Search Results

Search found 3545 results on 142 pages for 'arrays'.

Page 43/142 | < Previous Page | 39 40 41 42 43 44 45 46 47 48 49 50  | Next Page >

  • Array value setting in javascript

    - by Dennis
    Hello. Again I'm still new to this javascript thing, so just would like to know if there is another way of setting the values of an array (just like declaring it); //correct way of declaring an array and reusing var adata = new Array('1','2','3'); //reusing of variable adata[0] = '4'; adata[1] = '5'; adata[2] = '6' ** This part is my question; I want to declare the values of the array just like declaring them to minimize the number of lines; //array declaration var data = new Array('1','2','3'); //reusing of variable data = ['4','5','6']; --- (as an example) I get an error msg "Invalid assignment left-hand side" is this possible? If so, what is the correct syntax? I hope I'm making sense. Thanking you in advance.

    Read the article

  • Easiest way to pass a javascript array or its values to a servlet using jQuery's ajax() function

    - by Ankur
    I have a Javascript array. I want to pass it's data to a servlet using the ajax() method of jQuery. What is the easiest way to do this. The index values i.e. the i in array[i] are not in order, they are numbers that have meaning themselves, hence I cannot simply loop through and create a GET queryString, or so I believe. Maybe I should be converting the JavaScript array to a JSON Object and sending that to the server ?? I am stumped on this one.

    Read the article

  • Understanding ruby array sort

    - by user257797
    I am having a problem understanding how array.sort{|x,y| block} works exactly,hence how to use it? ruby-doc example: a = [ "d", "a", "e", "c", "b" ] a.sort #=> ["a", "b", "c", "d", "e"] a.sort {|x,y| y <=> x } #=> ["e", "d", "c", "b", "a"] thanks

    Read the article

  • Register javascript array from code behind in facebook

    - by Ahmy
    I need to set a javascript array from code behind using C# in Asp.Net2008 the problem now is that when i register the array using the following C# code: string ArrVal = ""; string Sep = ""; for (int i = 0; i < 17; i++) { ArrVal += Sep + FilesCount[i].ToString(); Sep = ","; } Page.ClientScript.RegisterArrayDeclaration("FilesArr", ArrVal); And the Client code is : var FileName = FilesArr[0]; in any web application it is working well but at my application that is released in the facebook platform the javascript code doesn't see the array but in ordinary web application the javscript code see the registered array can any one tell me why this problem occurrs ? Thanks in advance for any reply and trial.

    Read the article

  • C++ a class with an array of structs, without knowing how large an array I need

    - by Dominic Bou-Samra
    New to C++, and for that matter OO programming. I have a class with fields like firstname, age, school etc. I need to be able to store other information like for instance, where they have travelled, and what year it was in. I cannot declare another class specifically to hold travelDestination and what year, so I think a struct might be best. This is just an example: struct travel { string travelDest; string year; }; The issue is people are likely to have travelled different amounts. I was thinking of just having an array of travel structs to hold the data. But how do I create a fixed sized array to hold them, without knowing how big I need it to be? Perhaps I am going about this the completely wrong way, so any suggestions as to a better way would be appreciated.

    Read the article

  • type of an array

    - by Tim
    Hi, when I need to pass an array to a function, it seems all the following declarations of the function will work void f(int arr[]) void f(int arr[4]) // is this one correct? for this: int a[]={1,2,3,4}; f(a); But when I assign an array to another array, it fails int a[]={1,2,3,4}; int b[4] = a; // error: array must be initialized with a brace-enclosed initializer So why an array passed as an argument of a function is okay, but used on the rhs of simple assignment is wrong? Thanks!

