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  • Sort Order With End Year and Start Year

    - by Maletor
    I'm looking to write a comparator to sort my items in a list. For items without an end year they should be at the top. For items with an end year they should be next. For items with the same end year the one with the lowest start year should be next. Something I have so far [item.get('end_year'), item.get('start_year')] Test sceanrios first is end year second is start year ("" is present) "", "" "", 2012 "", 2011 2012, 2005 2012, 2008 2011, 2011 2010, 2005

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  • best book to start XML and Html5?

    - by asad26
    hey every one can some one help that , how can start XML and Html and what i have to start first and what steps should I take , and because I know Objective c as iphone programmer but i what to know more about web base application so please some one help me with steps should I take and as beginner? thanks

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  • Start Windows GUI Application Development With C++

    - by Chris
    I'm looking into creating a GUI program for Windows in C++, I have a good knowledge of C++ in the command line and also in game creation. But I'm not sure where to start with GUI application development. I have Visual Studio 2010 and have created new projects with a GUI but these templates are complex and leaves me not understanding whats happening and how to modify it. So I'm asking where do I start? Preferably good websites that you can recommend or tutorials, rather than books being a poor student :)

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  • start service under logged on user account by changing token

    - by sam
    hi all,i have a desktop application that install and start a service,i know a process can get the explorer.exe token and lunch another process with the tkoen,it means the second process will run us logged on account, my question is this that can i start my service by explorer.exe token too ? is there is an example in delphi? thx for ur time

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  • Process.Start to run exe in same folder as application is

    - by Hallgaws
    When I am running myProcess = Process.Start("something.exe") and want to start it using button it doen not find the file - i need to execute it from the same folder where application is how can i do that? Thank you. System could not find this file - but it is there . in the same folder as application. Using Visual Basic 2008 Express

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  • Start a list from a certain number

    - by Colin
    What's the best way to get a ul to start from 'x'? The start tag is depricated and everything I have found on Google has used the :before pseudo class which doesn't work in IE6 or 7. Didn't have much luck when searching stack either. Only thing I can think of is manually go through and number the lists myself and style accordingly? Any help appreciated.

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  • C# code to start selenium-server on remote machine

    - by Naresh Thandu
    As part of my test automation, I have to start Selenium Server on my server. As of now I am manually executing a batch file to start selenium server on m,y machine. Batch file contains the following command. java -jar selenium-server-standalone-2.16.1.jar -role hub http://server.com:5555/grid/register But as I required it for my test automation, I want to automate running the selenium server on a remote server from my C# code. How do I do this?

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  • rails foreman does not load all my services on start

    - by Rubytastic
    Rails foreman does not load all my services defined in Procfile. Procfile.rb: redis: redis-server resque: bundle exec rake resque:start &&> log/resque_worker_queue.log privpub: bundle exec rackup private_pub.ru -s thin -E production & &> log/private_pub.log sunspot: bundle exec rake sunspot:solr:run I always have to manually start all of them by copy paste the commands in terminal foreman start does not work, what am i missing? This is foreman output: 12:35:40 privpub.1 | process terminated 12:35:40 system | sending SIGTERM to all processes 12:35:40 system | sending SIGTERM to pid 4375 12:35:40 redis.1 | [4375] 02 Jun 12:35:40 # Received SIGTERM, scheduling shutdown... 12:35:40 redis.1 | [4375] 02 Jun 12:35:40 # User requested shutdown... 12:35:40 redis.1 | [4375] 02 Jun 12:35:40 * Saving the final RDB snapshot before exiting. 12:35:40 redis.1 | [4375] 02 Jun 12:35:40 * DB saved on disk 12:35:40 redis.1 | [4375] 02 Jun 12:35:40 # Redis is now ready to exit, bye bye... 12:35:40 system | sending SIGTERM to pid 4376 12:35:40 resque.1 | rake aborted! 12:35:40 resque.1 | SIGTERM 12:35:40 resque.1 | 12:35:40 resque.1 | (See full trace by running task with --trace) 12:35:40 system | sending SIGTERM to pid 4378 12:35:40 sunspot.1 | rake aborted! 12:35:40 sunspot.1 | SIGTERM 12:35:40 sunspot.1 | 12:35:40 sunspot.1 | (See full trace by running task with --trace) 12:35:40 sunspot.1 | process terminated 12:35:40 resque.1 | process terminated 12:35:40 redis.1 | process terminated

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  • Illegal start of expression?

