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  • Memory Issues When DOM Parsing A Large XML File on Android Devices

    - by tonyc
    Hey awesome SO users, I have an Android application that parses an XML file for users and displays results in a much more mobile friendly format. The app works great for most users, but some users have lots and lots of data and the app crashes on them because it runs out of memory. Is there any way I have a DOM style XML parser quit parsing data after a certain amount of parsing? I only need the first 30 or so elements so it would make the application much more efficient. I'd like to use a SAX or pull parser instead, but the XML I'm parsing is not valid and I have no control over it. Unless anyone has some good SAX solutions that let me parse messy, invalid XML, I think DOM is the only way to go. Thanks for reading!

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  • Deserialize XML to custom Class in Flex?

    - by MysticEarth
    Is it possible to deserialize an XML file to a class in Flex without manually checking the XML and/or creating the class, with the help of a HttpService? Edit: Explained a bit more and better. We have an XML file which contains: <Project> <Name>NameGoesHere</Name> <Number>15</Number> </Project> In Flex we want this to be serialized to our Project class: package com.examplepackage { import mx.collections.ArrayCollection; [XmlClass] public class Project { public var Name:String; public var Number:int; public function Project() { } } } The XML is loaded with a HTTPService.

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  • something like INotifyCollectionChanged fires on xml file changed

    - by netmajor
    It's possible to implement INotifyCollectionChanged or other interface like IObservable to enable to bind filtered data from xml file on this file changed ? I see examples with properties or collection, but what with files changes ? I have that code to filter and bind xml data to list box: XmlDocument channelsDoc = new XmlDocument(); channelsDoc.Load("RssChannels.xml"); XmlNodeList channelsList = channelsDoc.GetElementsByTagName("channel"); this.RssChannelsListBox.DataContext = channelsList;

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  • XML/C#: Read content if only if attribute is correct

    - by Zach
    Hi Guys, I have an XML file as follows, and I'm trying to read the content of the Name tag, only if the attribute of the Record tag is what I want. (continued below code) The XML file is: <?xml version="1.0" encoding="utf-8" ?> <Database> <Record Number="1"> <Name>John Doe</Name> <Position>1</Position> <HoursWorked>290</HoursWorked> <LastMonthChecked>0310</LastMonthChecked> </Record> <Record Number="2"> <Name>Jane Doe</Name> <Position>1</Position> <HoursWorked>251</HoursWorked> <LastMonthChecked>0310</LastMonthChecked> </Record> </Database> This is the C# code I have so far: public static string GetName(int EmployeeNumber) { XmlTextReader DataReader = new XmlTextReader("Database.xml"); DataReader.MoveToContent(); while (DataReader.Read()) { if (DataReader.NodeType == XmlNodeType.Element && DataReader.HasAttributes && DataReader.Name == "Record") { DataReader.MoveToAttribute(EmployeeNumber); DataReader.MoveToContent(); if (DataReader.NodeType == XmlNodeType.Element && DataReader.Name == "Name") { return DataReader.ReadContentAsString(); } } } } So for example, if 2 is passed to the function, I want it to return the string "Jane Doe". I'm new to XML parsing, so any help would be appreciated. Thanks.

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  • Validate XSD with XML .

    - by munish
    I want to know how to validate XML with XSD . XML is not of an element type but a complex type . Since validator class's validate method compare only element type. So basically I want to valide XSD's complex type with an XML. e.g. Basic XSD below xs:element name="Customer"> <xs:complexType> <xs:sequence> <xs:element name="Dob" type="xs:date" /> <xs:element name="Address"> <xs:complexType> <xs:sequence> <xs:element name="Line1" type="xs:string" /> <xs:element name="Line2" type="xs:string" /> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> We can assume we have multiple complex type in the Customer element. MY XML is <Address> <Line1>34 thingy street, someplace</Line1> <Line2>sometown, w1w8uu </Line2> </Address> How I validate my XML with XSD. Kindly post your suggestions in java

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  • Referencing Environment Variables in web.xml

