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  • .NET: Is it possible to get HttpWebRequest to automatically decompress gzip'd responses?

    - by Cheeso
    In this answer, I described how I resorted to wrappnig a GZipStream around the response stream in a HttpWebResponse, in order to decompress it. The relevant code looks like this: HttpWebRequest hwr = (HttpWebRequest) WebRequest.Create(url); hwr.CookieContainer = PersistentCookies.GetCookieContainerForUrl(url); hwr.Accept = "text/xml, */*"; hwr.Headers.Add(HttpRequestHeader.AcceptEncoding, "gzip, deflate"); hwr.Headers.Add(HttpRequestHeader.AcceptLanguage, "en-us"); hwr.UserAgent = "My special app"; hwr.KeepAlive = true; var resp = (HttpWebResponse) hwr.GetResponse(); using(Stream s = resp.GetResponseStream()) { Stream s2 = s; if (resp.ContentEncoding.ToLower().Contains("gzip")) s2 = new GZipStream(s2, CompressionMode.Decompress); else if (resp.ContentEncoding.ToLower().Contains("deflate")) s2 = new DeflateStream(s2, CompressionMode.Decompress); ... use s2 ... } Is there a way to get HttpWebResponse to provide a de-compressing stream, automatically? In other words, a way for me to eliminate the following from the above code: Stream s2 = s; if (resp.ContentEncoding.ToLower().Contains("gzip")) s2 = new GZipStream(s2, CompressionMode.Decompress); else if (resp.ContentEncoding.ToLower().Contains("deflate")) s2 = new DeflateStream(s2, CompressionMode.Decompress); Thanks.

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  • Saving image to database as varbinary, arraylength (part 2)

    - by Thomas Schoof
    This is a followup to my previous question, which got solved (thank you for that) but now I am stuck at another error. I'm trying to save an image in my database (called 'Afbeelding'), for that I made a table which excists of: id: int souce: varbinary(max) I then created a wcf service to save an 'Afbeelding' to the database. private static DataClassesDataContext dc = new DataClassesDataContext(); [OperationContract] public void setAfbeelding(Afbeelding a) { //Afbeelding a = new Afbeelding(); //a.id = 1; //a.source = new Binary(bytes); dc.Afbeeldings.InsertOnSubmit(a); dc.SubmitChanges(); } I then put a reference to the service in my project and when I press the button I try to save it to the datbase. private void btnUpload_Click(object sender, RoutedEventArgs e) { Afbeelding a = new Afbeelding(); OpenFileDialog openFileDialog = new OpenFileDialog(); openFileDialog.Filter = "JPEG files|*.jpg"; if (openFileDialog.ShowDialog() == true) { //string imagePath = openFileDialog.File.Name; //FileStream fileStream = new FileStream(imagePath, FileMode.Open, FileAccess.Read); //byte[] buffer = new byte[fileStream.Length]; //fileStream.Read(buffer, 0, (int)fileStream.Length); //fileStream.Close(); Stream stream = (Stream)openFileDialog.File.OpenRead(); Byte[] bytes = new Byte[stream.Length]; stream.Read(bytes, 0, (int)stream.Length); string fileName = openFileDialog.File.Name; a.id = 1; a.source = new Binary { Bytes = bytes }; } EditAfbeeldingServiceClient client = new EditAfbeeldingServiceClient(); client.setAfbeeldingCompleted +=new EventHandler<System.ComponentModel.AsyncCompletedEventArgs>(client_setAfbeeldingCompleted); client.setAfbeeldingAsync(a); } void client_setAfbeeldingCompleted(object sender, System.ComponentModel.AsyncCompletedEventArgs e) { if (e.Error != null) txtEmail.Text = e.Error.ToString(); else MessageBox.Show("WIN"); } However, when I do this, I get the following error: System.ServiceModel.FaultException: The formatter threw an exception while trying to deserialize the message: There was an error while trying to deserialize parameter :a. The InnerException message was 'There was an error deserializing the object of type OndernemersAward.Web.Afbeelding. The maximum array length quota (16384) has been exceeded while reading XML data. This quota may be increased by changing the MaxArrayLength property on the XmlDictionaryReaderQuotas object used when creating the XML reader.'. Please see InnerException for more details. at System.ServiceModel.Channels.ServiceChannel.HandleReply(ProxyOperationRuntime operation, ProxyRpc& rpc) at System.ServiceModel.Channels.ServiceChannel.EndCall(String action, Object[] outs, IAsyncResult result) at System.ServiceModel.ClientBase`1.ChannelBase`1.EndInvoke(String methodName, Object[] args, IAsyncResult result) atOndernemersAward.EditAfbeeldingServiceReference.EditAfbeeldingServiceClient.EditAfbeeldingServiceClientChannel.EndsetAfbeelding(IAsyncResult result) at OndernemersAward.EditAfbeeldingServiceReference.EditAfbeeldingServiceClient.OndernemersAward.EditAfbeeldingServiceReference.EditAfbeeldingService.EndsetAfbeelding(IAsyncResult result) at OndernemersAward.EditAfbeeldingServiceReference.EditAfbeeldingServiceClient.OnEndsetAfbeelding(IAsyncResult result) at System.ServiceModel.ClientBase`1.OnAsyncCallCompleted(IAsyncResult result) I'm not sure what's causing this but I think it has something to do with the way I write the image to the database? (The array length is too big big, I don't really know how to change it) Thank you for your help, Thomas

