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  • How to create a SHA1 digest on a tree of objects?

    - by Torok Balint
    Let's say that I have a tree of objects of which every one have a string representation. I want to create a SHA1 digest on the whole tree. The easiest way would be to recursively go over each node of the tree. For each node I would concatenate (as simple strings) the SHA1 digests of all the children, add the string representation of the given nod to this concatenated string, and do a SHA1 on it. This would be the SHA1 digest of the given node. The question is will this digest be just as "good" as if I would have concatenated the string representation of the child nodes, and not the digests of the child nodes? Thanks

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  • How to store Hierarchical K-Means tree for a large number of images, using Opencv?

    - by AquaAsh
    I am trying to make a program that will find similar images from a dataset of images. The steps are 1)extract SURF descriptors for all images 2)store the descriptors 3)Apply knn on the stored descriptors 4)Match the stored descriptors to the query image descriptor using KNN Now each images SURF descriptor will be stored as Hierarchical k means tree, now do I store each tree as a separate file or is it possible to build some sort of single tree with all the images descriptors and updated as images are added to dataset. This is the paper I am basing the program on www.ijest.info/docs/IJEST10-02-03-13.pdf.

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  • Getting minimum - Min() - for DateTime column in a DataTable using LINQ to DataSets?

    - by Jay Stevens
    I need to get the minimum DateTime value of a column in a DataTable. The DataTable is generated dynamically from a CSV file, therefore I don't know the name of that column until runtime. Here is code I've got that doesn't work... private DateTime GetStartDateFromCSV(string inputFile, string date_attr) { EnumerableRowCollection<DataRow> table = CsvStreamReader.GetDataTableFromCSV(inputFile, "input", true).AsEnumerable(); DateTime dt = table.Select(record => record.Field<DateTime>(date_attr)).Min(); return dt; } The variable table is broken out just for clarity. I basically need to find the minimum value as a DateTime for one of the columns (to be chosen at runtime and represented by date_attr). I have tried several solutions from SO (most deal with known columns and/or non-DateTime fields). What I've got throws an error at runtime telling me that it can't do the DateTime conversion (that seems to be a problem with Linq?) I've confirmed that the data for the column name that is in the string date_attr is a date value.

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  • Adding a minimum display time for Silverlight splash screen.

    - by David
    When hosting a silverlight application on a webpage it is possible to use the splashscreensource parameter to specify a simple Silverlight 1.0 (xaml+javascript) control to be displayed while the real xap file is downloaded, and which can receive notification of the downloads progress through onSourceDownloadProgressChanged. If the xap file is in cache, the splash screen is not shown (and if the download only takes 1 second, the splash screen will only be shown for 1 second). I know this is not best practice in general, but I am looking for a way to specify a minimum display time for the splash screen - even if the xap cached or the download is fast, the splash screen would remain up for at least, let's say, 5 seconds (for example to show a required legal disclaimer, corporate identity mark or other bug). I do want to do it in the splash screen exclusively (rather then in the main xap) as I want it to be clean and uninterupted (for example a sound bug) and shown to the user as soon as they open the page, rather then after the download (which could take anywhere from 1 to 20+ seconds). I'd prefer not to accomplish this with preloading - replacing the splash screen with a full Silverlight xap application (with it's own loading screen), which then programmably loads and displays the full xap after a minimum wait time.

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  • Workarounds for supporting MVVM in the Silverlight TreeView Control

