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  • MySQL query with JOINS and GROUP BY

    - by user1854049
    I'm building a MySQL query but I can't seem to get it right. I have four tables: - customers - orders - sales_rates - purchase_rates There is a 1:n relation 'customernr' between customers and orders. There is a 1:n relation 'ordernr' between orders and sales_rates. There is a 1:n relation 'ordernr' between orders and purchase_rates. What I would like to do is produce an output of all customers with their total purchase and sales amounts. So far I have the following query. SELECT c.customernr, c.customer_name, SUM(sr.sales_price) AS sales_price, SUM(pr.purchase_price) AS purchase_price FROM orders o, customers c, sales_rates sr, purchase_rates pr WHERE o.customernr = c.customernr AND o.ordernr = sr.ordernr AND o.ordernr = pr.ordernr GROUP BY k.bedrijfsnaam The result of the sales_price and purchase_price is far too high. I seem to be getting double counts. What am I doing wrong? Is it possible to perform this in a single query? Thank for your response!

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  • sql query help join (i think)

    - by milan
    I am having trouble figuring our how I can get results only when products.published, product_types.published, and product_cats.published = 1 but my query isn't working. Please help: SELECT `products`.`title`, `products`.`menu_id`, `products`.`short_description`, `products`.`datasheet_icon`, `products`.`datasheet`, `products`.`ordering`, `products`.`product_type_id`, CASE WHEN CHAR_LENGTH(`products`.`alias`) THEN CONCAT_WS(':', `products`.`id`, `products`.`alias`) ELSE `products`.`id` END AS slug FROM `products`, `product_cats`, `product_types` WHERE `products`.published=1 AND `product_cats`.published=1 AND `product_types`.published=1 AND `products`.`product_cat_id`='42' AND `product_types`.`id` IN (1,40,48,49,50) GROUP BY `products`.`id` ORDER BY `product_types`.`ordering`, `products`.`ordering`

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  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

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  • Join two results sets to make one result set in T-SQL

    - by Michael Kniskern
    What would be the best approach to combine the two results sets in one result set in T-SQL? SQL statment #1: SELECT COUNT(t.col1) as 'Number of Responses', t.col2 as 'Department' FROM table t WHERE col3 IS NOT NULL GROUP BY t.col1 ORDER BY t.col1 SQL Statment #1: SELECT COUNT(t.col1) as 'Total number of participants', t.col2 as 'Department' FROM table t GROUP BY t.col1 ORDER by t.col1 Desired result set Number of Responses | Total Number of participants | Department

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  • Activerecord join search

    - by VP
    Hi, i have two models: class Category has many :jobs end class Job belongs_to :category end So for sure i'm able to do c = Category.first c.jobs My question is: how can i find just categories that has at least one job?

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  • How do I get a right outer join in L2E?

    - by Dan
    I have two tables that I set up through the VS Entity Data Model Diagram tool. I'm trying to do a right outer join and it doesn't return results from the 2nd table. I have set up a 0..1 to MANY relationship from the diagram tool. When I run a Linq-To-Entities query, it still defaults to an INNER JOIN. From my understanding of entities, if I set up the relationship using VS, when I join the tables, it should automagically figure out the join syntax based on the relationship I supply. It doesn't seem to be doing that. I am using EF v1 (not Linq-to-Sql). Query I'm running: from s in SomeTable join t in SomeOtherTable on s.ID equals t.ID select new { s.MyFieldName, t.MyOtherFieldName }

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  • How to convert full outer join query to O-R query?

    - by Kugel
    I'm converting relational database into object-relational in Oracle. I have a query that uses full outer join in the old one. Is it possible to write the same query for O-R database without explicitly using full outer join? For normal inner join it simple, I just use dot notation together with ref/deref. I'm interested in this in general so let's say the relational query is: select a.attr, b.attr from a full outer join b on (a.fk = b.pk); I want to know if it's a good idea to do it this way: select a.attr, b.attr from a_obj a full outer join b_obj b on (a.b_ref = ref(b));

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  • SQL JOIN with two or more tables as output - most efficient way?

    - by littlegreen
    I have an SQL query that executes a LEFT JOIN on another table, then outputs all results that could be coupled into a designated table. I then have a second SQL query that executes the LEFT JOIN again, then outputs the results that could not be coupled to a designated table. In code, this is something like: INSERT INTO coupledrecords SELECT b.col1, b.col2... s.col1, s.col2... FROM bigtable AS b LEFT JOIN smallertable AS s ON criterium WHERE s.col1 IS NOT NULL INSERT INTO notcoupledrecords SELECT b.col1, b.col2... bigtable AS b LEFT JOIN smallertable AS s ON criterium WHERE s.col1 IS NULL My question: I now have to execute the JOIN two times, in order to achieve what I want. I have a feeling that this is twice as slow as it could be. Is this true, and if yes, is there a way to do it more efficiently?

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  • JavaScript: String Concatenation slow performance? Array.join('')?

    - by NickNick
    I've read that if I have a for loop, I should not use string concation because it's slow. Such as: for (i=0;i<10000000;i++) { str += 'a'; } And instead, I should use Array.join(), since it's much faster: var tmp = []; for (i=0;i<10000000;i++) { tmp.push('a'); } var str = tmp.join(''); However, I have also read that string concatention is ONLY a problem for Internet Explorer and that browsers such as Safari/Chrome, which use Webkit, actually perform FASTER is using string concatention than Array.join(). I've attempting to find a performance comparison between all major browser of string concatenation vs Array.join() and haven't been able to find one. As such, what is faster and more efficient JavaScript code? Using string concatenation or Array.join()?

