Search Results

Search found 3825 results on 153 pages for 'regex negation'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 41/153 | < Previous Page | 37 38 39 40 41 42 43 44 45 46 47 48  | Next Page >

  • Parsing SQLIO Output to Excel Charts using Regex in PowerShell

    - by Jonathan Kehayias
    Today Joe Webb ( Blog | Twitter ) blogged about The Power of Regex in Powershell, and in his post he shows how to parse the SQL Server Error Log for events of interest. At the end of his blog post Joe asked about other places where Regular Expressions have been useful in PowerShell so I thought I’d blog my script for parsing SQLIO output using Regex in PowerShell, to populate an Excel worksheet and build charts based on the results automatically. If you’ve never used SQLIO, Brent Ozar ( Blog | Twitter...(read more)

    Read the article

  • What’s New in Delphi XE6 Regular Expressions

    - by Jan Goyvaerts
    There’s not much new in the regular expression support in Delphi XE6. The big change that should be made, upgrading to PCRE 8.30 or later and switching to the pcre16 functions that use UTF-16, still hasn’t been made. XE6 still uses PCRE 7.9 and thus continues to require conversion from the UTF-16 strings that Delphi uses natively to the UTF-8 strings that older versions of PCRE require. Delphi XE6 does fix one important issue that has plagued TRegEx since it was introduced in Delphi XE. Previously, TRegEx could not find zero-length matches. So a regex like (?m)^ that should find a zero-length match at the start of each line would not find any matches at all with TRegEx. The reason for this is that TRegEx uses TPerlRegEx to do the heavy lifting. TPerlRegEx sets its State property to [preNotEmpty] in its constructor, which tells it to skip zero-length matches. This is not a problem with TPerlRegEx because users of this class can change the State property. But TRegEx does not provide a way to change this property. So in Delphi XE5 and prior, TRegEx cannot find zero-length matches. In Delphi XE6 TPerlRegEx’s constructor was changed to initialize State to the empty set. This means TRegEx is now able to find zero-length matches. TRegex.Replace() using the regex (?m)^ now inserts the replacement at the start of each line, as you would expect. If you use TPerlRegEx directly, you’ll need to set State to [preNotEmpty] in your own code if you relied on its behavior to skip zero-length matches. You will need to check existing applications that use TRegEx for regular expressions that incorrectly allow zero-length matches. In XE5 and prior, TRegEx using \d* would match all numbers in a string. In XE6, the same regex still matches all numbers, but also finds a zero-length match at each position in the string. RegexBuddy 4 warns about zero-length matches on the Create panel if you set it to Detailed mode. At the bottom of the regex tree there will be a node saying either “your regular expression may find zero-length matches” or “zero-length matches will be skipped” depending on whether your application allows zero-length matches (XE6 TRegEx) or not (XE–XE5 TRegEx).

    Read the article

  • Is it possible to get the matched regex from within the apache LocationMatch directive?

    - by tftd
    I'm wondering if the following code should be working: <LocationMatch "/(.*)([/])?(.*)"> Order allow,deny Allow from all AuthType Basic AuthName "Git" AuthUserFile /git/.htpasswd AuthGroupFile /git/.htgroup Require group $1 </LocationMatch> What I am trying to achieve with this is to require a group based on the first regex variable. So if the user goes to http://localhost/a-repository-name he has to be in the group a-repository-name to be able to open the url. For some reason I can't get this code working and apache returns: Authorization of user **** to access /a-repository-name failed, reason: user is not part of the 'require'ed group(s). I guess it's not matching against the proper variable at Require group $1. Is this the right way to be done or I'm missing something?

    Read the article

  • How to recall search pattern when writing replace regex pattern in Vim?

    - by Tom Morris
    Here's the scenario: I've got a big file filled with all sorts of eclectic rubbish that I want to regex. I fiddle around and come up with a perfect search pattern by using the / command and seeing what it highlights. Now I want to use that pattern to replace with. So, I start typing :%s/ and I cannot recall what the pattern was. Is there some magical keyboard command that will pull in my last search pattern here? If I'm writing a particularly complex regex, I have even opened up a new MacVim window, typed the regex from the first window into a buffer there, then typed it back into the Vim window when writing the replace pattern. There has got to be a better way of doing so.