    Read the article

  • Ladder-like word game in Java

    - by sasquatch90
    I've found this question http://stackoverflow.com/questions/2844190/choosing-design-method-for-ladder-like-word-game and I would also like to do this kind of program. I've written some code but already have two issues. Here's what I already have : GRID : public class Grid { public Grid(){} public Grid( Element e ){} } ELEMENT : public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){} //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public static void changeState(int s){ } public int getState(){ return state; } public boolean equalLength(){ return true; } public boolean equalValue(){ return true; } @Override public String toString(){ return "["+letter+"]"; } } MAIN: import java.util.Scanner; public class Main { public static void main(String[] args){ Scanner sc = new Scanner(System.in); System.out.println("Height: "); while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); Grid[] game = new Grid[height]; for(int i = 1; i <= height; i++) { String s; do { System.out.println("Length " + i + ", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()+1]; Element single = null; String[] temp = null; //issue here temp = s.split(""); System.out.println("s.length: "+s.length()); System.out.println("temp.length: "+temp.length); // for(String str : temp){ System.out.println("str:"+str); } for (int k = 0 ; k < temp.length ; k++) { if( k == 0 ){ single = new Element(temp[k], 2); System.out.println("single1: "+single); } else{ single = new Element(temp[k], 3); System.out.println("single2: "+single); } line[k] = single; } for (Element l : line) { System.out.println("line:"+l); } //issue here game[i] = line; } // for (Grid g : game) { System.out.println(g); } } } And sample output for debug : Height: 3 Length 1, please! A s.length: 1 temp.length: 2 str: str:A single1: [] single2: [A] line:[] line:[A] Here's what I think it should work like. I grab a word from user. Next create Grid element for whole game. Then for each line I create Element[] array called line. I split the given text and here's the first problem. Why string.split() adds a whitespace ? You can see clearly in output that it is added for no reason. How can I get rid of it (now I had to add +1 to the length of line just to run the code). Continuing I'm throwing the splitted text into temporary String array and next from each letter I create Element object and throw it to line array. Apart of this empty space output looks fine. But next problem is with Grid. I've created constructor taking Element as an argument, but still I can't throw line as Grid[] elements because of 'incompatible types'. How can I fix that ? Am I even doing it right ? Maybe I should get rid of line as Element[] and just create Grid[][] ?

    Read the article

  • Setting an Excel Range with an Array using Python and comtypes?

    - by technomalogical
    Using comtypes to drive Python, it seems some magic is happening behind the scenes that is not converting tuples and lists to VARIANT types: # RANGE(“C14:D21”) has values # Setting the Value on the Range with a Variant should work, but # list or tuple is not getting converted properly it seems >>>from comtypes.client import CreateObject >>>xl = CreateObject("Excel.application") >>>xl.Workbooks.Open(r'C:\temp\my_file.xlsx') >>>xl.Visible = True >>>vals=tuple([(x,y) for x,y in zip('abcdefgh',xrange(8))]) # creates: #(('a', 0), ('b', 1), ('c', 2), ('d', 3), ('e', 4), ('f', 5), ('g', 6), ('h', 7)) >>>sheet = xl.Workbooks[1].Sheets["Sheet1"] >>>sheet.Range["C14","D21"].Value() (('foo',1),('foo',2),('foo',3),('foo',4),('foo',6),('foo',6),('foo',7),('foo',8)) >>>sheet.Range["C14","D21"].Value[()] = vals # no error, this blanks out the cells in the Range According to the comtypes docs: When you pass simple sequences (lists or tuples) as VARIANT parameters, the COM server will receive a VARIANT containing a SAFEARRAY of VARIANTs with the typecode VT_ARRAY | VT_VARIANT. This seems to be inline with what MSDN says about passing an array to a Range's Value. I also found this page showing something similar in C#. Can anybody tell me what I'm doing wrong? EDIT I've come up with a simpler example that performs the same way (in that, it does not work): >>>from comtypes.client import CreateObject >>>xl = CreateObject("Excel.application") >>>xl.Workbooks.Add() >>>sheet = xl.Workbooks[1].Sheets["Sheet1"] # at this point, I manually typed into the range A1:B3 >>> sheet.Range("A1","B3").Value() ((u'AAA', 1.0), (u'BBB', 2.0), (u'CCC', 3.0)) >>>sheet.Range("A1","B3").Value[()] = [(x,y) for x,y in zip('xyz',xrange(3))] # Using a generator expression, per @Mike's comment # However, this still blanks out my range :(

