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  • PHP regex for password validation

    - by Fabio Anselmo
    I not getting the desired effect from a script. I want the password to contain A-Z, a-z, 0-9, and special chars. A-Z a-z 0-9 2 special chars 2 string length = 8 So I want to force the user to use at least 2 digits and at least 2 special chars. Ok my script works but forces me to use the digits or chars back to back. I don't want that. e.g. password testABC55$$ is valid - but i don't want that. Instead I want test$ABC5#8 to be valid. So basically the digits/special char can be the same or diff - but must be split up in the string. PHP CODE: $uppercase = preg_match('#[A-Z]#', $password); $lowercase = preg_match('#[a-z]#', $password); $number = preg_match('#[0-9]#', $password); $special = preg_match('#[\W]{2,}#', $password); $length = strlen($password) >= 8; if(!$uppercase || !$lowercase || !$number || !$special || !$length) { $errorpw = 'Bad Password';

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  • jQuery password strength plugin callback validation method

    - by jmorhardt
    I'm using a a jQuery plugin to evaluate password strength. It gives a graphical representation for the user to see how secure the password is. I'd like to use it to validate the field as well. The plugin works by assessing the password and giving it a score. I want to be able to verify that the user has entered a password of at least a certain score. The code is hosted on jQuery's site here: http://plugins.jquery.com/project/pstrength. The documentation states that there is a way to add a rule and do custom validation. I'm not sure where to start. The inline documentation states: * === Changelog === * Version 2.1 (18/05/2008) * Added a jQuery method to add a new rule: jQuery('input[@type=password]').pstrength.addRule(name, method, score, active) And later in the code there's this method: jQuery.extend(jQuery.fn.pstrength, { 'addRule': function (name, method, score, active) { digitalspaghetti.password.addRule(name, method, score, active); return true; }, 'changeScore': function (rule, score) { digitalspaghetti.password.ruleScores[rule] = score; return true; }, 'ruleActive': function (rule, active) { digitalspaghetti.password.rules[rule] = active; return true; } }); If anybody has seen an example of how to do this I'd appreciate a pointer in the right direction. Thanks!

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  • Is this simple XOR encrypted communication absolutely secure?

    - by user3123061
    Say Alice have 4GB USB flash memory and Peter also have 4GB USB flash memory. They once meet and save on both of memories two files named alice_to_peter.key (2GB) and peter_to_alice.key (2GB) which is randomly generated bits. Then they never meet again and communicate electronicaly. Alice also maintains variable called alice_pointer and Peter maintains variable called peter_pointer which is both initially set to zero. Then when Alice needs to send message to Peter they do: encrypted_message_to_peter[n] = message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] Where n i n-th byte of message. Then alice_pointer is attached at begining of the encrypted message and (alice_pointer + encrypted message) is sent to Peter and then alice_pointer is incremented by length of message (and for maximum security can be used part of key erased) Peter receives encrypted_message, reads alice_pointer stored at beginning of message and do this: message_to_peter[n] = encrypted_message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] And for maximum security after reading of message also erases used part of key. - EDIT: In fact this step with this simple algorithm (without integrity check and authentication) decreases security, see Paulo Ebermann post below. When Peter needs to send message to Alice they do analogical steps with peter_to_alice.key and with peter_pointer. With this trivial schema they can send for next 50 years each day 2GB / (50 * 365) = cca 115kB of encrypted data in both directions. If they need more data to send, they simple use larger memory for keys for example with today 2TB harddiscs (1TB keys) is possible to exchange next 50years 60MB/day ! (thats practicaly lots of data for example with using compression its more than hour of high quality voice communication) It Seems to me there is no way for attacker to read encrypted message without keys even if they have infinitely fast computer. because even with infinitely fast computer with brute force they get ever possible message that can fit to length of message, but this is astronomical amount of messages and attacker dont know which of them is actual message. I am right? Is this communication schema really absolutely secure? And if its secure, has this communication method its own name? (I mean XOR encryption is well-known, but whats name of this concrete practical application with use large memories at both communication sides for keys? I am humbly expecting that this application has been invented someone before me :-) ) Note: If its absolutely secure then its amazing because with today low cost large memories it is practicaly much cheeper way of secure communication than expensive quantum cryptography and with equivalent security! EDIT: I think it will be more and more practical in future with lower a lower cost of memories. It can solve secure communication forever. Today you have no certainty if someone succesfuly atack to existing ciphers one year later and make its often expensive implementations unsecure. In many cases before comunication exist step where communicating sides meets personaly, thats time to generate large keys. I think its perfect for military communication for example for communication with submarines which can have installed harddrive with large keys and military central can have harddrive for each submarine they have. It can be also practical in everyday life for example for control your bank account because when you create your account you meet with bank etc.

