Search Results

Search found 40581 results on 1624 pages for 'mysql select db'.

Page 413/1624 | < Previous Page | 409 410 411 412 413 414 415 416 417 418 419 420  | Next Page >

  • again new query. i am trying to solve this from one hour. please help

    - by Dharmendra
    Query : List the film title and the leading actor for all of 'Julie Andrews' films. there are three tables : movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) select movie.title,actor.name as cont from movie join casting on (movie.id=casting.movieid) join actor on (casting.actorid=actor.id) where actor.name='Julie andrews' actually i can' get how to find the leading actor.

    Read the article

  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

    Read the article

  • Compare 2 database

    - by shantanuo
    I have 2 identical databases. abc15 and abc18. But one of the database has one extra table and I need to find that. I thought the following query should return it, but is it not showing the record that I expect. select * from information_schema.tables as a left join information_schema.tables as b on a.TABLE_SCHEMA=b.TABLE_SCHEMA AND a.TABLE_NAME=b.TABLE_NAME where a.TABLE_SCHEMA = 'abc15' AND b.TABLE_SCHEMA='abc18' and b.TABLE_NAME IS NULL

    Read the article

  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

    Read the article

  • Sql query listing Fathers and childs with joins, how to distinct them?

    - by DaNieL
    Having those tables: table_n1: | t1_id | t1_name | | 1 | foo | table_n2: | t2_id | t1_id | t2_name | | 1 | 1 | bar | I need a query that gives me two result: | names | | foo | | foo / bar | But i cant figure out the right way. I wrote this one: SELECT CONCAT_WS(' / ', table_n1.t1_name, table_n2.t2_name) AS names FROM table_n1 LEFT JOIN table_n2 ON table_n2.t1_id = table_n1.t1_id that works for an half: this only return the 2° row (in the example above): | names | | foo - bar | This query return the 'father' (table_n1) name only when it doesnt have 'childs' (table_n2). How can i fix it?

    Read the article

  • can i use MAX function for each tuple in the retrieved data set

    - by kshama
    Hi, My table result contains fields: id count ____________ 1 3 2 2 3 2 From this table i have to form another table **score** which should look as follows id my_score ___________ 1 1.0000 2 0.6667 3 0.6667 That is my_score=count/MAX(count) but if i give the query as create TEMPORARY TABLE(select id,(count/MAX(count)) AS my_score from result); only 1 st row is retrieved.Can any one suggest the query so that my_score is calculated for all tuples. Thanks in advance.

    Read the article

  • Why does this PHP script interfere with my CSS layout?

