Search Results

Search found 31657 results on 1267 pages for 'too much php'.

Page 414/1267 | < Previous Page | 410 411 412 413 414 415 416 417 418 419 420 421  | Next Page >

  • [php,mysql] insert only adds upto 1000 records and ignoresall records after that.

    - by user560559
    Hello i have a large database where the client stores personal messages and fire email notifications [if allowed by the users]. certain users have the option of sending messages to their entire network of friends. some users have over 5000 friends in their network so if they select the whole network they'll be sending messages to over 5000 friends and system will store all the messages into a table. the problem is this that it does not insert more than 1000 records and ignores all inserts after the first 1000. i have increased the packet size, bulk_insert_buffer_size but still no luck. since the system stores some of the info in another table for reports, every insert returns its new message id. due to this i can not use the "insert into table (column1,column2) values (value1,value2) , (value1,value2)....etc." table engine is innodb, mysql version is 5.1.3 and is hosted on amazon web services. all i want is to fix this issue of inserting more than 1000 records at a time. as mentioned earlier, it works fine but only up to 1000 records and simply ignores all the records after that. i'm using php foreach(){} to insert message for each friend and if email is available, send notification to the user. this foreach(){} also inserts the same record in another table [with only 3 columns] for generating reports. thank you in advance for all the help and support. WMA.

    Read the article

  • PHP arrays. There must be a simpler method to do this

    - by RisingSun
    I have this array in php returned from db Array ( [inv_templates] = Array ( [0] = Array ( [inven_subgroup_template_id] = 1 [inven_group] = Wires [inven_subgroup] = CopperWires [inven_template_id] = 1 [inven_template_name] = CopperWires6G [constrained] = 0 [value_constraints] = [accept_range] = 2 - 16 [information] = Measured Manual ) [1] = Array ( [inven_subgroup_template_id] = 1 [inven_group] = Wires [inven_subgroup] = CopperWires [inven_template_id] = 2 [inven_template_name] = CopperWires2G [constrained] = 0 [value_constraints] = [accept_range] = 1 - 7 [information] = Measured by Automated Calipers ) ) ) I need to output this kind of multidimensional stuff Array ( [Wires] = Array ( [inv_group_name] = Wires [inv_subgroups] = Array ( [CopperWires] = Array ( [inv_subgroup_id] = 1 [inv_subgroup_name] = CopperWires [inv_templates] = Array ( [CopperWires6G] = Array ( [inv_name] = CopperWires6G [inv_id] = 1 ) [CopperWires2G] = Array ( [inv_name] = CopperWires2G [inv_id] = 2 ) ) ) ) ) ) I currently do this stuff foreach ($data['inv_templates'] as $key = $value) { $processeddata[$value['inven_group']]['inv_group_name'] = $value['inven_group']; $processeddata[$value['inven_group']]['inv_subgroups'][$value['inven_subgroup']]['inv_subgroup_id'] = $value['inven_subgroup_template_id']; $processeddata[$value['inven_group']]['inv_subgroups'][$value['inven_subgroup']]['inv_subgroup_name'] = $value['inven_subgroup']; $processeddata[$value['inven_group']]['inv_subgroups'][$value['inven_subgroup']]['inv_templates'][$value['inven_template_name']]['inv_name'] = $value['inven_template_name']; $processeddata[$value['inven_group']]['inv_subgroups'][$value['inven_subgroup']]['inv_templates'][$value['inven_template_name']]['inv_id'] = $value['inven_template_id']; } return $processeddata; EDIT : A var_export array ( 'inv_templates' = array ( 0 = array ( 'inven_subgroup_template_id' = '1', 'inven_group' = 'Wires', 'inven_subgroup' = 'CopperWires', 'inven_template_id' = '1', 'inven_template_name' = 'CopperWires6G', 'constrained' = '0', 'value_constraints' = '', 'accept_range' = '2 - 16', 'information' = 'Measured Manual', ), 1 = array ( 'inven_subgroup_template_id' = '1', 'inven_group' = 'Wires', 'inven_subgroup' = 'CopperWires', 'inven_template_id' = '2', 'inven_template_name' = 'CopperWires6G', 'constrained' = '0', 'value_constraints' = '', 'accept_range' = '1 - 7', 'information' = 'Measured by Automated Calipers', ), ), ) The foreach is almost unreadable. There must be a simpler way

    Read the article

  • PHP mail function, some clients aren't showing my mails as html?

