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  • jquery form select (if exists in $_POST)

    - by SoulieBaby
    Hi all, I'm trying to redo this in jQuery: <script language="JavaScript" type="text/javascript"> var thisIsSelected = '<?php echo $_POST['image']; ?>'; var sel1= document.getElementById('image'); sel1.value = thisIsSelected; </script> But I seem to keep breaking it lol Basically I want jQuery to check if $_POST['image'] exists and if so make it selected on the form. I'm assuming if it's possibly with javascript, jquery can do it easier ;)

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  • MySQL Select statement Where table1.id != table2.id

    - by Michael
    I have a table of data which has posts, then I have a separate table of data which has deleted posts. What happens when a post is deleted is that it's ID get's added to the deleted table rather than removing the post entry. What is a clean efficient way of selecting all the posts from the posts table without selecting the ones that have their ID in the deleted table

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  • sql select puzzle: remove children when parent is filtered out

    - by knicnak32
    I have a table essentially: name has_children parent_id row_id values0.....valuesn parent 1 1 1 children 0 1 2 children 0 1 3 parent 0 4 4 parent 1 5 5 children 0 5 6 children 0 5 7 the values for the children can be different than the values for the parent. i want some selects/joins that will filter the table on a value column (i.e. 10) and will return the parent (even if false for the filter) if one of it's children is true for the filter. acceptable return: parent=true all children=false, return just parent parent=false >=1 children=true, return parent and one non-filtered child i'm sure this has been thought about before but i don't have the faintest idea how to phrase the question to find a solution.

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  • Setting selected item in custom Zend_Form_Element

    - by sanders
    Hello Everyone, I have created my own little form element for inputting time's. Since I need this on a few places in my application, i decided to create a seperate element for it. Here is the code so fa: class EventManager_Form_Element_Time extends Zend_Form_Element { public function init() { parent::init(); $this->addDecorator('ViewScript', array( 'viewScript' => 'time.phtml' )); $this->addValidator(new Zend_Validate_Regex('/^[0-9]+:[0-9]+:[0-9]+$/')); } public function setValue($value) { if(is_array($value)) { @list($hours, $minutes, $seconds) = $value; $value = sprintf('%s:%s:%s', $hours, $minutes, $seconds); } return parent::setValue($value); } } The corresponding view script, which I have created is: <?php @list($hours, $minutes, $seconds) = explode(':', $this->element->getValue()); ?> <dt> <?= $this->formLabel($this->element->getName(), $this->element->getLabel()); ?> </dt> <dd> <select id="<?= $this->element->getName();?>"> <option value="00">00</option> <option value="01">01</option> <option value="02">02</option> <option value="03">03</option> <option value="04">04</option> <option value="05">05</option> <option value="06">06</option> <option value="07">07</option> <option value="08">08</option> <option value="09">09</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> </select> <select id="<?= $this->element->getName();?>"> <option value="00">00</option> <option value="15">15</option> <option value="30">30</option> <option value="45">45</option> </select> <input id="<?= $this->element->getName(); ?>" type="hidden" name="<?= $this->element->getName(); ?>[]" value="00" /> <?php if(count($this->element->getMessages()) > 0): ?> <?= $this->formErrors($this->element->getMessages()); ?> <?php endif; ?> </dd> My problem is that sometimes i want to set a default selected value to my selecboxes when I populate my form. The question is how? Is there anyone that could help me out with this? Thanks.

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  • select rows with unidentical column values using R

    - by Bazon
    Hi Guys, I need to create a new data frame that excludes dams that appear in "dam1" and "dam2" columns on the same fosdate (fostering date). I tried df <- df[df$dam1!=df$dam2,] but did not work. Dam1 and dam2 are factors which are the ids's of mothers. my df: fosdate dam1 dam2 8/09/2009 2Z523 2Z523 30/10/2009 1W509 5C080 30/10/2009 1W509 5C640 30/10/2009 1W509 1W509 1/10/2009 1W311 63927 The new data frame that I need to get is: dfnew: fosdate dam1 dam2 30/10/2009 1W509 5C080 30/10/2009 1W509 5C640 1/10/2009 1W311 63927 Would appreciate any help! Bazon

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  • MySQL Many to Many with Unique keys and Update/Select if Exists otherwise Insert

    - by Jayrox
    In my goal to have a Many-to-Many relationship in my MySQL database I have arrived at another bridge to build. Current Tables: Users (id, name) Tags (id, name) User_Tags (user_id, tag_id) Here is the goal: I would like to have the ability to take a tag i.e: #fb and insert it into my Tags database which has a unique constraint on name and if the tag exists I would like to return it's id I would like to insert the tag.id and the current user's user.id into User_Tags. I do not have any unique constraints on the User_Tags table because I would like to be able to track the user's most commonly used tags and present them in a list ordered by frequency of use. I am currently developing this project in PHP using prepared statements. Additionally, performance is not currently an issue as my user count is still fairly small, but it is steadily growing and may be an issue in the future.

