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• Approaches for cross server content sharing?

  - by Anonymity

  I've currently been tasked with finding a best solution to serving up content on our new site from another one of our other sites. Several approaches suggested to me, that I've looked into include using SharePoint's Lists Web Service to grab the list through javascript - which results in XSS and is not an option. Another suggestion was to build a server side custom web service and use SharePoint Request Forms to get the information - this is something I've only very briefly looked at. It's been suggested that I try permitting the requesting site in the HTTP headers of the serving site since I have access to both. This ultimately resulted in a semi-working solution that had major security holes. (I had to include username/password in the request to appease AD Authentication). This was done by allowing Access-Control-Allow-Origin: * The most direct approach I could think of was to simply build in the webpart in our new environment to have the authors manually update this content the same as they would on the other site. Are any one of the suggestions here more valid than another? Which would be the best approach? Are there other suggestions I may be overlooking? I'm also not sure if WebCrawling or Content Scrapping really holds water here...

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• Problem logging in and changing permissions in Facebook

  - by kujawk

  Hi everybody, I've got a piece of code that logs into Facebook, gets a session, sets status_update and offline_access permission if they are not set, and gets a new session with the newly set permissions. This code used to work fine but now I'm getting error 100 "One of the parameters specified was missing or invalid" as a response to the second call to get session and I can't figure out why. Here's the sequence in detail: CREATE TOKEN restserver.php?method=auth.createToken&api_key=[our key]&v=1.0&format=JSON&sig=[sig created with our secret] response: new token LOGIN m.facebook.com/login.php?api_key=[our key]&v=1.0&auth_token=[token created above] login screen loads and user successfully logs in with their username/password. GET SESSION restserver.php?method=auth.getSession&api_key=[our key]&v=1.0&format=JSON&auth_token=token created above&sig=[sig created with our secret] response: session key with expiration date and a secret CHECK/AUTHORIZE PERMISSIONS restserver.php?method=users.hasAppPermission&api_key=[our key]&v=1.0&format=JSON&ext_perm=status_update&call_id=[proper id]&session_key=[key returned above]&sig=[sig created with secret returned for get session] response: 0 m.facebook.com/authorize.php?api_key=[our key]&v=1.0&ext_perm=status_update authorization screen loads and user authorizes Same steps for status_update CREATE NEW TOKEN Same steps as done to create the first token LOGIN m.facebook.com/login.php?api_key=[our key]&v=1.0&auth_token=[new token] user is already logged in, redirected to their homepage GET NEW SESSION restserver.php?method=auth.getSession&api_key=[our key]&format=JSON&auth_token=[new token]&sig=[sig created with our secret] response: error 100 - missing or invalid parameter. Of course it doesn't tell me which one. Anybody have any ideas what I'm doing wrong here? I tried skipping the second login and going right to creating the new session and that didn't work. The only thing that seems to work is logging out the user after they've authorized the permissions and having them log back in again. I'd like to avoid this if possible. Can you have two outstanding sessions at one time? This code used to work but I'm thinking maybe something changed on Facebook's end that I'm not aware of. Thanks, kris

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• How to visually reject user input in a table?

  - by FX

  In the programming of a table-based application module (i.e. the user mostly enters tabular data in an already laid-out table), how would you reject user input for a given cell? The scenario is: the user edits the cell, enters something (text, picture, ...) and you want them to notice when they finish editing (hitting enter, for example) that their entry is not valid for your given "format" (in the wider meaning: it can be that they entered a string instead of a number, that their entry is too long, too short, they include a picture while it's not acceptable, ...). I can see two different things happening: You can rather easily fit their entry into your format, and you do so, but you want them to notice it so they can change if your guess is not good enough (example: they entered "15.47" in a field that needs to be an integer, so your program makes it "15") You cannot guess what to do with their entry, and want to inform them that it's not valid. My question specifically is: what visual display can you offer to inform the user that his input is invalid? Is it preferable to refuse to leave the editing mode, or not? The two things I can imagine are: using colors (red background if invalid, yellow background for my case 1 above) when you reject an input, do something like Apple does for password entry of user accounts: you make the cell "shaking" (i.e. oscillating left and right) for one second, and keep the focus/editing in their so they don't loose what they've typed. Let's hear your suggestions. PS: This question is, at least in my thought process, somehow a continuation and a specialization of my previous question on getting users to read error messages. PPS: Made this community wiki, was that the right thing to do on this kind of question or not?