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  • Can't get Postfix Admin to use Dovecot password hashing

    - by Paul
    I'm setting up Postfix Admin 2.91 and trying to use dovecot:SHA512-CRYPT for password hashing. In config.inc.php I have set: // dovecot:CRYPT-METHOD = use dovecotpw -s 'CRYPT-METHOD'. Example: dovecot:CRAM-MD5 // (WARNING: don't use dovecot:* methods that include the username in the hash - you won't be able to login to PostfixAdmin in this case) $CONF['encrypt'] = 'dovecot:SHA512-CRYPT'; // If you use the dovecot encryption method: where is the dovecotpw binary located? // for dovecot 1.x // $CONF['dovecotpw'] = "/usr/sbin/dovecotpw"; // for dovecot 2.x (dovecot 2.0.0 - 2.0.7 is not supported!) $CONF['dovecotpw'] = "/usr/sbin/doveadm pw"; I have also tried SHA256-CRYPT and MD5-CRYPT with same results (as I understand it, these do not include usernames in the hash) In running setup.php, I get the following message when trying to create an admin account: can't encrypt password with dovecotpw, see error log for details Server error log reports: 1624#0: *6 FastCGI sent in stderr: "PHP message: dovecotpw password encryption failed. PHP message: STDERR output: sh: 1: /usr/sbin/doveadm: not found" while reading response header from upstream <...> upstream: "fastcgi://unix:/var/run/php5-fpm.sock:" <...> A couple quick checks: # ll /usr/sbin/doveadm -rwxr-xr-x 1 root root 423264 Feb 13 23:23 /usr/bin/doveadm* # doveadm pw -l CRYPT MD5 MD5-CRYPT SHA SHA1 SHA256 SHA512 SMD5 SSHA SSHA256 SSHA512 PLAIN CLEAR CLEARTEXT PLAIN-TRUNC CRAM-MD5 SCRAM-SHA-1 HMAC-MD5 DIGEST-MD5 PLAIN-MD4 PLAIN-MD5 LDAP-MD5 LANMAN NTLM OTP SKEY RPA SHA256-CRYPT SHA512-CRYPT # doveadmin pw -s SHA512-CRYPT Enter new password: Retype new password: {SHA512-CRYPT}$6$<long string here>/ Using Dovecot 2.2, PHP 5.5, MariaDB 10, Postfix 2.11, nginx 1.6.0, Ubuntu 12.04.

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  • samsung CLP-310N password recovery

    - by alumb
    I have a Samsung CLP-310N printer and I'm trying to get the Administrator password. Is there a default password? Any way to reset the printer to defaults? Anyone run into this problem before? (I tried Network Settings -- Reset -- Factory Defaults, but that requires a password)

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  • Enable SMB file sharing on OS X - "Incorrect Password"

    - by Tim Robinson
    I have a Mac running Snow Leopard connected to an Active Directory domain. I can share folders on the Mac and view files from Windows without problems. When I try to enable my Mac account for write access through System Preferences, I'm prompted for my account's password. Even though I'm entering the right one, I get an "Incorrect Password" response. The same process works fine for the local Mac administrator account; it's the Active Directory account I'm having problems with. I followed the advice on this page on apple.com without success: (I used the Mac to reset my domain password, and re-created my login keychain) If you want to use a user account that existed before you installed Mac OS X 10.3 (Panther), you may need to reset the password for the account using Accounts preferences. Can anyone suggest what might be wrong? Until I fix this I can't write to my Mac file share from Windows.