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  • Problems compiling peazip on OSX

    - by Yansky
    I'm having some problems with compiling Peazip on OSX (10.6). I emailed the Peazip developer and he said he probably couldn't help me too much as the error seems to be OSX specific and he doesn't have access to an OSX machine any more. The compiler I'm using is Lazarus as the source is in Pascal. The actual compile process seems to go ok, but when I run the peazip.app program launcher, I get the following error: http://img.photobucket.com/albums/v215/thegooddale/Screen-shot-2010-05-22-at-71907-PM.png Here is the app launcher that the compile made: http://forboden.com/coding/peazip.app.zip - you can use an unzip program to look at the files inside (i.e. unzip it twice). I also tried just running the peazip unix file executable that was produced after the compile from the terminal and I got this: http://img.photobucket.com/albums/v215/thegooddale/Screen-shot-2010-05-22-at-72148-PM.png Here are the messages from the compile log from Lazarus while compiling Peazip: http://pastebin.com/qK4bdncL (I asked on the Lazarus forums and they said I can just ignore those "ld: warning: unknown stabs type" warnings). Here is the info from the project_peach.compiled file: <?xml version="1.0"?> <CONFIG> <Compiler Value="/usr/local/bin/ppc386" Date="1238949773"/> <Params Value=" -MObjFPC -Sgi -O1 -gl -k-framework -kCarbon -k-framework -kOpenGL -k'-dylib_file' -k'/System/Library/Frameworks/OpenGL.framework/Versions/A/Libraries/libGL.dylib:/System/Library/Frameworks/OpenGL.framework/Versions/A/Libraries/libGL.dylib' -WG -vewnhi -l -Fu/Users/yansky/Desktop/peazip-3.1.src/res/themes/crystalc/ -Fu/Developer/lazarus/components/synedit/units/i386-darwin/ -Fu/Developer/lazarus/ideintf/units/i386-darwin/ -Fu/Developer/lazarus/lcl/units/i386-darwin/ -Fu/Developer/lazarus/lcl/units/i386-darwin/carbon/ -Fu/Developer/lazarus/packager/units/i386-darwin/ -Fu/Users/yansky/Desktop/peazip-3.1.src/ -Fu. -opeazip -dLCL -dLCLcarbon project_peach.lpr"/> </CONFIG> I guess there's little chance that anyone here has experience with Pascal and Lazarus since it's not that popular a language and the compiler is still in beta, but I thought I would post here in the hopes that someone might point me in the right general direction about where/how the peazip.app launcher is breaking.

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  • MySQL create stored procedure fails but all internal queries succeed alone?

    - by Mark
    Hi all, I just created a simple database in MySQL, and I am learning how to write stored proc's. I'm familiar with M$SQL and as far as I can see the following should work: use mydb; -- -------------------------------------------------------------------------------- -- Routine DDL -- -------------------------------------------------------------------------------- DELIMITER // CREATE PROCEDURE mydb.doStats () BEGIN CREATE TABLE IF NOT EXISTS resultprobability ( ballNumber INT NOT NULL , probability FLOAT NULL, PRIMARY KEY (ballNumber) ); CREATE TABLE IF NOT EXISTS drawProbability ( drawDate DATE NOT NULL , ball1 INT NULL , ball2 INT NULL , ball3 INT NULL , ball4 INT NULL , ball5 INT NULL , ball6 INT NULL , ball7 INT NULL , score FLOAT NULL , PRIMARY KEY (drawDate) ); TRUNCATE TABLE resultprobability; TRUNCATE TABLE drawprobability; INSERT INTO resultprobability (ballNumber, probability) (select resultset.ballNumber ballNumber,(count(0)/(select count(0) from resultset)) probability from resultset group by resultset.ballNumber); INSERT INTO drawProbability (drawDate, ball1, ball2, ball3, ball4, ball5, ball6, ball7, score) (select distinct r.drawDate, a.ballnumber ball1, b.ballnumber ball2, c.ballnumber ball3, d.ballnumber ball4, e.ballnumber ball5, f.ballnumber ball6,g.ballnumber ball7, ((a.probability + b.probability + c.probability + d.probability + e.probability + f.probability + g.probability)/7) score from resultset r inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 1) a on a.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 2) b on b.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 3) c on c.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 4) d on d.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 5) e on e.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 6) f on f.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 7) g on g.drawdate = r.drawDate order by score desc); END // DELIMITER ; instead i get the following Executed successfully in 0.002 s, 0 rows affected. Line 1, column 1 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 26 Line 6, column 1 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')) probability from resultset group by resultset.ballNumber); INSERT INTO d' at line 1 Line 31, column 51 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') score from resultset r inner join (select r.drawDate, r.ballNumber, p.probabi' at line 1 Line 39, column 114 Execution finished after 0.002 s, 3 error(s) occurred. What am I doing wrong? I seem to have exhausted my limited mental abilities!

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  • Why does Python's math.factorial not play nice with threads?

