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  • object references an unsaved transient instance

    - by developer
    Hi, I have 2 tables, user and userprofile, both with almost identical fields. user table references userprofile table by primary key ID. My requirement is that on click of a button I need to dump user table record to userprofile table. Now for a particular user table, if there is a corresponding userprofile entry, I am successfully able to dump the data, but if there is no record in userprofile table then I need to create a new record by dumping all the data. My problem is that I am able to update the data when the record is present in userprofile table, but in the case wherein I have to create a new record I get the below error "object references an unsaved transient instance - save the transient instance before flushing". `<class name="User"> <id name="ID" type="Int32"> <generator class="native" /> </id> <many-to-one name="Pid" class="UserProfile" /> </class>` UserProfile is another table and Pid above references the Primary key ID of UserProfile table.

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  • Devise password reset issue (new_user?)

    - by rabid_zombie
    When a user's email is inputted into the forgot password form and submitted, I am receiving an error saying login can't be blank. I looked around devise.en.yml for this error message, but can't seem to find it anywhere. Here is my views/devise/passwords/new.html.haml: %div.registration_page %h2 Forgot your password? = form_for(resource, :as => resource_name, :url => user_password_path, :html => { :method => :post, :id => 'forgot_pw_form', :class => 'forgot_pw' }) do |f| %div = f.email_field :email, :placeholder => 'Email', :autofocus => true, :autocomplete => 'off' %div.email_error.error %input.btn.btn-success{:type => 'submit', :value => 'Send Instructions'} = render "devise/shared/links" The form is posting to users/password like it should, but I noticed that my forgot password form attaches class = 'new_user'. Here is what my form displays: <form accept-charset='UTF-8' action='/users/password' class='new_user' id='forgot_pw_form' method='post' novalidate='novalidate'></form> My routes for devise (I have custom sessions and registrations controllers): devise_for :users, :controllers => {:sessions => 'sessions', :registrations => 'registrations'} How can I setup devise's forgot password functionality? Why am I receiving this error message and why is that class being added there? I've tried: Adding my own passwords controller and adding new routes for my custom controller. Same error Adding my own class and id to the form. This successfully changes the id and class of the form, but reverts back to class and id of new_user Thanks.

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  • How to debug python del self.callbacks[s][cid] keyError when the error message does not indicate where in my code the error is

    - by lkloh
    In a python program I am writing, I get an error saying Traceback (most recent call last): File "/Applications/Canopy.app/appdata/canopy-1.4.0.1938.macosx- x86_64/Canopy.app/Contents/lib/python2.7/lib-tk/Tkinter.py", line 1470, in __call__ return self.func(*args) File "/Users/lkloh/Library/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/matplotlib/backends/backend_tkagg.py", line 413, in button_release_event FigureCanvasBase.button_release_event(self, x, y, num, guiEvent=event) File "/Users/lkloh/Library/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/matplotlib/backend_bases.py", line 1808, in button_release_event self.callbacks.process(s, event) File "/Users/lkloh/Library/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/matplotlib/cbook.py", line 525, in process del self.callbacks[s][cid] KeyError: 103 Do you have any idea how I can debug this/ what could be wrong? The error message does not point to anywhere in code I have personally written. I get the error message only after I close my GUI window, but I want to fix it even though it does not break the functionality of my code. The error is part of a very big program I am writing, so I cannot post all my code, but below is code I think is relevant: def save(self, event): self.getSaveAxes() self.save_connect() def getSaveAxes(self): saveFigure = figure(figsize=(8,1)) saveFigure.clf() # size of save buttons rect_saveHeaders = [0.04,0.2,0.2,0.6] rect_saveHeadersFilterParams = [0.28,0.2,0.2,0.6] rect_saveHeadersOverride = [0.52,0.2,0.2,0.6] rect_saveQuit = [0.76,0.2,0.2,0.6] #initalize axes saveAxs = {} saveAxs['saveHeaders'] = saveFigure.add_axes(rect_saveHeaders) saveAxs['saveHeadersFilterParams'] = saveFigure.add_axes(rect_saveHeadersFilterParams) saveAxs['saveHeadersOverride'] = saveFigure.add_axes(rect_saveHeadersOverride) saveAxs['saveQuit'] = saveFigure.add_axes(rect_saveQuit) self.saveAxs = saveAxs self.save_connect() self.saveFigure = saveFigure show() def save_connect(self): #set buttons self.bn_saveHeaders = Button(self.saveAxs['saveHeaders'], 'Save\nHeaders\nOnly') self.bn_saveHeadersFilterParams = Button(self.saveAxs['saveHeadersFilterParams'], 'Save Headers &\n Filter Parameters') self.bn_saveHeadersOverride = Button(self.saveAxs['saveHeadersOverride'], 'Save Headers &\nOverride Data') self.bn_saveQuit = Button(self.saveAxs['saveQuit'], 'Quit') #connect buttons to functions they trigger self.cid_saveHeaders = self.bn_saveHeaders.on_clicked(self.save_headers) self.cid_savedHeadersFilterParams = self.bn_saveHeadersFilterParams.on_clicked(self.save_headers_filterParams) self.cid_saveHeadersOverride = self.bn_saveHeadersOverride.on_clicked(self.save_headers_override) self.cid_saveQuit = self.bn_saveQuit.on_clicked(self.save_quit) def save_quit(self, event): self.save_disconnect() close()