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• iPhone - Problem with in-app purchases

  - by Satyam svv

  I've created iPhone app with in-app purchase. Now, I'm in testing phase. I created provisioning profile com.satyam.testapp In iTunes connected I created the application and uploaded the images, screen shots, desscription etc. I also created two id's for in-app purchase. One is com.satyam.testapp.book1 and the other one is com.satyam.testapp.book5 I created test account also for verifying my in-app purchases. Using com.stayam.testapp i created developer test profile and using the same in my developed application. I logged out the itunes app store account in my iphone. Now i started running my application on my iphone. Its saying that no items are there to purchase. But its not even asking me for credentials where i've to enter test account username and password..... how to debug it? Here's my delegate: - (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response { NSArray *myProduct = [[NSArray alloc] initWithArray:response.products]; for(int i=0;i<[myProduct count];i++) { SKProduct *product = [myProduct objectAtIndex:i]; NSLog(@"Name: %@ - Price: %f",[product localizedTitle],[[product price] doubleValue]); NSLog(@"Product identifier: %@", [product productIdentifier]); } for(NSString *invalidProduct in response.invalidProductIdentifiers) NSLog(@"Problem in iTunes connect configuration for product: %@", invalidProduct); [request autorelease]; [myProduct release]; }

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• Silverlight 4 XAML Collections

  - by mattduffield

  Hello, I have authored some custom classes that I would like to create using XAML: <Grid Width="300" Height="300"> <l:DashboardTable> <l:DashboardTable.DashboardTableQuery> <dq:DashboardTableQuery ConnectionString="Data Source=bunkerhill;Initial Catalog=emgov_data;User Id=emgovadmin;Password=p@$$word;" Query="select datename(month, cr_tb_DateDue) AS Month, sum(cr_tb_AmountTransaction) AS Total from cr_tb_transactionbill where Year(cr_tb_DateDue) = 2005 and Month(cr_tb_DateDue) IN (1,2,3,4) group by datename(month, cr_tb_DateDue)" > <dq:DashboardTableQuery.DataColumns> <dq:DataColumn ColumnName="Month" ColumnOrder="0" Label="Month" /> <dq:DataColumn ColumnName="Total" ColumnOrder="1" Label="Total" /> </dq:DashboardTableQuery.DataColumns> </dq:DashboardTableQuery> </l:DashboardTable.DashboardTableQuery> </l:DashboardTable> </Grid> The problem is that I get a XamlParseException when I try to run this XAML. I have determined it is when it gets to the dq:DataColumn element. It seems like this is only happening when I have a property that then has a collection and then several items in the collection that I am getting this issue. Has any encountered anything similar? I am try to achieve this all in XAML declaratively.

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• Session variables not getting set but only in Internet Explorer and not on all machines

  - by gaoshan88

  Logging into a site I'm working on functions as expected on my local machine but fails on the remote server but ONLY in Internet Explorer. The kicker is that it works in IE locally, just not on the remote machine. What in the world could cause this? I have stepped through the code on the remote machine and can see the entered login values being checked in the database, they are found and then a login function is called. This sets two $_SESSION variables and redirects to the main admin page. However, in IE only (and not when run on local machine... this is key) the $_SESSION variables are not present by the time you get to the main admin page. var_dump($_SESSION) gives me what I expect on every browser when I am running this in my local environment and in every browser except IE 6, 7 and 8 when run on the remote server (where I get a null value as if nothing has been set for $_SESSION). This really has me stumped so any advice is appreciated. For an example... in IE, run locally, var_dump gives me: array 'Username' => string 'theusername' length=11 'UserID' => string 'somevalue' length=9 Run on the remote server (IE only... works fine in other browsers) var_dump gives me: array(0){} Code: $User = GetUser($Username, $Password); if ($User->UserID <> "") { // this works so we call Login()... Login($User); // this also works and gives expected results. on to redirect... header("Location: index.php"); // a var_dump at index.php shows that there is no session data at all in IE, remotely. } else { header("Location: login.php"); } function Login($data) { $_SESSION['Username'] = $data->Username; $_SESSION['UserID'] = $data->UserID; // a var dump here gives the expected data in every browser }

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• LDAP query using Python: always no result

  - by Grey

  I am trying to use python to query LDAP server, and it always returns me no result. and anyone help me find what wrong with my python code? it runs fine without excpetions, and it always has no result. i played around with the filter like "cn=partofmyname" but just no luck. thanks for help import ldap try: l = ldap.open("server") l.protocol_version = ldap.VERSION3 l.set_option(ldap.OPT_REFERRALS, 0) output =l.simple_bind("cn=username,cn=Users,dc=domian, dc=net",'password$R') print output except ldap.LDAPError, e: print e baseDN = "DC=rim,DC=net" searchScope = ldap.SCOPE_SUBTREE ## retrieve all attributes - again adjust to your needs - see documentation for more options retrieveAttributes = None Filter = "(&(objectClass=user)(sAMAccountName=myaccount))" try: ldap_result_id = l.search(baseDN, searchScope, Filter, retrieveAttributes) print ldap_result_id result_set = [] while 1: result_type, result_data = l.result(ldap_result_id, 0) if len(result_data) == 0: print 'no reslut' break else: for i in range(len(result_set)): for entry in result_set[i]: try: name = entry[1]['cn'][0] email = entry[1]['mail'][0] phone = entry[1]['telephonenumber'][0] desc = entry[1]['description'][0] count = count + 1 print "%d.\nName: %s\nDescription: %s\nE-mail: %s\nPhone: %s\n" %\ (count, name, desc, email, phone) except: pass ## here you don't have to append to a list ## you could do whatever you want with the individual entry #if result_type == ldap.RES_SEARCH_ENTRY: # result_set.append(result_data) # print result_set except ldap.LDAPError, e: print e l.unbind()

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• PHP Ampersand in String

  - by John

  Hello. I'm having a bit of a problem. I am trying to create an IRC bot, which has an ampersand in its password. However, I'm having trouble putting the ampersand in a string. For example... <?php $var = "g&abc123"; echo $var; ?> I believe this should print g&abc123. However it's printing g. I have tried this as well: <?php $arr = array("key" => "g&abc123"); print_r($arr); ?> This prints it correctly with the g&abc123, however when I say echo $arr['key']; it prints g again. Any help would be appreciated. I'm running PHP5.3.1. EDIT: Also, I just noticed that if I use g&abc123&abc123 it prints g&abc123. Any suggestions?

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• How many WCF connections can a single host handle?

  - by mafutrct

  I'll try to explain this with an example. I'm writing a chat application. There are users that can join chat rooms. A user has to log in before he can join any room. Currently, there is a single service. A user logs in using this service. Then, the user sends and receives messages for all joined rooms via this single service. channel.Login("Hans Moleman", "password"); channel.JoinRoom("name of room"); channel.SendChat("name of room", "hello"); I'm thinking about changing the design so there is a new WCF connection for each joined room. In the actual app, the number of connections is likely going to be in the range of 10-100, possibly more. Is this a good idea? Or are ~100 connections per client too much? The server should be able to handle many clients (range 100-1000, later up to 10k). In case it matters, I'm using NetTcpBinding.

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• Getting response status code 0 in SmartGWT webservice call using json

  - by Girish

  I have developed application using SmartGWT, now i need to call webservice using json to another application which is deployed in another server for submitting username and password. When i make a request with url and POST method, getting the response status code as 0 and response text as blank. Here is my code, public void sendRequest() throws Exception { // Get login json data to be sent to server. String strData = createLoginReqPacket(); String url = "some url"; RequestBuilder builder = new RequestBuilder(RequestBuilder.POST, url); builder.setHeader("Content-Type", "application/json"); builder.setHeader("Content-Length", strData.length() + ""); Request response = builder.sendRequest(strData, new RequestCallback() { @Override public void onResponseReceived(Request request, Response response) { int statusCode = response.getStatusCode(); System.out.println("Response code ----"+response.getStatusCode()+""); if (statusCode == Response.SC_OK) { String responseBody = response.getText(); System.out.println("Respose :" + responseBody); // do something with the response } else { GWT.log("Response error at server side ----",null); // do in case of server error } }// end of method. @Override public void onError(Request request, Throwable exception) { GWT.log("**** Error in service call ******",null); }// end of method. }); builder.send(); }// end of send request. Please anybody knows the solution?? Give some reference code or links for this. Thanks.

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• why does cx_oracle execute() not like my string now?

  - by Frank Stallone

  I've downloaded cx_oracle some time ago and wrote a script to convert data to XML. I've had to reisntall my OS and grabbed the latest version of cx_Oracle (5.0.3) and all of the sudden my code is broken. The first thing was that cx_Oracle.connect wanted unicode rather string for the username and password, that was very easy to fix. But now it keeps failing on the cursor.execute and tells me my string is not a string even when type() tells me it is a string. Here is a test script I initally used ages ago and worked fine on my old version but does not work on cx_Oracle now. import cx_Oracle ip = 'url.to.oracle' port = 1521 SID = 'mysid' dsn_tns = cx_Oracle.makedsn(ip, port, SID) connection = cx_Oracle.connect(u'name', u'pass', dsn_tns) cursor = connection.cursor() cursor.arraysize = 50 sql = "select isbn, title_code from core_isbn where rownum<=20" print type(sql) cursor.execute(sql) for isbn, title_code in cursor.fetchall(): print "Values from DB:", isbn, title_code cursor.close() connection.close() When I run that I get: Traceback (most recent call last): File "C:\NetBeansProjects\Python\src\db_temp.py", line 48, in cursor.execute(sql) TypeError: expecting None or a string Does anyone know what I may be doing wrong?

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• Upcasting without any added data fields.

  - by Benjamin Manns

  In my project I have a generic Packet class. I would like to be able to upcast to other classes (like LoginPacket or MovePacket). The base class contains a command and arguments (greatly simplified): public class Packet { public String Command; public String[] Arguments; } I would like to have be able to convert from Packet to LoginPacket (or any other) based on a check if Packet.Command == "LOGIN". The login packet would not contain any new data members, but only methods for accessing specific arguments. For example: public class LoginPacket : Packet { public String Username { get { return Arguments[0]; } set { Arguments[0] == value; } } public String Password { get { return Arguments[1]; } set { Arguments[1] == value; } } } It would be great if I could run a simple code that would cast from Packet to LoginPacket with something like LoginPacket _Login = (LoginPacket)_Packet;, but that throws a System.InvalidCastException. It seems like this would be an easy task, as no new data is included, but I can't figure out any other way than copying everything from the Packet class to a new LoginPacket class.

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• Any suggestions to improve my PDO connection class?

  - by Scarface

  Hey guys I am pretty new to pdo so I basically just put together a simple connection class using information out of the introductory book I was reading but is this connection efficient? If anyone has any informative suggestions, I would really appreciate it. class PDOConnectionFactory{ public $con = null; // swich database? public $dbType = "mysql"; // connection parameters public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } }

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• ASP can't connect to SQL Server database

  - by birdus

  I'm trying to get a classic ASP application to connect to a local SQL Server 2008 database. The app and database were built by someone else. I'm just trying to get them installed and running on my machine (Windows 7). I'm getting the following error when when the ASP app tries to connect to the database: Could not connect to database: Error Number: -2147467259 Error Message: [ConnectionOpen (Connect()).] does not exist or access denied. I don't see any messages in the Windows Event Viewer. I'm looking at: Event Viewer-Windows Logs-Application. It's a fresh database install using a simple restore. The SQL Server install uses the default instance. SQL Server and Windows authentication are both allowed. I left the existing connection string (in the ASP code) in tact and just tried adding that to my SQL Server installation. Here's the connection string: strConn = "PROVIDER=SQLOLEDB;SERVER=localhost;UID=TheUser;PWD=ThePassword;DATABASE=TheDatabase;" To add that user to SQL Server, I went to Security/Logins in SSMS and added the user and the password. I selected the database in question as the Default database. I thought that might do the trick, but it didn't. Then, I went into TheDatabase, then went into Security there. I added a new user there, referencing the new user I had already added in server Security. Under Owned Schemas, I clicked db_owner and under Role Members I checked db_accessadmin and db_owner. None of this gave the ASP application access to the database. The sid values match in sys.database_principals and sys.server_principals for the login in question. I am able to login to SSMS using this login. The app needs to execute selects against the database like this: oConn.Execute('select * from someTable') I'm not a DBA and am sort of grasping at straws here. How do I get this thing connected? Thanks, Jay

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• How do I implement aasm in Rails 3 for what I want it to do?

  - by marcamillion

  I am a Rails n00b and have been advised that in order for me to keep track of the status of my user's accounts (i.e. paid, unpaid (and therefore disabled), free trial, etc.) I should use an 'AASM' gem. So I found one that seems to be the most popular: https://github.com/rubyist/aasm But the instructions are pretty vague. I have a Users model and a Plan model. User's model manages everything you might expect (username, password, first name, etc.). Plan model manages the subscription plan that users should be assigned to (with the restrictions). So I am trying to figure out how to use the AASM gem to do what I want to do, but no clue where to start. Do I create a new model ? Then do I setup a relationship between my User model and the model for AASM ? How do I setup a relationship? As in, a user 'has_many' states ? That doesn't seem to make much sense to me. Any guidance would be really appreciated. Thanks. Edit: If anyone else is confused by AASMs like myself, here is a nice explanation of their function in Rails by the fine folks at Envy Labs: http://blog.envylabs.com/2009/08/the-rails-state-machine/ Edit2: How does this look: include AASM aasm_column :current_state aasm_state :paid aasm_state :free_trial aasm_state :disabled #this is for accounts that have exceed free trial and have not paid #aasm_state :free_acct aasm_event :pay do transitions :to => :paid, :from => [:free_trial, :disabled] transitions :to => :disabled, :from => [:free_trial, :paid] end

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• NHibernate is not connecting to sql server.

  - by user177883

  When i set up a regular connection, it works, however when i try to use nhibernate, hibernate.cfg.xml, i m getting the following error. Message="A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: SQL Network Interfaces, error: 26 - Error Locating Server/Instance Specified)" Source=".Net SqlClient Data Provider" What would be the reason for this and how can i resolve it ? I doubt that it s a network or sql server configuration error. <?xml version="1.0" ?> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2" > <session-factory> <property name="connection.provider">NHibernate.Connection.DriverConnectionProvider</property> <property name="dialect">NHibernate.Dialect.MsSql2005Dialect</property> <property name="connection.driver_class">NHibernate.Driver.SqlClientDriver</property> <property name="connection.connection_string">Server=(ServerName\DEV_ENV);Initial Catalog=dbName;User Id=SA;Password=PASS</property> <property name="proxyfactory.factory_class">NHibernate.ByteCode.LinFu.ProxyFactoryFactory, NHibernate.ByteCode.LinFu</property> </session-factory> </hibernate-configuration>

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• @selector and return value

  - by user320926

  The idea it's very easy, i have an http download class, this class must support the http authentication but it's basically a background thread so i would like to avoid to prompt directly to the screen, i would like to use a delegate method to require from outside of the class, like a viewController. But i don't know if is possible or if i have to use a different syntax. This class use this delegate protocol: //Updater.h @protocol Updater <NSObject> -(NSDictionary *)authRequired; @optional -(void)statusUpdate:(NSString *)newStatus; -(void)downloadProgress:(int)percentage; @end @interface Updater : NSThread { ... } This is the call to the delegate method: //Updater.m // This check always fails :( if ([self.delegate respondsToSelector:@selector(authRequired:)]) { auth = [delegate authRequired]; } This is the implementation of the delegate method //rootViewController.m -(NSDictionary *)authRequired; { // TODO: some kind of popup or modal view NSMutableDictionary *ret=[[NSMutableDictionary alloc] init]; [ret setObject:@"utente" forKey:@"user"]; [ret setObject:@"password" forKey:@"pass"]; return ret; }

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• unable to use html form post in php

  - by kossibox

  Hello i have an html form and i'm posting data but i'm unable to get the posted data on a php page (same page) can you please help me. thanks in advance <div class="left"> <form name="form_signin" method="post" onsubmit="return signinValid();" > <table> <tr> <td> Email : </td> <td> <input type="text" id="email" length ="40"> </td> </tr> <tr> <td> Mot de Passe : </td> <td> <input type="password" id ="pass" length ="40"> </td> </tr> <tr> <td> &nbsp; </td> <td> <input type="submit" value="Connexion" length ="40"> </td> </tr> </table> </form> <?php include 'includes.php'; include DB_CONNECT_FILE; //session_start(); print_r($_POST); // prints an empty array even if fields are filled $smart->assign('tpl_file',TEMPLATES_DIR.'signin.html'); $smart->display(TEMPLATES_DIR."with_right.html"); include DB_DISCONNECT_FILE; ?>

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• javax.xml.ws.soap.SOAPFaultException: Could not send Message - at JaxWsClientProxy.invoke - caused by HTTP response code: 401 for URL

  - by Mikkis

  I moved a working code from dev to test and encountered the following error(s) in test: javax.xml.ws.soap.SOAPFaultException: Could not send Message. at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:143) ...... at org.apache.cxf.interceptor.MessageSenderInterceptor$MessageSenderEndingInterceptor.handleMessage(MessageSenderInterceptor.java:64) at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:236) at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:472) at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:302) at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:254) at org.apache.cxf.frontend.ClientProxy.invokeSync(ClientProxy.java:73) at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:123) at $Proxy739.copyIntoItems(Unknown Source) Caused by: java.io.IOException: Server returned HTTP response code: 401 for URL: http:///_vti_bin/Copy.asmx at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1436) at java.net.HttpURLConnection.getResponseCode(HttpURLConnection.java:379) at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponseInternal(HTTPConduit.java:2046) Environment specs: Java 1.6 Tomcat 6 Eclipse Helios Maven2 CXF 2.2.3 As a background work, tried to explore about the error in similar category bad URL (ruled out as i am using same URL in dev and test. and the url, userid, password are all accessible from both the machines), connection timeout( error is not 404 or it doesnt specify connection timed out... it says 401 response code for url) Checked if all the jars and same versions are included in the test environment. Can someone shed some light to understand and resolve the error? please let me know if any more details are to be included.

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• explode is not working to split string

