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  • more radio problems * sighs * been at this for one week now

    - by jeansymolanza
    hi guys really i don't know what im doing wrong... i am trying to process multiple radios with mysql. the first step has involved me echoing the results on the process page. each time i select any radio option it simply displays the first row result. this is that i see after trying to submit the form: Notifications Thank you. The notifications have been updated successfully. statusid: 14 notc2: 1 Return this is the code for the form: <div style="padding: 15px;"> <span class="loginfail" style="font-size:24px; font-weight: bold">Notifications</span><p> <?php include("progress_insertcomment.php"); ?> <?php // Make a MySQL Connection mysql_select_db("speedycm_data") or die(mysql_error()); $query_comment = "select * from tbl_alert order by id desc limit 1"; $comment = mysql_query($query_comment, $speedycms) or die(mysql_error()); $row_comment = mysql_fetch_assoc($comment); $totalRows_comment = mysql_num_rows($comment); ?> <!--- add notification ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <span id="sprytextarea1"> <textarea id='comment' name="comment" style="height: 75px; width:330px;"><?php echo $row_comment['comment']; ?></textarea> </span> <p> <button type="submit">Add</button> <input type="hidden" name="notc" value="1"/> </form> <!--- notification history ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table border="0" cellspacing="2" cellpadding="2"> <?php if ( $row_comment == 0 ) { echo "<span style='font-size: 11px;'>No current alerts.</span>"; } else { // Get all the data from the "example" table $result = mysql_query("SELECT * FROM tbl_alert ORDER BY id DESC") or die(mysql_error()); while($rows=mysql_fetch_array($result)){ ?> <tr> <td> <?php echo "<div class='bubble'><div class='pimped'> <blockquote>" . $rows['comment'] . " </blockquote></div> <cite><strong>" . $rows['user'] . "</strong> @ " . $rows['date'] . "</cite> <span style='font-size: 10px;'> <p> <a href='editalert.php?id=". $rows['id'] ."' class='form' >Edit</a>&nbsp;&#8226;&nbsp;<a href='deletealert.php?id=". $rows['id'] ."' class='form'>Delete</a> </span> </div> "; ?> </td> <td valign="top" align="center"><div style="padding-left: 30px;"><span style="font-size: 10px;">Completed?</span> <p class="field switch"> <!--- determine status of notification ---> <?php $status = $rows['status']; $id = $rows['id']; ?> <input type="radio" name="selstatus[<?php echo $id; ?>]" value="no" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="radio" name="selstatus[<?php echo $id; ?>]" value="yes" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="hidden" name="statusid" value="<?php echo $id; ?>"/> <label for="radio1" class="cb-enable <?php if($status == 'yes') {echo 'selected';} else {echo '';} ?>"><span>Yes</span></label> <label for="radio2" class="cb-disable <?php if($status == 'no') {echo 'selected';} else {echo '';} ?>"><span>No</span></label> </p> </div></td> </tr> <tr> <td></td> <?php } } ?> <td align="center"><div style="padding-left: 30px;"> <button type="submit">Update</button> <input type="hidden" name="notc2" value="1"/> </div></td> </tr> </table> </form> </div> this is the code for the processing page: <?php // 6) update notifications if (array_key_exists('notc2',$_POST)) { $update = $_POST['selstatus']; echo "<p style='font-size: 12px;'>Thank you. The notifications have been updated successfully.<p>"; foreach($_POST as $key => $value){ echo $key . ': ' . $value . '<br>'; } echo "<p><span style='font-size: 12px;'> <a onClick=\"history.go(-1)\" class='form'>Return</a></p> <p></span> "; exit; }; ?> how do i resolve this problem? please any help would be appreciated. i would like to display the id and value of the selected checkbox on the processing page before inserting it into the table. thanking you in advance. GOD BLESS

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  • WHERE id IN doesn't work in UPDATE

    - by Donator
    UPDATE statistics' SET money = money + '$money' WHERE member_id IN ((SELECT member_id FROM races WHERE l_id = '$mem_id'), $other_id) What's wrong with that? I want to retrieve all member_ids from races and also include to member_id $other_id. Without $other_id it works. By the way, it gives me "Subquery returns more than 1 row" error.

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  • passing a scalar query result to coalesce

    - by Fakrudeen
    How can I pass the result from a scalar [single row, single value] query to coalesce? I am trying to pick the priority as (the biggest priority so far in the table) + 1. [0 if it is the first row.] create trigger priority_SuperRuleSamples before insert on SuperRuleSamples FOR EACH ROW SET NEW.Priority=coalesce(NEW.Priority, coalesce( select Priority from SuperRuleSamples order by Priority desc limit 1, -1 )+1 )

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  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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  • SQL clone record with a unique index

    - by Milhous
    Is there a clean way of cloning a record in SQL that has an index(auto increment). I want to clone all the fields except the index. I currently have to enumerate every field, and use that in an insert select, and I would rather not explicitly list all of the fields, as they may change over time.

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  • How many indexes will actually get used?

