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  • Create xml file to be used in wordpress post import

    - by adedoy
    Alright here is the thing, I have this site that was once wordpress but have been converted into 70+ static pages, the admin is deleted and the whole site is static(which means every page is in index.html), I want to create a script that makes an xml so that I will just have to import it in the new wordpress install. So far, I am able to create an XML but it only imports one post. The data source is the URL of a page and I use jquery $get to filter only to gather the post of a given archive. //html <input type="text" class="full_path"> <input type="button" value="Get Data" class="getdata"> //script $('.getdata').click(function(){ $.get($('.full_path').val(), function(data) { post = $(data).find('div [style*="width:530px;"]'); $('.result').html(post.html()); }); });//get Data Through AJAX I send the cleaned data into a php below that creates the XML: $file = 'newpost.xml'; $post_data = $_REQUEST['post_data']; // Open the file to get existing content $current = file_get_contents($file); // Append a new post to the file $catStr = ''; if(isset($post_data['categories']) && count($post_data['categories']) > 0){ foreach($post_data['categories'] as $category) { $catStr .= '<category domain="category" nicename="'.$category.'"><![CDATA['.$category.']]></category>'; } } $tagStr = ''; if(isset($post_data['tags']) && count($post_data['tags']) > 0){ foreach($post_data['tags'] as $tag) { $tagStr = '<category domain="post_tag" nicename="'.$tag.'"><![CDATA['.$tag.']]></category>'; } } $post_name = str_replace(' ','-',$post_data["title"]); $post_name = str_replace(array('"','/',':','.',',','[',']','“','”'),'',strtolower($post_name)); $post_date = '2011-4-0'.rand(1, 29).''.rand(1, 12).':'.rand(1, 59).':'.rand(1, 59); $pubTime = rand(1, 12).':'.rand(1, 59).':'.rand(1, 59).' +0000'; $post = ' <item> <title>'.$post_data["title"].'</title> <link>'.$post_data["link"].'</link> <pubDate>'.$post_data["date"].' '.$pubTime.'</pubDate> <dc:creator>admin</dc:creator> <guid isPermaLink="false">http://localhost/saunders/?p=1</guid> <description></description> <content:encoded><![CDATA['.$post_data["content"].']]></content:encoded> <excerpt:encoded><![CDATA[]]></excerpt:encoded> <wp:post_id>1</wp:post_id> <wp:post_date>'.$post_date.'</wp:post_date> <wp:post_date_gmt>'.$post_date.'</wp:post_date_gmt> <wp:comment_status>open</wp:comment_status> <wp:ping_status>open</wp:ping_status> <wp:post_name>'.$post_name.'</wp:post_name> <wp:status>publish</wp:status> <wp:post_parent>0</wp:post_parent> <wp:menu_order>0</wp:menu_order> <wp:post_type>post</wp:post_type> <wp:post_password></wp:post_password> <wp:is_sticky>0</wp:is_sticky> '.$catStr.' '.$tagStr.' <wp:postmeta> <wp:meta_key>_edit_last</wp:meta_key> <wp:meta_value><![CDATA[1]]></wp:meta_value> </wp:postmeta> </item> '; // Write the contents back to the file with the appended post file_put_contents($file, $current.$post); After being appended I add the code below to complete the xml rss tag </channel> </rss> If I look and compare the xml file of one that is exported from a wordpress site, I see little difference. Please HELP!! here is a sample of a generated xml: <?xml version="1.0" encoding="UTF-8" ?