    - by Fraser
    I'm trying to build a simple Android app that increments a number displayed every time a button is pressed, but I can't work out how to fix the "illegal start of expression" error I keep getting. My code: package com.clicker; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.TextView; public class Clicker extends Activity { private int clickerNumber = 0; private TextView clickerText; private Button clickerButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); clickerText = (TextView)findViewById(R.id.clickerText); final Button clickerButton = (Button)findViewById(R.id.clickerButton); clickerButton.setOnClickListener(new View.OnClickListener()); { public void onClick(); { clickerNumber = clickerNumber++; clickerText.setText(Integer.toString(clickerNumber)); } } } } And compiler output: compile: [javac] Compiling 2 source files to /home/fraser/Applications/Android/Code/Clicker/bin/classes [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:24: ')' expected [javac] clickerButton.setOnClickListener(new View.OnClickListener(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: ';' expected [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:29: ';' expected [javac] clickerText.setText(Integer.toString(clickerNumber))); [javac] ^ [javac] 5 errors

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  • Which CEP product to start with?

    - by Andreas
    Hi, I want to learn more on how to build CEP based applications. So I looked around and found several products (overview found here: http://rulecore.com/CEPblog/?page_id=47). But as there are quite a few at the moment, I don't know which is the best to start with. And overall I just would consider the one available for free. The rest is a bit to expensive for just private use ;) Esper is for free, but without Esper studio it seems quite tedious to develop a cep app. Streambase offers a free trial, but I couldn't find out how long you can use this (if only for a month, no that helpful for longer research). Oracle CEP suite seems quite complete, but in the cep scene - as far as I can see - it is the least recognized compared to Esper or Streambase. So do you have any hints on what is the best way to start with cep development? Is it worth to spent time on working through the oracle documenation or is it better to start with Esper or Streambase? Cheers, Andreas

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  • How to handle ASP.NET application error that occurs on application start and transfer & display erro

    - by Soul_Master
    I know that ASP.NET MVC has error filter attribute to handle specified error type. However, this feature cannot catch any error that occurs when application start. Therefore, I need to add some code to “Application_Error” method for handling this error like the following code. public void Application_Error(object sender, EventArgs e) { // At this point we have information about the error var ctx = HttpContext.Current; var exception = ctx.Server.GetLastError(); var errorInfo = "<br>Offending URL: " + ctx.Request.Url + "<br>Source: " + exception.Source + "<br>Message: " + exception.Message + "<br>Stack trace: " + exception.StackTrace; ctx.Response.Write(errorInfo); Server.ClearError(); } Although, this code will works fine, when normal application error occurs like error that occurs in view page. Nevertheless, it does not work when error occurs on application starting because request and response objects are always null. Next, I try to solve this question by setting default redirect in custom errors like the following code. <customErrors mode="On" defaultRedirect="Scripts/ApplicationError.htm"></customErrors> Unfortunately, it does not work because when application receive redirected request, it try to start application again and it throw exception again. How do to solve this problem? Alternatively, Do you have other idea for handling this error. Thanks, PS. The main reason for creating this handler because I want to display error when application cannot connect to other service like database for caching data on application start.

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  • python can't start a new thread

    - by Giorgos Komnino
    I am building a multi threading application. I have setup a threadPool. [ A Queue of size N and N Workers that get data from the queue] When all tasks are done I use tasks.join() where tasks is the queue . The application seems to run smoothly until suddently at some point (after 20 minutes in example) it terminates with the error thread.error: can't start new thread Any ideas? Edit: The threads are daemon Threads and the code is like: while True: t0 = time.time() keyword_statuses = DBSession.query(KeywordStatus).filter(KeywordStatus.status==0).options(joinedload(KeywordStatus.keyword)).with_lockmode("update").limit(100) if keyword_statuses.count() == 0: DBSession.commit() break for kw_status in keyword_statuses: kw_status.status = 1 DBSession.commit() t0 = time.time() w = SWorker(threads_no=32, network_server='http://192.168.1.242:8180/', keywords=keyword_statuses, cities=cities, saver=MySqlRawSave(DBSession), loglevel='debug') w.work() print 'finished' When the daemon threads are killed? When the application finishes or when the work() finishes? Look at the thread pool and the worker (it's from a recipe ) from Queue import Queue from threading import Thread, Event, current_thread import time event = Event() class Worker(Thread): """Thread executing tasks from a given tasks queue""" def __init__(self, tasks): Thread.__init__(self) self.tasks = tasks self.daemon = True self.start() def run(self): '''Start processing tasks from the queue''' while True: event.wait() #time.sleep(0.1) try: func, args, callback = self.tasks.get() except Exception, e: print str(e) return else: if callback is None: func(args) else: callback(func(args)) self.tasks.task_done() class ThreadPool: """Pool of threads consuming tasks from a queue""" def __init__(self, num_threads): self.tasks = Queue(num_threads) for _ in range(num_threads): Worker(self.tasks) def add_task(self, func, args=None, callback=None): ''''Add a task to the queue''' self.tasks.put((func, args, callback)) def wait_completion(self): '''Wait for completion of all the tasks in the queue''' self.tasks.join() def broadcast_block_event(self): '''blocks running threads''' event.clear() def broadcast_unblock_event(self): '''unblocks running threads''' event.set() def get_event(self): '''returns the event object''' return event

