $object->username = $record['username']; $object->password = $record['password']; $object->first_name = $record['first_name']; $object->last_name = $record['last_name']; // echo $object->full_name(); echo $object->id;// successfully print the id echo $object->username;//success fully print the username echo->$object->full_name();//**ERROR:Using $this when not in object context** ?>

    Read the article

  • how can i export some values in mysql to an php array?

    - by sebastian
    hi, here is what i'm trying to make. i want to select all the users from a table. for all of these users i want to make a for cycle. from what i know for has three statements something like so for($i=0;$i++;$i=$max) how can i put the user id's in to an array so i can define my $max variable? or can this be done in an other method? thanks,

    Read the article

  • PHP, MySQL: Security concern; Page loads in a weird way

    - by Devner
    Hi all, I am testing the security of my website. I am using the following URL to load a PHP page in my website, on localhost: http://localhost/domain/user/index.php/apple.php When I do this, the page is not loading normally; Instead the images, icons used in the page simply vanish/disappear from the page. Only text appears. And also on any link I click on this page, it brings me to this same page again without navigating to the required page. So if I have hyperlinks to other pages, such as "SEARCH", which points to search.php, instead of navigating to the search.php page, it refreshes the index.php page and just appends the page name of the destination page to the end of the URL. For example, say I used the link above. It then loads the index.php page minus the images at it's will. When I click on the "Search" link to navigate to the search page, I see the following in the URL: http://localhost/domain/user/index.php/search.php I have a redirection configured to a 404 error page in my .htaccess file, but the page does not redirect to the 404 error page. Notice the search.php towards the end of the URL above. Any other link that I click, reloads the index.php page and just appends the destination page name to the end of the URL like I have shown above. I was expecting to see a 404 Error but that does not happen. The URL should not even be able to load the page because I do NOT have a "index.php" folder in my website. What can I do to solve this? All help is appreciated. Thank you.

    Read the article

  • Using jQuery to store basic text string in mySQL base?

    - by Kenny Bones
    Could someone point me in the right direction here? Basically, I've got this jQuery code snippet: $('.bggallery_images').click(function () { var newBG = "url('" + $(this).attr('src'); var fullpath = $(this).attr('src'); var filename = fullpath.replace('img/Bakgrunner/', ''); $('#wrapper').css('background-image', newBG); // Lagre til SQL $.ajax({ url: "save_to_db.php", // The url to your function to handle saving to the db data: filename, dataType: 'Text', type: 'POST', // Could also use GET if you prefer success: function (data) { // Just for testing purposes. alert('Background changed to: ' + data); } }); }); This is being run when I click a certain button. So it's actually within a click handler. If I understand this correctly, this snippet takes the source if the image I just clicked and strips it so I end up with only the filename. If I do an alert(filename), I get the filename only. So this is working ok. But then, it does an ajax call to a php file called "save_to_db.php" and sends data: filename. This is correct right? Then, it does a callback which does an alert + data. Does this seem correct so far? Cause my php file looks like this: <?php require("dbconnect2.php"); $uploadstring = $_POST['filename']; $sessionid = $_SESSION['id']; echo ($sessionid); mysql_query("UPDATE brukere SET brukerBakgrunn = '$uploadstring' WHERE brukerID=" .$_SESSION['id']); mysql_close(); ?> When I click the image, the jQuery snippet fires and I get the results of this php file as output for the alert box. I think that the variables somehow are empty. Because notice the echo($sessionid); which is a variable I've created just to test what the session ID is. And it returns nothing. What could be the issue here? Edit: I just tried to echo out the $uploadstring variable as well and it also returns nothing. It's like the jQuery snippet doesn't even pass the variable on to the php file?

    Read the article

  • How do I use on delete cascade in mysql?

    - by Marius
    I have a database of components. Each component is of a specific type. That means there is a many-to-one relationship between a component and a type. When I delete a type, I would like to delete all the components which has a foreign key of that type. But if I'm not mistaken, cascade delete will delete the type when the component is deleted. Is there any way to do what I described?

    Read the article

  • I have a 18MB MySQL table backup. How can I restore such a large SQL file?