    - by Ender
    I'm writing a page that does very simple search queries, resulting in something like: SELECT * FROM my_table WHERE A in (a1, a2, a3) AND B in (b1, b2) AND C in (c1, c2, c3, c4) AND And so on for a variable number of columns, usually ~5. If I create a separate index for each column (one for A, one for B, one for C, not (A,B,C)), will all of them be used in the above query?

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  • Where binary in SQL

    - by fire
    I have an SQL statement: SELECT * FROM customers WHERE BINARY login='xxx' AND password='yyyy' There are no blob/binary fields in the table, do I need the BINARY after the WHERE what else does it do?

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  • Translate SQL statement into named_scope?

    - by keruilin
    How can I translate this SQL into a named_scope? Also, I want the total comments param to be passed through a lambda. "select users., count() as total_comments from users, comments where (users.id = comments.user_id) and (comments.public_comment = 1) and (comments.aasm_state = 'posted') and (comments.forum_user_id is null) group by users.id having total_comments 25"

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • Joining 3 tables - doing joins how to

    - by Kieran
    This is my current query - its not getting the required result. I want it do display all of the "resources" even if they dont have a connection. SELECT * FROM (`user_permissions`) JOIN `user_groups` ON `user_groups`.`id` = `user_permissions`.`role` JOIN `user_resources` ON `user_resources`.`id` = `user_permissions`.`resource` WHERE `role` = '4' When I try left join or right join it still returns the same result. The result I get is: id | role | resource | name 5 | 4 | 2 | Changelog I want id | role | resource | name 5 | 4 | 2 | Changelog null | null | null | Resource2 null | null | null | Resource3 Is this possible?

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  • php functions within functions.

    - by Adamski
    Hi all, ihave created a simple project to help me get to grips with php and mysql, but have run into a minor issue, i have a working solution but would like to understand why i cannot run this code successfully this way, ill explain: i have a function, function fetch_all_movies(){ global $connection; $query = 'select distinct * FROM `'.TABLE_MOVIE.'` ORDER BY movieName ASC'; $stmt = mysqli_prepare($connection,$query); mysqli_execute($stmt); mysqli_stmt_bind_result($stmt,$id,$name,$genre,$date,$year); while(mysqli_stmt_fetch($stmt)){ $editUrl = "index.php?a=editMovie&movieId=".$id.""; $delUrl = "index.php?a=delMovie&movieId=".$id.""; echo "<tr><td>".$id."</td><td>".$name."</td><td>".$date."</td><td>".get_actors($id)."</td><td><a href=\"".$editUrl."\">Edit</a> | <a href=\"".$delUrl."\">Delete</a></td></tr>"; } } this fetches all the movies in my db, then i wish to get the count of actors for each film, so i pass in the get_actors($id) function which gets the movie id and then gives me the count of how many actors are realted to a film. here is the function for that: function get_actors($movieId){ global $connection; $query = 'SELECT DISTINCT COUNT(*) FROM `'.TABLE_ACTORS.'` WHERE movieId = "'.$movieId.'"'; $result = mysqli_query($connection,$query); $row = mysqli_fetch_array($result); return $row[0]; } the functions both work perfect when called separately, i just would like to understand when i pass the function inside a function i get this warning: Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /Applications/MAMP/htdocs/movie_db/includes/functions.inc.php on line 287 could anyone help me understand why? many thanks.

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  • mysql_query arguments in PHP

    - by Chris Wilson
    I'm currently building my first database in MySQL with an interface written in PHP and am using the 'learn-by-doing' approach. The figure below illustrates my database. Table names are at the top, and the attribute names are as they appear in the real database. I am attempting to query the values of each of these attributes using the code seen below the table. I think there is something wrong with my mysql_query() function since I am able to observe the expected behaviour when my form is successfully submitted, but no search results are returned. Can anyone see where I'm going wrong here? Update 1: I've updated the question with my enter script, minus the database login credentials. <html> <head> <title>Search</title> </head> <body> <h1>Search</h1> <!--Search form - get user input from this--> <form name = "search" action = "<?=$PHP_SELF?>" method = "get"> Search for <input type = "text" name = "find" /> in <select name = "field"> <option value = "Title">Title</option> <option value = "Description">Description</option> <option value = "City">Location</option> <option value = "Company_name">Employer</option> </select> <input type = "submit" name = "search" value = "Search" /> </form> <form name = "clearsearch" action = "Search.php"> <input type = "submit" value = "Reset search" /> </form> <?php if (isset($_GET["search"])) // Check if form has been submitted correctly { // Check for a search query if($_GET["find"] == "") { echo "<p>You did not enter a search query. Please press the 'Reset search' button and try again"; exit; } echo "<h2>Search results</h2>"; ?> <table align = "left" border = "1" cellspacing = "2" cellpadding = "2"> <tr> <th><font face="Arial, Helvetica, sans-serif">No.</font></th> <th><font face="Arial, Helvetica, sans-serif">Title</font></th> <th><font face="Arial, Helvetica, sans-serif">Employer</font></th> <th><font face="Arial, Helvetica, sans-serif">Description</font></th> <th><font face="Arial, Helvetica, sans-serif">Location</font></th> <th><font face="Arial, Helvetica, sans-serif">Date Posted</font></th> <th><font face="Arial, Helvetica, sans-serif">Application Deadline</font></th> </tr> <? // Connect to the database $username=REDACTED; $password=REDACTED; $host=REDACTED; $database=REDACTED; mysql_connect($host, $username, $password); @mysql_select_db($database) or die (mysql_error()); // Perform the search $find = mysql_real_escape_string($find); $query = "SELECT job.Title, job.Description, employer.Company_name, address.City, job.Date_posted, job.Application_deadline WHERE ( Title = '{$_GET['find']}' OR Company_name = '{$_GET['find']}' OR Date_posted = '{$_GET['find']}' OR Application_deadline = '{$_GET['find']}' ) AND job.employer_id_job = employer.employer_id AND job.address_id_job = address.address_id"; if (!$query) { die ('Invalid query:' .mysql_error()); } $result = mysql_query($query); $num = mysql_numrows($result); $count = 0; while ($count < $num) { $title = mysql_result ($result, $count, "Title"); $date_posted = mysql_result ($result, $count, "Date_posted"); $application_deadline = mysql_result ($result, $count, "Application_deadline"); $description = mysql_result ($result, $count, "Description"); $company = mysql_result ($result, $count, "Company_name"); $city = mysql_result ($result, $count, "City"); ?> <tr> <td><font face = "Arial, Helvetica, sans-serif"><? echo $count + 1; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $title; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $company; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $description; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $date_posted; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $application_deadline; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $education_level; ?></font></td> <td><font face = "Arial, Helvetica, sans-serif"><? echo $years_of_experience; ?></font></td> <? $count ++; } } ?> </body> </html>