    Read the article

  • Need help modifying my Custom Replace code based on string passed to it

    - by fraXis
    Hello, I have a C# program that will open a text file, parse it for certain criteria using a RegEx statement, and then write a new text file with the changed criteria. For example: I have a text file with a bunch of machine codes in it such as: X0.109Y0Z1.G0H2E1 My C# program will take this and turn it into: X0.109Y0G54G0T3 G43Z1.H2M08 (Note: the T3 value is really the H value (H2 in this case) + 1). T = H + 1 It works great, because the line usually always starts with X so the RegEx statement always matches. My RegEx that works with my first example is as follows: //Regex pattern for: //- X(value)Y(value)Z(value)G(value)H(value)E(value) //- X(value)Y(value)Z(value)G(value)H(value)E(value)M(value) //- X(value)Y(value)Z(value)G(value)H(value)E(value)A(value) //- X(value)Y(value)Z(value)G(value)H(value)E(value)M(value)A(value) //value can be positive or negative, integer or floating point number with multiple decimal places or without any private Regex regReal = new Regex("^(X([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(Y([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(Z([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(G([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(H([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(E([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(M([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*)?(A([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*)?$"); This RegEx works great because sometimes the line of code could also have an M or A at the end such as: X0.109Y0Z1.G0H2E1A2 My problem is now I have run into some lines of code that have this: G90G0X1.5Y-0.036E1Z3.H1 and I need to turn it into this: G90G0X1.5Y-0.036G54T2 G43Z3.H1M08 Can someone please modify my RegEx and code to turn this: G90G0X1.5Y-0.036E1Z3.H1 into: G90G0X1.5Y-0.036G54T2 G43Z3.H1M08 But sometimes the values could be a little different such as: G(value)G(value)X(value)Y(value)E(value)Z(value)H(value) G(value)G(value)X(value)Y(value)E(value)Z(value)H(value)A(value) G(value)G(value)X(value)Y(value)E(value)Z(value)H(value)A(value)(M)value G(value)G(value)X(value)Y(value)E(value)Z(value)H(value)M(value)(A)value But also (this is where Z is moved to a different spot) G(value)G(value)X(value)Y(value)Z(value)E(value)H(value) G(value)G(value)X(value)Y(value)Z(value)E(value)H(value)A(value) G(value)G(value)X(value)Y(value)Z(value)E(value)H(value)A(value)(M)value G(value)G(value)X(value)Y(value)Z(value)E(value)H(value)M(value)(A)value Here is my code that needs to be changed (I did not include the open and saving of the text file since that is pretty standard stuff). //Regex pattern for: //- X(value)Y(value)Z(value)G(value)H(value)E(value) //- X(value)Y(value)Z(value)G(value)H(value)E(value)M(value) //- X(value)Y(value)Z(value)G(value)H(value)E(value)A(value) //- X(value)Y(value)Z(value)G(value)H(value)E(value)M(value)A(value) //value can be pozitive or negative, integer or floating point number with multiple decimal places or without any private Regex regReal = new Regex("^(X([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(Y([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(Z([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(G([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(H([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(E([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*){1}(M([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*)?(A([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]*)?$"); private string CheckAndModifyLine(string line) { if (regReal.IsMatch(line)) //Check the first Regex with line string { return CustomReplace(line); } else { return line; } } private string CustomReplace(string input) { string returnValue = String.Empty; int zPos = input.IndexOf("Z"); int gPos = input.IndexOf("G"); int hPos = input.IndexOf("H"); int ePos = input.IndexOf("E"); int aPos = input.IndexOf("A"); int hValue = Int32.Parse(input.Substring(hPos + 1, ePos - hPos - 1)) + 1; //get H number //remove A value returnValue = ((aPos == -1) ? input : input.Substring(0, aPos)); //replace Z value returnValue = Regex.Replace(returnValue, "Z[-]?\\d*\\.*\\d*", "G54"); //replace H value returnValue = Regex.Replace(returnValue, "H\\d*\\.*\\d*", "T" + hValue.ToString() + ((aPos == -1) ? String.Empty : input.Substring(aPos, input.Length - aPos))); //replace E, or E and M value returnValue = Regex.Replace(returnValue, "E\\d*\\.*\\d(M\\d*\\.*\\d)?", Environment.NewLine + "G43" + input.Substring(zPos, gPos - zPos) + input.Substring(hPos, ePos - hPos) + "M08"); return returnValue; } I tried to modify the above code to match the new line of text I am encountering (and split into two lines like my first example) but I am failing miserably. Thanks so much.

