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With WebMatrix, How do I Connect to a MySQL Database on a Colleague's Machine?

- by Ash Clarke

I have scoured Google trying to discover how to do this, but essentially I want to connect to a colleague's MySQL database for working together on a Wordpress installation. I am having no luck and keep getting an error about the connection not being possible: Unable to connect to any of the specified MySQL hosts. MySql.Data.MySqlClient.MySqlException (0x80004005): Unable to connect to any of the specified MySQL hosts. at MySql.Data.MySqlClient.NativeDriver.Open() at MySql.Data.MySqlClient.Driver.Open() at MySql.Data.MySqlClient.Driver.Create(MySqlConnectionStringBuilder settings) at MySql.Data.MySqlClient.MySqlPool.GetPooledConnection() at MySql.Data.MySqlClient.MySqlPool.TryToGetDriver() at MySql.Data.MySqlClient.MySqlPool.GetConnection() at MySql.Data.MySqlClient.MySqlConnection.Open() at Microsoft.WebMatrix.DatabaseManager.MySqlDatabase.MySqlDatabaseProvider.TestConnection(String connectionString) at Microsoft.WebMatrix.DatabaseManager.IisDbManagerModuleService.TestConnection(DatabaseConnection databaseConnection, String configPathState) at Microsoft.WebMatrix.DatabaseManager.Client.ClientConnection.Test(ManagementConfigurationPath configPath) at Microsoft.WebMatrix.DatabaseManager.Client.DatabaseHierarchyInfo.EnsureLoaded() The connection details are copied from my colleague's connection string, with the exception of the server being modified to match the IP address of his machine. I'm not sure if there is a firewall port I have to open or a configuration file I have to modify, but I'm not having much luck so far. (There is a strong chance that, by default, web matrix / iis express doesn't set the mysql database it creates to accept remote connections. If anyone knows how to change this, that would be grand!) Anyone have any ideas?

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Nginx , Apache , Mysql , Memcache with server 4G ram. How optimize to enought memory?

- by TomSawyer

i have 1 dedicated server with Nginx proxy for Apache. Memcache, mysql, 4G Ram. These day, my visitor on my site wasn't increased, but my server get overload always in some specified time. (9AM - 15PM) Ram in use is increased second by second to full. that's moment, my server will get overload. i have to kill all apache , mysql service and reboot it to get free memory. that's the circle. here is my ram in use at the moment 160(nginx) 220(apache) 512(memcache) 924(mysql) here's process number 4(nginx) 14(apache) 5(memcache) 20(mysql) and here's my my.cnf config. someone can help me to optimize it? [mysqld] datadir=/var/lib/mysql socket=/var/lib/mysql/mysql.sock user=mysql skip-locking skip-networking skip-name-resolve # enable log-slow-queries log-slow-queries = /var/log/mysql-slow-queries.log long_query_time=3 max_connections=200 wait_timeout=64 connect_timeout = 10 interactive_timeout = 25 thread_stack = 512K max_allowed_packet=16M table_cache=1500 read_buffer_size=4M join_buffer_size=4M sort_buffer_size=4M read_rnd_buffer_size = 4M max_heap_table_size=256M tmp_table_size=256M thread_cache=256 query_cache_type=1 query_cache_limit=4M query_cache_size=16M thread_concurrency=8 myisam_sort_buffer_size=128M # Disabling symbolic-links is recommended to prevent assorted security risks symbolic-links=0 [mysqldump] quick max_allowed_packet=16M [mysql] no-auto-rehash [isamchk] key_buffer=256M sort_buffer=256M read_buffer=64M write_buffer=64M [myisamchk] key_buffer=256M sort_buffer=256M read_buffer=64M write_buffer=64M [mysqlhotcopy] interactive-timeout [mysql.server] user=mysql basedir=/var/lib [mysqld_safe] log-error=/var/log/mysqld.log pid-file=/var/run/mysqld/mysqld.pid

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What can cause legit MySql INSERT INTO command to fail?

