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  • Flex Datagrid File Download old value

    - by Vish
    Hi, We use a AIR client and WAMP server. Got a weird issue with Flex datagrid. When I download an image by double clicking on a datagrid row, the file gets downloaded correctly. But when I go on to select another row for download, even though the correct parameters are being passed, it again prompts download of old file. Upon cancelling that and trying again, it picks up the selected row. Not sure how to fix this issue, below is the datagrid code I am using, <mx:DataGrid x="10" y="10" id="ourDataGrid" visible="true" enabled="true" dataProvider="{fileList}" verticalScrollPolicy="on" selectionColor="#B7C6E7" itemClick="downloadFile(event)"> <mx:columns> <mx:DataGridColumn headerText="Name" dataField="@name" /> <mx:DataGridColumn headerText="LastName" dataField="@lastname" /> <mx:DataGridColumn headerText="FirstName" dataField="@firstname" /> </mx:columns> </mx:DataGrid>

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  • Fill Combo-box via DataSource Using Values from Various Columns

    - by peace
    Employee emp = new Employee(); comHandledBySQt.DataSource = emp.GetDataFromTable("1"); comHandledBySQt.DisplayMember = "FirstName"; The above code displays drop list of employees first names in a combo box. I want first name and last name to be displayed. How can i do it? I tried to include two columns FirstName and LastName as below but didn't work. comHandledBySQt.DisplayMember = "FirstName" + " " + "LastName"; Any help will be appreciated.

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  • Multiple many-to-many JOINs in a single mysql query without Cartesian Product

    - by VWD
    At the moment I can get the results I need with two seperate SELECT statements SELECT COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID GROUP BY bl.biblioID Combining them like this however SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ), COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID causes the author result column to have duplicate names. How can I get the desired results from one SELECT statement without using DISTINCT? With subqueries?

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  • Comparing Nested object properties using C#

    - by Kumar
    I have a method which compares two objects and returns a list of all the property names which are different. public static IList<string> GetDifferingProperties(object source, object) { var sourceType = source.GetType(); var sourceProperties = sourceType.GetProperties(); var targetType = target.GetType(); var targetProperties = targetType.GetProperties(); var properties = (from s in sourceProperties from t in targetProperties where s.Name == t.Name && s.PropertyType == t.PropertyType && s.GetValue(source,null) != t.GetValue(target,null) select s.Name).ToList(); return properties; } For example if I have two classes as follows: public class Address { public string AddressLine1 { get; set; } public string AddressLine2 { get; set; } public string City { get; set; } public string State { get; set; } public string Zip { get; set; } } public class Employee { public string FirstName { get; set; } public string MiddleName { get; set; } public string LastName { get; set; } public Address EmployeeAddress { get; set; } } I am trying to compare the following two employee instances: var emp1Address = new Address(); emp1Address.AddressLine1 = "Microsoft Corporation"; emp1Address.AddressLine2 = "One Microsoft Way"; emp1Address.City = "Redmond"; emp1Address.State = "WA"; emp1Address.Zip = "98052-6399"; var emp1 = new Employee(); emp1.FirstName = "Bill"; emp1.LastName = "Gates"; emp1.EmployeeAddress = emp1Address; var emp2Address = new Address(); emp2Address.AddressLine1 = "Gates Foundation"; emp2Address.AddressLine2 = "One Microsoft Way"; emp2Address.City = "Redmond"; emp2Address.State = "WA"; emp2Address.Zip = "98052-6399"; var emp2 = new Employee(); emp2.FirstName = "Melinda"; emp2.LastName = "Gates"; emp2.EmployeeAddress = emp2Address; So when I pass these two employee objects to my GetDifferingProperties method currently it returns FirstName and EmployeeAddress, but it does not tell me which exact property (which in this case is Address1) in the EmployeeAddress has changed. How can I tweak this method to get something like EmployeeAddress.Address1?