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  • Cannot login to Postgrest database despite setting password for user 'postgres'

    - by Serg
    I'm trying to use pgAdmin III to manage my Postgres database. Here are the commands I've run on my machine: sudo apt-get install postgresql Then I installed the pgAdmin III application: sudo apt-get install pgadmin3 Next I focused on setting my username and password in order to login: sudo -u postgres psql postgres Here I set my password \password postgres Finally I just created my database: sudo -u postgres createdb repairsdatabase When I try to login using pgAdmin III, I get the error: An error has occurred: Error connecting to the server: FATAL: Peer authentication failed for user "postgres"

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  • Changed Password Won't seem to work for account

    - by erik
    Bit of an odd problem. I've got a server I can SSH into as one of two logins: root or erik. Once I've logged in as erik I've tried to switch to the root user: # sudo su - root Password: And entered the password. After several failures I thought I might have forgotten. So I SSH'd in as root, and changed the root password: # passwd Now back to the other shell (erik) and attempt to run sudo su - root and again, it won't accept the just changed password. Any ideas?

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  • Suggestions for Scheduled Tasks to call OSQL without hard-coding cleartext password

    - by Ian Boyd
    Can anyone think of any techniques where i can have a Windows scheduled task run OSQL, but not have to pass the clear-text password with cleartext password being in the clear? E.g.: >osql -U iboyd -P BabyBatterStapleCorrect Assumption: No Windows Authentication (since it's not an option) i was hoping there was a >OSQL -encryptPassword "BabyBatterStapleCorrect" > > OSQL > Encrypted password: WWVzIGkgd2FudCB0byByYXBlIGJhYmllcy4gQmlnIHdob29wLiBXYW5uYSBmaWdodCBhYm91dCBpdD8= And then i could call OSQL with: >osql -U ian -P WWVzIGkgd2FudCB0byByYXBlIGJhYmllcy4gQmlnIHdob29wLiBXYW5uYSBmaWdodCBhYm91dCBpdD8= But that's not something Microsoft implemented.

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  • Ubuntu: How to login without entering username and password

    - by torbengb
    I'm a newbie running Ubuntu 9.10. I have two users (wife and me), and each user's screensaver is set to lock so that on wakeup, we get to choose which user's desktop to go to. However, Ubuntu requires a password, so this is pretty tedious. I'd like to switch users without entering any password. I know about this trick that works for the boot login, but it doesn't deal with multiple users. Is it possible to set empty passwords for users in Ubuntu, or skip the password in other ways? (I'm expecting real Linux users to suggest that passwordless users must not get any rights and there be an admin user with a strong password. Yes, you're right. But that's not what this question is about. Thanks.)

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  • Password rules for yppasswd

    - by gstoynev
    Hello all, I have a NIS master-slave setup and I would like to improve the password rules/complexity for it. Seems like if I introduce new rules to the NIS Master they are applicable only from there. What I mean: I want minimal password length of 9 characters. On the NIS master if I run 'passwd' it obeys this requirement. If I run 'yppasswd' it just go to the default 6 characters. If I use 'chage -d 0 user1' to force a user to change a password, the user is prompted only when login on the NIS Master. The user's old password is still good to login at NIS clients. All machines are running Ubuntu 9.10 or 10.04. How I can strengthen yppasswd rules and make it warn users to change their passwords? Thank you all!

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  • Any command line tool checking windows domain password?

    - by Chen Jun
    Does Windows provide a command line utility that lets me check a domain user's password? It is sufficient that the utility returns success(0) if I provide a matching domain user name and password. Alternatively, is there a simple VB/JS script that can do this? I'm the Intranet admin of my company and have the default password set for corporate staff, so I'd like to quickly scan which users have not changed their default password. Better yet, are there any books or websites which cover such topics so that I can get more information?

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  • How to change Windows admin password from guest user

    - by John Smiith
    How to gain access of admin account of Windows, I activated a guest user and I want to change the admin password from the command line. When I type: net user administrator password the response is System error 5 has occurred. Access is denied I am using winxp pro sp2 I am running this command from cdm.exe and I am running this command from guest user. I actually want to change my admin password from guest user.

