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  • Crash the program with cmd line args

    - by Debanjan
    Lets us consider the following program : #include <stdlib.h> int main(int argc, char **argv){ int a,b; if (argc != 3) return -1; a = atoi(argv[1]); b = atoi(argv[2]); a = b ? a/b : 0; return a; } The task is to crash the program by providing arguments in command-line.

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  • What does an object file contain

    - by benjamin button
    HI everyone, during the various stages of compilation in C or C++, i know that an object file gets generated. i.e., any_name.o file. what does thos .o file contain actually. i cant open it since its a binary file. Could anybody please help me? are the contents of the object file mainly Dependant on the compiler which we use on unix?

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  • C++ interview question

    - by benjamin button
    as i am not an expert in c++,i was not aware of the answer to this question asked in one of the interviews. lets say there is a base class pointer which is pointing to a base class object: baseclass *bptr; bptr= new baseclass; now if i do bptr= new derived; what is the problem here?

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  • Interview Question: What are the characteristics of a good programmer?

    - by froadie
    I was asked this question on an interview a few months ago - "What would you say are the characteristics of a good programmer?" What would you answer to this? What, as a hiring manager, would you be looking for in an answer? I did get the job and am currently working with this company, although I don't know if that means I answered what they wanted to hear, but here were a couple of the points I mentioned: Passion PATIENCE Logic Teamwork etc. I'm especially curious to hear from the hiring side of things what would impress as an answer...

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  • How to find the number of inversions in an array ?

    - by Michael
    This is an phone interview question: "Find the number of inversions in an array". I guess they mean O(N*log N) solution since O(N^2) is trivial. I guess it cannot be better than O(N*log N) since sorting is O(N*log N) I have checked a similar question from SO and can summarize the answers as follows: Calculate half the distance the elements should be moved to sort the array : copy the array and sort the copy. For each element of the original array a[i] find it's position j in the sorted copy (binary search) and sum abs(i - j)/2. Modify merge sort : modify merge to count inversions between two sorted arrays (it takes O(N)) and run merge sort with the modified merge. Does it make sense ? Are there other (maybe simpler) solution ? Isn't it too hard for a phone interview ?

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  • Java Inheritance Concept Understanding

    - by Nirmal
    Hello All.... I am just refreshing the oops features of the java. So, I have a little confusion regarding inheritance concept. For that I have a following sample code : class Super{ int index = 5; public void printVal(){ System.out.println("Super"); } } class Sub extends Super{ int index = 2; public void printVal(){ System.out.println("Sub"); } } public class Runner { public static void main(String args[]){ Super sup = new Sub(); System.out.println(sup.index+","); sup.printVal(); } } Now above code is giving me output as : 5,Sub. Here, we are overriding printVal() method, so that is understandable that it is accessing child class method only. But I could not understand why it's accessing the value of x from Super class... Thanks in advance....

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  • Interview question : What is the fastest way to generate prime number recursively ?

    - by hilal
    Generation of prime number is simple but what is the fastest way to find it and generate( prime numbers) it recursively ? Here is my solution. However, it is not the best way. I think it is O(N*sqrt(N)). Please correct me, if I am wrong. public static boolean isPrime(int n) { if (n < 2) { return false; } else if (n % 2 == 0 & n != 2) { return false; } else { return isPrime(n, (int) Math.sqrt(n)); } } private static boolean isPrime(int n, int i) { if (i < 2) { return true; } else if (n % i == 0) { return false; } else { return isPrime(n, --i); } } public static void generatePrimes(int n){ if(n < 2) { return ; } else if(isPrime(n)) { System.out.println(n); } generatePrimes(--n); } public static void main(String[] args) { generatePrimes(200); }

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  • Algorithms for finding the intersections of intervals

    - by tomwu
    I am wondering how I can find the number of intervals that intersect with the ones before it. for the intervals [2, 4], [1, 6], [5, 6], [0, 4], the output should be 2. from [2,4] [5,6] and [5,6] [0,4]. So now we have 1 set of intervals with size n all containing a point a, then we add another set of intervals size n as well, and all of the intervals are to the right of a. Can you do this in O(nlgn) and O(nlg^2n)?

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  • suggest an algorithm for the following puzzle!!

    - by garima
    There are n petrol bunks arranged in circle. Each bunk is separated from the rest by a certain distance. You choose some mode of travel which needs 1litre of petrol to cover 1km distance. You can't infinitely draw any amount of petrol from each bunk as each bunk has some limited petrol only. But you know that the sum of litres of petrol in all the bunks is equal to the distance to be covered. ie let P1, P2, ... Pn be n bunks arranged circularly. d1 is distance between p1 and p2, d2 is distance between p2 and p3. dn is distance between pn and p1.Now find out the bunk from where the travel can be started such that your mode of travel never runs out of fuel.