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  • Time to start a counter on client-side.

    - by Felipe
    Hi everybody, I'm developing an web application using asp.net mvc, and i need to do a stopwatch (chronometer) (with 30 seconds preprogrammed to start in a certain moment) on client-side using the time of the server, by the way, the client's clock can't be as the server's clock. So, i'm using Jquery to call the server by JSon and get the time, but it's very stress because each one second I call the server to get time, something like this: $(function() { GetTimeByServer(); }); function GetTimeByServer() { $.getJSon('/Home/Time', null, function(result) { if (result.SecondsPending < 30) { // call another function to start an chronometer } else { window.SetTimeout(GetTimeByServer, 1000); //call again each 1 second! } }); } It works fine, but when I have more than 3 or 4 call like this, the browser slowly but works! I'd like to know, how improve more performace in client side, or if is there any way to do this... is there any way to client listen the server like a "socket" to know if the chronometer should start... PS: Sorry for my english! thanks Cheers

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  • Where to start when doing a Domain Model?

    - by devoured elysium
    Let's say I've made a list of concepts I'll use to draw my Domain Model. Furthermore, I have a couple of Use Cases from which I did a couple of System Sequence Diagrams. When drawing the Domain Model, I never know where to start from: Designing the model as I believe the system to be. This is, if I am modelling a the human body, I start by adding the class concepts of Heart, Brain, Bowels, Stomach, Eyes, Head, etc. Start by designing what the Use Cases need to get done. This is, if I have a Use Case which is about making the human body swallow something, I'd first draw the class concepts for Mouth, Throat, Stomatch, Bowels, etc. The order in which I do things is irrelevant? I'd say probably it'd be best to try to design from the Use Case concepts, as they are generally what you want to work with, not other kind of concepts that although help describe the whole system well, much of the time might not even be needed for the current project. Is there any other approach that I am not taking in consideration here? How do you usually approach this? Thanks

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  • how to delete multiple folders,desktop and start menu shortcut using vbscript

    - by user1756858
    I never did any vbscript before, so i don't know if my question is very easy one. Following is the flow of steps that has to be done : Check if exist and delete a folder at c:\test1 if found and continue. If not found continue. Check if exist and delete a folder at c:\programfiles\test2 if found and continue. If not found continue. Check if a desktop shortcut and start menu shortcut exist and delete if found. If not exit. I could delete 2 folders with the following code: strPath1 = "C:\test1" strPath1 = "C:\test1" DeleteFolder strPath1 DeleteFolder strPath1 Function DeleteFolder(strFolderPath1) Dim objFSO, objFolder Set objFSO = CreateObject ("Scripting.FileSystemObject") If objFSO.FolderExists(strFolderPath) Then objFSO.DeleteFolder strFolderPath, True End If Set objFSO = Nothing But i need to run one script to delete 2 folders in different paths, 2 shortcuts one in start menu and one on desktop. I was experimenting with this code to delete the shortcut on my desktop: Dim WSHShell, DesktopPath Set WSHShell = WScript.CreateObject("WScript.Shell") DesktopPath = WSHShell.SpecialFolders("Desktop") on error resume next Icon = DesktopPath & "\sample.txt" Set fs = CreateObject("Scripting.FileSystemObject") Set A = fs.GetFile(Icon) A.Delete WScript.Quit It works fine for txt file on desktop, but how do i delete a shortcut for an application from desktop as well as start menu.

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  • CreateProcessWithLogonW : unable to start process

    - by Vivek
    Hi I am completely new to programming. And please someone help me. I am trying to start a pocess from a service. I need to start the new process by prompting user to enter admin credentials. I was trying to use CreateProcessWithLogonW(). Am I using the right function. I tried to give input username, password, domain as localhost. I gave full pathe to the .exe file that i need to start. Here is the piece of code. CreateProcessWithLogonW(L"Administrator", L"localhost", L"password", 0, NULL, L"c:\myupdates\myapp.exe", NORMAL_PRIORITY_CLASS | CREATE_CONSOLE, NULL, NULL, &si, &pi); Si.cb = sizeof(si); Si.lpDesktop = L"winsta0\\default"; But the process never started. Can you guys tell me what I am doing wrong. And what do I need to do to promt user to enter credentials of administrator instead of hardcoding it.