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  • extend web server to serve static files

    - by Turtle
    Hello, I want to extend a web server which is only able to handle RPC handling now. The web server is written in C#. It provides a abstract handler function like following: public string owsHandler(string request, string path, string param, OSHttpRequest httpRequest, OSHttpResponse httpResponse) And I wrote following code to handle image files: Bitmap queryImg = new Bitmap(path); System.IO.MemoryStream stream = new System.IO.MemoryStream(); queryImg.Save(stream, System.Drawing.Imaging.ImageFormat.Bmp); queryImg.Dispose(); byte[] byteImage = stream.ToArray(); stream.Dispose(); return Convert.ToBase64String(byteImage); And I test it in the browser, the image is returned but the image dimension info is missed. Shall I add something more to the code? Or is any general way to server static files? I do not want to serve it in a ASP.net server. Thanks

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  • Clojure: Avoiding stack overflow in Sieve of Erathosthene?

    - by nixx
    Here's my implementation of Sieve of Erathosthene in Clojure (based on SICP lesson on streams): (defn nats-from [n] (iterate inc n)) (defn divide? [p q] (zero? (rem q p))) (defn sieve [stream] (lazy-seq (cons (first stream) (sieve (remove #(divide? (first stream) %) (rest stream)))))) (def primes (sieve (nats-from 2))) Now, it's all OK when i take first 100 primes: (take 100 primes) But, if i try to take first 1000 primes, program breaks because of stack overflow. I'm wondering if is it possible to change somehow function sieve to become tail-recursive and, still, to preserve "streamnes" of algorithm? Any help???

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  • How do I record streams in chunks on Flash Media Server.

    - by Vasil
    I want to record a stream which is published with Flash Live Encoder to FMS 3.5, but split the recording in files with predefined length. For example if a stream 'webcam' is published I want to record it in chunks of 10 minutes: 'webcam1.flv', 'webcam2.flv' ... From what I can tell there's no facility to work with timers. The only solution I could think of was using stream.record() with a time limit parameter but that seems like a hack because it triggers NetStream.Record.DiskQuotaExceeded on the stream when the recordin should stop and start recording another chunk. Has anyone done something similar?

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  • problem downloading movie to iphone for storage and playback

    - by padatronic
    I am basically making a video library where you download videos and I then write them to the applications documents folder. This all works fine and if i stream the video from online it plays fine. Or indeed I can stream it from the resource folder fine. However, after downloading it and saving to the documents folder then attempting to stream I get the error 'movie format not supported' any ideas? thanks very much

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  • Download dynamic file with GWT