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  • Calculate value from two field in third field

    - by terence6
    I'm trying to create a query, that will calculate sum of products on invoice. I have 3 tables : Product (with product's price) Invoice (with invoice id) Products on invoice (with invoice id, product id and number of particular products) So in my query I take invoice_id (from invoice), price (from product),number of products sold and invoice_id (from products on invoice) and calculate their product in fourth column. I know I sohuld use 'Totals' but how to achieve that ? Model:

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  • Binding the selected value from a combobox to a member of a class.

    - by CM
    I have a combobox that is bound to a an instance of a class. I need to get the user's selection ID of the combobox and set a class property equal to it. For example, here is the class: public class robot { private string _ID; private string _name; private string _configFile; [XmlElement("hardware")] public hardware[] hardware; public string ID { get { return _ID; } set { _ID = value; } } public string name { get { return _name; } set { _name = value; } } public string configFile { get { return _configFile; } set { _configFile = value; } } } Now here is the code to bind the combobox to an instance of that class. This display's the name of each robot in the array in the combobox. private void SetupDevicesComboBox() { robot[] robot = CommConfig.robot; cmbDevices.DataSource = robot; cmbDevices.DisplayMember = "name"; cmbDevices.ValueMember = "ID"; } But now I can't seem to take what the user selects and use it. How do I use the "ID" of what the user select's from the combobox? Settings.selectedRobotID = cmbDevices.ValueMember; //This just generates "ID" regardless of what is selected. I also tried Settings.selectedRobotID = cmbDevices.SelectedItem.ToString(); //This just generates "CommConfig.robot" Thanks

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  • Wildcard App IDs for iPhone/iPod Touch Apps

    - by Can Berk Güder
    I'm writing my third app, and I already have an app in the App Store, but I still don't get this App ID business. I created the App IDs for my first two applications like this: XXXXXXXXXX.me.cbg.FirstApp YYYYYYYYYY.me.cbg.SecondApp but then Apple introduced the App ID wizard, which I used to create the App ID and provisioning profiles for my third application: ZZZZZZZZZZ.* So my question is: What is the "proper" way of creating App IDs for three completely independent apps? Should I use the XXXXXXXXXX.* format or XXXXXXXXXX.me.cbg.*? Should I create three different App IDs, or just one wildcard ID?

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  • How can I differentiate two different touches on a layer ?

    - by srikanth rongali
    I am writing an app in cocos2d. I hava a sprite and a text in my scene. I have written two separate classes for sprite and text. And I added both of them to another class. In sprite class I have written - (void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event And in text class I have written -(void) registerWithTouchDispatcher { [[CCTouchDispatcher sharedDispatcher]addTargetedDelegate:self priority:0 swallowsTouches:YES]; } -(BOOL) ccTouchBegan:(UITouch *)touch withEvent:(UIEvent *)event { return YES; } -(void) ccTouchEnded:(UITouch *)touch withEvent:(UIEvent *)event { NSLog(@"Recognized tOuches in Instructions");// CGSize windowSize = [[CCDirector sharedDirector] winSize]; CCNode *node = [self getChildByTag:kTagNode]; [node setPosition: ccp(text1.contentSize.width/2,text1.contentSize.height/2 - windowSize.height)]; } -(void) ccTouchMoved:(UITouch *)touch withEvent:(UIEvent *)event { CGPoint touchLocation = [touch locationInView: [touch view]]; CGPoint prevLocation = [touch previousLocationInView: [touch view]]; touchLocation = [[CCDirector sharedDirector] convertToGL: touchLocation]; prevLocation = [[CCDirector sharedDirector] convertToGL: prevLocation]; CGPoint diff = ccpSub(touchLocation,prevLocation); CCNode *node = [self getChildByTag:kTagNode]; CGPoint currentPos = [node position]; [node setPosition: ccpAdd(currentPos, diff)]; } But, only touches in the text are recognized and touch of sprite is not recognized ? How can I differentiate the two touches.

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  • How to display icons next to a select1 control with xxforms:tree appearance

    - by user557060
    Hi, I display a list of items via select1 control using xxforms:tree appearance. They are displayed via a code block like: <xforms:itemset nodeset="instance('dataInstance')/*"> <xforms:label ref="fn:concat(./NAME,', ','ID: ',./ID)"/> <xforms:value ref="./ID"/> </xforms:itemset> </xforms:select1> I want to display two icons for each item on the same row as the item: one icon for deleting and one for editing that item, which would all invoke XPL with the item ID as the parameter. The question, how do I render those icons - does itemset support nested trigger elements? If not, how do I go about achieving it (clicking on the item results in an action other than edit or delete, so cannot use that; can show delete/edit on the page shown when user clicks on the item, but want to save that one click if the user just wants to delete the item for example). Thanks.

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  • How to coerce type of ActiveRecord attribute returned by :select phrase on joined table?

    - by tribalvibes
    Having trouble with AR 2.3.5, e.g.: users = User.all( :select => "u.id, c.user_id", :from => "users u, connections c", :conditions => ... ) Returns, e.g.: => [#<User id: 1000>] >> users.first.attributes => {"id"=>1000, "user_id"=>"1000"} Note that AR returns the id of the model searched as numeric but the selected user_id of the joined model as a String, although both are int(11) in the database schema. How could I better form this type of query to select columns of tables backing multiple models and retrieving their natural type rather than String ? Seems like AR is punting on this somewhere. How could I coerce the returned types at AR load time and not have to tack .to_i (etc.) onto every post-hoc access?

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  • ListView exception for Images + Text

    - by drozzy
    I am trying to create a simple Icon+Text ListView but it does not work. I am using 2.1 Android SDK. My main class is very small slightly modified from the tutorial: public class Stuffs extends ListActivity { static final String[] COUNTRIES = new String[] {"A", "B","C"}; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setListAdapter(new ArrayAdapter<String>(this, R.layout.list_item, R.id.title, COUNTRIES)); } } and my list_item.xml file is this: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation = "horizontal"> <ImageView android:id = "@+id/icon" android:src="@drawable/icon" /> <TextView android:id = "@+id/title" android:padding="10dp" android:textSize="16sp" > </TextView> </LinearLayout> I have also created a "drawable" directory in my res directory and copied a "icon.png" into it. But any time I try to run this the application hangs up unexpected in my android emulator. Am I missing something?

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  • Django: Why Doesn't the Current URL Match any Patterns in urls.py

    - by austin_sherron
    I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

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  • Does SQL Server guarantee sequential inserting of an identity column?

    - by balpha
    In other words, is the following "cursoring" approach guaranteed to work: retrieve rows from DB save the largest ID from the returned records for later, e.g. in LastMax later, "SELECT * FROM MyTable WHERE Id > {0}", LastMax In order for that to work, I have to be sure that every row I didn't get in step 1 has an Id greater than LastMax. Is this guaranteed, or can I run into weird race conditions?

