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• How to leave out some statements while executing java code?

  - by iamrohitbanga

  In C++ if we do not want some statements to compile into code that ships like assert function calls, we control their compilation through #ifndef preprocessor directives. How do we do this in Java? I have some System.out.println() statements for debugging which I would like to remove for the final code. one way is to make them execute conditionally under the affect of a boolean variable. Is there a better way of doing this? As I have a java swing application I can turn off the System.out.println statements without affecting the output. What is the method of doing this?

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• What is the explanation of this results in Java ?

  - by M.H

  I have the following code : public class Main { private int i = j; //1 private int j = 10; public static void main(String[] args) { System.out.println((new Main()).i); } } and there is a compiler error in line 1 because an illegal forward reference. But when I am trying the following code : public class Main { int i = getJ(); //1 int getJ(){ return j; } int j=10; public static void main(String[] args) { System.out.println(new Main().i); } } it works fine and the result is 0.Why there is no illegal forward reference in line 1 here?.The two codes look similar to me.

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• Distinguish between a single click and a double click in Java

  - by user552279

  Hi, I search the forum and see this codes: public void mouseClicked(MouseEvent e) { if (e.getClickCount() == 2) { System.out.println(" and it's a double click!"); wasDoubleClick = true; } else { Integer timerinterval = (Integer) Toolkit.getDefaultToolkit().getDesktopProperty( "awt.multiClickInterval"); timer = new Timer(timerinterval.intValue(), new ActionListener() { public void actionPerformed(ActionEvent evt) { if (wasDoubleClick) { wasDoubleClick = false; // reset flag } else { System.out.println(" and it's a simple click!"); } } }); timer.setRepeats(false); timer.start(); } } but the code runs incorrectly(Sometime it prints out " and it's a single click!" 2 times . It should print out " and it's a double click!"). Can anybody show me why? or can you give me some better ways to do this? Thank you!

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• apache commons http client efficiency

  - by wo_shi_ni_ba_ba

  I use apache commons http client to send data via post every second, is there a way to make the following code more efficient? I know http is stateless, but is there anything I can do to improve since the base url is always the same in this case(only the parameter value change. private void sendData(String s){ try { HttpClient client = getHttpClient(); HttpPost method = new HttpPost("http://192.168.1.100:8080/myapp"); System.err.println("send to server "+s); List formparams = new ArrayList(); formparams.add(new BasicNameValuePair("packet", s)); UrlEncodedFormEntity entity = new UrlEncodedFormEntity(formparams, "UTF-8"); method.setEntity(entity); HttpResponse resp=client.execute(method); String res = EntityUtils.toString(resp.getEntity()); System.out.println(res); } catch (Exception e) { e.printStackTrace(); } } private HttpClient getHttpClient() { if(httpClient==null){ httpClient = new DefaultHttpClient(); } return httpClient; }

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• Scala : cleanest way to recursively parse files checking for multiple strings

  - by fred basset

  Hi All, I want to write a Scala script to recursively process all files in a directory. For each file I'd like to see if there are any cases where a string occurs at line X and line X - 2. If a case like that occurs I'd like to stop processing that file, and add that filename to a map of filenames to occurrence counts. I just started learning Scala today, I've got the file recurse code working, and need some help with the string searching, here's what I have so far: import java.io.File import scala.io.Source val s1= "CmdNum = 506" val s2 = "Data = [0000,]" def processFile(f: File) { val lines = scala.io.Source.fromFile(f).getLines.toArray for (i = 0 to lines.length - 1) { // want to do string searches here, see if line contains s1 and line two lines above also contains s1 //println(lines(i)) } } def recursiveListFiles(f: File): Array[File] = { val these = f.listFiles if (these != null) { for (i = 0 to these.length - 1) { if (these(i).isFile) { processFile(these(i)) } } these ++ these.filter(_.isDirectory).flatMap(recursiveListFiles) } else { Array[File]() } } println(recursiveListFiles(new File(args(0))))

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• Matching Line Boundaries in a Regular Expression (Pattern.MULTILINE/(?m)) is broken in Java?

  - by Mister M. Bean

  The example on http://www.exampledepot.com/egs/java.util.regex/Line.html gives false for me twice but should'nt! Why? CharSequence inputStr = "abc\ndef"; String patternStr = "abc$"; // Compile with multiline enabled Pattern pattern = Pattern.compile(patternStr, Pattern.MULTILINE); Matcher matcher = pattern.matcher(inputStr); boolean matchFound = matcher.find(); // true // Use an inline modifier to enable multiline mode matchFound = pattern.matches(".*abc$.*", "abc\r\ndef"); // false System.out.println(matchFound); // false matchFound = pattern.matches("(?m).*abc$.*", "abc\r\ndef"); // true System.out.println(matchFound);// false !!!!!