- by Makis

I can't figure out what's causing my INSERT INTO's to fail to certain table in MySql. I can manage them to other tables. The table looks like: CREATE TABLE IF NOT EXISTS `Match` ( `id` int(11) NOT NULL AUTO_INCREMENT, `match_no` int(11) NOT NULL, `season` int(11) NOT NULL, `hometeam` int(11) NOT NULL, `awayteam` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `match_no` (`match_no`), KEY `season` (`season`), KEY `hometeam` (`hometeam`), KEY `awayteam` (`awayteam`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; And the command is INSERT INTO Match (`match_no`, `season`, `hometeam`, `awaytem`) VALUES (1, 1, 2, 3) All I get is: 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Match (match_no, season, hometeam, awaytem) VALUES (1, 1, 2, 3)' at line 1 I have checked the manual and half-a-dozen examples from the web and whatnought and tried all sorts of changes to the syntax in case there is some MySql specific oddity, but nothing seems to work.

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What's the cause of (and treatment for) this java MySQL exception?

- by justkevin

I'm getting the following exception when executing the first preparedstatement after a period of inactivity: com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure The last packet successfully received from the server was 2,855,054 milliseconds ago. The last packet sent successfully to the server was 123 milliseconds ago. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at com.mysql.jdbc.Util.handleNewInstance(Util.java:406) at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1074) at com.mysql.jdbc.MysqlIO.reuseAndReadPacket(MysqlIO.java:3052) at com.mysql.jdbc.MysqlIO.reuseAndReadPacket(MysqlIO.java:2938) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3481) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1959) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2109) at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2648) at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2077) at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2228) This only shows up if my application hasn't communicated with MySQL recently. Subsequent queries execute normally. I suspect it's some kind of timeout issue, but the periods of inactivity are way below the 8 hour timeout for MySQL. Any suggestions?

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I want to search and replace multiple values in a table column in one MYsql querry.

- by user204245

Query to Where X update Y and where A update B in a Mysql Table column. How can I Do this in MYsql in one querry on the same column in a specific table. I want to search and replace multiple values in a table column. Conditons in table1 in column1 Where X update Y and Where a update b and Where 1 update 2 and Where 3 update 4 and Where value1 update value 2 And So on. I can individually do this but how can I do this faster is there a mysql function to help me with this. I have about 120 columns with 200 search and replace/update values for each column. Thanks.

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Mysql replace() function, help with query (what chars do I escape?)

- by jyoseph

I am trying to update an old cms where images were stored in /images/editor/, they are now stored in a bucket on amazon s3. I'm trying to update the database using mysql replace. I've done this in the past with replacing simple words, but now Mysql is reporting an error, I suspect because this is more than a simple word: UPDATE contents SET desc = replace(desc, '/images/editor/', 'http://s3.amazonaws.com/my_bucket/editor/') Do I need to escape the : or slashes? I've tried escaping it with a '\' to no avail. Can someone get me pointed in the right direction? Thanks! Edit Here's the error I am getting, nothing too telling error : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc = replace(desc, '/images/editor', 'http://s3.amazonaws.com/app_navigator/ed' at line 1

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How to speed up this simple mysql query?

