Search Results

Search found 14175 results on 567 pages for 'home entertainment'.

Page 425/567 | < Previous Page | 421 422 423 424 425 426 427 428 429 430 431 432  | Next Page >

  • How do I find the top N batters per year?

    - by Drew Stephens
    I'm playing around with the Lahman Baseball Database in a MySQL instance. I want to find the players who topped home runs (HR) for each year. The Batting table has the following (relevant parts) of its schema: +-----------+----------------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------+----------------------+------+-----+---------+-------+ | playerID | varchar(9) | NO | PRI | | | | yearID | smallint(4) unsigned | NO | PRI | 0 | | | HR | smallint(3) unsigned | YES | | NULL | | +-----------+----------------------+------+-----+---------+-------+ For each year, every player has an entry (between hundreds and 12k per year, going back to 1871). Getting the top N hitters for a single year is easy: SELECT playerID,yearID,HR FROM Batting WHERE yearID=2009 ORDER BY HR DESC LIMIT 3; +-----------+--------+------+ | playerID | yearID | HR | +-----------+--------+------+ | pujolal01 | 2009 | 47 | | fieldpr01 | 2009 | 46 | | howarry01 | 2009 | 45 | +-----------+--------+------+ But I'm interested in finding the top 3 from every year. I've found solutions like this, describing how to select the top from a category and I've tried to apply it to my problem, only to end up with a query that never returns: SELECT b.yearID, b.playerID, b.HR FROM Batting AS b LEFT JOIN Batting b2 ON (b.yearID=b2.yearID AND b.HR <= b2.HR) GROUP BY b.yearID HAVING COUNT(*) <= 3; Where have I gone wrong?

    Read the article

  • Prevent Casual Piracy for Simple Utility

    - by Chad
    I've written a small utility that I wish to sell for less than $10. My primary concern is "casual piracy". The scenario that plays out in my mind is this: User buys the program, enjoys using it and tells their friends. The friends copy the application to their USB drives and take it home - using the application for free (maybe never realizing they should have purchased it. Since I've got absolutely no protection built in, it would just be a simple copy'n paste to pirate the app. The users who would be using the app are in close proximity to each other (work in the same environment), so casual piracy would likely occur frequently. Any ideas? Keeping in mind the app is cheap (partly to reduce casual piracy), and the level of effort to write the app hasn't been very demanding. Update: the app will run on any system that supports .NET 3.5.

    Read the article

  • Work with a local copy of the "master" SVN repo

    - by Werner
    Hi, at work, we have a SVN repo, which we access to thorugh http, like: svn co http://user@machine/PATH even at work and for some misterious reasons, teh connections between local machines and the repo machine are very slow, but the connection between home and work is almost impossible. I wonder if I could do somethin like: 1- get a copy of the "master" SVN repo to my local machine 2- each time i make modifications etc, use svn co http://user@MYLOCALmachine/PATH instead of svn co http://user@machine/PATH 3- when I am back at work, "merge" somehow all the modifications in my local repo to the master one. Sorry, I am ewally new to SVN, any hint would be appreciated. Thanks