    - by W1N9Zr0
    Why does math.factorial act so weird in a thread? Here is an example, it creates three threads: thread that just sleeps for a while thread that increments an int for a while thread that does math.factorial on a large number. It calls start on the threads, then join with a timeout The sleep and spin threads work as expected and return from start right away, and then sit in the join for the timeout. The factorial thread on the other hand does not return from start until it runs to the end! import sys from threading import Thread from time import sleep, time from math import factorial # Helper class that stores a start time to compare to class timed_thread(Thread): def __init__(self, time_start): Thread.__init__(self) self.time_start = time_start # Thread that just executes sleep() class sleep_thread(timed_thread): def run(self): sleep(15) print "st DONE:\t%f" % (time() - time_start) # Thread that increments a number for a while class spin_thread(timed_thread): def run(self): x = 1 while x < 120000000: x += 1 print "sp DONE:\t%f" % (time() - time_start) # Thread that calls math.factorial with a large number class factorial_thread(timed_thread): def run(self): factorial(50000) print "ft DONE:\t%f" % (time() - time_start) # the tests print print "sleep_thread test" time_start = time() st = sleep_thread(time_start) st.start() print "st.start:\t%f" % (time() - time_start) st.join(2) print "st.join:\t%f" % (time() - time_start) print "sleep alive:\t%r" % st.isAlive() print print "spin_thread test" time_start = time() sp = spin_thread(time_start) sp.start() print "sp.start:\t%f" % (time() - time_start) sp.join(2) print "sp.join:\t%f" % (time() - time_start) print "sp alive:\t%r" % sp.isAlive() print print "factorial_thread test" time_start = time() ft = factorial_thread(time_start) ft.start() print "ft.start:\t%f" % (time() - time_start) ft.join(2) print "ft.join:\t%f" % (time() - time_start) print "ft alive:\t%r" % ft.isAlive() And here is the output on Python 2.6.5 on CentOS x64: sleep_thread test st.start: 0.000675 st.join: 2.006963 sleep alive: True spin_thread test sp.start: 0.000595 sp.join: 2.010066 sp alive: True factorial_thread test ft DONE: 4.475453 ft.start: 4.475589 ft.join: 4.475615 ft alive: False st DONE: 10.994519 sp DONE: 12.054668 I've tried this on python 2.6.5 on CentOS x64, 2.7.2 on Windows x86 and the factorial thread does not return from start on either of them until the thread is done executing. I've also tried this with PyPy 1.8.0 on Windows x86, and there result is slightly different. The start does return immediately, but then the join doesn't time out! sleep_thread test st.start: 0.001000 st.join: 2.001000 sleep alive: True spin_thread test sp.start: 0.000000 sp DONE: 0.197000 sp.join: 0.236000 sp alive: False factorial_thread test ft.start: 0.032000 ft DONE: 9.011000 ft.join: 9.012000 ft alive: False st DONE: 12.763000

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  • problem with "select new Object ... join ... where"

    - by jacob
    Hi, I'm having a problem with an HQL query Three classes ClassOne is my BusinessObject public class ClassOne { private int id; private int status; private Set<ClassTwo> classTwos; + other fields/getters/setters/constructor etc } ClassTwo is referenced in a set of ClassOne and is kind of the history of an object of ClassOne public class ClassTwo { private int id; private int oldStatus; private int newStatus; private String message; //+ getters/setters/constructor etc } ClassThree is my DTO/VO with just one classTwo (not the whole history) public class ClassThree { private int id; private int status; private ClassTwo classTwo; public ClassThree(int pId, int pStatus, ClassTwo pClassTwo) { id=pId; status=pStatus; classTwo=pClassTwo; } //+ getters/setters etc } Now I'd like to create an HQL query like this: I'd like to get all objects of ClassThree with a certain status and if it exists the newest ClassTwo with a certain newStatus. For example: I'd like to get all the DTOs (ClassThree) of ClassOne whose status is now 1, but earlier in their history it has been 2 and I'd like to have the latest ClassTwo object which has 2 as newStatus. SELECT new ClassThree(c1.id, c1.status, c2) FROM ClassOne c1 LEFT JOIN c1.classtwos c2 (...) and (...) is where I don't know what to do, I'm not even sure if it's a join / join fetch Looked around and tried quite a lot already, but no clue. Especially with the join fetch I get some Hibernate errors like org.hibernate.QueryException: query specified join fetching, but the owner of the fetched association was not present in the select list. Fetching the BusinessObject like that is no problem SELECT distinct(c1) FROM ClassOne c1 LEFT OUTER JOIN FETCH c1.classtwos c2 and I get the ClassTwos as my field. Thanks in advance, Jacob P.S.: One thing might be important, ClassTwo has no reference to ClassOne!!

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  • Flow-Design Cheat Sheet &ndash; Part I, Notation