    - by Don
    I'm trying to send emails to my website members using the mail() function with PHP, The mails are in hebrew, and I want to send an html email, That's pretty much how I send it $mail_to = "[email protected]"; $message = " <html> some content here </html> "; $headers = "MIME-Version: 1.0" . "\r\n"; $headers .= "Content-type:text/html;charset=windows-1255" . "\r\n"; $headers .= 'From: "MyWebsiteName" <[email protected]>' . "\r\n"; $mail = mail($mail_to, $subject, $message, $headers ); It works completely fine with clients such as Gmail, or thunderbird users, but I viewed it in a few other clients, that aren't so famous, but still widely used in my country, and it just shows me the html source.. I'll also add that I've seen other mails in those clients that are working fine, so they are supporting html mails. What am I doing wrong?

    Read the article

  • [PHP, CSS, & ?] fixed width div, resizing text on the fly based on length

    - by Andrew Heath
    Let's say you've got a simple fixed-width layout that pulls a title from a MySQL database. CSS: #wrapper { width: 800px; } h1 { width: 100%; } HTML: <html> <body> <div id="wrapper"> <h1> $titleString </h1> </div> </body> </html> But the catch is, the length of the title string pulled from your MySQL database varies wildly. Sometimes it might be 10 characters, sometimes it might be 80. It's possible to establish a min & max character count. How, if at all possible, do I get the text-size of my <h1>$titleString</h1> to enlarge/decrease on-the-fly such that the string is only ever on one line and best fit to that line length? I've seen a lot of questions about resizing the div - but in my case the div must always be 100% (800px) and I want to best-fit the title. Obviously a maximum text-size value would have to be set so 5 character strings don't become gargantuan. Does anyone have a suggestion? I'm only using PHP/MySQL/CSS on this page at the moment, but incorporation of another language is fine if it means I can solve the problem. The only thing I can think of is a bruteforce approach whereby through trial and error I establish acceptable string character count ranges matched with CSS em sizes, but that'd be a pretty ugly implementation from the code side.

    Read the article

  • formatting mysql data for ouptut into a table

    - by bsandrabr
    Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

    Read the article

  • Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

    Read the article

  • Accessing cookies in php which are set in java web application

    - by user866937
    I am setting a cookie at the domain level on encrypted connection in Java web application running on tomcat and I would like it to be accessible in a php web application running on a same domain but different subdomain. Java web application running on https://javaapp.mycompany.com php web application running on https://phpapp.mycompany.com/subpath/index.php From java, I am setting the cookie with following parameters: Domain: .mycompany.com Send For: Encrypted connections only Expires: After 2 months Path: /subpath Name: __C Value: 1 Dumping all the cookies from my php web application running on https, I do not see any cookies getting dumped by the php web application. Whereas if I set the cookies in Java for any type of connection, only then php web application is able to see them if I run the php app on http instead of https. I believe php web app should be able to retrieve then cookies set for https only and for particular domain and all immediate sub-domains. What am I doing wrong here? Thanks in advance for the help.

    Read the article

  • Importing a div's content from a Static HTML file using PHP or jQuery or Ajax?

    - by Vikram
    Hello friends a newbie question... The Issue is like this: I have a static HTML file and I want to import just a portion of that file into another page. How can I do that. Example Code: <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Some title here</title> <link rel="stylesheet" type="text/css" href="styles.css" /> </head> <body> <div id="box-1"> <div class="block"> <!-- Some code here --> </div> </div> <div id="box-2"> <div class="block"> <!-- Some code here --> </div> </div> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script src="script.js"></script> </body> </html> Now what I want is to read this HTML file and import just this bit: <div id="box-1"> <div class="block"> <!-- Some code here --> </div> </div> Is there a way of doing it? Kindly help. Even a PHP, jQuery, Ajax or any other solution will also do. Please help me.