    Read the article

  • Problem with launching JAGUAR in R

    - by Gerry
    Windows XP, R 2.11.1, Java JRE6 I just installed the Jaguar package. From an R console, I can do this: > library(JGR) Loading required package: rJava Loading required package: JavaGD Loading required package: iplots Please use the corresponding JGR launcher to start JGR. Run JGR() for details. You can also use JGR(update=TRUE) to update JGR. and so JGR appears to be correctly installed. JGR() yields On Windows JGR must be started using the JGR.exe launcher. Please visit http://www.rosuda.org/JGR/ to download it. > I'm not sure how to run Jaguar - I know I have to run jgr.exe - but should R be already open? If so, should the JGR library be already loaded? I've tried all of these, and what seems to happen regardless is a console window opens briefly, then disappears. I've run jrg --debug, with no apparent error message: (same file regardless of choice made above). What should I be doing? Thanks! System: Version 5.1 (build 2600), platform 2 [Service Pack 3] JGR loader version 1.61 (build Jul 23 2008) parseParams> 1 parameters parsed. parseParams par 10> "--debug" > rhome="C:\Program Files\R\R-2.11.1" > srhome="C:\PROGRA~1\R\R-211~1.1" getPkgVersion(JGR): 010702 getPkgVersion(rJava): 000805 getPkgVersion(JavaGD): 000503 getPkgVersion(iplots): 010103 Loading preferences from "C:\Documents and Settings\gblais\.JGRprefsrc" > javakey="Software\JavaSoft\Java Runtime Environment\1.6" > javah="C:\Program Files\Java\jre6" > tp="C:\Perl\site\bin;C:\Perl\bin;C:\PHP\;C:\Program Files\MiKTeX 2.8\miktex\bin;C:\Python26\Lib\site-packages\PyQt4;C:\Program Files\Tcl\bin;C:\oracle\product\10.2.0\client_2\BIN;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\Program Files\Support Tools\;c:\belfry;c:\belfry\usr\local\wbin;C:\WINDOWS;C:\WINDOWS\System32;C:\WINDOWS\System32\WBEM;c:\Program Files\QuickTime\QTSystem\;C:\Program Files\SlikSvn\bin\;c:\progra~1\Microsoft Visual Studio 9.0\VC\bin\" Got RuntimeLib from registry, using "C:\Program Files\Java\jre6\bin\client;" PATH prefix. Java home: "C:\Program Files\Java\jre6" R home: "C:\Program Files\R\R-2.11.1" JAR files: "-Drjava.class.path=C:\PROGRA~1\R\R-211~1.1\library\rJava\jri\JRI.jar;C:\PROGRA~1\R\R-211~1.1\library\iplots\java\iplots.jar;C:\PROGRA~1\R\R-211~1.1\library\JGR\java\JGR.jar;C:\PROGRA~1\R\R-211~1.1\etc\classes;C:\PROGRA~1\R\R-211~1.1\etc\classes.jar" desired PATH: "C:\Program Files\Java\jre6\bin\client;C:\Program Files\Java\jre6\bin\client;C:\Program Files\Java\jre6\bin;C:\Program Files\R\R-2.11.1\bin;C:\PROGRA~1\R\R-211~1.1\library\rJava\jri;C:\Perl\site\bin;C:\Perl\bin;C:\PHP\;C:\Program Files\MiKTeX 2.8\miktex\bin;C:\Python26\Lib\site-packages\PyQt4;C:\Program Files\Tcl\bin;C:\oracle\product\10.2.0\client_2\BIN;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\Program Files\Support Tools\;c:\belfry;c:\belfry\usr\local\wbin;C:\WINDOWS;C:\WINDOWS\System32;C:\WINDOWS\System32\WBEM;c:\Program Files\QuickTime\QTSystem\;C:\Program Files\SlikSvn\bin\;c:\progra~1\Microsoft Visual Studio 9.0\VC\bin\" actual PATH: "C:\Program Files\Java\jre6\bin\client;C:\Program Files\Java\jre6\bin\client;C:\Program Files\Java\jre6\bin;C:\Program Files\R\R-2.11.1\bin;C:\PROGRA~1\R\R-211~1.1\library\rJava\jri;C:\Perl\site\bin;C:\Perl\bin;C:\PHP\;C:\Program Files\MiKTeX 2.8\miktex\bin;C:\Python26\Lib\site-packages\PyQt4;C:\Program Files\Tcl\bin;C:\oracle\product\10.2.0\client_2\BIN;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\Program Files\Support Tools\;c:\belfry;c:\belfry\usr\local\wbin;C:\WINDOWS;C:\WINDOWS\System32;C:\WINDOWS\System32\WBEM;c:\Program Files\QuickTime\QTSystem\;C:\Program Files\SlikSvn\bin\;c:\progra~1\Microsoft Visual Studio 9.0\VC\bin\" getenv PATH: "C:\Perl\site\bin;C:\Perl\bin;C:\PHP\;C:\Program Files\MiKTeX 2.8\miktex\bin;C:\Python26\Lib\site-packages\PyQt4;C:\Program Files\Tcl\bin;C:\oracle\product\10.2.0\client_2\BIN;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\Program Files\Support Tools\;c:\belfry;c:\belfry\usr\local\wbin;C:\WINDOWS;C:\WINDOWS\System32;C:\WINDOWS\System32\WBEM;c:\Program Files\QuickTime\QTSystem\;C:\Program Files\SlikSvn\bin\;c:\progra~1\Microsoft Visual Studio 9.0\VC\bin\" argv[0]:C:\PROGRA~1\Java\jre6\bin\java.exe argv[1]:-Drjava.class.path=C:\PROGRA~1\R\R-211~1.1\library\rJava\jri\JRI.jar;C:\PROGRA~1\R\R-211~1.1\library\iplots\java\iplots.jar;C:\PROGRA~1\R\R-211~1.1\library\JGR\java\JGR.jar;C:\PROGRA~1\R\R-211~1.1\etc\classes;C:\PROGRA~1\R\R-211~1.1\etc\classes.jar argv[2]:-Xmx512m argv[3]:-cp argv[4]:C:\PROGRA~1\R\R-211~1.1\library\rJava\java\boot argv[5]:-Drjava.path=C:\PROGRA~1\R\R-211~1.1\library\rJava argv[6]:-Dmain.class=org.rosuda.JGR.JGR argv[7]:-Djgr.load.pkgs=yes argv[8]:-Djgr.loader.ver=1.61 argv[9]:RJavaClassLoader argv[10]:--debug