    - by Udi Bar-On
    I'm pre-packaging a JSP web-app that relies on some file path settings found within web.xml. These settings are unknown at packaging time, because they reference a path the customer will set when deploying the entire application (of which the web-app is a management interface). It seems that the easiest way to avoid tokens and file modifications in my installer script, is to ask the user for an install location, set this location as an environment variable (e.g JAVA_HOME), and have web.xml always reference that variable. Is there a way to reference an environment variable value from within web.xml? Google searches lead to the J2EE method of SETTING environment variables from ejb xml files. This is not what I'm looking for. Thanks Udi

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  • Getting an invalidoperationexception when deserialising XML

    - by Paul Johnson
    Hi, I'm writing a simple proof of concept application to load up an XML file and depending on the very simple code, create a window and put something into it (it's for a much larger project). Due to limitations in Mono, I'm having to run in this way. The code I currently have looks like this using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Windows.Forms; using System.IO; using System.Collections; using System.Xml; using System.Xml.Serialization; namespace form_from_xml { public class xmlhandler : Form { public void loaddesign() { FormData f; f = null; try { string path_env = Path.GetDirectoryName(Application.ExecutablePath) + Path.DirectorySeparatorChar; // code dies on the line below XmlSerializer s = new XmlSerializer(typeof(FormData)); TextReader r = new StreamReader(path_env + "designer-test.xml"); f = (FormData)s.Deserialize(r); r.Close(); } catch (System.IO.FileNotFoundException) { MessageBox.Show("Unable to find the form file", "File not found", MessageBoxButtons.OK); } } } [XmlRoot("Forms")] public class FormData { private ArrayList formData; public FormData() { formData = new ArrayList(); } [XmlElement("Element")] public Elements[] elements { get { Elements[] elements = new Elements[formData.Count]; formData.CopyTo(elements); return elements; } set { if (value == null) return; Elements[] elements = (Elements[])value; formData.Clear(); foreach (Elements element in elements) formData.Add(element); } } public int AddItem(Elements element) { return formData.Add(element); } } public class Elements { [XmlAttribute("formname")] public string name; [XmlAttribute("winxsize")] public int winxs; [XmlAttribute("winysize")] public int winys; [XmlAttribute("type")] public object type; [XmlAttribute("xpos")] public int xpos; [XmlAttribute("ypos")] public int ypos; [XmlAttribute("externaldata")] public bool external; [XmlAttribute("externalplace")] public string externalplace; [XmlAttribute("text")] public string text; [XmlAttribute("questions")] public bool questions; [XmlAttribute("questiontype")] public object qtype; [XmlAttribute("numberqs")] public int numberqs; [XmlAttribute("answerfile")] public string ansfile; [XmlAttribute("backlink")] public int backlink; [XmlAttribute("forwardlink")] public int forwardlink; public Elements() { } public Elements(string fn, int wx, int wy, object t, int x, int y, bool ext, string extpl, string te, bool q, object qt, int num, string ans, int back, int end) { name = fn; winxs = wx; winys = wy; type = t; xpos = x; ypos = y; external = ext; externalplace = extpl; text = te; questions = q; qtype = qt; numberqs = num; ansfile = ans; backlink = back; forwardlink = end; } } } With a very simple xmlhandler xml = new xmlhander(); xml.loaddesign(); attached to a winform button. Everything is in the same namespace and the xml file actually exists. This is annoying me now - can anyone spot the error of my ways? Paul

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  • How to get an xml file when running mstest

    - by devlife
    I have a class which loads an xml file using the following: Path.Combine( AppDomain.CurrentDomain.BaseDirectory, "Xml", documentName ); The documents that are being loaded are set to copy to the output directory. However, when I run mstest the xml file is not being copied to the BaseDirectory. Does anyone have any idea how I can accomplish this?

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  • Create xml document in java applet.

    - by zproxy
    If I try to create a new xml document in a java applet by this code: http://java.sun.com/j2se/1.4.2/docs/api/javax/xml/parsers/DocumentBuilderFactory.html#newInstance() DocumentBuilderFactory.newInstance(); I will get this error: Java Plug-in 1.6.0_19 Using JRE version 1.6.0_19-b04 Java HotSpot(TM) Client VM javax.xml.parsers.FactoryConfigurationError: Provider <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> not found at javax.xml.parsers.DocumentBuilderFactory.newInstance(Unknown Source) I do not care about DTD's. Why is it looking for it? How am I supposed to create a xml document in java applets? How can I make it work? The enclosing html document looks like this: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html> <head> <title>Loading...</title> </head> Can some comment this thread? The problem was with the entity resolver, which points to the w3c.org web site. The access to the reference DTDs on this site has been restricted for application use. The solution was to implement my own entity resolver. Related: http://forums.sun.com/thread.jspa?threadID=515055 http://stackoverflow.com/questions/1016286/org-apache-xerces-jaxp-saxparserfactoryimpl-not-found-when-importing-gears-api-in http://java.itags.org/java-desktop/4839/

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  • Is XML a good logic to load data??

