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  • Calculating the null space of a matrix

    - by Ainsworth
    I'm attempting to solve a set of equations of the form Ax = 0. A is known 6x6 matrix and I've written the below code using SVD to get the vector x which works to a certain extent. The answer is approximately correct but not good enough to be useful to me, how can I improve the precision of the calculation? Lowering eps below 1.e-4 causes the function to fail. from numpy.linalg import * from numpy import * A = matrix([[0.624010149127497 ,0.020915658603923 ,0.838082638087629 ,62.0778180312547 ,-0.336 ,0], [0.669649399820597 ,0.344105317421833 ,0.0543868015800246 ,49.0194290212841 ,-0.267 ,0], [0.473153758252885 ,0.366893577716959 ,0.924972565581684 ,186.071352614705 ,-1 ,0], [0.0759305208803158 ,0.356365401030535 ,0.126682113674883 ,175.292109352674 ,0 ,-5.201], [0.91160934274653 ,0.32447818779582 ,0.741382053883291 ,0.11536775372698 ,0 ,-0.034], [0.480860406786873 ,0.903499596111067 ,0.542581424762866 ,32.782593418975 ,0 ,-1]]) def null(A, eps=1e-3): u,s,vh = svd(A,full_matrices=1,compute_uv=1) null_space = compress(s <= eps, vh, axis=0) return null_space.T NS = null(A) print "Null space equals ",NS,"\n" print dot(A,NS)

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  • Change|Assign parent for the Model instance on Google App Engine Datastore

    - by Vladimir Prudnikov
    Is it possible to change or assign new parent to the Model instance that already in datastore? For example I need something like this task = db.get(db.Key(task_key)) project = db.get(db.Key(project_key)) task.parent = project task.put() but it doesn't works this way because task.parent is built-in method. I was thinking about creating a new Key instance for the task but there is no way to change key as well. Any thoughts?

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  • Django. default=datetime.now() problem

    - by Shamanu4
    Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

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  • Flask Admin didn't show all fields

    - by twoface88
    I have model like this: class User(db.Model): __tablename__ = 'users' __table_args__ = {'mysql_engine' : 'InnoDB', 'mysql_charset' : 'utf8'} id = db.Column(db.Integer, primary_key=True) username = db.Column(db.String(80), unique=True) email = db.Column(db.String(120), unique=True) _password = db.Column('password', db.String(80)) def __init__(self, username = None, email = None, password = None): self.username = username self.email = email self._set_password(password) def _set_password(self, password): self._password = generate_password_hash(password) def _get_password(self): return self._password def check_password(self, password): return check_password_hash(self._password, password) password = db.synonym("_password", descriptor=property(_get_password, _set_password)) def __repr__(self): return '<User %r>' % self.username I have ModelView: class UserAdmin(sqlamodel.ModelView): searchable_columns = ('username', 'email') excluded_list_columns = ['password'] list_columns = ('username', 'email') form_columns = ('username', 'email', 'password') But no matter what i do, flask admin didn't show password field when i'm editing user info. Is there any way ? Even just to edit hash code. UPDATE: https://github.com/mrjoes/flask-admin/issues/78

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  • UDP security and identifying incoming data.

    - by Charles
    I have been creating an application using UDP for transmitting and receiving information. The problem I am running into is security. Right now I am using the IP/socketid in determining what data belongs to whom. However, I have been reading about how people could simply spoof their IP, then just send data as a specific IP. So this seems to be the wrong way to do it (insecure). So how else am I suppose to identify what data belongs to what users? For instance you have 10 users connected, all have specific data. The server would need to match the user data to this data we received. The only way I can see to do this is to use some sort of client/server key system and encrypt the data. I am curious as to how other applications (or games, since that's what this application is) make sure their data is genuine. Also there is the fact that encryption takes much longer to process than unencrypted. Although I am not sure by how much it will affect performance. Any information would be appreciated. Thanks.

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  • make a tree based on the key of each element in list.

