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• how to do a line break in xml ? ( xml to html )

  - by stdnoit

  trying to convert xml to html ... my line break in xml is treated as literals in html... any idea how to keep the line break from xml to html ? sorry dont have the code. not exactly my question thanks

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• Write Mysql tables to XML : Security Issue

  - by jasmine

  I want to make a news portal(php) with minimum mysql force. :create a cron, fetch data from mysql and write to a php file . (I dont know is it right way) But Can I use xml instead of php file? Write mysql data to xml. Is this a secure way? What is the best way? XML or php file? Thanks in advance

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• Help me choose between XML or SQL Lite on android

  - by Ngetha

  I have an android app that periodically, say once a week downloads content from a server in XML. The content is used by the app, different Acitivities use different parts of the content. My question is a design one, should I save the data in SQlite or just keep it as an XML file, which one would be faster to read? The app can only use one content piece at a time, which means subsequent XML content downloads replace the old one.

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• Serializing a class containing a custom class

  - by Netfangled

  I want to serialize an object as xml that contains other custom classes. From what I understand (I've been reading MSDN and SO mostly), the XmlSerializer doesn't take this into account. This is the line that's confusing me: XML serialization serializes only the public fields and property values of an object into an XML stream. XML serialization does not include type information. For example, if you have a Book object that exists in the Library namespace, there is no guarantee that it will be deserialized into an object of the same type. Taken from MSDN, here For example, I want to serialize an object of type Order, but it contains a list of Products, and each one contains an object of type Category: class Order { List<Product> products; } class Product { Category type; } class Category { string name; string description; } And I want my Order object to be serialized like so: <Order> <Product> <Category Name=""> <Description></Description> </Category> </Product> <Product> <Category Name=""> <Description></Description> </Category> </Product> <Order> Does the XmlSerializer already do this? If not, is there another class that does or do I have to define the serialization process myself?

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• Nokogiri extract data from xml

  - by Awea

  Hi guys, i try to extract data from a xml in rails application with the Nokogiri gem, the xml : <item> <description> <img src="something" title="anothething"> <p>text, bla bla...</p> </description> </item> Actually i do something like this to extract data from the xml : def test_content @return = Array.new site = 'http://www.les-encens.com/modules/feeder/rss.php?id_category=0' @doc = Nokogiri::XML(open(site, "UserAgent" => "Ruby-OpenURI")) @doc.xpath("//item").each do |n| @return << [ n.xpath('description') ] end end Could you show me how extract just the src attribute from the img tag ?

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• Sorting the output from XmlSerializer in C#

  - by prosseek

  In this post, I could get an XML file generated based on C# class. Can I reorder the XML elements based on its element? My code uses var ser = new XmlSerializer(typeof(Module)); ser.Serialize(WriteFileStream, report, ns); WriteFileStream.Close(); to get the XML file, but I need to have the XML file sorted based on a BlocksCovered variable. public class ClassInfo { public string ClassName; public int BlocksCovered; public int BlocksNotCovered; public double CoverageRate; public ClassInfo() {} public ClassInfo(string ClassName, int BlocksCovered, int BlocksNotCovered, double CoverageRate) { this.ClassName = ClassName; this.BlocksCovered = BlocksCovered; this.BlocksNotCovered = BlocksNotCovered; this.CoverageRate = CoverageRate; } } [XmlRoot("Module")] public class Module { [XmlElement("Class")] public List<ClassInfo> ClassInfoList; public int BlocksCovered; public int BlocksNotCovered; public string moduleName; public Module() { ClassInfoList = new List<ClassInfo>(); BlocksCovered = 0; BlocksNotCovered = 0; moduleName = ""; } } Module report = new Module(); ... TextWriter WriteFileStream = new StreamWriter(xmlFileName); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); var ser = new XmlSerializer(typeof(Module)); ser.Serialize(WriteFileStream, report, ns); WriteFileStream.Close();

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• Update Empty XML Tag in SQL Server

  - by monO

  I'm trying to update an empty XML Tag in my Xml string on sql server; it says the row is updated when i run the following script, but when I view the XML; nothing has changed: Declare @newValue varchar(100) select @newValue = '01' update dbo.UploadReport set XmlTest.insert('replace value of (/CodeFiveReport/Owner/AgencyID/text())[1] with sql:variable("@newValue")') where id = 'myId' The xml after still appears as this in the databse <AgencyID /> What am I doing wrong? I've tried @AgencyID without the text() at the end and still no avail...