    Read the article

  • Using Regex, how can I remove certain characters from the inside of tags in a string of html?

    - by Iain Fraser
    Suppose I have a string of html that contains a bunch of control characters and I want to remove the control characters from inside tags only, leaving the characters outside the tags alone. For example Here the control character is the numeral "1". Input The quick 1<strong>orange</strong> lemming <sp11a1n 1class1='jumpe111r'11>jumps over</span> 1the idle 1frog Desired Output The quick 1<strong>orange</strong> lemming <span class='jumper'>jumps over</span> 1the idle 1frog So far I can match tags which contain the control character but I can't remove them in one regex. I guess I could perform another regex on my matches, but I'd really like to know if there's a better way. My regex Bear in mind this one only matches tags which contain the control character. <(([^>])*?`([^>])*?)*?> Thanks very much for your time and consideration. Iain Fraser

    Read the article

  • What is the C# equivalent of java.util.regex?

    - by peter.murray.rust
    I am converting Java code to C# and need to replace the use of Java's regex. A typical use is import java.util.regex.Matcher; import java.util.regex.Pattern; //... String myString = "B12"; Pattern pattern = Pattern.compile("[A-Za-z](\\d+)"); Matcher matcher = Pattern.matcher(myString); String serial = (matcher.matches()) ? matcher.group(1) : null; which should extract a capture group from a matched target string. I'd be grateful for simple examples. EDIT: I have now added the C# equivalent of the code as an answer. EDIT: Here is a tutorial on the use of the actual expressions. EDIT: Here is a useful comparison of C# and Java (and Perl.)

    Read the article

  • How to put .com at the end of email addressed by regex?

    - by terces907
    Example I received a email-list from my friends but the problem is some people typed an email in full form ([email protected]) and some people typed (xxx@xxx without .com). And i want to improve it into the same format. How can i improve it if i want to edit them on vi? In my emaillist.txt foo@gmail [email protected] bas@gmail [email protected] mike@abc john@email My try: i tried to use an easy regex like this to catch the pattern like xxx@xxx :%s/\(\w*@\w*\)/\0.com/g and :%s/\(\w*@\w*[^.com]\)/\0.com/g But the problem is this regex include [email protected] also And the result become like this after i enter the command above [email protected] [email protected] [email protected] [email protected] [email protected] [email protected] So, My expectation after substitution is should be like this: [email protected] [email protected] [email protected] [email protected] [email protected] [email protected] How to use regex in this situation?

    Read the article

  • How to match multiple lines with Regex in C#?

    - by Emanuel
    I have the following text: --------------030805090908050805080502 Content-Type: image/jpeg Content-Transfer-Encoding: base64 Content-ID: <[email protected]> /9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA /9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA QBQH/9k= --------------030805090908050805080502 Content-Type: image/jpeg Content-Transfer-Encoding: base64 Content-ID: <[email protected]> /9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA /9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA juu41lRHFLufPCAID//Z --------------030805090908050805080502-- And I need to get with Regex in C# 2 parts: between the first and the second occurence of the string "--------------030805090908050805080502" between the strings "--------------030805090908050805080502" and "--------------030805090908050805080502--" I tried this regex: --------------030805090908050805080502(\r.*)*--------------030805090908050805080502 but in C# regex.Matches(...) return only "--------------030805090908050805080502". Any idee? Thanks.