    - by cocobear
    >>> s [{'000000': [['apple', 'pear']]}, {'100000': ['good', 'bad']}, {'200000': ['yeah', 'ogg']}, {'300000': [['foo', 'foo']]}, {'310000': [['#'], ['#']]}, {'320000': ['$', ['1']]}, {'321000': [['abc', 'abc']]}, {'322000': [['#'], ['#']]}, {'400000': [['yeah', 'baby']]}] >>> for i in s: ... print i ... {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} i want to make a tree based on the key of each element in list. result in logic will be: {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} perhaps a nested list can implement this or I need a tree type?

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  • How to insert several thousand columns into sqlite3?

    - by user291071
    Similar to my last question, but I ran into problem lets say I have a simple dictionary like below but its Big, when I try inserting a big dictionary using the methods below I get operational error for the c.execute(schema) for too many columns so what should be my alternate method to populate an sql databases columns? Using the alter table command and add each one individually? import sqlite3 con = sqlite3.connect('simple.db') c = con.cursor() dic = { 'x1':{'y1':1.0,'y2':0.0}, 'x2':{'y1':0.0,'y2':2.0,'joe bla':1.5}, 'x3':{'y2':2.0,'y3 45 etc':1.5} } # 1. Find the unique column names. columns = set() for _, cols in dic.items(): for key, _ in cols.items(): columns.add(key) # 2. Create the schema. col_defs = [ # Start with the column for our key name '"row_name" VARCHAR(2) NOT NULL PRIMARY KEY' ] for column in columns: col_defs.append('"%s" REAL NULL' % column) schema = "CREATE TABLE simple (%s);" % ",".join(col_defs) c.execute(schema) # 3. Loop through each row for row_name, cols in dic.items(): # Compile the data we have for this row. col_names = cols.keys() col_values = [str(val) for val in cols.values()] # Insert it. sql = 'INSERT INTO simple ("row_name", "%s") VALUES ("%s", "%s");' % ( '","'.join(col_names), row_name, '","'.join(col_values) )

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  • Time difference in seconds (as a floating point)

    - by pocoa
    >>> from datetime import datetime >>> t1 = datetime.now() >>> t2 = datetime.now() >>> delta = t2 - t1 >>> delta.seconds 7 >>> delta.microseconds 631000 Is there any way to get that as 7.631000 ? I can use time module, but I also need that t1 and t2 variables as DateTime objects. So if there is a way to do it with datettime, that would be great.

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  • Strip text except from the contents of a tag

    - by myle
    The opposite may be achieved using pyparsing as follows: from pyparsing import Suppress, replaceWith, makeHTMLTags, SkipTo #... removeText = replaceWith("") scriptOpen, scriptClose = makeHTMLTags("script") scriptBody = scriptOpen + SkipTo(scriptClose) + scriptClose scriptBody.setParseAction(removeText) data = (scriptBody).transformString(data) How could I keep the contents of the tag "table"?

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  • Problems with 'while' loop and 'for' loop when reading through file

    - by David Beckham
    I wasted plenty of hours trying to figure out the problem but no luck. Tried asking the TA at my school, but he was useless. I am a beginner and I know there are a lot of mistakes in it, so it would be great if I can get some detail explanation as well. Anyways, basically what I am trying to do with the following function is: Use while loop to check and see if random_string is in TEXT, if not return NoneType if yes, then use a for loop to read lines from that TEXT and put it in list, l1. then, write an if statement to see if random_string is in l1. if it is, then do some calculations. else read the next line Finally, return the calculations as a whole. TEXT = open('randomfile.txt') def random (TEXT, random_string): while random_string in TEXT: for lines in TEXT: l1=TEXT.readline().rsplit() if random_string in l1: ''' do some calculations ''' else: TEXT.readline() #read next line??? return #calculations return None

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  • Recursion function not working properly

    - by jakecar
    I'm having quite a hard time figuring out what's going wrong here: class iterate(): def init(self): self.length=1 def iterated(self, n): if n==1: return self.length elif n%2==0: self.length+=1 self.iterated(n/2) elif n!=1: self.length+=1 self.iterated(3*n+1) For example, x=iterate() x.iterated(5) outputs None. It should output 6 because the length would look like this: 5 -- 16 -- 8 -- 4 -- 2 -- 1 After doing some debugging, I see that the self.length is returned properly but something goes wrong in the recursion. I'm not really sure. Thanks for any help.