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• Behavior of nested finally in Exceptions

  - by kuriouscoder

  Hello: Today at work, I had to review a code snippet that looks similar to this mock example. package test; import java.io.IOException; import org.apache.log4j.Logger; public class ExceptionTester { public static Logger logger = Logger.getLogger(ExceptionTester.class); public void test() throws IOException { new IOException(); } public static void main(String[] args) { ExceptionTester comparator = new ExceptionTester(); try { try { comparator.test(); } finally { System.out.println("Finally 1"); } } catch(IOException ex) { logger.error("Exception happened" ex); // also close opened resources } System.out.println("Exiting out of the program"); } } It's printing the following output.I expected an compile error since the inner try did not have a catch block. Finally 1 Exiting out of the program I do not understand why IOException is caught by the outer catch block. I would appreciate if anyone can explain this, especially by citing stack unwinding process

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• How to read comma separated values from text file in JAVA?

  - by user1425223

  I have got this text file with latitude and longitude values of different points on a map. I want to store these coordinates into a mySQL database using hibernate. I want to know how can I split my string into latitudes and longitudes? What is the general way to do these type of things that is with other delimiters like space, tab etc.? File: 28.515046280572285,77.38258838653564 28.51430151808072,77.38336086273193 28.513566177802456,77.38413333892822 28.512830832397192,77.38490581512451 28.51208605426073,77.3856782913208 28.511341270865113,77.38645076751709 28.510530488025346,77.38720178604126 28.509615992924807,77.38790988922119 28.50875805732363,77.38862872123718 28.507994394490268,77.38943338394165 28.50728729434496,77.39038825035095 28.506674470385246,77.39145040512085 28.506174780521828,77.39260911941528 28.505665660113582,77.39376783370972 28.505156537248446,77.39492654800415 28.50466626846366,77.39608526229858 28.504175997400655,77.39724397659302 28.503685724059455,77.39840269088745 28.503195448440064,77.39956140518188 28.50276174118543,77.4007523059845 28.502309175192945,77.40194320678711 28.50185660725938,77.40313410758972 28.50140403738471,77.40432500839233 28.500951465568985,77.40551590919495 28.500498891812207,77.40670680999756 28.5000463161144,77.40789771080017 28.49959373847559,77.40908861160278 Code I am using to read from file: try { BufferedReader in = new BufferedReader(new FileReader("G:\\RoutePPAdvant2.txt")); String str; str = in.readLine(); while ((str = in.readLine()) != null) { System.out.println(str); } in.close(); } catch (IOException e) { System.out.println("File Read Error"); }

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• doubt in Exceptions

  - by Ajay Singh

  class MyException extends Exception { MyException() {} MyException(String msg) { super(msg);} } public class NewException { static void f() throws MyException { System.out.println("throwing exception from f()"); throw new ClassCastException(); } static void g() throws MyException { System.out.println("throwing exception from g()"); throw new MyException("parametrized "); } public static void main(String ...strings ) { try { f(); } catch(MyException e) { e.printStackTrace(System.out); } try { g(); } catch(MyException e) { e.printStackTrace(System.out); } } } In the function f() iam specifying that "MyException " exception will be thrown and actually iam throwing some other exception which has no relation with MyException but still the compiler does not report any complain.Why is it so??

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• create and insert values using mysql JDBC

  - by S.PRATHIBA

  Hi all, I have the sample code. public void UpdateTable1() { for(int t=0;t<20;t++) { if(consumer==1 && number==1 && provider1==31 && feedback==1) { try{ Class.forName(driverName); con = DriverManager.getConnection(url+dbName,"root","mysql"); try { Statement st = con.createStatement(); int val = st.executeUpdate("INSERT Consumer1 VALUES ("+31+","+"'Printer'"+", "+1+" "+")"); System.out.println("1 row affected"); } catch (SQLException s) { System.out.println("SQL statement is not executed!"); } con.close(); } I want to insert the same set of values(31,printer,1) into the table consumer2,consumer3.Is it possible without using another try catch statements...Please help me.

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• Do "if" statements affect in the time complexity analysis?