    - by CT
    This page uses $_GET to grab an asset id and query a mysql database and return some information. If 'id' does not match anything, no results are displayed but the page looks fine. If 'id' is null an error would occur at $id = $_GET["id"] or die(mysql_error()); When this occurs, they page layout is not displayed correctly. How do I fix this? Bonus question: How would I get a message like "No matching results found" or something when the id does not match any id in the database or is null. Thank you. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" type="text/css" href="style.css" /> <title>Wagman IT Asset</title> </head> <body> <div id="page"> <div id="header"> <img src="images/logo.png" /> </div> </div> <div id="content"> <div id="container"> <div id="main"> <div id="menu"> <ul> <table width="100%" border="0"> <tr> <td><li><a href="index.php">Search Assets</a></li></td> <td><li><a href="browse.php">Browse Assets</a></li></td> <td><li><a href="add_asset.php">Add Asset</a></li></td> <td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td> </tr> </table> </ul> </div> <div id="text"> <ul> <li> <h1>View Asset</h1> </li> </ul> <table width="100%" border="0" cellpadding="2"> <?php //make database connect mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); //get asset $id = $_GET["id"] or die(mysql_error()); //get type of asset $sql = "SELECT asset.type From asset WHERE asset.id = $id"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_assoc($result); $type = $row['type']; switch ($type){ case "Server": $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serial_number ,server.esc ,server.user ,server.prev_user ,server.warranty FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Asset ID:</td><td>"; $id = $row['id']; setcookie('id', $id); echo "$id</td></tr>"; echo "<tr<td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Company:</td><td>"; $company = $row['company']; setcookie('company', $company); echo "$company</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Location:</td><td>"; $location = $row['location']; setcookie('location', $location); echo "$location</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Date:</td><td>"; $purchase_date = $row['purchase_date']; setcookie('purchase_date', $purchase_date); echo "$purchase_date</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Order:</td><td>"; $purchase_order = $row['purchase_order']; setcookie('purchase_order', $purchase_order); echo "$purchase_order</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Value:</td><td>"; $value = $row['value']; setcookie('value', $value); echo "$value</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Type:</td><td>"; $type = $row['type']; setcookie('type', $type); echo "$type</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Notes:</td><td>"; $notes = $row['notes']; setcookie('notes', $notes); echo "$notes</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Manufacturer:</td><td>"; $manufacturer = $row['manufacturer']; setcookie('manufacturer', $manufacturer); echo "$manufacturer</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Model / Description:</td><td>"; $model = $row['model']; setcookie('model', $model); echo "$model</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Serial Number / Service Tag:</td><td>"; $serial_number = $row['serial_number']; setcookie('serial_number', $serial_number); echo "$serial_number</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Express Service Code:</td><td>"; $esc = $row['esc']; setcookie('esc', $esc); echo "$esc</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>User:</td><td>"; $user = $row['user']; setcookie('user', $user); echo "$user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Previous User:</td><td>"; $prev_user = $row['prev_user']; setcookie('prev_user', $prev_user); echo "$prev_user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Warranty:</td><td>"; $warranty = $row['warranty']; setcookie('warranty', $warranty); echo "$warranty</td></tr>"; } break; case "Laptop": $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,laptop.manufacturer ,laptop.model ,laptop.serial_number ,laptop.esc ,laptop.user ,laptop.prev_user ,laptop.warranty FROM asset LEFT JOIN laptop ON laptop.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Asset ID:</td><td>"; $id = $row['id']; setcookie('id', $id); echo "$id</td></tr>"; echo "<tr<td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Company:</td><td>"; $company = $row['company']; setcookie('company', $company); echo "$company</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Location:</td><td>"; $location = $row['location']; setcookie('location', $location); echo "$location</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Date:</td><td>"; $purchase_date = $row['purchase_date']; setcookie('purchase_date', $purchase_date); echo "$purchase_date</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Order:</td><td>"; $purchase_order = $row['purchase_order']; setcookie('purchase_order', $purchase_order); echo "$purchase_order</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Value:</td><td>"; $value = $row['value']; setcookie('value', $value); echo "$value</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Type:</td><td>"; $type = $row['type']; setcookie('type', $type); echo "$type</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Notes:</td><td>"; $notes = $row['notes']; setcookie('notes', $notes); echo "$notes</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Manufacturer:</td><td>"; $manufacturer = $row['manufacturer']; setcookie('manufacturer', $manufacturer); echo "$manufacturer</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Model / Description:</td><td>"; $model = $row['model']; setcookie('model', $model); echo "$model</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Serial Number / Service Tag:</td><td>"; $serial_number = $row['serial_number']; setcookie('serial_number', $serial_number); echo "$serial_number</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Express Service Code:</td><td>"; $esc = $row['esc']; setcookie('esc', $esc); echo "$esc</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>User:</td><td>"; $user = $row['user']; setcookie('user', $user); echo "$user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Previous User:</td><td>"; $prev_user = $row['prev_user']; setcookie('prev_user', $prev_user); echo "$prev_user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Warranty:</td><td>"; $warranty = $row['warranty']; setcookie('warranty', $warranty); echo "$warranty</td></tr>"; } break; case "Desktop": $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,desktop.manufacturer ,desktop.model ,desktop.serial_number ,desktop.esc ,desktop.user ,desktop.prev_user ,desktop.warranty FROM asset LEFT JOIN desktop ON desktop.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Asset ID:</td><td>"; $id = $row['id']; setcookie('id', $id); echo "$id</td></tr>"; echo "<tr<td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Company:</td><td>"; $company = $row['company']; setcookie('company', $company); echo "$company</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Location:</td><td>"; $location = $row['location']; setcookie('location', $location); echo "$location</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Date:</td><td>"; $purchase_date = $row['purchase_date']; setcookie('purchase_date', $purchase_date); echo "$purchase_date</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Order:</td><td>"; $purchase_order = $row['purchase_order']; setcookie('purchase_order', $purchase_order); echo "$purchase_order</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Value:</td><td>"; $value = $row['value']; setcookie('value', $value); echo "$value</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Type:</td><td>"; $type = $row['type']; setcookie('type', $type); echo "$type</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Notes:</td><td>"; $notes = $row['notes']; setcookie('notes', $notes); echo "$notes</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Manufacturer:</td><td>"; $manufacturer = $row['manufacturer']; setcookie('manufacturer', $manufacturer); echo "$manufacturer</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Model / Description:</td><td>"; $model = $row['model']; setcookie('model', $model); echo "$model</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Serial Number / Service Tag:</td><td>"; $serial_number = $row['serial_number']; setcookie('serial_number', $serial_number); echo "$serial_number</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Express Service Code:</td><td>"; $esc = $row['esc']; setcookie('esc', $esc); echo "$esc</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>User:</td><td>"; $user = $row['user']; setcookie('user', $user); echo "$user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Previous User:</td><td>"; $prev_user = $row['prev_user']; setcookie('prev_user', $prev_user); echo "$prev_user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Warranty:</td><td>"; $warranty = $row['warranty']; setcookie('warranty', $warranty); echo "$warranty</td></tr>"; } break; } ?> </table> <br /> <br /> <table width="100%" border="0"> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td><a href="#">Add Software</a></td> <td><a href="#">Edit Asset</a></td> <td><a href="#">Delete Asset</a></td> </tr> </table> </div> </div> </div> <div class="clear"></div> <div id="footer" align="center"> <p>&nbsp;</p> </div> </div> <div id="tagline"> Wagman Construction - Bridging Generations since 1902 </div> </body> </html>