  - by pmms

  we unable to split the string following code.please Help us. <?php $i=0; $myFile = "testFile.txt"; $fh = fopen($myFile, 'a') or die("can't open file"); $stringData = "no\t"; fwrite($fh, $stringData); $stringData = "username \t"; fwrite($fh, $stringData); $stringData ="password \t"; fwrite ($fh,$stringData); $newline ="\r\n"; fwrite ($fh,$newline); $stringData1 = "1\t"; fwrite($fh, $stringData1); $stringData1 = "srinivas \t"; fwrite($fh, $stringData1); $stringData1 ="malayappa \t"; fwrite ($fh,$stringData1); fclose($fh); ?> $fh = fopen("testFile.txt", "r"); $ while (!feof($fh)) { $line = fgets($fh); echo $line; } fclose($fh); $Beatles = array('pmm','malayappa','sreenivas','PHP'); for($i=0;$i<count($Beatles);$i++) { if($i==2) { echo $Beatles[$i-1]; echo $Beatles[$i-2]; } } $pass_ar=array(); $fh = fopen("testFile.txt", "r"); while (!feof($fh)) { $line = fgets($fh); echo $line; $t1=explode(" ",$line); print_r($t1); array_push($pass_ar,t1); } fclose($fh); Thanks & Regards pmms

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• SugarmCRM REST API always returns "null"

  - by TuomasR

  I'm trying to test out the SugarCRM REST API, running latest version of CE (6.0.1). It seems that whenever I do a query, the API returns "null", nothing else. If I omit the parameters, then the API returns the API description (which the documentation says it should). I'm trying to perform a login, passing as parameter the method (login), input_type and response_type (json) and rest_data (JSON encoded parameters). The following code does the query: $api_target = "http://example.com/sugarcrm/service/v2/rest.php"; $parameters = json_encode(array( "user_auth" => array( "user_name" => "admin", "password" => md5("adminpassword"), ), "application_name" => "Test", "name_value_list" => array(), )); $postData = http_build_query(array( "method" => "login", "input_type" => "json", "response_type" => "json", "rest_data" => $parameters )); echo $parameters . "\n"; echo $postData . "\n"; echo file_get_contents($api_target, false, stream_context_create(array( "http" => array( "method" => "POST", "header" => "Content-Type: application/x-www-form-urlencoded\r\n", "content" => $postData ) ))) . "\n"; I've tried different variations of parameters and using username instead of user_name, and all provide the same result, just a response "null" and that's it.

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• PEAR:DB connection parameters

  - by Markus Ossi

  I just finished my first PHP site and now I have a security-related question. I used PEAR:DB for the database connection and made a separate parameter file for it. How should I hide this parameter file? I found a guide (http://www.kitebird.com/articles/peardb.html) that says: Another way to specify connection parameters is to put them in a separate file that you reference from your main script. ... It also enables you to move the parameter file outside of the web server's document tree, which prevents its contents from being displayed literally if the server becomes misconfigured and starts serving PHP scripts as plain text. I have now put my file in a directory like this /include/db_parameters.inc However, if I go to this URL, the web server shows me the contents of the file including my database username and password. From what I've understood, I should protect this file so, that even though PHP would be served as text, nobody could read this. What does outside of web server's document tree mean here? Put the PHP file out of public_html directory altogether deeper into the server file system? Some CHMOD?

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• xml parser not able to read all the nodes of the xml

  - by pankaj

  Hi i am trying to get values from all the nodes of a xml returned from a web service. But my code only reads first node, it does not read it further. code: -(void)parseData{ NuanceAppDelegate *appDel = (NuanceAppDelegate *)[[UIApplication sharedApplication] delegate]; NSString *url = @"http://cmweb.bpomatrix.net/SmartPhoneService.svc/login/"; url = [[[url stringByAppendingString:UserName] stringByAppendingString:@"/"] stringByAppendingString:Password]; url = [[url stringByAppendingString:@"/"] stringByAppendingString:appDel.CPAID]; NSLog(@"log: @%",url); NSURL *loginURL = [NSURL URLWithString:url]; NSXMLParser *home_Parser = [[NSXMLParser alloc] initWithContentsOfURL:loginURL]; [home_Parser setDelegate:self]; dict = [[NSMutableDictionary alloc] init]; [home_Parser parse]; } - (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qualifiedName attributes:(NSDictionary *)attributeDict{ if([elementName isEqualToString:@"Address"]) addressFound = TRUE; if([elementName isEqualToString:@"Name"]) nameFound = TRUE; if([elementName isEqualToString:@"LoyaltyNum"]) loyaltyNumFound = TRUE; if([elementName isEqualToString:@"City"]) cityFound = TRUE; if([elementName isEqualToString:@"Province"]) proFound = TRUE; if([elementName isEqualToString:@"Zip"]) zipFound = TRUE; //NSLog(@"Response %@",responseFound); } - (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string{ if(addressFound) { [dict setObject:string forKey:@"address"]; addressFound = FALSE; } else if(nameFound) { [dict setObject:string forKey:@"name"]; nameFound = FALSE; } else if(loyaltyNumFound) { [dict setObject:string forKey:@"loyaltyNum"]; loyaltyNumFound = FALSE; } else if(cityFound) { [dict setObject:string forKey:@"city"]; cityFound = FALSE; } else if(proFound) { [dict setObject:string forKey:@"province"]; proFound = FALSE; } else if(zipFound) { [dict setObject:string forKey:@"zip"]; zipFound = FALSE; } } - (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName { if([elementName isEqualToString:@"clsUserProfile"]) { [self parsingOver]; } } -(void)parsingOver { NuanceAppDelegate *appDel = (NuanceAppDelegate *)[[UIApplication sharedApplication] delegate]; appDel.dictProfile = dict; }