- by Jim Thio

The query is simple: SELECT TB.ID, TB.Latitude, TB.Longitude, 111151.29341326*SQRT(pow(-6.185-TB.Latitude,2)+pow(106.773-TB.Longitude,2)*cos(-6.185*0.017453292519943)*cos(TB.Latitude*0.017453292519943)) AS Distance FROM `tablebusiness` AS TB WHERE -6.2767668133836 < TB.Latitude AND TB.Latitude < -6.0932331866164 AND FoursquarePeopleCount >5 AND 106.68123318662 < TB.Longitude AND TB.Longitude <106.86476681338 ORDER BY Distance See, we just look at all business within a rectangle. 1.6 million rows. Within that small rectangle there are only 67,565 businesses. The structure of the table is 1 ID varchar(250) utf8_unicode_ci No None Change Change Drop Drop More Show more actions 2 Email varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 3 InBuildingAddress varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 4 Price int(10) Yes NULL Change Change Drop Drop More Show more actions 5 Street varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 6 Title varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 7 Website varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 8 Zip varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 9 Rating Star double Yes NULL Change Change Drop Drop More Show more actions 10 Rating Weight double Yes NULL Change Change Drop Drop More Show more actions 11 Latitude double Yes NULL Change Change Drop Drop More Show more actions 12 Longitude double Yes NULL Change Change Drop Drop More Show more actions 13 Building varchar(200) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 14 City varchar(100) utf8_unicode_ci No None Change Change Drop Drop More Show more actions 15 OpeningHour varchar(400) utf8_unicode_ci Yes NULL Change Change Drop Drop More Show more actions 16 TimeStamp timestamp on update CURRENT_TIMESTAMP No CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP Change Change Drop Drop More Show more actions 17 CountViews int(11) Yes NULL Change Change Drop Drop More Show more actions The indexes are: Edit Edit Drop Drop PRIMARY BTREE Yes No ID 1965990 A Edit Edit Drop Drop City BTREE No No City 131066 A Edit Edit Drop Drop Building BTREE No No Building 21 A YES Edit Edit Drop Drop OpeningHour BTREE No No OpeningHour (255) 21 A YES Edit Edit Drop Drop Email BTREE No No Email (255) 21 A YES Edit Edit Drop Drop InBuildingAddress BTREE No No InBuildingAddress (255) 21 A YES Edit Edit Drop Drop Price BTREE No No Price 21 A YES Edit Edit Drop Drop Street BTREE No No Street (255) 982995 A YES Edit Edit Drop Drop Title BTREE No No Title (255) 1965990 A YES Edit Edit Drop Drop Website BTREE No No Website (255) 491497 A YES Edit Edit Drop Drop Zip BTREE No No Zip (255) 178726 A YES Edit Edit Drop Drop Rating Star BTREE No No Rating Star 21 A YES Edit Edit Drop Drop Rating Weight BTREE No No Rating Weight 21 A YES Edit Edit Drop Drop Latitude BTREE No No Latitude 1965990 A YES Edit Edit Drop Drop Longitude BTREE No No Longitude 1965990 A YES The query took forever. I think there has to be something wrong there. Showing rows 0 - 29 ( 67,565 total, Query took 12.4767 sec)

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mysql join with multiple values in one column

- by CYREX

I need to make a query that creates 3 columns that come from 2 tables which have the following relations: TABLE 1 has Column ID that relates to TABLE 2 with column ID2 In TABLE 1 there is a column called user In TABLE 2 there is a column called names There can be 1 unique user but there can be many names associated to that user. If i do the following i get all data BUT the user column repeats itself for each name it has associated. What i want is for use to appear unique but the names columns appear with all the names associated to the user column but separated by commas, like the following: select user,names from TABLE1 left join TABLE2 on TABLE1.id = TABLE2.id This will show the users repeated everytime a name appears for that user. what i want is to appear like this: USER - NAMES cyrex - pedrox, rambo, zelda homeboy - carmen, carlos, tom, sandra jerry - seinfeld, christine ninja - soloboy etc....

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Overlap of the variable in mysql, my column are set to my query result

- by foodil

The question is not clear , let me clarify it: try{ $sql = ' SELECT UserID <==== (***********Used here for query ******) FROM user WHERE Rights != ?'; $stmt = $conn->prepare($sql); $stmt->execute(array('admin')); $result= $stmt->fetchAll(); } catch(PDOException $e) { die ($e->getMessage().'<a href="add.php"> Back</a>'); } foreach ($result as $set) { if ($set['UserID']==$_SESSION['username']) $rights='edit'; else {$rights=$_POST[$set['UserID']];} if (($rights != 'default' || $set['UserID']==$_SESSION['username']) && $_POST['public']==0 ) { $user=$set['UserID']; try { $query="INSERT INTO user_list(UserID <==== (***********Used here for insert ******),ListID,UserRights) VALUES ($user,$lastID,$rights)"; $stmt = $conn->prepare($query); $stmt->execute(); } catch(PDOException $e) { die ($e->getMessage().'<a href="add.php"> Back</a>'); $conn->rollBack(); } } } As you can see the UserID is a query result but it is also the column i need to insert, so when i insert into the table it will casued an error SQLSTATE[42S22]: Column not found: 1054 Unknown column 'UserA_ID' in 'field list' because the column is modify by my query result from: $query="INSERT INTO user_list(UserID,ListID,UserRights) VALUES ($user,$lastID,$rights)"; to: $query="INSERT INTO user_list(query_result_id,ListID,UserRights) VALUES ($user,$lastID,$rights)"; How to fix it ?Thank you.