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  • At What point should you understand References?

    - by Vaccano
    I asked a question like this in an interview for a entry level programmer: var instance1 = new myObject{Value = "hello"} var instance2 = instance1; instance1.Value = "bye"; Console.WriteLine(instance1.Value); Console.WriteLine(instance2.Value); The applicant responded with "hello", "bye" as the output. Some of my co-workers said that "pointers" are not that important anymore or that this question is not a real judge of ability. Are they right?

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  • Interview question: C program to sort a binary array in O(n)

    - by Zacky112
    I've comeup with the following program to do it, but it does not seem to work and goes into infinite loop. Its working is similar to quicksort. int main() { int arr[] = {1,1,0,1,0,0,0,1,0,1,0,1,0,1,0,1,0,1}; int N = 18; int *front, *last; front = arr; last = arr + N; while(front <= last) { while( (front < last) && (*front == 0) ) front++; while( (front < last) && (*last == 1) ) last--; if( front < last) { int temp = *front; *front = *last; *last = temp; front ++; last--; } } for(int i=0;i<N;i++) printf("%d ",arr[i]); return 0; }

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  • Dealbreakers for new programming jobs?

    - by Echostorm
    What might be said or implied at an interview or job posting that should set off alarm bells for a coder? I'm still only a few years in the industry but I already know to look out for excessive red tape and bureaucracy. Cubes and a noisy office also tell me that I'll be both miserable and unproductive and that management does not appreciate what coders need to work well. Edit: The way things are going I'm taking extra time to look at the company's stability. If they depend on a single vendor for their livelihood and could be out of business if the vendor decides they don't really need the service or can do it in-house. What are your dealbreakers?

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  • How can we find second maximum from array efficiently?

    - by Xinus
    Is it possible to find the second maximum number from an array of integers by traversing the array only once? As an example, I have a array of five integers from which I want to find second maximum number. Here is an attempt I gave in the interview: #define MIN -1 int main() { int max=MIN,second_max=MIN; int arr[6]={0,1,2,3,4,5}; for(int i=0;i<5;i++){ cout<<"::"<<arr[i]; } for(int i=0;i<5;i++){ if(arr[i]>max){ second_max=max; max=arr[i]; } } cout<<endl<<"Second Max:"<<second_max; int i; cin>>i; return 0; } The interviewer, however, came up with the test case int arr[6]={5,4,3,2,1,0};, which prevents it from going to the if condition the second time. I said to the interviewer that the only way would be to parse the array two times (two for loops). Does anybody have a better solution?

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  • Arrange 0's & 1's in a array

    - by Ganesh M
    This is one of an interview question which I had recently. I would like to know others perception of approach for this problem. Question: You are given a structure which holds an employee details with two elements as int Deptartment and string Name. struct Employee { string Name; int Dept; } You are given details of N Employees among which there are N/2 employees Dept are 0's and N/2 employees dept are 1's arranged in some random order. You need to sort the employee details based on their Dept value and it should be stable i.e., the order of 1s and 0s in the original record should be maintained. For example, given the following sample data: Name Dept X1 0 X2 1 X3 0 X4 1 X5 0 after sorting the result should be: Name Dept X2 1 X4 1 X1 0 X3 0 X5 0 The algorithm should be stable and the complexity should be o(N), with constant space for additional variables (which means sorting should be done in-place).

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  • How to guard against memory leaks?

    - by just_wes
    I was recently interviewing for a C++ position, and I was asked how I guard against creating memory leaks. I know I didn't give a satisfactory answer to that question, so I'm throwing it to you guys. What are the best ways to guard against memory leaks? Thanks!

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  • Given a linked list of numbers. Swap every 2 adjacent links.

    - by Learner
    Given a linked list of numbers. Swap every 2 adjacent links. For eg if a linked list given to you is- a-b-c-d-e-f O/p expected- b-a-d-c-f-e Every 2 alternate links have to be swapped. I have written a solution here. Can you suggest me some other solution. Can you comment on my solution and help me better write it? void SwapAdjacentNodes (Node head) { if (head == null) return; if (head.next == null) return; Node curr = head; Node next = curr.Next; Node temp = next.Next; while (true) { temp = next.Next; next.Next = curr; curr.Next = temp; if (curr.Next != null) curr = curr.Next; else break; if (curr.Next.Next!=null) next = curr.Next.Next; else break; } }

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  • finding middle element of an array

    - by senthil
    Hi all, I came cross a question in my interview. Question: Array of integers will be given as the input and you should find out the middle element when sorted , but without sorting. For Example. Input: 1,3,5,4,2 Output: 3 When you sort the given input array, it will be 1,2,3,4,5 where middle element is 3. You should find this in one pass without sorting. Any solutions for this?

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