    Read the article

  • Creating a Variable that is the Sum of Two Other Variables

    - by John
    Hello, For the code below, I would like to make a new variable called totalScore2 that equals days + totalScore. How can I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore

    Read the article

  • Basic join query understanding

    - by OM The Eternity
    I know this very silly, but can anybody help me in understanding what does this join query is doing in elabortive description? SELECT j1.* FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON (j1.trackid = j2.trackid AND j1.field = j2.field AND j1.changedone < j2.changedone) WHERE j1.operation = 'UPDATE' AND j1.trackid=$t_ids[$n] AND j2.id IS NULL I know its very silly, but i need to go ahead with my further need... Pls do help me...

    Read the article

  • Active User Tracking, PHP Sessions

    - by Nik
    Alright, I'm trying to work on a function for active user counting in an AJAX based application. I want to express the below SQL Query in correct syntax but I'm not sure how to write it. The desired SQL Query is below: SELECT count(*) FROM active WHERE timestamp > time() - 1800 AND nick=(a string that doesn't contain [AFK]) Now, I do understand that time() - 1800 can be assigned to a variable, but how is timestamp > variable and nick that doesn't contain a string written in SQL?

    Read the article

  • how to create a dynamic sql statement w/ python and mysqldb

    - by Elias Bachaalany
    I have the following code: def sql_exec(self, sql_stmt, args = tuple()): """ Executes an SQL statement and returns a cursor. An SQL exception might be raised on error @return: SQL cursor object """ cursor = self.conn.cursor() if self.__debug_sql: try: print "sql_exec: " % (sql_stmt % args) except: print "sql_exec: " % sql_stmt cursor.execute(sql_stmt, args) return cursor def test(self, limit = 0): result = sql_exec(""" SELECT * FROM table """ + ("LIMIT %s" if limit else ""), (limit, )) while True: row = result.fetchone() if not row: break print row result.close() How can I nicely write test() so it works with or without 'limit' without having to write two queries?

    Read the article

  • Is it possible to LIMIT results from a JOIN query?

    - by Arms
    I've got a query that currently queries a Post table while LEFT JOINing a Comment table. It fetches all Posts and their respective Comments. However, I want to limit the number of Comments returned. I tried adding a sub-select, but ran into errors if I didn't LIMIT the results to 1. I'm really not sure how to go about this while still using only one query. Is this possible?

    Read the article

  • Wordpress - Total User Count who only have posts

    - by knightrider
    I want to display total number of user who only have posts at Wordpress. I can get all users by this query <?php $user_count = $wpdb->get_var("SELECT COUNT(*) FROM $wpdb->users;"); echo $user_count ?> But for the user count only with posts, i think i might need to join another table, does anyone have snippets ? Thanks.