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• Traverse a XML using Recursive function

  - by Kaja

  How can I traverse (read all the nodes in order) a XML document using recursive functions in c#? What I want is to read all the nodes in xml (which has attributes) and print them in the same structure as xml (but without Node Localname) Thanks

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• Export XML with only one MySQL request ?

  - by mere-teresa

  I want to export in XML format some data from 7 tables (MySQL database), and then I want to import in another database. And I have a update or insert rule for data. I already have a SQL query retrieving all data, with JOINs on my 7 tables. But...when I try to put data in XML format, I reach a limit. My PHP loop can catch each row, but I would like to benefit from hierachical structure of the XML, and all I have are rows with the same data repeated. It is better to query once and to construct the XML tree in PHP or to query each time I want access to a lower level ?

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• XML Database in C#.net

  - by rookieinfotech

  I am developing a WPF client program for some websites. It uses XML database. I am new to XML. Would someone please explain how to create,append(Most important),edit,read&encrypt XML file. It is a big question,i know . But, it is urgent.Have to complete the work ASAP. Searched in the internet, not getting correct info.

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• Read [for xml auto, elements] into DataTable in ADO.NET

  - by ihorko

  Hello All! I have MS SQL Server stored procedure that returns XML (it uses SELECT with for xml auto, elements) I tried read it into DataTable: DataTable retTable = new DataTable(); SqlCommand comm = new SqlCommand("exec MySP", connection); SqlDataAdapter da = new SqlDataAdapter(comm); connection.Open(); da.Fill(retTable); but retTable contains 12 rows with separated full xml thar SQL Server returns. How can I read that XML from DB into DataTable object? Thanks!

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• From Java/C++ to XML

  - by Greenhouse Gases

  I know Java and C++ but am looking to get in to XML. I don't want to waste time reading over the basics of programming in a book, so has anyone any recommendations for resources for learning XML that assume a knowledge of programming already, or even better highlight how to switch from Java/C++ to XML ie. main differences etcs.

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• Obtaining XML from U.S. Postal Service (USPS) rate calculator API with PHP

  - by Chris F

  hoping somebody here can help me. I'm attempting to pull an XML page from the U.S. Postal Service (USPS) rate calculator, using PHP. Here is the code I am using (with my API login and password replaced of course): <? $api = "http://production.shippingapis.com/ShippingAPI.dll?API=RateV4&XML=<RateV4Request ". "USERID=\"MYUSERID\" PASSWORD=\"MYPASSWORD\"><Revision/><Package ID=\"1ST\">". "<Service>FIRST CLASS</Service><FirstClassMailType>PARCEL</FirstClassMailType>". "<ZipOrigination>12345</ZipOrigination><ZipDestination>54321</ZipDestination>". "<Pounds>0</Pounds><Ounces>9</Ounces><Container/><Size>REGULAR</Size></Package></RateV4Request>"; $xml_string = file_get_contents($api); $xml = simplexml_load_string($xml_string); ?> Pretty straightforward. However it never returns anything. I can paste the URL directly into my browser's address bar: http://production.shippingapis.com/ShippingAPI.dll?API=RateV4&XML=<RateV4RequestUSERID="MYUSERID" PASSWORD="MYPASSWORD"><Revision/><Package ID="1ST"><Service>FIRST CLASS</Service><FirstClassMailType>PARCEL</FirstClassMailType><ZipOrigination>12345</ZipOrigination><ZipDestination>54321</ZipDestination><Pounds>0</Pounds><Ounces>9</Ounces><Container/><Size>REGULAR</Size></Package></RateV4Request> And it returns the XML I need, so I know the URL is valid. But I cannot seem to capture it using PHP. Any help would be tremendously appreciated. Thanks in advance.

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• Load php file wth xml header

