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  • MySQL SUM Query daily values of a week problem

    - by davykiash
    Am trying to return the sum of each day of a week in mysql but it returns nothing despite having values for the 3rd Week of March 2010 SELECT SUM(expense_details_amount) AS total FROM expense_details WHERE YEAR(expense_details_date) = '2010' AND MONTH(expense_details_date) = '03' AND WEEK(expense_details_date) = '3' GROUP BY DAY(expense_details_date) How do I go about this?

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  • Working with Database using LINQ to XML

    - by M.H
    Hi,I am Working on a project (C#) in the university and they said that we can't use a DBMS like SQL Server so we decide to use Linq and XML...we learned some basics in Linq to Xml But really we don't know how we can create tables and fields and work with them in Xml.any suggestions ?

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  • Query to look up comment in one table, username in another table

    - by John
    Hello, I am using a MySQL table called "login" with the following structure: loginid, username, password, email, actcode, disabled, activated, created, points I am using another MySQL table called "comment" with the following structure: commentid, loginid, submissionid, comment, datecommented For a given "submisssionid", I would like to print out the following information from the table "comment": -The fields "comment" and "datecommented". At the same time, I would like to print out the following from the table "login": -The "username" that corresponds to the "loginid" for each row being row being selected from the table "comment". How can I do this? I tried the code below but it did not work. Thanks in advance, John $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); $sqlStr = "SELECT c.loginid ,c.submissionid ,c.comment ,c.datecommented ,l.username ,COUNT(c.commentid) countComments FROM comment c WHERE c.submissionid = $submissionid INNER JOIN login l ON c.loginid = l.loginid GROUP BY c.submissionid ORDER BY c.datecommented DESC LIMIT 100"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1">'.$row["comment"].'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a>'.$row["datecommented"].'</td>'; echo '</tr>'; } echo "</table>";

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  • MYSQL distinct query

    - by Patrick
    This is my example of my table: id | name | foreign_id | 1 a 100 2 b 100 3 c 100 4 a 101 5 b 101 6 c 101 I would like to get the distinct file with the latest foreign_id (bigger number). In this example, it would be row with id 4,5,6. Anyone has any idea? Thank you very much!

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  • sql insert query needed

    - by masfenix
    Hey guys, so I have two tables. They are pictured below. I have a master table "all_reports". And a user table "user list". The master table may have users that do not exist in the user list. I need to add them to the user list. The master table may have duplicates in them (check picture). The master list does not contain all the information that the user list requires (no manager, no HR status, no department.. again check picture).

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  • HIbernate query language problem.....

    - by mslatf
    I have a Project class that has a Set of userstories called userStories12many. I'm having troubles trying to get the project that has a certain userstory in its set getComponent(int userStoryID) I think im on the right track but i dont know what i did wrong public Projects getComponent(int userStoryID) { Session session = SessionFactoryHelper.getSessionFactory() .getCurrentSession(); session.beginTransaction(); List<Projects> compo = session.createQuery("select p " + "from Projects as p inner join fetch p.userStories12many as u " + "where u.storyId='" + userStoryID + "'").list(); session.getTransaction().commit(); return compo.get(0); }

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  • innerJoin query show error

    - by Chithri Ajay
    just i print the two table data so i am using inner join SELECT sd.GameName FROM LottoryTickets AS sd JOIN group AS p ON sd.Group = p.groupname WHERE p.groupname = 11 now i get #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'group AS p ON sd.Group = p.groupname WHERE p.groupname = 11 LIMIT 0, 30' at line 3 this response please guide me thanks for advance.