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  • PostgreSQL - select only when specific multiple apperance in column

    - by Horse SMith
    I'm using PostgreSQL. I have a table with 3 fields person, recipe and ingredient person = creator of the recipe recipe = the recipe ingredient = one of the ingredients in the recipe I want to create a query which results in every person who whenever has added carrot to a recipe, the person must also have added salt to the same recipe. More than one person can have created the recipe, in which case the person who added the ingredient will be credited for adding the ingredient. Sometimes the ingredient is used more than once, even by the same person. If this the table: person1, rec1, carrot person1, rec1, salt person1, rec1, salt person1, rec2, salt person1, rec2, pepper person2, rec1, carrot person2, rec1, salt person2, rec2, carrot person2, rec2, pepper person3, rec1, sugar person3, rec1, carrot Then I want this result: person1 Because this person is the only one who whenever has added carrot also have added salt.

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  • MySQL PHP | "SELECT FROM table" using "alphanumeric"-UUID. Speed vs. Indexed Integer / Indexed Char

    - by dropson
    At the moment, I select rows from 'table01' using: SELECT * FROM table01 WHERE UUID = 'whatever'; The UUID column is a unique index. I know this isn't the fastest way to select data from the database, but the UUID is the only row-identifier that is available to the front-end. Since I have to select by UUID, and not ID, I need to know what of these two options I should go for, if say the table consists of 100'000 rows. What speed differences would I look at, and would the index for the UUID grow to large, and lag the DB? Get the ID before doing the "big" select 1. $id = "SELECT ID FROM table01 WHERE UUID = '{alphanumeric character}'"; 2. $rows = SELECT * FROM table01 WHERE ID = $id; Or keep it the way it is now, using the UUID. 1. SELECT FROM table01 WHERE UUID '{alphanumeric character}'; Side note: All new rows are created by checking if the system generated uniqueid exists before trying to insert a new row. Keeping the column always unique. The "example" table. CREATE TABLE Table01 ( ID int NOT NULL PRIMARY KEY, UUID char(15), name varchar(100), url varchar(255), `date` datetime ) ENGINE = InnoDB; CREATE UNIQUE INDEX UUID ON Table01 (UUID);

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  • select query related problem

    - by user222585
    i have interest rate and amount in a table where interest rate are ranged in different values like 4.5,4.6,5.2,5.6 etc. i want to get sum of amounts classified by interest rate where interest rate will be separated by .25. for example all amount having interest rate 1.25,1.3,1.4 will be in one group and 1.5,1.67,1.9 will be in another group how can i write the query?

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  • Select Query Joined on Two Fields?

    - by btollett
    I've got a few tables in an access database: ID | LocationName 1 | Location1 2 | Location2 ID | LocationID | Date | NumProductsDelivered 1 | 1 | 12/10 | 3 2 | 1 | 01/11 | 2 3 | 1 | 02/11 | 2 4 | 2 | 11/10 | 1 5 | 2 | 12/10 | 1 ID | LocationID | Date | NumEmployees | EmployeeType 1 | 1 | 12/10 | 10 | 1 (=Permanent) 2 | 1 | 12/10 | 3 | 2 (=Temporary) 3 | 1 | 12/10 | 1 | 3 (=Support) 4 | 2 | 10/10 | 1 | 1 5 | 2 | 11/10 | 2 | 1 6 | 2 | 11/10 | 1 | 2 7 | 2 | 11/10 | 1 | 3 8 | 2 | 12/10 | 2 | 1 9 | 2 | 12/10 | 1 | 3 What I want to do is pass in the LocationID as a parameter and get back something like the following table. So, if I pass in 2 as my LocationID, I should get: Date | NumProductsDelivered | NumPermanentEmployees | NumSupportEmployees 10/10 | | 1 | 11/10 | 1 | 2 | 1 12/10 | 1 | 2 | 1 It seems like this should be a pretty simple query. I really don't even need the first table except as a way to fill in the combo box on the form from which the user chooses which location they want a report for. Unfortunately, everything I've done has resulted in me getting a lot more data than I should be getting. My confusion is in how to set up the join (presumably that's what I'm looking for here) given that I want both the date and locationID to be the same for each row in the result set. Any help would be much appreciated. Thanks.