    Read the article

  • Loading zsh as the default shell in gnu screen

    - by joel
    Hello, Im using KUbuntu 10.04 (Lucid Lynx). I have installed zsh and screen. I have set zsh as the default shell, by setting Command to zsh in Settings-Edit Current Profile of the terminal. But,when i launch screen,the bash shell is loaded. If i run the command zsh, then zsh starts but the following message is displayed: "/home/joel/.zshrc:36: Can't add module parameter `mapfile': parameter already exists" Also,zsh is invoked for only the current screen instance and i have to invoke it manually again for other instances. So,is there any way to make screen load zsh by default and invoke it automatically for every instance ? Thank You

    Read the article

  • Socket error in python

    - by Alice Everett
    I am using python-monetdb 11.16.0.7. I created my database farm and database according to instructions given below (source: http://www.monetdb.org/Documentation/monetdbd) % monetdbd start /home/my-dbfarm % monetdb create my-first-db Then I tried to connect to the database using the below mentioned command in python(https://pypi.python.org/pypi/python-monetdb/). Upon doing so I am getting the below mentioned error: >import monetdb.sql >connection=monetdb.sql.connect(username="monetdb",password="monetdb",hostname="localhost",database="my-first-db"); File "/usr/local/lib/python2.7/dist-packages/monetdb/sql/__init__.py", line 28, in connect return Connection(*args, **kwargs) File "/usr/local/lib/python2.7/dist-packages/monetdb/sql/connections.py", line 58, in __init__ unix_socket=unix_socket) File "/usr/local/lib/python2.7/dist-packages/monetdb/mapi.py", line 93, in connect self.socket.connect((hostname, port)) File "/usr/lib/python2.7/socket.py", line 224, in meth return getattr(self._sock,name)(*args) socket.error: [Errno 111] Connection refused Can someone please help me with this?

    Read the article

  • ASP .net MVC Invoking default controller and action vs Setting a startup page

    - by SARAVAN
    Hi, I am developing code on the sample ASP .net MVC template provided by VS2010. The first time I ran the code without adding anything, the index.aspx page was invoked which is expected. But for some reasons I added a login.aspx and then accidentally set that as a startup page. Now when I ran the application the default startup url look like http://localhost/Views/login.aspx. I am thinking this is not a valid MVC routing path and I get the requested resource cannot be found error. I am not sure how to revert this back and make sure the default ../home/index is invoked. Can any one throw some light on this? Also should I not set the startup page as we do in asp .net webforms?

