Search Results

Search found 18954 results on 759 pages for 'connection reset'.

Page 451/759 | < Previous Page | 447 448 449 450 451 452 453 454 455 456 457 458  | Next Page >

  • Add subview to another view

    - by Martol1ni
    With two ViewControllers, MyView 1 and MyView 2, is there possible to add a subview to MyView2 from MyView1.m? I have tried: MyView2 * screen = [[MyView2 alloc]initWithNibName:nil bundle:nil]; [screen.view addSubView:mySubView]; But my new instance of MyView 2 has no connection to the 'visible' ViewController on MyView2, right? To clarify, the ViewController that is showing, is MyView1. I want MyView1 to be able to add a subview to the MyView2 view. Thanks

    Read the article

  • Integration Services Throws an Error Reading Access 2007 Table

    - by Eric Flamm
    [Participant Table [1994]] Error: SSIS Error Code DTS_E_CANNOTACQUIRECONNECTIONFROMCONNECTIONMANAGER. The AcquireConnection method call to the connection manager "I:\My Documents\Flamm Consulting\Migrations.accdb" failed with error code 0xC0209303. There may be error messages posted before this with more information on why the AcquireConnection method call failed. Frankly, I'm confused about how SSIS should connect to Access 2007 - the UI just isn't very friendly - there's no file browser, for example. I'm wondering if there's something wrong with my install - missing drivers, etc.

    Read the article

  • How can I split mySQL query logs by database?

    - by barnaby
    I've been trying to implement a mySQL Proxy solution that can separate out the queries into per-database logs. Everything I've Googled has pointed to mySQL Proxy but I can only seem to capture the database a connection was opened to, not which the current query is being issued against. Is it even possible? Is there a different tool to use? Thanks for any suggestions.

    Read the article

  • PHP syntax error “unexpected $end”

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • HTML5 validator.w3.org

    - by danixd
    My site was valid until today, wondering wether it is my site's or the validator's fault. I am getting this message: The error encountered was: 500 Can't connect to localhost:8888 (connect: Connection refused)

    Read the article

  • I cnn't use Database in SQL Azure!

    - by Nahid
    Hi, I am trying to use a Database in SQL AZURE. I have installed SQL Server 2008. I can Login SQL Azure and can use master Database. But I can't use other Database and I can't see any things in my object explorer. Its Show Error: "USE statement is not supported to switch between databases. Use a new connection to connect to a different Database." How can I use other database?

    Read the article

  • Default MVC Web Application Database

    - by wows
    When setting up a new ASP.NET MVC Web Application, the default connection string inside Web.Config is something like this: connectionString="data source=.\SQLEXPRESS;Integrated Security=SSPI;AttachDBFilename=|DataDirectory|aspnetdb.mdf;User Instance=true" I'm just wanting to play around with logging in and registering, etc but when I run the app it obviously can't find a SQL database. What database with what tables do I need to setup to do this? I have SQL Server 2005 Standard installed on my system, is that enough? Thanks.

    Read the article

  • timeout stringwithcontentsofurl

    - by sergiobuj
    Hi, I have this call to stringwithcontentsofurl: [NSString stringWithContentsOfURL:url usedEncoding:NSASCIIStringEncoding error:nil]; How can I give that a simple timeout? I don't want to use threads or operation queues (the content of the url is about 100 characters), I just don't want to wait too long when the connection is slow.

    Read the article

  • QueryTables error

    - by ktm5124
    I have the following VBA code inside an Excel macro: With ActiveSheet.QueryTables.Add( _ Connection:=ConnStr, _ Destination:=ActiveSheet.Range("A1"), _ Sql:=SqlStr) .Refresh End With And yet I am getting the error: "Run-time error '1004': Application-defined or object-defined error." The debugger points to this code as the source of error. Assuming that my ConnStr and SqlStr are correct, why am I getting this error? I am using Excel 2007 and I am querying an Oracle database.

    Read the article

  • How to connect laptop with telephone using WI-FI? (ethernet)

    - by rmaster
    What I did: 1)added new wireless network in wireless network settings and gave it SSID 2)gave laptop the IP like 192.168.0.1, mask: 255.255.255.0, gateway: 192.168.0.2 3)gave the telephone with wifi the same mask but IP and gateway rewersed But telephone can not find my new wireless network(it can find all other networks), computer also can not find it. where is error? how to make it visible and working? if my steps are wrong tell me correct way to establish this connection via wi-fi

    Read the article

  • Read some content of a resource on internet

    - by Andreas Johannessen
    Hi For my iPhone application I need to read some content of a plain html file on the web. It's just some text within a pre-tag. However I don't want to download the whole file and then get the line I need. The format is: TextTextTextTextTextTextTextText TextTextTextTextTextTextTextText TextTextTextTextTextTextTextText TextTextTextTextTextTextTextText I only need the first line and then close the connection to that resource. Thanks in advance.

    Read the article

  • Compare Tables in different databases with ADO.Net 3.5

    - by MicMit
    I need to compare tables with the same names in different databases ( Sql Server 2008 ). How using C# code and ADO.Net to identify additions, deletions, updates. Is DataReader going to work in this scenario without stored procedures ? DataReader seems to be suitable for single database connection, or am I missing something ?