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  • AuthSub target path prefix does not match the provided "next" URL

    - by dweebsonduty
    I am trying to use the Gcal API in PHP. I am using the ZEND framework function getAuthSubUrl($company) { $next = "http://$company.mysite.com"; $scope = 'http://www.google.com/calendar/feeds/'; $secure = false; $session = true; return (Zend_Gdata_AuthSub::getAuthSubTokenUri($next, $scope, $secure, $session)); } $authSubUrl = getAuthSubUrl(); echo "<a href=\"$authSubUrl\">login to your Google account"</a> I am not sure what I am doing wrong here. I am following the google example almost exactly. They do have $next = getCurrentUrl(); in their expample but I am getting undefined errors when I try that.

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  • Zend_Navigation failing to load

    - by Grant Collins
    Hi, Following on from my earlier question, I am still having issues with loading the xml file into Zend_Navigation. I am now getting the following error message: <b>Fatal error</b>: Uncaught exception 'Zend_Navigation_Exception' with message 'Invalid argument: Unable to determine class to instantiate' in C:\www\mysite\development\website\library\Zend\Navigation\Page.php:223 I've tried to make my navigation.xml file look similar to the example on the Zend Documentation, However I just can't seem to get it to work. My XML file looks like this: <?xml version="1.0" encoding="UTF-8"?> <configdata> <navigation> <default> <label>Home</label> <controller>index</controller> <action>index</action> <module>default</module> <pages> <tour> <label>Tour</label> <controller>tour</controller> <action>index</action> <module>default</module> </tour> <blog> <label></label> <uri>http://blog.mysite.com</uri> </blog> <support> <label>Support</label> <controller>support</controller> <action>index</action> <module>default</module> </support> </pages> </default> <users> <label>Home</label> <controller>index</controller> <action>index</action> <module>users</module> <role>guser</role> <resource>owner</resource> <pages> <jobmanger> <label>Job Manager</label> <controller>jobmanager</controller> <action>index</action> <module>users</module> <role>guser</role> <resource>owner</resource> </jobmanger> <myaccount> <label>My Account</label> <controller>profile</controller> <action>index</action> <role>guser</role> <resource>owner</resource> <module>users</module> <pages> <detail> <label>Account Details</label> <controller>profile</controller> <action>detail</action> <module>users</module> <role>guser</role> <resource>owner</resource> <pages> <history> <label>Account History</label> <controller>profile</controller> <action>history</action> <module>users</module> <role>guser</role> <resource>owner</resource> </history> <password> <label>Change Password</label> <controller>profile</controller> <action>changepwd</action> <module>users</module> <role>employer</role> <resource>employers</resource> </password> </pages> </detail> ... </navigation> </configdata> Now I confess that I've totally got the wrong end of the stick with this, but rapidly running out of ideas, and it's been a long week. Thanks, Grant

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  • Strategy for storing and displaying form dropdown data for provinces, states, prefixes?

    - by meder
    I'm currently migrating from a class that stores lists of countries, states & provinces in the form of arrays to using Zend's Locale data in the form of ldml xml files. These ldml files provide localised lists of countries, currencies, languages - so I'm not exactly sure where I should store US States, ( Canadian Provinces ), Prefixes - I was thinking possibly just create a generic xml file and store it in the same directory as the ldml files, but having doubts because it wouldn't really be localised as I'd store it in English. Should I go with storing it in a generic xml file, or possibly update each of the locale files ( eg en.xml ) and append them? The latter is probably not worth the work, which is why I'm swaying towards just a general.xml or dropdown-data.xml. As for generating dropdown options, I suppose I could just say, grab all US states, append the array with Canadian provinces, and append that with an 'Other' option - does this seem like the right way to go about?

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  • Mysql adapter for Zend_Translate

    - by Peter
    Hi everybody, I'm currently in the planning phase of a rather large project that I'll develop in the Zend Framework. One of the problems I'm facing is that the customers will want to translate not only the content but also the interface. I'm currently using gettext and poedit to manage my language files but this is not an option for the customer as they, for one, want have FTP access to the site. Hence, I'm thinking of a mysql back end with an interface in the front end for the customer to manage his own translations of the interface. There is however still no mysql adapater for Zend_Translate. So, does anybody now of an adapter script for Zend_Translate so it can work with a mysql table? Or any arguments against using mysql and possible other solutions for this problem?

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  • How can I generate XML application configuration using Zend_Tool?

    - by wimvds
    When creating a new project using zf create project myproject it will create a default project layout with an application.ini in the configs folder. Where can I change these default settings so that it generates (and uses) an XML file (application.xml)? I've looked at the documentation for Zend_Tool (http://framework.zend.com/manual/en/zend.tool.html), but there seems to be no information on how to do this. And suppose you'd like to use a different default folder layout (ie. use htdocs instead of public as your document root), is there a way to specify this as well? Any pointers to relevant information (btw I've looked at the Quickstart, nothing relevant is mentioned there unless I'm overlooking it)? edit I already tried creating a profile (stored in .zf/project/profiles), and used that to create a project (using zf create project myproject myprofile) but that doesn't change anything, even though the .zfproject.xml file in the root of the new project does contain the <applicationConfigFile type="xml"/> setting... The new project contains this (as you can see, it's just the default settings, only the type of applicationConfigFile has been changed) : <?xml version="1.0"?> <projectProfile type="default" version="1.10"> <projectDirectory> <projectProfileFile filesystemName=".zfproject.xml"/> <applicationDirectory classNamePrefix="Application_"> <apisDirectory enabled="false"/> <configsDirectory> <applicationConfigFile type="xml"/> </configsDirectory> <controllersDirectory> <controllerFile controllerName="Index"> <actionMethod actionName="index"/> </controllerFile> <controllerFile controllerName="Error"/> </controllersDirectory> <formsDirectory enabled="false"/> <layoutsDirectory enabled="false"/> <modelsDirectory/> <modulesDirectory enabled="false"/> <viewsDirectory> <viewScriptsDirectory> <viewControllerScriptsDirectory forControllerName="Index"> <viewScriptFile forActionName="index"/> </viewControllerScriptsDirectory> <viewControllerScriptsDirectory forControllerName="Error"> <viewScriptFile forActionName="error"/> </viewControllerScriptsDirectory> </viewScriptsDirectory> <viewHelpersDirectory/> <viewFiltersDirectory enabled="false"/> </viewsDirectory> <bootstrapFile filesystemName="Bootstrap.php"/> </applicationDirectory> <dataDirectory enabled="false"> <cacheDirectory enabled="false"/> <searchIndexesDirectory enabled="false"/> <localesDirectory enabled="false"/> <logsDirectory enabled="false"/> <sessionsDirectory enabled="false"/> <uploadsDirectory enabled="false"/> </dataDirectory> <docsDirectory> <file filesystemName="README.txt"/> </docsDirectory> <libraryDirectory> <zfStandardLibraryDirectory enabled="false"/> </libraryDirectory> <publicDirectory> <publicStylesheetsDirectory enabled="false"/> <publicScriptsDirectory enabled="false"/> <publicImagesDirectory enabled="false"/> <publicIndexFile filesystemName="index.php"/> <htaccessFile filesystemName=".htaccess"/> </publicDirectory> <projectProvidersDirectory enabled="false"/> <temporaryDirectory enabled="false"/> <testsDirectory> <testPHPUnitConfigFile filesystemName="phpunit.xml"/> <testApplicationDirectory> <testApplicationBootstrapFile filesystemName="bootstrap.php"/> </testApplicationDirectory> <testLibraryDirectory> <testLibraryBootstrapFile filesystemName="bootstrap.php"/> </testLibraryDirectory> </testsDirectory> </projectDirectory> </projectProfile>

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  • zend studio 5.5.1 on windows xp - won't open!

    - by esther h
    I have been using zend studio 5.5.1 for the last year and and a half (on windows xp), with some occasional issues, such as a blank error dialog box when I started the program, but always went away when i restarted my computer, and usually got messages about javaw.exe errors. But now, the program does not open at all. What happens is, I get a little dialog that says Loading project - this is normal... but then, nothing. The zend program item is sitting in the taskbar, but when i click on it - nothing! there is nothing to show. i can right click and press close, but that is all. restarting computer did not help. i just uninstalled it, downloaded again from zend website, and reinstalled. tried opening - get loading box, seems to have loaded, even got tip of the day box. but there is nothing showing behind them. once i closed the tip box, i dont have any indication that zend is open besides the program item in the taskbar. windows task manager says it is running... anyone have a clue? help!!! thanks

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  • ...Welche DB-Hintergrundprozesse sind für was zuständig?... wie ging das nochmal? Und wie heisst noch diese eine wichtige Data Dictionary View? ...