    Read the article

  • regex: trim all strings directly preceeded by digit except if string belongs to predefined set of st

    - by Geert-Jan
    I've got addresses I need to clean up for matching purposes. Part of the process is trimming unwanted suffices from housenumbers, e.g: mainstreet 4a --> mainstreet 4. However I don't want: 618 5th Ave SW --> 618 5 Ave SW in other words there are some strings (for now: st, nd, rd, th) which I don't want to strip. What would be the best method of doing this (regex or otherwise) ? a wokring regex without the exceptions would be: a = a.replaceAll("(^| )([0-9]+)[a-z]+($| )","$1$2$3"); //replace 1a --> 1 I thought about first searching and substiting the special cases with special characters while keeping the references in a map, then do the above regex, and then doing the reverse substitute using the reference map, but I'm looking for a simpler solution. Thanks

    Read the article

  • Can a regex return a match that's not a part of the original string?

    - by Vishnu
    I'm using an application that requires me to provide a regex for various files. It uses the matches from the regex to uniquely identify each file and then use a data store to retrieve metadata about these files. there is however a problem with the application, so it assumes that the data which is used to identify each file is only numeric data. Hence, it stores the results of matches in integers. I control the data store but not the names of the files. Since the application has a bug in it, I was hoping that I could use an encoding scheme to convert the non-numeric data to an integer. But for that I'd require the regex to return something that's not part of the original string as a match. Is this possible?

    Read the article

  • Yet another URL prefix regex question (to be used in C#).

    - by Hamish Grubijan
    Hi, I have seen many regular expressions for Url validation. In my case I want the Url to be simpler, so the regex should be tighter: Valid Url prefixes look like: http[s]://[www.]addressOrIp[.something]/PageName.aspx[?] This describe a prefix. I will be appending ?x=a&y=b&z=c later. I just want to check if the web page is live before accessing it, but even before that I want to make sure that it is properly configured. I want to treat bad url and host is down conditions differently, although when in doubt, I'd rather give a host is down message, because that is an ultimate test anyway. Hopefully that makes sense. I guess what I am trying to say - the regex does not need be too aggressive, I just want it to cover say 95% of the cases. This is C# - centric, so Perl regex extensions are not helpful to me; let's stick to the lowest common denominator. Thanks!

    Read the article

  • How do I specify a wildcard (for ANY character) in a c# regex statement?

    - by Scott
    Trying to use a wildcard in C# to grab information from a webpage source, but I cannot seem to figure out what to use as the wildcard character. Nothing I've tried works! The wildcard only needs to allow for numbers, but as the page is generated the same every time, I may as well allow for any characters. Regex statement in use: Regex guestbookWidgetIDregex = new Regex("GuestbookWidget(' INSERT WILDCARD HERE ', '(.*?)', 500);", RegexOptions.IgnoreCase); If anyone can figure out what I'm doing wrong, it would be greatly appreciated!

    Read the article

  • How do I get regex support in excel via a function, or custom function?

    - by blunders
    It appears that regex (as in regular expressions) is not supported in excel, except via VBA. Is this so, and is it is, are there any "open source" custom VBA functions that support regex. In this case I'm looking to extract complex pattern within a string, but any implementation of a custom VBA function that expose support of regex within the function itself would be of use. If you know of semi-related function such as the IS function, feel feel to comment, though I'm really looking for a full regular expression implementation that is exposed via functions. Might even be open to a pay to use add-in if the implementation is good. If you have questions, please comment.

    Read the article

  • Is there a way to create a string that matches a given C# regex?