    Read the article

  • Need help with this Regex + UrlRewriter.NET please :)

    - by Pure.Krome
    Previously, on StackOverflow ... (Summarized) I need to capture all requests, for a particluar subdomain .. and rewrite their destination. Now, the trick to determining the host via regex was solved. Now, i need to make sure all requests to the root index page is rewritten, but i can't figure out the correct regex to find the 'homepage' / website root. this is what i have.... <if header="HTTP_HOST" match="^foo\.mydomain\.com\.au(?::\d+)?/?$"> <!-- snip some other rewrites, eg./buying/product -> ~/Pages/Foo/Bar.aspx --> <rewrite url="^/$" to="~/Pages/SomeWeirdFolder/Home.aspx" processing="stop"/> </if> Now if one of the rewrites were not found, then it falls through and continues. So .. can anyone please help?

    Read the article

  • How to disable all hardware keys programatically in android?

    - by Raghu Rami Reddy
    I am developing android application with lock functionality. please suggest me how to disable all the hard keys programatically. here i am using beleow code to disable back button. i want like this functionality for all hard keys like home,search,camera, shortcut keys here is my code: @Override public boolean onKey(View v, int keyCode, KeyEvent event) { if (keyCode == KeyEvent.KEYCODE_SEARCH) { Log.d("KeyPress", "search"); return true; } return false; } Thanks in advance.

    Read the article

  • I'm installing mysql with homebrew, how do I set value to 'log_output'?

    - by imjared
    I've been following directions here: brew install mysql on mac os and have now run into the same issue both on my home machine and work (both MacBook Pro running OSX 10.7.5 and ZSH): 121031 12:18:03 [ERROR] /usr/local/opt/mysql/bin/mysqld: Error while setting value '/Users/me/.mysql/logs/' to 'log_output' The full output of the error can be found in this gist: https://gist.github.com/3988275 I'm really at a loss for what I'm doing incorrectly or what I need to change. It should be noted that there are no logs for me to check in /usr/local/var/mysql. Any help is greatly appreciated.

    Read the article

  • Internet Explorer not displaying gif file

    - by INTPnerd
    My friend is making a website for a class. Some of the pages display gif image files as links. They display correctly in Firefox and Chrome but not in Internet Explorer. Anybody know why? Here is a line of html code that should display the gif links: <a href="kendo.htm"><img src="arrowprev.gif" alt="previous page arrow"/></a> | <a href="index.htm">HOME</a> | <a href="festivals.htm"><img src="arrownext.gif" alt="next page arrow"/></a> Thanks for the help!

    Read the article

  • Autmatically create table on MySQL server based on date?

    - by Anthony
    Is there an equivalent to cron for MySQL? I have a PHP script that queries a table based on the month and year, like: SELECT * FROM data_2010_1 What I have been doing until now is, every time the script executes it does a query for the table, and if it exists, does the work, if it doesn't it creates the table. I was wondering if I can just set something up on the MySQL server itself that will create the table (based on a default table) at the stroke of midnight on the first of the month. Update Based on the comments I've gotten, I'm thinking this isn't the best way to achieve my goal. So here's two more questions: If I have a table with thousands of rows added monthly, is this potentially a drag on resources? If so, what is the best way to partition this table, since the above is verboten? What are the potential problems with my home-grown method I originally thought up?

    Read the article

  • Strange JavaScript Regular Expression Behavior

    - by Kiwi
    I'm getting different behavior from a regular expression in JavaScript depending on whether or not I declare it using literal syntax. Using a extremely simple test HTML file: <html> <head> <script type="text/javascript"> var s = '3'; var regex1 = /\d/; var regex2 = new RegExp('\d'); alert(s.search(regex1)); // 0 (matches) alert(s.search(regex2)); // -1 (does not match) </script> </head> <body></body> </html> The regular expression declared with literal syntax (/\d/) works correctly, while the other (new RegExp('\d')) does not. Why on earth is this happening? I'm using Google Chrome 5.0.375.70 on Windows Vista Home Premium, if that's at all helpful.