    Read the article

  • running php script manually and getting back to the command line?

    - by Simpson88Keys
    I'm running a php script via command line, and it works just fine, except that when it's finished, it doesn't go back to the command line? Just sits there, so I never when it's done... This is the script: $conn_id = ftp_connect(REMOTE) or die("Couldn't connect to ".REMOTE); $login_result = ftp_login($conn_id, 'OMITTED','OMITTED'); if ((!$conn_id) || (!$login_result)) die("FTP Connection Failed"); $dir = 'download'; if ($dir != ".") { if (ftp_chdir($conn_id, $dir) == false) { echo ("Change Dir Failed: $dir<BR>\r\n"); return; } if (!(is_dir($dir))) mkdir($dir); chdir ($dir); } $contents = ftp_nlist($conn_id, "."); foreach ($contents as $file) { if ($file == '.' || $file == '..') continue; if (@ftp_chdir($conn_id, $file)) { ftp_chdir ($conn_id, ".."); ftp_sync ($file); } else ftp_get($conn_id, $file, $file, FTP_BINARY); } ftp_chdir ($conn_id, ".."); chdir (".."); ftp_close($conn_id);

    Read the article

  • method for creating PHP templates (ie html with variables)?

    - by Haroldo
    I'm designing my html emails, these are to be a block of html containing variables that i can store in a $template variable. My problem comes with the storing in the variable part. putting all my html into php makes it a pain in the bum to work with. for example, the below code is fine for a simple email but once i start getting nested tables etc its going to get really confusing... $template.= 'Welcome ' . $username . '<br /><br /><br />'; $template.= 'Thank-you for creating an account <br /><br />'; $template.= 'Please confirm your account by click the link below! <br /><br />'; $template.= '<a href="' . $sitepath . '?email=' . $email . '&conf_key=' . $key . '" style="color: #03110A;"><font size="5" font-family="Verdana, Geneva, sans-serif" color="#03110A">' . $key . '</font></a>'; $template.='</body></html>'; is there a way i can still store the html in a $var but not have to write it like this?

    Read the article

  • About Web service ,how to use Ajax to call a specific member function of a class?

    - by Liu chwen
    I'm trying to build a web service by PHP. In my case, I called the getINFO(), but the return value on client side always null. Have no idea to solve this problem.. Here's the SOAPserver code(WS.WEB_s.php): require("WEB_s.php"); ini_set("soap.wsdl_cache_enabled", 0); $server = new SoapServer('wsdl/WEB_s.wsdl'); $server->setClass("WEB_s"); $server->handle(); Where the main Class is(WEB_s.php): final class WEB_s { public function getINFO(){ $JsonOutput = '{"key":"value",...}'; return $JsonOutput; } public function setWAN($setCommand,$newConfigfilePath){ $bOutput; return $bOutput; } } And Client side: $(document).ready(function(){ $('#qqq').button().click(function(){ var soapMessage = LoginSoap($('#uid').val(),$('#pwd').val()); alert('soapMessage'); $.ajax({ //url: 'libraries/WS.WEB_s.php/WEB_s/getINFO',//success , return null //url: 'libraries/WS.WEB_s.php/', //success , return null url: 'libraries/WS.WEB_s.php/getINFO',//success , return null type: 'GET', timeout: (10* 1000), contentType: "text/xml", dataType: "xml", success: function( data,textStatus,jqXHR){ alert('Server success(' + data+')('+ textStatus + ')(' + jqXHR + ')'); }, error: function (request, status, error) { alert('Server Error(' + status+')->'+error); }, complete: function (jqXHR, textStatus) { alert('Server success(' + jqXHR+')('+ textStatus + ')'); } }); }); }); The following is the corresponding WSDL file : http://codepaste.net/95wq9b

    Read the article

  • Why won't the following PDO transaction won't work in PHP?

