Search Results

Search found 20677 results on 828 pages for 'python team'.

Page 426/828 | < Previous Page | 422 423 424 425 426 427 428 429 430 431 432 433  | Next Page >

  • Google App Engine - Is os.environ reset between requests?

    - by Ian Charnas
    Hello I can't think of a way to test this and was hoping someone here knew the answer... I'm storing some request-specific data in os.environ, and was wondering if that data was going to leak to other requests. Does anyone know? Yes I realize that it's normal to use request.environ for this, and usually I do, but I want to store the currently authorized user ID (I'm using custom auth, not GAE auth) inside os.environ so that the models know the currently logged in user (remember, they don't have access to request.environ) without me having to pass the request object to just about every single model method. any help would be greatly appreciated Ian

    Read the article

  • Type-aware rendering (and editing) of tabular data in pyqt4

    - by pihentagy
    I would like to have a very short / minimal example of how to create some tabular widget with different types of item in it. In the first round let's say I'd like to render [["Hello", 12, True], ["World", 13, False]] (Hello as string, 12 as number (right-align), True as a checkbox for eg.), but it would be nice to have Dates, Colors, and other type of info. Next round: editing (integer with spinbox, maybe sometimes a combobox is handy, but that may not work out of the box). There must be a simple solution, but I couldn't find...

    Read the article

  • using dictionary to assign misspelled words to its line number

    - by jad
    This is the code I have so far d = {} counter = 0 for lines in words: counter += 1 for word in text1: if word not in words: d[word] = [counter] else: d[word].append(counter) print(word, d[counter]) words = my text file text1 is my misspelled words But this gives me an error. What I want to do is print the word and the line number e.g. togeher 5 7

    Read the article

  • how to print the linenumber of incorrectwords located in a txt file ?

    - by jad
    i have this piece of code which only prints the line number of the incorrect words. i want it to print the linenumbers of the incorrect words from the txt file. Am i able to modify this code to do that? # text1 is my incorrect words # words is my text file where my incorrect word are in from collections import defaultdict d = defaultdict(list) for lineno, word in enumerate(text1): d[word].append(lineno) print(d)

    Read the article

  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

    Read the article

  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

    Read the article

  • Finding out event that called a CGI script

    - by Acorn
    What I want is to be able to make my CGI script do different things depending on what action initiated the calling of the script. For example, if one button is pressed, a database is cleared. If another button is pressed, a form is submitted and that data is added to the database. Should I be doing something like adding the name of the form/button to the end of the POST data submitted in jQuery and then .poping it off in the script? Or is there some other data that's already sent in the POST that I could get from FieldStorage that would give me the information I need to decide what the script should do when it's called? And what if I wasn't using javascript? Would I have to have a hidden field that gets submitted with the name of the form/button? Or is it best to use a different target script for each button on a page?

    Read the article

  • Showing updated content on the client

    - by tazim
    Hi, I have a file on server which is viewed by the client asynchronously as and when required . The file is going to get modified on server side . Also updates are reflected in browser also In my views.py the code is : def showfiledata(request): somecommand ="ls -l > /home/tazim/webexample/templates/tmp.txt" with open("/home/tazim/webexample/templates/tmp.txt") as f: read_data = f.read() f.closed return_dict = {'filedata':read_data} json = simplejson.dumps(return_dict) return HttpResponse(json,mimetype="application/json") Here, entire file is sent every time client requests for the file data .Instead I want that only modified data sholud be received since sending entire file is not feasible if file size is large . My template code is : < html> < head> < script type="text/javascript" src="/jquerycall/">< /script> < script type="text/javascript"> $(document).ready(function() { var setid = 0; var s = new String(); var my_array = new Array(); function displayfile() { $.ajax({ type:"POST", url:"/showfiledata/", datatype:"json", success:function(data) { s = data.filedata; my_array = s.split("\n"); displaydata(my_array); } }); } function displaydata(my_array) { var i = 0; length = my_array.length; for(i=0;i<my_array.length;i++) { var line = my_array[i] + "\n"; $("#textid").append(line); } } $("#b1").click(function() { setid= setInterval(displayfile,1000); }); $("#b2").click(function() { clearInterval(setid); }) }); < /script> < /head> < body> < form method="post"> < button type="button" id="b1">Click Me< /button>< br>< br> < button type="button" id="b2">Stop< /button>< br>< br> < textarea id="textid" rows="25" cols="70" readonly="true" disabled="true">< /textarea> < /form> </body> </html> Any Help will be beneficial . some sample code will be helpful to understand

    Read the article

  • Remove all user's cookies/sessions when password is reset

    - by Juraj
    I'm interested in improving security of my TurboGears 2.2 application so that when user changes his password, it logs him out from all sessions and he must login again. When user changes password on browser 1, he must relogin on browser 2, too. Experiments show that this is not the case, especially if browser 2 had "remember me" enabled. It's standard quickstarted app using repoze.who. It seems maybe I need to change AuthTktCookiePlugin, but don't see a way to do it without much rewiring.

    Read the article

  • django file serving issues

    - by tipu
    I have in my url patterns, urlpatterns += patterns('', (r'^(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/home/tipu/Dropbox/dev/workspace/search/images'}) In my template when I do <link rel="stylesheet" type="text/css" href="{{ MEDIA_URL }}style.css" /> It serves the css just fine. But the file logo.png, that's in the same directory as style.css, doesn't show when I do this: <img src = "{{ MEDIA_URL }}logo.png" id = "logo" /> Any idea why?