    - by Ralf Westphal
    You want to avoid the pitfalls of object oriented design? Then this is the right place to start. Use Flow-Oriented Analysis (FOA) and –Design (FOD or just FD for Flow-Design) to understand a problem domain and design a software solution. Flow-Orientation as described here is related to Flow-Based Programming, Event-Based Programming, Business Process Modelling, and even Event-Driven Architectures. But even though “thinking in flows” is not new, I found it helpful to deviate from those precursors for several reasons. Some aim at too big systems for the average programmer, some are concerned with only asynchronous processing, some are even not very much concerned with programming at all. What I was looking for was a design method to help in software projects of any size, be they large or tiny, involing synchronous or asynchronous processing, being local or distributed, running on the web or on the desktop or on a smartphone. That´s why I took ideas from all of the above sources and some additional and came up with Event-Based Components which later got repositioned and renamed to Flow-Design. In the meantime this has generated some discussion (in the German developer community) and several teams have started to work with Flow-Design. Also I´ve conducted quite some trainings using Flow-Orientation for design. The results are very promising. Developers find it much easier to design software using Flow-Orientation than OOAD-based object orientation. Since Flow-Orientation is moving fast and is not covered completely by a single source like a book, demand has increased for at least an overview of the current state of its notation. This page is trying to answer this demand by briefly introducing/describing every notational element as well as their translation into C# source code. Take this as a cheat sheet to put next to your whiteboard when designing software. However, please do not expect any explanation as to the reasons behind Flow-Design elements. Details on why Flow-Design at all and why in this specific way you´ll find in the literature covering the topic. Here´s a resource page on Flow-Design/Event-Based Components, if you´re able to read German. Notation Connected Functional Units The basic element of any FOD are functional units (FU): Think of FUs as some kind of software code block processing data. For the moment forget about classes, methods, “components”, assemblies or whatever. See a FU as an abstract piece of code. Software then consists of just collaborating FUs. I´m using circles/ellipses to draw FUs. But if you like, use rectangles. Whatever suites your whiteboard needs best.   The purpose of FUs is to process input and produce output. FUs are transformational. However, FUs are not called and do not call other FUs. There is no dependency between FUs. Data just flows into a FU (input) and out of it (output). From where and where to is of no concern to a FU.   This way FUs can be concatenated in arbitrary ways:   Each FU can accept input from many sources and produce output for many sinks:   Flows Connected FUs form a flow with a start and an end. Data is entering a flow at a source, and it´s leaving it through a sink. Think of sources and sinks as special FUs which conntect wires to the environment of a network of FUs.   Wiring Details Data is flowing into/out of FUs through wires. This is to allude to electrical engineering which since long has been working with composable parts. Wires are attached to FUs usings pins. They are the entry/exit points for the data flowing along the wires. Input-/output pins currently need not be drawn explicitly. This is to keep designing on a whiteboard simple and quick.   Data flowing is of some type, so wires have a type attached to them. And pins have names. If there is only one input pin and output pin on a FU, though, you don´t need to mention them. The default is Process for a single input pin, and Result for a single output pin. But you´re free to give even single pins different names.   There is a shortcut in use to address a certain pin on a destination FU:   The type of the wire is put in parantheses for two reasons. 1. This way a “no-type” wire can be easily denoted, 2. this is a natural way to describe tuples of data.   To describe how much data is flowing, a star can be put next to the wire type:   Nesting – Boards and Parts If more than 5 to 10 FUs need to be put in a flow a FD starts to become hard to understand. To keep diagrams clutter free they can be nested. You can turn any FU into a flow: This leads to Flow-Designs with different levels of abstraction. A in the above illustration is a high level functional unit, A.1 and A.2 are lower level functional units. One of the purposes of Flow-Design is to be able to describe systems on different levels of abstraction and thus make it easier to understand them. Humans use abstraction/decomposition to get a grip on complexity. Flow-Design strives to support this and make levels of abstraction first class citizens for programming. You can read the above illustration like this: Functional units A.1 and A.2 detail what A is supposed to do. The whole of A´s responsibility is decomposed into smaller responsibilities A.1 and A.2. FU A thus does not do anything itself anymore! All A is responsible for is actually accomplished by the collaboration between A.1 and A.2. Since A now is not doing anything anymore except containing A.1 and A.2 functional units are devided into two categories: boards and parts. Boards are just containing other functional units; their sole responsibility is to wire them up. A is a board. Boards thus depend on the functional units nested within them. This dependency is not of a functional nature, though. Boards are not dependent on services provided by nested functional units. They are just concerned with their interface to be able to plug them together. Parts are the workhorses of flows. They contain the real domain logic. They actually transform input into output. However, they do not depend on other functional units. Please note the usage of source and sink in boards. They correspond to input-pins and output-pins of the board.   Implicit Dependencies Nesting functional units leads to a dependency tree. Boards depend on nested functional units, they are the inner nodes of the tree. Parts are independent, they are the leafs: Even though dependencies are the bane of software development, Flow-Design does not usually draw these dependencies. They are implicitly created by visually nesting functional units. And they are harmless. Boards are so simple in their functionality, they are little affected by changes in functional units they are depending on. But functional units are implicitly dependent on more than nested functional units. They are also dependent on the data types of the wires attached to them: This is also natural and thus does not need to be made explicit. And it pertains mainly to parts being dependent. Since boards don´t do anything with regard to a problem domain, they don´t care much about data types. Their infrastructural purpose just needs types of input/output-pins to match.   Explicit Dependencies You could say, Flow-Orientation is about tackling complexity at its root cause: that´s dependencies. “Natural” dependencies are depicted naturally, i.e. implicitly. And whereever possible dependencies are not even created. Functional units don´t know their collaborators within a flow. This is core to Flow-Orientation. That makes for high composability of functional units. A part is as independent of other functional units as a motor is from the rest of the car. And a board is as dependend on nested functional units as a motor is on a spark plug or a crank shaft. With Flow-Design software development moves closer to how hardware is constructed. Implicit dependencies are not enough, though. Sometimes explicit dependencies make designs easier – as counterintuitive this might sound. So FD notation needs a ways to denote explicit dependencies: Data flows along wires. But data does not flow along dependency relations. Instead dependency relations represent service calls. Functional unit C is depending on/calling services on functional unit S. If you want to be more specific, name the services next to the dependency relation: Although you should try to stay clear of explicit dependencies, they are fundamentally ok. See them as a way to add another dimension to a flow. Usually the functionality of the independent FU (“Customer repository” above) is orthogonal to the domain of the flow it is referenced by. If you like emphasize this by using different shapes for dependent and independent FUs like above. Such dependencies can be used to link in resources like databases or shared in-memory state. FUs can not only produce output but also can have side effects. A common pattern for using such explizit dependencies is to hook a GUI into a flow as the source and/or the sink of data: Which can be shortened to: Treat FUs others depend on as boards (with a special non-FD API the dependent part is connected to), but do not embed them in a flow in the diagram they are depended upon.   Attributes of Functional Units Creation and usage of functional units can be modified with attributes. So far the following have shown to be helpful: Singleton: FUs are by default multitons. FUs in the same of different flows with the same name refer to the same functionality, but to different instances. Think of functional units as objects that get instanciated anew whereever they appear in a design. Sometimes though it´s helpful to reuse the same instance of a functional unit; this is always due to valuable state it holds. Signify this by annotating the FU with a “(S)”. Multiton: FUs on which others depend are singletons by default. This is, because they usually are introduced where shared state comes into play. If you want to change them to be a singletons mark them with a “(M)”. Configurable: Some parts need to be configured before the can do they work in a flow. Annotate them with a “(C)” to have them initialized before any data items to be processed by them arrive. Do not assume any order in which FUs are configured. How such configuration is happening is an implementation detail. Entry point: In each design there needs to be a single part where “it all starts”. That´s the entry point for all processing. It´s like Program.Main() in C# programs. Mark the entry point part with an “(E)”. Quite often this will be the GUI part. How the entry point is started is an implementation detail. Just consider it the first FU to start do its job.   Patterns / Standard Parts If more than a single wire is attached to an output-pin that´s called a split (or fork). The same data is flowing on all of the wires. Remember: Flow-Designs are synchronous by default. So a split does not mean data is processed in parallel afterwards. Processing still happens synchronously and thus one branch after another. Do not assume any specific order of the processing on the different branches after the split.   It is common to do a split and let only parts of the original data flow on through the branches. This effectively means a map is needed after a split. This map can be implicit or explicit.   Although FUs can have multiple input-pins it is preferrable in most cases to combine input data from different branches using an explicit join: The default output of a join is a tuple of its input values. The default behavior of a join is to output a value whenever a new input is received. However, to produce its first output a join needs an input for all its input-pins. Other join behaviors can be: reset all inputs after an output only produce output if data arrives on certain input-pins