    Read the article

  • Sum an Array - Objective-C

    - by Graham
    Hi Guys, I'm just starting out and I'm looking for an easy way to sum a simple array. I've read into apple developer site on key value coding and I don't understand how to apply that to my array or if that's the appropriate way to sum this. My stumbling block with the key value coding is the .keypathToProperty - I can sort of understand that you need a further reference in a 2D array but they don't show the array code, only the keypath to the title of the row so I can't figure it out yet. NSMutableArray *numArray = [NSMutableArray arrayWithCapacity:4]; [numArray addObject:num1]; [numArray addObject:num2]; [numArray addObject:num3]; [numArray addObject:num4]; I appreciate the replies! Thanks Graham

    Read the article

  • Why is System.arraycopy native in Java?

    - by James B
    I was surprised to see in the Java source that System.arraycopy is a native method. Of course the reason is because it's faster. But what native tricks is the code able to employ that make it faster? Why not just loop over the original array and copy each pointer to the new array - surely this isn't that slow and cumbersome? Thanks, -James

    Read the article

  • jQuery.Ajax makes the wrong request with array data

    - by user46503
    Hello, I have the following array: var idParam = ["1","2","3"]; I want to send this data as request using jQuery.ajax, what I'm doing: $.ajax({ type: "GET", url: "Services/GetInfo.ashx", data: { "id": idParam }, contentType: "application/text", dataType: "json", success: function(result) { ... }, error: function(XMLHttpRequest, textStatus, errorThrown) { ... } }); But as result I have the following ugly string: ?id[]=1&id[]=2&id[]=4 (actually it's much uglier:id%5B%5D=1&id%5B%5D=2&id%5B%5D=4). What to do to get the normal string like: id=1&id=2&id=4 ?? Thanks

    Read the article

  • How do I name an array key with a key inside the array

    - by Confused
    I have some data, yes, data. This data came from a MySQL query and it will always contain 4 items, always. I want to cache that data in an array table for use later within a web page but I want to keep the keys from the query and separate out each grouping within a multidimensional array. However to save time iterating through the array each time I want to find a given group of data, I want to call the keys of the first array the same as the ID key which is always the first key within each four items. At the minute I'm using this code: function mysql_fetch_full_result_array($result) { $table_result=array(); $r=0; while($row = mysql_fetch_assoc($result)){ $arr_row=array(); $c=0; while ($c < mysql_num_fields($result)) { $col = mysql_fetch_field($result, $c); $arr_row[$col -> name] = $row[$col -> name]; $c++; } $table_result[$r] = $arr_row; $r++; } return $table_result; } I'm currently testing this using 3 unique users, so I'm getting three rows back from the query and the data from this function ends up in the format: [0]=> . . [id] => 1 . . [name] => random name . . [tel] => random tel . . [post] => post code data [1]=> . . [id] => 34 . . [name] => random name . . [tel] => random tel . . [post] => post code data [2]=> . . [id] => 56 . . [name] => random name . . [tel] => random tel . . [post] => post code data So how do I alter the code to instead of the keys [0], [1], [2] give me the output: [1]=> . . [id] => 1 . . [name] => random name . . [tel] => random tel . . [post] => post code data [34]=> . . [id] => 34 . . [name] => random name . . [tel] => random tel . . [post] => post code data [56]=> . . [id] => 56 . . [name] => random name . . [tel] => random tel . . [post] => post code data I don't mind if the main array keys are strings of numbers rather than numbers but I'm a bit stuck, I tried changing the $table_result[$r] = $arr_row; part to read $table_result[$result['id']] = $arr_row; but that just outputs an array of one person. I know I need another loop but I'm struggling to work out how to write it.

    Read the article

  • Number of different elements in an array.

    - by AB
    Is it possible to compute the number of different elements in an array in linear time and constant space? Let us say it's an array of long integers, and you can not allocate an array of length sizeof(long). P.S. Not homework, just curious. I've got a book that sort of implies that it is possible.