  - by John Smith

  I have a php file with an xml header and xml code, named test.php. How do I load this file as an xml? The following doesn't work: $xml = simplexml_load_file('test.php'); echo $xml; I just get a white page. The test file is saved as php, as it's dynamic. It's loading data from the tradedoubler api. The xml looks something like this: <voucherList> <voucher> <id>115</id> <programId>111</programId> <programName>Program 111</programName> <code>AF30C5</code> <updateDate>1332422674941</updateDate> <startDate>1332370800000</startDate> <endDate>1363906800000</endDate> <title>Voucher number one</title> <shortDescription>Short description of the voucher.</shortDescription> <description>This is a long version of the voucher description.</description> <voucherTypeId>1</voucherTypeId> <defaultTrackUri>http://clk.tradedoubler.com/click?a(222)p(111)ttid(13)</defaultTrackUri> <siteSpecific>True</siteSpecific> </voucher> <voucher> <id>116</id> <programId>111</programId> <programName>Program 111</programName> <code>F90Z4F</code> <updateDate>1332423212631</updateDate> <startDate>1332370800000</startDate> <endDate>1363906800000</endDate> <title>The second voucher</title> <shortDescription>Short description of the voucher.</shortDescription> <description>This is a long version of the voucher description.</description> <voucherTypeId>1</voucherTypeId> <defaultTrackUri>http://clk.tradedoubler.com/click?a(222)p(111)ttid(13)url(http://www.example.com/product?id=123)</defaultTrackUri> <siteSpecific>False</siteSpecific> <landingUrl>http://www.example.com/product?id=123</landingUrl> </voucher> </voucherList>

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• Java: Writing a DOM to an XML file (formatting issues)

  - by Vhaerun

  I'm using org.w3c XML API to open an existing XML file. I'm removing some nodes , and I'm adding others instead . The problem is that the new nodes that are added are written one after another , with no newline and no indentation what so ever. While it's true that the XML file is valid , it is very hard for a human to examnine it. Is there anyway to add indentation , or at least a newline after each node ?

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• receive xml file as a parameter to a .net web service

  - by fizch

  My company is currently looking into bringing a new piece of third party software in for online ordering. The software does not handle pricing so they are requesting the pricing information from a web service. Their software is passing an XML file as a parameter, and expecting an XML file as a response. I would think that returning an XML file would be pretty straight forward, but I cannot think of a way to receive an XML file as a parameter. Has anyone done this, or am I missing something really obvious?

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• xml parsing takes extra spaces.

  - by SDK

  I have been trying to write/parse xml file in python. The tags are very simple <main> <data> abcdef </data> </main> I have written this xml using xml document writer from xml.dom.minidom. How-ever when i try to parse this and try to fetch data-text value, i get 'abcdef' with spaces/carriage return/newline characters in beg and end. Does parsing does not take of indenting spaces? Following is the parsing snippet (ref from net) dom = parseString(data) clipTag = dom.getElementsByTagName('clipdata')[0].toxml() clipData=clipTag.replace('<clipdata>','').replace('</clipdata>','') Kindly suggest.

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• Android Java error handling XML file

  - by Paul

  I'm using SAX and XML reader to read XML weather info from the web and it works fine if the page exists. But if for instance the user inputs an invalid city, zip etc the XML page that gets read from is empty and the app force closes with nullpointerexception. The area that generates the error is here right at open inputstream. Any suggestions?: SAXParserFactory spf = SAXParserFactory.newInstance(); SAXParser sp = null; try { sp = spf.newSAXParser(); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* Get the XMLReader of the SAXParser we created. */ XMLReader xr = null; try { xr = sp.getXMLReader(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* Create a new ContentHandler and apply it to the XML-Reader*/ WeatherHandler myExampleHandler = new WeatherHandler(); xr.setContentHandler(myExampleHandler); /* Parse the xml-data from our URL. */ try { xr.parse(new InputSource(url.openStream())); parsedWeatherDataSet = myExampleHandler.getParsedData(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } return parsedWeatherDataSet.toString();

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• Invalid XML Replace Content in PHP

  - by streetparade

  I have a invalid XML like this Warning: count() [function.count]: Node no longer exists in /var/bla/test.php <?xml version="1.0" encoding="ISO-8859-1"?> <nodes> <some>test</some> </nodes> Now i need a regex which would replace the Warning: count() [function.count]: Node no longer exists in /var/bla/test.php with "" how can i do that? The above xml is is not generated on my localmachine, its a api call which returned a invalid xml

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• Editing XML file content with Python.

  - by Hooloovoo

  Hi, I am trying to use Python to read in an XML file containing some parameter names and values, e.g. ... <parameter name='par1'> <value>24</value> </parameter> <parameter name='par2'> <value>Blue/Red/Green</value> </parameter> ... and then pass it a dictionary with the parameter names {'par1':'53','par2':'Yellow/Pink/Black',...} and corresponding new values to replace the old ones in the XML file. The output should then overwrite the original XML file. At the moment I am converting the XML to a python dictionary and after some element comparison and regular expression handling, writing the output again in XML format. I am not too happy with this and was wondering whether anyone can recommend a more efficient way of doing it? Thanks.