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  • Mysql - help me optimize this query

    - by sandeepan-nath
    About the system: -The system has a total of 8 tables - Users - Tutor_Details (Tutors are a type of User,Tutor_Details table is linked to Users) - learning_packs, (stores packs created by tutors) - learning_packs_tag_relations, (holds tag relations meant for search) - tutors_tag_relations and tags and orders (containing purchase details of tutor's packs), order_details linked to orders and tutor_details. For a more clear idea about the tables involved please check the The tables section in the end. -A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is a simpler representation (not the actual) of the more complex query which I am trying to optimize:- I have used statements like explanation of parts in the query select SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) as key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) as key_2_total_matches, td., u., count(distinct(od.id_od)), if (lp.id_lp > 0) then some conditional logic on lp fields else 0 as tutor_popularity from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN `some other tables on lp.id_lp - let's call learning pack tables set (including Learning_Packs table)` LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) where some condition on Users table's fields AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN `some conditions on learning pack tables set` ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN `some conditions on webclasses tables set` ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and some conditions on Orders table's fields ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%") group by td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 ===================================================================== What does the above query do? Does AND logic search on the search keywords (2 in this example - "Democracy" and "Dictatorship"). Returns only those tutors for which both the keywords are present in the union of the two sets - tutors details and details of all the packs created by a tutor. To make things clear - Suppose a Tutor name "Sandeepan Nath" has created a pack "My first pack", then:- Searching "Sandeepan Nath" returns Sandeepan Nath. Searching "Sandeepan first" returns Sandeepan Nath. Searching "Sandeepan second" does not return Sandeepan Nath. ====================================================================================== The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query on heavily loaded databases is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed, but I would appreciate a better query as a solution, optimized as much as possible, displaying the same results ========================================================================================== How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. ==================================================================== The tables Most of the following tables contain many other fields which I have omitted here. CREATE TABLE IF NOT EXISTS users ( id_user int(10) unsigned NOT NULL AUTO_INCREMENT, name varchar(100) NOT NULL DEFAULT '', surname varchar(155) NOT NULL DEFAULT '', PRIMARY KEY (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=636 ; CREATE TABLE IF NOT EXISTS tutor_details ( id_tutor int(10) NOT NULL AUTO_INCREMENT, id_user int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_tutor), KEY Users_FKIndex1 (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=51 ; CREATE TABLE IF NOT EXISTS orders ( id_order int(10) unsigned NOT NULL AUTO_INCREMENT, PRIMARY KEY (id_order), KEY Orders_FKIndex1 (id_user), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=275 ; ALTER TABLE orders ADD CONSTRAINT Orders_ibfk_1 FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS order_details ( id_od int(10) unsigned NOT NULL AUTO_INCREMENT, id_order int(10) unsigned NOT NULL DEFAULT '0', id_author int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_od), KEY Order_Details_FKIndex1 (id_order) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=284 ; ALTER TABLE order_details ADD CONSTRAINT Order_Details_ibfk_1 FOREIGN KEY (id_order) REFERENCES orders (id_order) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs ( id_lp int(10) unsigned NOT NULL AUTO_INCREMENT, id_author int(10) unsigned NOT NULL DEFAULT '0', PRIMARY KEY (id_lp), KEY Learning_Packs_FKIndex2 (id_author), KEY id_lp (id_lp) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=23 ; CREATE TABLE IF NOT EXISTS tags ( id_tag int(10) unsigned NOT NULL AUTO_INCREMENT, tag varchar(255) DEFAULT NULL, PRIMARY KEY (id_tag), UNIQUE KEY tag (tag), KEY id_tag (id_tag), KEY tag_2 (tag), KEY tag_3 (tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3419 ; CREATE TABLE IF NOT EXISTS tutors_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, KEY Tutors_Tag_Relations (id_tag), KEY id_tutor (id_tutor), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE tutors_tag_relations ADD CONSTRAINT Tutors_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, id_lp int(10) unsigned DEFAULT NULL, KEY Learning_Packs_Tag_Relations_FKIndex1 (id_tag), KEY id_lp (id_lp), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE learning_packs_tag_relations ADD CONSTRAINT Learning_Packs_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; =================================================================================== Following is the exact query (this includes classes also - tutors can create classes and search terms are matched with classes created by tutors):- select count(distinct(od.id_od)) as tutor_popularity, CASE WHEN (IF((wc.id_wc 0), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT'))), 0)) THEN 1 ELSE 0 END as 'classes_published', CASE WHEN (IF((lp.id_lp 0), (lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT'))),0)) THEN 1 ELSE 0 END as 'packs_published', td . * , u . * from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN Learning_Packs_Categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN Learning_Packs_Categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN Learning_Pack_Content as lpct on (lp.id_lp = lpct.id_lp) LEFT JOIN Webclasses_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN WebClasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN Learning_Packs_Categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN Learning_Packs_Categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) OR (t.id_tag = wtagrels.id_tag) where (u.country='IE' or u.country IN ('INT')) AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and o.order_status = 'paid' and CASE WHEN (od.id_wc 0) THEN od.can_attend_class=1 ELSE 1 END ELSE 1 END AND 1 group by td.id_tutor order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 Please note - The provided database structure does not show all the fields and tables as in this query

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  • SQL SERVER – Puzzle to Win Print Book – Write T-SQL Self Join Without Using FIRST _VALUE and LAST_VALUE