    Read the article

  • ffmpeg libavcodec.so missing while compile with cygwin

    - by nick
    I am building ffmpeg for android by following this tutorial now i got android folder inside the ffmpeg2.0.1 folder but there is no libavcodec-55.so file. instead of that i have lib/libavcodec.a how can i get libavcodec.so file? build_android.sh #!/bin/bash NDK=$HOME/Desktop/adt/android-ndk-r9 SYSROOT=$NDK/platforms/android-9/arch-arm/ TOOLCHAIN=$NDK/toolchains/arm-linux-androideabi-4.8/prebuilt/windows-x86_64 function build_one { ./configure \ --prefix=$PREFIX \ --enable-shared \ --disable-static \ --disable-doc \ --disable-ffmpeg \ --disable-ffplay \ --disable-ffprobe \ --disable-ffserver \ --disable-avdevice \ --disable-doc \ --disable-symver \ --cross-prefix=$TOOLCHAIN/bin/arm-linux-androideabi- \ --target-os=linux \ --arch=arm \ --enable-cross-compile \ --sysroot=$SYSROOT \ --extra-cflags="-Os -fpic $ADDI_CFLAGS" \ --extra-ldflags="$ADDI_LDFLAGS" \ $ADDITIONAL_CONFIGURE_FLAG make clean make make install } CPU=arm PREFIX=$(pwd)/android/$CPU ADDI_CFLAGS="-marm" build_one

    Read the article

  • scala REPL is slow on vista

    - by Jacques René Mesrine
    I installed scala-2.8.0.RC3 by extracting the tgz file into my cygwin (vista) home directory. I made sure to set $PATH to scala-2.8.0.RC3/bin. I start the REPL by typing: $ scala Welcome to Scala version 2.8.0.RC3 (Java HotSpot(TM) Client VM, Java 1.6.0_20). Type in expressions to have them evaluated. Type :help for more information. scala> Now when I tried to enter an expression scala> 1 + 'a' the cursor hangs there without any response. Granted that I have chrome open with a million tabs and VLC playing in the background, but CPU utilization was 12% and virtual memory was about 75% utilized. What's going on ? Do I have to set the CLASSPATH or perform other steps.

    Read the article

  • How to achieve this site structure?

    - by Sushant
    Hi, I need to develop a website that looks like this. In central administration however, in the operations tab, It shows Central Administration-- Operations. But I checked, operations is not a subsite. Then what is it. In my application, I always get Home-- Operations. To add to trouble,it changes the name at the top as Operations. I need to keep it central administration only. Please help me sort this out. Thanks.