    - by Chris Phillips
    My application has a feature that parses text using a regular expression to extract special values. I find myself also needing to create strings that follow the same format. Is there a way to use the already defined regular expression to create those strings? For example, assume my regex looks something like this: public static Regex MyRegex = new Regex( @"sometext_(?<group1>\d*)" ); I'd like to be able to use MyRegex to create a new string, something like: var created = MyRegex.ToString( new Dictionary<string, string>() {{ "group1", "data1" }}; Such that created would then have the value "sometextdata1".

    Read the article

  • Auto-converting numbers to comma-fied versions

    - by Jeff Atwood
    Given the following text /feeds/tag/remote-desktop 1320 17007 22449240 /feeds/tag/terminal-server 1328 15805 20989040 /foo/23211/test 1490 11341 16898090 Let's say we want to convert those numbers to their comma-fied forms, like so /feeds/tag/remote-desktop 1,320 17,007 22,449,240 /feeds/tag/terminal-server 1,328 15,805 20,989,040 /foo/23211/test 1,490 11,341 16,898,090 (don't worry about fixing the fixed-width ASCII spacing, that's a problem for another day) This is the best regex I could come up with; it's based on this JavaScript regex solution from Regex Ninja Steven Levithan: return Regex.Replace(s, @"\b(?<!\/)\d{4,}\b(?<!\/)", delegate(Match match) { string output = ""; string m = match.Value; int len = match.Length; for (int i = len - 1; i >= 0 ; i--) { output = m[i] + output; if ((len - i) % 3 == 0) output = "," + output; } if (output.StartsWith(",")) output = output.Substring(1, output.Length-1); return output; }); In a related question, there is a very clever number comma insertion regex proposed: text = Regex.Replace(text, @"(?<=\d)(?=(\d{3})+$)", ",") However this requires an end anchor $ which, as you can see, I don't have in the above text -- the numbers are "floating" in the rest of the text. I suspect there is a cleaner way to do this than my solution? After writing this, I just realized I could combine them, and put one Regex inside the other, like so: return Regex.Replace(s, @"\b(?<!\/)\d{4,}\b(?<!\/)", delegate(Match match) { return Regex.Replace(match.Value, @"(?<=\d)(?=(\d{3})+$)", ","); });

    Read the article

  • Why do I get extra, unexpected results with my ack regex?

    - by Gauthier
    I'm finally learning regexps and training with ack. I believe this uses Perl regexp. I want to match all lines where the first non-blank characters are if (<word> !, with any number of spaces in between the elements. This is what I came up with: ^[ \t]*if *\(\w+ *! It only nearly worked. ^[ \t]* is wrong, since it matches one or none [space or tab]. What I want is to match anything that may contain only space or tab (or nothing). For example these should not match: // if (asdf != 0) else if (asdf != 1) How can I modify my regexp for that? EDIT adding command line ack -i --group -a '^\s*if *\(\w+ *!' c:/work/proj/proj Note the single quotes, I'm not so sure about them anymore. My search base is a larger code base. It does include matching expressions (quite some), but even for example: 274: }else if (y != 0) , which I get as a result of the above command. EDIT adding the result of mobrule's test Mobrule, thanks for providing me a text to test on. I'll copy here what I get on my prompt: C:\Temp\regex>more ack.test # ack.test if (asdf != 0) # no spaces - ok if (asdf != 0) # single space - ok if (asdf != 0) # single tab - ok if (asdf != 0) # multiple space - ok if (asdf != 0) # multiple tab - ok if (asdf != 0) # spaces + tab ok if (asdf != 0) # tab + space ok if (asdf != 0) # space + tab + space ok // if (asdf != 0) # not ok } else if (asdf != 0) # not ok C:\Temp\regex>ack '^[ \t]*if *\(\w+ *!' ack.test C:\Temp\regex>"C:\Program\git\bin\perl.exe" C:\bat\ack.pl '[ \t]*if *\(\w+ *!' a ck.test if (asdf != 0) # no spaces - ok if (asdf != 0) # single space - ok if (asdf != 0) # single tab - ok if (asdf != 0) # multiple space - ok if (asdf != 0) # multiple tab - ok if (asdf != 0) # spaces + tab ok if (asdf != 0) # tab + space ok if (asdf != 0) # space + tab + space ok // if (asdf != 0) # not ok } else if (asdf != 0) # not ok The problem is in my call to my ack.bat! ack.bat contains: "C:\Program\git\bin\perl.exe" C:\bat\ack.pl %* Although I call with a caret, it gets away at the call of the bat file! Escaping the caret with ^^ does not work. Quoting the regex with " " instead of ' ' works. My problem was a DOS/win problem, sorry for bothering you all for that.