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  • JavaFx 2.1, 2.2 TableView update issue

    - by Lewis Liu
    My application uses JPA read data into TableView then modify and display them. The table refreshed modified record under JavaFx 2.0.3. Under JavaFx 2.1, 2.2, the table wouldn't refresh the update anymore. I found other people have similar issue. My plan was to continue using 2.0.3 until someone fixes the issue under 2.1 and 2.2. Now I know it is not a bug and wouldn't be fixed. Well, I don't know how to deal with this. Following are codes are modified from sample demo to show the issue. If I add a new record or delete a old record from table, table refreshes fine. If I modify a record, the table wouldn't refreshes the change until a add, delete or sort action is taken. If I remove the modified record and add it again, table refreshes. But the modified record is put at button of table. Well, if I remove the modified record, add the same record then move the record to the original spot, the table wouldn't refresh anymore. Below is a completely code, please shine some light on this. import javafx.application.Application; import javafx.beans.property.SimpleStringProperty; import javafx.collections.FXCollections; import javafx.collections.ObservableList; import javafx.event.ActionEvent; import javafx.event.EventHandler; import javafx.geometry.HPos; import javafx.geometry.Insets; import javafx.geometry.Pos; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.control.*; import javafx.scene.control.cell.PropertyValueFactory; import javafx.scene.layout.GridPane; import javafx.scene.layout.HBox; import javafx.scene.layout.VBox; import javafx.scene.text.Font; import javafx.stage.Modality; import javafx.stage.Stage; import javafx.stage.StageStyle; public class Main extends Application { private TextField firtNameField = new TextField(); private TextField lastNameField = new TextField(); private TextField emailField = new TextField(); private Stage editView; private Person fPerson; public static class Person { private final SimpleStringProperty firstName; private final SimpleStringProperty lastName; private final SimpleStringProperty email; private Person(String fName, String lName, String email) { this.firstName = new SimpleStringProperty(fName); this.lastName = new SimpleStringProperty(lName); this.email = new SimpleStringProperty(email); } public String getFirstName() { return firstName.get(); } public void setFirstName(String fName) { firstName.set(fName); } public String getLastName() { return lastName.get(); } public void setLastName(String fName) { lastName.set(fName); } public String getEmail() { return email.get(); } public void setEmail(String fName) { email.set(fName); } } private TableView<Person> table = new TableView<Person>(); private final ObservableList<Person> data = FXCollections.observableArrayList( new Person("Jacob", "Smith", "[email protected]"), new Person("Isabella", "Johnson", "[email protected]"), new Person("Ethan", "Williams", "[email protected]"), new Person("Emma", "Jones", "[email protected]"), new Person("Michael", "Brown", "[email protected]")); public static void main(String[] args) { launch(args); } @Override public void start(Stage stage) { Scene scene = new Scene(new Group()); stage.setTitle("Table View Sample"); stage.setWidth(535); stage.setHeight(535); editView = new Stage(); final Label label = new Label("Address Book"); label.setFont(new Font("Arial", 20)); TableColumn firstNameCol = new TableColumn("First Name"); firstNameCol.setCellValueFactory( new PropertyValueFactory<Person, String>("firstName")); firstNameCol.setMinWidth(150); TableColumn lastNameCol = new TableColumn("Last Name"); lastNameCol.setCellValueFactory( new PropertyValueFactory<Person, String>("lastName")); lastNameCol.setMinWidth(150); TableColumn emailCol = new TableColumn("Email"); emailCol.setMinWidth(200); emailCol.setCellValueFactory( new PropertyValueFactory<Person, String>("email")); table.setItems(data); table.getColumns().addAll(firstNameCol, lastNameCol, emailCol); //--- create a edit button and a editPane to edit person Button addButton = new Button("Add"); addButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { fPerson = null; firtNameField.setText(""); lastNameField.setText(""); emailField.setText(""); editView.show(); } }); Button editButton = new Button("Edit"); editButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { if (table.getSelectionModel().getSelectedItem() != null) { fPerson = table.getSelectionModel().getSelectedItem(); firtNameField.setText(fPerson.getFirstName()); lastNameField.setText(fPerson.getLastName()); emailField.setText(fPerson.getEmail()); editView.show(); } } }); Button deleteButton = new Button("Delete"); deleteButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { if (table.getSelectionModel().getSelectedItem() != null) { data.remove(table.getSelectionModel().getSelectedItem()); } } }); HBox addEditDeleteButtonBox = new HBox(); addEditDeleteButtonBox.getChildren().addAll(addButton, editButton, deleteButton); addEditDeleteButtonBox.setAlignment(Pos.CENTER_RIGHT); addEditDeleteButtonBox.setSpacing(3); GridPane editPane = new GridPane(); editPane.getStyleClass().add("editView"); editPane.setPadding(new Insets(3)); editPane.setHgap(5); editPane.setVgap(5); Label personLbl = new Label("Person:"); editPane.add(personLbl, 0, 1); GridPane.setHalignment(personLbl, HPos.LEFT); firtNameField.setPrefWidth(250); lastNameField.setPrefWidth(250); emailField.setPrefWidth(250); Label firstNameLabel = new Label("First Name:"); Label lastNameLabel = new Label("Last Name:"); Label emailLabel = new Label("Email:"); editPane.add(firstNameLabel, 0, 3); editPane.add(firtNameField, 1, 3); editPane.add(lastNameLabel, 0, 4); editPane.add(lastNameField, 1, 4); editPane.add(emailLabel, 0, 5); editPane.add(emailField, 1, 5); GridPane.setHalignment(firstNameLabel, HPos.RIGHT); GridPane.setHalignment(lastNameLabel, HPos.RIGHT); GridPane.setHalignment(emailLabel, HPos.RIGHT); Button saveButton = new Button("Save"); saveButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { if (fPerson == null) { fPerson = new Person( firtNameField.getText(), lastNameField.getText(), emailField.getText()); data.add(fPerson); } else { int k = -1; if (data.size() > 0) { for (int i = 0; i < data.size(); i++) { if (data.get(i) == fPerson) { k = i; } } } fPerson.setFirstName(firtNameField.getText()); fPerson.setLastName(lastNameField.getText()); fPerson.setEmail(emailField.getText()); data.set(k, fPerson); table.setItems(data); // The following will work, but edited person has to be added to the button // // data.remove(fPerson); // data.add(fPerson); // add and remove refresh the table, but now move edited person to original spot, // it failed again with the following code // while (data.indexOf(fPerson) != k) { // int i = data.indexOf(fPerson); // Collections.swap(data, i, i - 1); // } } editView.close(); } }); Button cancelButton = new Button("Cancel"); cancelButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { editView.close(); } }); HBox saveCancelButtonBox = new HBox(); saveCancelButtonBox.getChildren().addAll(saveButton, cancelButton); saveCancelButtonBox.setAlignment(Pos.CENTER_RIGHT); saveCancelButtonBox.setSpacing(3); VBox editBox = new VBox(); editBox.getChildren().addAll(editPane, saveCancelButtonBox); Scene editScene = new Scene(editBox); editView.setTitle("Person"); editView.initStyle(StageStyle.UTILITY); editView.initModality(Modality.APPLICATION_MODAL); editView.setScene(editScene); editView.close(); final VBox vbox = new VBox(); vbox.setSpacing(5); vbox.getChildren().addAll(label, table, addEditDeleteButtonBox); vbox.setPadding(new Insets(10, 0, 0, 10)); ((Group) scene.getRoot()).getChildren().addAll(vbox); stage.setScene(scene); stage.show(); } }

