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  • Auto enter pass phrase in case of Python ssl Client/Server

    - by rauch
    I need to create Client/Server application to send files from clients to Server. I use simple ssl sockets for that and authenticate with certificates. ms = socket.socket(socket.AF_INET, socket.SOCK_STREAM) ssl_sock = ssl.wrap_socket(ms, keyfile=".../newCA/my_client.key", certfile=".../newCA/my_client.crt", server_side=0, cert_reqs=ssl.CERT_REQUIRED, ca_certs=".../newCA/CA/my-ca.crt" ) ssl_sock.connect((HOST, MPORT)) And Server side: msock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) self.ssl_sock = ssl.wrap_socket(msock, keyfile=".../newCA/my_server.key", certfile=".../newCA/my_server.crt", server_side=1, cert_reqs=ssl.CERT_REQUIRED, ca_certs=".../newCA/CA/my-ca.crt" ) self.ssl_sock.bind(('', self.PORT)) self.ssl_sock.listen(self.QUEUE_MAX) The problem is the following: when client tries to connect to Server, it requires Enter the pass phrase for private key for Both: for Server-side and Client-side. In Java we need to set System Property: javax.net.ssl.keyStorePassword="" and it has to be used automatically, But how is it been used in Python? I can't enter pass phrase all time the client connects.

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  • connecting clients to server with emulator on different computers

    - by prolink007
    I am writing an application that communicates using sockets. I have a server running on one android emulator on a computer, then i have 2 other clients running on android emulators on 2 other computers. I am trying to get the 2 clients to connect to the server. This works when i run the server and clients on the same computer, but when i attempt to do this on the same wifi network and on separate computers it gives me the following error. The client and server code is posted below. A lot is stripped out just to show the important stuff. Also, after the server starts i telnet into the server and run these commands redir add tcp:5000:6000 (i have also tried without doing the redir but it still says the same thing). Then i start the clients and get the error. Thanks for the help! Both the 5000 port and 6000 port are open on my router. And i have windows firewall disabled on the computer hosting the server. 11-27 18:54:02.274: W/ActivityManager(60): Activity idle timeout for HistoryRecord{44cf0a30 school.cpe434.ClassAidClient/school.cpe434.ClassAid.ClassAidClient4Activity} 11-27 18:57:02.424: W/System.err(205): java.net.SocketException: The operation timed out 11-27 18:57:02.454: W/System.err(205): at org.apache.harmony.luni.platform.OSNetworkSystem.connectSocketImpl(Native Method) 11-27 18:57:02.454: W/System.err(205): at org.apache.harmony.luni.platform.OSNetworkSystem.connect(OSNetworkSystem.java:114) 11-27 18:57:02.465: W/System.err(205): at org.apache.harmony.luni.net.PlainSocketImpl.connect(PlainSocketImpl.java:245) 11-27 18:57:02.465: W/System.err(205): at org.apache.harmony.luni.net.PlainSocketImpl.connect(PlainSocketImpl.java:220) 11-27 18:57:02.465: W/System.err(205): at java.net.Socket.startupSocket(Socket.java:780) 11-27 18:57:02.465: W/System.err(205): at java.net.Socket.<init>(Socket.java:314) 11-27 18:57:02.465: W/System.err(205): at school.cpe434.ClassAid.ClassAidClient4Activity.onCreate(ClassAidClient4Activity.java:102) 11-27 18:57:02.474: W/System.err(205): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1047) 11-27 18:57:02.474: W/System.err(205): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2459) 11-27 18:57:02.474: W/System.err(205): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2512) 11-27 18:57:02.474: W/System.err(205): at android.app.ActivityThread.access$2200(ActivityThread.java:119) 11-27 18:57:02.474: W/System.err(205): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1863) 11-27 18:57:02.474: W/System.err(205): at android.os.Handler.dispatchMessage(Handler.java:99) 11-27 18:57:02.474: W/System.err(205): at android.os.Looper.loop(Looper.java:123) 11-27 18:57:02.486: W/System.err(205): at android.app.ActivityThread.main(ActivityThread.java:4363) 11-27 18:57:02.486: W/System.err(205): at java.lang.reflect.Method.invokeNative(Native Method) 11-27 18:57:02.486: W/System.err(205): at java.lang.reflect.Method.invoke(Method.java:521) 11-27 18:57:02.486: W/System.err(205): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:860) 11-27 18:57:02.486: W/System.err(205): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:618) 11-27 18:57:02.486: W/System.err(205): at dalvik.system.NativeStart.main(Native Method) The server code public class ClassAidServer4Activity extends Activity { ServerSocket ss = null; String mClientMsg = ""; String mClientExtraMsg = ""; Thread myCommsThread = null; public static final int SERVERPORT = 6000; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); TextView tv = (TextView) findViewById(R.id.textView1); tv.setText("Nothing from client yet"); this.myCommsThread = new Thread(new CommsThread()); this.myCommsThread.start(); } class CommsThread implements Runnable { public void run() { // Socket s = null; try { ss = new ServerSocket(SERVERPORT ); } catch (IOException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } while(true) { try { Socket socket = ss.accept(); connectedDeviceCount++; Thread lThread = new Thread(new ListeningThread(socket)); lThread.start(); } catch (IOException e) { e.printStackTrace(); } } } } class ListeningThread implements Runnable { private Socket s = null; public ListeningThread(Socket socket) { // TODO Auto-generated constructor stub this.s = socket; } @Override public void run() { // TODO Auto-generated method stub while (!Thread.currentThread().isInterrupted()) { Message m = new Message(); // m.what = QUESTION_ID; try { if (s == null) s = ss.accept(); BufferedReader input = new BufferedReader( new InputStreamReader(s.getInputStream())); String st = null; st = input.readLine(); String[] temp = parseReadMessage(st); mClientMsg = temp[1]; if(temp.length > 2) { mClientExtraMsg = temp[2]; } m.what = Integer.parseInt(temp[0]); myUpdateHandler.sendMessage(m); } catch (IOException e) { e.printStackTrace(); } } } } } The client code public class ClassAidClient4Activity extends Activity { //telnet localhost 5554 //redir add tcp:5000:6000 private Socket socket; private String serverIpAddress = "192.168.1.102"; private static final int REDIRECTED_SERVERPORT = 5000; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); try { InetAddress serverAddr = InetAddress.getByName(serverIpAddress); socket = new Socket(serverAddr, REDIRECTED_SERVERPORT); } catch (UnknownHostException e1) { mQuestionAdapter.add("UnknownHostException"); e1.printStackTrace(); } catch (IOException e1) { mQuestionAdapter.add("IOException"); e1.printStackTrace(); } } }