    - by pinaldave
    Last week we asked a puzzle SQL SERVER – Puzzle to Win Print Book – Functions FIRST_VALUE and LAST_VALUE with OVER clause and ORDER BY . This puzzle got very interesting participation. The details of the winner is listed here. In this puzzle we received two very important feedback. This puzzle cleared the concepts of First_Value and Last_Value to the participants. As this was based on SQL Server 2012 many could not participate it as they have yet not installed SQL Server 2012. I really appreciate the feedback of user and decided to come up something as fun and helps learn new feature of SQL Server 2012. Please read yesterday’s blog post SQL SERVER – Introduction to LEAD and LAG – Analytic Functions Introduced in SQL Server 2012 before continuing this puzzle as it is based on yesterday’s post. Yesterday I ran following query which uses functions LEAD and LAG. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: Puzzle: Now use T-SQL Self Join where same table is joined to itself and get the same result without using LEAD or LAG functions. Hint: Introduction to JOINs – Basic of JOINs Self Join A new analytic functions in SQL Server Denali CTP3 – LEAD() and LAG() Rules Leave a comment with your detailed answer by Nov 21's blog post. Open world-wide (where Amazon ships books) If you blog about puzzle’s solution and if you win, you win additional surprise gift as well. Prizes Print copy of my new book SQL Server Interview Questions Amazon|Flipkart If you already have this book, you can opt for any of my other books SQL Wait Stats [Amazon|Flipkart|Kindle] and SQL Programming [Amazon|Flipkart|Kindle]. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Join us for our WebLogic Communtiy webcast on November 2nd 2012! OOW update WebLogic & ExaLogic

    - by JuergenKress
    NOVEMBER 2nd, 2012 AT 11:00 -11:45 AM CET (BERLIN TIME) Do you want to learn the latest about WebLogic and ExaLogic? Would you like to know what did Oracle announce at Oracle OpenWorld 2012? Join us for our WebLogic Communtiy webcast on November 2nd 2012! Don't miss this unique opportunity and learn the latest announcement and product updates on WebLogic and ExaLogic portfolio. Agenda Update announced about Cloud Application Foundation ExaLogic Update Key examples from successful customer Updated Roadmap Q&A Register to Attend! To Join the Webcast (Employees and Partners) AND / OR DIAL IN If you would like to dial in to the audio portion of the Webconference. Call ID: 8000524 & Call Passcode: 333111 Austria : +43(0)19286512 Belgium: +32(0)24010528 Denmark: +4532729222 Finland: +358(0)923193923 France: +33(0)176728936 Germany: +49(0)69222216106 Ireland: +353(0)12475650 Italy: +39(0)236008198 Netherlands: +31(0)207143543 Norway: +4721033443 Spain: +34914143755 Sweden: +46(0)856619465 Switzerland: +41(0)445804003 United Kingdom: +44(0)2081181001 Please click here to find more Local Numbers. Presenters: Maciej Gruszka Senior Principal Product Manager Tel: +4 (0) 8601 156 464 E-Mail: [email protected] LinkedIn: http://pl.linkedin.com/pub/maciej-gruszka/2/169/89 Jürgen Kress WebLogic Partner Adoption EMEA Tel. +49 89 1430 1479 E-Mail: [email protected] LinkedIn: http://de.linkedin.com/in/kress Twitter: http://twitter.com/wlscommunity Delivery Format This FREE online LIVE eSeminar will be delivered over the Web. Registrations received less than 24hours prior to start time may not receive confirmation to attend. Duration: 1 hour Looking forward to your participation! WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. BlogTwitterLinkedInMixForumWiki Technorati Tags: WebLogic Community Webcast,webcst,OOW updates WebLogic ExaLogic,WebLogic ppt,presenation,sales,WebLogic Community,Oracle,OPN,Jürgen Kress

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  • SQL query. An unusual join. DB implemented in sqlite-3

    - by user02814
    This is essentially a question about constructing an SQL query. The db is implemented with sqlite3. I am a relatively new user of SQL. I have two tables and want to join them in an unusual way. The following is an example to explain the problem. Table 1 (t1): id year name ------------------------- 297 2010 Charles 298 2011 David 300 2010 Peter 301 2011 Richard Table 2 (t2) id year food --------------------------- 296 2009 Bananas 296 2011 Bananas 297 2009 Melon 297 2010 Coffee 297 2012 Cheese 298 2007 Sugar 298 2008 Cereal 298 2012 Chocolate 299 2000 Peas 300 2007 Barley 300 2011 Beans 300 2012 Chickpeas 301 2010 Watermelon I want to join the tables on id and year. The catch is that (1) id must match exactly, but if there is no exact match in Table 2 for the year in Table 1, then I want to choose the year that is the next (lower) available. A selection of the kind that I want to produce would give the following result id year matchyr name food ------------------------------------------------- 297 2010 2010 Charles Coffee 298 2011 2008 David Cereal 300 2010 2007 Peter Barley 301 2011 2010 Richard Watermelon To summarise, id=297 had an exact match for year=2010 given in Table 1, so the corresponding line for id=297, year=2010 is chosen from Table 2. id=298, year=2011 did not have a matching year in Table 2, so the next available year (less than 2011) is chosen. As you can see, I would also like to know what that matched year (whether exactly , or inexactly) actually was. I would very much appreciate (1) an indication (yes/no answer) of whether this is possible to do in SQL alone, or whether I need to look outside SQL, and (2) a solution, if that is not too onerous.

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  • When is the right time to join open source project for programmer?

    - by Mahesh
    Most of the newcomers in programming start with basic projects to start with programming. Most of the C++ progammers spend some time with puzzles and contests but this is not always helpful. Sometimes you've to spend some time on real projects. Starting your own open source project could be a problem in self-learning for newbie cause of lack of mentors and peers who can't look at your code and give suggestions. Open source projects can solve this problem, some projects could be best suited for new programmers. Besides everybody is newbie at some point. So i'll try and make this question a bit from beginners perspective. I tried few questions on stack overflow before asking this like How do i join & Bare minimum you need and how to get involved with open source and what level of programming etc. But this is not helping me when it comes to self-evaluating with skills. How to find that out ? How can i check what it takes to join open source project and am i really that comfortable with huge source code etc. My question is when to consider yourself comfortable joining open source programming ? I mean how will you test yourself that you're ready to take burden of big/small projects of open source ? how will you test yourself to see if you could work with version control/other programmers/tight schedule etc ?