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  • Syncronizing mobile phone contacts with contacts from social networks

    - by Pentium10
    I retrieve a JSON list of contacts from a social network site. It contains firstname, lastname, displayname, data1, data2, etc... What is the efficient way to quickly lookup my local phone contacts database and "match" them based on their name. Since there are firstname, lastname and displayname this can vary. What do you think, how can the best match be achieved? Also how do I make sure I don't parse for each JSON item the whole database I want to avoide having JSON_COUNT x MOBILE COUNT steps.

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  • SQL Server: How to remove empty lines in SSMS?

    - by atricapilla
    I have many .sql files with lots of empty lines e.g. WITH cteTotalSales (SalesPersonID, NetSales) AS ( SELECT SalesPersonID, ROUND(SUM(SubTotal), 2) FROM Sales.SalesOrderHeader WHERE SalesPersonID IS NOT NULL GROUP BY SalesPersonID ) SELECT sp.FirstName + ' ' + sp.LastName AS FullName, sp.City + ', ' + StateProvinceName AS Location, ts.NetSales FROM Sales.vSalesPerson AS sp INNER JOIN cteTotalSales AS ts ON sp.BusinessEntityID = ts.SalesPersonID ORDER BY ts.NetSales DESC Is ther a way to remove these empty lines in SQL Server Management Studio? This is what I would like to have: WITH cteTotalSales (SalesPersonID, NetSales) AS ( SELECT SalesPersonID, ROUND(SUM(SubTotal), 2) FROM Sales.SalesOrderHeader WHERE SalesPersonID IS NOT NULL GROUP BY SalesPersonID ) SELECT sp.FirstName + ' ' + sp.LastName AS FullName, sp.City + ', ' + StateProvinceName AS Location, ts.NetSales FROM Sales.vSalesPerson AS sp INNER JOIN cteTotalSales AS ts ON sp.BusinessEntityID = ts.SalesPersonID ORDER BY ts.NetSales DESC

