Search Results

Search found 68301 results on 2733 pages for 'file shredding'.

Page 42/2733 | < Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >

• Read multiple strings from a file C++

  - by user69514

  Hi I need to read different values stored in a file one by one. So I was thinking I can use ifstream to open the file, but since the file is set up in such a way that a line might contain three numbers, and the other line one number or two numbers I'm not sure how to read each number one by one. I was thinking of using stringstream but I'm not sure if that would work. The file is a format like this. 52500.00 64029.50 56000.00 65500.00 53780.00 77300.00 44000.50 80100.20 90000.00 41000.00 60500.50 72000.00 I need to read each number and store it in a vector. What is the best way to accomplish this? Reading one number at a time even though each line contains a different amount of numbers?

  Read the article

• searching within a compressed sorted fixed width file

  - by user275455

  Assume I have a regular compressed fixed width file that is sorted on one of the fields. Given that I know the length of the records, I can use lseek to implement a binary search to records with fields that match a given value without having to read the entire file. Now the difficulty is that the file is gzipped. Is it possible to do this without completely inflating the file? If not with gzip. is there any compression that supports this kind of behavior?

  Read the article

• Loading data from file to Vector structure

  - by owca

  I'm trying to parse through fixed-width formatted file extracting x,y values of points from it, and then storing them in int[] array inside a Vector. Text file looks as follows : 0006 0015 0125 0047 0250 0131 That's the code : Vector<int[]> vc = new Vector<int[]>(); try { BufferedReader file = new BufferedReader(new FileReader("myfile.txt")); String s; int[] vec = new int[2]; while ((s = file.readLine()) != null) { vec[0] = Integer.parseInt(s.substring(0, 4).trim()); vec[1] = Integer.parseInt(s.substring(5, 8).trim()); vc.add(vec); } file.close(); } catch (IOException e) { } for(int i=0; i<vc.size(); i++){ for(int j=0; j<2; j++){ System.out.println(vc.elementAt(i)[j]); } } But the output shows only last line. 250 131 250 131 250 131 Should I somehow use Vector.nextElement() here to get all my data ?

  Read the article

• Read Text File line by line using Command Prompt/Batch

  - by user353305

  Hello All, First of all I am very thankful to the owner of this website. I have learned and implement various technologies with the help of solutions provided by the readers. I know the question I asked is posted many time in this forum. And I have tired all of the solutions available, but no luck I may case I am trying to read a dat file which is basically a msg/feed file having more than 22000 Characters. Every line may or may not be of same length. My requirement is to convert the file to fixed line length character file. I have a logic that work well using vb script, however its pretty slow. I have checked with For f/ but no luck. The only delimiter I have is EOT, which i can see in Textpad but not in notepad. I have tried with \n, token=. Please help me in resolving the issue. Regards, Rajiv [email protected]

  Read the article

• Ajax(jQuery) strange file post problem

  - by faya

  Hello, I have a problem posting file via ajax jQuery function. I have something like this: $('#my_form').submit(function() { var serialized = $(this).formSerialize(); var sUrl = "xxx"; $.ajax({ url: sUrl, type: "POST", data: serialized, success: function(data) { $(".main_container").html(data); } }) return false; // THIS return statment blocks sending file content }); When I remove return false statement everything is okey, server side gets the file content and etc, but when it's there (i monitor with firebug) that this posting sends only file name. What can be wrong? P.S. - I need this return false statement, because I want to manipulate return data myself.

  Read the article

• Import small number of records from a very large CSV file in Biztalk 2006

  - by rwmnau

  I have a Biztalk project that imports an incoming CSV file and dumps it to a database table. The import works fine, but I only need to keep about 200-300 records from a file with upwards of a million rows. My orchestration discards these rows, but the problem is that the flat file I'm importing is still 250MB, and when converted to XML using a regular flat file pipeline, it takes hours to process and sometimes causes the server to run out memory. Is there something I can do to have the Custom Pipeline itself discard rows I don't care about? The very first item in each CSV row is one of a few strings, and I only want to keep rows that start with a certain string. Thanks for any help you're able to provide.

  Read the article

• Java Save Object to File

  - by Kristian Matthews

  I've tried implementing various methods from around the internet, all seem to be providing the same solution. But it just won't work and I'm unsure why, it creates the file, however, it's blank and if I try loading that file, it has an error. Main.java contains the code to save and load the file: 190-224. Rooms.java contains the object. Code Any help is greatly appreciated, I've been trying for almost a week now! Thanks in advanced!