    Read the article

  • Why "Not an ARRAY reference" error?

    - by Sandra Schlichting
    I have this script #!/usr/bin/perl use strict; use warnings; use yy; my $data = [ ["aax", "ert", "ddd"], ["asx", "eer", "kkk"], ["xkk", "fff", "lll"], ["xxj", "vtt", "lle"], ]; use Test::More tests => 4; is(yy::type1_to_type2(\$data, 'aax'), 'ert'); is(yy::type1_to_type3(\$data, 'asx'), 'kkk'); is(yy::type2_to_type3(\$data, 'fff'), 'lll'); is(yy::type3_to_type1(\$data, 'lle'), 'xxj'); which uses this module package yy; sub typeX_to_typeY { my ($x, $y, $data, $str) = @_; foreach (@$data) { if ($_->[$x - 1] eq $str) { return $_->[$y - 1]; } } return; } sub type1_to_type2 { typeX_to_typeY(1, 2, @_) } sub type1_to_type3 { typeX_to_typeY(1, 3, @_) } sub type2_to_type1 { typeX_to_typeY(2, 1, @_) } sub type2_to_type3 { typeX_to_typeY(2, 3, @_) } sub type3_to_type1 { typeX_to_typeY(3, 1, @_) } sub type3_to_type2 { typeX_to_typeY(3, 2, @_) } 1; and gives this error Not an ARRAY reference at yy.pm line 6. # Looks like your test died before it could output anything. The line it complains about is foreach (@$data) { Isn't this the way to pass an array reference? What am I doing wrong?

    Read the article

  • Perl throws an error message about syntax

    - by Ben Dauphinee
    So, building off a question about string matching (this thread), I am working on implementing that info in solution 3 into a working solution to the problem I am working on. However, I am getting errors, specifically about this line of the below function: next if @$args->{search_in} !~ /@$cur[1]/; syntax error at ./db_index.pl line 16, near "next " My question as a perl newbie is what am I doing wrong here? sub search_for_key { my ($args) = @_; foreach $row(@{$args->{search_ary}}){ print "@$row[0] : @$row[1]\n"; } my $thiskey = NULL; foreach $cur (@{$args->{search_ary}}){ print "\n" . @$cur[1] . "\n" next if @$args->{search_in} !~ /@$cur[1]/; $thiskey = @$cur[0]; last; } return $thiskey; }

    Read the article

  • PHP: Next Available Value in an Array, starting with a non-indexed value

    - by Erik Smith
    I've been stumped on this PHP issue for about a day now. Basically, we have an array of hours formatted in 24-hour format, and an arbitrary value ($hour) (also a 24-hour). The problem is, we need to take $hour, and get the next available value in the array, starting with the value that immediately proceeds $hour. The array might look something like: $goodHours = array('8,9,10,11,12,19,20,21). Then the hour value might be: $hour = 14; So, we need some way to know that 19 is the next best time. Additionally, we might also need to get the second, third, or fourth (etc) available value. The issue seems to be that because 14 isn't a value in the array, there is not index to reference that would let us increment to the next value. To make things simpler, I've taken $goodHours and repeated the values several times just so I don't have to deal with going back to the start (maybe not the best way to do it, but a quick fix). I have a feeling this is something simple I'm missing, but I would be so appreciative if anyone could shed some light. Erik

    Read the article

  • Create and populate two-dimensional array in Scala

    - by ~asteinlein
    What's the recommended way of creating a pre-populated two-dimensional array in Scala? I've got the following code: val map = for { x <- (1 to size).toList } yield for { y <- (1 to size).toList } yield (x, y) How do I make an array instead of list? Replacing .toList with .toArray doesn't compile. And is there a more concise or readable way of doing this than the nested for expressions?

    Read the article

  • C array assignment and indexing with similar variable.

    - by Todd R.
    Hello! I apologize if this has been posted before. Compiling under two separate compilers, BCC 5.5 and LCC, yields 0 and 1. #include <stdio.h> int main(void) { int i = 0, array[2] = {0, 0}; array[i] = ++i; printf("%d\n", array[1]); } Am I to assume not all compilers evaluate expressions within an array from right to left?