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  • Sharepoint 2010 start workflow programmatically error

    - by user522429
    I have a workflow associated with a content type. I try to kick it off from code from within the event receiver on the same content type, so when an item is updated, if there is a certain condition (status = ready for review) I start it. //This line does find the workflow association var assoc = properties.Web.ContentTypes["Experiment Document Set"].WorkflowAssociations.GetAssociationByName("Experiment Review Workflow", ultureInfo.CurrentUICulture); //I had tried to use this line from something I found online, but it would return null //var assoc = properties.Web.WorkflowAssociations.GetAssociationByName("Experiment Review Workflow", CultureInfo.CurrentUICulture); var result = properties.Web.Site.WorkflowManager.StartWorkflow(properties.ListItem, assoc, string.Empty, SPWorkflowRunOptions.Synchronous); //The line above gives me this error: System.ArgumentException: Workflow failed to start because the workflow is associated with a content type that does not exist in a list. Before re-starting the workflow, the content type must be added to the list. To check this, I was looking at the content type of the list item being updated and it is correct properties.ListItem.ContentType.Name "Experiment Document Set" So basically I have a workfow associated with the content type "Experiment Document Set". When I try to start a workflow from an event receiver in "Experiment Document Set", I get an error saying the content type "Experiment Document Set" does not exist in the list which doesn't make sense.

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  • Error when trying to start Apache after installing SSL cert

    - by chris
    I am trying to install an SSL certificate, and I get the following errors: AH02241: Init: Unable to read server certificate from file /path/my.crt SSL Library Error: error:0D0680A8:asn1 encoding routines:ASN1_CHECK_TLEN:wrong tag SSL Library Error: error:0D07803A:asn1 encoding routines:ASN1_ITEM_EX_D2I:nested asn1 error (Type=X509) AH02312: Fatal error initialising mod_ssl, exiting. Here's the process I followed: I generated my private key with: openssl genrsa -out my.key 2048 I created the CSR with: openssl req -new -key my.key -out my.csr I provided the CSR to our IT department, and they returned a crt - it starts with -----BEGIN CERTIFICATE----- My ssl.conf has (my.example.com matches the Common name used during the generation of the CSR): <VirtualHost my.example.com:443> SSLEngine On ServerName my.example.com SSLCertificateFile /path/my.crt SSLCertificateKeyFile /path/my.key </VirtualHost> I do not have SSLCertificateChainFile or SSLCACertificate file set. The private key starts with ----BEGIN RSA PRIVATE KEY----- The csr starts with -----BEGIN CERTIFICATE REQUEST----- I have verified that both: openssl rsa -noout -modulus -in my.key openssl req -noout -modulus -in my.csr produce the same output. I cannot figure out how to verify the crt - trying both x509 and rsa produce an error. Should this process have worked? Can I verify that my.crt matches the key somehow?

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  • MySQL won't start or won't installed

    - by Owen
    Hi there, I'm trying to get a local LAMP setup on my Ubuntu desktop. I'm successfully got PHP install but I'm having trouble with MySQL If PHP tries to connet to MySQL I get this error: Warning: mysql_connect() [function.mysql-connect]: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) in /var/www/testing.php on line 3 Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) If I try via command line I get much the same error: owen@desktop:~$ mysql ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (13) Weirdly "/var/run/mysqld" does not exist. Running a whereis command I get the following: owen@desktop:~$ whereis mysqld.sock mysqld: /usr/sbin/mysqld /usr/share/man/man8/mysqld.8.gz So is MySQL even installed? Well acording to dpkg owen@desktop:~$ dpkg -l | grep mysql ii libapache2-mod-auth-mysql 4.3.9-13ubuntu1 Apache 2 module for MySQL authentication ii libdbd-mysql-perl 4.016-1 Perl5 database interface to the MySQL database ii libmysqlclient15off 5.1.30really5.0.83-0ubuntu3 MySQL database client library ii libmysqlclient16 5.1.49-1ubuntu8.1 MySQL database client library ii mysql-admin 5.0r14+openSUSE-2.1 GUI tool for intuitive MySQL administration ii mysql-client-5.1 5.1.49-1ubuntu8.1 MySQL database client binaries ii mysql-client-core-5.1 5.1.49-1ubuntu8.1 MySQL database core client binaries ii mysql-common 5.1.49-1ubuntu8.1 MySQL database common files, e.g. /etc/mysql/my.cnf ii mysql-gui-tools-common 5.0r14+openSUSE-2.1 Architecture independent files for MySQL GUI Tools ii mysql-query-browser 5.0r14+openSUSE-2.1 Official GUI tool to query MySQL database ii mysql-server 5.1.49-1ubuntu8.1 MySQL database server (metapackage depending on the latest version) ii mysql-server-5.1 5.1.49-1ubuntu8.1 MySQL database server binaries and system database setup ii mysql-server-core-5.0 5.1.30really5.0.83-0ubuntu3 MySQL database core server files ii mysql-server-core-5.1 5.1.49-1ubuntu8.1 MySQL database server binaries ii php5-mysql Can someone please help I'm really confused as what to do next. I'm not a Linux expert at all most of these commands I've ran I found of diffrent blogs and help forums.