    - by Henryz
    I use a Wordpress plugin called 'Shopp'. It stores product images in the database rather than the filesystem as standard, I didn't think anything of this until now. I have to move server, and so I made a backup, but restoring the backup is proving a horrible task. I need to restore one table called wp_shopp_assets which is 18MB. Any advice is hugely appreciated. Thanks, Henry.

    Read the article

  • how read data from file and execute to MYSQL?

    - by Mahran Elneel
    i create form to load sql file and used fopen function top open file and read this but when want to execute this data to database not work? what is wrong in my code????????????? $ofile = trim(basename($_FILES['sqlfile']['name'])); $path = "sqlfiles/".$ofile; //$data = settype($data,"string"); $file = ""; $connect = mysql_connect('localhost','root',''); $selectdb = mysql_select_db('files'); if(isset($_POST['submit'])) { if(!move_uploaded_file($_FILES['sqlfile']['tmp_name'],"sqlfiles/".$ofile)) { $path = ""; } $file = fopen("sqlfiles/".$ofile,"r") or exit("error open file!"); while (!feof($file)) { $data = fgetc($file); settype($data,"string"); $rslt = mysql_query($data); print $data; } fclose($file); }

    Read the article

  • Search-friendly way to store checkbox values in MySQL?

    - by Alex
    What is a search-friendly way to store checkbox values in the database? Currently, checkboxes are processed as an array and values are separated by a ";" As such: <input type="checkbox" name="frequency[]" value="Daily"/> Daily <input type="checkbox" name="frequency[]" value="Weekly"/> Weekly <input type="checkbox" name="frequency[]" value="Monthly"/> Monthly The PHP backend runs implode(';', $frequency) and adds the string to the database. This works fine but it's a nightmare when it comes to searching. Is there a better way to approach this?

    Read the article

  • Doctrine MYSQL 150+ tables: generating models works, but not vice-versa?

    - by ropstah
    I can generate my models and schema.yml file based on an existing database. But when I try to do it the other way around using Doctrine::createTablesFromModels() i get an error: Syntax error or access violation: 1064 So either of these works: Doctrine::generateYamlFromDb(APPPATH . 'models/yaml'); Doctrine::generateYamlFromModels(APPPATH . 'models/yaml', APPPATH . 'models'); Doctrine::generateModelsFromYaml(APPPATH . 'models/yaml', APPPATH . 'models', array('generateTableClasses' => true)); Doctrine::generateModelsFromDb(APPATH . 'models', array('default'), array('generateTableClasses' => true)); But this fails (it drops/creates the database and around 50 tables): Doctrine::dropDatabases(); Doctrine::createDatabases(); Doctrine::createTablesFromModels(); The partially outputted SQL query shows that the error is around the Notification object which looks like this: Any leads would be highly appreciated! <?php // Connection Component Binding Doctrine_Manager::getInstance()->bindComponent('Notification', 'default'); /** * BaseNotification * * This class has been auto-generated by the Doctrine ORM Framework * * @property integer $n_auto_key * @property integer $type * @property string $title * @property string $message * @property timestamp $entry_date * @property timestamp $update_date * @property integer $u_auto_key * @property integer $c_auto_key * @property integer $ub_auto_key * @property integer $o_auto_key * @property integer $notified * @property integer $read * @property integer $urgence * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ abstract class BaseNotification extends Doctrine_Record { public function setTableDefinition() { $this->setTableName('Notification'); $this->hasColumn('n_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => true, 'autoincrement' => true, 'length' => '4', )); $this->hasColumn('type', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); $this->hasColumn('title', 'string', 50, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '50', )); $this->hasColumn('message', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('entry_date', 'timestamp', 25, array( 'type' => 'timestamp', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '25', )); $this->hasColumn('update_date', 'timestamp', 25, array( 'type' => 'timestamp', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '25', )); $this->hasColumn('u_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('c_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('ub_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('o_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('notified', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'default' => '0', 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); $this->hasColumn('read', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'default' => '0', 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); $this->hasColumn('urgence', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'default' => '0', 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); } public function setUp() { parent::setUp(); } }

    Read the article

  • Is the development stack of java/spring/hibernate/eclipse/tomcat/mysql riddled with config hacking?