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Recommend hosting with fast MySQL database please [closed]

- by Keith Groben

Possible Duplicate: How to find web hosting that meets my requirements? I am frustrated to no end with my current hosting provider, mediaTemple. Yes, they are flashy, and have some decent degree of flexibility with their GS plan, which I have. But anytime I install a site that needs a database, it is slow. like really slow. Taking anywhere from 10 - 15 seconds just to load a page. I would host in house, but there are a lot of complications that come with a LAMP server that I don't want to deal with. Honestly, I'd rather spend the time developing. What can you recommend?

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Auto backup mysql database to dropbox [closed]

- by Rob

Is it possible to automatically backup my database to dropbox? If so how can I do it? The key criteria I need it to do is: Be automatic. Be Mac compliant. Be weekly. Sync with dropbox (http://www.dropbox.com) automatically. Be able to backup several databases from several websites. Be free... or relatively cheap! Have a guide on how to setup the solution. UPDATE: I've managed to setup an auto weekly backup using a cronjob: mysqldump -u username -pMyPassword Mydatabase > backup-file.sql That is saving the backup to my hosting space. It's a start but isn't ideal, how can I save that backup to a folder on my computer? Automatically of course.

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Recommend hosting with fast MySQL database please.

- by Keith Groben

I am frustrated to no end with my current hosting provider, mediaTemple. Yes, they are flashy, and have some decent degree of flexibility with their GS plan, which I have. But anytime I install a site that needs a database, it is slow. like really slow. Taking anywhere from 10 - 15 seconds just to load a page. I would host in house, but there are a lot of complications that come with a LAMP server that I don't want to deal with. Honestly, I'd rather spend the time developing. What can you recommend?

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MySQL: operation of summing and division ?

- by Nick

Alright, so I have a user table and would like to get the max value for the user with the highest amount of points divided by a score. Below is a rough idea of what I'm looking for: SELECT MAX(SUM(points)/SUM(score)) FROM users I'm not interested in adding up both columns and dividing, rather I'm interested in dividing the points and score for each user and retrieve the highest value out of the lot.

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Cannot Install mysql-query-browser in Ubuntu 12.04

- by doy

Please help..... I tried to install mysql-query-browser in my Ubuntu 12.04 GUI, I get the error message: Updating mysql-administrator installation paths... ./mysql-administrator: 59: ./mysql-administrator: cannot create /opt/mysql-gui-tools-5.0/lib/pangorc.bak: Permission denied Error updating files for new installation path. Please make sure mysql-administrator is installed correctly and you have proper write permissions in the installation directory. Tried the ..... /opt/mysql-gui-tools-5.0$ ./mysql-administrator --update-paths . and /opt/mysql-gui-tools-5.0$ ./mysql-administrator --update-paths but still no success.........

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How to sum and divide in MySql [migrated]

- by Nick

Alright, so I have a user table and would like to get the max value for the user with the highest amount of points divided by a score. Below is a rough idea of what I'm looking for: SELECT MAX(SUM(points)/SUM(score)) FROM users I'm not interested in adding up both columns and dividing, rather I'm interested in dividing the points and score for each user and retrieve the highest value out of the lot.

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Synchronizing Mysql Table Schema [on hold]

- by user1122069

I have some difficulty keeping track of my SQL changes in a text file in SVN. One solution that I am aware of is to put the SQL queries in files (1.sql, 2.sql...) and to manually load each file at the proper time. Besides missing commas, the process is too cumbersome when builds become more frequent. I have actually taken to asking a co-worker to send me his SQL changes on Skype and we just apply the changes immediately on our local, development, and production servers (using three PhpMyAdmin tabs). I have seen several GUI tools mentioned in similar questions on SO, but these are actually more work and less automated than the aforementioned methods. Is there any standardized process by which this is done in an automated way? I can only guess that large companies build their own mechanisms of keeping track of database schema changes (yet I can't find a word about it - maybe they use files?). This question was closed as off-topic on Stack Overflow, so I am re-posting it here.