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  • ASP.NET WebMethod Returns JSON wrapped in quotes

    - by CL4NCY
    Hi, I have an asp.net page with a WebMethod on it to pass JSON back to my javascript. Bellow is the web method: [WebMethod] public static string getData(Dictionary<string, string> d) { string response = "{ \"firstname\": \"John\", \"lastname\": \"Smith\" }"; return response; } When this is returned to the client it is formatted as follows: { \"d\": \"{ \"firstname\": \"John\", \"lastname\": \"Smith\" }\" } The problem is the double quotes wrapping everything under 'd'. Is there something I've missed in the web method or some other means of returning the data without the quotes? I don't really want to be stripping it out on the client everytime. Also I've seen other articles where this doesn't happen. Any help would be appreciated thanks.

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  • mysql left outer join

    - by tirso
    hi to all I have two tables employee and timecard, employee table has fields employee_id,firstname,middlename,lastname and timecard table has fields employee_id,time-in,time-out,tc_date_transaction. I want to select all employee records which have the same employee_id with timecard and date is equal with the current date. If there are no records equal with the current date then return also the records of employee even without time-in,timeout and tc_date_transaction. I have query like this SELECT * FROM employee LEFT OUTER JOIN timecard ON employee.employee_id = timecard.employee_id WHERE tc_date_transaction = "17/06/2010"; result should like this: employee_id,firstname, middlename, lastname,time-in,time-out,tc_date_transaction 1,john,t,cruz,08:00,05:00,17/06/2010 2,mary,j,von,null,null,null any help would greatly appreciated Thanks in advance

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  • Lua: Why changing value on one variable changes value on an other one too?

    - by user474563
    I think that running this code you will get excactly what I mean. I want to register 5 names to a register(people). I loop 5 times and in each loop I have a variable newPerson which is supposed to save all information about a person and then be added to the people register. In this example only the names of the people are being registered for simplicity. The problem is that in the end all people turn to have the same name: "Petra". I playied a bit with this but can't get a reasonable reason for this behaviour. Help appreciated! local people={} local person={ name="Johan", lastName="Seferidis", class="B" } local names={"Markus", "Eva", "Nikol", "Adam", "Petra"} --people to register for i=1, 5 do --register 5 people local newPerson=person local name=names[i] for field=1, 3 do --for each field(name, lastname, class) if field==1 then newPerson["name"]=name end --register name end people[i]=newPerson end print("First person name: " ..people[1]["name"]) print("Second person name: "..people[2]["name"]) print("Third person name: " ..people[3]["name"])

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  • Implementing sub fields in a PropertyGrid

    - by evolve
    Alright so my terminology when it comes to C# isn't great, so I'll attempt to explain this with a small example. If you create a class which you are using within a PropertyGrid and you have the following values: class Test { public Point example { get; set; } } This will produce a PropertyGrid which has an expandable object "example" which has fields X and Y in order to create a "Point". I'm attempting to create an object "name" which has fields "firstname" and "lastname", so I have: class Test { public Name example { get; set; } } public struct Name { public string firstname { get; set; } public string lastname { get; set; } } This however isn't working as intended. I think I need to override some method(s) in order to get this working, however since I don't really have the terminology down for PropertyGrids it is difficult for me to find a solution. Any help would be great.

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  • error in mysql syntax in vb.net

    - by user225269
    I get this error, while I'm testing the code below: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[student](ID, LASTNAME, FIRSTNAME, SCHOOL) VALUES ('333', 'aaa', 'aaa', 'aaa')' at line 1 I just recycled the code that I used in manipulating ms sql database. So the syntax must be wrong. What might be the correct syntax for adding records into mysql database? Here is my current code: idnum = TextBox1.Text lname = TextBox2.Text fname = TextBox3.Text skul = TextBox4.Text Using sqlcon As New MySqlConnection("Server=localhost; Database=testing;Uid=root;Pwd=nitoryolai123$%^;") sqlcon.Open() Dim sqlcom As New MySqlCommand() sqlcom.Connection = sqlcon sqlcom.CommandText = "INSERT INTO [student](ID, LASTNAME, FIRSTNAME, SCHOOL) VALUES (@ParameterID, @ParameterLastName, @ParameterFirstName, @ParameterSchool)" sqlcom.Parameters.AddWithValue("@ParameterID", TextBox1.Text) sqlcom.Parameters.AddWithValue("@ParameterLastName", TextBox2.Text) sqlcom.Parameters.AddWithValue("@ParameterFirstName", TextBox3.Text) sqlcom.Parameters.AddWithValue("@ParameterSchool", TextBox4.Text) sqlcom.ExecuteNonQuery() End Using Please help, thanks