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  • How to re-join an AD2003 domain with Samba after deleting the machine account?

    - by Guss
    During some troubleshooting I deleted the machine account for a Linux server running samba from our AD 2003 domain. We are using Kerberos for authentication, and after I deleted the machine account I tried to join the domain again using net ads join -U Administrator But I keep getting Kerberos errors like these: [2009/08/18 16:14:36, 0] libads/kerberos.c:ads_kinit_password(228) kerberos_kinit_password [email protected] failed: Client not found in Kerberos database Failed to join domain: Improperly formed account name It appears as if samba remembers that it once had an account with the AD and keeps trying to reconnect to it, but I want to create a new account from scratch. I tried to delete all the .tdb files I could find as well as everything under /var/cache/samba but to no avail - it still behaves the same. I also tried to create the machine account on the AD side, but then I get a similar error when I try to join, about failure to authenticate with the machine account - it looks like samba tries the previous machine account password and I don't know how to reset it, or even if I could figure out what samba uses - how to set it in the AD. Any help would be greatly appreciated, as at this point the only thing I can think about is to reformat and reinstall the machine, and I would really REALLY love to not do that. Thanks in advance.

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  • STORED PROCEDURE working in my local test machine cannot be created in production environment.

    - by Marcos Buarque
    Hi, I have an SQL CREATE PROCEDURE statement that runs perfectly in my local SQL Server, but cannot be recreated in production environment. The error message I get in production is Msg 102, Level 15, State 1, Incorrect syntax near '='. It is a pretty big query and I don't want to annoy StackOverflow users, but I simply can't find a solution. If only you could point me out what settings I could check in the production server in order to enable running the code... I must be using some kind of syntax or something that is conflicting with some setting in production. This PROCEDURE was already registered in production before, but when I ran a DROP - CREATE PROCEDURE today, the server was able to drop the procedure, but not to recreate it. I will paste the code below. Thank you! =============== USE [Enorway] GO /****** Object: StoredProcedure [dbo].[Spel_CM_ChartsUsersTotals] Script Date: 03/17/2010 11:59:57 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE PROC [dbo].[Spel_CM_ChartsUsersTotals] @IdGroup int, @IdAssessment int, @UserId int AS SET NOCOUNT ON DECLARE @RequiredColor varchar(6) SET @RequiredColor = '3333cc' DECLARE @ManagersColor varchar(6) SET @ManagersColor = '993300' DECLARE @GroupColor varchar(6) SET @GroupColor = 'ff0000' DECLARE @SelfColor varchar(6) SET @SelfColor = '336600' DECLARE @TeamColor varchar(6) SET @TeamColor = '993399' DECLARE @intMyCounter tinyint DECLARE @intManagersPosition tinyint DECLARE @intGroupPosition tinyint DECLARE @intSelfPosition tinyint DECLARE @intTeamPosition tinyint SET @intMyCounter = 1 -- Table that will hold the subtotals... DECLARE @tblTotalsSource table ( IdCompetency int, CompetencyName nvarchar(200), FunctionRequiredLevel float, ManagersAverageAssessment float, SelfAssessment float, GroupAverageAssessment float, TeamAverageAssessment float ) INSERT INTO @tblTotalsSource ( IdCompetency, CompetencyName, FunctionRequiredLevel, ManagersAverageAssessment, SelfAssessment, GroupAverageAssessment, TeamAverageAssessment ) SELECT e.[IdCompetency], dbo.replaceAccentChar(e.[Name]) AS CompetencyName, (i.[LevelNumber]) AS FunctionRequiredLevel, ( SELECT ROUND(avg(CAST(ac.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData aa INNER JOIN Spel_CM_CompetenciesLevels ab ON aa.[IdCompetencyLevel] = ab.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels ac ON ab.[IdLevel] = ac.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents ad ON aa.[IdAssessmentEvent] = ad.[IdAssessmentEvent] WHERE aa.[EvaluatedUserId] = @UserId AND aa.[AssessmentType] = 't' AND aa.[IdGroup] = @IdGroup AND ab.[IdCompetency] = e.[IdCompetency] AND ad.[IdAssessment] = @IdAssessment ) AS ManagersAverageAssessment, ( SELECT bc.[LevelNumber] FROM Spel_CM_AssessmentsData ba INNER JOIN Spel_CM_CompetenciesLevels bb ON ba.[IdCompetencyLevel] = bb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels bc ON bb.[IdLevel] = bc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents bd ON ba.[IdAssessmentEvent] = bd.[IdAssessmentEvent] WHERE ba.[EvaluatedUserId] = @UserId AND ba.[AssessmentType] = 's' AND ba.[IdGroup] = @IdGroup AND bb.[IdCompetency] = e.[IdCompetency] AND bd.[IdAssessment] = @IdAssessment ) AS SelfAssessment, ( SELECT ROUND(avg(CAST(cc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData ca INNER JOIN Spel_CM_CompetenciesLevels cb ON ca.[IdCompetencyLevel] = cb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels cc ON cb.[IdLevel] = cc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents cd ON ca.[IdAssessmentEvent] = cd.[IdAssessmentEvent] WHERE ca.[EvaluatedUserId] = @UserId AND ca.[AssessmentType] = 'g' AND ca.[IdGroup] = @IdGroup AND cb.[IdCompetency] = e.[IdCompetency] AND cd.[IdAssessment] = @IdAssessment ) AS GroupAverageAssessment, ( SELECT ROUND(avg(CAST(dc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData da INNER JOIN Spel_CM_CompetenciesLevels db ON da.[IdCompetencyLevel] = db.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels dc ON db.[IdLevel] = dc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents dd ON da.[IdAssessmentEvent] = dd.[IdAssessmentEvent] WHERE da.[EvaluatedUserId] = @UserId AND da.[AssessmentType] = 'm' AND da.[IdGroup] = @IdGroup AND db.[IdCompetency] = e.[IdCompetency] AND dd.[IdAssessment] = @IdAssessment ) AS TeamAverageAssessment FROM Spel_CM_AssessmentsData a INNER JOIN Spel_CM_AssessmentsEvents c ON a.[IdAssessmentEvent] = c.[IdAssessmentEvent] INNER JOIN Spel_CM_CompetenciesLevels d ON a.[IdCompetencyLevel] = d.[IdCompetencyLevel] INNER JOIN Spel_CM_Competencies e ON d.[IdCompetency] = e.[IdCompetency] INNER JOIN Spel_CM_Levels f ON d.[IdLevel] = f.[IdLevel] -- This will link with user's assigned functions INNER JOIN Spel_CM_FunctionsCompetenciesLevels g ON a.[IdFunction] = g.[IdFunction] INNER JOIN Spel_CM_CompetenciesLevels h ON g.[IdCompetencyLevel] = h.[IdCompetencyLevel] AND e.[IdCompetency] = h.[IdCompetency] INNER JOIN Spel_CM_Levels i ON h.[IdLevel] = i.[IdLevel] WHERE (NOT c.[EndDate] IS NULL) AND a.[EvaluatedUserId] = @UserId AND c.[IdAssessment] = @IdAssessment AND a.[IdGroup] = @IdGroup GROUP BY e.[IdCompetency], e.[Name], i.[LevelNumber] ORDER BY e.[Name] ASC -- This will define the position of each element (managers, group, self and team) SELECT @intManagersPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT ManagersAverageAssessment IS NULL IF IsNumeric(@intManagersPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intGroupPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT GroupAverageAssessment IS NULL IF IsNumeric(@intGroupPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intSelfPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT SelfAssessment IS NULL IF IsNumeric(@intSelfPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intTeamPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT TeamAverageAssessment IS NULL -- This will render the final table for the end user. The tabe will flatten some of the numbers to allow them to be prepared for Google Graphics. SELECT SUBSTRING( ( SELECT ( '|' + REPLACE(ma.[CompetencyName],' ','+')) FROM @tblTotalsSource ma ORDER BY ma.[CompetencyName] DESC FOR XML PATH('') ), 2, 1000) AS 'CompetenciesNames', SUBSTRING( ( SELECT ( ',' + REPLACE(ra.[FunctionRequiredLevel]*10,' ','+')) FROM @tblTotalsSource ra FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredLevel', SUBSTRING( ( SELECT ( ',' + CAST(na.[ManagersAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource na FOR XML PATH('') ), 2, 1000) AS 'ManagersAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(oa.[GroupAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource oa FOR XML PATH('') ), 2, 1000) AS 'GroupAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(pa.[SelfAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource pa FOR XML PATH('') ), 2, 1000) AS 'SelfAssessment', SUBSTRING( ( SELECT ( ',' + CAST(qa.[TeamAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource qa FOR XML PATH('') ), 2, 1000) AS 'TeamAverageAssessment', SUBSTRING( ( SELECT ( '|t++' + CAST([FunctionRequiredLevel] AS varchar(10)) + ',' + @RequiredColor + ',0,' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredAverageLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([ManagersAverageAssessment] AS varchar(10)) + ',' + @ManagersColor + ',' + CAST(@intManagersPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'ManagersLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([GroupAverageAssessment] AS varchar(10)) + ',' + @GroupColor + ',' + CAST(@intGroupPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'GroupLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([SelfAssessment] AS varchar(10)) + ',' + @SelfColor + ',' + CAST(@intSelfPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'SelfLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([TeamAverageAssessment] AS varchar(10)) + ',' + @TeamColor + ',' + CAST(@intTeamPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',10') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'TeamLabel', (Count(src.[IdCompetency]) * 30) + 100 AS 'ControlHeight' FROM @tblTotalsSource src SET NOCOUNT OFF GO