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  • Generating Unordered List with PHP + CodeIgniter from a MySQL Database

    - by Tim
    Hello Everyone, I am trying to build a dynamically generated unordered list in the following format using PHP. I am using CodeIgniter but it can just be normal php. This is the end output I need to achieve. <ul id="categories" class="menu"> <li rel="1"> Arts &amp; Humanities <ul> <li rel="2"> Photography <ul> <li rel="3"> 3D </li> <li rel="4"> Digital </li> </ul> </li> <li rel="5"> History </li> <li rel="6"> Literature </li> </ul> </li> <li rel="7"> Business &amp; Economy </li> <li rel="8"> Computers &amp; Internet </li> <li rel="9"> Education </li> <li rel="11"> Entertainment <ul> <li rel="12"> Movies </li> <li rel="13"> TV Shows </li> <li rel="14"> Music </li> <li rel="15"> Humor </li> </ul> </li> <li rel="10"> Health </li> And here is my SQL that I have to work with. -- -- Table structure for table `categories` -- CREATE TABLE IF NOT EXISTS `categories` ( `id` mediumint(8) NOT NULL auto_increment, `dd_id` mediumint(8) NOT NULL, `parent_id` mediumint(8) NOT NULL, `cat_name` varchar(256) NOT NULL, `cat_order` smallint(4) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; So I know that I am going to need at least 1 foreach loop to generate the first level of categories. What I don't know is how to iterate inside each loop and check for parents and do that in a dynamic way so that there could be an endless tree of children. Thanks for any help you can offer. Tim

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  • Making a relevant search of text in database using regex

    - by madphp
    Can anyone tell me how I could count the possible instances of a keyword in a block of text? I've split a search term up into separate tokens, so just need to run through and do a count for every instance and removing punctuation or other special characters when making the count. Secondly, if someone has inserted search terms surrounded by double quotes, i want to be able to skip explode, but just count instances of that exact phrase. It doesn't have to be case sensitive and I would like to remove punctuation from the phrase when doing the count. Thirdly, in both cases i want to be able to ignore wordpress and html tags. Lastly, if anyone know any good tutorials for relevant searches that answer the questions above, that would cool too. I've got this far. $results = $wpdb->get_results($sql); $tokens = explode('search_terms'); // Re-arrange Relevant Results foreach ($results As $forum_topic){ foreach($tokens As $token){ // count tokens in topic_title if ($token ){ } } }

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  • Appending a Query String to the End of a Function Action URL

    - by John
    Hello, For the code below, I would like to append echo $_SERVER['QUERY_STRING']; to the end of index.php. But when I try to do it, it makes the code return a blank page. So I think I might be doing it wrong. How can I correctly make this appendage? Thanks in advance, John <?php function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> ... ?>

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  • Postgres vs Firebird

    - by Tedi
    I'm looking to use either Firebird or Postgres in my next development project ... largely because both are available under a BSD-like license. I found a great comparison of the two database at http://www.amsoftwaredesign.com/pg_vs_fb But this comparison is a good 2+ years old and both databases have come a long ways since. Does anyone mind updating the comparison table to be relevant for the current versions of both Firebird and Postgres ... or have a link to a site that does a good recent comparison between the two database?

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  • Upgrade Oracle database from 9.2.0.7 to 9.2.0.8

    - by b_dws
    We are planning to upgrade from Oracle 9.2.0.7 to 9.2.0.8. Main reason of the proposed upgrade is to address the issue in relation to exception "terminated with error: ORA-00904: "T2"."SYS_DS_ALIAS_4": invalid identifier" when we try to execute DBMS_STATS.GATHER_SCHEMA_STATS. We are concerned that the proposed upgrade may have negative impact on our Java application or in the worst case may not even support by our Java application. What are the possible approaches or strategies that we can take to ensure the upgrade from Oracle 9.2.0.7 to 9.2.0.8 will not have adverse impact on our Java application or will not cause our Java application to function incorrectly. Essentially we just want to confirm that our application will still support Oracle 9.2.0.8. Thank you.

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  • Why use hashing to create pathnames for large collections of files?

    - by Stephen
    Hi, I noticed a number of cases where an application or database stored collections of files/blobs using a has to determine the path and filename. I believe the intended outcome is a situation where the path never gets too deep, or the folders ever get too full - too many files (or folders) in a folder making for slower access. EDIT: Examples are often Digital libraries or repositories, though the simplest example I can think of (that can be installed in about 30s) is the Zotero document/citation database. Why do this? EDIT: thanks Mat for the answer - does this technique of using a hash to create a file path have a name? Is it a pattern? I'd like to read more, but have failed to find anything in the ACM Digital Library

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  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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  • Database Schema for Machine Tags?