    - by Maksim
    I have a GWT page where user enter data (start date, end date, etc.), then this data goes to the server via RPC call. On the server I want to generate Excel report with POI and let user save that file on their local machine. This is my test code to stream file back to the client but for some reason I think it does not know how to stream file to the client when I'm using RPC: public class ReportsServiceImpl extends RemoteServiceServlet implements ReportsService { public String myMethod(String s) { File f = new File("/excelTestFile.xls"); String filename = f.getName(); int length = 0; try { HttpServletResponse resp = getThreadLocalResponse(); ServletOutputStream op = resp.getOutputStream(); ServletContext context = getServletConfig().getServletContext(); resp.setContentType("application/octet-stream"); resp.setContentLength((int) f.length()); resp.setHeader("Content-Disposition", "attachment; filename*=\"utf-8''" + filename + ""); byte[] bbuf = new byte[1024]; DataInputStream in = new DataInputStream(new FileInputStream(f)); while ((in != null) && ((length = in.read(bbuf)) != -1)) { op.write(bbuf, 0, length); } in.close(); op.flush(); op.close(); } catch (Exception ex) { ex.printStackTrace(); } return "Server says: " + filename; } } I've red somewhere on internet that you can't do file stream with RPC and I have to use Servlet for that. Is there any example of how to use Servlet and how to call that servlet from ReportsServiceImpl. Do I really need to make a servlet or it is possible to stream it back with my RPC?

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  • real time stock quotes, StreamReader performance optimization

    - by sean717
    I am working on a program that extracts real time quote for 900+ stocks from a website. I use HttpWebRequest to send HTTP request to the site and store the response to a stream and open a stream using the following code: HttpWebResponse response = (HttpWebResponse)request.GetResponse(); Stream stream = response.GetResponseStream (); StreamReader reader = new StreamReader( stream ) the size of the received HTML is large (5000+ lines), so it takes a long time to parse it and extract the price. For 900 files, It takes about 6 mins for parsing and extracting. Which my boss isn't happy with, he told me he'd want the whole process to be done in TWO mins. I've identified the part of the program that takes most of time to finish is parsing and extracting. I've tried to optimize the code to make it faster, the following is what I have now after some optimization: // skip lines at the top for(int i=0;i<1500;++i) reader.ReadLine(); // read the line that contains the price string theLine = reader.ReadLine(); // ... extract the price from the line now it takes about 4 mins to process all the files, there is still a significant gap to what my boss's expecting. So I am wondering, is there other way that I can further speed up the parsing and extracting and have everything done within 2 mins?

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  • Getresponse not working after authentication

    - by Hazler
    For starters, here's my code: // Create a request using a URL that can receive a post. WebRequest request = WebRequest.Create("http://mydomain.com/cms/csharptest.php"); request.Credentials = new NetworkCredential("myUser", "myPass"); // Set the Method property of the request to POST. request.Method = "POST"; // Create POST data and convert it to a byte array. string postData = "name=PersonName&age=25"; byte[] byteArray = Encoding.UTF8.GetBytes(postData); // Set the ContentType property of the WebRequest. request.ContentType = "application/x-www-form-urlencoded"; // Set the ContentLength property of the WebRequest. request.ContentLength = byteArray.Length; // Get the request stream. Stream dataStream = request.GetRequestStream(); // Write the data to the request stream. dataStream.Write(byteArray, 0, byteArray.Length); // Close the Stream object. dataStream.Close(); // Get the response. HttpWebResponse response = (HttpWebResponse)request.GetResponse(); // Display the status. Console.WriteLine((response).StatusDescription); // Get the stream containing content returned by the server. dataStream = response.GetResponseStream(); // Open the stream using a StreamReader for easy access. StreamReader reader = new StreamReader(dataStream); // Read the content. string responseFromServer = reader.ReadToEnd(); // Display the content. Console.WriteLine(responseFromServer); // Clean up the streams. reader.Close(); dataStream.Close(); response.Close(); The directory cms/ requires authentication, but if I try running this same code somewhere, where authentication isn't needed, it works fine. The error (System.Net.WebException: The remote server returned an error: (403) Forbidden) occurs at HttpWebResponse response = (HttpWebResponse)request.GetResponse(); I have managed in reading data after authenticating, but not if I also send POST data. What's wrong with this?