  Read the article

• Unzip .zip file uploaded from Android via PHP to IIS 7

  - by HaOx

  I'm sending compressed file in .zip extension from Android via PHP to IIS server. Almost is working everything, but I cannot achieve unzip files with php. I've this code: <?php $target_path1 = "C:/Windows/Temp/"; $target_path1 = $target_path1 . basename( $_FILES['uploaded_file']['name']); /* I'm making the folder */ $directorio = substr($target_path1, 0, 32); if (!is_dir($directorio)) { mkdir($directorio); } /* I declare a path */ $barra = "/"; $target_path1 = $directorio . $barra . basename( $_FILES['uploaded_file']['name']); $target_path2 = $directorio . $barra; if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path1)) { /* Here I want to unzip the uploaded file */ } else{ echo "There was an error uploading the file, please try again!"; echo "filename: " . basename( $_FILES['uploaded_file']['name']); echo "target_path: " .$target_path1; } ?> So, how can I unzip uploaded file? I tried so many methods but no one worked. I'd be appreciated if someone could tell what I have to do to unzip the uploaded file. And if I have to configure some parameters in php.ini or IIS server. Thanks in advance.

  Read the article

• What is the best file format to parse?

  - by anxiety

  Scenario: I'm working on a rails app that will take data entry in the form of uploaded text-based files. I need to parse these files before importing the data. I can choose the file type uploaded to the app; the software used by those uploading has several export options regarding file type. While it may be insignificant, I was wondering if there is a specific file type that is most efficiently parsed. This question can be viewed as language-independent, I believe. (While XML is commonly parsed, it is not a feasible file type for sake of this project.)

  Read the article

• RAKE won'tt create xml file

  - by user296507

  hi, i'm a bit lost here as to why my RAKE task will not create the desired XML file, however it works fine when i have the method 'build_xml' in the .RB file. require 'rubygems' require 'nokogiri' require 'open-uri' namespace :xml do desc "xml build test" task :xml_build => :environment do build_xml end end def build_xml #build xml docoument builder = Nokogiri::XML::Builder.new do |xml| xml.root { xml.location { xml.value "test" } } end File.open("test.xml", 'w') {|f| f.write(builder.to_xml) } end

  Read the article

• Read txt file using Javascript

  - by piemesons

  I am taking a text file from user and then posting that file back to the browser using ajax storing the content in db and then showing the content back to user page using Jquery post response. Now i want to something like this.. Read the text file from the user computer using javascript. Display the content and when he submits the page I will save the values.

  Read the article

• parsing urls from windows batch file

  - by modest

  I have a text file (myurls.txt) whose contents are a list of URLs as follow: Slides_1: http://linux.koolsolutions.com/svn/ProjectA/tags/REL-1.0 Exercise_1: http://linux.koolsolutions.com/svn/ProjectA/tags/REL-1.0 Slides_2: http://linux.koolsolutions.com/svn/oldproject/ProjectB/tags/REL-2.0 Exercise_2: http://linux.koolsolutions.com/svn/ProjectB/tags/REL-1.0 Exercise_3: http://linux.koolsolutions.com/svn/BlueBook/ProjectA/tags/REL-1.0 Now I want to parse this text file in a for loop such that after each iteration (for e.g. take the first url from the above file) I have the following information into different variables: %i% = REL-1.0 %j% = http://linux.koolsolutions.com/svn/ProjectA %k% = http://linux.koolsolutions.com/svn/ProjectA/tags/REL-1.0 After some experiment I have the following code but it only works (kind of) if the URLs have same number of slashes: @echo off set FILE=myurls.txt FOR /F "tokens=2-9 delims=/ " %%i in (%FILE%) do ( @REM <do something with variables i, j and k.> ) I am fine with other solutions like for e.g. using Windows Script Host/VBS script as long as it can run with a default Windows XP/7 installation. In other words, I know I can use awk, grep, sed, python, etc. for Windows and get the job done but I don't want the users to have to install anything besides a standard windows installation.

  Read the article

• How to insert / retrieve a file stored as a BLOB in a MySQL db using python

  - by Phage

  I want to write a python script that populates a database with some information. One of the columns in my table is a BLOB that I would like to save a file to for each entry. How can I read the file (binary) and insert it into the DB using python? Likewise, how can I retrieve it and write that file back to some arbitrary location on the hard drive?

  Read the article

• I want to know when a file is down downloading

  - by paulj3000

  Hi, I have a file which I want users to download only once. After it's done downloading, the file is no longer available. Outside of setting up a streaming system, is there any way I can set some sort of callback up to say the file is done downloading on the client's computer? Thanks

  Read the article

• php - efficent way to get and remove first line in file

  - by Marco Demaio

  Hello, I have a script that each time is called gets the 1st line of a file. Each line is known to be exactly of the same length (32 alphanumerci chars) and terminates with a "\r\n". After getting the 1st line, the script removes it. Now I do in this way: $contents = file_get_contents($file)); $first_line = substr($contents, 0, 32); file_put_contents($file, substr($contents, 32 + 2)); //+2 because we remove also the \r\n Obvioulsy it works, but I was wondering if there could be a smarter (or more efficent) way to do this??? In my simple solution I basically read and rewrite all the file just to take and remove the 1st line. Thanks!

  Read the article

• Need to copy remotely hosted file via Shell Command

  - by pnm123

  There is a file that hosted remotely on a server that is not supporting Shell Access. I bought a new server that supports Shell Access so now I want to copy a file that is on the non-supporting server to new server via a Shell Command using Putty. File url is like this http://www.domain.com/file.gzip and it is username/password protected. To be more specific, I want to copy a backup of a home directory from cPanel to my new server via Shell command. I have done this few months ago but I don't remember it now and also I failed to Google it.

  Read the article

• Uploading File Problem in PHP on Drupal

  - by Nitz

  I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

  Read the article

• Most Efficient Way to Write to Fixed Width File (Ruby)

  - by Ruby Novice

  I'm currently working with extremely large fixed width files, sometimes well over a million lines. I have written a method that can write over the files based on a set of parameters, but I think there has to be a more efficient way to accomplish this. The current code I'm using is: def self.writefiles(file_name, positions, update_value) @file_name = file_name @positions = positions.to_i @update_value = update_value line_number = 0 @file_contents = File.open(@file_name, 'r').readlines while line_number < @file_contents.length @read_file_contents = @file_contents[line_number] @read_file_contents[@positions] = @update_value @file_contents[line_number] = @read_file_contents line_number += 1 end write_over_file = File.new(@file_name, 'w') line_number = 0 while line_number < @file_contents.length write_over_file.write @file_contents[line_number] line_number += 1 end write_over_file.close end For example, if position 25 in the file indicated that it is an original file the value would be set to "O" and if I wanted to replace that value I would use ClassName.writefiles(filename, 140, "X") to change this position on each line. Any help on making this method more efficient would be greatly appreciated! Thanks

  Read the article

• File upload-download in its actual format.

  - by ras

  hi, I've to make a code to upload/download a file on remote machine. But when i upload the file new line is not saved as well as it automatically inserts some binary characters. Also I'm not able to save the file in its actual format, I've to save it as "filename.ser". I'm using serialization-deserialization concept of java. Thanks in advance.

  Read the article

• SHFileOperation replace file dialog

  - by JHowzer

  Currently, SHFileOperation has some confirm file replacement dialog boxes that ask the user if they would like to replace a file or not. I find these useful, but I would like to be able to modify the scenario in which they occur. Instead, I would like to compare the file contents first with a bool compareFile() function I wrote. Then, if the files are identical the file replacement dialog box will not come up. Assuming, I already have a working compareFile() function, is there a way for me to do this? Thank you for your time.

  Read the article

• Reading a large text file to memory in C++

  - by NoneType

  Is there a way to read a large text file (~60MB) into memory at once (like a compiler flag to increase program memory limit) ? Currently, ofstream's open function throws a segmentation fault while trying to read this file. ifstream fis; fis.open("my_large_file.txt"); // Segfaults here The file just consists of rows of the form number_1<tabspace>number_2 i.e., two numbers separated by a tabspace.

  Read the article

• Batch file to perform a looped search based on the line items of a text file.

  - by Tulga

  I have been reading great posts in this forum and got close to what I want to do but couldn't figure out the exact code. I want to create a windows batch file to do following: Perform a looped search for each line item of a text file (this is a list of keyword) to locate files in a a specific directory For this search partial match is okay. Each time a file is found, move it to a predefined directory (e.g. C:\temp\search_results) Thanks.

  Read the article

• How to Generate the .Form file using .java file in swings

  - by vamshikpd

  Hi all, I am using SunJavaStudio Enterprise 8 and Swing frame work In swing, In My source folder, I have Demo.java and Demo.form file. Demo.form file is the Design file. If both files in the Source folder,java file shows source and design view in IDE. If I delete the Demo.form in source folder,The Design view doesn't show. I have only Demo.java file,How can i generate the Demo.form ? please can u help me urgent

  Read the article

• Python text file processing speed issues

  - by Anonymouslemming

  Hi all, I'm having a problem with processing a largeish file in Python. All I'm doing is f = gzip.open(pathToLog, 'r') for line in f: counter = counter + 1 if (counter % 1000000 == 0): print counter f.close This takes around 10m25s just to open the file, read the lines and increment this counter. In perl, dealing with the same file and doing quite a bit more (some regular expression stuff), the whole process takes around 1m17s. Perl Code: open(LOG, "/bin/zcat $logfile |") or die "Cannot read $logfile: $!\n"; while (<LOG>) { if (m/.*\[svc-\w+\].*login result: Successful\.$/) { $_ =~ s/some regex here/$1,$2,$3,$4/; push @an_array, $_ } } close LOG; Can anyone advise what I can do to make the Python solution run at a similar speed to the Perl solution? I've tried just uncompressing the file and dealing with it using open instead of gzip.open, but that made a very small difference to the overall time.

  Read the article

• File mode for creating+reading+appending+binary

  - by MihaiD

  I need to open a file for reading and writing. If the file is not found, it should be created. It should also be treated as a binary for Windows. Can you tell me the file mode sequence I need to use for this? I tried 'r+ab' but that doesn't create the files if they are not found. Thanks

  Read the article

< Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >