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  • Type-aware rendering (and editing) of tabular data in pyqt4

    - by pihentagy
    I would like to have a very short / minimal example of how to create some tabular widget with different types of item in it. In the first round let's say I'd like to render [["Hello", 12, True], ["World", 13, False]] (Hello as string, 12 as number (right-align), True as a checkbox for eg.), but it would be nice to have Dates, Colors, and other type of info. Next round: editing (integer with spinbox, maybe sometimes a combobox is handy, but that may not work out of the box). There must be a simple solution, but I couldn't find...

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  • How to insert several thousand columns into sqlite3?

    - by user291071
    Similar to my last question, but I ran into problem lets say I have a simple dictionary like below but its Big, when I try inserting a big dictionary using the methods below I get operational error for the c.execute(schema) for too many columns so what should be my alternate method to populate an sql databases columns? Using the alter table command and add each one individually? import sqlite3 con = sqlite3.connect('simple.db') c = con.cursor() dic = { 'x1':{'y1':1.0,'y2':0.0}, 'x2':{'y1':0.0,'y2':2.0,'joe bla':1.5}, 'x3':{'y2':2.0,'y3 45 etc':1.5} } # 1. Find the unique column names. columns = set() for _, cols in dic.items(): for key, _ in cols.items(): columns.add(key) # 2. Create the schema. col_defs = [ # Start with the column for our key name '"row_name" VARCHAR(2) NOT NULL PRIMARY KEY' ] for column in columns: col_defs.append('"%s" REAL NULL' % column) schema = "CREATE TABLE simple (%s);" % ",".join(col_defs) c.execute(schema) # 3. Loop through each row for row_name, cols in dic.items(): # Compile the data we have for this row. col_names = cols.keys() col_values = [str(val) for val in cols.values()] # Insert it. sql = 'INSERT INTO simple ("row_name", "%s") VALUES ("%s", "%s");' % ( '","'.join(col_names), row_name, '","'.join(col_values) )

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  • how to print the linenumber of incorrectwords located in a txt file ?

    - by jad
    i have this piece of code which only prints the line number of the incorrect words. i want it to print the linenumbers of the incorrect words from the txt file. Am i able to modify this code to do that? # text1 is my incorrect words # words is my text file where my incorrect word are in from collections import defaultdict d = defaultdict(list) for lineno, word in enumerate(text1): d[word].append(lineno) print(d)

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  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

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  • Element not found blocks execution in Selenium

    - by Mariano
    In my test, I try to verify if certain text exists (after an action) using find_element_by_xpath. If I use the right expression and my test pass, the routine ends correctly in no time. However if I try a wrong text (meaning that the test will fail) it hangs forever and I have to kill the script otherwise it does not end. Here is my test (the expression Thx user, client or password you entered is incorrect does not exist in the system, no matter what the user does): # -*- coding: utf-8 -*- import gettext import unittest from selenium import webdriver class TestWrongLogin(unittest.TestCase): def setUp(self): self.driver = webdriver.Firefox() self.driver.get("http://10.23.1.104:8888/") # let's check the language try: self.lang = self.driver.execute_script("return navigator.language;") self.lang = self.lang("-")[0] except: self.lang = "en" language = gettext.translation('app', '/app/locale', [self.lang], fallback=True) language.install() self._ = gettext.gettext def tearDown(self): self.driver.quit() def test_wrong_client(self): # test wrong client inputElement = self.driver.find_element_by_name("login") inputElement.send_keys("root") inputElement = self.driver.find_element_by_name("client") inputElement.send_keys("Unleash") inputElement = self.driver.find_element_by_name("password") inputElement.send_keys("qwerty") self.driver.find_element_by_name("form.submitted").click() # wait for the db answer self.driver.implicitly_wait(10) ret = self.driver.find_element_by_xpath( "//*[contains(.,'{0}')]".\ format(self._(u"Thx user, client or password you entered is incorrect"))) self.assertTrue(isinstance(ret, webdriver.remote.webelement.WebElement)) if __name__ == '__main__': unittest.main() Why does it do that and how can I prevent it?

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  • Setting opacity on a PyGTK label

    - by snostorm
    Is there a way to make a PyGTK widget partly transparent, so that the widgets behind it can be seen through it? Specifically I'm trying to do this on a label, for typographic effect; I don't want to change the color instead, as it may not look right on all themes.

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  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

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  • How do I do a semijoin using SQLAlchemy?

    - by Jason Baker
    http://en.wikipedia.org/wiki/Relational_algebra#Semijoin Let's say that I have two tables: A and B. I want to make a query that would work similarly to the following SQL statement using the SQLAlchemy orm: SELECT A.* FROM A, B WHERE A.id = B.id AND B.type = 'some type'; The thing is that I'm trying to separate out A and B's logic into different places. So I'd like to make two queries that I can define in separate places: one where A uses B as a subquery, but only returns rows from A. I'm sure this is fairly easy to do, but an example would be nice if someone could show me.

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  • Query distinct list of choices for Django form with App Engine Datastore

    - by Brian
    I've been trying to figure this out for hours across a couple of days, and can not get it to work. I've been everywhere. I'll continue trying to figure it out, but was hoping for a quicker solution. I'm using App Engine datastore + Django. Using a query in a view and custom forms, I was able to get a list to the form but then I was not able to post. I have been trying to figure out how to dynamically add the choices as part of the Django form... I've tried various ways with no success. Help! Below are the two models. I'd like to get a distinct list of address_id to show in the location field in InfoForm. This fields could (and maybe should) be named the same, but I thought it'd be easier if they were named different. class Info(db.Model): user = db.UserProperty() location = db.StringProperty() info = db.StringProperty() created = db.DateTimeProperty(auto_now_add=True) modified = db.DateTimeProperty(auto_now=True) class Locations(db.Model): user = db.UserProperty() address_id = db.StringProperty() address = db.StringProperty() class InfoForm(djangoforms.ModelForm): info = forms.ChoiceField(choices=INFO_CHOICES) location = forms.ChoiceField() class Meta: model = Info exclude = ['user','created','modified']

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  • Suffix if statement

    - by Aardschok
    I was looking for a way to add a suffix to jointchain in Maya. The jointchain has specific naming so I create a list with the names they need to be. The first chain has "_1" as suffix, result: R_Clavicle_1|R_UpperArm_1|R_UnderArm_1|R_Wrist_1 When I create the second this is the result: R_Clavicle_2|R_UpperArm_1|R_UnderArm_1|R_Wrist_1 The code: DRClavPos = cmds.xform ('DRClavicle', q=True, ws=True, t=True) DRUpArmPos = cmds.xform ('DRUpperArm', q=True, ws=True, t=True) DRUnArmPos = cmds.xform ('DRUnderArm', q=True, ws=True, t=True) DRWristPos = cmds.xform ('DRWrist', q=True, ws=True, t=True), cmds.xform('DRWrist', q=True, os=True, ro=True) suffix = 1 jntsA = cmds.ls(type="joint", long=True) while True: jntname = ["R_Clavicle_"+str(suffix),"R_UpperArm_"+str(suffix),"R_UnderArm_"+str(suffix),"R_Wrist_"+str(suffix)] if jntname not in jntsA: cmds.select (d=True) cmds.joint ( p=(DRClavPos)) cmds.joint ( p=(DRUpArmPos)) cmds.joint ( 'joint1', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[0]) cmds.joint ( p=(DRUnArmPos)) cmds.joint ( 'joint2', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[1]) cmds.joint ( p=(DRWristPos[0])) cmds.joint ( 'joint3', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[2]) cmds.rename ('joint4', jntname[3]) cmds.select ( cl=True) break else: suffix + 1 I tried adding +1 in jntname which resulted in a good second chain but the third chain had "_2" after R_Clavicle_3 The code, in my eyes should work. Can anybody point me in the correct direction :)

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  • Flask Admin didn't show all fields