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  • Using Full-Text Search in SQL Server 2005 across multiple tables, columns

    - by crisgomez
    Hi, I have a problem, I created a full text search query which return a record(s), in which the paramater I have supplied match(es) in every fields(full-text indexed) of multiple tables. The problem is , when the user.id is equal to ceritification.AId it returns a records eventhough it was not satisfied with the parameter supplied. For this example I supplied a value "xandrick" which return an Id=184, but the problem is it returns two ids which is 184 and 154.What is the best way to return an ID(s) that satisfied of the supplied given value? User table Id Firstname Lastname Middlename Email AlternativeEmail 154 Gregorio Honasan Pimentel [email protected] [email protected] 156 Qwerty Qazggf fgfgf [email protected]. [email protected] 184 Xandrick Flores NULL [email protected] null Certification table Id AID Certification School 12 184 sdssd AMA 13 43 web-based and framework 2 Asian development foundation college 16 184 hjhjhj STI 17 184 rrrer PUP 18 154 vbvbv AMA SELECT DISTINCT Users.Id FROM Users INNER JOIN Certification on Users.Id=Certification.aid LEFT JOIN FREETEXTTABLE (Users,(Firstname,Middlename,Lastname,Email,AlternativeEmail), 'xandrick' )as ftUsr ON Users.Id=ftUsr.[KEY] LEFT JOIN FREETEXTTABLE (Certification,(Certification,School), 'xandrick' )as ftCert ON Certification.Id=ftCert.[KEY]

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  • node.js with SQL Server Native Client 11 scope_identity not being returned

    - by binderbound
    I'm having trouble with inserting a value into a database through node.js. Here is the offending code: sql.query(conn_str ,"INSERT INTO Login(email, hash, salt, firstName, lastName) VALUES(?, ?, ?, ?, ?); SELECT SCOPE_IDENTITY() AS 'Identity';" , [email, hash, salt, firstName, lastName], function(err, results){ console.log(results) } Unfortunately, the console is just echoing [], meaning results is an empty array, I suppose. Does anyone know why the identity is not being returned? Even if it was null, why isn't results then [{Identity: null }] ? Database is on Azure, which does have a "Scope_Identity" function, and the native client also recognises this function. Using node package "msnodesql" Please Help

