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  • A regular expression question

    - by Hellnar
    Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

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  • Regular expression for a list of numbers without other characters

    - by JamesW
    I need a regular expression for a list of numbers in a text box with carriage returns and line feeds, but no other characters. e.g. 1234 5678 5874 3478 I have this: Regex(@"\d\r\n${0,}?"); ... but it is accepting commas when I paste them into my text box: e.g. 1234, 5678 5874, 3478 Can someone please tell me what I'm doing wrong? Thanks

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  • How to match parameter names in an expression?

    - by burak ozdogan
    Hi, I have a set of expressions representing some formula with some parameters inside. Like: [parameter1] * [parameter2] * [multiplier] And many others like this. I want to use a regular expression so that I can get a list of strings (List<string>) which will have the following inside: [paramter1] [paramter2] [multiplier] I am not using regular expressions so often; if you have already used something like this I would appreciate if you can share. Thanks!

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  • Regular Expression Fails

    - by Meander365
    Anyone help? When I run this I get " invalid quantifier ?<=href= " var aHrefMatch = new RegExp("(?<=href\=")[^]+?(?=")"); var matchedLink = mystring.match(aHrefMatch); But I know the regular expression is valid. Any ideas?

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  • Regular Expression Routes in Rails

    - by Kevin Sylvestre
    I am looking to create a rails route that is capable of accepting requests using a regular expression. Specifically, I need optional paths. As an example: "(/first)?(/second)?" Would match: /first /second /first/second But not: /second/first Is this possible? Thanks.

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  • Regular expression - starting and ending with a letter, accepting only letters, numbers and _

    - by jreid9001
    I'm trying to write a regular expression which specifies that text should start with a letter, every character should be a letter, number or underscore, there should not be 2 underscores in a row and it should end with a letter or number. At the moment, the only thing I have is ^[a-zA-Z]\w[a-zA-Z1-9_] but this doesn't seem to work properly since it only ever matches 3 characters, and allows repeated underscores. I also don't know how to specify requirements for the last character.

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  • regular expression breaking on new line

    - by shyam
    I'm trying to use a regular expression as below: preg_match_all('|<table.*</table>|',$html,$matches, PREG_SET_ORDER); But this is not working, and I think the problem is the new line inside the string $html. Could someone tell me a work around?

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  • Regular Expression not disappearing

    - by user2439019
    I have 3 phone fields and any one is required. SO i had a custom validation class to make any one of them is required. And i am calling those class as follows [RegularExpression(@"^\(?([0-9]{3})\)?. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [AtLeastOneRequired("PhoneHome", "PhoneMobile", "PhoneOffice", ErrorMessage = "Please provide either of PhoneHome or PhoneMobile or phoneOffice. ")] public string PhoneHome { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneOffice", ResourceType = typeof(ResContactItems))] public string PhoneOffice { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneMobile", ResourceType = typeof(ResContactItems))] public string PhoneMobile { get; set; } The problem is with only "PhoneHome " field , if i enter incorrect format, it will display error message based ont he regular expression given .But the regular expression message is not disappearing wwhen we enter the correct format too.It will disappear only in f the field is empty.Other two fields are showing properly. Is this due to the custom class i am calling.? Please help me to sort out this issue Thanks, Vidya

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  • .NET regular expression

    - by vert
    How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following: a-z A-Z Æ æ Å å Ø ø - '

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  • Regular expression to process key value pairs

    - by user677680
    I am attempting to write a regular expression to process a string of key value(s) pairs formatted like so KEY/VALUE KEY/VALUE VALUE KEY/VALUE A key can have multiple values separated by a space. I want to match a keys values together, so the result on the above string would be VALUE VALUE VALUE VALUE I currently have the following as my regex [A-Z0-9]+/([A-Z0-9 ]+)(?:(?!^[A-Z0-9]+/)) but this returns VALUE KEY as the first result.

