Search Results

Search found 7813 results on 313 pages for 'color'.

Page 42/313 | < Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >

  • change color of red box on tri-state checkbox

    - by Adam S
    Hi all. I'm trying to get the green box that appears on the second click of a tri-state checkbox to be red, and also to fill up the box. I found an article here that demonstrates a little bit about using templates to do this: http://social.msdn.microsoft.com/Forums/en-US/wpf/thread/98cf8a65-f4ca-4ff5-9851-c2989b91a013 However, I can't figure out how to interpret all that. I only understand a few of the things in that template and don't know how to get my red box. Can anyone help, and also tell me how you knew what to do?

    Read the article

  • Background color of the main content on the html page disappears

    - by Denis
    It just makes me go mad. I can't realize what the problem is. Please have a look at the pixeli.ca/glass. There is a home page that looks good - white background of the main content and looks good. But all the other pages don't have white background so they look not the way they should look. All the pages have the same style sheet and the same layout elements taken from 960.gs framework. It's just some kind of mystery there. What I need is to make all page look like the home page - having white background. Thanks.

    Read the article

  • MATLAB: Need to make a 4D plot (3D + Colour/Color)

    - by user1305624
    I need to make a 3D surface where colour will represent the fourth variable. I know "surf" is SIMILAR to what I need, but that's not quite it. Basically, I have the following variables: t = [1:m] y = [1:n] a = [1:o] These should be the three Cartesian corodinate axes. I also have a variable S that is of dimensions m x n x o, and is basically the amplitude, a function of the previous three variables (i.e. S = f(t,y,a)). I want this to be represented by colour. So to summarize, I need a graph of the form (t,y,a,S), where the first three variables are vectors of unequal sizes and the final variable is a multidimensional array whose dimensions are determined by the first three. Thanks in advance.

    Read the article

  • Get color output in bash

    - by Werner
    Hi, when compiling some projects on linux terminal, I get usually a long output consisting of a lot of information. Usually this information is MONOCHROME. I wonder if bash can be modified somehow, so in all outputs or in some specific outputs (like from Makefile, etc) I can get different colors dependeing on, for instance: make[1]: Leaving directory or g++ -DHAVE_CONFIG_H -I. etc. Thanks

    Read the article

  • [Android] Show default selection color for custom listview

    - by Diego
    Hello, I have a listview with a custom BaseAdapter. Each row of the listview has a TextView and a CheckBox. The problem is when I click (or touch) any row, the textview foreground becomes gray, instead of the default behavior (background - green, textview foreground - white). Here is the code: row.xml: <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" style="@style/layout"> <TextView android:id="@+id/main_lv_item_textView" style="@style/textViewBig" android:layout_alignParentLeft="true"/> <CheckBox android:id="@+id/main_lv_item_checkBox" style="@style/checkBox" android:layout_width="wrap_content" android:layout_alignParentRight="true"/> </RelativeLayout> Custom Adapter: public class CustomAdapter extends BaseAdapter { private List<Profile> profiles; private LayoutInflater inflater; private TextView tvName; private CheckBox cbEnabled; public CustomAdapter(List<Profile> profiles) { this.profiles = profiles; inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); } public int getCount() { return profiles.size(); } public Object getItem(int position) { return profiles.get(position); } public long getItemId(int position) { return position; } public View getView(final int position, View convertView, ViewGroup parent) { View row = inflater.inflate(R.layout.main_lv_item, null); final Profile profile = profiles.get(position); tvName = (TextView) row.findViewById(R.id.main_lv_item_textView); registerForContextMenu(tvName); cbEnabled = (CheckBox) row.findViewById(R.id.main_lv_item_checkBox); tvName.setText(profile.getName()); if (profile.isEnabled()) { cbEnabled.setChecked(true); } tvName.setOnClickListener(new OnClickListener() { public void onClick(View v) { Bundle bundle = new Bundle(); bundle.putString(PROFILE_NAME_KEY, profile.getName()); Intent intent = new Intent(context, GuiProfile.class); intent.putExtras(bundle); startActivity(intent); } }); tvName.setOnLongClickListener(new OnLongClickListener() { public boolean onLongClick(View v) { selectedProfileName = ((TextView) v).getText().toString(); return false; } }); cbEnabled.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() { public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) { if (!profile.isEnabled()) { for (Profile profile : profiles) { if (profile.isEnabled()) { profile.setEnabled(false); Database.getInstance().storeProfile(profile); } } } profile.setEnabled(isChecked); Database.getInstance().storeProfile(profile); updateListView(); } }); return row; } } Any help would be appreciated.