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  • Java Mvc And Hibernate

    - by GigaPr
    Hi i am trying to learn Java, Hibernate and the MVC pattern. Following various tutorial online i managed to map my database, i have created few Main methods to test it and it works. Furthermore i have created few pages using the MVC patter and i am able to display some mock data as well in a view. the problem is i can not connect the two. this is what i have My view Looks like this <%@ include file="/WEB-INF/jsp/include.jsp" %> <html> <head> <title>Users</title> <%@ include file="/WEB-INF/jsp/head.jsp" %> </head> <body> <%@ include file="/WEB-INF/jsp/header.jsp" %> <img src="images/rss.png" alt="Rss Feed"/> <%@ include file="/WEB-INF/jsp/menu.jsp" %> <div class="ContainerIntroText"> <img src="images/usersList.png" class="marginL150px" alt="Add New User"/> <br/> <br/> <div class="usersList"> <div class="listHeaders"> <div class="headerBox"> <strong>FirstName</strong> </div> <div class="headerBox"> <strong>LastName</strong> </div> <div class="headerBox"> <strong>Username</strong> </div> <div class="headerAction"> <strong>Edit</strong> </div> <div class="headerAction"> <strong>Delete</strong> </div> </div> <br><br> <c:forEach items="${users}" var="user"> <div class="listElement"> <c:out value="${user.firstName}"/> </div> <div class="listElement"> <c:out value="${user.lastName}"/> </div> <div class="listElement"> <c:out value="${user.username}"/> </div> <div class="listElementAction"> <input type="button" name="Edit" title="Edit" value="Edit"/> </div> <div class="listElementAction"> <input type="image" src="images/delete.png" name="image" alt="Delete" > </div> <br /> </c:forEach> </div> </div> <a id="addUser" href="addUser.htm" title="Click to add a new user">&nbsp;</a> </body> </html> My controller public class UsersController implements Controller { private UserServiceImplementation userServiceImplementation; public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ModelAndView modelAndView = new ModelAndView("users"); List<User> users = this.userServiceImplementation.get(); modelAndView.addObject("users", users); return modelAndView; } public UserServiceImplementation getUserServiceImplementation() { return userServiceImplementation; } public void setUserServiceImplementation(UserServiceImplementation userServiceImplementation) { this.userServiceImplementation = userServiceImplementation; } } My servelet definitions <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <bean name="/home.htm" class="com.rssFeed.mvc.HomeController"/> <bean name="/rssFeeds.htm" class="com.rssFeed.mvc.RssFeedsController"/> <bean name="/addUser.htm" class="com.rssFeed.mvc.AddUserController"/> <bean name="/users.htm" class="com.rssFeed.mvc.UsersController"> <property name="userServiceImplementation" ref="userServiceImplementation"/> </bean> <bean id="userServiceImplementation" class="com.rssFeed.ServiceImplementation.UserServiceImplementation"> <property name="users"> <list> <ref bean="user1"/> <ref bean="user2"/> </list> </property> </bean> <bean id="user1" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName1"/> <property name="lastName" value="lastName1"/> <property name="username" value="username1"/> <property name="password" value="password1"/> </bean> <bean id="user2" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName2"/> <property name="lastName" value="lastName2"/> <property name="username" value="username2"/> <property name="password" value="password2"/> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans> and finally this class to access the database public class HibernateUserDao extends HibernateDaoSupport implements UserDao { public void addUser(User user) { getHibernateTemplate().saveOrUpdate(user); } public List<User> get() { User user1 = new User(); user1.setFirstName("FirstName"); user1.setLastName("LastName"); user1.setUsername("Username"); user1.setPassword("Password"); List<User> users = new LinkedList<User>(); users.add(user1); return users; } public User get(int id) { throw new UnsupportedOperationException("Not supported yet."); } public User get(String username) { return null; } } the database connection occurs in this file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver"/> <property name="url" value="jdbc:hsqldb:hsql://localhost/rss"/> <property name="username" value="sa"/> <property name="password" value=""/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean" > <property name="dataSource" ref="dataSource" /> <property name="mappingResources"> <list> <value>com/rssFeed/domain/User.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <props> <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory"/> </bean> <bean id="userDao" class="com.rssFeed.dao.hibernate.HibernateUserDao"> <property name="sessionFactory" ref="sessionFactory"/> </bean> </beans> Could you help me to solve this problem i spent the last 4 days and nights on this issue without any success Thanks

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  • new line in java

    - by user225269
    Java newbie here, I'm having trouble setting a new line in this code: String FnameTextboxText = FnameTextbox.getText(); String LastnameTextboxText = LastnameTextbox.getText(); String CourseTextboxText = CourseTextbox.getText(); Summary.setText("Firstname:" + " " + FnameTextboxText + "\nLastname:" + " " + LastnameTextboxText + "\nCourse:" + " " + CourseTextboxText); Also tried something like: "\n" + "Lastname" But its no good. Do you have any idea on how to make new lines. So that it'll look like this; Firstname: x Lastname: y Course: Z Using netbeans 6.8. On windows.

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  • EntityFramework & RowNumber

    - by Dan
    Hello. How can I query RowNumber with Entity Framework? For example: var result = data.Users .OrderByDescending("Birthday") .ThenBy("LastName") .ThenBy("FirstName") .Select(u => { RowNumber = ???, u.FirstName, u.LastName }); I want to implement paging for my grid, but I cannot solve problem with finding page with needed user. I'm using EF4.0. Select method with index(http://msdn.microsoft.com/en-us/vcsharp/aa336758.aspx#SelectIndexed) not works with EF. May be there is another way to implement this?

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  • ASP.NET MVC 2: Deserialize SPROC Response

    - by dcolumbus
    I need to ask a general question. I don't have the code in front of me because I'm writing this on my iPhone. I have a Class that represents a certain XML schema. I have a SPROC that returns this XML. What I need to do is deserialize the XML to this Class. XML: <xml> <person> <firstName>Bob</firstName> <lastName>Robby</lastName> </person> </xml> I need to deserialize this XML into the custom Person Class so I can loop through this Model and spit it out in the View. I'm sure there's some kind of casting involved, I just don't know how to do it.

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  • SQL: How can i update a value on a column only if that value is null?

