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  • Django - Expression based model constraints

    - by rtmie
    Is it possible to set an expression based constraint on a django model object, e.g. If I want to impose a constraint where an owner can have only one widget of a given type that is not in an expired state, but can have as many others as long as they are expired. Obviously I can do this by overriding the save method, but I am wondering if it can be done by setting constraints, e.g. some derivative of the unique_together constraint WIDGET_STATE_CHOICES = ( ('NEW', 'NEW'), ('ACTIVE', 'ACTIVE'), ('EXPIRED', 'EXPIRED') ) class MyWidget(models.Model): owner = models.CharField(max_length=64) widget_type = models.CharField(max_length = 10) widget_state = models.CharField(max_length = 10, choices = WIDGET_STATE_CHOICES) #I'd like to be able to do something like class Meta: unique_together = (("owner","widget_type","widget_state" != 'EXPIRED')

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  • Finding a Eulerian Tour

    - by user590903
    I am trying to solve a problem on Udacity described as follows: # Find Eulerian Tour # # Write a function that takes in a graph # represented as a list of tuples # and return a list of nodes that # you would follow on an Eulerian Tour # # For example, if the input graph was # [(1, 2), (2, 3), (3, 1)] # A possible Eulerian tour would be [1, 2, 3, 1] I came up with the following solution, which, while not as elegant as some of the recursive algorithms, does seem to work within my test case. def find_eulerian_tour(graph): tour = [] start_vertex = graph[0][0] tour.append(start_vertex) while len(graph) > 0: current_vertex = tour[len(tour) - 1] for edge in graph: if current_vertex in edge: if edge[0] == current_vertex: current_vertex = edge[1] else: current_vertex = edge[0] graph.remove(edge) tour.append(current_vertex) break return tour graph = [(1, 2), (2, 3), (3, 1)] print find_eulerian_tour(graph) >> [1, 2, 3, 1] However, when submitting this, I get rejected by the grader. I am doing something wrong? I can't see any errors.

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  • How to use ';' in urls, using Google Appengine

    - by tonfa
    Using the local dev server, I can use ';' in urls, but as soon as I try the live version hosted by Google, it looks like the ';' and everything afterward is stripped (at least according to request.path_qs). (I would prefer not to encode them if possible, it's much less user friendly if the url cannot be constructed by copy-pasting, especially since other characters works fine, e.g. ':').

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  • How to access the calling source line from interactive shell

    - by TJD
    I want to make a function that can determine the source code of how it was called. I'm aware of how to do this generally with the inspect module. For example, this question, works well and provides my desired output in the lines variable as shown below: def hello(x): frame,filename,line_number,function_name,lines,index=\ inspect.getouterframes(inspect.currentframe())[1] print(frame,filename,line_number,function_name,lines,index) The problem is that this solution doesn't work in an interactive command line session. For example, from a command line, the result looks like: >>> y = hello(7) (<frame object at 0x01ECA9E8>, '<stdin>', 1, '<module>', None, None) The problem is that the source file is '<stdin>', so the lines variable is None. How can I access the calling line to find the result containing the string y = hello(7) during an interactive session?

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  • Using adaptive step sizes with scipy.integrate.ode

    - by Mike
    The (brief) documentation for scipy.integrate.ode says that two methods (dopri5 and dop853) have stepsize control and dense output. Looking at the examples and the code itself, I can only see a very simple way to get output from an integrator. Namely, it looks like you just step the integrator forward by some fixed dt, get the function value(s) at that time, and repeat. My problem has pretty variable timescales, so I'd like to just get the values at whatever time steps it needs to evaluate to achieve the required tolerances. That is, early on, things are changing slowly, so the output time steps can be big. But as things get interesting, the output time steps have to be smaller. I don't actually want dense output at equal intervals, I just want the time steps the adaptive function uses.

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  • Using classes for the first time,help in debugging

    - by kaushik
    here is post my code:this is no the entire code but enough to explain my doubt.please discard any code line which u find irrelavent enter code here saving_tree={} isLeaf=False class tree: global saving_tree rootNode=None lispTree=None def __init__(self,x): file=x string=file.readlines() #print string self.lispTree=S_expression(string) self.rootNode=BinaryDecisionNode(0,'Root',self.lispTree) class BinaryDecisionNode: global saving_tree def __init__(self,ind,name,lispTree,parent=None): self.parent=parent nodes=lispTree.getNodes(ind) print nodes self.isLeaf=(nodes[0]==1) nodes=nodes[1]#Nodes are stored self.name=name self.children=[] if self.isLeaf: #Leaf Node print nodes #Set the leaf data self.attribute=nodes print "LeafNode is ",nodes else: #Set the question self.attribute=lispTree.getString(nodes[0]) self.attribute=self.attribute.split() print "Question: ",self.attribute,self.name tree={} tree={str(self.name):self.attribute} saving_tree=tree #Add the children for i in range(1,len(nodes)):#Since node 0 is a question # print "Adding child ",nodes[i]," who has ",len(nodes)-1," siblings" self.children.append(BinaryDecisionNode(nodes[i],self.name+str(i),lispTree,self)) print saving_tree i wanted to save some data in saving_tree{},which i have declared previously and want to use that saving tree in the another function outside the class.when i asked to print saving_tree it printing but,only for that instance.i want the saving_tree{} to have the data to store data of all instance and access it outside. when i asked for print saving_tree outside the class it prints empty{}.. please tell me the required modification to get my required output and use saving_tree{} outside the class..