  - by FranXh

  According to my analysis, the running time of this algorithm should be N2, because each of the loops goes once through all the elements. I am not sure whether the presence of the if statement changes the time complexity? for(int i=0; i<N; i++){ for(int j=1; j<N; j++){ System.out.println("Yayyyy"); if(i<=j){ System.out.println("Yayyy not"); } } }

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• Why does Java return a date in GMT-4.5 when choosing Co-ordinated Universal Time time zone in Window

  - by Simon Nickerson

  We have seen a strange issue on some Windows XP machines involving the "Co-ordinated Universal Time" time zone. Not all Windows XP machines seem to have it, but on those that do, the following simple Java program public class TimeTest { public static void main(String[] args) { System.out.println(java.util.TimeZone.getDefault()); System.out.println(new java.util.Date()); } } on JDK 1.6.0_06 prints: sun.util.calendar.ZoneInfo[id="America/Caracas",offset=-16200000,dstSavings=0,useDaylight=false,transitions=5,lastRule=null] Fri Nov 13 05:34:14 VET 2009 (i.e. 4 and a half hours behind GMT). I should add that I am based in London, and have never been to South America. :-) My questions are: Where does Java get this time zone from? I thought Co-ordinated Universal Time was supposed to be the new name for GMT. Why do some Windows machines have this time zone but not others?

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• Why does the right-shift operator produce a zero instead of a one?

  - by mrt181

  Hi, i am teaching myself java and i work through the exercises in Thinking in Java. On page 116, exercise 11, you should right-shift an integer through all its binary positions and display each position with Integer.toBinaryString. public static void main(String[] args) { int i = 8; System.out.println(Integer.toBinaryString(i)); int maxIterations = Integer.toBinaryString(i).length(); int j; for (j = 1; j < maxIterations; j++) { i >>= 1; System.out.println(Integer.toBinaryString(i)); } In the solution guide the output looks like this: 1000 1100 1110 1111 When i run this code i get this: 1000 100 10 1 What is going on here. Are the digits cut off? I am using jdk1.6.0_20 64bit. The book uses jdk1.5 32bit.

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• Accessing variablss through a different class within the constructor of latter classes of an object

  - by Haxed

  In the code below, I've added two lines that print output. The first line prints junk as usual, but surprisingly the second one gives me a compilation error. Why? class Student { private String name; public Student(String name){ this.name = name; } public String getName(){ return name; } } class StudentServer { public StudentServer(){ Student[] s = new Student[30]; s[0] = new Student("Nick"); // LINE 01: This compiles, although prints junk System.out.println(s[0]); // LINE 02: I get a error called cannot find symbol System.out.println(s[0].getName()); } public static void main(){ new StudentServer(); } } Many Thanks

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• Why baseclass calls method of subclass?

  - by twlkyao

  I encounter some code like the following: BaseClass: public class BaseClass { String name = "Base"; public BaseClass() { printName(); } public void printName() { System.out.println(name + "——Base"); } } DrivedClass: public class SubClass extends BaseClass { String name = "Sub"; public SubClass() { printName(); } public void printName() { System.out.println(name + "——Sub"); } public static void main(String[] args) { new SubClass(); } } When run the code, the output is: null——Sub Sub——Sub while it should be: Base——Base Sub——Sub I wonder why the BaseClass constructor calls the SubClass method, can anybody explain this? Thanks in advance.

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• Creation obex connection without service discovery

  - by Vio

  Hello there my problem is this,i want to create an obex connection but i already know my server adress.The problem is how to get the connection url without service discovery.I use a normal java project for my server side and a midlet project for my client side.I will post the code maybe it helps. Server connection UUID uuid=new UUID("8841",true); String url="btgoep://localhost:"+uuid+";name=FTP;authenticate=false;master=false;encrypt=false"; SessionNotifier sn=(SessionNotifier)Connector.open(url); System.out.println("Now waiting for a client to connect"); sn.acceptAndOpen(this); System.out.println("A client is now connected"); When i try to connect with the client it doesn't get to the last line :(....any ideas why?Hope u can help...thanks

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• biginteger calculation problem

  - by murali

  I am using the following code but the parameters are not passed to the methods. BigInteger p = BigInteger.valueOf(0); BigInteger u1 = obj.bigi_calc(g1, l); In this g1,l are long values. The method is private BigInteger bigi_calc(long g1, long l){ BigInteger cal = BigInteger.valueOf(g1); BigInteger cal1= BigInteger.valueOf(l); for(BigInteger f = BigInteger.ONE;f.compareTo(cal1)>0;f=f.add(BigInteger.ONE)){ //BigInteger p= BigInteger.valueOf(0); p = cal.multiply(cal1); System.out.println("check p"+p); } // System.out.println("check p"+p); return p; } The elipse shows that it may be out of sync, but the parameters are not passed to the functions. Can you please help me to solve this problem?