    Read the article

  • Returning Json object from controller action to jQuery

    - by PsychoCoder
    I'm attempting to get this working properly (2 days now). I'm working on a log in where I'm calling the controller action from jQuery, passing it a JSON object (utilizing json2.js) and returning a Json object from the controller. I'm able to call the action fine, but instead of being able to put the response where I want it it just opens a new window with this printed on the screen: {"Message":"Invalid username/password combination"} And the URL looks like http://localhost:13719/Account/LogOn so instead of calling the action and not reloading the page it's taking the user to the controller, which isn't good. So now for some code, first the controller code [HttpPost] public ActionResult LogOn(LogOnModel model, string returnUrl = "") { if (ModelState.IsValid) { var login = ObjectFactory.GetInstance<IRepository<PhotographerLogin>>(); var user = login.FindOne(x => x.Login == model.Username && x.Pwd == model.Password); if (user == null) return Json(new FailedLoginViewModel { Message = "Invalid username/password combination" }); else { if (!string.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } return RedirectToAction("Index", "Home"); } And the jQuery code $("#signin_submit").click(function () { var login = getLogin(); $.ajax({ type: "POST", url: "../Account/LogOn", data: JSON.stringify(login), dataType: 'json', contentType: 'application/json; charset=utf-8', error: function (xhr) { $("#message").text(xhr.statusText); }, success: function (result) { } }); }); function getLogin() { var un = $("#username").val(); var pwd = $("#password").val(); var rememberMe = $("#rememberme").val(); return (un == "") ? null : { Username: un, Password: pwd, RememberMe: rememberMe }; } In case you need to see the actual login form here that is as well <fieldset id="signin_menu"> <div> <span id="message"></span> </div> <% Html.EnableClientValidation(); %> <% using (Html.BeginForm("LogOn", "Account", FormMethod.Post, new { @id = "signin" })) {%> <% ViewContext.FormContext.ValidationSummaryId = "valLogOnContainer"; %> <%= Html.LabelFor(m => m.Username) %> <%= Html.TextBoxFor(m => m.Username, new { @class = "inputbox", @tabindex = "4", @id = "username" })%><%= Html.ValidationMessageFor(m => m.Username, "*")%> <p> <%= Html.LabelFor(m=>m.Password) %> <%= Html.PasswordFor(m => m.Password, new { @class = "inputbox", @tabindex = "5", @id = "password" })%><%= Html.ValidationMessageFor(m => m.Password, "*")%> </p> <p class="remember"> <input id="signin_submit" value="Sign in" tabindex="6" type="submit"/> <%= Html.CheckBoxFor(m => m.RememberMe, new { @class = "inputbox", @tabindex = "7", @id = "rememberme" })%> <%= Html.LabelFor(m => m.RememberMe) %> <p class="forgot"> <a href="#" id="forgot_password_link" title="Click here to reset your password.">Forgot your password?</a> </p> <p class="forgot-username"> <a href="#" id="forgot_username_link" title="Fogot your login name? We can help with that">Forgot your username?</a> </p> </p> <%= Html.ValidationSummaryJQuery("Please fix the following errors.", new Dictionary<string, object> { { "id", "valLogOnContainer" } })%> <% } %> </fieldset> The login form is loaded on the main page with <% Html.RenderPartial("LogonControl");%> Not sure if that has any bearing on this or not but thought I'd mention it. EDIT: The login form is loaded similar to the Twitter login, click a link and the form loads with the help of jQuery & CSS

    Read the article

  • Assigning a MVC Controller property from Asp.Net page

    - by JasonMHirst
    I don't know if I've understanding MVC correctly if my question makes no sense, but I'm trying to understand the following: I have some code on a controller that returns JSON data. The JSON data is populated based on a choice from a dropdown box on an Asp.Net page. I thought (incorrectly) that Session variables would be shared between the Asp.Net project and the MVC Project. What I'd like to do therefore (if this is possible), is to call a Sub on the MVC that sets a variable before the JSON query is run. I have the following: Sub SetCountryID(ByVal CountryID As Integer) Me.pCountrySelectedID = CountryID End Sub Which I can call by the following: Response.Write("http://localhost:7970/Home/SetCountryID/?CountryID=44") But this then results in a blank page - again obviouslly totally incorrect! Am I going about MVC the wrong way or do I still have a hell of a lot more learning to do? Is this even possible to do?

    Read the article

  • Memory section handling error

    - by Basilevs
    I'm getting a link time error: WARNING: /home/gulevich/development/camac-fedorov/camac/linux/k0607-lsi6/camac-k0607-lsi6.o (.ctors): unexpected non-allocatable section. Did you forget to use "ax"/"aw" in a .S file? Note that for example <linux/init.h> contains section definitions for use in .S files. The code causing the error (assembly in C source): # if defined(__ELF__) # define __SECTION_FLAGS ", \"aw\" , @progbits" /* writable flag needed for ld ".[cd]tors" sections bug workaround) */ # elif defined(__COFF__) # define __SECTION_FLAGS ", \"dr\"" /* untested, may be writable flag needed */ # endif asm ( ".section .ctors" __SECTION_FLAGS "\n" ".globl __ctors_begin__\n" "__ctors_begin__:\n" ".previous\n" ); Is there any way to fix this? The idea is to put a varaible __ctors_begin__ at the beginning of a certain memory section. This code is a legacy that worked fine using a different build system and older compiler. Meaning of this assembly code explained in an answer to my previous question.