    - by user321185
    Hey, I have an SQL question which may be basic to some but is confusing me. Here is an example of column names for a table 'Person': PersonalID, FirstName, LastName, Car, HairColour, FavDrink, FavFood Let's say that I input the row: 121312, Rayna, Pieterson, BMW123d, Brown, NULL, NULL Now I want to update the values for this person, but only if the new value is not null, Update: 121312, Rayna, Pieterson, NULL, Blonde, Fanta, NULL The new row needs to be: 121312, Rayna, Pieterson, BMW123d, Blonde, Fanta, NULL So I was thinking something along the lines of: Update Person(PersonalID, FirstName, LastName, Car, HairColour, FavDrink, FavFood) set Car = @Car (where @Car is not null), HairColour = @HairColour (where @HairColour...)... etc. My only concern is that I can't group all the conditions at the end of the query because it will require all the values to have the same condition. Can't i do something like Update HairColour if @HairColour is not Null

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  • Jquery problem with errorPlacement.

    - by Eyla
    Greetings, I have problem with errorPlacement, I'm trying to place the error message next to the field but it appearing on the top of the page. any advice how to fix this problem?? here is my code: <%@ Page Title="" Language="C#" MasterPageFile="~/Master.Master" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="IMAM_APPLICATION.WebForm1" %> <%@ Register assembly="AjaxControlToolkit" namespace="AjaxControlToolkit" tagprefix="asp" %> <asp:Content ID="Content1" ContentPlaceHolderID="head" runat="server"> <script src="js/jquery-1.4.1.js" type="text/javascript"></script> <script src="js/jquery.validate.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { $("#aspnetForm").validate({ groups: { username: "fname lname", address: "address1 phone" }, errorPlacement: function(error, element) { if (element.attr("name") == "fname" || element.attr("name") == "lname") error.insertAfter("#lastname"); else error.insertAfter(element); }, debug: true }) }); </script> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="ContentPlaceHolder1" runat="server"> </asp:Content> <asp:Content ID="Content3" ContentPlaceHolderID="ContentPlaceHolder2" runat="server"> <p style="height: 313px"> <label style="position:absolute; top: 227px; left: 22px;">Your Name</label> &nbsp;<input name="fname" value="Pete" style="position:absolute; top: 226px; left: 102px;"/> <input name="lname" id="lastname" style="position:absolute; top: 264px; left: 95px;"/> <input name="address1" style="position:absolute; top: 347px; left: 102px;"/> <input name="phone" id="lastname" style="position:absolute; top: 315px; left: 102px;"/> <br/> <input type="submit" value="Submit Name" style="position:absolute; top: 407px; left: 73px;"/> <input type="submit" value="Submit Address" style="position:absolute; top: 370px; left: 437px;"/> </p> </asp:Content>

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  • A better UPDATE method in LINQ to SQL

    - by Refracted Paladin
    The below is a typical, for me, Update method in L2S. I am still fairly new to a lot of this(L2S & business app development) but this just FEELs wrong. Like there MUST be a smarter way of doing this. Unfortunately, I am having trouble visualizing it and am hoping someone can provide an example or point me in the right direction. To take a stab in the dark, would I have a Person Object that has all these fields as Properties? Then what, though? Is that redundant since L2S already mapped my Person Table to a Class? Is this just 'how it goes', that you eventually end up passing 30 parameters(or MORE) to an UPDATE statement at some point? For reference, this is a business app using C#, WinForms, .Net 3.5, and L2S over SQL 2005 Standard. Here is a typical Update Call for me. This is in a file(BLLConnect.cs) with other CRUD methods. Connect is the name of the DB that holds tblPerson When a user clicks save() this is what is eventually called with all of these fields having, potentially, been updated-- public static void UpdatePerson(int personID, string userID, string titleID, string firstName, string middleName, string lastName, string suffixID, string ssn, char gender, DateTime? birthDate, DateTime? deathDate, string driversLicenseNumber, string driversLicenseStateID, string primaryRaceID, string secondaryRaceID, bool hispanicOrigin, bool citizenFlag, bool veteranFlag, short ? residencyCountyID, short? responsibilityCountyID, string emailAddress, string maritalStatusID) { using (var context = ConnectDataContext.Create()) { var personToUpdate = (from person in context.tblPersons where person.PersonID == personID select person).Single(); personToUpdate.TitleID = titleID; personToUpdate.FirstName = firstName; personToUpdate.MiddleName = middleName; personToUpdate.LastName = lastName; personToUpdate.SuffixID = suffixID; personToUpdate.SSN = ssn; personToUpdate.Gender = gender; personToUpdate.BirthDate = birthDate; personToUpdate.DeathDate = deathDate; personToUpdate.DriversLicenseNumber = driversLicenseNumber; personToUpdate.DriversLicenseStateID = driversLicenseStateID; personToUpdate.PrimaryRaceID = primaryRaceID; personToUpdate.SecondaryRaceID = secondaryRaceID; personToUpdate.HispanicOriginFlag = hispanicOrigin; personToUpdate.CitizenFlag = citizenFlag; personToUpdate.VeteranFlag = veteranFlag; personToUpdate.ResidencyCountyID = residencyCountyID; personToUpdate.ResponsibilityCountyID = responsibilityCountyID; personToUpdate.EmailAddress = emailAddress; personToUpdate.MaritalStatusID = maritalStatusID; personToUpdate.UpdateUserID = userID; personToUpdate.UpdateDateTime = DateTime.Now; context.SubmitChanges(); } }