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  • Regular expression to remove one parameter from query string

    - by Kip
    I'm looking for a regular expression to remove a single parameter from a query string, and I want to do it in a single regular expression if possible. Say I want to remove the foo parameter. Right now I use this: /&?foo\=[^&]+/ That works as long as foo is not the first parameter in the query string. If it is, then my new query string starts with an ampersand. (For example, "foo=123&bar=456" gives a result of "&bar=456".) Right now, I'm just checking after the regex if the query string starts with ampersand, and chopping it off if it does. Example edge cases: Input | Output -------------------------+----------------- foo=123 | (empty string) foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 Edit OK as pointed out in comments there are there are way more edge cases than I originally considered. I got the following regex to work with all of them: /&foo(\=[^&]*)?(?=&|$)|^foo(\=[^&]*)?(&|$)/ This is modified from Mark Byers's answer, which is why I'm accepting that one, but Roger Pate's input helped a lot too. Here is the full suite of test cases I'm using, and a Perl script which tests them. Input | Output -------------------------+------------------- foo | foo&bar=456 | bar=456 bar=456&foo | bar=456 abc=789&foo&bar=456 | abc=789&bar=456 foo= | foo=&bar=456 | bar=456 bar=456&foo= | bar=456 abc=789&foo=&bar=456 | abc=789&bar=456 foo=123 | foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 xfoo | xfoo xfoo&bar=456 | xfoo&bar=456 bar=456&xfoo | bar=456&xfoo abc=789&xfoo&bar=456 | abc=789&xfoo&bar=456 xfoo= | xfoo= xfoo=&bar=456 | xfoo=&bar=456 bar=456&xfoo= | bar=456&xfoo= abc=789&xfoo=&bar=456 | abc=789&xfoo=&bar=456 xfoo=123 | xfoo=123 xfoo=123&bar=456 | xfoo=123&bar=456 bar=456&xfoo=123 | bar=456&xfoo=123 abc=789&xfoo=123&bar=456 | abc=789&xfoo=123&bar=456 foox | foox foox&bar=456 | foox&bar=456 bar=456&foox | bar=456&foox abc=789&foox&bar=456 | abc=789&foox&bar=456 foox= | foox= foox=&bar=456 | foox=&bar=456 bar=456&foox= | bar=456&foox= abc=789&foox=&bar=456 | abc=789&foox=&bar=456 foox=123 | foox=123 foox=123&bar=456 | foox=123&bar=456 bar=456&foox=123 | bar=456&foox=123 abc=789&foox=123&bar=456 | abc=789&foox=123&bar=456 Test script (Perl) @in = ('foo' , 'foo&bar=456' , 'bar=456&foo' , 'abc=789&foo&bar=456' ,'foo=' , 'foo=&bar=456' , 'bar=456&foo=' , 'abc=789&foo=&bar=456' ,'foo=123' , 'foo=123&bar=456' , 'bar=456&foo=123' , 'abc=789&foo=123&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); @exp = ('' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); print "Succ | Input | Output | Expected \n"; print "-----+--------------------------+--------------------------+-------------------------\n"; for($i=0; $i <= $#in; $i++) { $out = $in[$i]; $out =~ s/_PUT_REGEX_HERE_//; $succ = ($out eq $exp[$i] ? 'PASS' : 'FAIL'); #if($succ eq 'FAIL') #{ printf("%s | %- 24s | %- 24s | %- 24s\n", $succ, $in[$i], $out, $exp[$i]); #} }

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  • Silverlight 4 application failing to build in Blend 4 Beta..

    - by loyalpenguin
    Hi, I'm creating a simple silverlight application using Silverlight 4 and Expression Blend 4 Beta, but when I run the Application I get the following Error: C:\Users\WebDevelop1\Documents\Expression\Blend 4 Beta\Projects\SilverlightApplication1\SilverlightApplication1.sln.metaproj : error MSB4126: The specified solution configuration "Debug|HPD" is invalid. Please specify a valid solution configuration using the Configuration and Platform properties (e.g. MSBuild.exe Solution.sln /p:Configuration=Debug /p:Platform="Any CPU") or leave those properties blank to use the default solution configuration. Done building project "SilverlightApplication1.sln" -- FAILED. Build failed. I'm relatively new to silverlight and not really sure where to start. This has happened with every project I have created in Blend, but when I run it in VS2010 it runs perfect. Is this a known issue with the Beta release or am I possibly missing something? Thanks in advance.

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  • Problem using Blend 3 Interaction.Behaviours in VS2010

    - by Andre Luus
    There seems to be a problem with support for the Interactivity namespace of Blend 3 in the VS2010 xaml editor. I have the following installed: VS2010 Blend 3 + Blend 3 SDK I am trying to compile a demo project that is targeted at .Net 4 Client Profile and has a reference to System.Windows.Interactivity (in the Blend 3 folder). In the object browser everything appears to be fine. I can also access Interaction.Behaviours from code-behind, but if I put the namespace xmlns:i="http://schemas.microsoft.com/expression/2010/interactivity" in the xaml file and try to use it, the intellisense is blank. If I copy something in there anyway, the compiler says: The tag 'Interaction.Behaviors' does not exist in XML namespace 'http://schemas.microsoft.com/expression/2010/interactivity'. Do I need to install Blend 4 RC or something?