    Read the article

  • NHibernate unable to create SessionFactory

    - by Tyler
    I'm having a bit of trouble setting up NHibernate, and I'm not too sure what the problem is exactly. I'm attempting to save a domain object to the database (Oracle 10g XE). However, I'm getting a TypeInitializationException while trying to create the ISessionFactory. Here is what my hibernate.cfg.xml looks like: <?xml version="1.0" encoding="utf-8"?> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2" > <session-factory name="MyProject.DataAccess"> <property name="connection.driver_class">NHibernate.Driver.OracleClientDriver</property> <property name="connection.connection_string"> User ID=myid;Password=mypassword;Data Source=localhost </property> <property name="show_sql">true</property> <property name="dialect">NHibernate.Dialect.OracleDialect</property> <property name="proxyfactory.factory_class">NHibernate.ByteCode.LinFu.ProxyFactoryFactory, NHibernate.ByteCode.LinFu</property> <mapping resource="MyProject/Domain/User.hbm.xml"/> </session-factory> </hibernate-configuration> I created a DAO which I will use to persist domain objects to the database. The DAO uses a HibernateUtil class that creates the SessionFactory. Both classes are in the DataAccess namespace along with the Hibernate configuration. This is where the exception is occuring. Here's that class: public class HibernateUtil { private static ISessionFactory SessionFactory = BuildSessionFactory(); private static ISessionFactory BuildSessionFactory() { try { // This seems to be where the problem occurs return new Configuration().Configure().BuildSessionFactory(); } catch (TypeInitializationException ex) { Console.WriteLine("Initial SessionFactory creation failed." + ex); throw new Exception("Unable to create SessionFactory."); } } public static ISessionFactory GetSessionFactory() { return SessionFactory; } } The DataAccess namespace references the NHibernate DLLs. This is virtually the same setup I've used with Hibernate in Java, so I'm not entirely sure what I'm doing wrong here. Any ideas? Edit The innermost exception is the following: "Could not find file 'C:\Users\Tyler\Documents\Visual Studio 2010\Projects\MyProject\MyProject\ConsoleApplication\bin\Debug\hibernate.cfg.xml'." ConsoleApplication contains the entry point where I've created a User object and am trying to persist it with my DAO. Why is it looking for the configuration file there? The actual persisting takes place in the DAO, which is in DataAccess. Also, when I add the configuration file to ConsoleApplication, it still does not find it.

    Read the article

  • Improve long mysql query

    - by John Adawan
    I have a php mysql query like this $query = "SELECT * FROM articles FORCE INDEX (articleindex) WHERE category='$thiscat' and did>'$thisdid' and mid!='$thismid' and status='1' and group='$thisgroup' and pid>'$thispid' LIMIT 10"; As optimization, I've indexed all the parameters in articleindex and I use force index to force mysql to use the index, supposedly for faster processing. But it seems that this query is still quite slow and it's causing a jam and maxing out the max mysql connection limit. Let's discuss how we can improve on such long query.

    Read the article

  • Improve long mysql query

    - by John Adawan
    I have a php mysql query like this $query = "SELECT * FROM articles FORCE INDEX (articleindex) WHERE category='$thiscat' and did>'$thisdid' and mid!='$thismid' and status='1' and group='$thisgroup' and pid>'$thispid' LIMIT 10"; As optimization, I've indexed all the parameters in articleindex and I use force index to force mysql to use the index, supposedly for faster processing. But it seems that this query is still quite slow and it's causing a jam and maxing out the max mysql connection limit. Let's discuss how we can improve on such long query.

    Read the article

  • What design pattern should be used to create an emulator?

    - by Facon
    I have programmed an emulator, but I have some doubts about how to organizate it properly, because, I see that it has some problems about classes connection (CPU <- Machine Board). For example: I/O ports, interruptions, communication between two or more CPU, etc. I need for the emulator to has the best performance and good understanding of the code. PD: Sorry for my bad English.

    Read the article

  • Definition of Connect, Processing, Waiting in apache bench.

    - by rpatel
    When I run apache bench I get results like: Command: abs.exe -v 3 -n 10 -c 1 https://mysite Connection Times (ms) min mean[+/-sd] median max Connect: 203 213 8.1 219 219 Processing: 78 177 88.1 172 359 Waiting: 78 169 84.6 156 344 Total: 281 389 86.7 391 563 I can't seem to find the definition of Connect, Processing and Waiting. What do those numbers mean?

    Read the article

  • cannot access sql server after publishing site in iis7

    - by vinu
    I am created a website using visual studio 2010. On the time of the development of website I am able to access the database.. but after publishing the site using IIS7..i was unable to access the database..the exception occured during that time was "the connection is in the closed state".in IIS7 When I changed the application pool identity to localsystem, it worked. Data base is installed in the same machine. and server is SQL SERVER 2008 R2

    Read the article

  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Check for live Data Source Name Before proceeding

    - by n_kips
    Would it be ok to get a CF app to check for a valid database before proceeding to process that request? This is because there may be instances where the database server may be down or being upgraded, hence an error comes when a db dependant request is made. If there is no connection to the db server, the user can be safely redirected to a safe page. Or can cfcatch work? How can this check be done? Thank you.

    Read the article

< Previous Page | 447 448 449 450 451 452 453 454 455 456 457 458  | Next Page >