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• xml cache on iphone

  - by dubbeat

  Hi, Could somebody suggest a technique or class library to read up on for XML Caching on the iphone? The biggest lag in my app is the XML being downloaded from the server. If a user views a screen the xml has to be downloaded and parsed and theres a wait of a few seconds. If they leave the screen and come back to it again they have to wait all over again which is kinda crappy.

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• Succinct LINQ to XML Query

  - by Kent Boogaart

  Assuming you have the following XML: <?xml version="1.0" encoding="utf-8"?> <content> <info> <media> <image> <info> <imageType>product</imageType> </info> <imagedata fileref="http://www.example.com/image1.jpg" /> </image> <image> <info> <imageType>manufacturer</imageType> </info> <imagedata fileref="http://www.example.com/image2.jpg" /> </image> </media> </info> </content> Using LINQ to XML, what is the most succinct, robust way to obtain a System.Uri for an image of a given type? At the moment I have this: private static Uri GetImageUri(XElement xml, string imageType) { return (from imageTypeElement in xml.Descendants("imageType") where imageTypeElement.Value == imageType && imageTypeElement.Parent != null && imageTypeElement.Parent.Parent != null from imageDataElement in imageTypeElement.Parent.Parent.Descendants("imagedata") let fileRefAttribute = imageDataElement.Attribute("fileref") where fileRefAttribute != null && !string.IsNullOrEmpty(fileRefAttribute.Value) select new Uri(fileRefAttribute.Value)).FirstOrDefault(); } This works, but feels way too complicated. Especially when you consider the XPath equivalent. Can anyone point out a better way?

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• convert &lt to < xml document

  - by Lenin Lourembam

  Hi, I have read an XML file and converted into NSXMLDocument object. But, due to the presence of "<" in the string content of a node, it has been converted into "&lt". So, when i write it as xml document to a file, it has the character "&lt" in it. How can i write to the file as ordinary XML file in which "&lt" will be replaced by "<". Thanks and Regards, Lenin

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• Java, UnmarshallingException caused by XML attribute with special chars: ;ìè+òàù-<^èç°§_>!£$%&/()=?~

  - by segolas

  Hi, my xml file has a tag with an attribute "containsValue" which contains the "special" characters you can see in the subject: <original_msg_body id="msgBodySpecialCharsRule" containsValue=";ìè+òàù-<^èç°§_>!£$%&/()=?~`'#;" /> in my xml schema the attribute has xs:string: <xs:attribute name="containsValue" type="xs:string" /> I use this value inside a Java software which check if this value is contained inside another String. but I always obtain this Exception: javax.xml.bind.UnmarshalException - with linked exception: [org.xml.sax.SAXParseException: The value of attribute "containsValue" associated with an element type "original_msg_body" must not contain the '<' character.] How can I solve it? I've tried changing the attribute type to xs:NMTOKEN, ut I get the same exception. Is there any other type? I think I could change the characters encoding, for example using the HTML representation, like <, but than could be tricky for the string comparison...

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• Procedural... house with rooms generator

  - by pek

  I've been looking at some algorithms and articles about procedurally generating a dungeon. The problem is, I'm trying to generate a house with rooms, and they don't seem to fit my requirements. For one, dungeons have corridors, where houses have halls. And while initially they might seem the same, a hall is nothing more than the area that isn't a room, whereas a corridor is specifically designed to connect one area to another. Another important difference with a house is that you have a specific width and height, and you have to fill the entire thing with rooms and halls, whereas with a dungeon, there is empty space. I think halls in a house is something in between a dungeon corridor (gets you to other rooms) and an empty space in the dungeon (it's not explicitly defined in code). More specifically, the requirements are: There is a set of predefined rooms I cannot create walls and doors on the fly. Rooms can be rotated but not resized Again, because I have a predefined set of rooms, I can only rotate them, not resize them. The house dimensions are set and has to be entirely filled with rooms (or halls) I.e. I want to fill a 14x20 house with the available rooms making sure there is no empty space. Here are some images to make this a little more clear: As you can see, in the house, the "empty space" is still walkable and it gets you from one room to another. So, having said all this, maybe a house is just a really really tightly packed dungeon with corridors. Or it's something easier than a dungeon. Maybe there is something out there and I haven't found it because I don't really know what to search for. This is where I'd like your help: could you give me pointers on how to design this algorithm? Any thoughts on what steps it will take? If you have created a dungeon generator, how would you modify it to fit my requirements? You can be as specific or as generic as you like. I'm looking to pick your brains, really.

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