    Read the article

  • VBA How to find last insert id?

    - by Muiter
    I have this code: With shtControleblad Dim strsql_basis As String strsql_basis = "INSERT INTO is_calculatie (offerte_id) VALUES ('" & Sheets("controleblad").Range("D1").Value & "')" rs.Open strsql_basis, oConn, adOpenDynamic, adLockOptimistic Dim last_id As String last_id = "select last_insert_id()" End With The string last_id is not filled. What is wrong? I need to find te last_insert_id so I can use it in an other query.

    Read the article

  • Unknown column even thoug it exits

    - by george
    I have SELECT servisler.geo_location, servisler.ADRES_MERKEZ, servisler.ADRES_ILCE, servisler.ADRES_IL, servisler.FIRMA_UNVANI, servisler.ADRES_ISTEL, servisler.YETKILI_ADISOYADI, urun_gruplari.GRUP_ADI FROM servisler INNER JOIN urun_gruplari ON kullanici_cihaz.URUN_GRUP_NO= urun_gruplari.RECNO INNER JOIN kullanici ON kullanici.SERVIS_RECNO = servisler.RECNO INNER JOIN kullanici_cihaz ON kullanici.RECNO = kullanici_cihaz.KUL_RECNO AND kullanici_cihaz.URUN_GRUP_NO = urun_gruplari.RECNO where kullanici.kullanici = 'MAR.EDI.003' but it says [Err] 1054 - Unknown column 'kullanici_cihaz.URUN_GRUP_NO' in 'on clause' enen though the column exits. What is its problem? schema Server version: 5.1.33-community-log

    Read the article

  • PHP PDO - Num Rows

    - by Ian
    PDO apparently has no means to count the number of rows returned from a select query (mysqli has the num_rows variable). Is there a way to do this, short of using count($results->fetchAll()) ?

    Read the article

  • How do I use Django to insert a Geometry Field into the database?

    - by alex
    class LocationLog(models.Model): user = models.ForeignKey(User) utm = models.GeometryField(spatial_index=True) This is my database model. I would like to insert a row. I want to insert a circle at point -55, 333. With a radius of 10. How can I put this circle into the geometry field? Of course, then I would want to check which circles overlap a given circle. (my select statement)

    Read the article

  • What's wrong with this SQL query?

    - by ThinkingInBits
    I have two tables: photographs, and photograph_tags. Photograph_tags contains a column called photograph_id (id in photographs). You can have many tags for one photograph. I have a photograph row related to three tags: boy, stream, and water. However, running the following query returns 0 rows SELECT p.* FROM photographs p, photograph_tags c WHERE c.photograph_id = p.id AND (c.value IN ('dog', 'water', 'stream')) GROUP BY p.id HAVING COUNT( p.id )=3 Is something wrong with this query?

    Read the article

  • update myqsl table

    - by Simon
    how can i write the query, to update the table videos, and set the value of field name to 'something' where the average is max(), or UPDATE the table, where average has the second value by size!!! i think the query must look like this!!! UPDATE videos SET name = 'something' WHERE average IN (SELECT `average` FROM `videos` ORDER BY `average` DESC LIMIT 1) but it doesn't work!!!

    Read the article

  • SQL join produces one result only

    - by Rami
    Can anyone please tell me why this result is generation only one results? taking in mind that everything is set right and the three tables are populated correctly, i took out the group_concat and it worked but of course with a php undefined index error! SELECT `songs`.`song_name`, `songs`.`add_date`, `songs`.`song_id`, `songs`.`song_picture`, group_concat(DISTINCT artists.artist_name) as artist_name FROM (`songs`) JOIN `mtm_songs_artists` ON `songs`.`song_id` = `mtm_songs_artists`.`song_id` JOIN `artists` ON `artists`.`artist_id` = `mtm_songs_artists`.`artist_id` ORDER BY `songs`.`song_id` DESC LIMIT 10 so i'm guessing it's something related to group_concat. best regards, Rami

    Read the article

< Previous Page | 409 410 411 412 413 414 415 416 417 418 419 420  | Next Page >