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  • The best way to organize WPF projects

    - by Mike
    Hello everybody, I've started recently to develop a new software in WPF, and I still don't know which is the best way to organize the application, to be more productive with Visual Studio and Expression Blend. I noticed 2 annoying things I'd like to solve: I'm using Code Contracts in my projects, and when I run my project with Expression Blend, it launches the static analysis of the code. How can I stop that? Which configuration of the project does Blend use by default? I've tried to disable Code Contracts in a new configuration. It works in VS as the static analysis is not launched, but it has no effects in Blend. I've thinked about splitting the Windows Application in 2 parts: the first one containing the views of the WPF (app.exe) and the second one being the core of the project, with the logic code (app.core.dll), and I would just open the former project in Blend. Any thoughts about that? Thanks in advance Mike

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  • PHP5 : Applying a method from an extended class on an object from the original (parent) class.

    - by Glauber Rocha
    Hello, I'm trying to extend two native PHP5 classes (DOMDocument and DOMNode) to implement 2 methods (selectNodes and selectSingleNode) in order to make XPath queries easier. I thought it would be rather straighforward, but I'm stuck in a problem which I think is an OOP beginner's issue. class nDOMDocument extends DOMDocument { public function selectNodes($xpath){ $oxpath = new DOMXPath($this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Then I tried to do extend DOMNode to implement the same methods so I can perform an XPath query directly on a node: class nDOMNode extends DOMNode { public function selectNodes($xpath){ $oxpath = new DOMXPath($this->ownerDocument,$this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Now if I execute the following code (on an arbitrary XMLDocument): $xmlDoc = new nDOMDocument; $xmlDoc->loadXML(...some XML...); $node1 = $xmlDoc->selectSingleNode("//item[@id=2]"); $node2 = $node1->selectSingleNode("firstname"); The third line works and returns a DOMNode object $node1. However, the fourth line doesn't work because the selectSingleNode method belongs to the nDOMNode class, not DOMNode. So my question: is there a way at some point to "transform" the returned DOMNode object into a nDOMNode object? I feel I'm missing some essential point here and I'd greatly appreciate your help. (Sorry, this is a restatement of my question http://stackoverflow.com/questions/2573820/)

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  • Regular Expressions, Checking for a range of occurrences

    - by gmcalab
    I have a phone number I want to match against a regular expression. The format of the phone number must match this: (123) 123-4567 x12345 The extension is optional. Also the extension must contain 1-5 numbers. Below is a regular expression I wrote that works. ^\(\d{3}\) \d{3}-\d{4}( x\d\d?\d?\d?\d?)?$ I was wondering if there is a better way to check for the extension instead of x\d\d?\d?\d?\d? Can I say 1-5 occurrences of \d instead of the above some how ?

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  • Equivalence of boolean expressions

    - by Iulian Serbanoiu
    Hello, I have a problem that consist in comparing boolean expressions ( OR is +, AND is * ). To be more precise here is an example: I have the following expression: "A+B+C" and I want to compare it with "B+A+C". Comparing it like string is not a solution - it will tell me that the expressions don't match which is of course false. Any ideas on how to compare those expressions? Any ideas about how can I tackle this problem? I accept any kind of suggestions but (as a note) the final code in my application will be written in C++ (C accepted of course). An normal expression could contain also parenthesis: (A * B * C) + D or A+B*(C+D)+X*Y Thanks in advance, Iulian

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  • C# LINQ Where Predicate Type Arguments

    - by blu
    I have an XElement with values for mock data. I have an expression to query the xml: Expression<Func<XElement, bool>> simpleXmlFunction = b => int.Parse(b.Element("FooId").Value) == 12; used in: var simpleXml = xml.Elements("Foo").Where(simpleXmlFunction).First(); The design time error is: The type arguments for method 'System.Linq.Enumerable.Where(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly' The delegate supplied to Where should take in an XElement and return a bool, marking if the item matches the query, I am not sure how to add anything more to the delegate or the where clause to mark the type. Also, the parallel method for the real function against the Entity Framework does not have this issue. What is not correct with the LINQ-to-XML version?

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