    - by cibrax
    MVVM (Model-View-ViewModel) is the pattern that you will typically choose for building testable user interfaces either in WPF or Silverlight. This pattern basically relies on the data binding support in those two technologies for mapping an existing model class (the view model) to the different parts of the UI or view. Unfortunately, MVVM was not threated as first citizen for some of controls released out of the box in the Silverlight runtime or the Silverlight toolkit. That means that using data binding for implementing MVVM is not always something trivial and usually requires some customization in the existing controls. In ran into different problems myself trying to fully support data binding in controls like the tree view or the context menu or things like drag & drop.  For that reason, I decided to write this post to show how the tree view control or the tree view items can be customized to support data binding in many of its properties. In first place, you will typically use a tree view for showing hierarchical data so the view model somehow must reflect that hierarchy. An easy way to implement hierarchy in a model is to use a base item element like this one, public abstract class TreeItemModel { public abstract IEnumerable<TreeItemModel> Children; } You can later derive your concrete model classes from that base class. For example, public class CustomerModel { public string FullName { get; set; } public string Address { get; set; } public IEnumerable<OrderModel> Orders { get; set; } }   public class CustomerTreeItemModel : TreeItemModel { public CustomerTreeItemModel(CustomerModel customer) { }   public override IEnumerable<TreeItemModel> Children { get { // Return orders } } } The Children property in the CustomerTreeItem model implementation can return for instance an ObservableCollection<TreeItemModel> with the orders, so the tree view will automatically subscribe to all the changes in the collection. You can bind this model to the tree view control in the UI by using a Hierarchical data template. <e:TreeView x:Name="TreeView" ItemsSource="{Binding Customers}"> <e:TreeView.ItemTemplate> <sdk:HierarchicalDataTemplate ItemsSource="{Binding Children}"> <!-- TEMPLATE --> </sdk:HierarchicalDataTemplate> </e:TreeView.ItemTemplate> </e:TreeView> An interesting behavior with the Children property and the Hierarchical data template is that the Children property is only invoked before the expansion, so you can use lazy load at this point (The tree view control will not expand the whole tree in the first expansion). The problem with using MVVM in this control is that you can not bind properties in model with specific properties of the TreeView item such as IsSelected or IsExpanded. Here is where you need to customize the existing tree view control to support data binding in tree items. public class CustomTreeView : TreeView { public CustomTreeView() { }   protected override DependencyObject GetContainerForItemOverride() { CustomTreeViewItem tvi = new CustomTreeViewItem(); Binding expandedBinding = new Binding("IsExpanded"); expandedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsExpandedProperty, expandedBinding); Binding selectedBinding = new Binding("IsSelected"); selectedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsSelectedProperty, selectedBinding); return tvi; } }   public class CustomTreeViewItem : TreeViewItem { public CustomTreeViewItem() { }   protected override DependencyObject GetContainerForItemOverride() { CustomTreeViewItem tvi = new CustomTreeViewItem(); Binding expandedBinding = new Binding("IsExpanded"); expandedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsExpandedProperty, expandedBinding); Binding selectedBinding = new Binding("IsSelected"); selectedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsSelectedProperty, selectedBinding); return tvi; } } You basically need to derive the TreeView and TreeViewItem controls to manually add a binding for the properties you need. In the example above, I am adding a binding for the “IsExpanded” and “IsSelected” properties in the items. The model for the tree items now needs to be extended to support those properties as well, public abstract class TreeItemModel : INotifyPropertyChanged { bool isExpanded = false; bool isSelected = false;   public abstract IEnumerable<TreeItemModel> Children { get; }   public bool IsExpanded { get { return isExpanded; } set { isExpanded = value; if (PropertyChanged != null) PropertyChanged(this, new PropertyChangedEventArgs("IsExpanded")); } }   public bool IsSelected { get { return isSelected; } set { isSelected = value; if (PropertyChanged != null) PropertyChanged(this, new PropertyChangedEventArgs("IsSelected")); } }   public event PropertyChangedEventHandler PropertyChanged; } However, as soon as you use this custom tree view control, you lose all the automatic styles from the built-in toolkit themes because they are tied to the control type (TreeView in this case).  The only ugly workaround I found so far for this problem is to copy the styles from the Toolkit source code and reuse them in the application.

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  • Monkey Hunter algorithm - Interview question [closed]

    - by Estefany Velez
    Question asked in an Interview: You are a hunter in the forest. A monkey is in the trees, but you don't know where and you can't see it. You can shoot at the trees, you have unlimited ammunition. Immediately after you shoot at a tree, if the monkey was in the tree, he falls and you win. If the monkey was not in the tree, he jumps (randomly) to an adjacent tree (he has to). Find an algorithm to get the monkey in the fewest shots possible. SOLUTION: The correct answer according to me was in the comments, credit to @rtperson: You could eliminate this possibility by shooting each tree twice as you sweep left, giving you a worst case of O(2n). EDIT: ...that is, a worst case of O(2n-1). You don't need to shoot the last tree twice.

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  • How to build, sort and print a tree of a sort?