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  • User has many computers, computers have many attributes in different tables, best way to JOIN?

    - by krismeld
    I have a table for users: USERS: ID | NAME | ---------------- 1 | JOHN | 2 | STEVE | a table for computers: COMPUTERS: ID | USER_ID | ------------------ 13 | 1 | 14 | 1 | a table for processors: PROCESSORS: ID | NAME | --------------------------- 27 | PROCESSOR TYPE 1 | 28 | PROCESSOR TYPE 2 | and a table for harddrives: HARDDRIVES: ID | NAME | ---------------------------| 35 | HARDDRIVE TYPE 25 | 36 | HARDDRIVE TYPE 90 | Each computer can have many attributes from the different attributes tables (processors, harddrives etc), so I have intersection tables like this, to link the attributes to the computers: COMPUTER_PROCESSORS: C_ID | P_ID | --------------| 13 | 27 | 13 | 28 | 14 | 27 | COMPUTER_HARDDRIVES: C_ID | H_ID | --------------| 13 | 35 | So user JOHN, with id 1 owns computer 13 and 14. Computer 13 has processor 27 and 28, and computer 13 has harddrive 35. Computer 14 has processor 27 and no harddrive. Given a user's id, I would like to retrieve a list of that user's computers with each computers attributes. I have figured out a query that gives me a somewhat of a result: SELECT computers.id, processors.id AS p_id, processors.name AS p_name, harddrives.id AS h_id, harddrives.name AS h_name, FROM computers JOIN computer_processors ON (computer_processors.c_id = computers.id) JOIN processors ON (processors.id = computer_processors.p_id) JOIN computer_harddrives ON (computer_harddrives.c_id = computers.id) JOIN harddrives ON (harddrives.id = computer_harddrives.h_id) WHERE computers.user_id = 1 Result: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | HARDDRIVE TYPE 25 | But this has several problems... Computer 14 doesnt show up, because it has no harddrive. Can I somehow make an OUTER JOIN to make sure that all computers show up, even if there a some attributes they don't have? Computer 13 shows up twice, with the same harddrive listet for both. When more attributes are added to a computer (like 3 blocks of ram), the number of rows returned for that computer gets pretty big, and it makes it had to sort the result out in application code. Can I somehow make a query, that groups the two returned rows together? Or a query that returns NULL in the h_name column in the second row, so that all values returned are unique? EDIT: What I would like to return is something like this: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | NULL | 14 | 27 | PROCESSOR TYPE 1 | NULL | NULL | Or whatever result that make it easy to turn it into an array like this [13] => [P_NAME] => [0] => PROCESSOR TYPE 1 [1] => PROCESSOR TYPE 2 [H_NAME] => [0] => HARDDRIVE TYPE 25 [14] => [P_NAME] => [0] => PROCESSOR TYPE 1