    Read the article

  • Number range for color in GLSL

    - by kotoko
    I'm figuring out how to set a colour in a Fragment Shader. This statement gl_FragColor = (0.1,0.6,1,1); gives me white regardless of what I enter in the first 3 values. I was expecting to either give it values between 0 and 255 or 0 and 1 but neither seems to work. I can change how bright it is with values from 0 to 1 in the fourth value, but nothing for colour. Can anybody tell me if: gl_FragColor is the right variable to set. What is the range of values for the first three values. What am I currently making the Shader do.

    Read the article

  • Changing UI color in Eclipse

    - by Lo'oris
    I'm aware of this topic: I've used it to change most of the editor colors, and that's great. But that wasn't enought, there's still too much white (and I need to change it because it hurts my eyes). I've searched in the preferences (both using Eclipse itself and editing the files) for instances of while (255,255,255) and changed them all. Looks like I'm missing something. too much white in the UI: http://www.imagebanana.com/view/gy89qf7/eclipse_too_much_white_1.png totally white in this screen: http://www.imagebanana.com/view/j8282wf/eclipse_too_much_white_2.png

    Read the article

  • get iphone window background color

    - by Jonathan
    I've been looking at the Stanford University iphone videos on iTunes U. And saw the teacher trying to do something similar to this code but he realised and said it didn't work though I didn't get why: - (IBAction)flashPressed{ if (window.backgroundColor == [UIColor magentaColor]){ window.backgroundColor = [UIColor redColor]; }else { window.backgroundColor = [UIColor magentaColor]; } } Objective-C, windows based application. Not sure what else you need to know.

    Read the article

  • interesting vba/access question: color rectangles according to data

    - by every_answer_gets_a_point
    i have a datasheet that looks like this: ID name_ 1 2 3 4 1 name1 x 0 0 0 2 name2 0 x 0 0 3 name3 0 0 x 0 4 name4 0 0 0 x i have rectangles on a report that correspond to this datasheet. when the report opens, i need the rectangles to be colored RED according to the data. for example where name1 and there is an x in the 1 column, i need the specific rectangle corresponding to this (name1, 1) to be colored red. here is the result that i will need: x x x x (where x is a rectangle that is RED) perhaps the best place to place this code would be in ON LOAD event of the report, but i am not sure exactly. can you please suggest to me some code that would turn the specified rectangles RED according to the data?

    Read the article

  • Setting a DataGrid background color based on the previous row

    - by Zipper
    I'm trying to setup a grid where I do column sorting, but I wanted to do zebra striping, only rather than every other row or every x rows, I want it to be based on the value of cells. i.e. All cells that contain 0 have a blue background, the next value would have a white background, the next value would be blue, etc.... The problem I have is that I can't seem to find where to actually do the setting of the background colors. I'm using a custom sorter and I tried setting it in there after I re-order the list and set the data source, but it appears that when the data source is set, that the rows don't exist yet. I tried using the DataContextChanged, but that event doesn't seem to be firing. Here is what I have now. namespace Foo.Bar { public partial class FooBar { List<Bla> ResultList { get; set; } SolidColorBrush stripeOneColor = new SolidColorBrush(Colors.Gold); SolidColorBrush stripeTwoColor = new SolidColorBrush(Colors.White); //********************************************************************************************* public Consistency() { InitializeComponent(); } //********************************************************************************************* override protected void PopulateTabWithData() { ResultList = GetBlas(); SortAndGroup("Source"); } //********************************************************************************************* private void SortAndGroup(string colName) { IOrderedEnumerable <Bla> ordered = null; switch (colName) { case "Source": case "ID": ordered = ResultList.OrderBy(r => r.Source).ThenBy(r => r.ID); break; case "Name": ordered = ResultList.OrderBy(r => r.Source).ThenBy(r => r.Name); break; case "Message": ordered = ResultList.OrderBy(r => r.Message); break; default: throw new Exception(colName); } ResultList = ordered.ThenBy(r => r.Source).ThenBy(r => r.ID).ToList(); // tie-breakers consistencyDataGrid.ItemsSource = null; consistencyDataGrid.ItemsSource = ResultList; ColorRows(); } //********************************************************************************************* private void consistencyDataGrid_Sorting(object sender, System.Windows.Controls.DataGridSortingEventArgs e) { SortAndGroup(e.Column.Header.ToString()); e.Handled = true; } private void ColorRows() { for (var i = 0; i < ResultList.Count; i++) { var currentItem = ResultList[i]; var row = myDataGrid.ItemContainerGenerator.ContainerFromItem(currentItem) as DataGridRow; if (row == null) { continue; } if (i > 0) { var previousItem = ResultList[i - 1]; var previousRow = myDataGrid.ItemContainerGenerator.ContainerFromItem(previousItem) as DataGridRow; if (currentItem.Source == previousItem.Source) { row.Background = previousRow.Background; } else { if (previousRow.Background == stripeOneColor) { row.Background = stripeTwoColor; } else { row.Background = stripeOneColor; } } } else { row.Background = stripeOneColor; } } } } } }

    Read the article

  • How to add Transparency information to a HEX color code?