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  • How do I prevent 'net ads join' from doing DDNS update?

    - by genehack
    I'm using 'net ads join' to add Linux servers to an AD domain. The servers are multi-homed, with a public IP on eth1 and a non-routable private background network on eth0 (in the 172.20 space, used for netboots and installs and stuff -- no routing to the Internet on that network). When I 'net ads join', it appears that a DDNS entry is getting created for the 172.20 interface. How can I prevent this from happening? (FWIW, my powers at the AD level are very limited -- I can join servers and delete server records but that's about it...)

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  • Is it bad to join open-source projects as an amateur?

    - by esqew
    I've thought for about six months now that I should join an open-source iPhone or iPad project to hone my skills in Objective-C, but every time I go to do it I see thousands of lines of code on huge projects that I end up convincing myself I would never understand. I always think that my commits would just end up being a hassle for project admins and more senior contributors, so I always back out at the last second. My question essentially is, is it a hassle when an intermediately-experienced programmer joins an open-source project?

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  • I'd like to learn how to do mobile development - which competitions can I join to help me learn?

    - by Oscar
    I want to start learning mobile device development, but I am someone that gets much more motivated when there is some goal to reach. Because of that, I would like to join a competition. I know about Microsoft Imagine Cup, which is a very nice competition. Are there any another mobile development competition with a deadline in the next 6~8 months? I have been googling for them, but I could not find any, maybe someone knows about something that I couldn't find.

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  • We are having a Social on the 15th April - Why not join us for some SQL fun

    - by NeilHambly
    TechDays are coming week, with the "SQL Server 2008 R2" Launch conference being held on the Thursday (15 th April) and followed by the much anticipated SQLBits VI the following day (16 th April) So we thought this an ideal opportunity to hold a SQL Social evening for those fortunate enough to be able to attend those conferences or just wanted to join us for the evening It is being held @ "The Bull" Pub @ Westfield centre (only a short walk from the venue of t the “SQL Server 2008...(read more)

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