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  • Why is a .net generic dictionary so big

    - by thefroatgt
    I am serializing a generic dictionary in VB.net and I am very surprised that it is about 1.3kb with a single item. Am I doing something wrong, or is there something else I should be doing? I have a large number of dictionaries and it is killing me to send them all across the wire. The code I use for serialization is Dim dictionary As New Dictionary(Of Integer, Integer) Dim stream As New MemoryStream Dim bformatter As New BinaryFormatter() dictionary.Add(1, 1) bformatter.Serialize(stream, dictionary) Dim len As Long = stream.Length

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  • htaccess for swf file

    - by Charles Wayne
    Does htaccess works with swf file that accepts variables? I have this swf url... http://subdom.domain.tld/subfolder/live.swf?stream=rtmp://stream.domain.com/application&provider=rtmp&file=streamname&autostart=true I want it to be rewrite as http://subdom.domain.tld/subfolder/assignedname/ So far this is what I written on .htaccess file RewriteEngine On RewriteRule ^kwt/?$ live.swf?stream=rtmp://stream.domain.com/application&provider=rtmp&file=streamname&autostart=true [NC,L] It does seem to rewrite to the swf file because the swf is showing but for some reason the variable is not recognized. It does not auto play even the auto play variable is set to true in the RewriteRule. Is there something wrong with my code or it can't be done in swf file?

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  • how to cout a vector of structs (that's a class member, using extraction operator)

    - by Julz
    hi, i'm trying to simply cout the elements of a vector using an overloaded extraction operator. the vector contians Point, which is just a struct containing two doubles. the vector is a private member of a class called Polygon, so heres my Point.h #ifndef POINT_H #define POINT_H #include <iostream> #include <string> #include <sstream> struct Point { double x; double y; //constructor Point() { x = 0.0; y = 0.0; } friend std::istream& operator >>(std::istream& stream, Point &p) { stream >> std::ws; stream >> p.x; stream >> p.y; return stream; } friend std::ostream& operator << (std::ostream& stream, Point &p) { stream << p.x << p.y; return stream; } }; #endif my Polygon.h #ifndef POLYGON_H #define POLYGON_H #include "Segment.h" #include <vector> class Polygon { //insertion operator needs work friend std::istream & operator >> (std::istream &inStream, Polygon &vertStr); // extraction operator friend std::ostream & operator << (std::ostream &outStream, const Polygon &vertStr); public: //Constructor Polygon(const std::vector<Point> &theVerts); //Default Constructor Polygon(); //Copy Constructor Polygon(const Polygon &polyCopy); //Accessor/Modifier methods inline std::vector<Point> getVector() const {return vertices;} //Return number of Vector elements inline int sizeOfVect() const {return vertices.size();} //add Point elements to vector inline void setVertices(const Point &theVerts){vertices.push_back (theVerts);} private: std::vector<Point> vertices; }; and Polygon.cc using namespace std; #include "Polygon.h" // Constructor Polygon::Polygon(const vector<Point> &theVerts) { vertices = theVerts; } //Default Constructor Polygon::Polygon(){} istream & operator >> (istream &inStream, Polygon::Polygon &vertStr) { inStream >> ws; inStream >> vertStr; return inStream; } // extraction operator ostream & operator << (ostream &outStream, const Polygon::Polygon &vertStr) { outStream << vertStr.vertices << endl; return outStream; } i figure my Point insertion/extraction is right, i can insert and cout using it and i figure i should be able to just...... cout << myPoly[i] << endl; in my driver? (in a loop) or even... cout << myPoly[0] << endl; without a loop? i've tried all sorts of myPoly.at[i]; myPoly.vertices[i]; etc etc also tried all veriations in my extraction function outStream << vertStr.vertices[i] << endl; within loops, etc etc. when i just create a... vector<Point> myVect; in my driver i can just... cout << myVect.at(i) << endl; no problems. tried to find an answer for days, really lost and not through lack of trying!!! thanks in advance for any help. please excuse my lack of comments and formatting also there's bits and pieces missing but i really just need an answer to this problem thanks again

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  • how do i insert html file that have hebrew text and read it back in sql server 2008 using the filest

    - by gadym
    hello all, i am new to the filestream option in sql server 2008, but i have already understand how to open this option and how to create a table that allow you to save files. let say my table contains: id,name, filecontent i tried to insert an html file (that has hebrew chars/text in it) to this table. i'm writing in asp.net (c#), using visual studio 2008. but when i tried to read back the content , hebrew char becomes '?'. the actions i took were: 1. i read the file like this: // open the stream reader System.IO.StreamReader aFile = new StreamReader(FileName, System.Text.UTF8Encoding.UTF8); // reads the file to the end stream = aFile.ReadToEnd(); // closes the file aFile.Close(); return stream; // returns the stream i inserted the 'stream' to the filecontent column as binary data. i tried to do a 'select' to this column and the data did return (after i coverted it back to string) but hebrew chars become '?' how do i solve this problem ? what I should pay attention to ? thanks, gadym

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  • Pass Types as arguments to a function in Haskell?

    - by Charles Peng
    The following two functions are extremely similar. They read from a [String] n elements, either [Int] or [Float]. How can I factor the common code out? I don't know of any mechanism in Haskell that supports passing types as arguments. readInts n stream = foldl next ([], stream) [1..n] where next (lst, x:xs) _ = (lst ++ [v], xs) where v = read x :: Int readFloats n stream = foldl next ([], stream) [1..n] where next (lst, x:xs) _ = (lst ++ [v], xs) where v = read x :: Float I am at a beginner level of Haskell, so any comments on my code are welcome.

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  • Streaming multiple TObjects to a TMemoryStream

    - by Altar
    I need to store multiple objects (most of them are TObject/non persistent) to a TMemoryStream, save the stream to disk and load it back. The objects need to be streamed one after each other. Some kind of universal container. I started to make several functions that store stuff to stream - for example function StreamReadString(CONST MemStream: TMemoryStream): string; StreamWriteString(CONST MemStream: TMemoryStream; s: string); However, it seems that I need to rewrite a lot of code. One of the many examples is TStringList.LoadFromStream that will not work so it needs to be rewritten. This is because TStringList needs to be the last object in the stream (it reads from current position to the end of the stream). Anybody knows a library that provide basic functionality like this? I am using Delphi 7 so RTTI won't help too much.

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  • How to get file path using FileUpload to be read by FileStream?

    - by john ryan
    I have a Method that open excel file and read it through exceldatareaderClass that i have downloaded in codeplex by using filestream. Currently I just declared the exact directory where the filestream open an excel file.And it works fine. Stream stream = new FileStream("C:\\" + FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Now i need to read the excel file wherever location the user place it like on windows forms fileupload.FileStream needs the exact location where the file is located. How to do this.? Example: Sample.xls is located on My Documents the file path should be like : C:\Documents and Settings\user\My Documents\ string openpath ="" ;//filepath Stream stream = new FileStream(openpath+ FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Thanks in Regards

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  • How to use files/streams as source/sink in PulseAudio

    - by Nilesh
    I'm a PulseAudio noob, and I'm not sure if I'm even using the correct terminology. I've seen that PulseAudio can perform echo cancellation, but it needs a source and a sink to filter from, and a new source and sink. I can provide my mic and my audio-out as the source and sink, right? Now, here's my situation: I have two video streams, say, rtmp streams, or consider two flv files, say at any given moment, stream X is the input stream that's coming from another computer's webcam+mic and stream Y is the output stream that I'm sending, (and it's coming from my computer's webcam+mic). Question: Back to the first paragraph - here's the thing, I don't want to use my mic and my audio-out, instead, I want to use these two "input" and "output" streams as my source and sink so to speak (of course, I'll use xuggler maybe, to extract just the audio from X and Y). It may be a strange question, and I have my reasons for doing this strange this - I need to experiment and verify the results to see.

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  • Streaming audio not working in Android

    - by user320293
    Hi, I'm sure that this question has been asked before but I've been unable to find a solid answer. I'm trying to load a streaming audio from a server. Its a audio/aac file http://3363.live.streamtheworld.com:80/CHUMFMAACCMP3 The code that I'm using is private void playAudio(String str) { try { final String path = str; if (path == null || path.length() == 0) { Toast.makeText(RadioPlayer.this, "File URL/path is empty", Toast.LENGTH_LONG).show(); } else { // If the path has not changed, just start the media player MediaPlayer mp = new MediaPlayer(); mp.setAudioStreamType(AudioManager.STREAM_MUSIC); try{ mp.setDataSource(getDataSource(path)); mp.prepareAsync(); mp.start(); }catch(IOException e){ Log.i("ONCREATE IOEXCEPTION", e.getMessage()); }catch(Exception e){ Log.i("ONCREATE EXCEPTION", e.getMessage()); } } } catch (Exception e) { Log.e("RPLAYER EXCEPTION", "error: " + e.getMessage(), e); } } private String getDataSource(String path) throws IOException { if (!URLUtil.isNetworkUrl(path)) { return path; } else { URL url = new URL(path); URLConnection cn = url.openConnection(); cn.connect(); InputStream stream = cn.getInputStream(); if (stream == null) throw new RuntimeException("stream is null"); File temp = File.createTempFile("mediaplayertmp", ".dat"); temp.deleteOnExit(); String tempPath = temp.getAbsolutePath(); FileOutputStream out = new FileOutputStream(temp); byte buf[] = new byte[128]; do { int numread = stream.read(buf); if (numread <= 0) break; out.write(buf, 0, numread); } while (true); try { stream.close(); } catch (IOException ex) { Log.e("RPLAYER IOEXCEPTION", "error: " + ex.getMessage(), ex); } return tempPath; } } Is this the correct implementation? I'm not sure where I'm going wrong. Can someone please please help me on this.