> <rss version="2.0" xmlns:excerpt="http://wordpress.org/export/1.2/excerpt/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:wp="http://wordpress.org/export/1.2/" > <channel> <title>lols why</title> <link>http://localhost/lols</link> <description>Just another WordPress site</description> <pubDate>Wed, 03 Oct 2012 04:24:04 +0000</pubDate> <language>en-US</language> <wp:wxr_version>1.2</wp:wxr_version> <wp:base_site_url>http://localhost/lols</wp:base_site_url> <wp:base_blog_url>http://localhost/lols</wp:base_blog_url> <wp:author><wp:author_id>1</wp:author_id><wp:author_login>adedoy</wp:author_login><wp:author_email>[email protected]</wp:author_email><wp:author_display_name><![CDATA[adedoy]]></wp:author_display_name><wp:author_first_name><![CDATA[]]></wp:author_first_name><wp:author_last_name><![CDATA[]]></wp:author_last_name></wp:author> <generator>http://wordpress.org/?v=3.4.1</generator> <item> <title>Sample lift?</title> <link>../../breast-lift/delaware-breast-surgery-do-i-need-a-breast-lift/</link> <pubDate>Wed, 03 Oct 2012 9:29:16 +0000</pubDate> <dc:creator>admin</dc:creator> <guid isPermaLink="false">http://localhost/lols/?p=1</guid> <description></description> <content:encoded><![CDATA[<p>sample</p>]]></content:encoded> <excerpt:encoded><![CDATA[]]></excerpt:encoded> <wp:post_id>1</wp:post_id> <wp:post_date>2011-4-0132:45:4</wp:post_date> <wp:post_date_gmt>2011-4-0132:45:4</wp:post_date_gmt> <wp:comment_status>open</wp:comment_status> <wp:ping_status>open</wp:ping_status> <wp:post_name>sample-lift?</wp:post_name> <wp:status>publish</wp:status> <wp:post_parent>0</wp:post_parent> <wp:menu_order>0</wp:menu_order> <wp:post_type>post</wp:post_type> <wp:post_password></wp:post_password> <wp:is_sticky>0</wp:is_sticky> <category domain="category" nicename="Sample Lift"><![CDATA[Sample Lift]]></category><category domain="category" nicename="Sample Procedures"><![CDATA[Yeah Procedures]]></category> <category domain="post_tag" nicename="delaware"><![CDATA[delaware]]></category> <wp:postmeta> <wp:meta_key>_edit_last</wp:meta_key> <wp:meta_value><![CDATA[1]]></wp:meta_value> </wp:postmeta> </item> <item> <title>lalalalalala</title> <link>../../administrative-tips-for-surgery/delaware-cosmetic-surgery-a-better-experience/</link> <pubDate>Wed, 03 Oct 2012 3:20:43 +0000</pubDate> <dc:creator>admin</dc:creator> <guid isPermaLink="false">http://localhost/lols/?p=1</guid> <description></description> <content:encoded><![CDATA[ lalalalalala ]]></content:encoded> <excerpt:encoded><![CDATA[]]></excerpt:encoded> <wp:post_id>1</wp:post_id> <wp:post_date>2011-4-0124:39:30</wp:post_date> <wp:post_date_gmt>2011-4-0124:39:30</wp:post_date_gmt> <wp:comment_status>open</wp:comment_status> <wp:ping_status>open</wp:ping_status> <wp:post_name>lalalalalala</wp:post_name> <wp:status>publish</wp:status> <wp:post_parent>0</wp:post_parent> <wp:menu_order>0</wp:menu_order> <wp:post_type>post</wp:post_type> <wp:post_password></wp:post_password> <wp:is_sticky>0</wp:is_sticky> <category domain="category" nicename="lalalalalala"><![CDATA[lalalalalala]]></category> <category domain="post_tag" nicename="oink"><![CDATA[oink]]></category> <wp:postmeta> <wp:meta_key>_edit_last</wp:meta_key> <wp:meta_value><![CDATA[1]]></wp:meta_value> </wp:postmeta> </item> </channel> </rss> Please tell me what am I missing....