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  • Find gap between start and end dates for multiple data ranges with overlaps

    - by sqlint
    Need to find gap between start and end dates more than 20 days for multiple data ranges with overlaps. One Id has multiple start dates and end dates. Following Id 1 has two gaps less that 20 day. It should be considered as one range from 10/01/2012 to 10/30/2014 without any gap. 1 10/01/2012 02/01/2013 1 01/01/2013 01/31/2013 1 02/10/2013 03/31/2013 1 04/15/2013 10/30/2014 Id 2 has a gap more than 20 days between end date 01/30/2013 and start date 05/01/2013. It has to be captured. 2 01/01/2013 01/30/2013 2 05/01/2013 06/30/2014 2 07/01/2013 02/01/2014 Id 3 should be considered as one range from 01/01/2012 to 06/01/2014 without any gap. The gap between end date 02/28/2013 and start date 07/01/2013 should be ignored because range from 01/01/2012 to 01/01/2014 cavers a gap. 3 01/01/2012 01/01/2014 3 01/01/2013 02/28/2013 3 07/01/2013 06/01/2014 The cursor can do it but it works extremely slow and not acceptable. SQL fiddle http://sqlfiddle.com/#!3/27e3f/2/0

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  • Mysql - GROUP BY Avoid using tempoary

    - by jwzk
    The goal of this query is to get a total of unique records (by IP) per ref ID. SELECT COUNT(DISTINCT ip), GROUP_CONCAT(ref.id) FROM `sess` sess JOIN `ref` USING(row_id) WHERE sess.time BETWEEN '2010-04-21 00:00:00' AND '2010-04-21 23:59:59' GROUP BY ref.id ORDER BY sess.time DESC The query works fine, but its using a temporary table. Any ideas?

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  • is it safe to refactor my django models?

    - by Johnd
    My model is similar to this. Is this ok or should I make the common base class abstract? What are the differcenes between this or makeing it abstract and not having an extra table? It seems odd that there is only one primary key now that I have factored stuff out. class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) pub_date = models.DateTimeField('date published') rating = models.IntegerField() def __unicode__(self): return self.details class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() is this ok to factor stuff out intpu Input? I noticed Cases and Arguments share a primary Key. like this: CREATE TABLE "cases_input" ( "id" integer NOT NULL PRIMARY KEY, "details" varchar(1000) NOT NULL, "user_id" integer NOT NULL REFERENCES "auth_user" ("id"), "pub_date" datetime NOT NULL, "rating" integer NOT NULL ) ; CREATE TABLE "cases_case" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "title" varchar(200) NOT NULL, "views" integer NOT NULL ) ; CREATE TABLE "cases_argument" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "case_id" integer NOT NULL REFERENCES "cases_case" ("input_ptr_id"), "side" bool NOT NULL )

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  • How do I create links in the cells of a PHP generated table?

    - by typoknig
    I have a table generated from some PHP code that lists a SMALL amount of important information for employees. I want to make it so each row, or at least one element in each row can be clicked on so the user will be redirected to ALL of the information (pulled from MySQL database) related to the employee who was clicked on. I am not sure how would be the best way to go about this, but I am open to suggestions. I would like to stick to PHP and/or JavaScript. Below is the code for my table: <table> <tr> <td id="content_heading" width="25px">ID</td> <td id="content_heading" width="150px">Last Name</td> <td id="content_heading" width="150px">First Name</td> <td id="content_heading" width="75px">SSN</td> </tr> <?php $user = 'user'; $pass = 'pass'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link){ die('Could not connect to database!' . mysql_error()); } mysql_select_db('mydb', $link); $query = "SELECT * FROM employees"; $result = mysql_query($query); mysql_close($link); $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr class=".$class.">"; echo "<td>".$row[id]."</td>"; echo "<td>".$row[l_name]."</td>"; echo "<td>".$row[f_name]."</td>"; echo "<td>".$row[ssn]."</td>"; echo "</tr>"; } ?> </table>

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  • If-statement: how to pull 2nd GET variable

    - by arsoneffect
    How do I get this to pull my 2nd variable? (I already have a switch setup) <body id="<?php if (! isset($_GET['page'])) { echo "home"; } else { $_GET['page']; echo $page; } ?>"> I have a switch statement that pulls the pages from index.php?page=##### and I have just added this part to my switch: index.php?page=####&section=##### Right now, if I am on page=photos, my code ends up being: <body id="photos"> I need to make it so that if any link has the "sections" variable on it like this page=photos&section=cars it uses the same ID: <body id="photos">

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  • How to set a predefined value in a form in Rails

    - by marco
    So I just got started in Rails, and I'm trying to create an Object (a book_loan in my case) with a Form. The thing is that I get to this form by clicking on a book, so I pass the book_id as a parameter, like localhost:3000/loans/new?id=1. Now I don't want the user to be able to set the book id field in the form, since I already know the id. So my question is how to set the value in the form. I have been trying things like: <% form_for(@loan) do |f| %> <%= f.error_messages %> ... <%= @loan.book_id = params[:id] %> <%= f.submit 'Create' %> <% end %> without any success. Does anybody have a hint for me?