    Read the article

  • Overriding constructors

    - by demas
    Here is sample code: class One def initialize(*args) case args.size when 0 puts "one initialize" when 1 puts "one initialize #{args[0]}" end end end class Two def initialize(*args) if args.size == 2 then puts "two initialize #{args[0]} and #{args[1]}" else super(args) end end end one = One.new one = One.new("thing") two = Two.new("some", "other") two = Two.new("some") Now I'm launching the code and getting the error message: [demas@arch.home.net][~/temp]% ruby test2.rb one initialize one initialize thing two initialize some and other test2.rb:17:in `initialize': wrong number of arguments(1 for 0) (ArgumentError) from test2.rb:17:in `initialize' from test2.rb:26:in `new' from test2.rb:26:in `<main>' How can I call parent's constructor from class Two ?

    Read the article

  • How does tomcat set its executable file as a windows service?

    - by Wing C. Chen
    Firstly, I am not at all familiar with windows batch file programing. Recently I am curious about how tomcat sets itself as a windows service using a batch file. I downloaded the service.bat file from tomcat 6. However, I still don't understand some part of it. I guess this is the line that the batch actually register the exe file to the OS, is it right? Is there any syntax explanation? "%EXECUTABLE%" //IS//%SERVICE_NAME% --StartClass org.apache.catalina.startup.Bootstrap --StopClass org.apache.catalina.startup.Bootstrap --StartParams start --StopParams stop And is this used to remove the service? "%EXECUTABLE%" //DS//%SERVICE_NAME% And this is the setting of the parameters? "%EXECUTABLE%" //US//%SERVICE_NAME% --JvmOptions "-Dcatalina.base=%CATALINA_BASE%;-Dcatalina.home=%CATALINA_HOME%;-Djava.endorsed.dirs=%CATALINA_HOME%\endorsed" --StartMode jvm --StopMode jvm Thanks.

    Read the article

  • IE Display bug - solved when using the "developer tools"?

    - by nute
    I have some Javascript/CSS issues with IE (no suprises?). So when I see the error in IE8, I go to Tools Developer Tools. Then I navigate to the correct DIV. I click on it, look around ... then I look again at my page, and the problem is fixed! This makes debugging pretty difficult... To see the display error, go to http://www.makemeheal.com/mmh/home.do in IE, and look at the "Your Recent History" module.

    Read the article

  • WCFExtras SOAP headers support returns null reference exception

    - by jlp
    I use WCFExtras to add headers to my service. I set up everything according to http://wcfextras.codeplex.com/wikipage?title=HowToUse&referringTitle=Home My WCF client works but throws NullReferenceException on both: client.InnerChannel.SetHeader("myHeader", new local.Header()); and var header = client.InnerChannel.GetHeader<local.Header>("myHeader"); I wonder if web.config element <wsdlExtensions location="noidea" singleFile="True"/> might cause a problem because I don't know what type in location attribute. I simply tried to type service address but it didn't fix anything.

    Read the article

  • Problems with list<T> in Asp.Net c#

    - by Johnathan Nardia
    I'm making a web app in Asp.Net using c# that lets you add items into the list. My problem is that each time that i click the button to add a new item into the list , its just shows me the last item and the list counter shows me only 1 . What am I doing wrong?? Here is the code : public partial class home : System.Web.UI.Page { List<string> messageboxs = new List<string>(); public string val = ""; public string data = ""; protected void Button1_Click(object sender, EventArgs e) { val = ""; messageboxs.Add(text1.Text); ListBox1.DataSource = messageboxs; ListBox1.DataBind(); val = messageboxs.Count.ToString(); } }

    Read the article

  • What is a good way to sync code files between computer?

    - by erotsppa
    I have a need to code from two computers during the week. What is the best way to sync the two computers (mac)? I've started using source control, like SVN. It works pretty good, except sometimes I check in code that I want to sync but they don't compile and it interferes with other people on the team working on the same project. I don't want to use branch. It wouldn't make sense to branch every night when I head home from office.

    Read the article

< Previous Page | 421 422 423 424 425 426 427 428 429 430 431 432  | Next Page >