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  • SSH asking for password for one user and not another

    - by Ocasta Eshu
    I have two users on the same machine and am attempting to set up SSH for user#2. SSH was still asking for a password for the second user so I copied the .rsa file from user#1 to user#2. although they have identical files and permissions and although no password is asked of user#1, SSH still asks for a password from user#2. What could cause two users on the same machine with identical .rsa files to have different responses from SSH?

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  • Windows Scheduled Tasks losing password configuration

    - by E Brown
    I have a couple of jobs scheduled to run daily on a customer server running Windows Server 2003 Standard Edition, SP1 using Windows Scheduled Tasks. The tasks are set to run as a user that is in the Administrators group, and were scheduled as that same user. The password of that user is set to never expire. These tasks fail to run pretty much every day. Going into Scheduled Tasks and attempting to run the tasks manually indicates that the password is incorrect. I go into the task properties, retype the password into the appropriate fields, click OK, and attempt to run the task manually again. Now it works fine. What might be the cause of the password being lost like this? These same tasks are running on other customers servers with no problems. Thanks in advance for any thoughts.

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  • SASL + postfixadmin - SMTP authentication with hashed password

    - by mateo
    Hi all, I'm trying to set up the mail server. I have problem with my SMTP authentication using sasl. I'm using postfixadmin to create my mailboxes, the password is in some kind of md5, postfixadmin config.inc.php: $CONF['encrypt'] = 'md5crypt'; $CONF['authlib_default_flavor'] = 'md5raw'; the sasl is configured like that (/etc/postfix/sasl/smtpd.conf): pwcheck_method: auxprop auxprop_plugin: sql sql_engine: mysql mech_list: plain login cram-md5 digest-md5 sql_hostnames: 127.0.0.1 sql_user: postfix sql_passwd: **** sql_database: postfix sql_select: SELECT password FROM mailbox WHERE username = '%u@%r' log_level: 7 If I want to authenticate (let's say from Thunderbird) with my password, I can't. If I use hashed password from MySQL I can authenticate and send an email. So I think the problem is with hash algorithm. Do you know how to set up the SASL (or postfixadmin) to work fine together. I don't want to store my passwords in plain text...

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  • sudo displays typed password in bash script

    - by Andy
    Hullo, I have a bash script that uses sudo a few times. There's a couple of strange points about it though. It asks me for my password a few seconds after I've already entered it for a previous command. The second time I enter my password, it's echoed to the display. Here's the relevant bits of the script. sudo service apache2 stop drush sql-dump --root="$SITE_DIR" --structure-tables-key=svn --ordered-dump | grep -iv 'dump completed on' | sudo tee "$DB_DIR/${SITE_NAME}.sql" > /dev/null sudo svn diff "$DB_DIR" | less sudo svn commit -m "$MESSAGE" "$DB_DIR" sudo service apache2 start The first password is to stop apache, and it works as expected. As mentioned, the sudo tee doesn't 'remember' that I have elevated privileges, asks for the password again, and echoes it to the screen. Given that tee is all about echoing to screen, I've played around a little with simple scripts which have | sudo tee, and they all work as expected. Ideas?! TIA Andy

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  • SVN shared password db on Windows server

    - by Greg McGuffey
    I'd like to have a shared password-db file for several repositories on my home svn server (run under Windows). I've figured out that I need to set all the repositories to have the same realm, but I can't figure out how to just put in an absolute path to the shared password-db. I.e. the full path is something like: c:\svn.users\passwrd What do I set the password-db setting to in svnserve.conf so it can find this file?

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  • How to switch users without entering password

    - by torbengb
    I'm a newbie running Ubuntu 9.10. I have two users (wife and me), and each user's screensaver is set to lock so that on wakeup, we get to choose which user's desktop to go to. However, Ubuntu requires a password, so this is pretty tedious. I'd like to switch users without entering any password. I know about this trick that works for the boot login, but it doesn't deal with multiple users. Is it possible to set empty passwords for users in Ubuntu, or skip the password in other ways? (I'm expecting real Linux users to suggest that passwordless users must not get any rights and there be an admin user with a strong password. Yes, you're right. But that's not what this question is about. Thanks.)

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