    - by Mat
    Hi stack, i'm working on an app that loads some data from xml file from internet. Is this a good way to develop iPhone apps??...I think xml is more light than SQlite database... Basically my logic is: 1 - Parsing Xml file from internet to retrive the data 2 - Load data on device Security?..other stuff??.. Thanks Mat

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  • Can't parse XML effectively using Python

    - by Harshit Sharma
    import urllib import xml.etree.ElementTree as ET def getWeather(city): #create google weather api url url = "http://www.google.com/ig/api?weather=" + urllib.quote(city) try: # open google weather api url f = urllib.urlopen(url) except: # if there was an error opening the url, return return "Error opening url" # read contents to a string s = f.read() tree=ET.parse(s) current= tree.find("current_condition/condition") condition_data = current.get("data") weather = condition_data if weather == "<?xml version=": return "Invalid city" #return the weather condition #return weather def main(): while True: city = raw_input("Give me a city: ") weather = getWeather(city) print(weather) if __name__ == "__main__": main() gives error , I actually wanted to find values from google weather xml site tags

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  • Convert CSV file to XML

    - by Soeren
    I need to Convert a CSV into an XML document. The examples I have seen so far, all show how to do this with a fixed number of columns in the CSV. I have this so far, using LINQ: String[] File = File.ReadAllLines(@"C:\text.csv"); String xml = ""; XElement top = new XElement("TopElement", from items in File let fields = items.Split(';') select new XElement("Item", new XElement("Column1", fields[0]), new XElement("Column2", fields[1]), new XElement("Column3", fields[2]), new XElement("Column4", fields[3]), new XElement("Column5", fields[4]) ) ); File.WriteAllText(@"C:\xmlout.xml", xml + top.ToString()); This is for a fixed amount of columns, but my .CSV has a different number of columns on each line. How would you fit some sort of loop into this, depending on how many words (columns) there are in each line of the .CSV? Thnx

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  • Why can't I access elements inside an XML file with XPath in XML::LibXML?

    - by John
    I have an XML file, part of which looks like this: <wave waveID="1"> <well wellID="1" wellName="A1"> <oneDataSet> <rawData>0.1123975676</rawData> </oneDataSet> </well> ... more wellID's and rawData continues here... I am trying to parse the file with Perl's libXML and output the wellName and the rawData using the following: use XML::LibXML; my $parser = XML::LibXML->new(); my $doc = $parser->parse_file('/Users/johncumbers/Temp/1_12-18-09-111823.orig.xml'); my $xc = XML::LibXML::XPathContext->new( $doc->documentElement() ); $xc->registerNs('ns', 'http://moleculardevices.com/microplateML'); my @n = $xc->findnodes('//ns:wave[@waveID="1"]'); #xc is xpathContent # should find a tree from the node representing everything beneath the waveID 1 foreach $nod (@n) { my @c = $nod->findnodes('//rawData'); #element inside the tree. print @c; } It is not printing out anything right now and I think I have a problem with my Xpath statements. Please can you help me fix it, or can you show me how to trouble shoot the xpath statements? Thanks.

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  • How can Perl's XML::Simple ignore HTML embedded in XML?

    - by Miriam Raphael Roberts
    I have an XML file that I am pulling from the web and parsing. One of the items in the XML is a 'content' value that has HTML. I am using XML::Simple::XMLin to parse the file like so: $xml= eval { $data->XMLin($xmldata, forcearray => 1, suppressempty=> +'') }; When I use Data::Dumper to dump the hash, I discovered that SimpleXML is parsing the HTML into the hash tree: 'content' = { 'div' = [ { 'xmlns' = 'http://www.w3.org/1999/xhtml', 'p' = [ { 'a' = [ { 'href' = 'http://miamiherald.typepad.com/.a/6a00d83451b26169e20133ec6f4491970b-pi', 'style' = 'FLOAT: left', 'img' = [ etc..... This is not what I want. I want to just grab content inside of this entry. How do I do this?