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i want to access mysql database table on given conditions in drop down menu [on hold]

- by user3909877

as the code below is accesing the database table directly but i want it to display the table content on giving conditions in drop down menu like when i select islamabad in one drop down menu and lahore in other as given in code and press search buttonn then it display the table flights.but it is displaying it directly <p class="h2">Quick Search</p> <div class="sb2_opts"> <p> </p> <form method="post" action=""> <p>Enter your source and destination.</p> <p> From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p> To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php $from = isset($_POST['from'])?$_POST['from']:''; $to = isset($_POST['to'])?$_POST['to']:''; if( $from =='Islamabad'){ if($to == 'Lahore'){ $db_host = 'localhost'; $db_user = 'root'; $database = 'homedb'; $table = 'flights'; if (!mysql_connect($db_host, $db_user)) die("Can't connect to database"); if (!mysql_select_db($database)) die("Can't select database"); $result = mysql_query("SELECT * FROM {$table}"); if (!$result) { die("Query to show fields from table failed"); } $result = mysql_query("SELECT * FROM {$table}"); if (!$result) { die("Query to show fields from table failed"); } $fields_num = mysql_num_fields($result); echo "<h1>Table: {$table}</h1>"; echo "<table border='1'><tr>"; while($row = mysql_fetch_row($result)) { echo "<tr>"; // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row as $cell) echo "<td>$cell</td>"; echo "</tr>\n"; } } } mysqli_close($con); ?>

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Group / User based security. Table / SQL question

- by Brett

Hi, I'm setting up a group / user based security system. I have 4 tables as follows: user groups group_user_mappings acl where acl is the mapping between an item_id and either a group or a user. The way I've done the acl table, I have 3 columns of note (actually 4th one as an auto-id, but that is irrelevant) col 1 item_id (item to access) col 3 user_id (user that is allowed to access) col 3 group_id (group that is allowed to access) So for example item1, peter, , item2, , group1 item3, jane, , so either the acl will give access to a user or a group. Any one line in the ACL table with either have an item - user mapping, or an item group. If I want to have a query that returns all objects a user has access to, I think I need to have a SQL query with a UNION, because I need 2 separate queries that join like.. item - acl - group - user AND item - acl - user This I guess will work OK. Is this how its normally done? Am I doing this the right way? Seems a little messy. I was thinking I could get around it by creating a single user group for each person, so I only ever deal with groups in my SQL, but this seems a little messy as well..

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Echoing users by group name in PHP

- by BobSapp

What I want to do is click a name of a group(every group what I create other than poweruser and admin groups) and that will echo all of the users in that group from the database. I have figured out the code so far but now my problem is how will I print it all out when clicking the name of the group? My code so far is: <h3>Groups</h3> <?php include('db.php'); if (isset($_GET["groupID"])) { $sql="SELECT `group`.*, `user`.* FROM `user` inner join `group` on group.groupID=user.groupID where group.groupID= " . mysql_real_escape_string($_GET["groupID"]) ; } else { $sql="SELECT * FROM `group` WHERE groupName <> 'admin' AND groupName <> 'poweruser'" ; } $result=mysql_query($sql,$connection); while($line=mysql_fetch_array($result)){ echo "<a href='index.php?page=groups&group=".$line['groupID']."'>".$line['groupName'].'</a><br />'; } mysql_free_result($result); mysql_close($connection); ?>

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Use Windows/Mac MySQL GUI over SSH Tunnel

- by Marcin

I am working on a client's website and he has hosting through 1and1. They don't allow connecting directly to their mySQL server from anywhere. I can't for instance load up a mySQL GUI on windows and just connect and work on the databases, it says host not found. His hosting account on the other hand is given access to the mySQL server even though it is in a different location. Let's say these are the servers I'm working with: His main hosting: Address: thehost.com Username: joe His mySQL server: Address: mysqlserver.com Port: 3306 Database: thedata User: dbouser The main hosting account he has comes with SSH. So if I SSH into thehost.com on port 22 and then use the mysql command to connect to mysqlserver.com, it works. I have tried to set up SSH tunneling but the problem is that it's not the mySQL server that has SSH allowed, it's the main hosting. How do I set up SSH Tunneling on both a Mac and a Windows machine so that I can run any GUI I want and I will be able to connect to the mysqlserver.com server. All based on the information above that SSH access is to thehost.com only, and thehost.com itself can connect to mysqlserver.com.