    Read the article

  • wxPython ,Change the background colour of a StyledTextCtrl

    - by user1357159
    I tried (but nothing happens) self.txt.SetBackgroundColour ((255,0,0)) As said in the title I'm trying to change the background colour StyledTextCtrl. Does anyone know a method that could be used? I've checked the API docs but I couldn't seem to find one, http://wxpython.org/docs/api/wx.stc.StyledTextCtrl-class.html (by background colour, I mean the whole writing area, of course) Does anyone know a way I could do this? EDIT: The background doesn't change in the following code import wx import wx.stc app = wx.App(redirect=True) top = wx.Frame(None, title="StyledTXTCtrl", size=(300,200)) txt=wx.stc.StyledTextCtrl(top) txt.SetBackgroundColour((255,255,0)) txt.Refresh() top.Show() app.MainLoop()

    Read the article

  • Django. default=datetime.now() problem

    - by Shamanu4
    Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

    Read the article

  • MongoDB lists with paginations?

    - by Timmy
    for documents with lists with pagination, is it better to embed or use reference? im reading the custom type "SONManipulator" and it appears to transform every thing on retrieval, even the sub docs. i want to keep the list in the document sorted, should this impact anything?

    Read the article

  • How to join list of strings?

    - by satsurae
    Hi all, This is probably seriously easy to solve for most of you but I cannot solve this simply putting str() around it can I? I would like to convert this list: ['A','B','C'] into 'A B C'. Thanks in advance!!

    Read the article

  • Py GTK Drawing area and Rich Text Editor

    - by crashekar
    I would like to include a rich text editor in a pygtk drawing area for an application i am developing. The editor ( a small resizable widget ) should be able to move around the drawing area like a rectangle. I am not sure how to start as I am pretty new to PyGTK. thank you !

    Read the article

  • make a tree based on the key of each element in list.

    - by cocobear
    >>> s [{'000000': [['apple', 'pear']]}, {'100000': ['good', 'bad']}, {'200000': ['yeah', 'ogg']}, {'300000': [['foo', 'foo']]}, {'310000': [['#'], ['#']]}, {'320000': ['$', ['1']]}, {'321000': [['abc', 'abc']]}, {'322000': [['#'], ['#']]}, {'400000': [['yeah', 'baby']]}] >>> for i in s: ... print i ... {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} i want to make a tree based on the key of each element in list. result in logic will be: {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} perhaps a nested list can implement this or I need a tree type?

    Read the article

  • programs hangs during socket interaction

    - by herrturtur
    I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

    Read the article

  • Calculating the null space of a matrix

    - by Ainsworth
    I'm attempting to solve a set of equations of the form Ax = 0. A is known 6x6 matrix and I've written the below code using SVD to get the vector x which works to a certain extent. The answer is approximately correct but not good enough to be useful to me, how can I improve the precision of the calculation? Lowering eps below 1.e-4 causes the function to fail. from numpy.linalg import * from numpy import * A = matrix([[0.624010149127497 ,0.020915658603923 ,0.838082638087629 ,62.0778180312547 ,-0.336 ,0], [0.669649399820597 ,0.344105317421833 ,0.0543868015800246 ,49.0194290212841 ,-0.267 ,0], [0.473153758252885 ,0.366893577716959 ,0.924972565581684 ,186.071352614705 ,-1 ,0], [0.0759305208803158 ,0.356365401030535 ,0.126682113674883 ,175.292109352674 ,0 ,-5.201], [0.91160934274653 ,0.32447818779582 ,0.741382053883291 ,0.11536775372698 ,0 ,-0.034], [0.480860406786873 ,0.903499596111067 ,0.542581424762866 ,32.782593418975 ,0 ,-1]]) def null(A, eps=1e-3): u,s,vh = svd(A,full_matrices=1,compute_uv=1) null_space = compress(s <= eps, vh, axis=0) return null_space.T NS = null(A) print "Null space equals ",NS,"\n" print dot(A,NS)

    Read the article

  • Django throws 404 at generic views

    - by x0rg
    I'm trying to get the generic views for a date-based archive working in django. I defined the urls as described in a tutorial, but django returns a 404 error whenever I want to access an url with a variable (such as month or year) in it. It don't even produces a TemplateDoesNotExist-execption. Normal urls without variables work fine. Here's my urlconf: from django.conf.urls.defaults import * from zurichlive.zhl.models import Event info_dict = { 'queryset': Event.objects.all(), 'date_field': 'date', 'allow_future': 'True', } urlpatterns += patterns('django.views.generic.date_based', (r'events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, slug_field='slug',template_name='archive/detail.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, template_name='archive/list.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/$','archive_day',dict(info_dict,template_name='archive/list.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/$','archive_month', dict(info_dict, template_name='archive/list.html')), (r'^events/(?P<year>)/$','archive_year', dict(info_dict, template_name='archive/list.html')), (r'^events/$','archive_index', dict(info_dict, template_name='archive/list.html')), ) When I access /events/2010/may/12/this-is-a-slug I should get to the detail.html template, but instead I get a 404. What am I doing wrong?

    Read the article

  • Strip text except from the contents of a tag

    - by myle
    The opposite may be achieved using pyparsing as follows: from pyparsing import Suppress, replaceWith, makeHTMLTags, SkipTo #... removeText = replaceWith("") scriptOpen, scriptClose = makeHTMLTags("script") scriptBody = scriptOpen + SkipTo(scriptClose) + scriptClose scriptBody.setParseAction(removeText) data = (scriptBody).transformString(data) How could I keep the contents of the tag "table"?

    Read the article

  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

    Read the article

< Previous Page | 422 423 424 425 426 427 428 429 430 431 432 433  | Next Page >