    - by Tuplanolla
    This is more of an algorithmic dilemma than a language-specific problem, but since I'm currently using Ruby I'll tag this as such. I've already spent over 20 hours on this and I would've never believed it if someone told me writing a LaTeX parser was a walk in the park in comparison. I have a loop to read hierarchies (that are prefixed with \m) from different files art.tex: \m{Art} graphical.tex: \m{Art}{Graphical} me.tex: \m{About}{Me} music.tex: \m{Art}{Music} notes.tex: \m{Art}{Music}{Sheet Music} site.tex: \m{About}{Site} something.tex: \m{Something} whatever.tex: \m{Something}{That}{Does Not}{Matter} and I need to sort them alphabetically and print them out as a tree About Me (me.tex) Site (site.tex) Art (art.tex) Graphical (graphical.tex) Music (music.tex) Sheet Music (notes.tex) Something (something.tex) That Does Not Matter (whatever.tex) in (X)HTML <ul> <li>About</li> <ul> <li><a href="me.tex">Me</a></li> <li><a href="site.tex">Site</a></li> </ul> <li><a href="art.tex">Art</a></li> <ul> <li><a href="graphical.tex">Graphical</a></li> <li><a href="music.tex">Music</a></li> <ul> <li><a href="notes.tex">Sheet Music</a></li> </ul> </ul> <li><a href="something.tex">Something</a></li> <ul> <li>That</li> <ul> <li>Doesn't</li> <ul> <li><a href="whatever.tex">Matter</a></li> </ul> </ul> </ul> </ul> using Ruby without Rails, which means that at least Array.sort and Dir.glob are available. All of my attempts were formed like this (as this part should work just fine). def fss_brace_array(ss_input)#a concise version of another function; converts {1}{2}...{n} into an array [1, 2, ..., n] or returns an empty array ss_output = ss_input[1].scan(%r{\{(.*?)\}}) rescue ss_output = [] ensure return ss_output end #define tree s_handle = File.join(:content.to_s, "*") Dir.glob("#{s_handle}.tex").each do |s_handle| File.open(s_handle, "r") do |f_handle| while s_line = f_handle.gets if s_all = s_line.match(%r{\\m\{(\{.*?\})+\}}) s_all = s_all.to_a #do something with tree, fss_brace_array(s_all) and s_handle break end end end end #do something else with tree

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  • Mysql query to get distict hotel id with minimum price and star?

    - by user1325929
    Current table hotel_id | price | star 1100 | 1999 | 3 1100 | 1565 | 3 1100 | 2000 | 3 1101 | 2010 | 4 1101 | 2050 | 4 1102 | 5599 | 5 1102 | 6599 | 5 Required result: distinct hotels with minimum price and it's star hotel_id | price | star 1100 | 1565 | 3 1101 | 2010 | 4 1102 | 5599 | 5 I wrote query as SELECT DISTINCT hotel_id, min(price),star FROM MyTable. It is giving only 1 row instead of 3

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  • What is the minimum number of socket port(s) required for a TCP server?

    - by Gwilym
    Hey SO Doing a some practice questions for exam tomorrow can't figure out this one What is the minimum number of socket port(s) required for a TCP server to connect a TCP client for communication? Surely its just two right? one for the server one for the client, but this seems to obvious. My mates thinks TCP uses two ports at the server end for for data in and one for data out. thanks in advance

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  • how to generate an N level tree using datatable?

    - by Kishore Kumar
    I have a DataTable with column ID, Name, RootID. The tree stucture is implmented using the RootId field. If the RootId is null it is considered as Root Node. How to create an Nlevel tree using the DataTale. eg. 1 Manager null, 2 Project Lead 1, 3 Test Lead 1, 4 Sr Soft Eng 2, 5 Soft eng 2, 6 HR Manager Null, 7 HR exec 6, ......

