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  • Objective c string formatter for distances

    - by nevan
    I have a distance as a float and I'm looking for a way to format it nicely for human readers. Ideally, I'd like it to change from m to km as it gets bigger, and to round the number nicely. Converting to miles would be a bonus. I'm sure many people have had a need for one of these and I'm hoping that there's some code floating around somewhere. Here's how I'd like the formats: 0-100m: 47m (as a whole number) 100-1000m: 325m or 320m (round to the nearest 5 or 10 meters) 1000-10000m: 1.2km (round to nearest with one decimal place) 10000m +: 21km If there's no code available, how can I write my own formatter? Thanks

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  • How does string comparison work in OCAML?

    - by Steve Rowe
    From what I can tell, = and != is supposed to work on strings in OCAML. I'm seeing strange results though which I would like to understand better. When I compare two strings with = I get the results I expect: # "steve" = "steve";; - : bool = true # "steve" = "rowe";; - : bool = false but when I try != I do not: # "steve" != "rowe";; - : bool = true # "steve" != "steve";; (* unexpected - shouldn't this be false? *) - : bool = true Can anyone explain? Is there a better way to do this?

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  • parsing a string based on specified identifiers

    - by jml
    Let's say that I have the following text: input = "one aaa and bbb two bbbb er ... // three cccc" I would like to parse this into a group of variables that contain criteria = ["one", "two", "three"] v1,v2,v3 = input.split(criteria) I know that the example above won't work, but is there some utility in python that would allow me to use this sort of approach? I know what the identifiers will be in advance, so I would think that there has got to be a way to do this... Thanks for any help, jml

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  • String Connection Issue

    - by Nano HE
    Hi, Could you please have a look at my code below. #!C:\Perl\bin\perl.exe use strict; use warnings; use Data::Dumper; my $fh = \*DATA; my $str1 = "listBox1.Items.Add(\""; my $str2 = "\")\;"; while(my $line = <$fh>) { $line=~s/^\s+//g; print $str1.$line.$str2; chomp($line); } __DATA__ Hello World Output: D:\learning\perl>test.pl listBox1.Items.Add("Hello ");listBox1.Items.Add("World "); D:\learning\perl> Style error. I want the style below. Is ther anything wrong about my code? thanks. D:\learning\perl>test.pl listBox1.Items.Add("Hello"); listBox1.Items.Add("World"); D:\learning\perl>

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  • Trim function in C, to trim in place (without returning the string)

    - by user364100
    I can't figure out what to do to make this work. Here's my code: char* testStr = " trim this "; char** pTestStr = &testStr; trim(pTestStr); int trim(char** pStr) { char* str = *pStr; while(isspace(*str)) { (*pStr)++; str++; } if(*str == 0) { return 0; } char *end = str + strlen(str) - 1; while(end > str && isspace(*end)) end--; *(end+1) = 0; return 0; } I get an access violation on *(end+1) = 0;, but I can't declare my testStr[] as such to avoid that, because I can't pass the pointers that way. Any ideas?

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  • String Manipulation: Spliting Delimitted Data

    - by Milli Szabo
    I need to split some info from a asterisk delimitted data. Data Format: NAME*ADRESS LINE1*ADDRESS LINE2 Rules: 1. Name should be always present 2. Address Line 1 and 2 might not be 3. There should be always three asterisks. Samples: MR JONES A ORTEGA*ADDRESS 1*ADDRESS2* Name: MR JONES A ORTEGA Address Line1: ADDRESS 1 Address Line2: ADDRESS 2 A PAUL*ADDR1** Name: A PAUL Address Line1: ADDR1 Address Line2: Not Given My algo is: 1. Iterate through the characters in the line 2. Store all chars in a temp variables until first * is found. Reject the data if no char is found before first occurence of asterisk. If some chars found, use it as the name. 3. Same as step 2 for finding address line 1 and 2 except that this won't reject the data if no char is found My algo looks ugly. The code looks uglier. Spliting using //* doesn't work either since name can be replaced with address line 1 If the data is *Address 1*Address2, split will create two indexes in the array where index 0 will have the value of Address 1 and index 2 will have the value of Address2. Where's the name. Was there a name? Any suggestion?

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  • Transform Search String into FullText Compatible Search String?

    - by Alex
    I'm working with the fulltext search engine of MSSQL 2008 which expects a search string like this: ("keyword1" AND "keyword2*" OR "keyword3") My users are entering things like this: engine 2009 "san francisco" hotel december xyz stuff* "in miami" 1234 something or "something else" I'm trying to transform these into fulltext engine compatible strings like these: ("engine" AND "2009") ("san francisco" AND "hotel" AND "december" AND "xyz") ("stuff*" "in miami" "1234") ("something" OR "something else") I have a really difficult time with this, tried doing it using counting quotation marks, spaces and inserting etc. but my code looks like horrible for-and-if vomit. Can someone help?

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  • javascript string exec strange behavior

    - by Michael
    have funciton in my object which is called regularly. parse : function(html) { var regexp = /...some pattern.../ var match = regexp.exec(html); while (match != null) { ... match = regexp.exec(html); } ... var r = /...pattern.../g; var m = r.exec(html); } with unchanged html the m returns null each other call. let's say parse(html);// ok parse(html);// m is null!!! parse(html);// ok parse(html);// m is null!!! // ...and so on... is there any index or somrthing that has to be reset on html ... I'm really confused. Why match always returns proper result?