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  • How to translate such AS3 class into C#?

    - by Ole Jak
    So I try to create opensource C# project for slicing FLVs I began with translating of existing project called flvslicer Can any one please help me with translating one of their classes package org.bytearray.video.events { import flash.events.Event; import flash.utils.ByteArray; public final class MergedEvent extends Event { public var time:Number; public var stream:ByteArray; public static const COMPLETE:String = "mergeComplete"; public function MergedEvent(type:String, stream:ByteArray, duration:Number) { super(type, false, false); // base this.stream = stream; this.time = duration; } } }

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  • PHP Readfile() number of bytes when user aborted

    - by jtnire
    Hi Everyone, I'm using a PHP script to stream a live video (i.e. a file which never ends) from a remote source. The output is viewed in VLC, not a web browser. I need to keep a count of the number of bytes transferred. Here is my code: <?php ignore_user_abort(true); $stream = $_GET['stream']; if($stream == "vid1") { $count = readfile('http://127.0.0.1:8080/'); logThis($count); } function logThis($c) { $myFile = "bytecount.txt"; $handle = fopen($myFile,'a'); fwrite($handle,"Count: " . $c . "\n"); fclose($handle); } ?> However it appears that when the user presses the stop button, logThis() is never called, even though I've put in ignore_user_abort(true); Any ideas on what I'm doing wrong? Thanks

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  • Technical non-terminating condition in a loop

    - by Snarfblam
    Most of us know that a loop should not have a non-terminating condition. For example, this C# loop has a non-terminating condition: any even value of i. This is an obvious logic error. void CountByTwosStartingAt(byte i) { // If i is even, it never exceeds 254 for(; i < 255; i += 2) { Console.WriteLine(i); } } Sometimes there are edge cases that are extremely unlikeley, but technically constitute non-exiting conditions (stack overflows and out-of-memory errors aside). Suppose you have a function that counts the number of sequential zeros in a stream: int CountZeros(Stream s) { int total = 0; while(s.ReadByte() == 0) total++; return total; } Now, suppose you feed it this thing: class InfiniteEmptyStream:Stream { // ... Other members ... public override int Read(byte[] buffer, int offset, int count) { Array.Clear(buffer, offset, count); // Output zeros return count; // Never returns -1 (end of stream) } } Or more realistically, maybe a stream that returns data from external hardware, which in certain cases might return lots of zeros (such as a game controller sitting on your desk). Either way we have an infinite loop. This particular non-terminating condition stands out, but sometimes they don't. A completely real-world example as in an app I'm writing. An endless stream of zeros will be deserialized into infinite "empty" objects (until the collection class or GC throws an exception because I've exceeded two billion items). But this would be a completely unexpected circumstance (considering my data source). How important is it to have absolutely no non-terminating conditions? How much does this affect "robustness?" Does it matter if they are only "theoretically" non-terminating (is it okay if an exception represents an implicit terminating condition)? Does it matter whether the app is commercial? If it is publicly distributed? Does it matter if the problematic code is in no way accessible through a public interface/API? Edit: One of the primary concerns I have is unforseen logic errors that can create the non-terminating condition. If, as a rule, you ensure there are no non-terminating conditions, you can identify or handle these logic errors more gracefully, but is it worth it? And when? This is a concern orthogonal to trust.