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MySQL table does not exist

- by Phanindra

I am getting following error in err file. 110803 6:51:26 InnoDB: Error: table `ims`.`temp_discoveryjobdetails` already exists in InnoDB internal InnoDB: data dictionary. Have you deleted the .frm file InnoDB: and not used DROP TABLE? Have you used DROP DATABASE InnoDB: for InnoDB tables in MySQL version <= 3.23.43? InnoDB: See the Restrictions section of the InnoDB manual. InnoDB: You can drop the orphaned table inside InnoDB by InnoDB: creating an InnoDB table with the same name in another InnoDB: database and copying the .frm file to the current database. InnoDB: Then MySQL thinks the table exists, and DROP TABLE will InnoDB: succeed. InnoDB: You can look for further help from InnoDB: http://dev.mysql.com/doc/refman/5.1/en/innodb-troubleshooting.html And when I do the same, like copying the frm file from other database to here and drop the table, i am getting following error, InnoDB: Error: trying to load index PRIMARY for table ims/temp_discoveryjobdetails InnoDB: but the index tree has been freed! 110803 6:50:26 InnoDB: Error: table `ims`.`temp_discoveryjobdetails` does not exist in the InnoDB internal InnoDB: data dictionary though MySQL is trying to drop it. InnoDB: Have you copied the .frm file of the table to the InnoDB: MySQL database directory from another database? InnoDB: You can look for further help from InnoDB: http://dev.mysql.com/doc/refman/5.1/en/innodb-troubleshooting.html Please any one help me out of this. Also can any one tell me why this error is coming. EDIT: The issue is occurring only when disk size is full and when we use Truncate table. Also this is occurring only in 5.1 version but not in 5.0 version.

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MySQL binlogs seems incomplete?

- by warl0ck

I created a Database, a table and inserted some data, and found this binlog.0000001 in my log folder, but when I do mysqlbinlog binlog.0000001, it only shows stuff below, seems incomplete: (There's only two files in the log dir: binlog.000001 binlog.index) /*!40019 SET @@session.max_insert_delayed_threads=0*/; /*!50003 SET @OLD_COMPLETION_TYPE=@@COMPLETION_TYPE,COMPLETION_TYPE=0*/; DELIMITER /*!*/; # at 4 #120924 21:12:56 server id 1 end_log_pos 107 Start: binlog v 4, server v 5.5.24-0ubuntu0.12.04.1-log created 120924 21:12:56 at startup # Warning: this binlog is either in use or was not closed properly. ROLLBACK/*!*/; BINLOG ' GAVhUA8BAAAAZwAAAGsAAAABAAQANS41LjI0LTB1YnVudHUwLjEyLjA0LjEtbG9nAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAYBWFQEzgNAAgAEgAEBAQEEgAAVAAEGggAAAAICAgCAA== '/*!*/; DELIMITER ; # End of log file ROLLBACK /* added by mysqlbinlog */; /*!50003 SET COMPLETION_TYPE=@OLD_COMPLETION_TYPE*/; If this warning was the cause: Warning: this binlog is either in use or was not closed properly.. How do I force close the log? EDIT After flush logs command, I see "0 rows" affected, and a few new files, binlog.000001 binlog.000002 binlog.000003 binlog.000004 binlog.index, the contents are nearly the same as binlog.000001. Now I dropped the database, and try restore it with mysqlbinlog binlog.0* | mysql -u root -p, but the database wasn't recovered. EDIT 2 [mysqld] user = mysql pid-file = /var/run/mysqld/mysqld.pid socket = /var/run/mysqld/mysqld.sock port = 3306 basedir = /usr datadir = /var/lib/mysql tmpdir = /tmp lc-messages-dir = /usr/share/mysql skip-external-locking log-bin=/var/log/mysql/binlog binlog-do-db=mydb bind-address = 127.0.0.1 key_buffer = 16M max_allowed_packet = 16M thread_stack = 192K thread_cache_size = 8 myisam-recover = BACKUP query_cache_limit = 1M query_cache_size = 16M expire_logs_days = 10 max_binlog_size = 100M P.S /var/log/mysql{.err,.log} are both empty

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jboss 5.1 mysql connection pooling