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  • Dump XML Posts from 'php://input' to file

    - by Mikey1980
    I'm trying to write a parser for a xml postback listener, but can't seem to get it to dump the xml for a sample. The API support guy told me to use 'DOMDocument', maybe 'SimpleXML'? Anyways here's the code: (thanks!) <?php $xml_document = file_get_contents('php://input'); $doc = new DOMDocument(); $doc->loadXML($xml_document); $doc->save("test2/".time().".sample.xml").".xml"); ?>

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  • Help Modifying Generic REST Helper PHP Example Code to Support XML DOM

    - by Jennifer Baker
    Hi! I found this example PHP source code at HTTP POST from PHP, without cURL I need some help modifying the example PHP source to support XML DOM for manipulating a REST API. I thought that if I update the CASE statement for the XML section below from $r = simplexml_load_string($res); to $r = new DOMDocument(); $r->load($res); that it would work but it doesn't. :( Any help would be appreciated. function rest_helper($url, $params = null, $verb = 'GET', $format = 'xml') { $cparams = array( 'http' => array( 'method' => $verb, 'ignore_errors' => true ) ); if ($params !== null) { $params = http_build_query($params); if ($verb == 'POST') { $cparams['http']['content'] = $params; } else { $url .= '?' . $params; } } $context = stream_context_create($cparams); $fp = fopen($url, 'rb', false, $context); if (!$fp) { $res = false; } else { // If you're trying to troubleshoot problems, try uncommenting the // next two lines; it will show you the HTTP response headers across // all the redirects: // $meta = stream_get_meta_data($fp); // var_dump($meta['wrapper_data']); $res = stream_get_contents($fp); } if ($res === false) { throw new Exception("$verb $url failed: $php_errormsg"); } switch ($format) { case 'json': $r = json_decode($res); if ($r === null) { throw new Exception("failed to decode $res as json"); } return $r; case 'xml': $r = simplexml_load_string($res); if ($r === null) { throw new Exception("failed to decode $res as xml"); } return $r; } return $res; }

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  • populate textboxs with xml node attributes

    - by Doug
    I have Data.xml: <?xml version="1.0" encoding="utf-8" ?> <data> <album> <slide title="Autum Leaves" description="Leaves from the fall of 1986" source="images/Autumn Leaves.jpg" thumbnail="images/Autumn Leaves_thumb.jpg" /> <slide title="Creek" description="Creek in Alaska" source="images/Creek.jpg" thumbnail="images/Creek_thumb.jpg" /> </album> </data> I'd like to be able to edit the attributes of each Slide node via GridView (that has a "Select" column added.) And so far I have: protected void GridView1_SelectedIndexChanged(object sender, EventArgs e) { int selectedIndex = GridView1.SelectedIndex; LoadXmlData(selectedIndex); } private void LoadXmlData(int selectedIndex) { XmlDocument xmldoc = new XmlDocument(); xmldoc.Load(MapPath(@"..\photo_gallery\Data.xml")); XmlNodeList nodelist = xmldoc.DocumentElement.ChildNodes; XmlNode xmlnode = nodelist.Item(selectedIndex); titleTextBox.Text = xmlnode.Attributes["title"].InnerText; descriptionTextBox.Text = xmlnode.Attributes["description"].InnerText; sourceTextBox.Text = xmlnode.Attributes["source"].InnerText; thumbTextBox.Text = xmlnode.Attributes["thumbnail"].InnerText; The code for LoadXmlData is just a guess on my part - I'm new to working with xml in this way. I'd like have the user to slected the row from the gridview, then populate a set of text boxes with each slide attributed for updating back to the Data.xml file. The error I'm getting is "Object reference not set to an instance of an object" at the line: titleTextBox.Text = xmlnode.Attributes["@title"].InnerText; - so I'm not reaching the attribute "title" of the slide node. Thanks for any ideas you may have.