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  • How to write CData in xml

    - by Rajesh Rolen- DotNet Developer
    i have an xml like : <?xml version="1.0" encoding="UTF-8"?> <entry> <entry_id></entry_id> <entry_status></entry_status> </entry> i am writing data in it like: XmlNode xnode = xdoc.SelectSingleNode("entry/entry_status"); xnode.InnerText = "<![CDATA[ " + Convert.ToString(sqlReader["story_status"]) + " ]]>" ; but its change "<" to "&lt" of CDATA. Please tell me how to fill values in above xml as a CData format. i know that we can create CDATA like : XmlNode itemDescription = doc.CreateElement("description"); XmlCDataSection cdata = doc.CreateCDataSection("<P>hello world</P>"); itemDescription.AppendChild(cdata); item.AppendChild(itemDescription); but my process is to read node of xml and change its value not to append in it. Thanks

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  • XML Serializing a class with a Dictionary<string, List<string>> object

    - by Matt
    Is it possible to implement IXmlSerializable and in my XML file capture an object of type Dictionary ? I have the following public class coolio : IXmlSerializable { private int a; private bool b; private string c; private Dictionary<string, List<string>> coco; public coolio(int _a, bool _b, string _c, Dictionary<string, List<string>> _coco) { a=_a; b=_b; c=_c; coco=_coco; } public System.Xml.Schema.XmlSchema GetSchema() { return null; } public void WriteXml(XmlWriter writer) { const string myType = "coolio"; writer.WriteStartElement(myType); writer.WriteAttributeString("a", a.ToString()); writer.WriteAttributeString("b", b.ToString()); writer.WriteAttributeString("c", c); // How do I add a subelement for Dictionary<string, List<string>> coco? writer.WriteEndElement(); } public void ReadXml(XmlReader reader) { if (reader.MoveToContent() != XmlNodeType.Element || reader.LocalName != "coolio") return; a= int.Parse(reader["a"]); b = bool.Parse(reader["b"]); c= reader["c"]; // How do I read subelement into Dictionary<string, List<string>> coco? } } But I am stumped as to how I could add the Dictionary (XML seriliazed to my XML file)

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  • xml attribure in dataset

    - by raging_boner
    I want to bind Repeater control to Dataset which is filled with XML data, but i don't know how to show attributes inside repeater. Xml File: <root> <items> <item id="9" name="111111111111" description="111111245" views="1" galleryID="0" /> </items> </root> Repeater code: <asp:Repeater ID="rptrGalleries" runat="server"> <ItemTemplate> <a href='Page?id=<%#DataBinder.Eval(Container.DataItem, "id") %>'><%#DataBinder.Eval(Container.DataItem, "name") %></a> </ItemTemplate> </asp:Repeater> Codebehind: XDocument doc = XDocument.Load(Server.MapPath("~/xml/gallery.xml")); IEnumerable<XElement> items = from item in doc.Descendants("item") orderby Convert.ToDateTime(item.Attribute("lastChanges").Value) descending where int.Parse(item.Attribute("galleryID").Value) == 0 && bool.Parse(item.Attribute("visible").Value) != false select item; DataSet ds = new DataSet(); ds.ReadXml(new StringReader(doc.ToString())); rptrGalleries.DataSource = ds; rptrGalleries.DataBind(); When I compile site I receive this error: System.Web.HttpException: DataBinding: 'System.Data.DataRowView' does not contain a property with the name 'id'.

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  • Output array of XML to plain XML

    - by danit
    I have a script which collects 4 URL's (XML) using CURL and returns an array with 4 items each ocntaining the results of the URL's. Here is the array: array(3) { [0]=> string(41772) "<?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created_at>Tue Mar 30 20:58:53 +0000 2010</created_at> <id>11328253513</id> <text>...</text> <source...</source> <truncated>false</truncated> <in_reply_to_status_id></in_reply_to_status_id> <in_reply_to_user_id></in_reply_to_user_id> <favorited>true</favorited> <in_reply_to_screen_name></in_reply_to_screen_name> <user> <id>1...</id> <name>....</name> </status> </statuses> " [1]=> string(20630) "<?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created_at>Sun Feb 28 14:12:30 +0000 2010</created_at> <id>...</id> <text>...</text> <source>&lt;a etc... How can I easily output the XML from the array? I also need to combine the 3 XML structures into one where begins and ends in between each array.

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  • XmlDocument.Load() throws XmlSchemaValidationException

    - by Praetorian
    Hi, I'm trying to validate an XML document against a schema (which is embedded in my program as a resource). I got everything to work, so I tried to test for errors by adding a second sibling node in the XML at a location where the schema specifies maxOccurs="1". The problem is that my ValidationEventHandler is never getting called, also XmlDocument.Load() is throwing an XmlSchemaValidationException exception when I'd expected XmlDocument.Validate() to do that. This is the code I have: private void ValidateUserData( string xmlPath ) { var resInfo = Application.GetResourceStream( new Uri( @"MySchema.xsd", UriKind.Relative ) ); var schema = XmlSchema.Read( resInfo.Stream, SchemaValidationCallBack ); XmlSchemaSet schemaSet = new XmlSchemaSet(); schemaSet.Add( schema ); schemaSet.ValidationEventHandler += SchemaValidationCallBack; XmlReaderSettings settings = new XmlReaderSettings(); settings.Schemas = schemaSet; settings.ValidationType = ValidationType.Schema; XmlDocument doc = new XmlDocument(); using( XmlReader reader = XmlReader.Create( xmlPath, settings ) ) { doc.Load( reader ); // <-- This line throws an exception if XML is ill-formed reader.Close(); } doc.Validate( SchemaValidationCallBack );// <-- This is never reached } private void SchemaValidationCallBack( object sender, ValidationEventArgs e ) { Console.WriteLine( "SchemaValidationCallBack: " + e.Message ); } How do I get the callback to be called so I can handle validation errors? Thanks for your help!

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  • PHP XML Parsing

    - by ashchawla
    Hi I am making get request in PHP but the parser is having issues. I am looking for a way to retreive the value of URL in the following example. The response xml looks like this. <?xml version="1.0" encoding="iso-8859-1" standalone="no"?> <testtemplate JobName="test1"> <Sources> <Source xmlns="http://www.microsoft.com/test/schema/api"> <System> <SystemIdentifier>HTTPS</SystemIdentifier> <URL>http://example.com</URL> </System> </Source> </Sources> <testtemplate> and my PHP code looks like this: $xml = DOMDocument::LoadXML($response); $mypath = new DOMXPath($xml); $mypath->registerNamespace("a", "http://www.microsoft.com/test/schema/api"); $url = $mypath->evaluate("/testtemplate/Sources/Source/System/URL"); $message = $url->item(0)->value; print($message); Any help would be appreciated. Thanks Ashish

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  • Add xml-stylesheet and get standalone = yes.

    - by tumba25
    The code at the bottom is what I have. I removed the creation of all tags. At the top in the xml file I get.<?xml version="1.0" encoding="UTF-8" standalone="no"?> Note that standalone is no, even thou I have it set to yes. The first question: How do I get standalone = yes? I would like to add <?xml-stylesheet type="text/xsl" href="my.stylesheet.xsl"?> at line two in the xml file. Second question: How do I do that? Some useful links? Anything? DocumentBuilderFactory dbfac = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = dbfac.newDocumentBuilder(); Document doc = docBuilder.newDocument(); <cut> TransformerFactory transfac = TransformerFactory.newInstance(); transfac.setAttribute("indent-number", new Integer(2)); Transformer trans = transfac.newTransformer(); trans.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no"); trans.setOutputProperty(OutputKeys.STANDALONE, "yes"); trans.setOutputProperty(OutputKeys.INDENT, "yes"); trans.setOutputProperty(OutputKeys.CDATA_SECTION_ELEMENTS, "name"); FileOutputStream fout = new FileOutputStream(filepath); BufferedOutputStream bout= new BufferedOutputStream(fout); trans.transform(new DOMSource(doc), new StreamResult(new OutputStreamWriter(bout, "utf-8")));

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  • Producing a static HTML site from XML content

    - by Skilldrick
    I have a long document in XML from which I need to produce static HTML pages (for distribution via CD). I know (to varying degrees) JavaScript, PHP and Python. The current options I've considered are listed here: I'm not ruling out JavaScript, so one option would be to use ajax to dynamically load the XML content into HTML pages. Learn some basic XSLT and produce HTML to the correct spec this way. Produce the site with PHP (for example) and then generate a static site. Write a script (in Python for example) to convert the XML into HTML. This is similar to the XSLT option but without having to learn XSLT. Useful information: The XML will likely change at some point, so I'd like to be able to easily regenerate the site. I'll have to produce some kind of menu for jumping around the document (so I'll need to produce some kind of index of the content). I'd like to know if anyone has any better ideas that I haven't thought of. If not, I'd like you to tell me which of my options seems the most sensible. I think I know what I'm going to do, but I'd like a second opinion. Thanks.

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  • Converting Python Script to Vb.NET - Involves Post and Input XML String

    - by Jason Shoulders
    I'm trying to convert a Python Script to Vb.Net. The Python Script appears to accept some XML input data and then takes it to a web URL and does a "POST". I tried some VB.NET code to do it, but I think my approach is off because I got an error back "BadXmlDataErr" plus I can't really format my input XML very well - I'm only doing string and value. The input XML is richer than that. Here is an example of what the XML input data looks like in the Python script: <obj is="MyOrg:realCommand_v1/" > <int name="priority" val="1" /> <real name="value" val="9.5" /> <str name="user" val="MyUserName" /> <reltime name="overrideTime" val="PT60S"/> </obj> Here's the Vb.net code I attempted to convert that: Dim reqparm As New Specialized.NameValueCollection reqparm.Add("priority", "1") reqparm.Add("value", "9.5") reqparm.Add("user", "MyUserName") reqparm.Add("overrideTime", "PT60S") Using client As New Net.WebClient Dim sTheUrl As String = "[My URL]" Dim responsebytes = client.UploadValues(sTheUrl, "POST", MyReqparm) Dim responsebody = (New System.Text.UTF8Encoding).GetString(responsebytes) End Using I feel like I should be doing something else. Can anyone point me to the right direction?

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  • How to compare dictonary key with xml attribute value in xml using LINQ in c #?

    - by Pramodh
    Dear all, i've a dictonary " dictSample " which contains 1 data1 2 data2 3 data3 4 data4 and an xml file"sample.xml" in the form of: <node> <element id="1" value="val1"/> <element id="2" value="val2"/> <element id="3" value="val3"/> <element id="4" value="val4"/> <element id="5" value="val5"/> <element id="6" value="val6"/> <element id="7" value="val7"/> </node> i need to match the dictonary keys with the xml attribute id and to insert the matching id and the value of attribute"value" into another dictonary now i'm using like: XmlDocument XDOC = new XmlDocument(); XDOC.Load("Sample.xml"); XmlNodeList NodeList = XDOC.SelectNodes("//element"); Dictionary<string, string> dictTwo = new Dictionary<string, string>(); foreach (string l_strIndex in dictSample .Keys) { foreach (XmlNode XNode in NodeList) { XmlElement XEle = (XmlElement)XNode; if (dictSample[l_strIndex] == XEle.GetAttribute("id")) dictTwo.Add(dictSample[l_strIndex], XEle.GetAttribute("value").ToString()); } } please help me to do this in a simple way using LINQ

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  • Parsing XML in Javascript getElementsByTagName not working

    - by Probocop
    Hi, I am trying to parse the following XML with javascript: <?xml version='1.0' encoding='UTF-8'?> <ResultSet> <Result> <URL>www.asd.com</URL> <Value>10500</Value> </Result> </ResultSet> The XML is generated by a PHP script to get how many pages are indexed in Bing. My javascript function is as follows: function bingIndexedPages() { ws_url = "http://archreport.epiphanydev2.co.uk/worker.php?query=bingindexed&domain="+$('#hidden_the_domain').val(); $.ajax({ type: "GET", url: ws_url, dataType: "xml", success: function(xmlIn){ alert('success'); result = xmlIn.getElementsByTagName("Result"); $('#tb_actualvsindexedbing_indexed').val($(result.getElementsByTagName("Value")).text()); $('#img_actualvsindexedbing_worked').attr("src","/images/worked.jpg"); }, error: function() {$('#img_actualvsindexedbing_worked').attr("src","/images/failed.jpg");} }); } The problem I'm having is firebug is saying: 'result.getElementsByTagName is not a function' Can you see what is going wrong? Thanks