- by boyd4715

I am using JBOSS 5.1.0.GA, MySQL 5.5 and Hibernate 3.3.1 GA (included with JBOSS) + Spring. My question is do I need to add c3p0 as a data source in my spring/hibernate configuration for connection pooling or are the setting in the JBOSS mysql-ds.xml setting enough. My mysql-ds.xml is the following: <datasources> <local-tx-datasource> <jndi-name>MySqlDS</jndi-name> <connection-url>jdbc:mysql://localhost:3306/ecotrak</connection-url> <driver-class>com.mysql.jdbc.Driver</driver-class> <user-name>ecotrak</user-name> <password>ecotrak</password> <min-pool-size>5</min-pool-size> <max-pool-size>20</max-pool-size> <idle-timeout-minutes>5</idle-timeout-minutes> <exception-sorter-class-name>org.jboss.resource.adapter.jdbc.vendor.MySQLExceptionSorter</exception-sorter-class-name>  <valid-connection-checker-class-name>org.jboss.resource.adapter.jdbc.vendor.MySQLValidConnectionChecker</valid-connection-checker-class-name>    <metadata> <type-mapping>mySQL</type-mapping> </metadata> </local-tx-datasource> </datasources>

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Updated XAMPP with MySQL, all my tables are missing

- by user371699

I just updated XAMPP to a newer version, which included updating MySQL from 5.5 to 5.6. Using phpMyAdmin, however, all of my tables within my databases still appear on the left navigation panel, but the main window shows that all my databases are empty (except for information_schema, and a couple other default tables.) Clicking on a table in the navigation panel gives me a "table doesn't exist" message. It does looks like information_schema.tables doesn't have my tables, either. Can anyone assist me with this? I did make a complete backup of all my databases before the upgrade, but I first want to see if I can fix this the "normal" way. Furthermore, I'm not sure if the MySQL upgrade involved making changes to the information/performance databases, so I don't know if I can restore the old ones. Thank you. EDIT: Continuing my searching, I realized that only the INNODB databases are missing. I've tried running the following with no avail: /opt/lampp/bin $ sudo ./mysql_install_db --basedir=/opt/lampp and /opt/lampp/bin $ sudo ./mysql_install_db --basedir=/opt/lampp --datadir=/opt/lampp/var/mysql The my.cnf file in /opt/lampp/etc contains the following InnoDB settings: innodb_data_home_dir = /opt/lampp/var/mysql/ innodb_data_file_path = ibdata1:10M:autoextend innodb_log_group_home_dir = /opt/lampp/var/mysql/ # You can set .._buffer_pool_size up to 50 - 80 % # of RAM but beware of setting memory usage too high innodb_buffer_pool_size = 16M # Deprecated in 5.6 #innodb_additional_mem_pool_size = 2M # Set .._log_file_size to 25 % of buffer pool size innodb_log_file_size = 5M innodb_log_buffer_size = 8M innodb_flush_log_at_trx_commit = 1 innodb_lock_wait_timeout = 50 What could possibly be wrong? Why is the information_schema not updating correctly? It looks like /opt/lampp/var/mysql has all my tables in it within the database directories, but they're still not showing up in information_schema.

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Cannot start MySQL

- by Mohamed Nour El-Din

I used this command from shell to repair all Databases mysqlcheck -u root -p --auto-repair --check --optimize --all-databases and after that I restarted the server when it came back alive again I tried to open my vBulletin forum but I recived Database error message. and also tried to open phpMyAdmin but I received this error : #2002 - The server is not responding (or the local MySQL server's socket is not correctly configured). I checked the services list and found that the MySQL Service is not listed, so I tried to start it from shell I receive this error : Starting MySQL.Manager of pid-file quit without updating fi[FAILED] could anyone help me in that ? thanks in advance. update I found these lines in the log file 101101 01:36:01 mysqld started 101101 1:36:01 [Warning] Asked for 196608 thread stack, but got 126976 101101 1:36:01 [ERROR] /usr/sbin/mysqld: Table './mysql/user' is marked as crashed and last (automatic?) repair failed 101101 1:36:01 [ERROR] /usr/sbin/mysqld: Table './mysql/user' is marked as crashed and last (automatic?) repair failed 101101 1:36:01 [ERROR] Fatal error: Can't open and lock privilege tables: Table './mysql/user' is marked as crashed and last (automatic?) repair failed 101101 01:36:01 mysqld ended What should I do then ?

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