    - by twoface88
    I have model like this: class User(db.Model): __tablename__ = 'users' __table_args__ = {'mysql_engine' : 'InnoDB', 'mysql_charset' : 'utf8'} id = db.Column(db.Integer, primary_key=True) username = db.Column(db.String(80), unique=True) email = db.Column(db.String(120), unique=True) _password = db.Column('password', db.String(80)) def __init__(self, username = None, email = None, password = None): self.username = username self.email = email self._set_password(password) def _set_password(self, password): self._password = generate_password_hash(password) def _get_password(self): return self._password def check_password(self, password): return check_password_hash(self._password, password) password = db.synonym("_password", descriptor=property(_get_password, _set_password)) def __repr__(self): return '<User %r>' % self.username I have ModelView: class UserAdmin(sqlamodel.ModelView): searchable_columns = ('username', 'email') excluded_list_columns = ['password'] list_columns = ('username', 'email') form_columns = ('username', 'email', 'password') But no matter what i do, flask admin didn't show password field when i'm editing user info. Is there any way ? Even just to edit hash code. UPDATE: https://github.com/mrjoes/flask-admin/issues/78

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  • Many-to-many relationship on same table with association object

    - by Nicholas Knight
    Related (for the no-association-object use case): http://stackoverflow.com/questions/1889251/sqlalchemy-many-to-many-relationship-on-a-single-table Building a many-to-many relationship is easy. Building a many-to-many relationship on the same table is almost as easy, as documented in the above question. Building a many-to-many relationship with an association object is also easy. What I can't seem to find is the right way to combine association objects and many-to-many relationships with the left and right sides being the same table. So, starting from the simple, naïve, and clearly wrong version that I've spent forever trying to massage into the right version: t_groups = Table('groups', metadata, Column('id', Integer, primary_key=True), ) t_group_groups = Table('group_groups', metadata, Column('parent_group_id', Integer, ForeignKey('groups.id'), primary_key=True, nullable=False), Column('child_group_id', Integer, ForeignKey('groups.id'), primary_key=True, nullable=False), Column('expires', DateTime), ) mapper(Group_To_Group, t_group_groups, properties={ 'parent_group':relationship(Group), 'child_group':relationship(Group), }) What's the right way to map this relationship?

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  • Weird callback execution order in Twisted?

    - by SlashV
    Consider the following code: from twisted.internet.defer import Deferred d1 = Deferred() d2 = Deferred() def f1(result): print 'f1', def f2(result): print 'f2', def f3(result): print 'f3', def fd(result): return d2 d1.addCallback(f1) d1.addCallback(fd) d1.addCallback(f3) #/BLOCK==== d2.addCallback(f2) d1.callback(None) #=======BLOCK/ d2.callback(None) This outputs what I would expect: f1 f2 f3 However when I swap the order of the statements in BLOCK to #/BLOCK==== d1.callback(None) d2.addCallback(f2) #=======BLOCK/ i.e. Fire d1 before adding the callback to d2, I get: f1 f3 f2 I don't see why the time of firing of the deferreds should influence the callback execution order. Is this an issue with Twisted or does this make sense in some way?

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  • Replace ",**" with a linebreak using RegEx (or something else)

    - by John
    I'm getting started with RegEx and I was wondering if anyone could help me craft a statement to convert coordinates as follows: 145.00694,-37.80421,9 145.00686,-37.80382,9 145.00595,-37.8035,16 145.00586,-37.80301,16 to 145.00694,-37.80421 145.00686,-37.80382 145.00595,-37.8035 145.00586,-37.80301 (Strip off the last comma and value and turn it into a line break.) I can't figure out how to use wildcards to do something like that. Any help would be greatly appreciated! Thanks.

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  • Fast image coordinate lookup in Numpy

    - by victor
    I've got a big numpy array full of coordinates (about 400): [[102, 234], [304, 104], .... ] And a numpy 2d array my_map of size 800x800. What's the fastest way to look up the coordinates given in that array? I tried things like paletting as described in this post: http://opencvpython.blogspot.com/2012/06/fast-array-manipulation-in-numpy.html but couldn't get it to work. I was also thinking about turning each coordinate into a linear index of the map and then piping it straight into my_map like so: my_map[linearized_coords] but I couldn't get vectorize to properly translate the coordinates into a linear fashion. Any ideas?