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• 2 dimensional arraylists in java

  - by Chris Maness

  So here's the deal I'm working on a project that requires me to have a 2 dimensional arraylist of 1 dimensional arrays. But every time I try to load in my data I get an error: Can't do this opperation because of bad input java.lang.IndexOutOfBoundsException: Index: 1, Size: 0 On some of the inputs. I've got no idea where I'm going wrong on this one. A little help please? Source Code: import java.io.BufferedInputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.util.ArrayList; import java.util.Scanner; import javax.swing.JOptionPane; import java.io.InputStream; public class Facebull { public static void main (String[] args) { if(args.length != 0){ load(args[0]); } else{ load("testFile"); } } public static void load(String fname) { int costOfMach = 0; ArrayList <Integer> finalMach = new ArrayList<Integer>(); ArrayList <ArrayList<int[]>>machines = new ArrayList<ArrayList<int[]>>(); Scanner inputFile = null; File f = new File(fname); if (f.exists ()) { try { inputFile = new Scanner (f); } catch (FileNotFoundException e) { JOptionPane.showMessageDialog(null,"Can't find the file\n" + e); } int i = 0; while (inputFile.hasNext ( )) { String str = inputFile.nextLine ( ); String [ ] fields = str.split ("[\t ]"); System.out.println(str); if (!(fields[0].isEmpty() || fields[0].equals (""))){ fields[0] = fields[0].substring(1); fields[1] = fields[1].substring(1); fields[2] = fields[2].substring(1); try { //data to be inputed is 0 and 3 location of data is 1 and 2 int[] item = new int[2]; item[1] = Integer.parseInt(fields[0]); item[0] = Integer.parseInt(fields[3]); if(machines.size() < Integer.parseInt(fields[1])){ ArrayList<int[]> column = new ArrayList<int[]>(); machines.add (Integer.parseInt(fields[1])-1, column); System.out.println("we're in the if"); } machines.get(Integer.parseInt(fields[1])-1).add(Integer.parseInt(fields[2])-1, item); } //catches any exception catch (Exception e) { System.out.println("Can't do this opperation because of bad input \n" + e); } } } inputFile.close ( ); } System.out.print(machines); }//end load }

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• lwjgl isKeyDown canceling out other keys

  - by AKrush95

  While trying to create a simple game where a square is manipulated via the keyboard keys, I have come across a small, rather irritating problem. I would like it to work so that when the opposite directional key is pressed, the character will stop; the character may move the other two directions while stopped in this situation. This works perfectly with LEFT and RIGHT held down; the player may move UP or DOWN. If UP and DOWN are held down, however, the player will not move, nor will Java recognize that the LEFT or RIGHT keys were pressed. import java.util.ArrayList; import java.util.Random; import org.lwjgl.*; import org.lwjgl.input.Keyboard; import org.lwjgl.opengl.*; import static org.lwjgl.opengl.GL11.*; public class Main { private Man p; private ArrayList<Integer> keysDown, keysUp; public Main() { try { Display.setDisplayMode(new DisplayMode(640, 480)); Display.setTitle("LWJGLHelloWorld"); Display.create(); } catch (LWJGLException e) { e.printStackTrace(); } p = new Man(0, 0); keysDown = new ArrayList<>(); keysUp = new ArrayList<>(); glMatrixMode(GL_PROJECTION); glLoadIdentity(); glOrtho(0, 640, 480, 0, 1, -1); glMatrixMode(GL_MODELVIEW); while (!Display.isCloseRequested()) { glClear(GL_COLOR_BUFFER_BIT); checkKeys(); p.draw(); Display.update(); Display.sync(60); } Display.destroy(); } public void checkKeys() { ArrayList<Integer> keys = new ArrayList<>(); keys.add(Keyboard.KEY_A); keys.add(Keyboard.KEY_D); keys.add(Keyboard.KEY_W); keys.add(Keyboard.KEY_S); for (int key : keys) { if (Keyboard.isKeyDown(key)) keysDown.add(key); else keysUp.add(key); } keysDown.removeAll(keysUp); keysUp = new ArrayList<>(); int speed = 4; int dx = 0; int dy = 0; if (keysDown.contains(keys.get(2))) { System.out.println("keyUP"); dy -= speed; } if (keysDown.contains(keys.get(3))) { System.out.println("keyDOWN"); dy += speed; } if (keysDown.contains(keys.get(0))) { System.out.println("keyLEFT"); dx -= speed; } if (keysDown.contains(keys.get(1))) { System.out.println("keyRIGHT"); dx += speed; } //if (keysDown.contains(keys.get(0)) && keysDown.contains(keys.get(1))) dx = 0; //if (keysDown.contains(keys.get(2)) && keysDown.contains(keys.get(3))) dy = 0; p.update(dx, dy); } public static void main(String[] args) { new Main(); } class Man { public int x, y, w, h; public float cR, cG, cB; public Man(int x, int y) { this.x = x; this.y = y; w = 50; h = 50; Random rand = new Random(); cR = rand.nextFloat(); cG = rand.nextFloat(); cB = rand.nextFloat(); } public void draw() { glColor3f(cR, cG, cB); glRecti(x, y, x+w, y+h); } public void update(int dx, int dy) { x += dx; y += dy; } } } That is the code that I am working with. In addition, I am unsure how to compile an executable jar that is using the lwjgl library in addition to slick-util.