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  • How to put comma in counted numbers?

    - by Ronnie Chester Lynwood
    hey huys im counting my table with this code: $county = mysql_query("SELECT COUNT(id) from table where type = 'application'"); $county = mysql_result($county, 0); $applications = ''.$county.''; this give me result like 1156563. but I want to see it like 1,156,563 with commas. how can i do this?

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  • Increment my id in my insert request

    - by Mercer
    hello, i have a table with some rows. idClient, name, adress,country,... i want to know how i can do an insert into this table with auto increment my idClient in my sql request..? Thx. edit: i want do a request like this insert into Client values((select max(idClient),...)

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  • SQL: How to order values inside group by

    - by Denis Yaremov
    Consider the following MS SQL Server table: ID | X | Y ------+-------+------- 1 | 1 | 1 2 | 1 | 2 3 | 1 | 3 4 | 2 | 40 5 | 2 | 500 6 | 3 | 1 7 | 3 | 100 8 | 3 | 10 I need to select the ID of the row that has the maximum value of Y grouped by x, i.e: ID | X | Y ------+-------+------- 3 | 1 | 3 5 | 2 | 500 7 | 3 | 100 The query will be nested several times so an optimal performance solution is required... Thank you!

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  • Unknown column '' in 'field list'

    - by Rixius
    I am running a sql in PHP query that is dieing with the mysql_error() of Unknown column '' in 'field list' The query: SELECT `standard` AS fee FROM `corporation_state_fee` WHERE `stateid` = '8' LIMIT 1 when I run the query in PHPmyadmin, it return the information without flagging the error

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  • SQL: count days in date range?

    - by John Isaacks
    I have a query like this: SELECT COUNT(*) AS amount FROM daily_individual_tracking WHERE sales = 'YES' AND daily_individual_tracking_date BETWEEN '2010-01-01' AND '2010-03-31' I am selected from a date range. Is there a way to also get the total days in the date range?

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  • Zend Framework Multiple Table Query

    - by Jeff
    I am looking to execute this statement via Zend Framework. As I understand it, I can use Zend_Db_Select. Is it possible to use Zend_Db_Table? Three tables: classes, students, and class_students select classes.name, students.student_id, students.fname, students.lname from students, classes, class_students where class_students.student_id=students.student_id AND class_students.class_id=classes.class_id;

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  • How to translate this query:

    - by xRobot
    How can I translate this 2 queries in postgresql ? : . CREATE TABLE example ( id int(10) unsigned NOT NULL auto_increment, from varchar(255) NOT NULL default '0', message text NOT NULL, lastactivity timestamp NULL default '0000-00-00 00:00:00', read int(10) unsigned NOT NULL, PRIMARY KEY (id), KEY from (from) ) DEFAULT CHARSET=utf8; . SELECT * FROM table_1 LEFT OUTER JOIN table_2 ON ( table_1.id = table_2.id ) WHERE (table_1.lastactivity > NOW()-100);

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  • Get previous and next row from current id

    - by Hukr
    How can I do to get the next row in a table? `image_id` int(11) NOT NULL auto_increment `image_title` varchar(255) NOT NULL `image_text` mediumtext NOT NULL `image_date` datetime NOT NULL `image_filename` varchar(255) NOT NULL If the current image is 3 for example and the next one is 7 etc. this won’t work: $query = mysql_query("SELECT * FROM images WHERE image_id = ".intval($_GET['id'])); echo $_GET['id']+1; How should I do? thanks

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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