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  • PyGTK: Radiobuttons are still displayed after removal

    - by canavanin
    Hi everyone! I am using PyGTK and the gtk.assistant. On one page I would like to display two radiobuttons in case the user selected a certain option on a previous page. The labels of the buttons - and whether the buttons are to be present at all - are to depend entirely on that earlier selection. Furthermore, if the user goes back and changes that selection, the page containing the radiobuttons is to be updated accordingly. I have got as far as having the radiobuttons displayed when necessary, and with the correct labels. The trouble is that if I go back and change the determining selection, or if I move one page further than the 'radiobutton page' and then move back, the buttons are not only not removed (in case that would have been required), their number has also doubled. To show you what I'm doing, here's part of my code (I've left out bits that do unrelated things, that's why the function name doesn't fit). The function is called when the "prepare" signal is emitted prior to construction of the 'radiobutten page'. def make_class_skills_treestore(self): print self.trained_by_default_hbox.get_children() # PRINT 1 for child in self.trained_by_default_hbox.get_children(): if type(child) == gtk.RadioButton: self.trained_by_default_hbox.remove(child) #child.destroy() # <-- removed the labels, but not the buttons print self.trained_by_default_hbox.get_children() # PRINT 2 class_skills = self.data.data['classes'][selected_class].class_skills.values() default_trained_count = (class_skills.count([True, True]) , class_skills.count([True, False])) num_default_trained_skills = default_trained_count[1] / 2 # you have to pick one of a pair --> don't # count each as trained by default for i in range(default_trained_count[0]): # those are trained by default --> no choice num_default_trained_skills +=1 selected_class = self.get_classes_key_from_class_selection() if default_trained_count[1]: for skill in self.data.data['classes'][selected_class].class_skills.keys(): if self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and not self.default_radio: self.default_radio.append(gtk.RadioButton(group=None, label=skill)) elif self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and self.default_radio: self.default_radio.append(gtk.RadioButton(group=self.default_radio[0], label=skill)) if self.default_radio: for radio in self.default_radio: self.trained_by_default_hbox.add(radio) self.trained_by_default_hbox.show_all() self.trained_by_default_hbox and self.trained_by_default_label, as well as self.default_radio stem from the above function's class. I have two print statements (PRINT 1 and PRINT 2) in there for debugging. Here's what they give me: PRINT 1: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>, <gtk.RadioButton object at 0x8fc4d4c (GtkRadioButton at 0x90e4018)>, <gtk.RadioButton object at 0x8fc4cac (GtkRadioButton at 0x90ceec0)>] PRINT 2: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>] So the buttons have indeed been removed, yet they still show up on the page. I know the code requires some refactoring, but first I'd like to get it to work at all... If someone could help me out that would be great! Thanks a lot in advance for your replies - any kind of help is highly appreciated.

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  • Transferring binary file from web server to client

    - by Yan Cheng CHEOK
    Usually, when I want to transfer a web server text file to client, here is what I did import cgi print "Content-Type: text/plain" print "Content-Disposition: attachment; filename=TEST.txt" print filename = "C:\\TEST.TXT" f = open(filename, 'r') for line in f: print line Works very fine for ANSI file. However, say, I have a binary file a.exe (This file is in web server secret path, and user shall not have direct access to that directory path). I wish to use the similar method to transfer. How I can do so? What content-type I should use? Using print seems to have corrupted content received at client side. What is the correct method?

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  • Django: automatically import MEDIA_URL in context

    - by pistacchio
    Hi, like exposed here, one can set a MEDIA_URL in settings.py (for example i'm pointing to Amazon S3) and serve the files in the view via {{ MEDIA_URL }}. Since MEDIA_URL is not automatically in the context, one have to manually add it to the context, so, for example, the following works: #views.py from django.shortcuts import render_to_response from django.template import RequestContext def test(request): return render_to_response('test.html', {}, context_instance=RequestContext(request)) This means that in each view.py file i have to add from django.template import RequestContext and in each response i have to explicitly specify context_instance=RequestContext(request). Is there a way to automatically (DRY) add MEDIA_URL to the default context? Thanks in advance.

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  • default model field attribute in Django

    - by Rosarch
    I have a Django model: @staticmethod def getdefault(): print "getdefault called" return cPickle.dumps(set()) _applies_to = models.TextField(db_index=True, default=getdefault) For some reason, getdefault() is never called, even as I construct instances of this model and save them to the database. This seems to contradict the Django documentation: Field.default The default value for the field. This can be a value or a callable object. If callable it will be called every time a new object is created. Am I doing something wrong? Update: Originally, I had this, but then I switched to the above version to debug: _applies_to = models.TextField(db_index=True, default=cPickle.dumps(set())) I'm not sure why that wouldn't work.

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