    - by jfizz
    I am using PHP version 5.4.4, and a MySQL database using InnoDB. I had been using PDO for awhile without utilizing transactions, and everything was working flawlessly. Then, I decided to try to implement transactions, and I keep getting Internal Server Error 500. The following code worked for me (doesn't contain transactions). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } Then I attempted to utilize transactions with the following code (which doesn't work). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->beginTransaction(); $dbh->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); $dbh->commit(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } When I run the previous code, I get an Internal Server Error 500. Any help would be greatly appreciated! Thanks!

    Read the article

  • How can I join 3 tables with mysql & php?

    - by steven
    check out the page [url]http://www.mujak.com/test/test3.php[/url] It pulls the users Post,username,xbc/xlk tags etc which is perfect... BUT since I am pulling information from a MyBB bulletin board system, its quite different. When replying, people are are allowed to change the "Thread Subject" by simplying replying and changing it. I dont want it to SHOW the changed subject title, just the original title of all posts in that thread. By default it repies with "RE:thread title". They can easily edit this and it will show up in the "Subject" cell & people wont know which thread it was posted in because they changed their thread to when replying to the post. So I just want to keep the orginial thread title when they are replying. Make sense~?? Tables:mybb_users Fields:uid,username Tables:mybb_userfields Fields:ufid Tables:mybb_posts Fields:pid,tid,replyto,subject,ufid,username,uid,message Tables:mybb_threads Fields:tid,fid,subject,uid,username,lastpost,lastposter,lastposteruid I haev tried multiple queries with no success: $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_userfields.ufid ) WHERE mybb_posts.fid=42"); $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_posts.uid ) WHERE mybb_threads.fid=42"); $result = mysql_query(" SELECT * FROM mybb_posts LEFT JOIN (mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid ) WHERE mybb_posts.fid=42");

    Read the article

  • What is a good RPC model for building a AJAX web app using PHP & JS?

    - by user366152
    I'm new to writing AJAX applications. I plan on using jQuery on the client side while PHP on the server side. I want to use something like XML-RPC to simplify my effort in calling server-side code. Ideally, I wouldn't care whether the transport layer uses XML or JSON or a format more optimized for the wire. If I was writing a console app I'd use some tool to generate function stubs which I would then implement on the RPC server while the client would natively call into those stubs. This provides a clean separation. Is there something similar available in the AJAX world? While on this topic, how would I proceed with session management? I would want it to be as transparent as possible. For example, if I try to hit an RPC end-point which needs a valid session, it should reject the request if the client doesn't pass a valid session cookie. This would really ease my application development. I'd then have to simply handle the frontend using native JS functions. While on the backend, I can simply implement the RPC functions. BTW I dont wish to use Google Web Toolkit. My app wont be extremely heavy on AJAX.

    Read the article

  • php weird bug where an array is not an array !

    - by iko
    I've been going mad trying to figure out why an array would not be an array in php. For a reason I can't understand I have a bug in a smarty class. The code is this : $compiled_tags = array(); for ($i = 0, $for_max = count($template_tags); $i < $for_max; $i++) { $this->_current_line_no += substr_count($text_blocks[$i], "\n"); // I tried array push instead to see // bug is here array_push($compiled_tags,$this->_compile_tag($template_tags[$i])); //$compiled_tags[] = $this->_compile_tag($template_tags[$i]); $this->_current_line_no += substr_count($template_tags[$i], "\n"); } the error message is Warning: array_push() expects parameter 1 to be array, integer given in .... OR before with [] Warning: Cannot use a scalar value as an array in .... I trying a var_debug on $compiled_tags and as soon I enter the for loop is not an array anymore but an integer. I tried renaming the variable, but same problem. I'm sure is something simple that I missed but I can't figure it out. Any help is (as always) welcomed !

    Read the article

  • How to get values from SQL query made by php?