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  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

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  • Django throws 404 at generic views

    - by x0rg
    I'm trying to get the generic views for a date-based archive working in django. I defined the urls as described in a tutorial, but django returns a 404 error whenever I want to access an url with a variable (such as month or year) in it. It don't even produces a TemplateDoesNotExist-execption. Normal urls without variables work fine. Here's my urlconf: from django.conf.urls.defaults import * from zurichlive.zhl.models import Event info_dict = { 'queryset': Event.objects.all(), 'date_field': 'date', 'allow_future': 'True', } urlpatterns += patterns('django.views.generic.date_based', (r'events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, slug_field='slug',template_name='archive/detail.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, template_name='archive/list.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/$','archive_day',dict(info_dict,template_name='archive/list.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/$','archive_month', dict(info_dict, template_name='archive/list.html')), (r'^events/(?P<year>)/$','archive_year', dict(info_dict, template_name='archive/list.html')), (r'^events/$','archive_index', dict(info_dict, template_name='archive/list.html')), ) When I access /events/2010/may/12/this-is-a-slug I should get to the detail.html template, but instead I get a 404. What am I doing wrong?

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  • string problems, tuple strings.

    - by suresh
    a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple n+m+1 = k, where m is the length of the first substring. Complete the definition def constrainedMatchPair(firstMatch,secondMatch,length):

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  • How to do a back-reference on Google Webapp?

    - by jCuga
    I'm trying to access an object that is linked to by a db.ReferenceProperty in Google app engine. here's the model's code: class InquiryQuestion(db.Model): inquiry_ref = db.ReferenceProperty(reference_class=GiftInquiry, required=True, collection_name="inquiry_ref") And I am trying to access it in the following way: linkedObject = question.inquiry_ref and then linkedKey = linkedObject.key but it's not working. Can anyone please help?

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  • How can I identify an element from a list within another list

    - by Alex
    I have been trying to make a block of code that finds the index of the largest bid for each item. Then I was going to use the index as a way to identify the person who paid that much moneys name. However no matter what i try I can't link the person and what they have gained from the auction together. Here is the code I have been writing: It has to be able to work with any information inputted def sealedBids(): n = int(input('\nHow many people are in the group? ')) z = 0 g = [] s = [] b = [] f = [] w = []#goes by number of items q = [] while z < n: b.append([]) z = z + 1 z = 0 while z < n: g.append(input('Enter a bidders name: ')) z = z + 1 z = 0 i = int(input('How many items are being bid on?')) while z < i: s.append(input('Enter the name of an item: ')) w.append(z) z = z + 1 z = 0 for j in range(n):#specifies which persons bids your taking for k in range(i):#specifies which item is being bid on b[j].append(int(input('How much money has {0} bid on the {1}? '.format(g[j], s[k])))) print(' ') for j in range(n):#calculates fair share f.append(sum(b[j])/n) for j in range(i):#identifies which quantity of money was the largest for each item for k in range(n): if w[j] < b[k][j]: w[j] = b[k][j] q.append(k) any advice is much appreciated.

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  • Tkinter after that survives clock rewinding.

    - by Oren
    I noticed that in my version of Tkinter, the after() call does not survive system clock rewinding. If the after(x, func) was called, and the system clock was rewinded, func will be called only after the clock returned to its time before the rewind + x milliseconds. I assume this is because Tkinter uses the system-clock instead of the "time.clock" (the amount of time that the program is running). I tested it only on windows, and maybe its because I have an old version of Tkinter. I want my App to work on computers that synchronize their clock from the network... Does anyone have a simple solution?

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