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  • Removing the Default Wrap Character From all records

    - by aceinthehole
    I am using BizTalk 2009 and I have a flat file that is similar to the following "0162892172","TIM ","LastName ","760 "," ","COMANCHE ","LN " "0143248282","GEORGE ","LastName ","625 "," ","ENID ","AVE " When I parse it and start mapping it I need to get rid of the quotation marks. I have marked the Wrap Character attribute for the schema as a quotation mark but it doesn't remove it when BizTalk is parsing the file. Is there an easy way to specify the removal of a wrap character or am I going to have to run it through a script functiod every time? Also I would like to be able to remove the trailing spaces as well, if at all possible.

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  • Comparing an id to id of different tables rows mysql

    - by jett
    So I am trying to retrieve all interests from someone, and be able to list them. This works with the following query. SELECT *,( SELECT GROUP_CONCAT(interest_id SEPARATOR ",") FROM people_interests WHERE person_id = people.id ) AS interests FROM people WHERE id IN ( SELECT person_id FROM people_interests WHERE interest_id = '.$site->db->clean($_POST['showinterest_id']).' ) ORDER BY lastname, firstname In this one which I am having trouble with, I want to select only those who happen to have their id in the table named volleyballplayers. The table just has an id, person_id, team_id, and date fields. SELECT *,( SELECT GROUP_CONCAT(interest_id SEPARATOR ",") FROM people_interests WHERE person_id = people.id ) AS interests FROM people WHERE id IN ( SELECT person_id FROM people_interests WHERE volleyballplayers.person_id = person_id ) ORDER BY lastname, firstname I just want to make sure that only the people who are in the volleyballplayers table show up, but I am getting an error saying that Unknown column 'volleyballplayers.person_id' in 'where clause' although I am quite sure of the name of table and I know the column is named person_id.

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  • c#, can you think of anymore optimization in this code?

    - by Sha Le
    Hi All: Look at the following code: StringBuilder row = TemplateManager.GetRow("xyz"); // no control over this method StringBuilder rows = new StringBuilder(); foreach(Record r in records) { StringBuilder thisRow = new StringBuilder(row.ToString()); thisRow.Replace("%firstName%", r.FirstName) .Replace("%lastName%", r.LastName) // all other replacement goes here .Replace("%LastModifiedDate%", r.LastModifiedDate); //finally append row to rows rows.Append(thisRow); } Currently 3 StringBuilders and row.ToString() is inside a loop. Is there any room for further optimization here? Thanks a bunch. :-)

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  • Linq Query ignore empty parameters

    - by Cj Anderson
    How do I get Linq to ignore any parameters that are empty? So Lastname, Firstname, etc? If I have data in all parameters it works fine. refinedresult = From x In theresult _ Where x.<thelastname>.Value.TestPhoneElement(LastName) Or _ x.<thefirstname>.Value.TestPhoneElement(FirstName) Or _ x.<id>.Value.TestPhoneElement(Id) Or _ x.<number>.Value.TestPhoneElement(Telephone) Or _ x.<location>.Value.TestPhoneElement(Location) Or _ x.<building>.Value.TestPhoneElement(building) Or _ x.<department>.Value.TestPhoneElement(Department) _ Select x Public Function TestPhoneElement(ByVal parent As String, ByVal value2compare As String) As Boolean 'find out if a value is null, if not then compare the passed value to see if it starts with Dim ret As Boolean = False If String.IsNullOrEmpty(parent) Then Return False End If If String.IsNullOrEmpty(value2compare) Then Return ret Else ret = parent.ToLower.StartsWith(value2compare.ToLower.Trim) End If Return ret End Function

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