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  • Using FOR XML AUTO against a synonym

    - by Rick
    We've just switched to synonyms for linked server stuff, and noticed that our FOR XML output is no longer correct. When returning XML results from a view, we could alias the view and that would be assigned as the element name. With synonyms, however, it seems to ignore the alias? We're still mostly on SQL 2005 - this bug doesn't seem to happen on our 2008 instance. Is this a known problem, and any ideas for work-arounds? For example, this is what we used to be able to do: select top 3 number from Numbers as elementname for xml auto <elementname number="0"/><elementname number="1"/><elementname number="2"/> And this is what happens with a synonym: select top 3 number from Numbers_synonym as elementname for xml auto <dbo.Numbers number="0"/><dbo.Numbers number="1"/><dbo.Numbers number="2"/> As you can see, SQL Server seems to use the name of the actual referenced object instead of the alias. This gets worse for cross server queries, because you get the four-part name instead of the nice alias. (eg: <rick_server.rick_database.dbo.Numbers number="0"/>...)

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  • read xml in javascript problem

    - by Najmi
    hai all, i have a problem with my code to read the xml.I have use ajax to read xml data and populate it in combobox. My problem is it only read the first data.Here is my code my xml like this <area> <code>1</code> <name>area1</name> </area> <area> <code>2</code> <name>area2</name> </area> and my javascript if(http.readyState == 4 && http.status == 200) { //get select elements var item = document.ProblemMaintenanceForm.elements["probArea"]; //empty combobox item.options.length = 0; //read xml data from action file var test = http.responseXML.getElementsByTagName("area"); alert(test.length); for ( var i=0; i < test.length; i++ ){ var tests = test[i]; item.options[item.options.length] = new Option(tests.getElementsByTagName("name")[i].childNodes[i].nodeValue,tests.getElementsByTagName("code")[i].childNodes[i].nodeValue); } }

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  • rails xml to active record object

    - by Brian D.
    I've been googling for a while to try and convert and incoming XML request into an active record object. I've tried using the ActiveRecordObject.new.from_xml method but it doesn't seem to handle relationships. For example, say I have the following xml: <blog> <title></title> <blog-pages> <blog-page> <page-number></page-number> <content></content> </blog-page> </blog-pages> </blog> And I have the following model objects: class Blog < ActiveRecord::Base has_many :blog_pages end class BlogPage < ActiveRecord::Base belongs_to :blog end Is there a way to convert the xml into a blog object WITH relationships? Or do I need to manually parse the XML? Thanks in advance.

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  • How to append new elements to Xml from stream

    - by Wololo
    I have a method which returns some xml in a memory stream private MemoryStream GetXml() { XmlWriterSettings settings = new XmlWriterSettings(); settings.Indent = true; using (MemoryStream memoryStream = new MemoryStream()) { using (XmlWriter writer = XmlWriter.Create(memoryStream, settings)) { writer.WriteStartDocument(); writer.WriteStartElement("root"); writer.WriteStartElement("element"); writer.WriteString("content"); writer.WriteEndElement(); writer.WriteEndElement(); writer.WriteEndDocument(); writer.Flush(); } return memoryStream; } } In this example the format of the xml will be: <?xml version="1.0" encoding="utf-8"?> <root> <element>content</element> </root> How can i insert a new element under the root e.g <?xml version="1.0" encoding="utf-8"?> <root> <element>content</element> ----->New element here <------ </root>

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  • Sorting XML file through multiple attributes