    - by Blankman
    From a M$ development perspective, using things like vs.net/c#/asp.net/asp.net mvc/sql server, things are pretty much smooth. (Obviously for someone coming from a microsoft background like me). Now I love the idea of open source, linux and terminal servering into the computer and doing things via the command line, no license issues really, etc. I've tried firing up eclipse etc., but I always seem to get stuck on some configuration issue or another. Does it get easier or is it just the territory when you are dealing with the java stack?

    Read the article

  • How does timezone really work in relation to PHP and MYSQL?

    - by Rick
    I am getting very strange results in terms of timezones. I am currently using Wordpress and everytime I register a new user, I see the wrong datetime in the database. Ok so I am suspecting it is picking up the server time. So then I then set in php.ini to have date.timezone = "America/Los_Angeles" but again the time is still not correct in the database...And yes I have also set the timezone in Wordpress correctly. So how can this be done?

    Read the article

  • My php script only reads the first row from mysql and doesn't check the rest of the rows for matches

    - by RobertH
    I'm trying to write a script for users to register to a club, and it does all the validation stuff properly and works great until it gets to the part where its supposed to check for duplicates. I'm not sure what is going wrong. HELP PLEASE!!! Thank you in Advance, <?php mysql_connect ("sqlhost", "username", "password") or die(mysql_error()); mysql_select_db ("databasename") or die(mysql_error()); $errormsgdb = ""; $errordb = "Sorry but that "; $error1db = "Name"; $error2db = "email"; $error3db = "mobile number"; $errordbe = " is already registered"; $pass1db = "No Matching Name"; $pass2db = "No Matching Email"; $pass3db = "No Matching Mobile"; $errorcount = 0; $qResult = mysql_query ("SELECT * FROM table"); $nRows = mysql_num_rows($qResult); for ($i=1; $i< $nRows+1; $i++){ $result = mysql_query("SELECT id,fname,lname,dob,email,mobile,agree,code,joindate FROM table WHERE fname = '$ffname"); if ($result > 0) { $errorcount = $errorcount++; $passdb = 0; $errormsgdb = $error1db; echo "<div class=\"box red\">$errordb $errormsgdb } else { $pass = 1; $errormsgdb = $pass1db; echo "<div class=\"box green\">$errormsgdb</div><br />"; } //--------------- Check if DB checks returned errors ------------------------------------> if($errorcount <= 0){ $dobp = $_REQUEST['day'].'/'.$_REQUEST['month'].'/'.$_REQUEST['year']; $dob = $_REQUEST['year'].$_REQUEST['month'].$_REQUEST['day']; //header('Location: thankyou.php?ffname='.$ffname.'&flname='.$flname.'&dob='.$dob.'&femail='.$femail.'&fmobile='.$fmobile.'&agree='.$agree.'&code='.$code.'&dobp='.$dobp); echo "<div class='box green'>Form completed! Error Count = $errorcount</div>"; } else { echo "<div class='box red'>There was an Error! Error Count = $errorcount</div>"; } } ?>

    Read the article

  • best method in jquery for replacing rows in a table after server side processing such as mysql sorti

    - by Kevin J
    What is the 'best practice' when returning dynamic data for a table (server side sorting, filtering etc from a db) ? Do you return just the data in json, and repeatedly clone a row element, replacing the values in each row (thus decreasing the size of the ajax call, but increasing the client side processing), or return the full html, and replace with .html or .append? Or is there another method I'm missing? This is a frequent situation in my app, and in some cases a bottleneck, and I am unsure if what I am doing is the best solution. Currently, I return the row html and use a single .append call, after emptying all the rows except the header.

    Read the article

  • How to current snapshot of MySQL Table and store it into CSV file(after creating it) ?