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  • What does this error mean (Can't create TCP/IP socket (24))?

    - by user105196
    I have web server with OS RHEL 6.2 and Mysql 5.5.23 on another server and the web server can read from Mysql server without problem, but some time I got this error: [Sun Sep 23 06:13:07 2012] [error] [client XXXXX] DBI connect('XXXX:192.168.1.2:3306','XXX',...) failed: Can't create TCP/IP socket (24) at /var/www/html/file.pm line 199. my question : What does this error mean (Can't create TCP/IP socket (24))? is it OS error or Mysql error ? perl -v This is perl, v5.10.1 (*) built for x86_64-linux-thread-multi mysql -V mysql Ver 14.14 Distrib 5.5.23, for Linux (x86_64) using readline 5.1 su - mysql -s /bin/bash -c 'ulimit -a' core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 127220 max locked memory (kbytes, -l) 64 max memory size (kbytes, -m) unlimited open files (-n) 1024 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 10240 cpu time (seconds, -t) unlimited max user processes (-u) 1024 virtual memory (kbytes, -v) unlimited file locks (-x) unlimited

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  • How can I send an std::vector<std::string> over a UNIX socket?

    - by Mike
    For my application, I need to be able to send an std::vector<std::string> over a UNIX socket(local), and get a copy of the vector on the other end of the socket. What's the easiest way to do this with O(1) messages relative to the size of the vector(i.e. without sending a message for each string in the vector)? Since this is all on the same host, and because I control both ends of the socket, I'm not concerned with machine-specific issues such as endinness or vector/string representation.

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  • Send less Server Data with "AFK"

    - by Oliver Schöning
    I am working on a 2D (Realtime) MultiPlayer Game. With Construct2 and a Socket.IO JavaScript Server. Right now the code does not include the Array for each Player. var io = require("socket.io").listen(80); var x = 10; io.sockets.on("connection", function (socket) { socket.on("message", function(data) { x = x+1; }); }); setInterval(function() { io.sockets.emit("message", 'Pos,' + x); },100); I noticed a very annoying problem with my server today. It sends my X Coordinates every 100 milliseconds. The Problem was, that when I went into another Browser Tab, the Browser stopped the Game from running. And when I went back, I think the Game had to run through all the packages. Because my Offline Debugging Button still worked immediately and the Online Button only responded after some seconds. So then I changed my Code so that it would only send out an update when it received a player Input: var io = require("socket.io").listen(80); var x = 10; io.sockets.on("connection", function (socket) { socket.on("message", function(data) { x = x+1; io.sockets.emit("message", 'Pos,' + x); }); }); And it Updated Immediately, even when I had been inactive on the Browser Tab for a long time. Confirming my suspicion that it had to get through all the data. Confirm Please! It would be insane to only send information on Client Input in a Real Time Game. But how would I write a AFK function? I would think it is easier to run a AFK Boolean Loop on the Server. Here is what I need help for: playerArray[Me] if ( "Not Given any Input for X amount of Seconds" ) { "Don't send Data" } else { "Send Data" }

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  • what type of bug causes a program to slowly use more processor power and all of a sudden go to 100%?