    - by Ole Jak
    So I made a query like this global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); in my DB there are filds ID, UID, SID, TIME (all INT type exept time) So I am triing to print query relult into form <form> <select class="multiselect" multiple="multiple" name="SIDs"> <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); for ($count=1; $count <= $streams_count; $count++) { echo "<option value=\"{$count}\""; echo ">{$count}</option>"; } ?> </select> <br/> <input type="submit" value="Submit Form"/> </form> How to print out as "option" "values" SID's from my sql query?

    Read the article

  • Can anyone explain this impossible bit of PHP logic?

    - by user268208
    I'm attempting to debug a simple PHP script. Essentially, there's a variable which is defined with: $variable = ($_GET['variable'] == 'true') ? TRUE : FALSE; Then, in the view file, the following code is meant to display a box if $variable == TRUE: <? if ($variable == true) { ?> <p class="box">You have imported a new plan.</p> <? } ?> Now, even when that $variable, as shown by var_dump($variable); == FALSE, that HTML is printed between the if { } tags. To me, this defies logic. I simply can't figure out this problem out. Furthermore, this code works fine on many PHP4 and PHP5 installations except for one particular server running PHP5.2. Any possible suggestions? Leads? I'm pulling out my hair trying to figure this one out. Thank you.

    Read the article

  • Where is a small, simple CMS that has no Front End done in PHP?

    - by user559469
    The keys are: small and simple PHP MySql no Front End By "no front end" I mean literally, I can control the look 100%. I just want a CMS on the "backend" to manage content (user login/security, upload images, udate articles, etc.) that will not dictate in anyway how the managed data is presented. Maybe it just keeps the info in a (MySql) database (which I can query and extract myself) or if it writes content, it is in super-clean xhtml fragments or even just xml I will parse myself? I have looked at Wordpress -- and don't like the code it generates, not to mention the sites look too "canned" (you can usually spot a WP site a mile a way.) Joomla and Drupal look more customizable, but they are bloated now in my opinion, and really I just want something lightweight and simple. For one-user mom-and-pop sites. (No tiered publishing/approval systems, and all that.) I envision plugging this CMS into existing websites/web apps where most of the site is made and managed by me, but a few choice areas are managed by the site owner.

    Read the article

  • How to write data option in jQuery.ajax() function when it include in a mysql_query?

    - by cj333
    I modify a php comment system. I want add it after every article witch are query from database. this is the php part <?php ... while($result = mysql_fetch_array($resultset)) { $article_title = $result['article_title']; ... ?> <form id="postform" class="postform"> <input type="hidden" name="title" id="title" value="<?=$article_title;?>" /> <input type="text" name="content" id="content" /> <input type="button" value="Submit" class="Submit" /> </form> ... <?php } ?> this is the ajax part. $.ajax({ type: "POST", url: "ajax_post.php", data: {title:$('#title').val(), content:$('#content').val() ajax_post.php echo $title; echo $content; How to modify the ajax data part that each article's comment can send each data to the ajax_post.php? thanks a lot.

    Read the article

  • PHP class extends not working why and is this how to correctly extend a class?

    - by Matthew
    Hi so I'm trying to understand how inherteince works in PHP using object oriented programming. The main class is Computer, the class that is inheriting is Mouse. I'm extedning the Computer class with the mouse class. I use __construct in each class, when I istinate the class I use the pc type first and if it has mouse after. For some reason computer returns null? why is this? class Computer { protected $type = 'null'; public function __construct($type) { $this->type = $type; } public function computertype() { $this->type = strtoupper($this->type); return $this->type; } } class Mouse extends Computer { protected $hasmouse = 'null'; public function __construct($hasmouse){ $this->hasmouse = $hasmouse; } public function computermouse() { if($this->hasmouse == 'Y') { return 'This Computer has a mouse'; } } } $pc = new Computer('PC', 'Y'); echo $pc->computertype; echo $pc->computermouse;

    Read the article

  • PHP - How do you secure a unique variable name?