    - by Rachel
    I have large database table, approximately 5GB, now I wan to getCurrentSnapshot of Database using "Select * from MyTableName", am using PDO in PHP to interact with Database. So preparing a query and then executing it // Execute the prepared query $result->execute(); $resultCollection = $result->fetchAll(PDO::FETCH_ASSOC); is not an efficient way as lots of memory is being user for storing into the associative array data which is approximately, 5GB. My final goal is to collect data returned by Select query into an CSV file and put CSV file at an FTP Location from where Client can get it. Other Option I thought was to do: SELECT * INTO OUTFILE "c:/mydata.csv" FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY "\n" FROM my_table; But I am not sure if this would work as I have cron that initiates the complete process and we do not have an csv file, so basically for this approach, PHP Scripts will have to create an CSV file. Do a Select query on the database. Store the select query result into the CSV file. What would be the best or efficient way to do this kind of task ? Any Suggestions !!!

    Read the article

  • problem by displaying images stored in a MySQL database?

    - by user1400
    i have images in my blob field in database i use blow colde for displaying image but it does not show any pic , someone could tell me where is my wrong? this is my model: public function getListUser() { $select = $this->select() ->order('lastname DESC'); $adapter = new Zend_Paginator_Adapter_DbTableSelect ($select); return $adapter; } this my controller: $userModel = new Admin_Model_User(); $adapter = $userModel->getListUser(); $paginator = new Zend_Paginator ($adapter); $paginator->setItemCountPerPage(1); $page = $this->_request->getParam('page', 1); $paginator->setCurrentPageNumber($page); $this->view->paginator = $paginator; this my view code: <td style="width: 20%;"> <?php echo $this->lastname ?> </td> <td style="width: 20%;"><?php header("Content-type: image/gif"); print $this->image; ?></td>

    Read the article

  • How can I remove Ruby, Rails & mysql to start the installation process again?

    - by ben
    I've been trying to get setup with Ruby on Rails today, but I think I've followed some bad instructions along the way, and nothing seems to work. I've now borrowed the book "Agile Web Development with Rails, Third Edition" from a friend, and want to follow the setup instructions in that. Firstly, do I need to remove what I've setup previously? If yes, how do I do it? I can't seem to find instructions anywhere. I'm running OSX 10.6.1, so I know that it came with some stuff already setup, but I've been installing customized stuff over the top which I think I'll have to remove. Thanks for reading!

    Read the article

  • How does SELinux affect the /home directory?

    - by Matt Solnit
    Hi everyone. I'm migrating a CentOS 5.3 system from MySQL to PostgreSQL. The way our machine is set up is that the biggest disk partition is mounted to /home. This is out of my control and is managed by the hosting provider. Anyway, we obviously want the database files to be on /home for this reason. With MySQL, we did the following: Edited my.cnf and changed the datadir setting to /home/mysql Added a new "File type" policy record (I hope I'm using the right terminology) to set /home/mysql(/.*)? to mysqld_db_t Ran restorecon -R /home/mysql to assign the labels and everything was good. With PostgreSQL, however, I did the following: Edited /etc/init.d/postgresql and changed the PGDATA and PGLOG variables to /home/pgsql/data and /home/pgsql/pgstartup.log, respectively Added a new policy record to set /home/pgsql/pgstartup.log to postgresql_log_t Added a new policy record to set /home/pgsql/data(/.*)? to postgresql_db_t Ran restorecon -R /home/pgsql to assign the labels At this point, I still cannot start PostgreSQL. pgstartup.log says: # cat pgstartup.log postmaster cannot access the server configuration file "/home/pgsql/data/postgresql.conf": Permission denied The weird thing is that I don't see any messages related to this in /var/log/messages or /var/log/secure, but if I turn off SElinux, then everything works. I made sure all the permissions are correct (600 for files and 700 for directories), as well as the ownership (postgres:postgres). Can anyone tell me what I am doing wrong? I'm using the Yum repository from commandprompt.com, version 8.3.7. EDIT: The reason my question specifically mentions the /home directory is that if I go through all these steps for any other directory, e.g. /var/lib/pgsql2 or /usr/local/pgsql, then it works as expected.

    Read the article

< Previous Page | 400 401 402 403 404 405 406 407 408 409 410 411  | Next Page >