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  • Dell 2950 Perc 6/i "physical disk" and "Enclosure(Backplane)" under Connector 1 in OMSA tree- Troubleshoot help

    - by user66357
    Just looking for someone who might know why this could occur... In OMSA, on my Dell 2950, there usually is only one "Physical Disks" child under "Enclosure (Backplane)" in the tree view. Currently, the tree looks like this: Dell PERC 6/i Integrated Connector 1 (RAID) Enclosure (Backplane) Physical Disks (1:04 good, 1:05 removed) Physical Disks (1:33 Ready but unused) Normally it's like this: Connector 1 (RAID) Enclosure (Backplane) Physical Disks (1:04 good, 1:05 good) From the front, 6 of 6 3.5" SAS drives are connected. The server is showing Slot 5 as bad and the disk as removed. It seems that the drive in Slot 5 is being sensed as external to the Enclosure. Any ideas why this would happen? Think I can get away with rebuilding the virtual disk by replacing 1:05 with 1:33? Thanks. UPDATE: The only options on the Physical Disk 1:33 were Assign as Global Hot Spare and Clear... After clearing, I assigned it as the Global Hot Spare. This allowed the rebuilding of the virtual disk. Hopefully it won't fail. I'm still unsure of the reason for this odd behavior. I'm checking the firmware next.

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  • Kill a tree, save your website? Content strategy in action, part III

    - by Roger Hart
    A lot has been written about how driving content strategy from within an organisation is hard. And that's true. Red Gate is pretty receptive to new ideas, so although I've not had a total walk in the park, it's been a hike with charming scenery. But I'm one of the lucky ones. Lots of people are involved in content, and depending on your organisation some of those people might be the kind who'll gleefully call themselves "stakeholders". People holding a stake generally want to stick it through something's heart and bury it at a crossroads. Winning them over is not always easy. (Richard Ingram has made a nice visual summary of how this can feel - Content strategy Snakes & ladders - pdf ) So yes, a lot of content strategy advocates are having a hard time. And sure, we've got a nice opportunity to get together and have a hug and a cry, but in the interim we could use a hand. What to do? My preferred approach is, I'll confess, brutal. I'd like nothing so much as to take a scorched earth approach to our website. Burn it, salt the ground, and build the new one right: focusing on clearly delineated business and user content goals, and instrumented so we can tell if we're doing it right. I'm never getting buy-in for that, but a boy can dream. So how about just getting buy-in for some small, tenable improvements? Easier, but still non-trivial. I sat down for a chat with our marketing and design guys. It seemed like a good place to start, even if they weren't up for my "Ctrl-A + Delete"  solution. We talked through some of this stuff, and we pretty much agreed that our content is a bit more broken than we'd ideally like. But to get everybody on board, the problems needed visibility. Doing a visual content inventory Print out the internet. Make a Wall Of Content. Seriously. If you've already done a content inventory, you know your architecture, and you know the scale of the problem. But it's quite likely that very few other people do. So make it big and visual. I'm going to carbon hell, but it seems to be working. This morning, I printed out a tiny, tiny part of our website: the non-support content pertaining to SQL Compare I made big, visual, A3 blowups of each page, and covered a wall with them. A page per web page, spread over something like 6M x 2M, with metrics, right in front of people. Even if nobody reads it (and they are doing) the sheer scale is shocking. 53 pages, all told. Some are redundant, some outdated, some trivial, a few fantastic, and frighteningly many that are great ideas delivered not-quite-right. You have to stand quite far away to get it all in your field of vision. For a lot of today, a whole bunch of folks have been gawping in amazement, talking each other through it, peering at the details, and generally getting excited about content. Developers, sales guys, our CEO, the marketing folks - they're engaged. Will it last? I make no promises. But this sort of wave of interest is vital to getting a content strategy project kicked off. While the content strategist is a saucer-eyed orphan in the cupboard under the stairs, they're not getting a whole lot done. Of course, just printing the site won't necessarily cut it. You have to know your content, and be able to talk about it. Ideally, you'll also have page view and time-on-page metrics. One of the most powerful things you can do is, when people are staring at your wall of content, ask them what they think half of it is for. Pretty soon, you've made a case for content strategy. We're also going to get folks to mark it up - cover it with notes and post-its, let us know how they feel about our content. I'll be blogging about how that goes, but it's exciting. Different business functions have different needs from content, so the more exposure the content gets, and the more feedback, the more you know about those needs. Fingers crossed for awesome.

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  • In this context with views in a tree, which class should perform the task?

    - by Jhonny 8
    Imagine that I have this context: A main view containing a table containing some cells. Each one of them with their own controller and view files. In the main view, I have an object "Person", with 3 different IDs. Depending on certain conditions (let say, time of the day), I have to choose one of them and display it in the cell. My question is, should the main view pass the whole object to the table, and this one to the cell, and the cell will calculate the ID that it will be shown? or, The main view calculates this parameter, and send the result to the table and this to the cell? Is a question focused on OO design, which one of this approaches is more suitable in an OO design and why?