    - by jbugeja
    I want to sort a 'free-form' XML file through multiple attributes (first by T and then by L). The XML is a bit complex and it is structured as shown below: <?xml version="1.0" encoding="utf-8"?> <wb xmlns:cf="http://www.macromedia.com/2004/cfform" xmlns:a="urn:dummy"> <a:form name="chart"> <a:fieldset FIELD="a" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="01" L="1" T="2" /> <a:input FIELDNUMBER="02" INDEX="4" L="200" T="1" /> </a:fieldset> <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="03" T="3" L="1" /> <a:input FIELDNUMBER="04" INDEX="7" T="4" L="200" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="05" T="10" INDEX="6" L="400" /> <a:input FIELDNUMBER="06" T="8" INDEX="8" L="200" /> </a:fieldset> </a:fieldset> <a:input FIELDNUMBER="08" INDEX="3" L="3" T="5" /> <a:input FIELDNUMBER="09" INDEX="2" L="2" T="4" /> </a:form> </wb> PS: The root element is wb and this is always followed by a:form The L and T are always found in elements that have a tag in the namespace a, the only exception being a:fieldset which does not have L and T a:fieldset could have multiple children of the namespace a including another a:fieldset We can also assume that L denotes Left and T denotes Top. So, the idea of this is that when I view the transformed XML I can immediately note which elements precede what. What's your take on this?

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  • XML File as Excel file.

    - by FrustratedWithFormsDesigner
    I have a number of reports that I run against my database that need to eventually go to the end-users as Excel spreadsheets. Initially, I was creating text reports, but the steps to convert the text to a spreadsheet were a bit cumbersome. There were too many steps to import text to the spreadsheet, and multi-line text rows were imported as individual rows in Excel (which was incorrect). Currently, I am generating simple XML saving the file with an ".xls" extension. This works better, but there is still the problem of Excel prompting the user with an XML import dialogue every time they open the file, and then having to save a new file if they add notes or change the layout to the file (which they almost certainly will be doing). Sample "xls" file: <?xml version="1.0" standalone="yes"?> <report_rows> <row> <NAME>Test Data</NAME> <COUNT>345</COUNT> </row> <!-- many more row elements... --> </report_rows> Is there any way to add markup to the file to hint to Excel how it should import and handle the file? Ideally, the end user should be able to open and save the file like any othe spreadsheet they create directly from Excel. Is this even possible? UPDATE: We are running Office 2003 here. UPDATE: The XML is generated from a sqlplus script, no option to use C#/.NET here.

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  • JavaScript, jQuery, XML - if statement not executing for unknown reason

    - by Jack Roscoe
    Hi, I have a 'for' loop which extracts data from an XML document and adds it into some JavaScript objects, each time the loop executes I want it to run a certain function depending on the value of the attribute 'typ' which is being retrieved from the xml. Currently, the data from the XML is successfully being parsed, which is proven by the first 'alert' you can see which produces the correct value. However, neither of the 'alert' lines in the 'if' statement lower down are being executed and as a result I cannot test the 'ctyp3' function which is supposed to be called. Where have I gone wrong? for (j=0; j<arrayIds.length; j++) { $(xml).find("C[ID='" + arrayIds[j] + "']").each(function(){ // pass values questions[j] = { typ: $(this).attr('typ'), width: $(this).find("I").attr('wid'), height: $(this).find("I").attr('hei'), x: $(this).find("I").attr('x'), y: $(this).find("I").attr('x'), baC: $(this).find("I").attr('baC'), boC: $(this).find("I").attr('boC'), boW: $(this).find("I").attr('boW') } alert($(this).attr('typ')); if ($(this).attr('typ') == '3') { ctyp3(x,y,width,height,baC); alert('pass'); } else { // Add here alert('fail'); } }); }

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  • Navigating sorted XML data (XSLT)

    - by Andrew Parisi
    I have an XML file with company data in it, for 30 companies across 8 industries, on a portfolio page. The user has the option to sort this data by Industry, and this XML file will be added to constantly. This sorting is done in my XSL file using <xsl:choose>. Example: <xsl:when test="(invest[@investid='con'])"> <xsl:for-each select="$invest-port/portfolio/company[@industry='Communications']"> <xsl:sort select="name" /> <div class="invest-port-thumb"> <a> <xsl:attribute name="href"> <xsl:value-of select="link" /> </xsl:attribute> </a> </div> </xsl:for-each> </xsl:when> When navigating to an individual company's page, there are "previous" and "next" buttons at the bottom of the window. My issue is that I need these to dynamically link to the previous and next elements from within the XML data that has been sorted. Is this possible? Or is there an easier way to do this? (such as place each company in industry-divided XML files instead of one) Any insight would be greatly appreciated!