    - by reinier
    Hi, I was hoping to get some good ideas as to what might be causing a really nasty bug. This is a program which is transmitting data over a socket, and also receives messages back. I could explain lots more, but I don't think this will help here. I'm just searching for hypothetical problems which can cause the following behaviour: program runs processor time slowly accumulates (till around 60%) all of a sudden (could be after 30 but also after 60 seconds) the processor time shoots to 100%. the program halts completely In my syslog it always ends on one line with a memory allocation (something similar to: myArray = new byte[16384]) in the same thread. now here is the weird part: if I set the debugger anywhere...it immediately stops on that line. So just the act of setting a breakpoint, made the thread continue (it wasn't running since I saw no log output anymore) I was thinking 'deadlock' but that would not cause 100% processor power. If anything, the opposite. Also, setting a breakpoint would not cause a deadlock to end. anyone else a theoretical suggestion as to what kind of 'construct' might cause this effect? (apart from 'bad programming') ;^) thanks EDIT: I just noticed.... by setting the sendspeed slower, the problem shows itself much later than expected. I would think around the same amount of packets send...but no the amount of packets send is much higher this way before it has the same problem.

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  • What do I need for development for an ARM processor?

    - by claws
    Hello, I'm familiar with X86[-64] architecture & assembly. I want to start develop for an ARM processor. But unlike desktop processors, I don't have an actual ARM processor. I think I need an ARM simulator. http://www.armtutorial.com/ say An ARM assembly compiler will be required, the most accessible is the ARMulator. I thought of downloading Armulator but found from http://forums.arm.com/index.php?showtopic=13744 that Its not sold seperately. But you can download an eval of RVDS - which includes RVISS/ARMulator I've downloaded & installed RVDS but It looks very complex. I'm unable to figure out what do I need to do to write ARM assembly & run it. I want to write in assembly not in C/C++. I don't have an ARM processor. What is a good simulator? Can any one please mention in short. How to write assembly & assemble & simulate using RVDS. Please be clear? Are there any other alternative ways. I can't afford buying any kind of boards. I always learn from books rather than tutorials. I'm following these two books: ARM System Developer's Guide: Designing and Optimizing System Software (The Morgan Kaufmann Series in Computer Architecture and Design) ARM System-on-Chip Architecture (2nd Edition) Do you have any better suggestions?

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  • When does an ARM7 processor increase its PC register?

    - by Summer_More_More_Tea
    Hi everyone: I'm thinking about this question for a time: when does an ARM7(with 3 pipelines) processor increase its PC register. I originally thought that after an instruction has been executed, the processor first check is there any exception in the last execution, then increase PC by 2 or 4 depending on current state. If an exception occur, ARM7 will change its running mode, store PC in the LR of current mode and begin to process current exception without modifying the PC register. But it make no sense when analyzing returning instructions. I can not work out why PC will be assigned LR when returning from an undefined-instruction-exception while LR-4 from prefetch-abort-exception, don't both of these exceptions happened at the decoding state? What's more, according to my textbook, PC will always be assigned LR-4 when returning from prefetch-abort-exception no matter what state the processor is(ARM or Thumb) before exception occurs. However, I think PC should be assigned LR-2 if the original state is Thumb, since a Thumb-instruction is 2 bytes long instead of 4 bytes which an ARM-instruction holds, and we just wanna roll-back an instruction in current state. Is there any flaws in my reasoning or something wrong with the textbook. Seems a long question. I really hope anyone can help me get the right answer. Thanks in advance.

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  • how to get adobe flash fullscreen video fluid with an atom processor?

    - by Antoine Rodriguez
    My system has an atom N270 + intel i915 graphic card. Under Windows I can enjoy 720p bigbuckbunny youtube video fullscreen without any trouble. Under Ubuntu 12.04 I have laggy and choppy fullscreen video and choppy video when not fullscreen. I've seen that under ubuntu the cpu is almost always at 100% use. What I must do in order to have videos playing well under ubuntu ? I've already tried the following : Force flash gpu detection : (no result) : mkdir /etc/adobe echo "OverrideGPUValidation = 1" | sudo tee -a /etc/adobe/mms.cfg grub options (had results but not enough) : i915_enable_rc6=1 i915_enable_fbc=1 i915_lvds_downclock=1 pcie_aspm=force updated intel drivers (glasen ppa) Using chrome instead of firefox (had impact but not enough)

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  • What is the *correct* term for a program that makes use of multiple hardware processor cores?