    Read the article

  • PHP: Filling in the 'gaps' in an array

    - by aboved
    Hey gurus, I've got a php array (obtained through checkbox values in a form - as you know checkboxes only show up in the _POST variable when they are not set). Array ( [2] => 0,2 [3] => 0,3 ) I need a way to 'fill in' the gaps between the range 0-5. So above would look like (filling the empty spaces with '-1'. I tried array_merge() with an array filled with '-1' but that didn't work. Array ( [0] => -1 [2] => 0,2 [3] => 0,3 [4] => -1 [5] => -1 ) I think I may have gone down the wrong road with the problem I am trying to solve, but I have put too much time into this solution to back out - a feeling I am sure most of you are familiar with(!) Cheers!

    Read the article

  • resizing an array with C

    - by Gary
    So I need to have an array of structs in a game I'm making - but I don't want to limit the array to a fixed size. I'm told there is a way to use realloc to make the array bigger when it needs to, but can't find any working examples of this. Could someone please show me how to do this? Thanks!

    Read the article

  • Formula needed: Sort Array

    - by aw
    I have the following array: a = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16] I use it for some visual stuff like this: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 Now I want to sort the array like this: 1 3 6 10 2 5 9 13 4 8 12 15 7 11 14 16 //So the original array should look like this: a = [1,5,2,9,6,3,13,10,7,4,14,11,8,15,12,16] Yeah, now I'm looking for a smart formula to do that ticker = 0; originalArray = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16] newArray = []; while(ticker < originalArray.length) { //do the magic here ticker++; }

    Read the article

  • PHP: Condense array of similar strings into one merged array

    - by Matt Andrews
    Hi everyone. Working with an array of dates (opening times for a business). I want to condense them to their briefest possible form. So far, I started out with this structure Array ( [Mon] => 12noon-2:45pm, 5:30pm-10:30pm [Tue] => 12noon-2:45pm, 5:30pm-10:30pm [Wed] => 12noon-2:45pm, 5:30pm-10:30pm [Thu] => 12noon-2:45pm, 5:30pm-10:30pm [Fri] => 12noon-2:45pm, 5:30pm-10:30pm [Sat] => 12noon-11pm [Sun] => 12noon-9:30pm ) What I want to achieve is this: Array ( [Mon-Fri] => 12noon-2:45pm, 5:30pm-10:30pm [Sat] => 12noon-11pm [Sun] => 12noon-9:30pm ) I've tried writing a recursive function and have managed to output this so far: Array ( [Mon-Fri] => 12noon-2:45pm, 5:30pm-10:30pm [Tue-Fri] => 12noon-2:45pm, 5:30pm-10:30pm [Wed-Fri] => 12noon-2:45pm, 5:30pm-10:30pm [Thu-Fri] => 12noon-2:45pm, 5:30pm-10:30pm [Sat] => 12noon-11pm [Sun] => 12noon-9:30pm ) Can anybody see a simple way of comparing the values and combining the keys where they're similar? My recursive function is basically two nested foreach() loops - not very elegant. Thanks, Matt EDIT: Here's my code so far, which produces the 3rd array above (from the first one as input): $last_time = array('t' => '', 'd' => ''); // blank array for looping $i = 0; foreach($final_times as $day=>$time) { if($last_time['t'] != $time ) { // it's a new time if($i != 0) { $print_times[] = $day . ' ' . $time; } // only print if it's not the first, otherwise we get two mondays } else { // this day has the same time as last time $end_day = $day; foreach($final_times as $day2=>$time2) { if($time == $time2) { $end_day = $day2; } } $print_times[] = $last_time['d'] . '-' . $end_day . ' ' . $time; } $last_time = array('t' => $time, 'd' => $day); $i++; }

    Read the article

< Previous Page | 39 40 41 42 43 44 45 46 47 48 49 50  | Next Page >