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  • XML parsing problem

    - by Albinoswordfish
    I'm having this strange XML parsing problem. I have this XML string I'm trying to parse <?xml version="1.0"?> <response status="success"> <lot>32342</lot> </response> I'm using XPath with Java in order to do this. I'm using the Xpath expression "/response/@status" to find the text "success". However whenever I evaluate this expression I get an empty string. However I am able to successfully parse this string using "/response/@type" <?xml version="1.0"?> <response type="success"> <lot>32342</lot> </response> So why would simply changing the name of the attribute change the return string to nothing? is = new InputSource(testWOcreateStrGood); xPathexpressionSuccess = xPath.compile("/response/@status"); responseStr = xPathexpressionSuccess.evaluate(is); reponseStr is the string I posted earlier with the "status" attribute

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  • Problem with LINQ to XML and Namespaces

    - by abtcabe
    I am having problems with working with a third party XML string that contains a Namespace with LINQ to XML. In the below code everything works find. I am able to select the xElement (xEl1) and update its value. 'Example Without Namespace Dim XmlWithOutNs = _ <?xml version="1.0"?> <RATABASECALC> <RATEREQUEST> <ANCHOR> <DATABASENAME>DatabaseName</DATABASENAME> <DATABASEPW>DatabasePw</DATABASEPW> </ANCHOR> </RATEREQUEST> </RATABASECALC> Dim xEl1 = XmlWithOutNs...<DATABASEPW>.FirstOrDefault If xEl1 IsNot Nothing Then xEl1.Value = "test" End If However, in the below code the xElement (xEl2) returns Nothing. The only difference is the Namespace (xmlns="http://www.cgi.com/Ratabase) 'Example With Namespace Dim XmlWithNs = _ <?xml version="1.0"?> <RATABASECALC xmlns="http://www.cgi.com/Ratabase"> <RATEREQUEST> <ANCHOR> <DATABASENAME>DatabaseName</DATABASENAME> <DATABASEPW>DatabasePw</DATABASEPW> </ANCHOR> </RATEREQUEST> </RATABASECALC> Dim xEl2 = XmlWithNs...<DATABASEPW>.FirstOrDefault If xEl2 IsNot Nothing Then xEl2.Value = "test" End If So my questions are: 1. Why is this happening? 2. How do I resolve this issue?

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  • Call stored proc using xml output from a table

    - by user263097
    Under a tight deadline and I know I can figure this out eventually but I don't have much time to do it on my own. I have a table that has columns for customer id and account number among many other additional columns. There could be many accounts for a single customer (Many rows with the same customer id but different account number). For each customer in the table I need to call a stored procedure and pass data from my table as xml in the following format. Notice that the xml is for all of the customers accounts. <Accounts> <Account> <AccountNumber>12345</AccountNumber> <AccountStatus>Open</AccountStatus> </Account> <Account> <AccountNumber>54321</AccountNumber> <AccountStatus>Closed</AccountStatus> </Account> </Accounts> So I guess I need help with 2 things. First, how to get the data in this xml format. I assuming I'll use some variation of FOR XML. The other thing is how do I group by customer id and then call a sproc for each customer id?

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  • How do I insert XML into another XML file with XSLT?

    - by Sandra
    Hello, I looked at this thread to find out how to insert XML into XML with XSLT http://stackoverflow.com/questions/862954/insert-xml-node-at-a-specific-position-of-an-existing-document But I have a problem since I need to insert XML between two grand child nodes. For example I want to insert <s>...</s> between <r>...</r> and <t>...</t> in this file <root> <child1> <a>...</a> <r>...</r> <t>...</t> <z>...</z> </child1> </root> to create this file <root> <child1> <a>...</a> <r>...</r> <s>...</s> <t>...</t> <z>...</z> </child1> </root> Thanks for your help.

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