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• schedule task with spring mvc

  - by user3586352

  I want to run the following method every specific time in spring mvc project it works fine and print first output but it doesn't access the database so it doesn't display list the method public class ScheduleService { @Autowired private UserDetailService userDetailService; public void performService() throws IOException { System.out.println("first output"); List<UserDetail> list=userDetailService.getAll(); System.out.println(list); } config file <!-- Spring's scheduling support --> <task:scheduled-tasks scheduler="taskScheduler"> <task:scheduled ref="ScheduleService" method="performService" fixed-delay="2000"/> </task:scheduled-tasks> <!-- The bean that does the actual work --> <bean id="ScheduleService" class="com.ctbllc.ctb.scheduling.ScheduleService" /> <!-- Defines a ThreadPoolTaskScheduler instance with configurable pool size. --> <task:scheduler id="taskScheduler" pool-size="1"/>

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• Log user authentication in grails/acegi

  - by xain

  Hi, where can I put a println in order to register a user's successful authentication in grails using acegi ? Thanks

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• Heap property of this array

  - by davit-datuashvili

  From programming pearls, it is known that array[1...n] has heap property if for all 2<=i<=n x[i/2]<=x[i]. Here is my code: import java.math.*; public class Heap { public static void main(String[]args){ int x[]=new int[]{12,20,15,29,23,17,22,35,40,26,51,19}; int i=1; while (i<x.length) { if (x[Math.round(i/2)]<=x[i]) System.out.println("heap"); i++; } System.out.println("not heap"); } } Here I used Math.round because 4/2 and 5/2 is same and =2. When I compile this code it shows me at last line that it is not heap. Maybe because the index starts from 1 and we don't pay attention to index 0, yes?

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• Current stock price by using sockets in java

  - by user2976396

  My program is to find the current stock price of a symbol ..this is the code which i m using `String yahoo = "finance.yahoo.com" ; final int httpd = 80; Socket sock = new Socket(yahoo,httpd); PrintWriter out = new PrintWriter( sock.getOutputStream(), true ); BufferedReader in =new BufferedReader(new InputStreamReader( sock.getInputStream() ) ); out.println( "GET http://finance.yahoo.com/q?s=ibm&f=1l HTTP/1.0\r\n\r\n " ); out.println(""); out.flush();` I am just getting the output as ibm .Can anyone please suggest how to get the price.

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• Integrate with Google calendar ?

  - by Karthick

  Hi all.I am using the following code to integrate with google calendar. CalendarService myService = new CalendarService("CalService"); myService.setUserCredentials("[email protected]", "xxxxxxx"); URL feedUrl = new URL("https://www.google.com/calendar/feeds/default/private/"); CalendarFeed resultFeed = myService.getFeed(feedUrl, CalendarFeed.class); System.out.println("Your calendars:"); for (int i = 0; i < resultFeed.getEntries().size(); i++) { CalendarEntry entry = resultFeed.getEntries().get(i); System.out.println("\t" + entry.getTitle().getPlainText()); } But it gives the Exception: Invalid credentials ERROR: JDWP Unable to get JNI 1.2 environment, jvm->GetEnv() return code = -2 JDWP exit error AGENT_ERROR_NO_JNI_ENV(183): [../../../src/share/back/util.c:820] Help me to solve this. Can anyone please list the needed jar files to adding calendar events to Google calendar

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• java overloaded method

  - by Sean Nguyen

  Hi, I have an abstract template method: class abstract MyTemplate { public void something(Object obj) { doSomething(obj) } protected void doSomething(Object obj); } class MyImpl extends MyTemplate { protected void doSomething(Object obj) { System.out.println("i am dealing with generic object"); } protected void doSomething(String str) { System.out.println("I am dealing with string"); } } public static void main(String[] args) { MyImpl impl = new MyImpl(); impl.something("abc"); // --> this return "i am dealing with generic object" } How can I print "I am dealing with string" w/o using instanceof in doSomething(Object obj)? Thanks,

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