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  • How can you tell whether to use Composite Pattern or a Tree Structure, or a third implementation?

    - by Aske B.
    I have two client types, an "Observer"-type and a "Subject"-type. They're both associated with a hierarchy of groups. The Observer will receive (calendar) data from the groups it is associated with throughout the different hierarchies. This data is calculated by combining data from 'parent' groups of the group trying to collect data (each group can have only one parent). The Subject will be able to create the data (that the Observers will receive) in the groups they're associated with. When data is created in a group, all 'children' of the group will have the data as well, and they will be able to make their own version of a specific area of the data, but still linked to the original data created (in my specific implementation, the original data will contain time-period(s) and headline, while the subgroups specify the rest of the data for the receivers directly linked to their respective groups). However, when the Subject creates data, it has to check if all affected Observers have any data that conflicts with this, which means a huge recursive function, as far as I can understand. So I think this can be summed up to the fact that I need to be able to have a hierarchy that you can go up and down in, and some places be able to treat them as a whole (recursion, basically). Also, I'm not just aiming at a solution that works. I'm hoping to find a solution that is relatively easy to understand (architecture-wise at least) and also flexible enough to be able to easily receive additional functionality in the future. Is there a design pattern, or a good practice to go by, to solve this problem or similar hierarchy problems? EDIT: Here's the design I have: The "Phoenix"-class is named that way because I didn't think of an appropriate name yet. But besides this I need to be able to hide specific activities for specific observers, even though they are attached to them through the groups. A little Off-topic: Personally, I feel that I should be able to chop this problem down to smaller problems, but it escapes me how. I think it's because it involves multiple recursive functionalities that aren't associated with each other and different client types that needs to get information in different ways. I can't really wrap my head around it. If anyone can guide me in a direction of how to become better at encapsulating hierarchy problems, I'd be very glad to receive that as well.

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  • I need some help creating a non-binary tree (or some other data structure that will better solve my problem)

    - by EDO
    I have about ten lists of numbers and some strings. Each list has about <= 30K lines. Each line on a list has a distinct number. I need to build an efficient way of finding all the lines in each list that has the same 'control' number (or key for dB guys) and comparing what is in their string parts. I am writing this in Java. I have thought about using trees but my brain cells are about burnt now. I need some help.

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  • How can I force apt to optimize the dependency tree for minimal download size?

    - by ObsessiveSSO?
    Some background information: As you may know, in a Debian package, there may be alternative dependencies, written in the CONTROL file as Depends: apache2|something-else, for example. How does apt select which dependencies to choose, and how can I override this so I can minimize download size? I'm on a slow connection on some locations and need it to use the smallest total download size. How can I force it to do so?

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  • tree view; show lines property is not working properly

    - by Jibu P C
    Hii, I am a bigginer in using tree view control. I am using tree view control to make a simple tree like structure. But when i use show lines property it is not connecting to the root node. The code which i have written is as follows. <asp:TreeView ID="treeSettings" runat="server" ImageSet="Simple2" NodeIndent="15" ShowLines="True"> <ParentNodeStyle Font-Bold="False" /> <HoverNodeStyle BackColor="#CCCCCC" BorderColor="#888888" BorderStyle="None" Font-Underline="True" /> <SelectedNodeStyle BackColor="#FFCCCC" Font-Underline="False" HorizontalPadding="0px" VerticalPadding="1px" Height="0px" /> <Nodes> <asp:TreeNode Text="Settings" Value="Settings"> <asp:TreeNode Text="Edit Task" Value="Edit Task"></asp:TreeNode> <asp:TreeNode Text="Assign" Value="Assign a Resource"></asp:TreeNode> <asp:TreeNode Text="Task Status" Value="Task Status"></asp:TreeNode> </asp:TreeNode> </Nodes> <NodeStyle Font-Names="Verdana" Font-Size="8pt" ForeColor="Black" HorizontalPadding="0px" NodeSpacing="1px" VerticalPadding="0px" Width="100px" ChildNodesPadding="0px" /> <LeafNodeStyle NodeSpacing="0px" /> </asp:TreeView>enter code here`

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