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  • How to facebook getuser() after login with javascript SDK

    - by user1848205
    So I have to ask for extended permission by clicking the enter button, but after the login is necessary to refresh the page in order to display the app. Here's my code: <?php require 'facebook.php'; $facebook = new Facebook(array( 'appId' => '< THE APPID >', 'secret' => '< THE SECRET >', 'cookie' => true, )); $user = $facebook->getUser(); if ($user) { try { $user_profile = $facebook->api('/me'); } catch (FacebookApiException $e) { error_log($e); $user = null; } } ?> <body> <div id="fb-root"></div> <script> window.fbAsyncInit = function() { FB.init({ appId : '< THE APPID >', status : true, cookie : true, xfbml : true }); // Additional initialization code such as adding Event Listeners goes here $('#btn-enter').click(function(){ login(); }); }; (function(d){ var js, id = 'facebook-jssdk', ref = d.getElementsByTagName('script')[0]; if (d.getElementById(id)) {return;} js = d.createElement('script'); js.id = id; js.async = true; js.src = "//connect.facebook.net/en_US/all.js"; ref.parentNode.insertBefore(js, ref); }(document)); function login() { FB.login(function(response) { if (response.authResponse) { // connected } else { // cancelled } //}); }, {scope: 'read_friendlists,friends_photos,publish_stream'}); } </script> <?php if ($user): ?> <!--Here is my APP--> <?php else: ?> <a id="btn-enter">Enter</a> <?php endif ?> Is there a better way to do this ? What works for me is: function login() { FB.login(function(response) { if (response.authResponse) { top.location.href='https://the_app_url'; } else { } //}); }, {scope: 'read_friendlists,friends_photos,publish_stream'}); } But this causes the entire page to refresh and is not 'elegant' per se...

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  • How do I bind functions to all input elements using jQuery?

    - by bakkelun
    Hi, let's say I have this set of HTML-markup and CSS #CSS .inputhelp_text { background: #000; color: #fff; } .nodisplay { display: none; } <input class="inputhelp" id="firstname" /><span class="inputhelp_text nodisplay" id="help_firstname">Write in your firstname</span> <input class="inputhelp" id="lastname" /><span class="inputhelp_text nodisplay" id="help_lastname">Write in your lastname</span> Using jQuery, I need to bind a function to all input fields (I guess using jQuery's EACH function) so that when I click the input field, it should switch the class of each span to only "inputhelp_text". I've gotten this to work in two separate functions for each field, but since I have alot of fields, I know there's a better way to solve it. Any suggestions?

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  • How to drag only one image with SDK Iphone

    - by loka
    Hi! I want to create a little app that takes two images and i want to make only the image over draggable. After research, i found this solution : -(void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [[ event allTouches] anyObject]; image.alpha = 0.7; if([touch view] == image){ CGPoint location = [touch locationInView:self.view]; image.center = location; } It works but the problem is that the image is draggable from its center and i don't want that. So i found another solution : - (void) touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event { // Retrieve the touch point CGPoint pt = [[touches anyObject] locationInView:self.view]; startLocation = pt; [[self view] bringSubviewToFront:self.view]; } - (void) touchesMoved:(NSSet*)touches withEvent:(UIEvent*)event { // Move relative to the original touch point CGPoint pt = [[touches anyObject] locationInView:self.view]; frame = [self.view frame]; frame.origin.x += pt.x - startLocation.x; frame.origin.y += pt.y - startLocation.y; [self.view setFrame:frame]; } It works very well but when i add another image, all the images of the view are draggable at the same time.I'm a beginner with the iphone programmation and i have no idea of how i can only make the image over draggable. Thank you in advance for your help!!

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  • why doesnt' nhibernate support this "exists in list" syntax ??