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• webBrower Button Click without element ID?

  - by Jeremy

  I'm working on a login system for a forum and trying to make it work via a c# .net form. I need to programitically click the login button on the forum with a webBrower control. So far I have this. webPage page = new webPage(); page.URL = txtURL.Text; page.Load(); //Load the text from the specified URL WebBrowser browser = new WebBrowser(); browser.Document.GetElementById("navbar_username").SetAttribute("value", textBox1.Text); browser.Document.GetElementById("navbar_password").SetAttribute("value", textBox2.Text); HtmlElement el = browser.Document.All["btnI"]; if (el != null) { el.InvokeMember("click"); } else { MessageBox.Show("There is an issue with the program"); } The issue is that the login button on the page does not have an ID or any real information that can allow me to click on it. Does anyone have any suggestions? Here is the code for the login button. <input type="image" src="images/loginbutton.png" class="loginbutton" tabindex="104" value="Log in" title="Enter your username and password in the boxes provided to login, or click the 'register' button to create a profile for yourself." accesskey="s">

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• Artisan unable to access environment variables from $_ENV

  - by hansn

  Any artisan command I enter into the command line throws this error: $ php artisan <? return array( 'DB_HOSTNAME' => 'localhost', 'DB_USERNAME' => 'root', 'DB_NAME' => 'pc_booking', 'DB_PASSWORD' => 'secret', ); PHP Warning: Invalid argument supplied for foreach() in /home/martin/code/www/pc_backend/vendor/laravel/framework/src/Illuminate/Config/EnvironmentVariables.php on line 35 {"error":{"type":"ErrorException","message":"Undefined index: DB_HOSTNAME","file":"\/home\/martin\/code\/www\/pc_backend\/app\/config\/database.php","line":57}} This is only on my local development system, where I recently installed apache and php. On my production system on a shared host artisan commands work just fine. The prod system has it's own .env.php, but other than that the code should be identical. Relevant files: .env.local.php <? return array( 'DB_HOSTNAME' => 'localhost', 'DB_USERNAME' => 'root', 'DB_NAME' => 'pc_booking', 'DB_PASSWORD' => 'secret', ); app/config/database.php <?php return array( 'fetch' => PDO::FETCH_CLASS, 'default' => 'mysql', 'connections' => array( 'mysql' => array( 'driver' => 'mysql', 'host' => $_ENV['DB_HOSTNAME'], 'database' => $_ENV['DB_NAME'], 'username' => $_ENV['DB_USERNAME'], 'password' => $_ENV['DB_PASSWORD'], 'charset' => 'utf8', 'collation' => 'utf8_unicode_ci', 'prefix' => '', ), ), 'migrations' => 'migrations', ), ); The $_ENV array is populated as expected on the website - the problem appears to be with artisan only.

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