    - by 102319141763223461745
    This function cropit, which I shamelessly stole off the internet, crops a 90x60 area from an existing image. In this code, when I use the function for more than one item (image) the one will display on top of the other (they come to occupy the same output space). I think this is because the function has the same (static) name ($dest) for the destination of the image when it's created (imagecopy). I tried, as you can see to include a second argument to the cropit function which would serve as the "name" of the $dest variable, but it didn't work. In the interest of full disclosure I have 22 hours of PHP experience (incidentally the same number of hours since the last I slept) and I am not that smart to begin with. Even if there's something else at work here entirely, seems to me that generally it must be useful to have a way to secure that a variable is always given a unique name. function cropit($srcimg, $dest) { $im = imagecreatefromjpeg($srcimg); $img_width = imagesx($im); $img_height = imagesy($im); $width = 90; $height = 60; $tlx = floor($img_width / 2) - floor ($width / 2); $tly = floor($img_height / 2) - floor ($height / 2); if ($tlx < 0) { $tlx = 0; } if ($tly < 0) { $tly = 0; } if (($img_width - $tlx) < $width) { $width = $img_width - $tlx; } if (($img_height - $tly) < $height) { $height = $img_height - $tly; } $dest = imagecreatetruecolor ($width, $height); imagecopy($dest, $im, 0, 0, $tlx, $tly, $width, $height); imagejpeg($dest); imagedestroy($dest); } $img = "imagefolder\imageone.jpg"; $img2 = "imagefolder\imagetwo.jpg"; cropit($img, $i1); cropit($img2, $i2); ?

    Read the article

  • object-oriented question

    - by user522962
    I am attempting to put all my database connections in 1 php file, rather than in each of my individual php pages. I have the following: //conn.php: <?php class conn { var $username = "name"; var $password = "password"; var $server = "localhost"; var $port = "3306"; var $databasename = "db"; var $tablename = "tablename"; var $connection; public function getConnected() { $this->connection = mysqli_connect( $this->server, $this->username, $this->password, $this->databasename, $this->port ); } } ?> // file.php: <?php require_once("conn.php"); class myClass{ public function con() { $conn = new conn(); $conn->getConnected(); } public function myF() { $stmt = mysqli_prepare($conn->connection, "SELECT * FROM $conn->tablename"); mysqli_stmt_execute($stmt); } } ?> I then call this as follows: $myNew = new myClass(); $myNew-con(); $myNew-myF(); When I call this, I get the following error: Undefined property: myClass::$connection What am I doing wrong?

    Read the article

  • How to check successful copy() function execution in php?

    - by OM The Eternity
    How to check successful copy() function execution in php? I am using the following code: <? function full_copy( $source, $target ) { if ( is_dir( $source ) ) { @mkdir( $target ); $d = dir( $source ); while ( FALSE !== ( $entry = $d->read() ) ) { if ( $entry == '.' || $entry == '..' ) { continue; } $Entry = $source . '/' . $entry; if ( is_dir( $Entry ) ) { full_copy( $Entry, $target . '/' . $entry ); continue; } copy( $Entry, $target . '/' . $entry ); } $d->close(); }else { copy( $source, $target ); } } $source ='.'; $destination = '/html/parth/'; full_copy($source, $destination); ?> I do not get anything in my parth folder. Why? I am using Windows, Script is executed on fedora system (its my server)...

    Read the article

  • ZF2 namespace and file system

    - by user1918648
    I have standard Application module in ZF2. It's configured by default, I didn't change anything. I just added some stuff: module/ Application/ src/ Application/ Entity/ Product/ **Product.php** Controller/ **IndexController.php** Product.php namespace Application\Entity; class Product { } IndexController.php namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } } and I get following error: Fatal error: Class 'Application\Entity\Product' not found in \module\Application\src\Application\Controller\IndexController.php on line 20 I use the same namespace, but it doesn't see it. Why? P.S: If I will change Product.php to be the following: namespace Application\Entity\Product; class Product { } then in the IndexController.php the following code will be working: namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } }

    Read the article

  • Why does this sql statement keep saying it is a boolean and not a parameter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

    Read the article

< Previous Page | 410 411 412 413 414 415 416 417 418 419 420 421  | Next Page >