    Read the article

  • How to use Regex Replace to conditionally remove blocks of text?

    - by lauren meyers
    I would like to conditionally remove a block of text between specifed start and stop delimiters. The code below does not work, but hopefully it suggests enough of what I am trying to accomplish. If dr("ReferralPoints") > 0 Then Dim objRegex As Regex = New Regex("[HASNOVALUE:REFERRALPOINTS](.*)[/HASNOVALUE:REFERRALPOINTS]", RegexOptions.IgnoreCase + RegexOptions.Singleline) Dim result As String = objRegex.Replace(strBody, "") End If

    Read the article

  • regex to break a string into "key" / "value" pairs when # of pairs is variable?

    - by user141146
    Hi, I'm using Ruby 1.9 and I'm wondering if there's a simple regex way to do this. I have many strings that look like some variation of this: str = "Allocation: Random, Control: Active Control, Endpoint Classification: Safety Study, Intervention Model: Parallel Assignment, Masking: Double Blind (Subject, Caregiver, Investigator, Outcomes Assessor), Primary Purpose: Treatment" The idea is that I'd like to break this string into its functional components Allocation: Random Control: Active Control Endpoint Classification: Safety Study Intervention Model: Parallel Assignment Masking: Double Blind (Subject, Caregiver, Investigator, Outcomes, Assessor) Primary Purpose: Treatment The "syntax" of the string is that there is a "key" which consists of one or more "words or other characters" (e.g. Intervention Model) followed by a colon (:). Each key has a corresponding "value" (e.g., Parallel Assignment) that immediately follows the colon (:)…The "value" consists of words, commas (whatever), but the end of the "value" is signaled by a comma. The # of key/value pairs is variable. I'm also assuming that colons (:) aren't allowed to be part of the "value" and that commas (,) aren't allowed to be part of the "key". One would think that there is a "regexy" way to break this into its component pieces, but my attempt at making an appropriate matching regex only picks up the first key/value pair and I'm not sure how to capture the others. Any thoughts on how to capture the other matches? regex = /(([^,]+?): ([^:]+?,))+?/ => /(([^,]+?): ([^:]+?,))+?/ irb(main):139:0> str = "Allocation: Random, Control: Active Control, Endpoint Classification: Safety Study, Intervention Model: Parallel Assignment, Masking: Double Blind (Subject, Caregiver, Investigator, Outcomes Assessor), Primary Purpose: Treatment" => "Allocation: Random, Control: Active Control, Endpoint Classification: Safety Study, Intervention Model: Parallel Assignment, Masking: Double Blind (Subject, Caregiver, Investigator, Outcomes Assessor), Primary Purpose: Treatment" irb(main):140:0> str.match regex => #<MatchData "Allocation: Random," 1:"Allocation: Random," 2:"Allocation" 3:" Random,"> irb(main):141:0> $1 => "Allocation: Random," irb(main):142:0> $2 => "Allocation" irb(main):143:0> $3 => " Random," irb(main):144:0> $4 => nil

    Read the article

  • How to construct a string based on regex and related parameters in PHP?

    - by user198729
    (?P<id>\d*)(/(?P<title>.*))? Most of the time,we use regex to match something,but how to generate the matching string if we have id and title already? Example,if id=4 and title='hello world',the result should be: 4/hello world But if we only have id=4,it should be: 4 Because as the regex indicates,title is optional. Two answers both misunderstood... There is no preg_match yet

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 37 38 39 40 41 42 43 44 45 46 47 48  | Next Page >