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  • Apache won't stop starting

    - by Rob
    /usr/local/apache/bin/httpd -k start -DSSL nobody 6906 0.0 0.1 187032 5448 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6907 0.0 0.1 187032 5448 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6908 0.0 0.1 187032 5448 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6909 0.0 0.1 187032 5448 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6910 0.7 0.1 187712 7024 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6911 1.7 0.1 188216 7036 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6912 0.5 0.1 187712 7020 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6913 0.4 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6914 0.8 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6915 0.7 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6916 0.5 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6917 0.2 0.1 188216 7024 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6918 0.5 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6919 0.8 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6920 0.5 0.1 187712 7020 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6921 0.8 0.1 187712 7020 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6922 1.0 0.1 188216 7024 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6923 0.6 0.1 188216 7024 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6924 1.5 0.1 187712 7020 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6925 0.1 0.1 187712 7012 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6926 1.2 0.1 187712 7016 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6927 0.5 0.1 188216 7028 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL nobody 6928 1.2 0.1 187712 7024 ? S 13:20 0:00 /usr/local/apache/bin/httpd -k start -DSSL I have 258 of these running. I stopped httpd, and it went back down to 0. I started it back up, and it quickly went back to 258. I have never seen this before. Anyone know what's wrong? I'm running CentOS5.5 with Apache2.2 on cPanel.

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  • SQL 2008 Database tuning advisor won’t start

    - by Andrew Hancox
    For some reason I can't get DTA to connect to my development machine. It connects to a remote DB just fine but when I point it to my dev machine I get an error saying: Failed to initialize MSDB database for tuning (exit code: -1073741819). I'm pretty sure it's not a permissions issue since I've used profiler to capture what it's doing and all of the commands it's run so far look fine and are being run under my account which is associated with the sysadmin role, when I run them in sql management studio they go through fine. I'm pretty convinced that the problem is related to creating the objects in MSDB that are used by DTA but I tried creating these manually (I found scripts on the web) and it just seems to push the problem along the line slightly. I'm going out of my mind - have even tried reinstalling SQL but that's not fixed it. I'm using SQL 2008 with SP1 (10.0.2531) on windows server 2008 (patched up to date). SAVE ME!!!!!

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  • Launching firefox on remote server causes local firefox to start instead

    - by terdon
    Right, this is strange. I am connecting from my laptop (LMDE) to a remote host (SUSE linux enterprise) using ssh -X. I want to launch a firefox instance running on the remote server so I can have access to webpages on a private network. User@RemoteMachine $ which -a firefox /usr/bin/firefox User@RemoteMachine $ /usr/bin/firefox --version Mozilla Firefox 2.0.0.2, Copyright (c) 1998 - 2007 mozilla.org User@LocalMachine $ which -a firefox /usr/bin/firefox User@LocalMachine $ /usr/bin/firefox --version Mozilla Firefox 14.0.1 Now, if firefox is not running on the local machine, everything goes as expected and executing firefox on the remote machine causes a firefox (v 2.0) window running on the remote machine to show up. However, if firefox is running on the local machine a second window of firefox 14.0.1 running on the local machine appears. I have checked top in both machines. In the 2nd case, a firefox process briefely appears on the remote machine and then disappears when the local version of firefox is launched. My questions are the following: What gives? How/why can firefox connect to its existing instance on the local machine? The remote machine appears to have access to the local machine. It, in fact, appears to have the right to execute programs on my local machine. Am I missing something or is this just weird? Is this not a security risk?

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