    - by Gabriel
    Machine tags are more precise tags: http://www.flickr.com/groups/api/discuss/72157594497877875. They allow a user to basically tag anything as an object in the format object:property=value Any tips on a rdbms schema that implements this? Just wondering if anyone has already dabbled with this. I imagine the schema is quite similar to implementing rdf triples in a rdbms

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  • Query related to Connection type BIS-B Socket in Blackberry application

    - by mobile_dev
    Hi all, I am trying to establish BIS Socket connection. I am able to establish BIS Http connection from my service provider. I have downloaded one chat application that checks network types supported by my device/service plan which has following list: 1)BIS-Http : OK 2)BIS-SOCKET :OK 3)BES-HTTP : NA 4)BES-SOCKET : NA 5)TCP-HTTP : BAD DNS 6)TCP-SOCKET : TIMED OUT As I know direct TCP is not supported by my service provider. So I would like to use BIS-Socket connection. Can anypne please help me in achieving this type of connectivity? Please help. Thanks in advance.

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  • NHibernate's ISQLQuery returns instances that are of an unexpected type.

    - by Frederik Gheysels
    Hi all, I'm using NHibernate 2.1.2.400, and I'm having an issue with a an ISQLQuery query. The reason why I use an ISQLQuery here, is that this query uses a table for which I have no entity mapped in NHibernate. The query looks like this: ISQLQuery query = session.CreateSQLQuery ( "select p.*, price.* " + "from prestation p left outer join prestationprice price on p.PrestationId = price.PrestationId " + "where p.Id IN ( select id from prestationregistry where ..."); 'Prestationregistry' is the table that is not known by NHibernate (unmapped, so therefore the native SQL Query). my code continues like this: query.AddEntity ("p", typeof(Prestation)); query.AddJoin ("price", typeof(PrestationPrice)); query.SetResultTransformer (Transformers.DistinctRootEntity); var result = query.List(); So far so good. I expect that I'm given a list of 'Prestation' instances as a result of this query, since I declared 'Prestation' as being the root-object that has to be returned by the AddEntity method. I also expect that the PrestationPrices for each Prestation are eagerly loaded by this query (hence the AddJoin method). To my surprise, the List() method returns a collection of PrestationPrice instances instead of Prestation instances. How come ? Am I doing something wrong ? And if so, could you be so kind to tell me what I'm doing wrong ? Edit: Additional Info: When I debug, and put a watch on the 'query' instance, I can see that the queryReturns member of the query contains 2 items: - one NativeSqlQueryRootReturn instance who'se ReturnEntityName is 'Prestation' - one NativeSqlQueryJoinReturn When I do not specify the 'DistinctRootEntity' result transformer, the query returns instances of 'Prestation' instead of PrestationPrice. However, it contains multiple copies of the same instance.

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  • How to design this simple database?

    - by Vafello
    I have 2 tables - one storing user information (id, username, password) and the second one storing information about events (id, name, description, date, username(represents the user who created the event)). I would like to implement 'favourite events' functionality. This would allow the user to store his favourite events and later display them in a list. I am not sure how to implement this in terms of design. I need a simple solution. Something like storing the IDs of favourite events in a field in the user table. I am using mysql and php. Can anyone point me to the right direction?

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  • Where does Subversion physically stores its DataBase ?

    - by Mika Jacobi
    After reading many introductions, starting guides, and documentation on SVN, I still cannot figure out where is my versioning data stored. I mean physically. I have over 3 GB of code checked in, and the repo is just a few MB large. This is still Voodoo for me. And, as a coder, I don't really believe in Magic. EDIT : A contributor stated that not all the code was stored in the repo, is that true ? I mean, if I delete my local working copy I still can get back my source code for the repository... If so, I still can't understand how such a compression can occur on my code...

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