    - by ooo
    i have the following query and its failing in Nhibernate 3 LINQ witha a "Non supported" exception. Its similar to this question but this question was asked over a year ago so i am positive that the answer is out of date. My DB tables are: VacationRequest (id, personId) VacationRequestDate (id, vacationRequestId) Person (id, FirstName, LastName) My Entities are: VacationRequest (Person, IList) VacationRequestDate (VacationRequest, Date) Here is the query that is getting a "Non supported" Exception Session.Query<VacationRequestDate>() .Where(r => people .Contains(r.VacationRequest.Person, new PersonComparer())) .Fetch(r=>r.VacationRequest) .ToList(); is there a better way to write this that would be supported in Nhibernate? fyi . .the PersonComparer just compared person.Id

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  • CSS list menu; extra padding on rollover of buttons

    - by user1669878
    I have been going crazy trying to figure out why there is extra padding showing up on my navigation buttons when I rollover them. It's only showing up to the left and right of them though. Here's a link to the screenshot of what it looks like: http://i179.photobucket.com/albums/w319/jdauel/Screenshot2012-09-13at25417PM.png I think it has something to do with my CSS but I have no idea anymore. Please help me??? I tried using Firebug to figure it out with no prevail. Here's the code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Farren's Photography</title> <style type="text/css"> html { height: 100%; width: 100%; } body { margin: 0px; } #container { font-family: Georgia, "Times New Roman", Times, serif; font-size: 1.2em; color: #000; background-color: #06F; text-align: left; padding: 0px; height: 650px; width: 960px; margin-right: auto; margin-left: auto; background-image: url(images/background_image.png); background-repeat: no-repeat; margin-top: 45px; } a:link { color: #FFF; } a:visited { color: #FFF; } a:hover { color: #FFF; } #container #logo { } #container #logo #fp-logo { background-image: url(images/logo.png); height: 137px; width: 408px; text-indent: -9999px; display: block; } #logo { height: 137px; width: 408px; position: relative; padding-top: 35px; padding-right: 0px; padding-bottom: 0px; padding-left: 35px; } #main { background-color: #FFF; min-height: 383px; width: 707px; position: relative; left: 217px; top: 16px; right: 36px; bottom: 113px; } #container #navbar { font-family: Georgia, "Times New Roman", Times, serif; font-size: 14px; color: #FFF; text-align: right; height: 45px; background-color: #CC0000; position: relative; top: 8px; bottom: 0px; left: 0px; right: 0px; } #container #navbar ul li a { text-decoration: none; } #container #navbar ul { list-style-type: none; padding-top: 16px; } #container #navbar ul li { display: inline; background-color: #280803; margin: 0px; height: 0px; width: 0px; position: relative; padding-top: 16px; padding-right: 15px; padding-bottom: 17px; padding-left: 15px; } #container #navbar ul li a:link { text-decoration: none; color: #FFF; } #container #navbar ul li a:visited { text-decoration: none; color: #FFF; } #container #navbar ul li a:hover { text-decoration: none; color: #FFF; background-color: #027e8e; padding-top: 16px; padding-right: 15px; padding-bottom: 17px; padding-left: 15px; margin: 0px; } #footer { font-family: Arial, Helvetica, sans-serif; font-size: x-small; height: 28px; position: relative; top: 8px; color: #FFF; font-style: italic; } </style> </head> <body> <div id="container"> <div id="logo"><a href="http://www.farrensphotography.com" title="Farren's Photography" target="_self" id="fp-logo">Farren's Photography</a></div><!-- end logo --> <div id="main"> <div id="content"> </div><!-- end content --> </div><!-- end main --> <div id="navbar"> <ul> <li><a href="index.html" target="_self">Home</a></li> <li><a href="portfolio.html" target="_self">Portfolio</a></li> <li><a href="mystyle.html" target="_self">My Style</a></li> <li><a href="specials.html" target="_self">Specials</a></li> <li><a href="pricing.html" target="_self">Pricing</a></li> <li><a href="contact.html" target="_self">Contact</a></li> </ul> </div> <!-- end navbar --> <div id="footer"> <div id="copyright">All images copyright© Farrens Photography </div><!-- end copyright --> <div id="network">Facebook button </div><!-- end network --> </div><!-- end footer --> </div><!-- end container --> </body> </html>

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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