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  • can't insert xml dml expression as a string

    - by 81967
    Here is the code below that would explain you the problem... I create a table below with an xml column and declare a variable, initialize it and Insert the Value into the xml column, create table CustomerInfo (XmlConfigInfo xml) declare @StrTemp nvarchar(2000) set @StrTemp = '<Test></Test>' insert into [CustomerInfo](XmlConfigInfo) values (@StrTemp) Then comes the part of the question,, if I write this... update [CustomerInfo] set XmlConfigInfo.modify('insert <Info></Info> into (//Test)[1]') -- Works Fine!!! but when I try this, set @StrTemp = 'insert <Info></Info> into (//Test)[1]' update [CustomerInfo] set XmlConfigInfo.modify(@StrTemp) -- Doesn't Work!!! and throws an error The argument 1 of the xml data type method "modify" must be a string literal. is there a way around for this one? I tried this, but it is not working :(

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  • Spec. for JUnit XML Output

    - by Gilad Naor
    Where can I find the specification of JUnit's XML output. My goal is to write a UnitTest++ XML reporter which produced JUnit like output. See: "Unable to get hudson to parse JUnit test output XML" and "http://stackoverflow.com/questions/411218/hudson-c-and-unittest"

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  • main.out.xml error

    - by husainsn
    Hello I installed Eclipse and Android ADT. When I create android project and try to run, I get following on main.out.xml file: This document is empty. Right click here to insert content However, main.xml file has xml data for layout. Please help what I need to do after right clicking. Thanks

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  • Read XML with PHP

    - by sea_1987
    I am trying to check a field in some XML that is returned from an outside. The XML is returned in a variable call $out and when you view the source of the page you get a XML output of the following, <?xml version="1.0" encoding="UTF-8"?> <ResponseBlock Live="FALSE" Version="3.51"> <Response Type="AUTH"> <OperationResponse> <TransactionReference>23-9-1334895</TransactionReference> <TransactionCompletedTimestamp>2010-04-30 15:59:05</TransactionCompletedTimestamp> <AuthCode>AUTH CODE:TEST</AuthCode> <TransactionVerifier>AlaUOS1MOnN/iwc5s2WPDm5ggrCLwesUnHs9h+W0N3CRaln2W6lh+6dtaRFFhLdwfnw6y7lRemyJUYl9a3dpWfzORE6DaZkFMb+dIb0Ne1UxjFEJkrEtjzx/i8KSayrIBrT/yGZOoOT42EZ9loc+UkdGk/pqYvj8bZztvgBNo2Ak=</TransactionVerifier> <Result>1</Result> <SettleStatus>0</SettleStatus> <SecurityResponseSecurityCode>1</SecurityResponseSecurityCode> <SecurityResponsePostCode>1</SecurityResponsePostCode> <SecurityResponseAddress>1</SecurityResponseAddress> </OperationResponse> <Order> <OrderInformation>This is a test order</OrderInformation> <OrderReference>Order0001</OrderReference> </Order> </Response> </ResponseBlock> I want check what value is in the 'Result' field. I am unsure how to access the information using PHP, so far I have, $xml = simplexml_load_string($out); Many Thanks

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  • Filtering most out of XML with XSL?

    - by Gnudiff
    I need to transform a lot of XML files (Fedora export) into a different kind of XML. Trying to do it with XSL stylesheets and checking with the msxsl transformer. Supposedly I have xml file like this (assuming there are actually other nodes inside AAA, OBJ, amd all other nodes), Source.XML: <DOC> <AAA> <STUFF>example</STUFF> <OBJ> <OBJVERS id="A1" CREATED="2008-02-18T13:28:08.245Z"/> <OBJVERS id="A2" CREATED="2008-02-19T10:42:41.965Z"/> <OBJVERS id="A13" CREATED="2009-03-16T12:43:11.703Z"/> </OBJ> </AAA> <FFF/> <GGG/> <DDD> <FILE /> </DDD> </DOC> Which I need to look something like this (Target.XML): <MYOBJ> <ELEM>contents of OBJVERS with the biggest id OR creation date (whichever is easier to do) go here</ELEM> <IMAGE> contents of <FILE> node go here</IMAGE> </MYOBJ> The main problem that I have is that since I am new to XSL (and for this particular task do not have enough time to learn it properly) is that I can't understand how to tell XSL processor not to process anything else, I keep getting output from , for example. Update: basically, I solved this problem meanwhile. I will post my own answer and close the question. Update2: OK, Andrew's answer works, too, so I am just accepting it. :)

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