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  • pgf/tikz: String Symbols as Input Coordinates

    - by red_lynx
    Hi all, I'm new to pgf so i was trying out some examples from the pgfplot manual. One example is especially relevant for my current task but, alas, it would not compile. Here is the code: \documentclass[11pt]{article} \usepackage{tikz} \usepackage{pgfplots} \begin{document} \begin{tikzpicture} \begin{axis}[symbolic x coords={a,b,c,d,e,f,g,h,i}] \addplot+[smooth] coordinates { (a,42) (b,50) (c,80) (f,60) (g,62) (i,90)}; \end{axis} \end{tikzpicture} \end{document} the compiler quits with the following error: ! Package PGF Math Error: Could not parse input 'a' as a floating point number, sorry. The unreadable part was near 'a'.. I have no clue how to correct this behavior. Other plots (smooth, scatter, bar), which contain only numerical data compile fine. Could anybody give me a hint? Cheers K.

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  • String Utility Library for Code Generation

    - by Adam Barney
    CodeSmith has a nice StringUtils class that can be used to change database object names to singular, plural, camel case, pascal case, etc... Very useful for creating data access layers in their code generation tool. I'm trying to port some CodeSmith templates to the T4 template files used by Visual Studio, and I'm trying to find a similar library to do these things. There must be one somewhere in T4, since that's what is used to produce the LINQ to SQL classes, and it does a nice job of pluralization / singularization. Does anyone know where this library exists, or if a free library with similar functionality exists somewhere? Thanks!

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  • String Manipulation: Splitting Delimitted Data

    - by Milli Szabo
    I need to split some info from a asterisk delimitted data. Data Format: NAME*ADRESS LINE1*ADDRESS LINE2 Rules: 1. Name should be always present 2. Address Line 1 and 2 might not be 3. There should be always three asterisks. Samples: MR JONES A ORTEGA*ADDRESS 1*ADDRESS2* Name: MR JONES A ORTEGA Address Line1: ADDRESS 1 Address Line2: ADDRESS 2 A PAUL*ADDR1** Name: A PAUL Address Line1: ADDR1 Address Line2: Not Given My algo is: 1. Iterate through the characters in the line 2. Store all chars in a temp variables until first * is found. Reject the data if no char is found before first occurence of asterisk. If some chars found, use it as the name. 3. Same as step 2 for finding address line 1 and 2 except that this won't reject the data if no char is found My algo looks ugly. The code looks uglier. Spliting using //* doesn't work either since name can be replaced with address line 1 if the data was *Address 1*Address2. Any suggestion?

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  • PostgreSQL String search for partial patterns removing exrtaneous characters

    - by tbrandao
    Looking for a simple SQL (PostgreSQL) regular expression or similar solution (maybe soundex) that will allow a flexible search. So that dashes, spaces and such are omitted during the search. As part of the search and only the raw characters are searched in the table.: Currently using: SELECT * FROM Productions WHERE part_no ~* '%search_term%' If user types UTR-1 it fails to bring up UTR1 or UTR 1 stored in the database. But the matches do not happen when a part_no has a dash and the user omits this character (or vice versa) EXAMPLE search for part UTR-1 should find all matches below. UTR1 UTR --1 UTR 1 any suggestions...

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  • Computed column should result to string

    - by strakastroukas
    Here is a snap of my database. Both col1 and col2 are declared as int. My ComputedColumn currently adds the Columns 1 and 2, as follows... col1 col2 ComputedColumn 1 2 3 4 1 5 Instead of this, my ComputedColumn should join the columns 1 and 2 (includimg the '-' character in the middle) as follows... col1 col2 ComputedColumn 1 2 1-2 4 1 4-1 So, what is the correct syntax?

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  • How to replace empty string with zero in comma-separated string?

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

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  • Spotting similarities and patterns within a string - Python

    - by RadiantHex
    Hi folks, this is the use case I'm trying to figure this out for. I have a list of spam subscriptions to a service and they are killing conversion rate and other usability studies. The emails inserted look like the following: [email protected] [email protected] [email protected] roger[...]_surname[...]@hotmail.com What would be your suggestions on spotting these entries by using an automated script? It feels a little more complicated than it actually looks. Help would be very much appreciated!

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  • Converting the value from string to integer in a nested dictionary

    - by tom smith
    I want to change the numbers in my dictionary to int values for use later in my program. So far I have import time import math x = 400 y = 300 def read_next_object(file): obj = {} for line in file: if not line.strip(): continue line = line.strip() key, val = line.split(": ") if key in obj and key == "Object": yield obj obj = {} obj[key] = val yield obj planets = {} with open( "smallsolar.txt", 'r') as f: for obj in read_next_object(f): planets[obj["Object"]] = obj print(planets) scale=250/int(max([planets[x]["Orbital Radius"] for x in planets if "Orbital Radius" in planets[x]])) print(scale) and the output is {'Sun': {'Object': 'Sun', 'Satellites': 'Mercury,Venus,Earth,Mars,Jupiter,Saturn,Uranus,Neptune,Ceres,Pluto,Haumea,Makemake,Eris', 'Orbital Radius': '0', 'RootObject': 'Sun', 'Radius': '20890260'}, 'Moon': {'Object': 'Moon', 'Orbital Radius': '18128500', 'Period': '27.321582', 'Radius': '1737000.10'}, 'Earth': {'Object': 'Earth', 'Satellites': 'Moon', 'Orbital Radius': '77098290', 'Period': '365.256363004', 'Radius': '6371000.0'}} 3.2426140709476178e-06 I want to be able to convert the numbers in the dict to ints for further use. Any help in greatly appreciated.

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  • Remove first and last characters from a string in Lisp

    - by powerj1984
    I am passing in command line arguments to my Lisp program and they are formatted like this when they hit my main function: ("1 1 1" "dot" "2 2 2") I have a dot function and would like to call it directly from the argument, but first I must strip the " characters. I tried variations of this function: (defun remove-quotes (s) (setf (aref s 0) '"")) to no avail, Lisp complains that "" is not a member of base-char. Thanks!

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