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  • implementing keepalives with Java

    - by Bilal
    Hi All, I am biulding a client-server application where I have to implement a keepalive mechanism in order to detect that the client has crashed or not. I have separate threads on both client and server side. the client thread sends a "ping" then sleeps for 3 seconds, while the server reads the BufferedInput Stream and checks whether ping is received, if so it makes the ping counter eqauls zero, else it increments the counter by +1, the server thread then sleeps for 3 seconds, if the ping counter reaches 3, it daclares the client as dead. The problem is that when the server reads the input stream, its a blocking call, and it blocks untill the next ping is received, irrespective of how delayed it is, so the server never detects a missed ping. any suggestions, so that I can read the current value of the stream and it doesn't block if there is nothing on the incoming stream. Thanks,

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  • Problem When Compressing File using vb.net

    - by Amr Elnashar
    I have File Like "Sample.bak" and when I compress it to be "Sample.zip" I lose the file extension inside the zip file I meann when I open the compressed file I find "Sample" without any extension. I use this code : Dim name As String = Path.GetFileName(filePath).Replace(".Bak", "") Dim source() As Byte = System.IO.File.ReadAllBytes(filePath) Dim compressed() As Byte = ConvertToByteArray(source) System.IO.File.WriteAllBytes(destination & name & ".Bak" & ".zip", compressed) Or using this code : Public Sub cmdCompressFile(ByVal FileName As String) 'Stream object that reads file contents Dim streamObj As Stream = New StreamReader(FileName).BaseStream 'Allocate space in buffer according to the length of the file read Dim buffer(streamObj.Length) As Byte 'Fill buffer streamObj.Read(buffer, 0, buffer.Length) streamObj.Close() 'File Stream object used to change the extension of a file Dim compFile As System.IO.FileStream = File.Create(Path.ChangeExtension(FileName, "zip")) 'GZip object that compress the file Dim zipStreamObj As New GZipStream(compFile, CompressionMode.Compress) 'Write to the Stream object from the buffer zipStreamObj.Write(buffer, 0, buffer.Length) zipStreamObj.Close() End Sub please I need to compress the file without loosing file extension inside compressed file. thanks,

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  • Change HttpContext.Request.InputStream

    - by user320478
    I am getting lot of errors for HttpRequestValidationException in my event log. Is it possible to HTMLEncode all the inputs from override of ProcessRequest on web page. I have tried this but it gives context.Request.InputStream.CanWrite == false always. Is there any way to HTMLEncode all the feilds when request is made? public override void ProcessRequest(HttpContext context) { if (context.Request.InputStream.CanRead) { IEnumerator en = HttpContext.Current.Request.Form.GetEnumerator(); while (en.MoveNext()) { //Response.Write(Server.HtmlEncode(en.Current + " = " + //HttpContext.Current.Request.Form[(string)en.Current])); } long nLen = context.Request.InputStream.Length; if (nLen > 0) { string strInputStream = string.Empty; context.Request.InputStream.Position = 0; byte[] bytes = new byte[nLen]; context.Request.InputStream.Read(bytes, 0, Convert.ToInt32(nLen)); strInputStream = Encoding.Default.GetString(bytes); if (!string.IsNullOrEmpty(strInputStream)) { List<string> stream = strInputStream.Split('&').ToList<string>(); Dictionary<int, string> data = new Dictionary<int, string>(); if (stream != null && stream.Count > 0) { int index = 0; foreach (string str in stream) { if (str.Length > 3 && str.Substring(0, 3) == "txt") { string textBoxData = str; string temp = Server.HtmlEncode(str); //stream[index] = temp; data.Add(index, temp); index++; } } if (data.Count > 0) { List<string> streamNew = stream; foreach (KeyValuePair<int, string> kvp in data) { streamNew[kvp.Key] = kvp.Value; } string newStream = string.Join("", streamNew.ToArray()); byte[] bytesNew = Encoding.Default.GetBytes(newStream); if (context.Request.InputStream.CanWrite) { context.Request.InputStream.Flush(); context.Request.InputStream.Position = 0; context.Request.InputStream.Write(bytesNew, 0, bytesNew.Length); //Request.InputStream.Close(); //Request.InputStream.Dispose(); } } } } } } base.ProcessRequest(context); }

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  • EMbed a video inside content

    - by Aruna
    Hi, I am working on Joomla currently for the past one month. I am trying to embed a video stream in my article page like inside the content i am trying to have video stream like youtube video. I have uploaded a video in my media manager. And i dono how to stream that video in my page. Please help me in doing so..

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