    - by Ryan Thompson
    I want to say that my program is capable of splitting some work across multiple CPU cores on a single system. What is the simple term for this? It's not multi-threaded, because that doesn't automatically imply that the threads run in parallel. It's not multi-process, because multiprocessing seems to be a property of a computer system, not a program. "capable of parallel operation" seems too wordy, and with all the confusion of terminology, I'm not even sure if it's accurate. So is there a simple term for this?

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  • How Do You Calculate Processor Speed on Multi-core Processors?

    - by Jason Fitzpatrick
    The advent of economical consumer grade multi-core processors raises the question for many users: how do you effectively calculate the real speed of a multi-core system? Is a 4-core 3Ghz system really 12Ghz? Read on as we investigate. Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-drive grouping of Q&A web sites. 6 Start Menu Replacements for Windows 8 What Is the Purpose of the “Do Not Cover This Hole” Hole on Hard Drives? How To Log Into The Desktop, Add a Start Menu, and Disable Hot Corners in Windows 8

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  • How can a Perfmon "% Processor Time" counter be over 100%?

    - by Bill Paetzke
    The counter, Process: % Processor Time (sqlservr), is hovering around 300% on one of my database servers. This counter reflects the percent of total time SQL Server spent running on CPU (user mode + privilege mode). The book, Sql Server 2008 Internals and Troubleshooting, says that anything greater than 80% is a problem. How is it possible for that counter to be over 100%?

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  • Does it make sense to have more than one UDP Datagram socket on standby? Are simultaneous packets dr

    - by Gubatron
    I'm coding a networking application on Android. I'm thinking of having a single UDP port and Datagram socket that receives all the datagrams that are sent to it and then have different processing queues for these messages. I'm doubting if I should have a second or third UDP socket on standby. Some messages will be very short (100bytes or so), but others will have to transfer files. My concern is, will the Android kernel drop the small messages if it's too busy handling the bigger ones?

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  • Any socket programmers out there? How can I obtain the IPv4 address of the client?

    - by Dr Dork
    Hello! I'm prepping for a simple work project and am trying to familiarize myself with the basics of socket programming in a Unix dev environment. At this point, I have some basic server side code setup to listen for incoming TCP connection requests from clients after the parent socket has been created and is set to listen... int sockfd, newfd; unsigned int len; socklen_t sin_size; char msg[]="Test message sent"; char buf[MAXLEN]; int st, rv; struct addrinfo hints, *serverinfo, *p; struct sockaddr_storage client; char ip[INET6_ADDRSTRLEN]; . . //parent socket creation and listen code omitted for simplicity . //wait for connection requests from clients while(1) { //Returns the socketID and address of client connecting to socket if( ( newfd = accept(sockfd, (struct sockaddr *)&client, &len) ) == -1 ){ perror("Accept"); exit(-1); } if( (rv = recv(newfd, buf, MAXLEN-1, 0 )) == -1) { perror("Recv"); exit(-1); } struct sockaddr_in *clientAddr = ( struct sockaddr_in *) get_in_addr((struct sockaddr *)&client); inet_ntop(client.ss_family, clientAddr, ip, sizeof ip); printf("Receive from %s: query type is %s\n", ip, buf); if( ( st = send(newfd, msg, strlen(msg), 0)) == -1 ) { perror("Send"); exit(-1); } //ntohs is used to avoid big-endian and little endian compatibility issues printf("Send %d byte to port %d\n", ntohs(clientAddr->sin_port) ); close(newfd); } } I found the get_in_addr function online and placed it at the top of my code and use it to obtain the IP address of the client connecting... // get sockaddr, IPv4 or IPv6: void *get_in_addr(struct sockaddr *sa) { if (sa->sa_family == AF_INET) { return &(((struct sockaddr_in*)sa)->sin_addr); } return &(((struct sockaddr_in6*)sa)->sin6_addr); } but the function always returns the IPv6 IP address since thats what the sa_family property is set as. My question is, is the IPv4 IP address stored anywhere in the data I'm using and, if so, how can I access it? Thanks so much in advance for all your help!

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  • Why sockets does not die when server dies? Why socket dies when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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