    - by britta.wolf
    ...Gab es da nicht mal ein gutes Oracle-Poster, wo man schnell nachschauen konnte und einen guten Überblick bekam? Viele Datenbankadministratoren haben das besagte Poster, das die Architektur und Prozesse sowie die Data Dictionary-Struktur der Oracle Datenbank beschreibt, vermisst! Daher wurde nun eine handliche kleine Flash-Applikation mit erweitertem Inhalt entwickelt - Oracle Database 11g: Interactive Quick Reference - die man sich hier downloaden kann (einfach auf den Button "Download now" klicken (Größe der Zip-Datei: 4.6 MB). Ist genial, muss man haben!!! :-)

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  • DB Documentation Tool

    - by Hisham El-bereky
     Recently I have uploaded new project to codeplex site, DbDocument or DbDoc project is a helper tool used side by side with MS SQL server management studio tool, you can design your DB Tables in visualized way through Diagrams and then use “DbDoc” tool to generate design document in MS Word format, the generated file can be used in design review process or as history reference, the tool facilitate and reduce the time of writing DB structure documentthe current version is not so sophisticated which is intend to generate word document in table format with all tables in DB illustrating its structure and constraints, but for now it seems to be good.   For more details check DbDoc document or go immediately to DbDoc home page http://dbdocument.codeplex.com/

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  • MySQL vs. SQL Server Go daddy, What is the difference bewteen hosted DB and App_Data Db.

    - by Nate Gates
    I'm using Goddady for site hosting, and I'm currently using MySQL, because there are less limits on size,etc. My question is what is the difference between using a hosted Godaddy Db such as MySQL vs. creating a SQL Serverdatabase in the the App_Data folder? My guess is security? Would it be a bad idea to use a SQL ServerDB thats located in the App_Data folder? Additional Well I am able to create a .mdf (SQL Server DB file) in the App_Data folder, but I'm really unsure if should use that or not, If I did use it it would simplify using some of the Microsoft tools. Like I said my guess is that it would be less secure, but I don't really know. I know I have a 10gb, file system limit, so I'm assuming my db would have to share that space.

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  • MySQL vs. SQL Server Go daddy, What is the difference bewteen hosted DB and App_Data Db

    - by Nate Gates
    I'm using Goddady for site hosting, and I'm currently using MySQL, because there are less limits on size,etc. My question is what is the difference between using a hosted Godaddy Db such as MySQL vs. creating a SQL Serverdatabase in the the App_Data folder? My guess is security? Would it be a bad idea to use a SQL ServerDB thats located in the App_Data folder? Additional Well I am able to create a .mdf (SQL Server DB file) in the App_Data folder, but I'm really unsure if should use that or not, If I did use it it would simplify using some of the Microsoft tools. Like I said my guess is that it would be less secure, but I don't really know. I know I have a 10gb, file system limit, so I'm assuming my db would have to share that space.

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  • EPM 11.1.2 - Issues during configuration when using Oracle DB if not using UTF8

    - by Ahmed A
    If you see issues during configuration when using Oracle DB if not using UTF8: Workaround: a. During configuration of EPM products, a warning message is displayed if the Oracle DB is not UTF8 enabled. If you continue with the configuration, certain products will not work as they will not be able to read the contents in the tables as the format is wrong.b. The Oracle DB must be setup to use AL32UTF8 or a superset that contains AL32UTF8. c. The only difference between AL32UTF8 and UTF8 character sets is that AL32UTF8 stores characters beyond U+FFFF as four bytes (exactly as Unicode defines UTF-8). Oracle’s “UTF8” stores these characters as a sequence of two UTF-16 surrogate characters encoded using UTF-8 (or six bytes per character). Besides this storage difference, another difference is better support for supplementary characters in AL32UTF8 character set.

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  • Itty bitty ITTIA DB for Java Embedded Device Development

    - by hinkmond
    Here's a nice 3rd party itty-bitty database, called ITTIA DB, for Java Embedded and Mobile development See: ITTIA DB for Java Embedded Here's a quote: Java applications on mobile devices and other embedded systems can now leverage the robust shared access and data distribution features of ITTIA DB SQL with a new JDBC (Java Database Connectivity) driver released this week. This driver provides significant value for Java developers targeting embedded platforms such as QNX and Linux. Plus, it can exchange data with an Oracle back-end database. That's good if that's what you have on the back-end. Hinkmond

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