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  • Updating a module level shared dictionary

    - by Vishal
    Hi, A module level dictionary 'd' and is accessed by different threads/requests in a django web application. I need to update 'd' every minute with a new data and the process takes about 5 seconds. What could be best solution where I want the users to get either the old value or the new value of d and nothing in between. I can think of a solution where a temp dictionary is constructed with a new data and assigned to 'd' but not sure how this works! Appreciate your ideas. Thanks

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  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

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  • How would I make this faster? Parsing Word/sorting by heading [on hold]

    - by Doof12
    Currently it takes about 3 minutes to run through a single 53 page word document. Hopefully you all have some advice about speeding up the process. Code: import win32com.client as win32 from glob import glob import io import re from collections import namedtuple from collections import defaultdict import pprint raw_files = glob('*.docx') word = win32.gencache.EnsureDispatch('Word.Application') word.Visible = False oFile = io.open("rawsort.txt", "w+", encoding = "utf-8")#text dump doccat= list() for f in raw_files: word.Documents.Open(f) doc = word.ActiveDocument #whichever document is active at the time doc.ConvertNumbersToText() print doc.Paragraphs.Count for x in xrange(1, doc.Paragraphs.Count+1):#for loop to print through paragraphs oText = doc.Paragraphs(x) if not oText.Range.Tables.Count >0 : results = re.match('(?P<number>(([1-3]*[A-D]*[0-9]*)(.[1-3]*[0-9])+))', oText.Range.Text) stylematch = re.match('Heading \d', oText.Style.NameLocal) if results!= None and oText.Style != None and stylematch != None: doccat.append((oText.Style.NameLocal, oText.Range.Text[:len(results.group('number'))],oText.Range.Text[len(results.group('number')):])) style = oText.Style.NameLocal else: if oText.Range.Font.Bold == True : doccat.append(style, oText) oFile.write(unicode(doccat)) oFile.close() The for Paragraph loop obviously takes the most amount of time. Is there some way of identifying and appending it without going through every Paragraph?

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  • Actual SQL statement after bind variables specified

    - by bioffe
    I am trying to log every SQL statement executed from my scripts. However I contemplate one problem I can not overcome. Is there a way to compute actual SQL statement after bind variables were specified. In SQLite I had to compute the statement to be executed manually, using code below: def __sql_to_str__(self, value,args): for p in args: if type(p) is IntType or p is None: value = value.replace("?", str(p) ,1) else: value = value.replace("?",'\'' + p + '\'',1) return value It seems CX_Oracle has cursor.parse() facilities. But I can't figure out how to trick CX_Oracle to compute my query before its execution.

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  • How to save to two tables using one SQLAlchemy model

    - by Oatman
    I have an SQLAlchemy ORM class, linked to MySQL, which works great at saving the data I need down to the underlying table. However, I would like to also save the identical data to a second archive table. Here's some psudocode to try and explain what I mean my_data = Data() #An ORM Class my_data.name = "foo" #This saves just to the 'data' table session.add(my_data) #This will save it to the identical 'backup_data' table my_data_archive = my_data my_data_archive.__tablename__ = 'backup_data' session.add(my_data_archive) #And commits them both session.commit() Just a heads up, I am not interested in mapping a class to a JOIN, as in: http://www.sqlalchemy.org/docs/05/mappers.html#mapping-a-class-against-multiple-tables

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  • rearranging a list of months

    - by MacUsers
    How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here?

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  • django-avatar: cant save thumbnail

    - by Znack
    I'm use django-avatar app and can't make it to save thumbnails. The original image save normally in my media dir. Using the step execution showed that error occurred here image.save(thumb, settings.AVATAR_THUMB_FORMAT, quality=quality) I found this line in create_thumbnail: def create_thumbnail(self, size, quality=None): # invalidate the cache of the thumbnail with the given size first invalidate_cache(self.user, size) try: orig = self.avatar.storage.open(self.avatar.name, 'rb') image = Image.open(orig) quality = quality or settings.AVATAR_THUMB_QUALITY w, h = image.size if w != size or h != size: if w > h: diff = int((w - h) / 2) image = image.crop((diff, 0, w - diff, h)) else: diff = int((h - w) / 2) image = image.crop((0, diff, w, h - diff)) if image.mode != "RGB": image = image.convert("RGB") image = image.resize((size, size), settings.AVATAR_RESIZE_METHOD) thumb = six.BytesIO() image.save(thumb, settings.AVATAR_THUMB_FORMAT, quality=quality) thumb_file = ContentFile(thumb.getvalue()) else: thumb_file = File(orig) thumb = self.avatar.storage.save(self.avatar_name(size), thumb_file) except IOError: return # What should we do here? Render a "sorry, didn't work" img? maybe all I need is just some library? Thanks

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  • Problem with validating ModelForm

    - by user561640
    I use ModelForm to create my form. All works fine except 1 thing - validating the unique field. Code: class Article(models.Model): ... title = models.CharField(max_length=255, unique=True, error_messages={'max_length' : 'max translation', 'unique' : 'unique translation', 'required' : 'req translation',}) ... class ArticleForm(ModelForm): ... title = forms.CharField(max_length=255, min_length=3, error_messages={'required' : 'req translation', 'min_length' : 'min translation', 'max_length' : 'max translation', 'unique' : 'unique translation',}) But when I save my form with non-unique title I don't get my custom translated error but I get default error. How to fix it, that my unique field error is displayed?

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