    - by TK123
    I have to modify some code and the previous developer left this comment: color: color, // e.g. '#RRGGBBFF' - Last 2 digits are alpha information On the page there is a color picker that let's the user change text color. It gives HEX values like so: #RRGGBB And there is a slider that allows the user to change a text's transparency. It runs from 0.1 to 1 Somehow I need to get a 2 digit letter from this transparency amount and append it to the HEX value for it to work. Does anyone know how to append Alpga information to HEX color codes? What is the math formula for it? I guess the question can also be answered if anyone knows how to concert RGBA color values with transparency into HEX: rgba(255, 255, 255, 0.6)

    Read the article

  • Float right is making background-color disappear in IE while hovering.

    - by janoChen
    Everything works OK in this language menu: http://alexchen.co.nr/beta (top right of the page). But I want the li elements to float to the right. But when I add float:right to #lang li a the background-color stop working while hovering when I hover them in IE7. #lang { float: right; padding: 50px 25px 0 0px; margin: 0 0 0 0px; width: 295px; } #lang li { font-size: 10px; width: 325px; /*ie hack */ } #lang li a { color: #FFF; padding: 5px 25px 5px 249px; line-height: 220%; } #lang li a:hover { color: #444; background-color: #FFF; } #lang li.current a { color: #444; background-color: #FFF; cursor: default; }

    Read the article

  • How to use vim's syntax files in emacs to color the text

    - by Vijayender
    Are there any snippets to make emacs use the .vim syntax files found in /usr/share/vim/vimfiles/ for coloring text. Many applications like conky have the vim syntax files like "conkyrc.vim" for vim but not for emacs. So is there an easy way to use those files rather than rewriting a new language-mode for each of those available in vimfiles directory.

    Read the article

  • Color banding only on Android 4.0+

    - by threeshinyapples
    On emulators running Android 4.0 or 4.0.3, I am seeing horrible colour banding which I can't seem to get rid of. On every other Android version I have tested, gradients look smooth. I have a SurfaceView which is configured as RGBX_8888, and the banding is not present in the rendered canvas. If I manually dither the image by overlaying a noise pattern at the end of rendering I can make the gradients smooth again, though obviously at a cost to performance which I'd rather avoid. So the banding is being introduced later. I can only assume that, on 4.0+, my SurfaceView is being quantized to a lower bit-depth at some point between it being drawn and being displayed, and I can see from a screen capture that gradients are stepping 8 values at a time in each channel, suggesting a quantization to 555 (not 565). I added the following to my Activity onCreate function, but it made no difference. getWindow().setFormat(PixelFormat.RGBA_8888); getWindow().addFlags(WindowManager.LayoutParams.FLAG_DITHER); I also tried putting the above in onAttachedToWindow() instead, but there was still no change. (I believe that RGBA_8888 is the default window format anyway for 2.2 and above, so it's little surprise that explicitly setting that format has no effect on 4.0+.) Which leaves the question, if the source is 8888 and the destination is 8888, what is introducing the quantization/banding and why does it only appear on 4.0+? Very puzzling. I wonder if anyone can shed some light?

    Read the article

  • jQuery slider - set background color to show desired range

    - by David
    Howdy, I'm setting up a Filament Group jQuery UI slider and using it in a gradebook. We need to allow teachers to set a desired background range (to show the desirable values vs. the actual value for a given grade). I'm hoping to set a shaded area (as shown in this picture) that would indicate to people viewing the slider which values are desirable. If the handle is within the desired ranges, then the value is satisfactory. If the handle is out of the background shaded range, then some changes may need to happen. Any suggestions on how to accomplish this? Based on what I've experimented with using Firebug, it looks like a <div class="ui-slider"> is setup, but the values inside of it don't seem to allow setting background-colors (only the div allows for that). Thanks for your help.

    Read the article

  • Change row table color with javaScript

    - by Slim Mils
    I try to change the background of rows in my table with javaScript but it's not working. This is my code. However I tried to create my table with html and it's work. P.S : I want to use webkit. Help please. Code : var table = document.getElementById("tab"); var rowCount = table.rows.length; for(var i=0;i<6;i++) { row = table.insertRow(rowCount); row.id = "row"+i; cell1 = row.insertCell(0); var content = document.createElement("output"); content.innerHTML = i ; cell1.appendChild(content); rowCount++; } $(document).ready(function(){ $('td').each(function(i) { $('#tab').on('click', '#row'+i, function(){ document.getElementById("row"+i).style.background = 'white'; //alert(i); }); }); //example2 $('#td1').on('click', function(){ document.getElementById("td1").style.background = 'white'; }); });

    Read the article

< Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >