Search Results

Search found 1874 results on 75 pages for 'jim lastname'.

Page 42/75 | < Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >

  • passport-linkedin-oauth2 not returning email address

    - by biborno
    here is my console.log(profile); { provider: 'linkedin', id: 'LJitOAshpU', displayName: 'Monist BD', name: { familyName: 'BD', givenName: 'Monist' }, emails: [ { value: undefined } ], _raw: '{\n "firstName": "Monist",\n "formattedName": "Monist BD",\n "id": " LJitOAshpU",\n "lastName": "BD"\n}', _json: { firstName: 'Monist', formattedName: 'Monist BD', id: 'LJitOAshpU', lastName: 'BD' } } here is my routing code: app.get('/auth/linkedin',passport.authenticate('linkedin', { scope: ['r_emailaddress', 'r_basicprofile', 'rw_nus'],state: 'DCEEFWF45453sdffef424' })); app.get('/auth/linkedin/callback',passport.authenticate('linkedin', { failureRedirect: '/' }),users.authCallback); here is passport.js config: passport.use(new LinkedInStrategy({ clientID: config.linkedIn.clientID, clientSecret: config.linkedIn.clientSecret, callbackURL: config.linkedIn.callbackURL, profileFields: ['id', 'first-name', 'last-name', 'email-address','public-profile-url'], passReqToCallback: true }, function(req,token, refreshToken, profile, done) { console.log(profile); })); why i m getting undefined in email values? :( it worked when i used passport-linkedin

    Read the article

  • C# Object Creation from Datatable

    - by Jonesy
    Hi Folks, Im just getting my head round C#. I've been creating classes and objects so say i created a class called Member: public class Member { public int MemberID; public string FirstName; public string LastName; public string UserName; } and i create a new object of that class by doing this: Member Billy = new Member(); Billy.UserName = "Jonesy"; Billy.FirstName = "Billy"; Billy.LastName = "Jones"; Thats all fine but what if I've queried a database and gotten back 5 members, can I create objects on the fly? Or what is the best way to store these members in memory? I've used VB.Net where I would just add them into a datatable. But I've never really done any object-oriented programming before and thought since I'm learning C sharp nows the best time to learn OOP.. Any help most appreciated! Jonesy

    Read the article

  • Adding lengths of strings together in Ruby

    - by ppreyer
    I'm trying to write a program that takes the length of my first, middle, and last names individually and then adds the total amount of letters up in the end. My answer keeps on being 666 instead of 18. Here is the code I have written: puts 'What is your first name?' firstName = gets.chomp realFirstName = firstName.length.to_i puts 'What is your middle name?' middleName = gets.chomp realMiddleName = middleName.length.to_i puts 'What is your last name?' lastName = gets.chomp realLastName = lastName.length.to_i puts 'Did you know there are ' + realFirstName.to_s + realMiddleName.to_s + realLastName.to_s + ' letters in your name?' Just wondering where I went wrong.

    Read the article

  • Access Database using do.cmd openform where clasue - returning all values

    - by primus285
    DoCmd.OpenForm "Database Search", acFormDS, , srcLastName & "AND " & srcFirstName This is only a small sample of the where clause - there are many more terms. First, there is a set of If, Then type tings up top that set the variable srcLastName and srcFirstName to some value. These are not the problem and work just fine. The trouble is getting them to return all values (for instance if you only want to search by one, on neither(return full database list)) Thus far I have settled for (in the if then section): srcLastName = "[Lastname] =" & Chr(34) & cboLastName & Chr(34) - to search for something and srcLastName = "[Lastname] <" & Chr(34) & "Nuthin" & Chr(34) - to return everything (not equal to an absurd and mispelled database term.) The trouble is that data that is null is also not returned. If I have a null firstname, it will not show up in any search period. is there a term I can set [lastname] and [firstname] equal to that will return EVERYTHING (null, open, data, numbers, wierd stuff and otherwise) in a search an SQL form of "give me everything shes got scotty" if you will. the real issue here comes from the data entry - if I could just know that the people would enter everything 100% of the time, this code would work. but forget to enter the persons age or whatever, and it wont return that entry. So far, the only other solution I have come up with is to put a counter in each if then statement. The count will go up by one for each thing that is being searched by. Then if the count is = 1, then I can search by something like just DoCmd.OpenForm "Database Search", acFormDS, , srcLastName or DoCmd.OpenForm "Database Search", acFormDS, , srcFirstName then revert back to the DoCmd.OpenForm "Database Search", acFormDS, , srcLastName & "AND " & srcFirstName when the count is 2 or more truoble here is that it only works for one (unless I so wanted to create a custon list of 2 combined, 3 combined, 4 combined, but that is not happening)

    Read the article

  • SQL Query that can return intersecting data

    - by Alex
    I have a hard time finding a good question title - let me just show you what I have and what the desired outcome is. I hope this can be done in SQL (I have SQL Server 2008). 1) I have a table called Contacts and in that table I have fields like these: FirstName, LastName, CompanyName 2) Some demo data: FirstName LastName CompanyName John Smith Smith Corp Paul Wade Marc Andrews Microsoft Bill Gates Microsoft Steve Gibbs Smith Corp Diane Rowe ABC Inc. 3) I want to get an intersecting list of people and companies, but companies only once. This would look like this: Name ABC Inc. Bill Gates Diane Rowe John Smith Marc Andrews Microsoft Smith Corp Steve Gibbs Paul Wade Can I do this with SQL? How?

    Read the article

  • PHP: How to use mysql fulltext search and handle fulltext search result

    - by garcon1986
    Hello, I have tried to use mysql fulltext search in my intranet. I wanted to use it to search in multiple tables, and get the independant results depending on tables in the result page. This is what i did for searching. $query = " SELECT * FROM testtable t1, testtable2 t2, testtable3 t3 WHERE match(t1.firstName, t1.lastName, t1.details) against(' ".$value."') or match(t2.others, t2.information, t2.details) against(' ".$value."') or match(t3.other, t2.info, t2.details) against(' ".$value."') "; $result = mysql_query($query)or die('query error'.mysql_error()); while($row = mysql_fetch_assoc($result)){ echo $row['firstName']; echo $row['lastName']; echo $row['details'].'<br />'; } Do you have any ideas about optimizing the query and format the output of search results?

    Read the article

  • Conditionals in Antlr String Templates

    - by Pat Long - Munkii Yebee
    We are using Antlr StringTemplates to give control over how a Entity's Name is output. The basic Stringtemplate is $FirstName$ $Initial$ $LastName$, $Suffix$, $Degree$ I want to add some smarts to that template so that the commas are only output when necessary i.e. The first comma is only output when there is a Suffix or Degree and the second commas is only output if there is a suffix. I tried the following template string bit it does not work. I guess I have misunderstood $FirstName$ $Initial$ $LastName$ <if(Suffix|Degree)>,<endif>, $Suffix$ <if(Suffix)>,<endif> $Degree$ If it helps we process the templates using this C# StringTemplate stringtemplate = new Antlr.StringTemplate.StringTemplate(template.Data); foreach (Pair<string, string> pair in dictionary) { if (pair.First != null && pair.Second != null) { stringtemplate.SetAttribute(pair.First, pair.Second); } } return stringtemplate.ToString();

    Read the article

  • C# LINQ XML Query with duplicate element names that have attributes

    - by ncain187
    <Party id="Party_1"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>John Doe</FullName> <GovtID>123456789</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <ResidenceState tc="35">New Jersey</ResidenceState> <Person> <FirstName>Frank</FirstName> <MiddleName>Roberts</MiddleName> <LastName>Madison</LastName> <Prefix>Dr.</Prefix> <Suffix>III</Suffix> <Gender tc="1">Male</Gender> <BirthDate>1974-01-01</BirthDate> <Age>35</Age> <Citizenship tc="1">United States of America</Citizenship> </Person> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <Line2></Line2> <Line3></Line3> <Line4></Line4> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> </Party> <!-- *********************** --> <!-- Insured Information --> <!-- *********************** --> <Party id="Party_2"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>Dollie Robert Madison</FullName> <GovtID>123956239</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <Person> <FirstName>Dollie</FirstName> <MiddleName>R</MiddleName> <LastName>Madison</LastName> <Suffix>III</Suffix> <Gender tc="2">Female</Gender> <BirthDate>1996-10-12</BirthDate> <Citizenship tc="1">United States of America</Citizenship> </Person> <!-- Insured Address --> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> <Risk> <!-- Disability Begin Effective Date --> <DisabilityEffectiveStartDate>2006-01-01</DisabilityEffectiveStartDate> <!-- Disability End Effective Date --> <DisabilityEffectiveStopDate>2008-01-01</DisabilityEffectiveStopDate> </Risk> </Party> <!-- ******************************* --> <!-- Company Information --> <!-- ****************************** --> <Party id="Party_3"> <PartyTypeCode tc="2">Organization</PartyTypeCode> <Organization> <DTCCMemberCode>1234</DTCCMemberCode> </Organization> <Carrier> <CarrierCode>105</CarrierCode> </Carrier> </Party> Here is my code which doesn't work because party 3 doesn't contain FullName, I know that partyelements contains 3 parties if I only return the name attribute. Is there a way to loop through each tag seperate? var partyElements = from party in xmlDoc.Descendants("Party") select new { Name = party.Attribute("id").Value, PartyTypeCode = party.Element("PartyTypeCode").Value, FullName = party.Element("FullName").Value, GovtID = party.Element("GovtID").Value, };

    Read the article

  • How can a user view profile info of other users?

    - by Arvind Singh
    I have stored profile info using this code ProfileBase userprofile = HttpContext.Current.Profile; userprofile.SetPropertyValue("FirstName", TextBoxFirstName.Text); userprofile.SetPropertyValue("LastName", TextBoxLastName.Text); userprofile.SetPropertyValue("AboutMe", TextBoxAboutMe.Text); userprofile.SetPropertyValue("ContactNo", TextBoxContactNo.Text); and in web.config <profile enabled="true" defaultProvider="AspNetSqlProfileProvider"> <properties> <add name="FirstName" type="String" /> <add name="LastName" type="String" /> <add name="AboutMe" type="String" /> <add name="ContactNo" type="String" /> </properties> </profile> The profile info is stored and every user is able to view his own profile info using something like this TextBoxFirstName.Text = HttpContext.Current.Profile.GetPropertyValue("FirstName").ToString(); How to fetch profile info of other user say a user types the username of other user in a text box and clicks a button?

    Read the article

  • XML Return from an Oracle Stored Procedure

    - by Tequila Jinx
    Unfortunately most of my DB experience has been with MSSQL which tends to hold your hand a lot more than Oracle. What I'm trying to do is fairly trivial in tSQL, however, pl/sql is giving me a headache. I have the following procedure: CREATE OR REPLACE PROCEDURE USPX_GetUserbyID (USERID USERS.USERID%TYPE, USERRECORD OUT XMLTYPE) AS BEGIN SELECT XMLELEMENT("user" , XMLATTRIBUTES(u.USERID AS "userid", u.companyid as "companyid", u.usertype as "usertype", u.status as "status", u.personid as "personid") , XMLFOREST( p.FIRSTNAME AS "firstname" , p.LASTNAME AS "lastname" , p.EMAIL AS "email" , p.PHONE AS "phone" , p.PHONEEXTENSION AS "extension") , XMLELEMENT("roles", (SELECT XMLAGG(XMLELEMENT("role", r.ROLETYPE)) FROM USER_ROLES r WHERE r.USERID = USERID AND r.ISACTIVE = 1 ) ) , XMLELEMENT("watches", (SELECT XMLAGG( XMLELEMENT("watch", XMLATTRIBUTES(w.WATCHID AS "id", w.TICKETID AS "ticket") ) ) FROM USER_WATCHES w WHERE w.USERID = USERID AND w.ISACTIVE = 1 ) ) ) AS "RESULT" INTO USERRECORD FROM USERS u LEFT JOIN PEOPLE p ON p.PERSONID = u.PERSONID WHERE u.USERID = USERID; END USPX_GetUserbyID; When executed, it should return an XML document with the following structure: <user userid="" companyid="" usertype="" status="" personid=""> <firstname /> <lastname /> <email /> <phone /> <extension /> <roles> <role /> </roles> <watches> <watch id="" ticket="" /> </watches> </user> When I execute the query itself, replacing the USERID parameter with a string and removing the "into" clause, the query runs fine and returns the expected structure. However, when the procedure attempts to execute the query, passing the results of the XMLELEMENT function into the USERRECORD output parameter, I get the following exception: Error report: ORA-01422: exact fetch returns more than requested number of rows ORA-06512: at "USPX_GETUSERBYID", line 4 ORA-06512: at line 3 01422. 00000 - "exact fetch returns more than requested number of rows" *Cause: The number specified in exact fetch is less than the rows returned. *Action: Rewrite the query or change number of rows requested I'm baffled trying to nail this down, and unfortunately my google-fu hasn't helped. I've found plenty of Oracle SQL|XML examples, but none that deal with XML returns from a procedure. Note: I know that an alternate method of retrieving XML using DBMS methods exists, however, it's my understanding that that functionality is deprecated in favor of SQL|XML.

    Read the article

  • Convert json to a string using jquery

    - by becomingGuru
    I have a nested json. I want to post it as a form input value. But, seems like jquery puts "Object object" string into the value. It seems easier to pass around the string and convert into the native form I need, than dealing with json as I don't need to change anything once it is generated. What is the simplest way to convert a json var json = { "firstName": "John", "lastName": "Smith", "age": 25, "address": { "streetAddress": "21 2nd Street", "city": "New York", "state": "NY", "postalCode": "10021" }, "phoneNumber": [ { "type": "home", "number": "212 555-1234" }, { "type": "fax", "number": "646 555-4567" } ], "newSubscription": false, "companyName": null }; into its string form? var json = '{ "firstName": "John", "lastName": "Smith", "age": 25, "address": { "streetAddress": "21 2nd Street", "city": "New York", "state": "NY", "postalCode": "10021" }, "phoneNumber": [ { "type": "home", "number": "212 555-1234" }, { "type": "fax", "number": "646 555-4567" } ], "newSubscription": false, "companyName": null }' Following doesn't do what I need: Json.stringify()

    Read the article

  • how to send a dynamic set of parameters to webmethod using jquery ajax method?

    - by kranthi
    hi, I am using jquery ajax method on my aspx page,which will invoke the webmethod in the code behind.Currently the webmethod takes a couple of parameters like firstname,lastname,address etc which I am passing from jquery ajax method using data:JSON.stringify({fname:firstname,lname:lastname,city:city}) now my requirement has been changed such that,the number and type of parameters that are going to be passed is not fixed for ex.parameter combination can be something like fname,city or fname,city or city,lname or fname,lname,city or something else.So the webmethod should be such that it should accept any number parameters.I thought of using arrays to do so, as described here. But I do not understand how can I identify which and how many parameters have been passed to the webmethod to insert/update the data to the DB.Please could someone help me with this? thanks

    Read the article

  • foreach loop...........

    - by nisardotnet
    I have two questions 1) my interface i have interface called IRegister and within it i have another interface called IPerson, is that right practice? 2) i have two List(IRegister, IPerson) both can have one or more rows. what is the best way to loop both List? within GetValidationRules? public interface IRegister { string FirstName { get; } string MiddleName { get; } string LastName { get; } string EmailAddress { get; } List Student { get; } } public static List GetValidationRules(List register) { List validationRules = new List(); foreach (IRegister myregister in register) { if (string.IsNullOrEmpty(myregister.FirstName)) validationRules.Add(new ValidationRule("Reg", "Must have aFirst Name")); if (string.IsNullOrEmpty(myregister.LastName)) validationRules.Add(new ValidationRule("Reg", "Must have a Last Name")); if (string.IsNullOrEmpty(myregister.EmailAddress)) validationRules.Add(new ValidationRule("Reg", "Must have a Email Address")); IPerson here? how }

    Read the article

  • nHibernate multiple classes pointing to same table?

    - by Amitabh
    Is it a good idea to create a lighter version of an Entity in some cases just for performance reason pointing to same table but with fewer columns mapped. E.g If I have a Contact Table which has 50 Columns and in few of the related entities I might be interested in FirstName and LastName property is it a good idea to create a lightweight version of Contact table. E.g. public class LightContact { public int Id {get; set;} public string FirstName {get; set;} public string LastName {get; set;} } Also is it possible to map multiple classes to same table?

    Read the article

  • Searches (and general querying) with HBase and/or Cassandra (best practices?)

    - by alexeypro
    I have User model object with quite few fields (properties, if you wish) in it. Say "firstname", "lastname", "city" and "year-of-birth". Each user also gets "unique id". I want to be able to search by them. How do I do that properly? How to do that at all? My understanding (will work for pretty much any key-value storage -- first goes key, then value) u:123456789 = serialized_json_object ("u" as a simple prefix for user's keys, 123456789 is "unique id"). Now, thinking that I want to be able to search by firstname and lastname, I can save in: f:Steve = u:384734807,u:2398248764,u:23276263 f:Alex = u:12324355,u:121324334 so key is "f" - which is prefix for firstnames, and "Steve" is actual firstname. For "u:Steve" we save as value all user id's who are "Steve's". That makes every search very-very easy. Querying by few fields (properties) -- say by firstname (i.e. "Steve") and lastname (i.e. "l:Anything") is still easy - first get list of user ids from "f:Steve", then list from "l:Anything", find crossing user ids, an here you go. Problems (and there are quite a few): Saving, updating, deleting user is a pain. It has to be atomic and consistent operation. Also, if we have size of value limited to some value - then we are in (potential) trouble. And really not of an answer here. Only zipping the list of user ids? Not too cool, though. What id we want to add new field to search by. Eventually. Say by "city". We certainly can do the same way "c:Los Angeles" = ..., "c:Chicago" = ..., but if we didn't foresee all those "search choices" from the very beginning, then we will have to be able to create some night job or something to go by all existing User records and update those "c:CITY" for them... Quite a big job! Problems with locking. User "u:123" updates his name "Alex", and user "u:456" updates his name "Alex". They both have to update "f:Alex" with their id's. That means either we get into overwriting problem, or one update will wait for another (and imaging if there are many of them?!). What's the best way of doing that? Keeping in mind that I want to search by many fields? P.S. Please, the question is about HBase/Cassandra/NoSQL/Key-Value storages. Please please - no advices to use MySQL and "read about" SELECTs; and worry about scaling problems "later". There is a reason why I asked MY question exactly the way I did. :-)

    Read the article

  • create new inbox folder and save emails

    - by kasunmit
    i am trying http://www.c-sharpcorner.com/uploadfile/rambab/outlookintegration10282006032802am/outlookintegration.aspx[^] this code for create inbox personal folder and save same mails at the datagrid view (outlook 2007 and vsto 2008) i am able to create inbox folder according to above example but couldn't wire code for save e-mails at that example to save contect they r using following code if (chkVerify.Checked) { OutLook._Application outlookObj = new OutLook.Application(); MyContact cntact = new MyContact(); cntact.CustomProperty = txtProp1.Text.Trim().ToString(); //CREATING CONTACT ITEM OBJECT AND FINDING THE CONTACT ITEM OutLook.ContactItem newContact = (OutLook.ContactItem)FindContactItem(cntact, CustomFolder); //THE VALUES WE CAN GET FROM WEB SERVICES OR DATA BASE OR CLASS. WE HAVE TO ASSIGN THE VALUES //TO OUTLOOK CONTACT ITEM OBJECT . if (newContact != null) { newContact.FirstName = txtFirstName.Text.Trim().ToString(); newContact.LastName = txtLastName.Text.Trim().ToString(); newContact.Email1Address = txtEmail.Text.Trim().ToString(); newContact.Business2TelephoneNumber = txtPhone.Text.Trim().ToString(); newContact.BusinessAddress = txtAddress.Text.Trim().ToString(); if (chkAdd.Checked) { //HERE WE CAN CREATE OUR OWN CUSTOM PROPERTY TO IDENTIFY OUR APPLICATION. if(string.IsNullOrEmpty(txtProp1.Text.Trim().ToString())) { MessageBox.Show("please add value to Your Custom Property"); return; } newContact.UserProperties.Add("myPetName", OutLook.OlUserPropertyType.olText, true, OutLook.OlUserPropertyType.olText); newContact.UserProperties["myPetName"].Value = txtProp1.Text.Trim().ToString(); } newContact.Save(); this.Close(); } else { //IF THE CONTACT DOES NOT EXIST WITH SAME CUSTOM PROPERTY CREATES THE CONTACT. newContact = (OutLook.ContactItem)CustomFolder.Items.Add(OutLook.OlItemType.olContactItem); newContact.FirstName = txtFirstName.Text.Trim().ToString(); newContact.LastName = txtLastName.Text.Trim().ToString(); newContact.Email1Address = txtEmail.Text.Trim().ToString(); newContact.Business2TelephoneNumber = txtPhone.Text.Trim().ToString(); newContact.BusinessAddress = txtAddress.Text.Trim().ToString(); if (chkAdd.Checked) { //HERE WE CAN CREATE OUR OWN CUSTOM PROPERTY TO IDENTIFY OUR APPLICATION. if (string.IsNullOrEmpty(txtProp1.Text.Trim().ToString())) { MessageBox.Show("please add value to Your Custom Property"); return; } newContact.UserProperties.Add("myPetName", OutLook.OlUserPropertyType.olText, true, OutLook.OlUserPropertyType.olText); newContact.UserProperties["myPetName"].Value = txtProp1.Text.Trim().ToString(); } newContact.Save(); this.Close(); } } else { OutLook._Application outlookObj = new OutLook.Application(); OutLook.ContactItem newContact = (OutLook.ContactItem)CustomFolder.Items.Add(OutLook.OlItemType.olContactItem); newContact.FirstName = txtFirstName.Text.Trim().ToString(); newContact.LastName = txtLastName.Text.Trim().ToString(); newContact.Email1Address = txtEmail.Text.Trim().ToString(); newContact.Business2TelephoneNumber = txtPhone.Text.Trim().ToString(); newContact.BusinessAddress = txtAddress.Text.Trim().ToString(); if (chkAdd.Checked) { //HERE WE CAN CREATE OUR OWN CUSTOM PROPERTY TO IDENTIFY OUR APPLICATION. if (string.IsNullOrEmpty(txtProp1.Text.Trim().ToString())) { MessageBox.Show("please add value to Your Custom Property"); return; } newContact.UserProperties.Add("myPetName", OutLook.OlUserPropertyType.olText, true, OutLook.OlUserPropertyType.olText); newContact.UserProperties["myPetName"].Value = txtProp1.Text.Trim().ToString(); } newContact.Save(); this.Close(); } } else { //CREATES THE OUTLOOK CONTACT IN DEFAULT CONTACTS FOLDER. OutLook._Application outlookObj = new OutLook.Application(); OutLook.MAPIFolder fldContacts = (OutLook.MAPIFolder)outlookObj.Session.GetDefaultFolder(OutLook.OlDefaultFolders.olFolderContacts); OutLook.ContactItem newContact = (OutLook.ContactItem)fldContacts.Items.Add(OutLook.OlItemType.olContactItem); //THE VALUES WE CAN GET FROM WEB SERVICES OR DATA BASE OR CLASS. WE HAVE TO ASSIGN THE VALUES //TO OUTLOOK CONTACT ITEM OBJECT . newContact.FirstName = txtFirstName.Text.Trim().ToString(); newContact.LastName = txtLastName.Text.Trim().ToString(); newContact.Email1Address = txtEmail.Text.Trim().ToString(); newContact.Business2TelephoneNumber = txtPhone.Text.Trim().ToString(); newContact.BusinessAddress = txtAddress.Text.Trim().ToString(); newContact.Save(); this.Close(); } } /// /// ENABLING AND DISABLING THE CUSTOM FOLDER AND PROPERY OPTIONS. /// /// /// private void rdoCustom_CheckedChanged(object sender, EventArgs e) { if (rdoCustom.Checked) { txFolder.Enabled = true; chkAdd.Enabled = true; chkVerify.Enabled = true; txtProp1.Enabled = true; } else { txFolder.Enabled = false; chkAdd.Enabled = false; chkVerify.Enabled = false; txtProp1.Enabled = false; } } i don t have idea to convert it to save e-mails in the datagrid view the data gride view i am mentioning here is containing details (sender address, subject etc.) of unread mails and the i i am did was perform some filter for that mails as follows string senderMailAddress = txtMailAddress.Text.ToLower(); List list = (List)dgvUnreadMails.DataSource; List myUnreadMailList; List filteredList = (List)(from ci in list where ci.SenderAddress.StartsWith(senderMailAddress) select ci).ToList(); dgvUnreadMails.DataSource = filteredList; it was done successfully then i need to save those filtered e-mails to that personal inbox folder i created already for that pls give me some help my issue is that how can i assign outlook object just like they assign it to contacts (name, address, e-mail etc.) because in the e-mails we couldn't find it ..

    Read the article

  • NHibernate GenericADO Exception

    - by Ris90
    Hi, I'm trying to make simple many-to-one association, using NHibernate.. I have class Recruit with this mapping: <class name="Recruit" table="Recruits"> <id name="ID"> <generator class="native"/> </id> <property name="Lastname" column="lastname"/> <property name="Name" column="name"/> <property name="MedicalReport" column="medicalReport"/> <property name="DateOfBirth" column ="dateOfBirth" type="Date"/> <many-to-one name="AssignedOnRecruitmentOffice" column="assignedOnRecruitmentOffice" class="RecruitmentOffice"/> which is many-to-one connected to RecruitmentOffices: <class name="RecruitmentOffice" table="RecruitmentOffices"> <id name="ID" column="ID"> <generator class="native"/> </id> <property name="Chief" column="chief"/> <property name="Name" column="name"/> <property name ="Address" column="address"/> <set name="Recruits" cascade="save-update" inverse="true" lazy="true"> <key> <column name="AssignedOnRecruitmentOffice"/> </key> <one-to-many class="Recruit"/> </set> And create Repository class with method Insert: public void Insert(Recruit recruit) { using (ITransaction transaction = session.BeginTransaction()) { session.Save(recruit); transaction.Commit(); } } then I try to save new recrui to base: Recruit test = new Recruit(); RecruitmentOffice office = new RecruitmentOffice(); ofice.Name = "test"; office.Chief = "test"; test.AssignedOnRecruitmentOffice = office; test.Name = "test"; test.DateOfBirth = DateTime.Now; RecruitRepository testing = new RecruitRepository(); testing.Insert(test); And have this error GenericADOException could not insert: [OSiUBD.Models.DAO.Recruit][SQL: INSERT INTO Recruits (lastname, name, medicalReport, dateOfBirth, assignedOnRecruitmentOffice) VALUES (?, ?, ?, ?, ?); select SCOPE_IDENTITY()] on session.Save

    Read the article

  • Can't figure out how to list all the people that don't live in same City as...

    - by AspOnMyNet
    I’d like to list all the people ( Person table ) that don’t live in same city as those cities listed in Location table. Thus, if Location table holds a record with City=’New York’ and State=’Moon’, but Person table holds a record with FirstName=’Someone’, City=’New York’ and Location=’Mars’, then Someone is listed in the resulting set, since she lives in New York located on Mars and not New York located on Moon, thus we’re talking about different cities with the same name. I tried solving it with the following query, but results are wrong: SELECT Person.FirstName, Person.LastName, Person.City, Person.State FROM Person INNER JOIN Location ON (Person.City <> Location.City AND Person.State = Location.State) OR (Person.City = Location.City AND Person.State <> Location.State) OR (Person.City <> Location.City AND Person.State <> Location.State) ORDER BY Person.LastName; Any ideas?

    Read the article

  • Query Concatenated Field (using SubSonic)

    - by jwynveen
    Is there a way to query against a concatenated field using MS SQL? For instance, what I want to do is something like: Select FirstName+' '+LastName as FullName from Attendees where FullName like '%Joe Schmoe%' The above doesn't work. What I have found works is: Select * from Attendee where FirstName+' '+LastName like '%Joe Schmoe%' but I can't figure out how to do that using a SubSonic SqlQuery. I have a number of joins and OR statements added dynamically that I don't want to have to write out the sql manually. Any help/ideas?

    Read the article

  • JQuery: is it possible to instantiate a class on client and pass it to $.ajax to post?

    - by nisardotnet
    what i mean by that is: i have a class called Customer: public class Customer { private string _firstName; private string _lastName; public string FirstName { get { return _firstName; } set { _firstName = value; } } public string LastName { get { return _lastName; } set { _lastName = value; } } } how do i instantitate the class "Customer" on the client code and add the data and post it? (not sure if this is possible) here is my client code: var customer = { "firstName": escape($('#txtFirstName').val()), "lastName": escape($('#txtLastName').val()) }; var jsonText = JSON.stringify({ customer: customer }); $.ajax( { type: "POST", url: "VisitorWS.asmx/AddCustomer", data: jsonText , //data: JSON.stringify(params), contentType: "application/json; charset=utf-8", dataType: "json", ...........

    Read the article

  • Declarative JDOQL vs Single-String JDOQL : performance

    - by DrDro
    When querying with JDOQL is there a performance difference between using the declarative version and the Single-String version: Example from the JDOQL doc: //Declarative JDOQL : Query q = pm.newQuery(org.jpox.Person.class, "lastName == \"Jones\" && age < age_limit"); q.declareParameters("double age_limit"); List results = (List)q.execute(20.0); //Single-String JDOQL : Query q = pm.newQuery("SELECT FROM org.jpox.Person WHERE lastName == \"Jones\"" + " && age < :age_limit PARAMETERS double age_limit"); List results = (List)q.execute(20.0); Other then performance, are there any reasons for which one is better to use then the other or is it just about the one with which we feel more comfortable.

    Read the article

  • SOA design principles with regards to database relationships

    - by Eitan
    If I were to extricate my current membership provider from my solution, i.e. as a dll and expose it as a web service with it's own db, how would I model the relationships with regards to SOA design. For example I have a table: USER id, name, lastname, username, password, role. and table PRODUCT id, name, price, createdate, userid the foreign key being userid to table user. How would I model the relationship and/or query the db. If I wanted to get all products that were uploaded today for example, before I would query: SELECT u.name, u.lastname, u.username, p.* FROM PRODUCT p INNER JOIN USER u ON p.userid = u.id WHERE createdate = '05/05/2010' Now that I don't have the table within the database how would I perform this query? Thanks.

    Read the article

  • nested linq-to-sql queries

    - by ile
    var result = ( from contact in db.Contacts join user in db.Users on contact.CreatedByUserID equals user.UserID orderby contact.ContactID descending select new ContactListView { ContactID = contact.ContactID, FirstName = contact.FirstName, LastName = contact.LastName, Company = (from field in contact.XmlFields.Descendants("Company") select field.Value).SingleOrDefault().ToString() }).Take(10); Here I described how my database tables look like. So, contacts table has one field that is xml type. In that field is stored Company filename and I need to read it. I tried it using this way: Company = (from field in contact.XmlFields.Descendants("Company") select field.Value).SingleOrDefault().ToString() }).Take(10); but I get following error: Member access 'System.String Value' of 'System.Xml.Linq.XElement' not legal on type 'System.Collections.Generic.IEnumerable`1[System.Xml.Linq.XElement]. Any solution for this? Thanks in advance, Ile

    Read the article

  • How to bind Dictionary with ComboBox and textbox?

    - by younevertell
    I have a Dictionary, where Person is a class, defined below String role; public class Person { public string firstname{ get; set; } public string lastname{ get; set; } public string city{ get; set; } } my question is how to bind the Dictionary key: String with a ComboBox, menwhile. have the Dictionary value: Person connected with three textboxes. That is, once a key is selected in the ComboBox, the corresponding value, firstname, lastname, city are shown in the three textboxes respectively? Thanks in advance!

    Read the article

  • php array code with regular expressions

    - by user551068
    there are few mistakes which it is showing as Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash in array 4,9,10,11,12... can anyone resolve them <?PHP $hosts = array( array("ronmexico.kainalopallo.com/","beforename=$F_firstname%20$F_lastname&gender=$F_gender","Your Ron Mexico Name is ","/the ultimate disguise, is <u><b>([^<]+)<\/b><\/u>/s"), array("www.fjordstone.com/cgi-bin/png.pl","gender=$F_gender&submit=Name%20Me","Your Pagan name is ","/COLOR=#000000 SIZE=6> *([^<]*)<\/FONT>/"), array("rumandmonkey.com/widgets/toys/mormon/index.php","gender=$F_gender&firstname=$F_firstname&surname=$F_lastname","Your Mormon Name is ","/<p>My Mormon name is <b>([^<]+)<\/b>!<br \/>/s"), array("cyborg.namedecoder.com/index.php","acronym=$F_firstname&design=edox&design_click-edox.x=0&design_click-edox.y=0&design_click-edox=edo","","Your Cyborg Name is ","/<p>([^<]+)<\/p>/"), array("rumandmonkey.com/widgets/toys/namegen/10/","nametype=$brit&page=2&id=10&submit=God%20save%20the%20Queen!&name=$F_firstname%20$F_lastname","Your Very British Name is ","/My very British name is \&lt\;b\&gt;([^&]+)\&lt;\/b\&gt;\.\&lt;br/"), array("blazonry.com/name_generator/usname.php","realname=$F_firstname+$F_lastname&gender=$F_gender","Your U.S. Name is ","/also be known as <font size=\'\+1\'><b>([^<]+)<\/b>/s"), array("www.spacepirate.org/rogues.php","realname=$F_firstname%20$F_lastname&formentered=Yes&submit=Arrrgh","Your Space Pirate name is ","/Your pirate name is <font size=\'\+1\'><b>([^<]+)<\/b><\/font>/s"), array("rumandmonkey.com/widgets/toys/ghetto/","firstname=$F_firstname&lastname=$F_lastname","Your Ghetto Name is ","/<p align=\"center\" style=\"font-size: 36px\">\s*<br \/>\s*([^<]*)<br \/>/"), array("www.emmadavies.net/vampire/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Find+My+Vampire+Name","","Your Vampire Name is ","/<i class=\"vampirecontrol vampire name\">([^<]*)<\/i>/"), array("www.emmadavies.net/fairy/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Seek+Fairy","","Your Fairy Name is ","/<i class=\'ng fairy name\'>([^<]*)<\/i>/"), array("www.irielion.com/israel/reggaename.html","phase=3&oldname=$F_firstname%20$F_lastname&gndr=$reggender","","Your Rasta Name is ","/Yes I, your irie new name is ([^\n]*)\n/"), array("www.ninjaburger.com/fun/games/ninjaname/ninjaname.php","realname=$F_firstname+$F_lastname","Your Ninja Burger Name is ","/<BR>Ninja Burger ninja name will be<BR><BR><FONT SIZE=\'\+1\'>([^<]*)<\/FONT>/"), array("gangstaname.com/pirate_name.php","sex=$F_gender&name=$F_firstname+$F_lastname","Your Pirate Name is ","/<p><strong>We\'ll now call ye:<\/strong><\/p> *<h2 class=\"newName\">([^<]*)<\/h2>/"), array("www.xach.com/nerd-name/","name=$F_firstname+$F_lastname&gender=$F_gender","Your Nerd Name is ","/<p><div align=center class=\"nerdname\">([^<]*)<\/div>/"), array("rumandmonkey.com/widgets/toys/namegen/5941/","page=2&id=5941&nametype=$dj&name=$F_firstname+$F_lastname","Your DJ Name is ","/My disk spinnin nu name is &lt\;b&gt\;([^<]*)&lt\;\/b&gt\;\./"), array("pizza.sandwich.net/poke/pokecgi.cgi","name=$F_firstname%20$F_lastname&color=black&submit=%20send%20","Your Pokename is ","/Your Pok&eacute;name is: <h1>([^<]*)<\/h1>/") ); return $hosts; ?>

    Read the article

< Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >